Answer:
q alguien me explique y pueden ser español
A bubble originating at the bottom of a lake rises to the surface within 10.0 seconds with an acceleration of 10.0 meters/second2. what is the depth of the lake? a. 100 meters b. 200 meters c. 300 meters d. 400 meters e. 500 meters
The depth of the lake is 500 meters.
According to the question
Acceleration = 10 m/s²
Time = 10 sec
Distance is the total movement of an object without any regard to direction. We can define distance as to how much ground an object has covered despite its starting or ending point.
The distance covered in a certain time of accelerated motion:
D = (1/2) × A × T²
Distance covered= (1/2) (Acceleration) (Time squared) .
The question gives us the acceleration and the time.
Let's plug them into the formula.
Distance = (1/2) (10 m/s²) (10 sec)²
= (5 m/s²) (100 sec²)
= 500 meters.
The depth of the lake is 500 meters.
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The _____ is used to test the significance of the population coefficient of determination.
A. chi-square distrubution
B. normal distribution
C. Student's t-distribution
D. F-distribution
The F-distribution is used to test the significance of the population coefficient of determination (option D).
The coefficient of determination, denoted as R², measures the proportion of the variance in the dependent variable that is explained by the independent variables in a regression model. It ranges from 0 to 1, where 0 indicates no relationship and 1 indicates a perfect relationship.
To determine the significance of R², the F-distribution is used. The F-test compares the variation explained by the regression model (numerator) to the unexplained or residual variation (denominator). It calculates the F-statistic, which is the ratio of the two variances.
The F-distribution provides critical values that allow us to determine whether the observed F-statistic is statistically significant or not. By comparing the calculated F-value with the critical value from the F-distribution, we can assess whether the coefficient of determination is significantly different from zero, indicating the presence of a meaningful relationship between the variables. The correct option is d.
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what is the equation for a cosecant function with vertical asymptotes found at such that n is an integer?
The equation for a cosecant function with vertical asymptotes found at x = nπ such that n is an integer is `y = csc(x - nπ)`.
The cosecant function is the reciprocal of the sine function. The cosecant of a particular angle in a right triangle is the ratio of the hypotenuse to the side opposite the angle.
The cosecant function is written as follows: `csc(x) = 1/sin(x)`
Asymptotes are straight lines or curves that a graph approaches but never touches.
As a result, the graph of a curve gets closer and closer to the asymptote as it moves further away from the origin, but it never touches it.
For a function to have vertical asymptotes at `x = nπ`, the denominator of the function should equal zero. In the cosecant function, the denominator is equal to `sin(x - nπ)`.
Therefore, the vertical asymptotes are where `sin(x - nπ) = 0`.
The general form of the cosecant function is `y = A csc(B(x - C)) + D`.
The constants A, B, C, and D are used to alter the form of the graph of the cosecant function.
They can be used to alter the amplitude, period, phase shift, and vertical displacement of the graph, respectively.
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factor by using the difference of two cubes
(2x)³- 8
Answer:
\((2x + 2)( {4x}^{2} - 4x + 4)\)Solution,
\( {(2x)}^{3} - 8 \\ \)
\(( {2x)}^{3} - {(2)}^{3} \)
Use the formula:
\( {a}^{3} - {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2} )\)
now,
\((2x + 2)( {(2x)}^{2} - 2x \times 2 + {(2)}^{2} )\)
\((2x + 2)( {4x}^{2} - 4x + 4)\)
Hope this helps...
Good luck on your assignment...
can someone help? the question is attached
Answer:
A
Step-by-step explanation:
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The value of W is inversely proportional to m. If w=8 then m=25, What is m when W is 20?Show me all the steps please?
Answer:
m = 10
Step-by-step explanation:
The values of w is inversely proportional to m
Mathematically the above statement is expressed as:
w ∝ 1/m
w = k × 1/m
w = k/m
Where k is the Proportionality Constant
First step
Solve for k
If w=8 then m=25
w = k/m
8 = k/25
Cross Multiply
k = 25 × 8
k = 200
Second step
what is m when w=20? Show me the steps please
We solve for m
w = k/m
k = 200
20 = 200/m
Cross Multiply
20m = 200
m = 200/20
m = 10
Please help this is due today
Using multiplication we know that after 141 min there will be 400,000 bacteria present.
What is multiplication?One of the four fundamental arithmetic operations, along with addition, subtraction, and division, is multiplication.
A product is the output of a multiplication operation.
When you take a single number and multiply it by several, you are multiplying.
A 5 multiplied by 4 results in 20 (5 + 5 + 5 + 5).
We multiplied the number five by four times.
