the difference in blood pressure between the head and the foot of a person who is 2.00 m tall and resting on an incline that is at an angle of 30.0 degrees to the horizontal is (density of blood is 1,060 kg/m3)

A generation is about one-third of a lifetime. Approximately 10^2 generations have passed since the year 0.

According to Guinness world records the most generations alive in a single family has been seven. Mrs. Fitzgerald stated she became "flabbergasted" to end up a super-great-fantastic grandmother.

The most normally accepted fee is four generations in keeping with the century, meaning that tracing backward by way of 10 generations could locate ancestors who lived approximately 250 years ago, inside the middle of the 18th century.

It is believed to have originated with the Iroquois – top notch regulation of the Iroquois – which holds suitable to assume seven generations ahead (about 525 years into the future, that's counted through multiplying the seventy-five years of a median human lifespan through 7) and determine whether or not the decisions they make these days would benefit.

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The wire 2 has the most charge flowing in it at the given time interval.

The total charge flowing in each wire is calculated using the following equation;

Q = It

where;

The charge flowing in wire 1 is calculated as follows;

Q = 1 x 60 = 60 C

The charge flowing in wire 2 is calculated as follows;

Q = 2 x 45 = 90 C

The charge flowing in wire 3 is calculated as follows;

Q = 3 x 10 = 30 C

Thus, the wire 2 has the most charge flowing in it at the given time interval.

The complete question is below

The current across three identical current carrying wires is measured during a certain time interval. The reading is reported in the table

        Current (A)        Time Interval (S)

Wire 1          1                  60

Wire 2         2                 45

Wire 3         3                  10

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Answer:

give brainliest please

Explanation:

T- lymphocytes or T cells

Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.

The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:

ωn = √(K / M),

where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.

Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.

ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.

Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

The correct question is given as,

M= 20kg

Fo = 90 N

ω = 6 rad/s

K = 400 N/m

C = 125 Ns/m

Determine the frequency of applied force at which resonance will occur?

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Answer:

Movement skills in square dancing transfer to ballroom dancing when they both require you to dance in a rhyme.

Explanation:

How fast sound travels through water at sea level and how deep the ocean is  1.432 x 10³m.

Given

Bulk modulus ( B ) = 0.21 x 10¹⁰ N/ m²

density of sea le ) = 1024 kg / m³

Speed of sound In sea water ( v ) = √B/е

V =√0. 21 x 10¹⁰/1024

V = 1-.432 x 10³ m/s

The Speed of sound has to travel at the bottom of sea and get reflected back to ship itself the distance travel by Sound is 2x

So

(t = 2 see )

2x = vt

2x = 1 . 432 x 10³ x 2

x = 1.432 x 10³m

By observing the velocity of this compressed area as it passes through the medium, we can determine the speed of sound. The sound wave travels at a speed of approximately 343 meters per second, or 767 miles per hour, in dry air at 20 degrees Celsius.

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According to the given statement 17.15 N force is exerted on the segment of wire in n.

Magnitude is essentially "distance or quantity" in the context of physics. In terms of motion, it shows the absolute and relative size, direction, or movement of an object. It is used to describe there is something volume or scope. Quantity in physics typically refers to a size or quantity.

The magnitude of the magnetic force on a conducting wire of length I carrying current II, and making an angle θ with a magnetic field of strength B is given by:

\($|\vec{F}|$\) = I l B sin 0

Rearranging to get the current:

I = \($|\vec{F}|$\)/ lB sin0

= 7 * 10⁻³ / 0.75 * (5.5 * 10⁻⁵)sin60

= 195.95 A

\($|\vec{F}|$\) = I l Bsin0

= (195.95)(0.05)(1.75)sin90

=17.15 N

I = 195.95 I

\($|\vec{F}|$\) = 17.15 N

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As the force exerted by the mass in the both cases was same on the both sides so that the object was said to be in the rest condition so they are said to be same in both conditions.

define pulleys ?

A wheel on an axle or shaft known as a pulley is used to transfer power from the shaft to the cable or belt or to sustain movement and direction change of a taut cable or belt. When a pulley is supported by a frame or shell and is used to guide a cable or apply force rather than transmit power to a shaft, the supporting shell is referred to as a block and the pulley may be referred to as a sheave.

