The distribution coefficient between methylene chloride and water for solute Y is 14. An amount of 72.0 g of Y is dissolved in 180 mL of water. a) What weight of Y would be removed from water with a single extraction with 180-mL of methylene chloride? Report to 1 decimal place. b) What total weight of Y would be removed from water (the original solution) with two successive extractions with 90-mL portions each of methylene chloride?

Answers

Answer 1

Answer:

a)Weight of Y extracted from water in single extraction = 67.2 g

b) Total weight of Y extracted from water in two successive extractions = 70.9 g

Explanation:

Distribution coefficient, Kd = Cs / Cm

where Cs  is concentration of solute in methylene chloride; Cm is concentration of solute in water

a) Let x g of solute Y be extracted into methylene chloride

72.0 - x g of Y will be left in water

Kd = (x/180 mL of methylene chloride) / (72.0 - x/180 mL of water) = 14

14 = 180 * x / 180 * 72.0 - x

x = 14(72.0 - x)

x = 1008 - 14x

15x = 1008

x = 1008/15

x = 67.2 g

Weight of Y extracted from water in single extraction = 67.2 g

b) First extraction: Let x g of solute Y be extracted into methylene chloride

72.0 - x g of Y will be left in water

14 = x/90 / 72.0 - x/180

14 = 180x/ 90(72.0 - x)

14 = 2x/ 72.0 - x

2x = 14(72.0 - x)

2x =  1008 - 14x

16x = 1008

x = 63.0 g

Second extraction: Amount of solute left in water after first extraction = 72 - 63 = 9.0 g

Let x g of solute Y be extracted into methylene chloride

9.0 - x g of Y will be left in water

14 = x/90 / 9.0 - x/180

14 = 180x/ 90(9.0 - x)

14 = 2x/ 9.0 - x

2x = 14(9.0 - x)

2x =  126 - 14x

16x = 126

x = 7.90 g

Total weight of Y extracted = (63 + 7.90) g

Total weight of Y extracted from water in two successive extractions = 70.9 g

Answer 2

a) The Weight of Y extracted from water in single extraction is 67.2 g

b) The Total weight of Y extracted from water in two successive extractions should be 70.9 g

Calculation of weight:

Here

The distribution coefficient, Kd should be

= Cs / Cm

where

Cs  should be a concentration of solute in methylene chloride;

Cm should be a concentration of solute in water

a) Let  us assume x g of solute Y that should be extracted into methylene chloride

So,

72.0 - x g of Y will be left in water

And, now

Kd = (x/180 mL of methylene chloride) / (72.0 - x/180 mL of water) = 14

So,

14 = 180 * x / 180 * 72.0 - x

x = 14(72.0 - x)

x = 1008 - 14x

15x = 1008

x = 1008/15

x = 67.2 g

b)

Now First extraction:

Let x g of solute Y be extracted into methylene chloride

So,

72.0 - x g of Y will be left in water

14 = x/90 / 72.0 - x/180

14 = 180x/ 90(72.0 - x)

14 = 2x/ 72.0 - x

2x = 14(72.0 - x)

2x =  1008 - 14x

16x = 1008

x = 63.0 g

Second extraction:

Amount of solute left in the water after the first extraction that should be

= 72 - 63

= 9.0 g

Now

Let x g of solute Y be extracted into methylene chloride

9.0 - x g of Y will be left in water

14 = x/90 / 9.0 - x/180

14 = 180x/ 90(9.0 - x)

14 = 2x/ 9.0 - x

2x = 14(9.0 - x)

2x =  126 - 14x

16x = 126

x = 7.90 g

Total weight of Y extracted = (63 + 7.90) g

= 70.9g

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Related Questions

Based on the evidence collected in the activity where a corn chip was burned, what claim can you make about the relationship between burning food outside the body and food reacting with oxygen inside the body?

