The energy transferred from the water in the kettle to the surroundings in 2 hours is
46 200 J.

The mass of water in the kettle is 0.50 kg.

The specific heat capacity of water is 4200 J/kg °C.

The initial temperature of the water is 100 °C.

Calculate the average power output from the water in the kettle to the surroundings in 2 hours​

The axial resistance of an axon is calculated using the formula R = ρL/A, where ρ is the resistivity, L is the length, and A is the cross-sectional area. In this case, the axial resistance is 11.28 MΩ.

The resistance along the axon is calculated using the following formula:

R = ρL/A

where:

R is the resistance in ohms

ρ is the resistivity in ohms per meter

L is the length in meters

A is the cross-sectional area in meters squared

In this case, we have:

ρ = 1.6 x 107 Ω.m

L = 0.5 mm = 0.0005 m

A = πr² = π(5 x 10-6)² = 7.854 x 10-13 m²

Therefore, the resistance is:

R = ρL/A = (1.6 x 107 Ω.m)(0.0005 m) / (7.854 x 10-13 m²) = 11.28 MΩ

Therefore, the axial resistance of the axon is 11.28 MΩ.

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(a) The potential at all points on the z-axis can be determined by integrating the contribution from each charged ring of the annulus.

(b) The electric field at all points on the z-axis can be obtained by differentiating the potential.

(c) Taking the limit as a approaches 0 and b approaches infinity, the electric field matches that of an infinite plane sheet of charge.

(d) With given values, the potential at the origin can be calculated using the expression obtained in part (a).

(e) The ultimate speed of the particle can be determined by conserving mechanical energy, equating the initial potential energy to the final kinetic energy.

(a) To determine the potential at all points on the z-axis, we can integrate the contribution to the potential from each infinitesimally charged ring of the annulus. The potential due to an infinitesimally charged ring at a distance z is given by:

dV = (k * dq) / sqrt(r^2 + z^2)

where k is the electrostatic constant, dq is the charge element on the ring, and r is the radial distance from the ring to the point on the z-axis. Since the charge density is uniform, dq = o * dA, where dA is the area element of the ring.

For an annulus with inner radius a and outer radius b, the area element is dA = 2πr * dr, where r is the radial distance from the origin to the ring. Thus, the potential contribution from each ring is:

dV = (k * o * 2πr * dr) / sqrt(r^2 + z^2)

To find the total potential at a point on the z-axis, we integrate this expression over the range of radii from a to b:

V = ∫[(k * o * 2πr * dr) / sqrt(r^2 + z^2)] (from r = a to r = b)

(b) The electric field at a point is the negative gradient of the potential. Therefore, we can differentiate the potential obtained in part (a) with respect to z to find the electric field at all points on the z-axis.

(c) To show that in the limit as a approaches 0 and b approaches infinity, the electric field reproduces the result for an infinite plane sheet of charge, we need to compare the expressions for the electric field obtained in part (b) with the known electric field expression for an infinite plane sheet of charge.

(d) To find the potential at the origin, we can substitute the given values of a, b, and the total charge on the annulus into the potential expression obtained in part (a).

(e) To determine the ultimate speed of the particle, we need to consider the conservation of mechanical energy. Since the particle is projected along the z-axis, the initial kinetic energy is zero. The final kinetic energy is given by:

K = (1/2) * m * v^2

where m is the mass of the particle and v is its speed. The potential energy at the origin is given by:

U = q * V

where q is the charge of the particle and V is the potential at the origin. By conserving mechanical energy, we can equate the initial potential energy to the final kinetic energy and solve for v.

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Answer:

b) resistance

Explanation:

since resistance is responsible for heating, if it increases the circuit breaker opens breaking the flow of current to the circuit and thus preventing short circuits.

Answer:

0.675 kg m/s

Explanation:

Momentum = mass x velocity

= 0.015 x 45 = 0.675 kg m/s

P.S. I'm not sure of this answer,  so it might be a good idea to check this with some other sources.

Change in momentum  = 0.675 kg m/s

Momentum  is a  property of a moving body that the body has by virtue of its mass and motion and that is equal to the product of the body's mass and velocity

change in momentum = final momentum - initial momentum

final momentum  = m*v = 0.015 *  45 = 0.675 kg m/s

initial momentum = m* v = 0.015 * 0 = 0

change in momentum  = 0.675 kg m/s

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1.44*10^-3N  is the force on each other. when 33 centimeters separates one charge from another charge. They both have charges of 1.2 x 10-5 coulombs.

