8. Fill in the table below with the maximum number of complete race cars that can be buike from each container of parts (A-E), and indicate which part limits the number of cars that can be built. Divide the work evenly among group members. Space is provided below the table for each group member to show their work. Have each group member describe to the group how they determined the maximum number of complete cars for their container. Container A from Model 2 is already completed as an example.
1 B + 3 Cy + 4Tr + 1 E - 1 car
Based on the principle of limiting reactants in chemical reactions, the maximum number of complete cars for their container based on the limiting parts of the car are as follows:
A - 2 cars
B - 4 cars
C - 4 cars
D - 3 cars
E - 10 cars
What is a limiting reactant in a reaction?The reactant that is consumed first in a chemical reaction, also known as the limiting reactant (or limiting reagent), limits the amount of product that can be produced.
Consider the reaction below:
N₂ + 3 H₂ ---> 2 NH₃One mole of N₂ cannot be used in its entirety if two moles of H₂ react with one mole of N₂, as there is not enough H₂ in the reaction. Hydrogen is the limiting reagent as a result.
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3. What is the energy of a photon that has a frequency of 2.3 x 1014 Hz?
The energy of a photon that has a frequency of 2.3 x 10¹⁴ Hz is 1.524 × 10-¹⁹J
HOW TO CALCULATE ENERGY OF A PHOTON:
The energy of a photon can be calculated by using the formula as follows:E = hf
Where;
E = energy of photon (J)
h = Planck's constant (6.626 × 10-³⁴J)
f = frequency of photon (Hz)
According to this question, a photon has a frequency of frequency of 2.3 x 10¹⁴ Hz. The energy of the photon can be calculated as follows:E = 6.626 × 10-³⁴ × 2.3 × 10¹⁴
E = 15.24 × 10-³⁴+¹⁴
E = 15.24 × 10-²⁰J
E = 1.524 × 10-¹⁹J
Therefore, energy of a photon that has a frequency of 2.3 x 10¹⁴ Hz is 1.524 × 10-¹⁹JLearn more at: https://brainly.com/question/23180082?referrer=searchResults
In the molecule C2H4 the valence orbitals of the carbon atoms are assumed to be?
a) dsp hybridized
b) not hybridized
c) sp hybridized
d) sp^3 hybridized
e) sp^2 hybridized
In the molecule C2H4, valence orbitals of the carbon atoms are assumed to be e) sp^2 hybridized.
What is valence orbitals?The set of orbitals that can energetically accept electrons to create chemical bonds is known as the valence shell. The ns and np orbitals in the outermost electron shell make form the valence shell for main-group elements.
The outside electrons engaged in bonding are called valence electrons. A particular atom can have 0 to 7 valance electrons since valance electrons can only exist in the s and p orbitals. Noble gases are atoms that have no valence electrons and dislike forming bonds.
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How many particles are in 0.55 mil NaCl?
Answer:
2 atoms
Explanation:
when water is boiling, adding heat responses a quickly raises the temperature.quickly raises the temperature. b slowly raises the temperature.slowly raises the temperature. c increases the temperature.increases the temperature. d does not increase the temperature.does not increase the temperature.
When water is boiling, adding heat does not increase the temperature. Correct option is d.
When water reaches its boiling point, which is 100°C (212°F) at standard atmospheric pressure, any additional heat supplied will not increase its temperature. Instead, the added heat is utilized to convert water from its liquid state to vapor through a process called phase transition.
During this phase change, the temperature remains constant as the extra energy is used to break the hydrogen bonds between the water molecules, allowing them to escape as steam. This is why the temperature does not increase even when more heat is added to boiling water.
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Calculate the number of grams in 4.56 x 1026 atoms of sodium phosphate. Be sure to balance the charges of sodium phosphate. Help please
Answer:
124225.91 g of Na₃PO₄
Explanation:
From the question given above, the following data were obtained:
Number of atoms of Na₃PO₄ = 4.56×10²⁶ atoms
Mass of Na₃PO₄ =?