For the purpose of locating the cable or belt, a pulley may include a groove or grooves between flanges around its circle. A rope, cable, belt, or chain may serve as the driving component of a pulley system.

As the force exerted by the mass in the both cases was same on the both sides so that the object was said to be in the rest condition so they are said to be same in both conditions.

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Given

\(m_1 = 2g\\\\m_2 = 0.2g\\\\v_1 = 2m/s\\\\v_2 = -8m/s\)

The expression for a perfectly inelastic collision,

\(m_1v_1 + m_2v_2 = (m_1+m_2)v_f\)

Therefore,

\(v_f = \frac{m_1v_1 + m_2v_2}{(m_1+m_2)} \\\\v_f = \frac{(2*2)+(0.2*-8)}{2+0.2}\\\\v_f = 1.09m/s\)

Since the bat and the bug fly towards each other, and after some time the bat swallows the bug, it is said to be a condition of perfectly inelastic collision.

The kinetic energy of the bat before it swallows the bug is,

\(KE_b = \frac{1}{2}m_1v_1^2\\\\KE_b = \frac{1}{2}2*2^2\\\\KE_b = 4gm^2/s^2\)

The kinetic energy of the bat after it swallows the bug is,

\(KE_f = \frac{1}{2}(m_1+m_2)v_f^2\\\\KE_f = \frac{1}{2}(2+0.2)1.09^2\\\\KE_f = 1.3gm^2/s^2\)

The total dissipation in the kinetic energy of the bat is calculated as,

\(\delta KE = KE_b - KE_f\\\\\delta KE = 4 - 1.3\\\\\delta KE = 2.7 gm^2/s^2\)

The fraction of the dissipated kinetic energy of the bat is calculated as,

\(d = \frac{\delta KE}{KE_b}\\\\d = \frac{2.7}{4}\\\\d = 0.67\)

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Answer:

no

Explanation:

the moon's force of gravity is not strong enough to pull you down compared to earth, so you will just float

Answer:

The time taken to reach the maximum height is 3.20 seconds

Explanation:

The given parameters are;

The initial height from which the volcano erupts the lava bomb = 64.4 m

The initial upward velocity of the lava bomb = 31.4 m/s

The acceleration due to gravity, g = 9.8 m/s²

The time it takes the lava bomb to reach its maximum height, t, is given by the following kinematic equation as follows;

v = u - g·t

Where;

v = The final velocity  = 0 m/s at maximum height

u = The initial velocity = 31.4 m/s

g = The acceleration due to gravity = 9.8 m/s²

t = The time taken to reach the maximum height

Substituting the values gives;

0 = 31.4 - 9.8 × t

∴ 31.4 = 9.8 × t

t = 31.4/9.8  ≈ 3.204

The time taken to reach the maximum height rounded to three significant figures = t ≈ 3.20 seconds

The law in South Africa, including the constitution, serves the interests of the dominant class, which historically has been the white minority. During apartheid, the law was used to enforce segregation and discrimination against the majority black population.

While the constitution and laws have since been revised to promote equality and protect human rights, there are still systemic issues that continue to serve the interests of the wealthy and powerful.

For example, land ownership remains highly concentrated in the hands of a few, and the legal system can be slow and expensive, making it difficult for marginalized communities to access justice. Additionally, the legacy of apartheid-era policies and practices continues to impact access to education, healthcare, and economic opportunities for many black South Africans.

Overall, while progress has been made in addressing inequality and promoting social justice, the law in South Africa still reflects the interests of the dominant class and requires continued efforts to ensure that it serves the needs of all citizens.

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Given,

Mass of basketball is 2 kg.

Mass of kickball is 1.32 kg

The initial velocity of the basket ball is 2.37m/s.

The final velocity of the kickball is 1.5 m/s

By conservation of momentum,

The velocity of the basketball is 1.38 m/s

Answer:

1500 N

Explanation:

• Initial velocity, u = 12 m/s

• Final velocity, v = 20 m/s

• Time taken, t = 6.4 s

• Mass, m = 1200 kg

\(\longrightarrow\) F = ma

a = (v – u)/t, so

\(\longrightarrow\) F = 1200 × (20 – 12)/6.4

\(\longrightarrow\) F = 1200 × 8/6.4

\(\longrightarrow\) F = 1200 × 80/64

\(\longrightarrow\) F = 1200 × 40/32

\(\longrightarrow\) F = 1200 × 20/16

\(\longrightarrow\) F = 300 × 20/4

\(\longrightarrow\) F = 300 × 5

\(\longrightarrow\) F = 1500 N (Answer)

The length of the blades required to capture 200 kW of wind power during summer is approximately 19.7 meters.

