The distance that students drive to school is best modeled with a skewed right distribution that has a mean of 10 miles and a standard deviation of 2 miles. Suppose a sample of 100 students has been taken and the sample mean distance for the sample is calculated. Describe the shape of the sampling distribution of the sample mean

Answer:

try 7 or 11.25 that all I got

Argon is the gas who would work best for something that needs a steady, nonreactive gas. (Ar).

When a neutral environment is required, argon is frequently used. In this manner, titanium and other volatile metals are produced. Additionally, it is used in the manufacture of incandescent bulbs to prevent air from corroding their filaments and by welders to safeguard the weld region.

A chemical substance in the periodic table's 18th group is argon. It is an expensive gas and the third most common gas in the atmosphere of the planet. Aside from nitrogen and oxygen, argon is the most prevalent gas in the atmosphere.

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What is the slope of the line that passes through the points (9 , -10 ) and (14 , 5)? Write your answer in simplest form.

From inspection on the given problem:

To calculate the slope of the line passing through the given points, we must use the formula below:

Substitute the given values into the slope formula and solve for m:

\( \sf{m = \dfrac{y_2 - y_1}{x_2 - x_1} = \dfrac{5 - (-10)}{14 - 9} = \dfrac{15}{5} = \pmb{3}}\)

Therefore, the slope of the line that passes through the given points is 3.

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According to the statement, the Ship must move at an average pace of 150 meters per hour.

The variable under examination is lessened when the gradient is "downhill" (negative). When used as a gauge of how well things are doing, "downhill" denotes a downward trend. Yet, if this indicates trouble or some other unpleasant quality, the situation is improving.

The chess player Carissa walks very, very slowly. She actually moves at speeds of 100 meters per hr upward, 150 meters per hr on flat terrain, and 200 meters every hour on downhill terrain.

Here,

Carissa traverses Boston on foot from a coffeehouse to a boba store before returning over the same path.

Total distance walked = 2 [200 + 100 + 150] = 900 meter

Total time = 2 [1 + 1 + 1] = 6 hour

Average speed is calculated as distance divided by time (900 / 6 = 150 m/s),

As a result, the needed Carissa average speed is 150 meters per hr.

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Answer:

Stop the line of production since the sample mean  (56.96) is outside the confidence interval [\(CI_{0.95}\) = ( 56.98, 57.05 )]

Step-by-step explanation:

Given that;

95% confidence interval for these parts is 56.98 to 57.05

\(CI_{0.95}\) = ( 56.98, 57.05 )

Sample mean = 56.96

We know that;

If the sample mean is within the confidence interval then, our decision is to keep the line operating as it is inside the confidence interval.

But if the sample mean is not within the confidence interval them, our decision is to stop the line of production as it is outside the confidence interval.

Now since our mean sample (56.96) does not lie between with the 95% confidence interval \(CI_{0.95}\) = ( 56.98, 57.05 ).

Therefore, Stop the line of production since the sample mean  (56.96) is outside the confidence interval [\(CI_{0.95}\) = ( 56.98, 57.05 )]

Answer:

63

Step-by-step explanation:

Answer:

Median: 379

Tho if it wrong Which half $777, $498, $619, $379, $895, $1,256, $1,052?

Answer: 0.07938

Step-by-step explanation:

Let X be  a binomial variable that represents the components of a specific engine.

As per given , the probability of componentis found to not perform to standards : p= 1%=0.01

Binomial probability formula :

\(P(X=x)=\ ^nC_xp^x(1-p)^{n-x}\)

Sample size : n= 100

If more than two are found to be non-performing the entire shipment is returned.

Now, Required probability : \(P(X>2)=1-P(X\leq 2)\)

\(=1-(P(X=0)+P(X=1)+P(X=2))\\\\=1- (^{100}C_{0}(0.01)^0(0.99)^{100}+^{100}C_{1}(0.01)^{1}(0.99)^{99}+^{100}C_{2}(0.01)^{2}(0.99)^{98})\\\\=1-((0.99)^{100}+(100)(0.01)(0.99)^{99}+\dfrac{100!}{2!98!}(0.01)(0.99)^98)\\\\=1-(0.36603+0.36973+0.18486)\\\\=1-(0.92062)\\\\=0.07938\)

So, the probability that a shipment is returned = 0.07938

To answer this question, you have that both equations can be equated since they represent the same angle since both lines are parallel. Then, we can write:

We need to solve for x, first, by subtracting x from both sides of the equation, and then subtracting 2 from both sides of the equation:

Finally, to find the value of x, we need to divide both sides by 2 as follows:

Therefore, the value for x = 13.

The algebraic expression that correctly represents the cost of t tickets is 8t , the correct option is (a) .

In the question ,

it is given that

the cost of 1 ticket for the theater is = $8.00

let the number of ticket be = t

so , the cost for t tickets = (cost of 1 ticket ) × ( number of tickets )

Substituting the values of number of tickets and cost of 1 ticket ,

we get ,

cost for t tickets = 8 × t

= 8t

Therefore , The algebraic expression that correctly represents the cost of t tickets is 8t .