Charge on the first sphere, q 1​ =1.2 x 10^-5  C

Charge on the second sphere, q 2 =1.2 x 10^-5  C

Distance between the spheres, r=30cm=0.3m

F= 4πε

​ q 1 q 2/  r2

​Where, ε 0

​ = Permittivity of free space 4πε 0

=9×10^9Nm2

F= (0.33) 2

1.2 x 10^-5 * 1.2 x 10^-5  C = 1.44*10^-3N

Hence, force between the two small charged spheres is 1.44*10^-3N.

The charges are of same nature. Hence, force between them will be repulsive.

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If the outside temperature is 35°c, what is the temperature in kelvin will be 308.15 K.  

To convert a temperature from degrees Celsius to Kelvin, we add 273.15 to the Celsius value. In this case, to convert the outside temperature of 35°C to Kelvin:

35°C + 273.15 = 308.15 K

Therefore, the temperature in Kelvin is 308.15 K.

The correct option is b) 308 K. It is important to remember that Kelvin is an absolute temperature scale where 0 K represents absolute zero, the point at which all molecular motion theoretically stops. Adding 273.15 to a temperature in Celsius brings it to the equivalent value on the Kelvin scale.

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Answer:

1. True

2. False

3. True

4. True

5. False

Projectile motion is the motion of an object that is thrown or launched into the air and then moves under the force of gravity. The angle at which the ball leaves the ground is an important factor in determining its trajectory and ultimately its landing point.

In order to determine the angle at which the ball leaves the ground, we need to use the parametric equations for projectile motion, which describe the motion of the object in terms of its x and y coordinates as functions of time. These equations are:

x = v0 cosθ t
y = v0 sinθ t - 1/2 gt²

where v0 is the initial velocity of the object, θ is the angle at which it is launched, t is time, and g is the acceleration due to gravity.

From these equations, we can see that the angle at which the ball leaves the ground affects both its horizontal and vertical motion. If the angle is too low, the ball will not travel far enough horizontally, while if the angle is too high, the ball will not travel far enough vertically.

To determine the optimal angle for maximum distance, we can use calculus to find the maximum of the function:

D(θ) = (v0²/g) sin 2θ

where D is the total distance traveled by the ball.

Taking the derivative of this function with respect to θ and setting it equal to zero, we find that the optimal angle is:

θ = 45 degrees

The optimal angle for maximum distance is 45 degrees, which means that the ball should be launched at an angle of 45 degrees in order to travel the farthest distance possible.

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To find the angle at which the ball leaves the ground using parametric equations for projectile motion, you will need information such as the initial velocity, launch height, and maximum height or range of the projectile.

Parametric equations for projectile motion can be defined as:
x(t) = v0x * t
y(t) = v0y * t - 0.5 * g * t^2
where x(t) and y(t) represent the horizontal and vertical positions of the projectile at time t, v0x and v0y are the initial horizontal and vertical velocities, and g is the acceleration due to gravity. To find the launch angle, you can use the equation:
tan(θ) = v0y / v0x
However, without specific information provided about the situation, it's impossible to determine the exact angle.

Hence,  To find the angle at which the ball leaves the ground in a projectile motion situation, you will need additional information such as initial velocity, launch height, and maximum height or range. Once you have this information, you can use the parametric equations for projectile motion to calculate the angle.

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Answer:

V=IR

5. = 2× RESISTANCE

RESISTANCE=5/2

=2.5 Ohms

The chance detection of photons from unrelated annihilation events within the coincidence timing window is called accidental coincidences.

Accidental coincidences refer to the random occurrence of photon detections that are not related to the event being studied. Accidental coincidences can occur when two unrelated annihilation events happen close together in time, causing photons from both events to be detected within the coincidence timing window.

This can happen due to background radiation or other sources of noise in the detection system. To understand accidental coincidences, let's consider an example. Imagine a scenario where researchers are studying the decay of a radioactive substance.

They use a detection system that can detect photons emitted during the decay process. However, there may be instances where unrelated decays occur simultaneously or very close in time. In such cases, photons from these unrelated decays can be detected within the coincidence timing window, leading to accidental coincidences.

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Answer:

h = 3.1 cm

Explanation:

Given that,

The volume of a oil drop, V = 10 m

Radius, r = 10 m

We need to find the thickness of the film. The film is in the form of a cylinder whose volume is as follows :

\(V=\pi r^2 h\\\\h=\dfrac{V}{\pi r^2}\\\\h=\dfrac{10}{\pi \times 10^2}\\\\h=0.031\ m\\\\h=3.1\ cm\)

So, the thickness of the film is equal to 3.1 cm.

