.The fee to check luggage with a
new airline is based on the weight
of each bag. Brett paid $7.14 to
check a 42-pound bag. How
much will Eileen pay if her bag
weighs 63 pounds?

The value x in the secant line using the Intersecting btheorem is 19.

Intersecting secants theorem states that " If two secant line segments are drawn to a circle from an exterior point, then the product of the measures of one  of secant line segment and its external secant line segment is the same or equal to the product of the measures of the other secant line segment and its external line secant segment.

From the image;

External line segement of the first secant line = 8

First sectant line segment = ( x + 8 )

External line segement of the second secant line = 9

First sectant line segment = ( 15 + 9 )

Using the Intersecting secants theorem:

8 ×  ( x + 8 ) = 9 × ( 15 + 9 )

Solve for x:

8x + 64 = 135 + 81

8x + 64 = 216

8x = 216 - 64

8x = 152

x = 152/8

x = 19

Therefore, the value of x is 19.

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Answer:

30

Step-by-step explanation:

each or those boxes is 5. so Thursday is 35 boxes. and Tuesday is 5. so 35-5 is 30

Answer:30

Step-by-step explanation:Thursday had 35 lunches eaten and Tuesday only had 5 so there being there was a difference of 30

The features needed to describe a rotation are Center, Direction and Angle

From the question, we have the following parameters that can be used in our computation:

The key features

From the key features, the terms that describe rotation are:

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Answer: 5

Step-by-step explanation: A cube has all lengths equal.

Volume is 125 find the cube root

Answer:

\(Area = 60x - x^2\)

Step-by-step explanation:

Given

\(Perimeter = 120\)

\(Side\ 1 = x\)

Required

The area of the garden

First, we calculate the length of the other side using:

\(Perimeter = 2 *(Side\ 1 + Side\ 2)\)

This gives:

\(120 = 2 *(x + Side\ 2)\)

Divide both sides by 2

\(60 = x + Side\ 2\)

Make Side 2 the subject

\(Side\ 2 = 60 - x\)

So, the area of the garden is:

\(Area = Side\ 1 * Side\ 2\)

\(Area = x * (60 - x)\)

Expand

\(Area = 60x - x^2\)

Answer:

x = 12

y = -2

Step-by-step explanation:

In a parallelogram, the sides opposite each other are equal.

Hence: PQ = SR and PS = QR

2x + 12 = 4x - 12

Rearrange to make x's on one side and the numbers on the other

4x - 2x = 12 + 12

2x = 24

x = 12

____________

y + 25 = 6y + 35

Rearrange to make y's on one side and the numbers on the other

6y - y = 25 - 35

5y = -10

y = -2

Answer:

please see detailed answers below

Step-by-step explanation:

a) there are one hunred squares in total.

there are 10 + 9 = 19 white (unshaded) ones.

so there are 100 -19 = 81 shaded ones.

(81/100) X 100 = 81%.

81% of 72, 200

= (81/100) X 72, 200

= 0.81 X 72, 200

= 58, 482

b) there are 5 equal rectangles. they make up a whole (ie 100%)

the shaded part (1 rectangle) = 100/5 = 20%.

for what? :)  .

...................

We can conclude after answering the presented question that Use the equation data to discover potential for process changes that might result in a reduction in the time necessary to perform the activity.

An equation in mathematics is a statement that states the equality of two expressions. An equation is made up of two sides that are separated by an algebraic equation (=). For example, the argument "2x + 3 = 9" asserts that the phrase "2x + 3" equals the number "9". The purpose of equation solving is to determine the value or readings of the variable(s) that will allow the equation to be true. Equations can be simple or complicated, regular or nonlinear, and include one or more elements. In the calculation "x2 + 2x - 3 = 0," for example, the variable x is raised to the second power. Lines are utilised in many different areas of mathematics, such as algebra, calculus, and geometry.

The procedures that a manufacturing organisation might take to undertake a time study analysis are as follows:

List the tasks performed by the workers and describe what constitutes a complete unit of labour.

Choose a representative sample of employees to observe. The sample size should be high enough to be statistically significant, but not so large that observing all workers becomes unfeasible.

Use the data to discover potential for process changes that might result in a reduction in the time necessary to perform the activity.

By doing a time study analysis, the manufacturing organisation may acquire useful insights into their workers' productivity and find chances for process changes that will help them fulfil the rising demand for their products.

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A weather front is a transition zone between two different air masses at the Earth's surface. Each air mass has unique temperature and humidity characteristics.

The following is an assembly program that calculates the value of the given polynomial, assuming signed integers x and y are stored in register r2 and r3, respectively.