From Avogadro's hypothesis,
6.02×10²³ atoms = 1 mole of Na₃PO₄
Next, we shall determine the mass of 1 mole of Na₃PO₄. This can be obtained as follow:
1 mole of Na₃PO₄ = (23×3) + 31 + (16×4)
= 69 + 31 + 64
= 164 g
Thus,
6.02×10²³ atoms = 164 g of Na₃PO₄
Finally, we shall determine the mass of Na₃PO₄ that contains 4.56×10²⁶ atoms. This can be obtained as follow:
6.02×10²³ atoms = 164 g of Na₃PO₄
Therefore,
4.56×10²⁶ atoms = (4.56×10²⁶ × 164)/6.02×10²³
4.56×10²⁶ atoms = 124225.91 g of Na₃PO₄
Therefore, 124225.91 g of Na₃PO₄ contains 4.56×10²⁶ atoms
How is cosmic microwave background radiation evidence for the Big Bang?
Answer:
In explanation,
Explanation:
Tests of Big Bang: The CMB. The Big Bang theory predicts that the early universe was a very hot place and that as it expands, the gas within it cools. Thus the universe should be filled with radiation that is literally the remnant heat left over from the Big Bang, called the “cosmic microwave background", or CMB.
I’ll mark you brainlist
Answer:
High mass star.
Explanation:
The mass of a star defines its life span. the least massive stars will live the longest and the most massive stars will use their fuel in a few million years and end in a spectacular supernova.
write the chemical properties of metal with an example of each
Answer:
high density, malleable, ductile, can corrode, good conductors,
Explanation:
gold's density is 19.3 g/cc compared to something like water which is 1g/cc
aluminum is extremely malleable, it can be flattened into thin sheets
copper can be formed into complex forms without breaking like wire, instruments, and bed frames
steel can get corroded by the oxygen particles in the air if it stays out too long.
copper is an excellent example of a conductor, it is used to make wires which conduct electricity that brings "power" into things like lights, computers, and TVs
Please balance these chemical equations
The chemical equations given would be balanced below
How should a chemical equation be balanced?The balanced equation of the various given chemical equations can be determined only when the number of atoms on the product part is the same with the number of atoms on the reactant side.
For 1.)
\(N_{2} + 3H_{2} ----- > 2NH_{3}\)
For 2.)
\(2KCl_{3} ----- > 2KCl + 3O_{2}\)
For 3.)
\(2NaCl + F_{2} ----- > 2NaF + Cl_{2}\)
For 4.)
\(2H_{2} + O_{2} ----- > 2H_{2} O\)
For 5.)
\(Pb(OH)_{2} + 2HCl ----- > 2H_{2} O +PbCl_{2}\)
For 6.)
\(2AlBr_{3} + 3K_{2}SO{4} ---- > 6KBr + Al_{2}(SO_{4})_{3}\)
For 7.)
\(CH_{4} + O_{2} ----- > CO_{2} + 2H_{2} O\)
For 8.)
\(C_{3} H_{8} + 3O_{2} ----- > 3CO_{2} + 4H_{2} O\)
For 9.)
\(C_{8} H_{18} + 8O_{2} ----- > 8CO_{2} + 9H_{2} O\)
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Give an example of gravitational potential
A raised weight.
Water that is behind a dam.
Have a nice day!
Answer:
When something has a high position, its gravitational potential energy is high. For example, a book on a high bookshelf has higher potential energy than a book on the bottom shelf because it has farther to fall. ... A book on a table before it falls. A child at the top of a slide.
Explanation:
U=m g h
An ion has 28 protons, 24 electrons, and 30 neutrons. What is its ionic
charge?
How much heat (in kJ ) is required to warm 12. 0 g of ice, initially at -11. 0 ∘C , to steam at 109. 0 ∘C ? The heat capacity of ice is 2. 09 J/g⋅∘C and that of steam is 2. 01 J/g⋅∘C
36.607 kJ of heat are needed to warm 12.0 g of ice.
For grade 11, how do you calculate enthalpy change?By deducting the total enthalpies of all the reactants from the total enthalpies of the products, the reaction enthalpy is determined. According to mathematics, tH is equal to the sum of the enthalpies of the reactants and the product.
The following formula can be used:
q1 = m ×Cice × ΔT1
When we change the values, we obtain:
q1 = 12.0 g ×2.09 J/g⋅∘C × 11.0°C
q1 = 273.48 J or 0.27348 kJ
We must apply the following formula to melt the ice at 0 degrees Celsius:
q2 = m * ΔHfus
where m is the mass of the ice (12.0 g), q2 is the necessary heat, and Hfus is the heat of fusion for water (334 J/g).