Cis-1,2-dimethylcyclopropane, a cyclic organic compound with two methyl groups attached to the same carbon atom on the cyclopropane ring, would exhibit two distinct signals in its 1H NMR spectrum.

This is because the two methyl groups are in different chemical environments due to the ring strain of the cyclopropane structure.

The hydrogen atoms on the methyl groups experience different local magnetic environments, leading to distinct resonance frequencies and separate peaks in the NMR spectrum.

Thus, cis-1,2-dimethylcyclopropane would display two 1H NMR signals, reflecting the presence of two chemically distinct hydrogen environments in the molecule.

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Answer:

Measure the length of a number of waves then divide by the number of waves to calculate the wavelength. wavelength. Count the number of waves passing a point in ten seconds then divide by ten to record frequency. Calculate the speed of the waves using: wave speed = frequency × wavelength.

The final temperature of the sample in degrees Fahrenheit when the desired temperature increase has been achieved is `123.78°F.`

The initial temperature of the sample is 62.4 °F. The boss instructs us to raise the temperature by 34.1°C. We need to determine the final temperature of the sample. Here's how we can do it.

Step 1: Use the conversion formula for Celsius to Fahrenheit.

C = (F - 32) x 5/9F = (C x 9/5) + 32where C is the temperature in Celsius and F is the temperature in Fahrenheit.

Step 2: Convert the initial temperature of the sample from Fahrenheit to Celsius.

C = (F - 32) x 5/9`C = (62.4 - 32) x 5/9``C = 16.89`°C The initial temperature of the sample is 16.89°C.Step 3: Add 34.1°C to the initial temperature of the sample to obtain the final temperature in Celsius. Final temperature in Celsius = 16.89 + 34.1``Final temperature in Celsius = 50.99`°CStep 4: Convert the final temperature in Celsius to Fahrenheit.

F = (C x 9/5) + 32`F

= (50.99 x 9/5) + 32`F

= 123.78`°F

Therefore, the final temperature of the sample in degrees Fahrenheit when the desired temperature increase has been achieved is `123.78°F.`

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The effect of - 0.1 miles tolerance on a 3595 miles radius of earth's surface area calculation is 0.00556 %

SA = 4 π r²

SA = Surface area of a sphere

r = Radius

Actual surface area,

r = 3595 mi

SA = 4 * 3.14 * 3595²

SA = 162325754 mi²

Surface area with tolerance,

r = 3595 - 0.1

r = 3594.9 mi

SA = 4 * 3.14 * 3594.9²

SA = 162316723.5 mi²

% error = ( Actual value - Error value ) / Actual value

% error = ( 162325754 - 162316723.5 ) / 162325754

% error = 9030.5 / 162325754

% error = 5.56 * \(10^{-5}\)

% error = 0.00556 %

Therefore, the effect of - 0.1 miles tolerance on a 3595 miles radius of earth's surface area calculation is 0.00556 %

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Answer:

Cho hai quả cầu nhỏ trung hòa điện đặt trong không khí, cách nhau 40cm và sử có bốn nhân 10 mũ 12 electron tư quả cầu này di chuyển sang qua câu kia hỏi khi đó hai quả cầu Vũ thấy đầy nhau tỉnh đô lớn của lực đó

The current confined by the Amperian loop of radius 0.0182 m is about 1.99 A.

The Amperian loop encloses a cylindrical volume of the conductor with a radius between 0.0065 m and 0.0182 m. To find the current enclosed by the loop, we need to calculate the total current passing through this cylindrical volume.

The current density J (current per unit area) is uniform across the cross-section of the conductor, and its magnitude is given by:

J = I/A

where I is the current passing through the conductor, and A is the cross-sectional area of the conductor.

The cross-sectional area of the conductor is the difference between the areas of the outer and inner cylinders:

A = π(r_outer² - r_inner²)

Substituting the given values, we get:

A = π(0.0293² - 0.0065²) = 0.00148058 m²

The total current passing through the cylindrical volume enclosed by the Amperian loop is:

I_enclosed = J × A_enclosed

where A_enclosed is the area enclosed by the loop, given by:

A_enclosed = πr²

Substituting the given values, we get:

A_enclosed = π(0.0182²) = 0.00104228 m²

Substituting the values we found, we get:

I_enclosed = J × A_enclosed = (3.00 A / 0.00148058 m²) × 0.00104228 m² ≈ 1.99 A

Therefore, the current enclosed by the Amperian loop of radius 0.0182 m is approximately 1.99 A.

