The discrete-time signal range of amplitudes: R which can be re-scaled, should map to the full Analog-to-Digital Converter range True False

1.int nPositive = 0;for (int i = 0; i < a2d.length; i++) {for (int j = 0; j < a2d[i].length; j++) { if (a2d[i][j] > 0) {nPositive++; } } }

Positive is having a positive outlook on life. It is the attitude of looking at the bright side of things and having an optimistic view of life. Positive thinking can help to reduce stress, improve mental and physical health, and increase overall happiness. Positive thinking can be cultivated through mindfulness, gratitude practices, and reframing negative thoughts.

2.public static void main(String[] args) {  if(args.length == 1 && args[0].equals(MyClass.class.getName())) {displayHelp(); } else if (args.length < 4) {argsError(args.length);} else { processArgs(args); } }

3.int[] myArray = {3, 8, 7, 6};int sum = 0;for (int i=0; i<myArray.length; i++) {

sum += myArray[i]; } double mean = sum/myArray.length;

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Note that a ground fault circuit interrupter (GFCI) protects you from shock by detecting differences in current as small as 5 milliamps between the amount of electricity flowing out.

A ground fault circuit interrupter (GFCI) protects you from shock by detecting differences in current as small as 5 milliamps between the amount of electricity flowing into a circuit and the amount flowing out. If the GFCI detects an imbalance in the current, it quickly interrupts the flow of electricity to prevent electric shock.

A ground fault circuit interrupter (GFCI) works by monitoring the flow of electricity in a circuit. If it detects an imbalance in the current, such as when electricity is flowing through an unintended path, it quickly interrupts the flow of electricity to prevent electric shock.

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Total unit weight, γ = 1.0825 kg/m³Void ratio, e = 3Porosity, n = 0.75

Water content (w%) = 12%Degree of saturation (Sr) = 75%Specific gravity of solids (Gs) = 2.65We have to calculate the total unit weight, void ratio (e), and porosity (n).Calculation:

First, we have to calculate the dry unit weight, γd

Dry unit weight, γd = γw / (1 + w%)

Let's calculate γw

Water content (w%) = 12%

So, moisture content (w) = w% * γd / 100= 12/100 * 1.65= 0.198 kg/kg of dry soil

Total weight of soil (Wt) = Weight of solids (Ws) + Weight of water (Ww)

Weight of solids (Ws) = Volume of solids (Vs) * Gs * γw/Vs = 1

Total volume of soil = Volume of solids (Vs) + Volume of voids (Vv)

Let's calculate Vv Degree of saturation (Sr) = 75%Vv/Vs = Sr / (1 - Sr)= 0.75 / 0.25= 3

Total volume of soil = Volume of solids (Vs) + Volume of voids (Vv)= 1 + 3= 4m^3

Let's calculate the weight of water,

WwWw = Wt - WsWw = 4 * 0.12 = 0.48 kg

Weight of solids, Ws = Gs * γs * Vsγs = (Wt - Ww) / Vst = (1 - 0.12) * 1.65= 1.452 kg/ m^3

Ws = Gs * γs * Vs= 2.65 * 1.452= 3.85 kg

Total unit weight, γ= Wt / Vt= (Ws + Ww) / Vt= (3.85 + 0.48) / 4= 1.0825 kg/m^3

Now, calculate the void ratio, eVv/Vs = 3Vv / Vt = Vv / (Vs + Vv) = 3 / 4e = Vv / Vs = 3 / 1 = 3

Porosity, n= Vv / Vt= 3 / 4= 0.75

Answer: Total unit weight, γ = 1.0825 kg/m³Void ratio, e = 3Porosity, n = 0.75

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Answer:

"cool"

Explanation:

Answer:

being prepared and having sufficient military resources available can be great IF there is an attack although it can be viewed as intimidating and scare off allies. also, it can cause other resources too thin.

Explanation:

it is great to have a sense of national pride and togetherness although if it gets out of hand it can be almost brainwashing and used to control citizens.

Answer:

219

Explanation:

Unsigned binary number (base two) 1101 1011 converted to decimal system (base ten) positive integer = 219.

Answer:219

Explanation:128+64+16+8+2+1

Answer:

C Electrical Connections

Explanation:

In reading says . However, electrical

connections aren’t shown in construction drawings.

Explanation:

The point on the line 3x + 4y = 5, which is equidistant from (1, 2) and (3, 4) is. Therefore, the point is (15, -10).