When we change the values, we obtain:
q2 = 12.0 g × 334 J/g
q2 = 4008 J or 4.008 kJ
We can use the formula below to warm the water from 0°C to 100°C:
q3 = m * Cwater * ΔT2
When we change the values, we obtain:
q3 = 12.0 g × 4.18 J/g⋅∘C * 100°C
q3 = 5025.6 J or 5.0256 kJ.
The following formula must be used to bring the water to a boil at 100°C:
q4 = m * ΔHvap
When we change the values, we obtain:
q4 = 12.0 g × 2257 J/g
q4 = 27,084 J or 27.084 kJ.
Lastly, we may apply the following formula to raise the steam's temperature from 100°C to 109°C:
q5 = m × Csteam × ΔT3
When we change the values, we obtain:
q5 = 12.0 g × 2.01 J/g⋅∘C × 9°C
q5 = 216.36 J or 0.21636 kJ
The total heat required is the sum of all these values:
Q1 + Q2 + Q3 + Q4 + Q5 = Qtotal
Qtotal = 0.21636 kJ +4.008 kJ +5.0256 kJ +27.084 kJ.
qtotal = 36.607 kJ
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Metallic behavior correlates with large atomic size and low ionization energy. Thus, metallic behavior increases down a group and decreases from left to right across a period.true or false
The statement "Metallic behavior correlates with large atomic size and low ionization energy. Thus, metallic behavior increases down a group and decreases from left to right across a period" is true.
The statement is true because metallic behavior correlates with large atomic size and low ionization energy. So, as you go down a group, the atomic size and ionization energy decrease, resulting in increased metallic behavior. As a result, when going from left to right across a period, the atomic size decreases, and the ionization energy increases, resulting in a decrease in metallic behavior.
As a result, the metallic behavior increases down a group and decreases from left to right across a period.
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Can someone pls answer quickly?
answer is atom.Hope it is helpful.
Answer:
Atoms are the smallest particles that made up matter.
7.The bond angles in SF5+are expected to be: a.90° b.120° c.90° and 120° d.90° and 180° e.90°, 120°, and 180°
The bond angles in SF₅⁺ are expected to be 90°, 120°, and 180°.
The correct option is E.
What are bond angles?Bond angles refer to the angles between the bond linking the atoms of elements in a compound or ion.
The bond angles exist as a result of either electrical repulsion between the electrons in the bonds.
The ion SF₅⁺ contains one atom of sulfur and five atoms of fluorine linked together by covalent bonds. The shape of the ion or the molecular geometry is square pyramidal. Hence, the bond angles are 90°, 120°, and 180°.
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Compounds are formed when two or more ___ are chemically combined.
Answer:
Elements
Explanation:
I just did this
How can you tell if atoms of two different elements will form polar covalent or nonpolar covalent bonds??
What is the mass of an object if the net force on the object is 15 N and it is accelerating at 3.0 m/s 2 ? (STOP REPORTING MY STUFF THIS TIME IT'S A QUESTION)
Answer:
the answer is 7.67
Explanation:
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What are five different types of air pollutant each
Which isotope has the greatest number of electrons? Pa-238 U-240 NP- 238 PU-239
All of the isotopes listed have the same number of electrons, which is determined by the atomic number of the element.
Pa-238 and NP-238 have 91 electrons each because they are both isotopes of the element Protactinium, which has an atomic number of 91.
U-240 has 92 electrons because it is an isotope of Uranium, which has an atomic number of 92.
PU-239 also has 94 electrons because it is an isotope of Plutonium, which has an atomic number of 94.
Therefore, all of the isotopes listed have the same number of electrons, which is determined by the atomic number of the element.
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Perform Calculatlons Using Ksp Question For the following equilibrium; HgBr2(s) ~= Hg?+(aq) + 2Br"(aq) If Ksp 6.2 x 10-20, what is the molar solubility of mercury (II) bromide (HgBrz)? Report your answer in scientific notation with the correct number of significant figures Provide your answer below:'
The molar solubility of mercury (II) bromide (HgBr2) is 7.00 × 10^-7 M. This is the long answer to the problem.