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Answer:

log(ab)=loga+logb

•log26.35=log26+log35

B.log26+log35

Answer:

The measure for angle 1 is 102 degrees. They would be interior angles because they add up to be 180 degrees.

Step-by-step explanation:

Hope this helps!! Please mark me brainliest!!

Answer:

Week                   Mass  (gram)

(start)                    80

   1                         88  

   2                        96.8

   3                         106.48

   4                          117.128

Step-by-step explanation:

From the question we are told that

   The  mass of the kitten at the start week  is  m  =  80 g

   The rate at which the kitten grows is  r  =  0.10

Generally the mass of the kitten at the first  week is mathematically represented as  

    \(m_1 = ( r *  m)  + m\)

=>\(m_1 = ( 0.10 *  80 )  + 80 \)      

=>\(m_1 = 88 \ g  \)      

Generally the mass of the kitten at the second week is mathematically represented as  

     \(m_2 = ( r *  m_1)  + m_1\)

=>\(m_2 = ( 0.10 *  88 )  + 88 \)      

=>\(m_2 = 96.8 \ g  \)      

Generally the mass of the kitten at the third  week is mathematically represented as  

     \(m_3 = ( r *  m_2)  + m_2\)

=>\(m_3 = ( 0.10 *  96.8)  + 96.8 \)      

=>\(m_3 = 106.48  \ g  \)      

Generally the mass of the kitten at the fourth  week is mathematically represented as  

     \(m_4 = ( r *  m_3)  + m_2\)

=>\(m_4 = ( 0.10 *  106.48)  + 106.48 \)      

=>\(m_4 = 117.128  \ g  \)              

Week                   Mass  (gram)

(start)                    80

   1                        88  

    2                      96.8

    3                      106.48

   4                        117.128

The probability that the animal's weight will be less than 151 pounds is 0.50.

The correct option is B.

Since the given probability distribution ranges from 148 to 152, and we need to find the probability that the animal's weight will be less than 151 pounds, we can add the probabilities corresponding to the weights less than 151.

From the distribution, we see that the probability of the animal's weight being less than 151 pounds is 0.2 + 0.3 = 0.5.

Therefore, the answer is O 0.50.

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The given information tells us that Terry's wins-to-races ratio is 2:3, but we cannot determine the exact number of races he has won without additional information about the total number of races he has participated in.

If the ratio of the number of times Terry has won to the number of races he has swum in is 2:3, we can set up a proportion to determine the number of races he has won.

Let's denote the number of times Terry has won as x, and the total number of races he has swum in as y. According to the given ratio, we have:

x/y = 2/3

To find the value of x, we need to solve for x when y is known. Since y represents the total number of races, we don't have that information in the given problem. Therefore, we cannot determine the exact number of races Terry has won without knowing the total number of races he has participated in.

The ratio tells us the relationship between the number of wins and the total number of races, but without knowing the denominator (total races), we cannot find a specific value for the numerator (number of wins). We can only determine the ratio between the two quantities.

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A hot dog costs 2.25 we get it by solving the equation

Let's denote the cost of one hot dog by x.

Then we can set up two equations:

5x + 6y = 18.39

x + 2y = 4.63

where y is the cost of one bag of chips.

We want to solve for x.

Let us isolate variable y in the second equation

y = 4.63 - x/2

Substitute the y equation in the equation (1)

\($5x + 6\left(\frac{4.63 - x}{2}\right) = 18.39$\)

Simplifying this equation gives:

5x + 13.89 - 3x = 18.39

2x = 4.5

x = 2.25

Hence, a hot dog costs 2.25.

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Answer:

c would be equal to 2948. hope that helps

Answer:

\(c=b-\frac{a}{4} +\frac{11}{4}\)

Step-by-step explanation:

\(a=11+4b-4c \\a-11=4b-4c\\a-11-4b=-4c\\-\frac{a}{4} +\frac{11}{4} +b=c\)

Rearranging the terms to make it look cleaner, we get:

\(c=b-\frac{a}{4} +\frac{11}{4}\)

Answer:

According to this author, the stories about Nancy Hart  

✔ likely have some basis in truth

.

As a result, they are  

✔ very important

to the study of Georgia’s past

Step-by-step explanation:

I just took it on Edge 2020

Answer:

Step-by-step explanation:

2x*2x=4x^2

2x*3=6x

Keep in mind 4x^2-6x

then next part:

3*2x=6x

3*3=9

6x-9

So totally

(4x^2-6x)-(6x-9)

Minus and minus is equal to +

(4x^2-12x+9)+2=45

4x^2-12x+11=45

-11 on both sides

4x^2-12x=34

X= -17/-2

Step-by-step explanation:

2x-3(2x-3)+2=45

2x-6x+9+2=45

-4x=45-11

x=34/-4=-17/2

Answer:

Ok so we have a set of 8 numbers {1,2,...,8}

a) 5 and 8 are picked.The probability here is:

In the first selection we can pick 5 or 8, so we have two possible outcomes out of 8 total outcomes, then the probability for the first selection is:

P = 2/8 = 1/4.