Answer:

C. Gas tungsten arc welding

Explanation:

Arc welding processes that employ a continuous fed wire electrode uses a constant voltage power source. This type of power source has a flat volt-ampere curve. The welding current and the electrode feed rate are matched to rate of wire melting and transfer across the arc into the weld pool. A monitoring system is responsible for controlling electrode speed using the arc voltage.

It should be noted that Constant voltage is not used for the Gas tungsten arc welding.

Constant voltage can be regarded as the ability to fluctuate output current ,so that in this process set voltage can be maintained. and it is used where the workpieces do not have flat surfaces.

Constant voltage can be used for applications  such as welding process like;

Therefore, option C is correct because Constant voltage is not used for the

Gas tungsten arc welding.

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Answer:

See explanation below

Explanation:

Hypo-eutectoid steel has less than 0,8% of C in its composition.

It is composed by pearlite and α-ferrite, whereas Hyper-eutectoid steel has between 0.8% and 2% of C, composed by pearlite and cementite.

Ferrite has a higher tensile strength than cementite but cementite is harder.

Considering that hypoeutectoid steel contains ferrite at grain boundaries and pearlite inside grains whereas hypereutectoid steel contains a higher amount of cementite, the following properties are obtainable:

Hypo-eutectoid steel has higher yield strength than Hyper-eutectoid steel

Hypo-eutectoid steel is more ductile than Hyper-eutectoid steel

Hyper-eutectoid steel is harder than Hyper-eutectoid steel

Hypo-eutectoid steel has more tensile strength than Hyper-eutectoid steel.

When making a knife or axe blade, I would choose Hyper-eutectoid steel alloy because

1. It is harder

2. It has low cost

3. It is lighter

When making a die to press powders or stamp a softer metals, I will choose hypo-eutectoid steel alloy because

1. It is ductile

2. It has high tensile strength

3. It is durable

Answer:

(a)

Steels having carbon within 0.02% – 0.8% which consist of ferrite and pearlite are known as hypoeutectoid steel.

Steels having greater than 0.8% carbon but less than 2.0% are known as hypereutectoid steel.

(b)

The proeutectoid ferrite formed at a range of temperatures from austenite in the austenite+ferrite region above 726°C. The eutectoid ferrite formed during the eutectoid transformation as it cools below 726°C. It is a part of the pearlite microconstiutents . Note that both hypereutectoid and hypoeutectoid steels have proeutectoid phases, while in eutectoid steel, no proeutectoid phase is present.

Proeutectoid signifies is a phase that forms (on cooling) before the eutectoid austenite decomposes. It has a parallel with primary solids in that it is the first phase to crystallize out of the austenite phase. If the steel is hypoeutectoid it will produce proeutectoid ferrite and if it is hypereutectoid it will produce proeutectoid cementite.  The carbon concentration for both ferrites is 0.022 wt% C.

(c)

(i) Yield strength: The hypoeutectoid steel have good yield strength and hypereutectoid steels have little higher yield strengh.

(ii) Ductility: The hypoeutectoid steel is more ductile and the ductility has decreased by a factor of three for the eutectoid alloy. In hypereutectoid alloys the additional, brittle cementite on the pearlite grain boundaries further decreases the ductility of the alloy. The proeutectoid cementite restricts plastic deformation to the ferrite lamellae in the pearlite.

(iii) Hardness:  hypoeutectoid steels are softer and hypereutectoid steel contains low strength cementite at grain boundary region which makes it harder than hypoeutectoids.

(iv) Tensile strength: Grain boundary regions of hypereutectoid steel are high energy regions prone to cracking because of cementite in the grain boundaries, its tensile strength decreases drastically even though pearlite is present. Hypoeutectoid steel contains ferrite at grain boundaries and pearlite inside grains, so grain boundaries being the high energy state region, it has a higher tensile strength.

(d)

I would recommend hypereutectoid steel alloy to make a knife or ax blade

1- Hardness is required at the surface of the blades.

2- Ductility is not needed for such application.

3- Due to constant impact, the material will not easily yield to stress.

(e)

I would choose a hypoeutectoid steel alloy to make a steel that was easy to machine.

1- hypoeutectoid steel alloys have high machinability, hence better productivity

2- It will be used on softer metals, hence its fitness for the application

3- Certain amount of ductility is required which hypoeutectoid steel alloys possess.