Multiplication is commonly referred to as "times" because of this.
So, in the given situation:
At the initial stage, the number of bacteria is: 50,000
Then, after 47 min: 50,000 * 2 = 100,000
Then, after 47 min which is after 94 min: 100,000 * 2 = 200,000
Then, after 47 min which is after 141 min: 200,000 * 2 = 400,000
Therefore, using multiplication we know that after 141 min there will be 400,000 bacteria present.
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Periodic Deposit: $? at the end of each monthRate: 7.5% compounded monthlyTime: 3 yearsFinancial Goal: $35,000O A. $2,628; $31,536 from deposits and $3,464 from interestB. $776; $27,936 from deposits and $7,064 from interestO c. $933; $33,588 from deposits and $1,412 from interestOD. $870; $31,320 from deposits and $3,680 from interest
Answer:
D. $870; $31,320 from deposits and $3,680 from interest
Explanation:
In order to calculate the monthly payment, we use the formula below:
\(P=\frac{A\mleft(\frac{r}{n}\mright)}{\mleft[\mleft(1+\frac{r}{n}\mright)^{nt}-1\mright]}\)Given:
• The Financial Goal, A= $35,000
,• Rate = 7.5% = 0.075
,• Number of compounding period = 12 (Monthly)
,• Time, t = 3 years
Substitute into the given formula:
\(\begin{gathered} P=\frac{35000\mleft(\frac{0.075}{12}\mright)}{\mleft[\mleft(1+\frac{0.075}{12}\mright)^{12\times3}-1\mright]} \\ P\approx\$870 \end{gathered}\)The monthly payment is $870.
\(\begin{gathered} \text{Total deposit}=870\times36=31,320 \\ \text{Interests}=35,000-31,320=3680 \end{gathered}\)Option D is correct.
A softball is thrown at an angle of 45° with an initial speed of 49 ft/s and an initial height
of 5 ft.
i) Write a set of parametric equations for the motion of the softball.
ii) Determine how long the softball was in the air.
iii) Determine how far the softball traveled in the air.
iv) Determine when the softball reached its maximum height.
v) Determine the maximum height reached by the softball.
Answer:
i) The horizontal and vertical components of the softball's motion can be described by the following parametric equations:
x(t) = v0x * t
y(t) = v0y * t - 1/2 * g * t^2 + h0
where v0x and v0y are the initial horizontal and vertical velocities, respectively, g is the acceleration due to gravity (32.2 ft/s^2), h0 is the initial height (5 ft), and t is time.
We can find v0x and v0y by resolving the initial velocity vector into horizontal and vertical components:
v0x = v0 * cos(45°) = 49 ft/s * cos(45°) ≈ 34.65 ft/s
v0y = v0 * sin(45°) = 49 ft/s * sin(45°) ≈ 34.65 ft/s
Substituting these values into the parametric equations, we get:
x(t) = 34.65 * t
y(t) = 34.65 * t - 16.1 * t^2 + 5
ii) The softball will be in the air until it hits the ground, which occurs when y(t) = 0. We can solve for t using the quadratic formula:
16.1 * t^2 - 34.65 * t + 5 = 0
t ≈ 2.19 s (rounded to two decimal places)
Therefore, the softball was in the air for approximately 2.19 seconds.
iii) The horizontal distance traveled by the softball can be found by evaluating x(t) at the time when the softball hits the ground:
x(2.19) ≈ 75.8 ft (rounded to one decimal place)
Therefore, the softball traveled approximately 75.8 feet in the air.
iv) The softball reaches its maximum height when its vertical velocity is zero. We can find the time when this occurs by setting v0y - g * t = 0 and solving for t:
t = v0y / g = 34.65 / 32.2 ≈ 1.08 s (rounded to two decimal places)
Therefore, the softball reaches its maximum height after approximately 1.08 seconds.
v) The maximum height reached by the softball can be found by evaluating y(t) at the time when the softball reaches its maximum height:
y(1.08) ≈
Step-by-step explanation:
A person owes $1000 on a credit card that charges an interest rate of 2% per month
Credit card balance each month:
First month: 1020 .00
Second month: 1040.4 0
Third month: 1061,208
Fourth month: 1082.43
Here we have to calculate the interest and add it to capital.