Answers

The evidence collected in the activity suggests that burning food outside the body is a form of oxidation, which is a reaction between food and oxygen inside the body. This reaction is responsible for the production of energy and the release of waste products.

5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure
water?

Answers

Answer:

2.8 m

Explanation:

From the question given above, the following data were obtained:

Number of mole KBr = 0.210 mole

Mass of water = 0.075 kg

Molality of KBr =?

Molality is simply defined as the mole of solute per unit kg of water. Mathematically, it can be expressed as follow:

Molality = mole of solute / Kg of water.

With the above formula, we can obtain the molality of the KBr solution. This can be obtained as follow:

Number of mole KBr = 0.210 mole

Mass of water = 0.075 kg

Molality of KBr =?

Molality = mole of solute / Kg of water.

Molality = 0.210 / 0.075

Molality = 2.8 m

Therefore, the molality of the KBr solution is 2.8 m.

perform the following operation and express the answer in scientific notation 6x10^2 / 8x10^12

Answers

Answer:

7.5 x 10 ^-11

Explanation:

6/8 = .75

10^2 / 10^12   = 10^ (2-12) = 10^(-10)

so far    .75  x 10^-10  

    which is   7.5 x 10^-11

2.5.2 Test (CST): Computer-Scored Unit Test
Question 3 of 25
Which characteristic gives the most information about what kind of element
an atom is?
OA. The number of electrons
B. The number of neutrons
C. The atomic number
OD. The atomic mass
k

2.5.2 Test (CST): Computer-Scored Unit TestQuestion 3 of 25Which characteristic gives the most information

Answers

The number of positive charge units (protons) in the nucleus is defined as the atomic number, which is the single most significant property of an atom. Atomic numbers are typically represented by the symbol Z.

What are an atom and atomic number?

A component of an element is an atom. A specific element only has one kind of atom per atom. Protons, neutrons, and electrons, which are subatomic particles, make up the remainder of an atom. Chemical reactions can result in the combination of elements to create molecules. The number assigned to a chemical element by its atomic number in the periodic system places the elements in ascending order of the number of protons in their nuclei.

The number of positive charge units (protons) in the nucleus is defined as the atomic number, which is the single most significant property of an atom. Atomic numbers are typically represented by the symbol Z.

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The pressure of a sample of argon gas was increased from 3.14 atm to 7.98 at a constant temperature. If the final volume of argon sample was 14.2 L what what’s the initial volume of the argon sample? Assume ideal behavior

Answers

Answer:

36.09 L

Explanation:

The initial volume can be found by using the formula for Boyle's law which is

\(P_1V_1 = P_2V_2\)

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume.

Since we're finding the initial volume

\(V_1 = \frac{P_2V_2}{P_1} \\\)

We have

\(V_1 = \frac{7.98 \times 14.2}{3.14} = \frac{113.316}{3.14} \\ = 36.0878...\)

We have the final answer as

36.09 L

Hope this helps you

21. What is the name of CaCO3?

Answers

The name of the compounds CaCO3 is calcium carbonate because it has three atoms of oxygen.

If a reaction starts with 30 grams of material, how many grams of material should be present at the end, according to the Law of Conservation of Mass. 

please help me​

Answers

If a reaction starts with 30 grams of material, the same amount of mass 30 grams of material should be present at the end, according to the Law of Conservation of Mass.

The law of conservation of mass states that no atoms are misplaced or made in a chemical reaction. as an alternative, the atoms be a part of collectively in distinctive methods to form merchandise.

The law of conservation of mass states that during a chemical reaction mass is neither created nor destroyed. for example, the carbon atom in coal turns into carbon dioxide when it's miles burned. The carbon atom changes from a stable structure to gas but its mass does not trade.

The law of conservation of mass states that depend cannot be created or destroyed in a chemical response. for example, when wooden burns, the mass of the soot, ashes, and gases equals the unique mass of the charcoal and the oxygen when it first reacted. So the mass of the product equals the mass of the reactant.