Power density of wind in winter and summer:

The power density of wind is given by:

P = 0.5 * ρ * A * v²

where P is the power density, ρ is the air density, A is the area perpendicular to the wind direction, and v is the wind speed.

The wind turbines are placed perpendicular to the direction of the wind. The air density ρ can be approximated as 1.225 kg/m³ at sea level and is reduced at higher altitudes. For the Snoqualmie pass area, we can use the approximation that the air density decreases by about 10% for every 1000 m increase in altitude. Therefore, the air density at 920 m above sea level can be estimated as:

ρ = 1.225 * (0.9)^(920/1000) = 1.044 kg/m³

a) Winter:

The average temperature during winter is -4°C or 269 K. Using the ideal gas law, we can calculate the air density as:

ρ = P / (R * T)

where P is the atmospheric pressure, R is the gas constant, and T is the temperature in Kelvin. The atmospheric pressure at 920 m above sea level can be approximated as 88.3 kPa. The gas constant R is 287 J/(kg*K). Therefore, we get:

ρ = 88.3 * 1000 / (287 * 269) = 1.15 kg/m^3

The power density of wind during winter can be calculated as:

P = 0.5 * 1.15 * A * 15³ = 86.625 A

b) Summer:

The average temperature during summer is 18°C or 291 K. Using the same method as above, we can calculate the air density as:

ρ = 80.8 * 1000 / (287 * 291) = 0.96 kg/m^3

The power density of wind during summer can be calculated as:

P = 0.5 * 0.96 * A * 15³ = 57.6 A

Therefore, the power density of wind is higher during winter than summer.

Length of blades to capture 200 kW of wind power during summer:

The power that can be extracted from the wind by a wind turbine is given by:

P = 0.5 * ρ * A * v³ * Cp

where Cp is the coefficient of performance, which is the fraction of the available wind power that can be extracted by the wind turbine. Assuming a coefficient of performance of 30%, we can calculate the area of the blades required to capture 200 kW of wind power during summer as:

A = (200 * 10^3) / (0.5 * 0.96 * 15^3 * 0.3) = 96.3 m³

Assuming the shape of the blade is a rectangular wing with a width of 1 meter, we can calculate the length of the blade as:

L = 2 * sqrt(A / pi) = 19.7 meters

Therefore, the length of the blades required to capture 200 kW of wind power during summer would be approximately 19.7 meters.

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(a) The force required to remove the sheet increases with increase in speed due to change in magnetic flux.

(b) The area in the magnetic field changes as the sheet is being put in between the poles. Thus, a force would be required to put the sheets.

When the sheet is pulled out, from the electromagnet there is change in magnetic flux given as follows;

Ф = BA

where;

emf = dФ/dt

F = qVB

Thus, the force required to remove the sheet increases with increase in speed due to change in magnetic flux.

Also, the area in the magnetic field changes as the sheet is being put in between the poles. Thus, a force would be required to put the sheets.

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Molecular Orbital Theory (MOT) is a key concept in understanding chemical bonding, and it explains the formation of bonds through the interaction of atomic orbitals. The essential feature of MOT responsible for bond formation is the concept of constructive and destructive interference between the overlapping atomic orbitals.

When two atoms approach each other, their atomic orbitals overlap and combine to form molecular orbitals. These molecular orbitals can be bonding or antibonding, depending on the nature of their interaction. Constructive interference occurs when the wave functions of the atomic orbitals combine in-phase, resulting in a lower energy molecular orbital with electron density concentrated between the nuclei. This increased electron density strengthens the electrostatic attraction between the positively charged nuclei and the negatively charged electrons, forming a stable chemical bond.

On the other hand, destructive interference occurs when the wave functions of the atomic orbitals combine out-of-phase, leading to the formation of a higher energy antibonding molecular orbital. In this case, electron density is reduced between the nuclei, creating a node that weakens the electrostatic attraction and destabilizes the bond. Electrons in antibonding orbitals can counteract the bonding effect of electrons in bonding orbitals.