Explanation:

See all together above

Answer:

200V

Explanation:

I = 5A

R = 40Ω

V = IR = (5)(40) = 200V

Answer:c. Operational Risk Management

Explanation:

The phrase "Fly-Crash-Fix-Fly" is often used to describe the concept of Operational Risk Management. It emphasizes the continuous cycle of identifying potential risks and hazards (Fly), analyzing and learning from past incidents and accidents (Crash), implementing corrective actions and preventive measures (Fix), and resuming normal operations with improved safety (Fly). This approach aims to proactively manage risks and enhance safety performance within an organization.

Answer:

1700 kg

Explanation:

Determine the total mass of the oil, m, by multiplying the density,

p= 850 kg/m3

to the volume, V = 2m3 or m=p x v.

m=pxv.

m= p x v = 850 kg / m3 x 2

m3 = 1700 kg

The program that takes in a line of text as input, and outputs that line of text in reverse is as follows:

list1 = []

x = input("input your text for it to be reverse: ")

while x != "done" and "d" and "Done":

    list1.append(x)

    x = input("input your text for it to be reverse: ")

for i in list1:

    print(i[::-1])

The code is written in python

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Answer: metal inert gas (MIG) welding

Explanation:

Gas metal arc welding (GMAW), also called metal inert gas (MIG) welding, is an arc welding process in which the heat for melting the metal is generated by an electric arc between a consumable electrode and the metal (Fig.

Answer:

I think the answer is B. but I'm not 100% sure.

Answer:

engine and landing gear maintenance and repair

Explanation:

Answer:

a) When the switch is off and there's no battery supply, the electric potential difference, or electromotive force E(t), is zero. That means the right-hand side of the given differential equation is zero. Therefore, the solution to the homogeneous differential equation represents the charge on the capacitor:

L d²Q/dt² + R dQ/dt + 1/C Q = 0

In this case, since there's no initial charge or current supplied, Q(t) = 0 for all t.

b) When the switch is turned on and a 12-Volt battery is connected:

i. The method of Undetermined Coefficients:

We can solve this by proposing a particular solution that has the same form as the non-homogeneous term, E(t). As E(t) = 12 volts is a constant, we propose Q(t) = A as a constant.

After substituting Q(t) = A into the equation, we would be able to find the value of A, which would give us the particular solution. The general solution would then be the sum of this particular solution and the solution to the homogeneous equation (obtained from part (a)).

ii. The method of Variation of Parameters:

In this method, we would make use of the solutions of the homogeneous differential equation. After finding these, we would propose a solution for the non-homogeneous differential equation in terms of these solutions, and a pair of functions (u and v) to be determined. We then substitute this proposal into the differential equation to obtain a set of two new first-order differential equations for u and v.

c) Once we've found the charge Q(t) in part (b), we can find the current I(t) by differentiating Q(t), as I(t) = dQ/dt.

d) With the given initial conditions (Q = 0.001 C, I = 0 A), we can substitute these into the general solution and its derivative obtained in part (b). We would then solve the resulting system of two equations to find the constants involved, allowing us to determine the specific solution for these initial conditions.

Explanation:

Complex question. Answer depends on data provided and format of equations provided.

Answer:

Near

Explanation:

Please mark me brainliest

Answer:

Near.... bcoz it is an adverb...

The molar volume of acetylene vapor at 247.1 K and 13.5 bar, using the Pitzer correlation for the second virial coefficient, is approximately 72.5 cm3/mol.

Explanation:

The Pitzer correlation can be used to estimate the second virial coefficient of a gas. The equation is given by B = (RTc)/(Pc) * (1 + m(1 - (T/Tc)^(0.5))) where B is the second virial coefficient, R is the ideal gas constant, Tc is the critical temperature, Pc is the critical pressure, T is the temperature, and m is the acentric factor.

Plugging in the given values and solving for B, we get B = -0.009413 m3/mol. Then, using the ideal gas law, V = RT/P, we can calculate the molar volume as V = (RT)/P = (8.314 J/mol-K * 247.1 K) / (13.5 bar * 10^5 Pa/bar) ≈ 0.0725 m3/mol ≈ 72.5 cm3/mol.