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Balance this equation using oxidation number change method. Show your steps. NH3+O2 -> NO2+H2O

Answers

Answer: The balanced equation is  4 NH3 + 7 O2  -->  4 NO2 + 6 H2O

Explanation:

Oxidation numbers

We begin by noting the oxidation numbers on each atom:

NH3:   N = -3, H = +1

O2:     O = 0

-----------------

NO2:  N = +4, O = -2

H2O:  H = +1,  O = -2

From this we conclude that N has lost 7 electrons, while O has gained 2.

Half-reactions

Because this case is more complex, we must consider the half-reactions:

Eq. 1)  N^-3  -->  N^+4  + 7 e-        (which says that N has lost 7 electrons)

Eq. 2) O  + 2 e- --> O^-2                (which says that O has gained 2 electrons)

However, oxygen is a diatomic atom, so we must adjust the second equation by a factor of 2.

Eq. 1)  N^-3  -->  N^+4  + 7 e-

Eq. 2) O2  + 4 e- --> 2 O^-2

Balancing the Half-reactions

To balance the half-reactions, we must multiply each equation by a factor that allows us to cancel out the electrons. The LCM of 7 and 4 is 28, so we multiply the first equation by 4, and the second equation by 7, giving:

Eq. 1)  4 N^-3  -->  4 N^+4  + 28 e-

Eq. 2) 7 O2  + 28 e- --> 14 O^-2      

Now, adding them together gives:

4 N^-3  +  7 O2  --> 4N^+4  + 14 O^-2

All together...

To complete the reaction, we must add the missing hydrogen atoms. With 4 nitrogen atoms on the left, we require 12 hydrogen atoms to construct the 4 NH3 molecules. We will add 12 H to both sides:

4 N^-3  +  7 O2  --> 4N^+4  + 14 O^-2

 + 12 H                      + 12 H

-------------------------------------------------------

4 N^-3 + 12 H + 7 O2  --> 4N^+4  + 14 O^-2 + 12 H

We can now combine all the atoms together into the known molecules on each side:

4 NH3 + 7 O2 --> 4N^+4 + 8 O^-2 + 12 H + 6 O^-2

which is,

4 NH3 + 7 O2 --> 4 NO2 + 6 H2O

what is the covalent bond for SO2? And please draw it, thank you​

Answers

Explanation:

SO2 comprises a double Covalent bond with one oxygen atom as well as a coordinate bond with another oxygen atom. The SO2 comprises 1s and 2p orbitals hybridized. Owing to the double Covalent bond of the molecule Sulphur Dioxide, it has 2 sigma and 2 pi bonds.

what is the covalent bond for SO2? And please draw it, thank you

Why do elements not have a numerical value for standard heats of formation and Free energies of formation but do have a numerical value for standard molar entropies?

Answers

Because it takes no energy to generate a naturally occurring compound, the enthalpy of formation for an element in its elemental state will always be 0.

What do you mean by formation standard free energies?

The free energy shift that happens when 1 mole of a material is created from its component elements in their standard states is referred to as the standard free energy of formation. The standard free energy of production of a pure element in its standard state is zero.

The distinction between Gibbs free energy and standard free energy is that the former is dependent on the experimental circumstances, whilst the latter describes the Gibbs free energy for reactants and products in their standard state.

learn more about standard free energy

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helppp nowwww plssssss!!

helppp nowwww plssssss!!

Answers

PLS HELP ME ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITs RIGHT OR WRONG. PLS HELP ME ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITs RIGHT OR WRONG. PLS HELP ME ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITs RIGHT OR WRONG. PLS HELP ME ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITs RIGHT OR WRONG. PLS HELP ME ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITs RIGHT OR WRONG. PLS HELP ME ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITs RIGHT OR WRONG. PLS HELP ME ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITs RIGHT OR WRONG. PLS HELP ME ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITs RIGHT OR WRONG.