Bond order, a measure of bond strength, is determined by the difference between the number of electrons in bonding and antibonding orbitals. A positive bond order signifies a stable bond, while a zero or negative bond order indicates that the bond is not formed or is weak.

In summary, the formation of molecular orbitals through constructive and destructive interference between atomic orbitals is the key feature of MOT responsible for bond formation. Bonding orbitals result in stable chemical bonds, while antibonding orbitals can weaken or prevent bonds from forming.

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The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:

\($$F=k\frac{q_1q_2}{r^2}$$\)

where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:

\($$E=\frac{kq}{r^2}$$\)  where k is the Coulomb constant.

So, let's calculate the electric field due to each charge separately and then add them up:

For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)

For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:

\($$E_2=\frac{kq_2}{r^2}\)

\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)

The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.

To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)

Substituting the values of E1 and E2:

\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)

net comes out to be -1.5×10⁴ N/C.

Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

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Add varying numbers of weights to M1 and measure the speed of the car.

Add varying numbers of weights to M2 and measure the speed of the cart.

In order to test the changing amount of force that is acting on the object has effect on the average speed of the object we have to change the amount of weight on the object and allows it to move to a certain point in this way we can check the effect of changing amount of weight on the speed of the object.

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To calculate the cost of delivering 10 kW of power to a home 100 miles away, we can start by drawing a schematic of the power transmission process.

The power is generated at a generating station with a voltage of less than 35,000 V. It is then stepped up using a transformer to a higher voltage of typically 345,000 V for transmission through power lines. Next, it is stepped down to 13,800 V for local transmission and finally, another step down transformer is used to bring the voltage down to 120 V for residential customers.

Now, let's calculate the cost per unit time to deliver 10 kW to the house.

First, we need to convert 10 kW to kilowatt-hours (kWh). Since power is measured in watts and time is measured in hours, we can divide 10 kW by the power factor (PF) to get the energy consumed in one hour.

The power factor is the ratio of real power (watts) to apparent power (volt-amperes). In this case, we assume an ideal power factor of 1, so the real power and apparent power are the same.

Since power is given in kilowatts (kW), we can convert it to watts by multiplying by 1000. So, 10 kW is equal to 10,000 watts.

Now, we need to find the energy consumed in one hour (kWh). We can use the formula:

Energy (kWh) = Power (watts) * Time (hours) / 1000

Plugging in the values, we get:

Energy (kWh) = 10,000 watts * 1 hour / 1000 = 10 kWh

Next, we need to calculate the cost of 10 kWh at a rate of 10 cents per kWh.

Cost = Energy (kWh) * Rate ($/kWh) = 10 kWh * $0.10/kWh = $1

So, it would cost $1 per unit time to deliver 10 kW to a house located 100 miles away when transmitting electricity at 120 V and 60 Hz.

Now, let's move on to the power factor in the problem above. Since we assumed an ideal power factor of 1, the power factor is 1.

If a large capacitor of 1F is used in parallel with the line coming into the house to filter out noise, we need to calculate the power lost in delivery. Assuming the same 10 kW load in parallel with the capacitor, we need to consider the power factor again.

In this case, the power factor will be affected by the reactive power of the capacitor. Reactive power is caused by the reactive components in the circuit, such as capacitors and inductors. To calculate the power factor, we need to know the reactive power and the apparent power.

The apparent power can be calculated using the formula:

Apparent Power (VA) = Voltage (V) * Current (A)

Since the load is parallel with the capacitor, the current will be the same for both the load and the capacitor. Therefore, the apparent power will be the same as the power consumed by the load.

Now, let's consider how to reduce the power factor and make it unity. The power factor can be improved by adding a power factor correction device, such as a capacitor or an inductor, to the circuit. These devices help to offset the reactive power and bring the power factor closer to unity (1).

In terms of resonance in a LCR circuit model, the inductor plays a role in storing and releasing energy in the form of a magnetic field. When the circuit is at resonance, the inductor and capacitor exchange energy back and forth, resulting in a high level of voltage and current oscillation. This can lead to increased losses and lower power factor if not properly managed.

The inductor current is determined by the inductance value and the rate of change of current flowing through it. It opposes changes in current, and in a resonant circuit, it helps to maintain a stable current flow.