To perform calculations using Ksp for the given equilibrium HgBr2(s) ↔ Hg2+(aq) + 2Br-(aq) and find the molar solubility of mercury (II) bromide (HgBr2) we have to use the solubility product expression.Ksp for HgBr2 is 6.2 × 10^-20Ksp = [Hg2+][Br-]^2 Since the initial concentration of HgBr2 is given as s, and after dissociation, the concentration of Hg2+ becomes s, while the concentration of Br- becomes 2s.[Hg2+] = s M and [Br-] = 2s MThus,Ksp = [Hg2+][Br-]^2= s(2s)^2= 4s^3= 6.2 × 10^-20Molar solubility of HgBr2 is given as s, therefore;s = (6.2 × 10^-20/4)1/3s = 7.00 × 10^-7 M
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When naming a compound, which of these is written first?
Answer:
cation
Explanation:
Metal
Nonmetal
Anion
Cation
When naming a chemical compound, the cation is written first before anything else.
A typical ionic compound consists of two components - the cation and the anion. While the cation is positively charged in ion, the anion is negatively charged. The cation of a typical ionic compound is named first before the anion and the name often carries that of the element that composes it.
The name of the element that makes up the anion is modified by removing the last few characters ending the name and replacing it with the suffix 'ide'. For example, NaCl is named sodium chloride.
At the time of naming a compound, the one that would be written first would be:
- Cation
The compounds are described as substances that consist of varying combinations of elements from the chemical union. The compounds are given the name by starting with the cation(+ve charged ion) that it possesses followed by the anions(-ve charged ions) it contains.For example, KCl(potassium chloride) involves K+ cations and Cl- anions. Thus, 'cation' would be the correct answer among the given options as they come later in the process.Learn more about 'Compound' here:
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if i take 2 tables two times per day with 300 tables how many days will my prescription last
Answer:
150
Explanation:
300 divided by 2
a solution k is saturated at 33 g solute in 100g solvent if a 50g solute is added to 200g solvent solution k is
Answer:
33 100gc50 is a 100
Explanation:
Plz help
A candle burning is an example of
A. an endothermic change
B. a physical change
C. energy being taken in
D. an exothermic change
Answer:
D
Explanation: An exothermic change is Because it has heat.
If the same large amount of heat is added to a 250 g piece of aluminum and a 150 g piece of aluminum, what will happen?
a can contains 325 ml of soda. how much is left after 244 ml is removed? (express your answer to the correct number of significant figures and proper units.)
After 244 ml of soda is removed, there is 325 ml - 244 ml = 81 ml left in the can. This answer should be reported with the correct number of significant figures and proper units, which in this case would be 81 ml (3 significant figures).
When calculating the remaining amount of a substance after a portion has been removed, it is important to consider both the accuracy and units of the measurements involved. In this case, a can contains 325 ml of soda and 244 ml of soda has been removed. To find the remaining amount, we subtract the amount removed from the original amount: 325 ml - 244 ml = 81 ml. The answer should be reported with the correct number of significant figures, which reflects the level of accuracy of the measurements, and proper units, which in this case would be 81 ml (3 significant figures). It is important to use the correct number of significant figures and proper units when reporting the results of any calculation, as this helps to ensure the accuracy and consistency of the results, and makes it easier for others to understand and interpret the results.
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the water in a beaker has a volume of 50 millimeters, is this an extensive property?
No, the volume of water in a beaker is not an extensive property.
Extensive properties are those that depend on the amount or size of the substance being measured. In other words, they are properties that change with the quantity of the substance. Examples of extensive properties include mass, volume, and total energy.
In the given scenario, the volume of water in the beaker is 50 milliliters. This volume remains the same regardless of the quantity of water present. Whether it's 50 milliliters or 500 milliliters, the volume measurement does not change. Therefore, the volume of water in the beaker is an example of an intensive property.
Intensive properties are independent of the amount or size of the substance. They are characteristics that remain constant regardless of the quantity of the substance. Examples of intensive properties include temperature, density, and color.
It's important to note that the distinction between extensive and intensive properties depends on the specific property being considered. While volume is typically an extensive property for a bulk substance, in the case of a fixed volume of water in a beaker, it becomes an intensive property.
In summary, the volume of water in a beaker is not an extensive property but rather an intensive property because it does not change with the quantity of the substance.
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what do atom, molecules, and elements have in common
Answer:
Solids, liquids, gases - all matter - are made up of atoms (or other things, like molecules, that are made from atoms)! ELEMENTS are the kinds of atoms that we can have. Carbon is an element, hydrogen is an element, and so is oxygen. ... Atoms can join together - they form bonds together - to make MOLECULES.