That is, 2% of 1000
First month:
Interest = 1000 (2/100)
Odds1 = 1020
Second month
Capital 1020
Interest = 1020 x 0.02 = 20.4
Odds2 = 1040.4
Third month
Capital = 1040.4
Interest = 1040.4 x 0.02 = 20.808
Odds3 = 1061,208
Fourth month
Capital = 1061,208
Interest = 1061.208 x 0.02 = 21.22
Odds = 1082.43
Therefore the credit card balance each month:
First month: 1020 .00
Second month: 1040.4 0
Third month: 1061,208
Fourth month: 1082.43
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The question is incomplete. Completed question is given below:
A person owes $1000 on a credit card that charges an interest rate of 2% per month. Complete this table showing the credit card balance each month if they do not make any payments. Month total bill in dollars11,00021,02031,040.40
What is the line of reflection?
Answer:
Y Axis
Step-by-step explanation:
The y axis is the best so it reflects off of both sides of the best axis in the world.
I need loads of help
Answer:
2 8c+3
Step-by-step explanation:
Answer:
8c+3
Step-by-step explanation:
for #2
1.sundaybought10pens,andapencost$5dollars.whatisthecostof15pensinnaira,if$1is30naira?
Answer:
Step-by-step explanation:
gnag dsewhqjhnqrhjwqkhjqrkhwq
56 dvide 9 please help me with steps
Answer: 6 your welcome :)
100 points Write a function g whose graph represents the indicated transformation of the graph of f. f(x) = (1/2)x - 5; reflection in the x-axis a g(x) = (1/2)x - 5 b g(x) = -(1/2)x + 5 c none d g(x) = -(1/2)x - 5 e g(x) = (1/2)x + 5
What is the surface area of right rectangular prism with dimensions of
4 centimeters by 4 centimeters by 6 centimeters?
6 cm
4 cm
4cm
Help asap!
Answer:
S.A of a rectangular prism is 2lh+2lw+2hw
2(4x6)+2(4×4)+2(6×4)
2(24)+2(16)+2(24)
48+32+48= 128cm²
Help me out please! Thanks
Answer:
c 25
Step-by-step explanation:
The exponents cancel out and leaves you with 5 × 5. which is 25
How did Euclid contribute to our understanding and practice of geometry?
Euclid started with a set of assumptions and used
(A. logic , B. calculations, C, experimentation)
to develop the proofs of geometric theories. He is often referred to
as (A. the custodian of logic , B. the architect of reason, C. the father of geometry)
Answer:
Euclid started with a set of assumptions and used logic to develop the proofs of geometric theories. He is often referred to as the father of geometry
Step-by-step explanation:
Answer: 1: Logic
2 : The father of geometry
Step-by-step explanation:
In each of Problems 38 through 42, a differential equation and one solution yı are given. Use the method of reduction of or- der as in Problem 37 to find a second linearly independent solution y2. . x2y" + xy' – 9y = 0 (x > 0); yı(x) = x3
A second linearly independent solution of y₂ is \(-\frac{1}{6x^3}\)
The general Equation is y" + P(x)y' + q(x)y = 0 ...............(i)
where P(x), Q(x) are continues in the internal I ≤ R.
If y₁(x) is a solution of equation 1 in I then y₁(x) ≠ 0.
Then y₂(x) = y₁(x)\(\int{\frac{e^{-\intP(x)dx}}{(y_{1}x)^2}}dx\) is another solution.
The differential equation is x²y" + xy' – 9y = 0 where x > 0.
As y₁(x) = x³ is one solution of differential equation.
Divide throughout by (x²) to given differential equation.
1/x² (x²y" + xy' – 9y = 0)
y" + (y'/x) – (9/x²)y = 0 ................(ii)
By comparing equation (i) & (ii) we get:
p(x)=1/x , q(x)= –are continuous for x>0
So, another solution,
y₂(x) = y₁(x)\(\int{\frac{e^{-\intP(x)dx}}{(y_{1}x)^2}}dx\)
Now putting the values of P(x) And Q(x)
y₂(x) = \(x^3\int\limits {\frac{e^{\int(1/x)dx} }{(x^3)^2}} \, dx\)
y₂(x) = \(x^3\int\limits {\frac{\frac{1}{x} }{x^6} }} \, dx\)
y₂(x) = \(x^3\int\limits {\frac{1}{x^7} }} \, dx\)
y₂(x) = \(x^3\int\limits {x^-7} } \, dx\)
y₂(x) = \(x^3\left[\frac{x^{-7+1}}{-7+1}\right]\)
y₂(x) = \(-\frac{1}{6}(x^3\times x^{-6})\)
y₂(x) = \(-\frac{1}{6x^3}\)
So, the answer of this question is \(-\frac{1}{6x^3}\).
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use the holt's method with smoothing constants of 0.3 for alpha and 0.6 for gamma. find the equation of the forecast line and the mse for this method. if required, round your answers to two decimal places.
To use Holt's method with smoothing constants of 0.3 for alpha and 0.6 for gamma, we first need to calculate the initial values for the level and slope.