\(```.LIST.ALIGN 4    .GLOBAL _start_start:    PUSH {R4, R5, LR}\)
   \(MOV R4, R2        // R4 < - x    MOV R5, #2        // R5 < - 2\)\(MUL R4, R4, R4    // R4 < - x^2    MUL R4, R4, R5    // R4 < - 2x^2    MOV R5, #3        // R5 < - 3\)
  \(ADD R4, R4, R5, LSL #16    // R4 < - 2x^2 + 3x^2    MOV R5, #5        // R5 < - 5    MUL R5, R5, R2    // R5 < - 5x\)
  \(SUB R4, R4, R5, LSL #16    // R4 < - 2x^2 + 3x^2 - 5x    MOV R5, #11       // R5 < - 11    SUB R4, R4, R5, LSL #16    // R4 < - 2x^2 + 3x^2 - 5x - 11\)
  \(MOV R3, R4        // R3 < - y    POP {R4, R5, PC}.END```\)

Explanation: The polynomial is given as

\(`y = 2x^4 + 3x^2 - 5x - 11`.\)

To calculate this polynomial in assembly language, we need to perform the following steps:

Load the value of `x` into a register. We assume that `x` is stored in register `r2`.

Calculate \(`2x^2`\) and add \(`3x^2`\) to it. We first square the value of `x` by multiplying it with itself and then multiply it with `2`. We then add \(`3x^2`\) to this result. We store this result in register `r4`.

Calculate `5x` and subtract it from the result of step 2. We first multiply the value of `x` with `5` and then subtract it from the result of step 2. We store this result in register `r4`.

Subtract `11` from the result of step 3. We subtract `11` from the result of step 3 and store this result in register `r4`.

Load the value of `y` into a register. We assume that `y` is stored in register `r3`.

Return from the subroutine. We pop the registers from the stack and return from the subroutine.

The assembly program that is used to calculate the value of a given polynomial assuming signed integers x and y are stored in registers r2 and r3, respectively. The polynomial given is\(y = 2x4 + 3x² - 5x - 11\). In this assembly program, we load the value of x into a register, calculate 2x^2, add 3x^2 to it, subtract 5x from the result, and subtract 11 from the final result. The value of y is then stored in a register, and we return from the subroutine.

This assembly program is designed for 32-bit ARM architecture, and it can be run on any ARM processor. The program is written in ARM assembly language, which is a low-level programming language used to write programs that run on ARM processors. It is a complex language that requires a deep understanding of the processor architecture and instruction set.

In conclusion, the assembly program presented here can be used to calculate the value of a given polynomial using signed integers x and y stored in registers r2 and r3, respectively. This program can be adapted to calculate other polynomials or perform other arithmetic operations on ARM processors. It is a powerful tool for low-level programming and optimization, but it requires a significant amount of expertise to write and debug.

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Answer:

25.5

Step-by-step explanation:

first pyramid: 6*8.5

second pyramid: 3 (half the length of the first) *8.5

3*8.5 = 25.5

Answer:

25.5

Step-by-step explanation:

There are multiple squares you need to find the area of each one by finding the area of each square then adding them together to get the surface area.

Answer:

$0.64

Step-by-step explanation:

Unit price is the cost of a single metre of ribbon

5.12/8=0.64

Answer:

Step-by-step explanation:

The equation of the line is y = 0.75x - 2

Linear equations are equations that have constant average rates of change. Note that the constant average rates of change can also be regarded as the slope or the gradient

A system of linear equations is a collection of at least two linear equations.

In this case, the linear equation has the following points

(8, 4) and (-8, -8)

Calculate the slope of the line using:

m = (y2 - y1)/(x2 - x1)

This gives

m = (-8 - 4)/(-8 - 8)

Evaluate

m = 0.75

The linear equation is then calculated as:

y = m(x - x1) + y1

This gives

y = 0.75(x - 8) + 4

Evaluate the bracket

y = 0.75x - 6 + 4

Evaluate the sum

y = 0.75x - 2

Hence, the equation of the line is y = 0.75x - 2

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Answer:

(0, -3, 2)

(0, -3, 0)

(-4, 0, 2)

Corner where 2 or more edges meet.

If the length of the diagonals are equal, then the vertices of a rhombus will form a square. Formula used: We will use the formula of distance between two points which is given

\(\[d = \sqrt {{{({x_2} - {x_1})}^2} + {{({y_2} - {y_1})}^2}} \], where \[({x_1},{y_1})\] and \[({x_2},{y_2})\]\)

be the two points.