Given that the density of Hg(l) at 0°C is about 14 g mL-­1, which of the following is closest to the volume of one mole of Hg(l) at this temperature?

Answers

Answer: 14mL

Explanation:

From the question, we've been told that the that the density of Hg(l) at 0°C is about 14 g mL-­1.

14g = 1mL

We should note that atomic weight of mercury = 200.59.

Therefore, 1 mol Hg = 200.59 g

Therefore, the answer that is closest to the volume of one mole of Hg(l) at this temperature will be:

= 200.59/14

= 14.3 mL

= 14mL approximately

The volume of 1 mole of Hg(l) at 0°C is 14.3 mL.

The molar mass of Hg is 200.6 g/mol. Given that the density of Hg(l) at 0°C is 14 g/mL, the volume of 1 mol of Hg is:

\(1 mol \times \frac{200.6g}{1mol} \times \frac{1mL}{14g} = 14.3 mL\)

The volume of 1 mole of Hg(l) at 0°C is 14.3 mL.

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What force opposes the electromagnetic force in the atom?

Answers

Answer:

The strong forces oppose the electromagnetic force of repulsion between protons. Like ”glue” the strong force keeps the protons together to form the nucleus. The strong forces and electromagnetic forces both hold the atom together.

Explanation:

Hope This helps

Answer:

The strong forces oppose the electromagnetic force of repulsion between protons.

The following Lewis diagram represents the valence electron configuration of a main-group element.


This element is in group
.

According to the octet rule, this element would be expected to form an ion with a charge of
.

If is in period 5, the ion formed has the same electron configuration as the noble gas
.

The symbol for the ion is
.

Answers

This element is in group 1.

According to the octet rule, this element would be expected to form an ion with a charge of +1.

If X is in period 5, the ion formed has the same electron configuration as the noble gas Krypton

The symbol for the ion is Rb⁺

What is electronic configuration?

Electronic configuration refers to the arrangement of electrons in the orbitals of an atom or molecule, indicating the energy level of the electrons, the number of electrons in each energy level, and the number of electrons in each orbital.

Considering the given element:

It has one valence electron, hence it is in group 1. Group 1 elements form ions with a charge of +1.

Losing one electron will give the ion the same electron configuration as Kyrton since it is the noble gas in Period 4.

The element is rubidium and the ion is Rb⁺.

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The following Lewis diagram represents the valence electron configuration of a main-group element.This

'How many atoms are in 2.45 moles of copper?


2.46 × 1023 atoms

2.45 atoms

155.70 atoms

1.48 × 1024 atoms

Answers

Answer:

\(\boxed {\boxed {\sf 1.48 \times 10^{24} \ atoms \ Cu}}\)

Explanation:

We are asked to find how many atoms are in 2.45 moles of copper (Cu).

We can convert moles to atoms using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of copper. There are 6.022 × 10²³ atoms of copper in 1 mole of copper.

We will convert using dimensional analysis, so we must set up a ratio using Avogadro's Number.

\(\frac {6.022 \times 10^{23}\ atoms \ Cu}{ 1 \ mol \ Cu}\)

We are converting 2.45 moles of copper to atoms, so we multiply the ratio by this value.

\(2.45 \ mol \ Cu*\frac {6.022 \times 10^{23}\ atoms \ Cu}{ 1 \ mol \ Cu}\)

The units of moles of copper cancel.

\(2.45*\frac {6.022 \times 10^{23}\ atoms \ Cu}{ 1}\)

The denominator of 1 is the same as the numerator by itself, so it can be ignored.

\(2.45* {6.022 \times 10^{23}\ atoms \ Cu}\)

\(1.47539 \times 10^{24} \ atoms \ Cu\)

The original measurement of moles (2.45) has 3 significant figures, so our answer must have the same. For the number we found that is the hundredth place. The 5 in the thousandth place to the right tells us to round the 7 up to an 8.

