The force on a particle is described by 8x^3 - 5 at a point a along the z-axis. Find the work done in moving the particle from the origin to x = 4

Answer:

y - 2 = 0.5(x - 1)

Step-by-step explanation:

use the two points to find the gradient of the line

Answer:

45:40

27:24

Step-by-step explanation:

45:40 c=5

27:24 c=3

Answer:

3

Step-by-step explanation:

Answer:

Step-by-step explanation:

(x-2)(2x+3)(x+1)

=x(2x+3)-2(2x+3)(x+1)

=(2x^2+3x-4x-6)(x-1)

=(2x^2-x-6)(x-1)

=2x^2(x-1)-x(x-1)-6(x-1)

=2x^3-2x^2-x^2+x-6x+6

=2x^3-3x^2-5x+6

( x - 2 )( x + 1 )( 2x + 3 ) =

( x^2 - x - 2 )( 2x + 3 ) =

2x^3 - 2x^2 - 4x + 3x^2 - 3x - 6 =

2x^3 + ( -2 + 3 )x^2 + ( - 4 - 3 )x - 6 =

2x^3 + x^2 - 7x - 6

Yes, they can speed up the run time by using a heuristic to output a playlist that is not optimal, but close enough.

A phase of the programming lifecycle is runtime. It is the period of time when a programme is simultaneously being executed by all external instructions required for proper operation. Some of these extraneous commands are built into programming languages and are known as runtime environments or runtime systems. The environment in which a programme or application is run is known as the runtime environment.

Programs may access all the features they want and operate independently of operating systems thanks to runtime environments, which is one of their main advantages. The runtime process is well-understood by most users of computer programmes, but it is crucial to software engineers because if flaws are identified in the code, the programme will throw runtime errors.

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Answer: 7313

Step-by-step explanation:

Answer:

it's really simple problem is C

Step-by-step explanation:

i wanna know too tho......

The outward flux of ⁻F across the surface of the solid bounded by the cylinder y² + z² = 4 and the plane x = z + 2 in the first octant is 6π.

To find the outward flux, we need to evaluate the surface integral of the vector field ⁻F over the given surface. The surface consists of the curved part of the cylinder and the plane in the first octant. We can parameterize the surface using cylindrical coordinates as follows:

x = ρcosθ

y = ρsinθ

z = z

The normal vector to the surface is given by n = ∇r, where r is the position vector of the surface. The outward flux is then given by the surface integral ∬S ⁻F · n dS.

Considering the cylindrical surface S1: ρ = 2, and the plane S2: x = z + 2, we can rewrite the surface integral as a double integral over the cylindrical surface in terms of ρ and θ:

∬S1 ⁻F · n dS + ∬S2 ⁻F · n dS

Using the parametric equations and the normal vector, we can calculate ⁻F · n for each surface:

For S1, ⁻F · n = ⁻F · (∇r) = ⁻F · (∂ρ/∂x, ∂ρ/∂y, ∂ρ/∂z)

             = (2xy)(∂ρ/∂x) + (2xy)(∂ρ/∂y) + (2xz + y - y²)(∂ρ/∂z)

For S2, ⁻F · n = ⁻F · (∇r) = ⁻F · (∂x/∂x, ∂x/∂y, ∂x/∂z)

             = (2xy)(∂x/∂x) + (2xy)(∂x/∂y) + (2xz + y - y²)(∂x/∂z)

Evaluating these dot products and performing the double integrals, we find the outward flux to be 6π.

The outward flux of the vector field ⁻F across the surface of the solid bounded by the cylinder y² + z² = 4 and the plane x = z + 2 in the first octant is 6π. This result indicates the net flow of the vector field outward through the surface.

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That a full cut round brilliant diamond with a 6.50 mm girdle diameter typically weighs around 1.00 carat.

carat weight is determined by a combination of a diamond's size and density. A diamond's size is measured by its diameter, which is the distance across the widest part of the diamond, known as the girdle. Therefore, a diamond with a larger girdle diameter will generally weigh more than a diamond with a smaller diameter, assuming all other factors are equal.

the weight of a diamond can be estimated based on its girdle diameter, and a full-cut round brilliant diamond with a 6.50 mm girdle diameter typically weighs around 1.00 carat. However, it's important to note that other factors, such as depth, cut, and clarity, can also affect a diamond's weight and value.