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Answer: hello your question is poorly written below is the complete question

Ethanol blended with gasoline can be used to power a flex-fueled car. One particular blend that is gaining in popularity is E85 , which is 85% ethanol and 15% gasoline. E85 is 80% cleaner burning than gasoline alone, and it reduces our dependency on foreign oil. But a flex-fueled car costs $1,000 more than a conventional gasoline-fueled car. Additionally, E85 fuel gets 10% less miles per gallon than a conventional automobile. Consider a 100% gasoline -fueled car that averages 30 miles per gallon. The E85-fueled car will average about 27 miles per gallon. If either car will be driven 81000 miles before being traded in, how much will the E85 fuel have to cost (per gallon) to make the flex-fueled car as economically attractive as a conventional gasoline-fueled car? Gasoline costs $3.89 per gallon. Work this problem without considering the time value of money

answer :

$3.17

Explanation:

Determine how much E85 fuel have to cost

Fuel needed by 100% gasoline fueled car

= 81,000 miles / 30 = 2700 gallons

Fueled needed by E85 car

= 81,000 miles / 27 = 3000 gallons

next step : use the relation below

[ (Additional cost of flex fuel car) + (flex fuel consumption * cost of flex fuel per gallon( x ) )  ]   = [ Gasoline consumption * cost of gasoline per gallon ]

= 1000 + 3000x = 2700 * 3.89

= 1000 + 3000x = 10503

∴ x = 9503 / 3000 = $3.17 per gallon

Performance-Based Engineering (PBE) is an approach used to design building structures that consider how the structure responds in case of fire. By using this approach, it can be established the effectiveness of fire safety measures and if these measures meet the safety objectives of the building owner and local fire authorities.

There are two different example projects where performance-based engineering could add value to the project. These examples are not real but show how performance-based design could be a better option than prescriptive fire design.

Example 1: High-rise office building The first project is a 20-story high-rise office building that is still in the planning phase. This building has been designed to meet the minimum fire safety requirements of the building codes. The design is based on traditional methods where the objective is to protect the occupants from fire until the fire department arrives.

Example 2: Healthcare facility The second project is a new hospital that is under construction. This hospital will have several departments, including an emergency room, surgery rooms, and patient wards. Due to the complexity of the hospital, the building codes have been difficult to implement in the design of the hospital. Performance-based engineering could be used to demonstrate how the hospital can meet the safety objectives of the building owner and local fire authorities.

The key considerations to take into account include the cost and time required to conduct a performance-based analysis, determining the level of safety objectives, and taking into account the needs of the occupants and staff during an emergency.

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Answer:

there is no difference in risk

Explanation:

even though they put out the fires, if they don't get rid of the source from which the wildfires comes from then wildfires wont stop coming

Answer:

The answer will be B i hope this helps

As the temperature of the material increases, the potential energy of the molecules increases. Thermal expansion occurs due to changes in temperature, and interatomic distances increase as potential energy increases.

Thermal expansion is used in a variety of applications such as rail buckling, engine coolant, mercury thermometers, joint expansion, and others.

It is to be noted that an application of the concept of liquid expansion in everyday life concerns liquid thermometers. As the heat rises, the mercury or alcohol in the thermometer tube moves in only one direction. As the heat decreases, the liquid moves back smoothly.

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Answer:

Can I be it plzzzzz!?

Explanation:

I need points

Answer:

B....................

The process of die forming that uses a die and a press to form parts from the given processes is called; C: Hydroforming

There are different types of die forming in sheet metal operations. Now, Hydroforming is a specialized type of die forming that uses a high pressure hydraulic fluid to press room temperature working material into a die.

Tailor Welding is a process of making welded blanks made from individual sheets of steel of different thickness, strength and even coating that are joined together by the use of laser welding.

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c) Urgent activities take priority considerations for crashing is NOT being considered for crashing an activity or the entire project.

Crashing refers to the procedure of shortening the length of the project schedule and, as a result, minimizing the total project duration. The activity duration can be shortened by increasing the resources available to it. The following criteria are taken into account when crashing an activity or the entire project:

To guarantee that the project is completed on time.

To reduce the total cost of the project.

To maintain quality.

To enhance the dependability of the project.

To maximize resource usage.

The amount by which an activity is crashed is, in fact, permissible. Taken together, the shortened activity durations will enable us to finish the project by the due date. The total cost of crashing is as small as possible is considered for crashing an activity or the entire project.

The criteria which is NOT being considered for crashing an activity or the entire project is Urgent activities take priority considerations for crashing.

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