The capacitor current is determined by the voltage across the capacitor and the capacitance value. It leads the voltage and helps to maintain a stable voltage across the capacitor.

to calculate the cost of delivering 10 kW to a home 100 miles away, we need to consider the power factor, energy consumption, and rate. Adding a large capacitor in parallel with the load can affect the power factor and result in power losses. Power factor can be improved by adding power factor correction devices. The inductor and capacitor in a resonance circuit play roles in storing and releasing energy.

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Answer:

Moving a magnet around a coil of wire, pushes the electrons in the wire and creates an electrical current.

In conclusion, when an air-track glider is attached to a spring and pulled to the right before being released from rest, it undergoes simple harmonic motion.

The air-track glider is attached to a spring and is pulled to the right before being released from rest. When the glider is released, it will experience simple harmonic motion due to the spring's restoring force.

During simple harmonic motion, the glider will oscillate back and forth along the air track. The motion is characterized by a period (T) and a frequency (f), which depend on the mass of the glider (m) and the spring constant (k).

The period of the motion, T, is the time it takes for the glider to complete one full oscillation. It can be calculated using the formula T = 2π√(m/k). The frequency, f, is the number of oscillations per second and is the reciprocal of the period (f = 1/T).

As the glider is released from rest, it will initially move to the right due to the pull. As it moves, the spring will stretch and create a restoring force that pulls the glider back towards the equilibrium position.

The glider will then pass the equilibrium position, compressing the spring and causing a restoring force that opposes the glider's motion.

This back and forth motion continues until the energy of the glider is dissipated due to friction or other factors. The glider will gradually come to a stop at the equilibrium position.

In conclusion, when an air-track glider is attached to a spring and pulled to the right before being released from rest, it undergoes simple harmonic motion.

This motion is characterized by oscillations back and forth along the air track, with a period and frequency determined by the mass of the glider and the spring constant.

The glider experiences a restoring force from the spring that opposes its motion, causing it to oscillate until energy is dissipated and it comes to a stop at the equilibrium position.

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Answer:

For electrostatic paint to be applied, the vehicle needs to be grounded and positively charged. This creates a magnetic attraction to the negatively charged paint. Due to this charge, when the paint leaves the nozzle, it is attracted to the vehicle's charge and will stick to it.

Explanation:

Answer:

1

Explanation:

Answer: Snowy and rainy

Explanation:

Absorbance is a unitless quantity, However, it is often expressed in optical density units (OD) or absorbance units (AU) for convenience.

The amount of light absorbed by a sample as it passes through it is measured by absorbance, also known as optical density. The logarithm of the ratio of incident light to transmitted light is used to express it. In spectrophotometry, a method for determining the intensity of light flowing through a substance at a particular wavelength, absorbance is frequently utilized. More light is absorbed by the sample at greater absorbance levels, which suggests that there are more absorbing molecules or substances present. Since contaminants or other chemicals can alter the amount of light absorbed, absorbance can also be used to assess the purity or quality of a sample.

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A planes average speed between two cities is 610 km/hr. If the trip takes 2. 25 hrs, then the distance covered by a plane is  1372.5 kilometers.

To calculate the distance the plane flies, we can use the formula:

Distance = Speed × Time

Given that the average speed of the plane is 610 km/hr and the trip takes 2.25 hours, we can substitute these values into the formula to find the distance.

Distance = 610 km/hr × 2.25 hrs

To multiply these values, we need to align the units correctly. By canceling out "hrs" in the numerator and denominator, we get:

Distance = 610 km × 2.25

Multiplying 610 km by 2.25 gives us:

Distance = 1372.5 km

Therefore, the plane flies a distance of 1372.5 kilometers.

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Given that a plane's average speed between two cities is 610 km/hr and the trip takes 2.25 hrs. We are to find the distance covered by the plane The plane flies 1372.5 km

Let's find the solution to this problem .The formula for distance, speed and time isd

= s * there,

d = distance covered by the planes

= speed t

= time taken

Substituting the given values, we have610 × 2.25 = 1372.5 km

Hence, the plane flies 1372.5 km.

Given that a plane's average speed between two cities is 610 km/hr and the trip takes 2.25 hrs. We are to find the distance covered by the plane

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