\(1.48 \times 10^{24} \ atoms \ Cu\)

There are approximately 1.48 × 10²⁴ atoms of copper in 1 mole of copper.

Answer:

\(:\implies \rm Moles =\dfrac{No. \: of \: atoms}{Avogadro's \: number} \\ \)

\(:\implies \rm M =\dfrac{N}{N_A} \\ \)

\(:\implies \rm N=M \times N_A \\ \)

\(:\implies \rm N=2.45\times6.022 \times {10}^{23} \\\)

\(:\implies \rm N=14.7539\times {10}^{23} \\\)

\(:\implies \rm N=1.47539\times 10^1\times {10}^{23} \\\)

\(:\implies\textsf{ \textbf{N = 1.48$\times${10}$^{24}$}} \\\)

Urgent help me please answer it if you know it

Urgent help me please answer it if you know it

Answers

i think it is c.

i know that plants take in co2 to then make oxygen and they need water and sunlight to grow and live.

DUE IN 4 MINUTES!!! NEED ANSWER ASAPSSSSSSSS

If 50 grams of water is to be heated from 42.0° C to 100.0° C to make a cup of tea, how much heat must be added?

Question 42 options:

15,200 calories


84 calories


2,900 calories


2,100 calories

Answers

Answer:

Explanation:

The amount of heat that must be added to heat 50 grams of water from 42.0° C to 100.0° C can be calculated using the specific heat capacity formula: Q = m*C*ΔT, where Q is the heat required, m is the mass of the water, C is the specific heat capacity of water, and ΔT is the temperature change.

Using the values given, we have:

Q = 50 g * 1 cal/g °C * (100.0°C - 42.0°C)

Q = 50 g * 1 cal/g °C * 58.0°C

Q = 2,900 calories

Therefore, the amount of heat that must be added to heat 50 grams of water from 42.0° C to 100.0° C is 2,900 calories. The answer is option (C).

when ethyne is passed through a red hot tube _______ is formed
a. Xylene
b. Butyne
c. propene
d. benzene

Answers

Answer:

when ethyne is passed through a red hot tube benzene is formed

Explanation:

The answer is D

Which of the following is a balanced equation for the combination reaction that takes placewhen iron(III) oxide is formed from its constituent elements.

Which of the following is a balanced equation for the combination reaction that takes placewhen iron(III)

Answers

Step 1 - Finding the formula of Iron (III) Oxide

Iron (III) Oxide is the resulting compound when two ions, Iron (III), Fe(3+), and O(2-) combine with each other. The resulting compound formula will be thus:

\(Fe^{3+}_{}+O^{2-}\to Fe_2O_3\)

Step 2 - Understanding what "constituent elements" means

When we refer to constituent elements we are talking about the most common form, found in nature, for the elements that compose a substance. Water, for example, is composed of the elements H and O (H2O).

The most common form of H atoms in nature is H2, hydrogen gas. The same is valid for O atoms (O2 gas). Therefore, the equation for forming water from its "constituent elements" would be:

\(2H_2+O_2\to2H_2O\)

Therefore, for the substance Fe2O3, the elements that compose it are Fe and O. O, as we saw, is found in the form of O2. But what about Fe? Well, Fe can be found as pure metal, which is represented as Fe only.

The equation for forming Fe2O3 from its "constituent elements" is thus:

\(Fe+O_2\to Fe_2O_3\)

Step 3 - Balancing the equation

To properly balance a chemical equation, we must guarantee the number of atoms of each element is the same in both sides of the equation.

Let's count the number of atoms in the previous reaction:

\(\begin{gathered} \text{left}-\text{hand side: one Fe, two O atoms} \\ \\ \text{right}-\text{hand side: two Fe, three O atoms} \end{gathered}\)

As we can see, this reaction is not balanced. We can start balacing it by multiplying Fe by 2:

\(2Fe+O_2\to Fe_2O_3\)

The quantity of Fe atoms is now properly balanced. Now, to balance O2, we can multiply it by 3/2:

\(2Fe+\frac{3}{2}O_2\to Fe_2O_3\)

If you feel unconfortable workin with fractions, there's no problem at all. Just multiply the whole equation by the denominator:

\(4Fe+3O_2\to2Fe_2O_3\)

The correct alternative is thus item a.