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Answer:

2.5 cm³

Explanation:

Use Boyle's Law

1×5=2×V

5=2V

V=5/2=2.5 cm³

In addition to a proper air void system and strength level, a concrete mixture must contain durable aggregates in order to perform adequately in a freeze-thaw service environment. The correct option is (c) .

Aggregates are the primary component in concrete and provide bulk and strength to the mixture. The durability of aggregates is critical in freeze-thaw environments, as the expansion and contraction caused by the freeze-thaw cycle can cause the aggregates to crack or break down, leading to deterioration of the concrete. Therefore, it is important to use high-quality and durable aggregates in concrete mixtures designed for freeze-thaw service environments.Aggregates are an essential component of concrete and play a crucial role in its performance. Durable aggregates help enhance the resistance of concrete to the damaging effects of freeze-thaw cycles, ensuring its durability and longevity in such environments.Therefore option C is correct.

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Answer:

For a given force (as determined by the elastic modulus), "light" molecules can oscillate at a greater frequency than "heavy" molecules; so a less dense medium will have a higher frequency per wavelength (i.e. a higher wave speed) than a more dense medium. The speed of sound in air is 332m/s.

Explanation:

i need one more brainliest plz

Depending on the different mediums, sound can travel faster through them.

The radius of its circular orbit is calculated to be 1/B √(2qV/m)

If the field is vacuum, then the magnetic field is dominant factor determining the motion. As the magnetic force is perpendicular to the direction of travel, a charged particle follows a curved path in a magnetic field. The particle then continues to follow curved path until it forms a complete circle. As the magnetic force is perpendicular to velocity, so that no work is done on the charged particle. The kinetic energy of the particle and speed remain constant. The direction of motion is usually affected but not the speed.

The speed of particle just before entering into magnetic field is v₀

qV = 1/2*m *v₀²

v₀= √(2qV/m)

Radius of the circular path is given by

 r= mv₀/qB

r=m/qB √(2qV/m)

=1/B √(2qV/m)

Radius of circular orbit = 1/B √(2qV/m)

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Answer:

300 kelvin

Explanation:

Answer:

A red giant or red super giant then a white dwarf

Explanation:

This also depends on what the star classification was to begin with.

Answer:

She will travel 180 kilometers.

Explanation:

You take the time and multiply it by your distance, and you get your total distance.

d = v.t

d = 60 km/h x 3 h

d = 180 km

Answer:

both statements are truth

Explanation:

a-The Joule effect, also called Joule's law, is the thermal manifestation of electrical resistance. ... In all these cases, it is intended to generate thermal energy with electricity passing through its conductors. This heat they give off is due to the Joule effect.

b-sure of a liquid tank depends only on the density of the liquid and depth from the free surface. It is a scalar quantity and is same in all directions, at a point.

The additional distance the buoy will sink when an 80.0-kg man stands on top of it is approximately 0.122 meters.

To calculate the additional distance the buoy will sink when an 80.0-kg man stands on top of it, we will use Archimedes' principle and the concept of buoyancy.
First, we need to find the volume of the water displaced by the 80.0-kg man. We can use the following formula to calculate this volume:
Volume_displaced = (Mass_man / Density_water)
Density of seawater is approximately 1025 kg/m³, so:
Volume_displaced = (80.0 kg / 1025 kg/m³) = 0.0780 m³
Now, we will find the height (h) that the cylindrical buoy sinks. The volume of the cylinder can be expressed as:
Volume_displaced = π(Diameter² / 4) * h
We know the diameter (0.900 m) and the volume displaced (0.0780 m³), so we can solve for h:
0.0780 m³ = π(0.900 m² / 4) * h
Rearranging the equation and solving for h:
h = (0.0780 m³) / (π(0.900 m² / 4))
h ≈ 0.122 m
So, the additional distance the buoy will sink when an 80.0-kg man stands on top of it is approximately 0.122 meters.

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Answer:

The suitcase weighs 225N

Explanation:

Weight can be defined as the force of gravity acting on an object. The unit of the weight of an object is Newton because it is a force.

Given that mass = 22.5

Weight = ?

Weight = mass × acceleration due to gravity.

Acceleration due to gravity = 10m/s2

W = mg

W = 22.5 × 10

W = 225N.

Hence, the suitcase weighs 225N.