Let L0 be the initial level and B0 be the initial slope. We can estimate these using the following equations:
L0 = y1
B0 = y2 - y1
where y1 and y2 are the first two observed values in the time series.
Once we have the initial values, we can use the following recursive equations to calculate the level and slope at each time period t:
Lt = alpha * yt + (1 - alpha) * (Lt-1 + Bt-1)
Bt = gamma * (Lt - Lt-1) + (1 - gamma) * Bt-1
where yt is the observed value at time t.
Using these equations and the given smoothing constants, we can find the equation of the forecast line as:
Ft+1 = Lt + Bt
and the mean squared error (MSE) as:
MSE = (1 / n) * sum((yt - Ft)^2)
where n is the number of observed values.
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Select the examples below that have a net torque of zero about the axis perpendicular to the page and extending from the center of the
In general, any symmetrical object will have a net torque of zero if the axis of rotation is through its center of mass.
It seems that the list of examples is missing from your question, so I'll provide a general explanation of situations where the net torque is zero. Please feel free to provide a list of examples for a more specific answer.
A net torque of zero about an axis perpendicular to the page and extending from the center means that the total clockwise torque is equal to the total counterclockwise torque. This can occur when:
1. There are no external forces acting on the system, so there is no torque.
2. The external forces are acting along the line of the axis, causing no rotation and hence no torque.
3. The clockwise and counterclockwise torques cancel each other out, resulting in a net torque of zero.
Some examples of objects that have a net torque of zero about the axis perpendicular to the page and extending from the center of the object are a sphere, a cube, a cylinder, and a cone.
Please provide the list of examples you'd like me to evaluate, and I'll be glad to help you determine which have a net torque of zero.
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if the mpc = 4/5, then the government purchases multiplier is a. 20. b. 5/4. c. 4/5. d. 5.
If the marginal propensity to consume(mpc) = 4/5 then the government purchases multiplier is 5. Therefore, the answer is (d) 5.
What is the marginal propensity to consume(mpc)?The marginal propensity to consume (MPC) is the fraction of each additional unit of income that is spent on consumption. In other words, it is the change in consumption that results from a one-unit change in income.
What is a government purchase multiplier?The government purchases multiplier is a measure of the impact that changes in government purchases of goods and services have on the overall economy. It is the ratio of the change in the equilibrium level of real GDP to the change in government purchases.
According to the given informationThe government purchases multiplier (K) is calculated using the formula:
K = 1 / (1 - MPC)
where MPC represents the marginal propensity to consume.
In this case, the MPC is given as 4/5, so we can substitute this value into the formula:
K = 1 / (1 - 4/5)
= 1 / (1/5)
= 5
Therefore, the government puchases multiplier is 5. Therefore, the answer is (d) 5.
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In a right triangle, angle C measures 40°. The hypotenuse of the triangle is 10 inches long. What is the approximate length of the side adjacent to angle C? 6. 4 inches 7. 7 inches 8. 4 inches 13. 1 inches.
Answer:
the answer is c uwU
Step-by-step explanation:
Here, base is the length of the side adjacent to angle and hypotenuse is the longest side of the right angle triangle.
The length of the side adjacent to angle C is 7.67 inches or 7.7 inches. Option B shows the correct length of the side adjacent to angle C.
What is a right-angle triangle?A right triangle or right-angled triangle is a triangle in which one angle is a right angle i. e. 90 degrees. The relation between the sides and other angles of the right triangle is the basis for trigonometry.
Given that in a right triangle, angle C measures 40°. The hypotenuse of the triangle is 10 inches long.
The attachment shows the right-angle triangle. In the triangle, hypotenuse AC = 10 inches and angle C = 40 degrees.
We need to find the value of BC.
We know that, in a right-angle triangle,
\(cos C = \dfrac {BC}{AC}\)
\(cos 40^\circ = \dfrac {BC}{10}\)
\(BC = 10 \times cos 40^\circ\)
\(BC = 7.67 \;\rm Inches\)
Hence we can conclude that the length of the side adjacent to angle C is 7.67 inches or 7.7 inches. Option B shows the correct length of the side adjacent to angle C.
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WILL GET BRAINLIEST!!!! I NEED IT BY TODAY!!!
NO FAKE ANSWERS!!!!
Answer:
d
Step-by-step explanation:
shades 2 out of 5 . 2/5 equals 0.40 shades 40% of 100.
with slope = 5/6, through (22, 12) with slope intercept form
The point-slope equation of something like the line, with slope equal to 5/6 but instead passing through the point at(22 , 12), is:
(y - 12) = 5/6(x - 22).