N2 + H2 -> NH3
How many moles of H2 gas are used to make 36.5 grams of NH3?

Answers

Explanation:

First, you need to balance the equation:

N2    +  3 H2   ====>    2  NH3

                  so three moles of H2   result in  2 moles of NH3

                               ratio of   3:2

How many moles of NH3 is 36.5 gm  ??

   Using periodic table NH3 mole weight = 14.007  + 3*1.008 =17.031 g/mole

     36.5 g / 17.031 g/mole = 2.14 moles  of NH3

Using the ratios above   3/2 = x / 2.14   shows x = 3.21 moles of H2 needed

Please answer this!

What are the half-reactions for electrolytic cell with aluminum and gold
electrodes?
A. Al³+ (aq) + 3e → Al(s) and Au(s) → Au* (aq) + e
B. Al³+ (aq) + 3e → Al(s) and Aut(aq) + e¯ → Au(s)
► Au(s).
C. Al(s) → A1³+ (aq) + 3e and Au* (aq) + e →
D. Al(s) → Al³+ (aq) + 3e¯ and Au(s) → Au*(aq) + e

Please answer this!What are the half-reactions for electrolytic cell with aluminum and goldelectrodes?A.

Answers

I think the answer is B.
the answer is B. it is a half reaction for electrolytic cell with aluminum and gold

A student was adding NaOH to two different acid solutions, HCl and HF, until a pH of 7 was reached in both solutions. The acids had the same initial volume, and both had an initial pH of 4.5. Which statement is true regarding the amount of NaOH added to each acid?

Answers

NaOH added for HCl will be more than NaOH added for HF

Which one of the following can be classified as a weak electrolyte?
HBr
CaF2
OBr2
HF
F2

Answers

F2 can be classified as a weak electrolyte.

An electrolyte is a medium containing ions that conducts electricity through the movement of those ions but does not conduct electrons. Most soluble salts, acids, and bases dissolved in a polar solvent, such as water, fall into this category.

A strong electrolyte is a solution/solute that ionizes or dissociates completely or almost completely in solution. In the solution, these ions are excellent conductors of electric current. Originally, a "strong electrolyte" was defined as a chemical that conducts electricity well in aqueous solution. Hydrogen chloride is an example of a strong electrolyte. A weak electrolyte is one that does not completely dissolve in water.

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Are cable wires made of thermoplastic? If so why?


(This is just a doubt that just came into my head)

Answers

\(\qquad\qquad\huge\underline{{\sf Answer}}\)

Cable wires are usually made of of thermoplastics because, current passing through the wire has heating effects as well, due to collision of electrons in the conducting wire. so to avoid the melting of normal wire which can break the circuit, Thermoplastics are used, that doesn't have much effect of heat on them.

Solid lithium hydroxide is used to "scrub" CO2 from the air inspacecraft and submarines; it reacts with the CO2 to produce lithium carbonate and water. What volume in liters of CO2 at 20°C and 753 torr can be removed by reaction with 440 g of lithium hydroxide?

Answers

Answer:

223 L

Explanation:

Step 1: Write the balanced equation.

2 LiOH + CO₂ = Li₂CO₃ + H₂O

Step 2: Calculate the moles corresponding to 440 g of LiOH

The molar mass of LiOH is 23.95 g/mol.

440 g × (1 mol/23.95 g) = 18.4 mol

Step 3: Calculate the moles of CO₂ that react with 18.4 moles of LiOH

The molar ratio of LiOH to CO₂ is 2:1. The reacting moles of CO₂ are 1/2 × 18.4 mol = 9.20 mol.