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Total number of students = 300 (given in the question)

The number of students who prefer vanilla = 105 (given in the question)

The number of students who prefer chocolate= 93 (given in the question)

The number of students who prefer both = 56 (given in the question)

Let the total number of students = T

Let the number of students who prefer vanilla = V = 105

Let the number of students who prefer chocolate  = C = 93

Then

the number of students that prefer both = V ∩ C = 56

Number of students that prefer neither = T - (V + C - V ∩ C )

Number of students that prefer neither = 300 - ( 105 + 93 - 56)

Number of students that prefer neither = 300 -  142

Number of students that prefer neither = 158

Then, P(V) = ( V - V ∩ C )/ 300

P(V) = 105 - 56/ 300

P(V) = 49/300

P(C) = C - V ∩ C/ 300

P(C) = 93 - 56/300

P(C) = 37/300

Then the probability that the random student prefers only chocolate or only  vanilla = P(V) + P(C)

= 49/300 + 37/300

= 49 + 37/300

= 86/300

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Answer:

1/3000

Step-by-step explanation:

3 meters to centimeters:

3 × 100 = 300

= 1/10 ÷ 300

= 1/10/300

= 1/(10×300)

= 1/3000

Among the given expressions, the one that could be the possible leading term for the polynomial function graphed below is -18x¹⁴.

The leading term of a polynomial function is the term containing the highest power of the variable. Among the given expressions, the one that could be the possible leading term for the polynomial function graphed below is -18x¹⁴.

The degree of a polynomial function is the highest degree of any of its terms.

If a polynomial has only one term, then the degree of that term is the degree of the polynomial and is also called a monomial.

For example, consider the given function:Now, observe the degree of the function, which is 14, as the highest exponent of the function is 14.

Thus, the term containing the highest power of the variable x is -18x¹⁴.

Therefore, among the given expressions, the one that could be the possible leading term for the polynomial function graphed below is -18x¹⁴.

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Stephen makes the mistake in the expression as he uses the 4 in the root and the 3 in the power and the expression actually is: ∛(16)/e

We start with the expression:

exp( (4/3)*ln(2) - 1)

Here we can use that:

exp(ln(x)) = x.

and e^(a + b) = e^a*e^b.

the first step here is:

e^((4/3)*ln(2) - 1) = e^((4/3)*ln(2)*e^(-1)

So the first step of Stephen is correct, but the first step of Helen is not, you can not simplify the expression in that way.

now, we have that:

a*ln(x) = ln(x^a)

then we can write:

(4/3)*ln(2) = ln(2^(4/3))

and e^(ln(2^(4/3)) = 2^(4/3)

then we have:

e^((4/3)*ln(2)*e^(-1) = 2^(4/3)/e

now we can write this as:

∛(2^4)/e

Here is where Stephen makes the mistake, he uses the 4 in the root and the 3 in the power.

The expression actually is: ∛(16)/e

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6 seconds, i think

sry if im wrong

In order to roughly determine the roots of the given equation, the bisection method divides the interval several times.

In order to get close to the equation's roots, the bisection method divides the interval several times.

This strategy is based on the continuous functions intermediate theorem. It works by reducing the gap between the positive and negative intervals as it approaches the desired response.

This method narrows the gap between the variables by averaging the positive and negative intervals. Even though it is a simple process, it proceeds slowly.

The bisection method is also known as the dichotomy method, binary search method, and root-finding method.

Then, according to the intermediate theorem, there is a point x that is a part of (a, b) and has the value f(x) = 0.

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The negative integer meet on integer hill .The result of -6+(-7) is -13

Any integer with a value below zero is referred to as a negative integer. Examples for each operation will help you understand the rules for adding, subtracting, multiplying, and dividing negative numbers.

On the number line, a negative integer is an integer that is to the left of zero.

All positive counting numbers, zero, and all negative counting numbers that count from negative infinity to positive infinity are included in the category of integers.