Now, if one of those numbers was picked in the first selection, only one outcome is possible in this second selection, (if before we picked a 5, here we only can pick an 8)

Then the probability is:

P = 1/8

The joint probability is equal to the product of the individual probabilities, so here we have:

P = (1/4)*(1/8) = 1/32 = 0.003

b) The numbers match:

In the first selection we can have any outcome, so the probability is:

P = 8/8 = 1

Now, based on the previous outcome, in the second selection we can have only one outcome, so here the probability is:

P = 1/8 = 0.125

The joint probability is p = 1/8

c) The sum is smaller than 4:

The combinations are:

1 - 1

1 - 2

2 - 1

We have 3 combinations, and the total number of possible combinations is:

8 options for the first number and 8 options for the second selection:

8*8  = 64

The probabilty is equal to the number of outcomes that satisfy the sentence divided by the total numberof outcomes:

P = 3/64 = 0.047

Using the probability concept, it is found that there is a:

i. 0.03125 = 3.125% probability that 5 and 8 are picked.

ii. 0.125 = 12.5% probability that both numbers match.

iii. 0.046875 = 4.6875% probability that the sum of the two numbers picked is less than 4.

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, two integers are chosen from a set of 8, hence, there are \(8^2 = 64\) total outcomes.

Item i:

Two outcomes result in 5 and 8 being picked, (5,8) and (8,5), hence:

\(p = \frac{2}{64} = 0.03125\)

0.03125 = 3.125% probability that 5 and 8 are picked.

Item ii:

8 outcomes result in both numbers matching, (1,1), (2,2), ..., (8,8), hence:

\(p = \frac{8}{64} = 0.125\)

0.125 = 12.5% probability that both numbers match.

Item ii:

Three outcomes result in a sum of less than 2, (1,1), (1,2), (2,1), hence:

\(p = \frac{3}{64} = 0.046875\)

0.046875 = 4.6875% probability that the sum of the two numbers picked is less than 4.

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Polling companies survey 1060 individuals to estimate a population proportion with a margin of error of 3% with 95% confidence because it strikes a balance between cost and accuracy, and it is based on statistical calculations that aim to achieve a reasonable level of precision while minimizing the margin of error.

When a polling company selects a sample size of 1060 individuals, it is based on statistical calculations that aim to achieve a 3% margin of error with 95% confidence. The sample size needs to be large enough to reduce the margin of error and increase the level of confidence in the results.

The margin of error decreases as the sample size increases, and it is inversely proportional to the square root of the sample size. Therefore, a larger sample size leads to a smaller margin of error. However, increasing the sample size also increases the cost and time required to conduct the survey.

Polling companies aim to strike a balance between the cost and the desired level of accuracy, which is typically a margin of error of 3-5% with 95% confidence. A sample size of 1060 individuals is often considered a reasonable compromise between cost and accuracy, as it provides a small enough margin of error to be useful while being feasible to conduct within a reasonable time and budget.

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Answer:

0.75

Step-by-step explanation:

Answer:

$1.33 per ticket cost

Step-by-step explanation:

5 / $3.75 = $1.33 per 1 ticket cost

Answer:

um i think 8 not really but its maybe 8 or 17 not really sure

Answer:

hi

Step-by-step explanation:

put 3 in place of x . its like a peice of cake

Answer:

h(3) = 6

Step-by-step explanation:

Given that,

→ x = 3

Then the value of h(3) will be,

→ h(x) = 3x - 3

→ h(3) = 3(3) - 3

→ h(3) = 9 - 3

→ [ h(3) = 6 ]

Hence, the answer is 6.

Answer:

The three components you should look for when examining distributions of numerical data are Shape, center, and spread

-Source(I took AP statistics in senior year of high school and passed the AP test)

The three components for examining distributions of numerical data are Shape, centre, and spread.

What is distribution of data?

A normal distribution is a common probability distribution. It has a shape often referred to as a "bell curve." Many everyday data sets typically follow a normal distribution: for example, the heights of adult humans, the scores on a test given to a large class, errors in measurements.

When examining the distribution of a quantitative variable, one should describe the overall pattern of the data (shape, centre, spread), and any deviations from the pattern (outliers). When describing the shape of a distribution, one should consider: Symmetry/skewness of the distribution Peakedness (modality) - the number of peaks (modes) the distribution has. Not all distributions have a simple, recognizable shape. Outliers are data points that fall outside the overall pattern of the distribution. It is always important to interpret the features of the distribution (as they appear in the histogram) mean in the context of the data.

Hence, The three components for examining distributions of numerical data are Shape, centre, and spread.

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Answer:

the answer is 24192

Answer: 24192

Step-by-step explanation:

Answer:

Step-by-step explanation:

Yes it is a function. Every x has only 1 y associated with it.

Answer:

$2.64

Step-by-step explanation:

I hoped I could help you!!