Step 4: Convert 20°C to Kelvin

K = °C + 273.15 = 20 + 273.15 = 293 K

Step 5: Convert 753 torr to atm

753 torr × (1 atm/760 torr) = 0.991 atm

Step 6: Calculate the volume of CO₂

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 9.20 mol × (0.0821 atm.L/mol.K) × 293 K / 0.991 atm

V = 223 L

The reaction 2 NO(g) ⇌ N2(g) + O2(g) has a Kc value of 2400 at 2000 K. If 0.850 M each of N2 and O2 are initially present in a 3.00-L vessel, calculate the equilibrium concentrations of NO, N2, and O2.

(I hope the word problem can be solved because my modules will be passed soon).

The reaction 2 NO(g) N2(g) + O2(g) has a Kc value of 2400 at 2000 K. If 0.850 M each of N2 and O2 are

Answers

Answer:

[N2] = [O2] = 0.841M

And [NO] = 0.00172M

Explanation:

The equilibrium constant of this reaction, Kc, is:

Kc = 2400 = [N2] [O2] / [NO]²

Where [] are the equilibrium concentration of each specie.

The initial concentration of [N2] = [O2] = 0.850M. The equilibrium will shift to the left in order to produce NO. The equilibrium concentrations are:

[N2] = [O2] = 0.850M - X

And [NO] = 2X

Replacing:

2400 = [0.850-X]²  / [2X]²

9600X² = 0.7225 - 1.7 X + X²

0 = 0.7225 - 1.7 X - 9599X²

Solving for X:

X = -0.0088M. False solution, there is no negative concentrations.

X = 0.00859M. Right solution.

Replacing:

[N2] = [O2] = 0.850M - 0.00859M

And [NO] = 2*0.00859M

[N2] = [O2] = 0.841M

And [NO] = 0.00172M

How does a magnet separate mixtures like sand and iron filings?​

Answers

Answer:

because iron is magnetic and sand is not

Explanation:

because iron filings are magnetic, but sand is not, so the magnet separates the filings from the sand due to magnetic attraction

A sealed 5.00L flask contains an unknown gas at 1.05 atm and 296 K. How many moles of the unknown gas are in the flask?

Answers

Moles of the unknown gas in the flask : 0.216

Further explanation

The gas equation can be written  

\(\large {\boxed {\bold {PV = nRT}}}\)

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

V=5 L

P = 1.05 atm

T = 296 K

\(\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1.05\times 5}{0.082\times 296}\\\\n=0.216\)

A 0.704-9 sample of a colorless liquid was vaporized in an evacuated 250-ml. flask at 121°C to give a pressure of 786 mmHg. What is the molecular weight of this substance?

Answers

Answer:

Molecular weight = amu

hopes this helps :)

Explanation:

Can you have a pH thats in decimals? For example .3 or .4?

Answers

A pH of 4 is ten times more acidic than a pH of 5.

Yes, pH can have decimal values. In fact, pH values can range from 0 to 14 and can have any value between them including decimals. pH is a measure of the acidity or alkalinity of a solution, and it is determined by the concentration of hydrogen ions (H+) in the solution.A solution with a pH of 7 is neutral, which means that it has an equal concentration of hydrogen ions (H+) and hydroxide ions (OH-). An acidic solution has a pH below 7 and a high concentration of H+ ions. On the other hand, an alkaline solution has a pH above 7 and a low concentration of H+ ions.A pH that is less than 7.0 indicates acidity. pH less than 7.0 is acidic while pH greater than 7.0 is alkaline. Each number on the pH scale represents a ten-fold change in the acidity/alkalinity of the solution. For example, a pH of 5 is 10 times more acidic than a pH of 6, and 100 times more acidic than a pH of 7.A pH of 0 indicates a very strong acidic solution while a pH of 14 indicates a very strong alkaline solution. It's worth noting that pH is a logarithmic scale, meaning that a change of one pH unit corresponds to a ten-fold change in hydrogen ion concentration.

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