Real integers that are less than zero are the negative integers. For instance, 147 and 4 are both negative numbers, but 10 and 0.4181554 are not (the former is a negative number but not an integer, the latter is a positive integer)

Given,

-6+(-7) by simplifying we got

=-13

Therefore The negative integer meet on integer hill .The result of -6+(-7) is -13

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Consuelo deposited an amount of money in a savings account that earned 6. 3% simple interest. After 20 years , she had earned $5’922 in interest then the initial deposit was $4700

Use the simple interest formula

I = P r t

where I = simple interest

P = principal

r= rate of interest

t= number of years

5922=Px6.3%x20

5922=Px1.26

P=5922/1.26

P=4700

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Answer:

The answer is A.

Step-by-step explanation:

Made a 100 on the quiz on E2020

Answer:

The correct answer is A

Step-by-step explanation:

284.30 also my name is Darlene

(x²-3x+4) - (x³ +7x-2)

= x²-3x+4-x³+7x-2

In this step, they took the equations out of the parenthesis. In order to do that, you must use the distributive property. In the second equation -(x³+7x-2), everything within the parenthesis should be multiplied by the negative. Here would be the correct answer:

=x²-3x+4-x³-7x+2

2) The slope of the tangent line at x = 1 is 3.

To differentiate the given function, we can apply the power rule and constant rule.

1. For s(t) = t^3 - 2:

The derivative of s(t), denoted as s'(t), is obtained by differentiating each term separately:

s'(t) = d/dt(t^3) - d/dt(2)

Using the power rule, the derivative of t^3 with respect to t is:

d/dt(t^3) = 3t^2

The derivative of a constant (in this case, 2) is zero:

d/dt(2) = 0

Therefore, the derivative s'(t) is:

s'(t) = 3t^2 - 0

s'(t) = 3t^2

2. For f(x) = 3x + 5:

The derivative of f(x), denoted as f'(x), is obtained by differentiating each term separately:

f'(x) = d/dx(3x) + d/dx(5)

The derivative of 3x with respect to x is:

d/dx(3x) = 3

The derivative of a constant (in this case, 5) is zero:

d/dx(5) = 0

Therefore, the derivative f'(x) is:

f'(x) = 3 + 0

f'(x) = 3

Now, let's find the slope of the tangent line at the given values of the independent variable:

1. For s(t) at t = 7:

Substituting t = 7 into s'(t), we get:

s'(7) = 3(7)^2

s'(7) = 3(49)

s'(7) = 147

The slope of the tangent line at t = 7 is 147.

2. For f(x) at x = 1:

Substituting x = 1 into f'(x), we get:

f'(1) = 3

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Answer:

1/16

Step-by-step explanation:

Answer:

713 puercos

Step-by-step explanation:

Sea T el número total de puercos

Número de cerdos = 57

Porcentaje = 8%

Para encontrar el número total de puercos;

Porcentaje = 8/100 * T = 57

8T/100 = 57

8T = 5700

T = 5700/8

T = 712,5 ≈ 713 puercos

Por lo tanto, el granjero tiene 713 puercos en total.

Answer:

Most students prefer math

Step-by-step explanation:

The scale of the blueprint is 1 in : 4 ft.

A map scale is the relationship between a distance on a map and the corresponding distance on the earth.

Given that, on a blueprint of a house, the kitchen is 5 inches long, the actual kitchen is 20 feet long, we are asked to find the scale of the blueprint.

Since, the kitchen in the map is 5 in long whereas n earth it is 20 ft long.

Therefore, the ratio =

5 in / 20 ft = 1 in / 4 ft

Hence, the scale of the blueprint is 1 in : 4 ft.

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Answer:

Step-by-step explanation:

x+10=0

x=-10

so vertex is (-10,-105)

Answer:

x = 40

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

126° is an exterior angle of the triangle, then

x + 2x + 6 = 126

3x + 6 = 126 ( subtract 6 from both sides )

3x = 120 ( divide both sides by 3 )

x = 40

Replace x with -2 and solve:

A) -2 + -2 = -4 which is not less than or equal to -8

B) 2 + -2 = 0, this is greater than or equal to -8

C) -2 + -2 = -4, this is not less than -8

D) 2 + -2 = 0, this is not greater than 8

Answer: B is true