The equation of a line describe as:A line's equation can be stated in three different ways:
standard formslope-intercept formpoint-slope form.The typical form of a line equation is ax + by = c, where a but rather b are the coefficients of variables x and y, respectively, as well as c is a constant if all possible values must be integers. In the meantime, the slope-intercept form is given by the formula y = mx + b, where m is the line's slope as well as b is the y-intercept. Given the slope m and a point on the line (x, y), we can formulate the equation using point-slope form, (y - y1) = m. (x - x1).
According to the given data:To build up the equation, use the point slope form and enter in the values.
(y - y1) = m(x - x1)
where;
m = 5/6
(x1 , y1) = (22 , 12)
(y - 12) = 5/6(x - 22)
In slope-intercept form, the equation of the line is:
(y - 12) = 5/6(x - 22)
y - 12 = 5/6 x - 110/6
y = 5/6 x - 19/3
In standard form, the equation of the line is:
y = 5/6 x - 19/3
5/6 x - y = 19/3
Multiplying both sides by 6,
5x - 6y = 38.
The point-slope equation of something like the line, with slope equal to 5/6 but instead passing through the point at(22 , 12), is:
(y - 12) = 5/6(x - 22).
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Javier jogs 3/4 of a mile in 8 1/2 minutes how much minutes will it take him to jog 1 mile?
Answer:
11 minutes and 20 seconds. or 11.33
Step-by-step explanation:
Reciprocal of .75 is 1.33. Multiply 1.33 times 8.5 minutes to find how long it would take to run one mile.
or
Divide 8.5 minutes by 3 to find how long it takes to run 1/4 of a mile, and multiply that time by 4 to see how long it takes to run one mile.
Find the equation that intersects the x-axis at point (3, 0) and
intersects the y-axis at
point (0, 5). Then sketch the diagram.
The equation of the line that intersects the x-axis at point (3, 0) and intersects the y-axis at point (0, 5) is y = (-5/3)x + 5.
To find the equation of a line that intersects the x-axis at point (3, 0) and intersects the y-axis at point (0, 5), we can use the slope-intercept form of a linear equation, which is y = mx + b. Given the point (3, 0) on the x-axis, we know that when x = 3, y = 0. This gives us one point on the line, and we can use it to calculate the slope (m).
Using the slope formula: m = (y2 - y1) / (x2 - x1)
Substituting the values (0 - 5) / (3 - 0) = -5 / 3
So, the slope (m) is -5/3. Now, we can substitute the slope and one of the given points (0, 5) into the slope-intercept form (y = mx + b) to find the y-intercept (b).
Using the point (0, 5):
5 = (-5/3) * 0 + b
5 = b
The y-intercept (b) is 5. Therefore, the equation of the line that intersects the x-axis at point (3, 0) and intersects the y-axis at point (0, 5) is:
y = (-5/3)x + 5
To sketch the diagram, plot the points (3, 0) and (0, 5) on the x-y plane and draw a straight line passing through these two points. This line represents the graph of the equation y = (-5/3)x + 5.
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WILL GIVE BRAINLIST!
Answer:
x=60
Step-by-step explanation:
Answer: The equation 60 + x= 3x -70 could be set up to solve for x.
Step-by-step explanation:
The two remote interior angles sums will equal to the exterior angle .
Meaning that angle 60 plus angle x has to equal to angle 3x -70.
60 + x= 3x -70 Now solve for x by adding 70 to both sides
+70 +70
130 + x = 3x Now subtract x from both sides
-x -x
130 = 2x Divide both sides by
x = 65
__________ is the IV and ____________ is the DV.
a. Gender: GSR
b. GSR: gender
c. Gender : Time
d. Breast feeding: GSR
Gender is the independent variable (IV) and Galvanic Skin Response (GSR) is the dependent variable (DV). This means that you are investigating how differences in gender might affect the GSR.
So, the correct is A. Gender: GSR
What's meant by Gender and GSRGender, as the IV, refers to the classification of individuals as male, female, or other, while GSR, as the DV, is a physiological measure of emotional arousal, often used in psychological research.
By examining the relationship between these two variables, you aim to determine whether variations in gender have any impact on GSR levels.
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What is the magnitude of ?
V
(9,-4)
Answer:
The magnitude is sqrt((-4)^2 + (-9)^2) = 9.85. The angle is atan(-9/-4) = 180 deg + 66 deg = 246 deg = -114 deg.
Step-by-step explanation:
hope it help
Answer:
9.85
Step-by-step explanation:
|v|= √9²+(-4)²
=√81+16
=√97
|v|= 9.85