Answer:

To regroup means to rearrange groups in place value to carry out an operation.

 we need to determine the quantities of each type of bean required. To make 18 oz. of Julio's premium coffee blend, you would need 10 oz. of arabica coffee beans and 8 oz. of robusta coffee beans.

Let's denote the number of ounces of arabica coffee beans as 'x' and the number of ounces of robusta coffee beans as 'y'.
According to the given information, the cost of arabica coffee beans is $7/oz and the cost of robusta coffee beans is $9/oz. We also know that the total number of ounces in Julio's premium coffee blend is 18 oz.
To find the number of ounces of arabica and robusta coffee beans required, we can set up a system of equations based on the cost and the total number of ounces:
Equation 1: Cost of arabica coffee beans = $7/oz * x
Equation 2: Cost of robusta coffee beans = $9/oz * y
Equation 3: Total number of ounces = x + y = 18 oz
Since we want to find the number of ounces of each type of coffee beans, we can solve this system of equations.
From Equation 3, we have x + y = 18. Rearranging this equation, we get y = 18 - x.
Substituting this into Equation 2, we have the cost of robusta coffee beans as $9/oz * (18 - x).
Equating the cost of arabica and robusta coffee beans, we get:
$7/oz * x = $9/oz * (18 - x)
Solving this equation will give us the value of x, which represents the number of ounces of arabica coffee beans. Then, substituting this value into the equation y = 18 - x will give us the number of ounces of robusta coffee beans.
Let's solve the equation:
7x = 9(18 - x)
7x = 162 - 9x
16x = 162
x = 10.125
Since we cannot have a fractional number of ounces, we round x down to 10 oz.
Substituting this value into y = 18 - x, we get y = 8 oz.
Therefore, to make 18 oz. of Julio's premium coffee blend, you would need 10 oz. of arabica coffee beans and 8 oz. of robusta coffee beans.

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The period of the given degree-4 LFSR with the polynomial p(x) = x^4 + x^2 + 1 and the seed (s3, s2, s1, s0) = 0110 is 15.

A Linear Feedback Shift Register (LFSR) is a deterministic algorithm that generates a pseudo-random sequence of numbers based on a polynomial function and an initial seed. The period of an LFSR is the length of the generated sequence before it repeats itself. In this case, the polynomial is p(x) = x^4 + x^2 + 1, and the seed is (s3, s2, s1, s0) = 0110. To find the period, we iterate through the LFSR sequence and count the steps until the seed is repeated. In this specific case, after iterating 15 times, the seed (0110) is repeated.

Thus, given the degree-4 LFSR with polynomial p(x) = x^4 + x^2 + 1 and seed (s3, s2, s1, s0) = 0110, the period of the generated sequence is 15.

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Answer:

x = 3

Step-by-step explanation:

First, you should put what is shown into an equation, which would be:

x + x + x + x + x + 2 = 17 or 5x + 2 = 17

Next, you subtract by two on both sides o the equation to isolate the variable x:

5x = 15

Now, you can divide by five on both sides to find the actual value of x:

x = 3

Hope this helped somewhat! :)

Valeria cannot cut any 23-foot pieces from the 9-foot ribbon. The length of the leftover piece of ribbon will be equal to the original length of the ribbon, which is 9 feet.

Valeria bought a 9-foot length of ribbon and wants to cut 23-foot pieces from it. We need to determine how many pieces she can cut and the length of the leftover piece of ribbon.

To find out how many 23-foot pieces Valeria can cut, we need to divide the length of the ribbon by the length of each piece. The calculation is as follows:

9 feet ÷ 23 feet = 0.39130434782

Since we can't have a fraction of a piece, Valeria can only cut 0 whole pieces. Therefore, she cannot cut any 23-foot pieces from the 9-foot ribbon.

As for the length of the leftover piece of ribbon, we need to subtract the total length of the cut pieces from the original length of the ribbon. In this case, since Valeria cannot cut any 23-foot pieces, the length of the leftover piece will be equal to the original length of the ribbon.

Hence, the length of the leftover piece of ribbon is 9 feet.

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we use the definition of supplementary angles again to conclude that ∠3 and ∠5 are supplementary.

To prove that ∠3 and ∠5 are supplementary, we can use the following steps:

Given: w ∥ x and y is a transversal.

∠1 ≅ ∠5 by the corresponding angles postulate.

By definition, ∠3 and ∠1 are a linear pair, so they are supplementary.

Therefore, m∠3 + m∠1 = 180 by the definition of supplementary angles.

Substituting m∠5 for m∠1, we get m∠3 + m∠5 = 180.

Therefore, by the definition of supplementary angles, ∠3 and ∠5 are supplementary.

In step 1, we use the corresponding angles postulate, which states that when two parallel lines are cut by a transversal, the pairs of corresponding angles are congruent. In step 2, we use the definition of a linear pair, which states that when two angles form a line, they are supplementary. In step 3, we use the definition of supplementary angles, which states that the sum of two supplementary angles is 180 degrees. In step 4, we substitute m∠5 for m∠1, since we know that ∠1 ≅ ∠5. Finally, in step 5, we use the definition of supplementary angles again to conclude that ∠3 and ∠5 are supplementary.

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The trapezoid's area can be understood as triangle a + triangle b. So, we write these triangles as an expression, and, since we cannot solve with no values, we simplify to prove the area of the trapezoid.

A triangle's area is 1/2bh. In their case, b is represented as b or a depending on the triangle.

t = 1/2ah + 1/2bh

Now, since both expressions use the terms 1/2 and h, distributed onto a second variable, it can be rewritten as a single expression where both are distributed onto both variables at the same time. This is because both terms being multiplied by something separately is the same as combining both terms and multiplying them both at the same time.

t = 1/2(a)h + 1/2(b)h
t = 1/2(a + b)h

Answer:

x = 24

Step-by-step explanation:

if a and b are parallel then

62 and 5x - 2 are same- side interior angles and sum to 180° , that is

5x - 2 + 62 = 180

5x + 60 = 180 ( subtract 60 from both sides )

5x = 120 ( divide both sides by 5 )

x = 24

thus for a to be parallel to b , then x = 24

So, the gradient vector field of f is (∇f) = (cos(5y/z), -5x sin(5y/z)/z, 5xy sin(5y/z)/z^2).

To find the gradient vector field of the function f(x, y, z) = x cos(5y/z), we need to calculate the partial derivatives with respect to each variable and combine them into a vector.

The gradient vector is defined as:

∇f = (∂f/∂x, ∂f/∂y, ∂f/∂z)

Taking the partial derivatives of f(x, y, z) with respect to each variable:

∂f/∂x = cos(5y/z)

∂f/∂y = -5x sin(5y/z)/z

∂f/∂z = 5xy sin(5y/z)/z^2

Putting these partial derivatives together, we have:

∇f = (cos(5y/z), -5x sin(5y/z)/z, 5xy sin(5y/z)/z^2)

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Step-by-step explanation:

so, working together, in 1 day 1/10 + 1/15 of the work is done.

how many days (x) until we get 1/1 of the work done ?

x × (1/10 + 1/15) = 1

x × (3/30 + 2/30) = 1

x × 5/30 = 1

x×5 = 30

x = 30/5 = 6

so, together, they will finish the work in 6 days.

Answer:

32.674/0.016 = 2042.125

Step-by-step explanation:

3.825/0.24 = 15.3

1. The 32.674 divided by 0.016 gives 2042.125.

2. The 3.825 divided by 0.25 gives 15.3

When 'a' is divided by 'b', then the result we get from the division is the part of 'a' that each one of 'b' items will get.

Thus, if 10 mangoes are there, and 2 people, then 10 ÷ 2 is the number of mangoes each person would get, which is 5.

Division interpreted as equally dividing the number that is being divided in total x parts; where x is the number of parts the given number is divided.

Thus,  \(a \div b = a\) divided in b equal parts.

1. 32.674 divided by 0.016

32.674 / 0.016 = 2042.125

The 32.674 divided by 0.016 gives 2042.125.

2. 3.825 divided by 0.25

3.825 / 0.25 = 15.3

The 3.825 divided by 0.25 gives 15.3

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Given:

Arear of rectangular rug = 48 sq. feet.

The rug is 8 feet longer than it is wide.

To find:

The width of the rug.

Solution:

Let x feet be the width of the rug.

The rug is 8 feet longer than it is wide.

Length of the rug = (x+8) feet

Area of a rectangle is

\(Area=Length\times Width\)

Arear of rectangular rug is 48 sq. feet.

\(48=(x+8)\times x\)

\(48=x^2+8x\)

\(0=x^2+8x-48\)

Splitting the middle term, we get

\(x^2+12x-4x-48=0\)

\(x(x+12)-4(x+12)=0\)

\((x+12)(x-4)=0\)

Using zero product property, we get

\((x+12)=0\text{ and }(x-4)=0\)

\(x=-12\text{ and }x=4\)

Width cannot be negative. So, \(x=4\).

Therefore, the width of the rug is 4 feet.