the diagram shows a triangle drawn between a pair of parallel lines
Find value of x and y​

a. The unemployment rate is 20%.

b. The labor-force participation rate is 60%.

According to the question,

Working age population- 100,000

Labour force - 60,000

Unemployed - 12000 instructions

a) The unemployment rate is the percentage of the labor force that is unemployed and it is calculated as follows:

Unemployment Rate = \(\frac{Number of unemployed People}{Labor force}\) × 100

When an unemployed population is 12,000 and the labor force is 60,000,

the unemployment rate is  = \(\frac{12000}{60000}\) × 100 = 20%

b) labor force participation rate is the percentage of working adult population that participates in labor either by actively looking for a job, or working. It is calculated as follows:

Labor Force Participation Rate = \(\frac{Labor force}{working age population}\) × 100

When the labor force is 60,000 and the working-age population is 100,000

Labor Force Participation Rate = \(\frac{60000}{100000}\) × 100 = 60%

So, a. The unemployment rate is 20%.

b. The labor-force participation rate is 60 %.

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Answer:

8 and 5

Step-by-step explanation:

8 - 5 = 3

8 + 5 = 13

Answer:

8 and 5

Step-by-step explanation:

8 - 5 = 3

8 + 5 = 13

5 equilateral triangles.

Hope this helps.

The probability that at least one of them is a girl is 0.9781

From the question, we have the following parameters that can be used in our computation:

P(Boy) = 0.529

Number of selection, n = 6

Using the above as a guide, we have the following:

P(At least 1 girl) = 1 - P(No girl)

Substitute the known values in the above equation, so, we have the following representation

P(At least 1 girl) = 1 - (0.529)^6

Evaluate

P(At least 1 girl) = 0.9781

Hence, the probability is 0.9781

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Each model should be produced on a weekly basis to maximize net profit is $75,900.

What is Net profit?

In both business and accounting, net income or profit is an entity's revenue less cost of goods sold, costs, depreciation and amortisation, interest, and taxes for a certain accounting period.

As given,

Number of products sold:

T ≥ 1.5G

Maximize Profit Z = 150T + 130G

Labor Constraint:

Labor hours Available:

Production Department:

Number of labor hours available per day = 58 × 7 = 406

Number of days in a week = 5

Number of lobor ours available per week = 406 × 5 = 2030

Assembly Department:

Number of labor hours available per day = 25 × 7 = 175

Number of days in a week = 5

Number of labor hours available per week = 175 × 5 = 875.

Labor hours Required:

Labor hours required for G1 model:

Labor hours required at Production department = 3.5G

Labor hours required at assembly department = 2G

Labor hours required for T1 model:

Labor hours required at Production department = 4T

Labor hours required at Assembly department = 1.5T

Total labor hours required at Production department = 3.5G + 4T

Total labor hours required at Assembly department = 2G + 1.5T.

Constraint:

Labor hours required ≤ Labor hours Available.

Production department Labor constraint

3.5G + 4T ≤ 2030

Assembly department Labor constraint:

2G + 1.5T ≤ 875

The function:

Maximum Profit Z = 150T +130G

Constraint:

3.5G +4T ≤ 2030

2G + 1.5T ≤ 875

T ≥ 1.5G

Suppose that for example:

10.5G +12T = 6090

 16G + 12T = 7000

Solve both equations simultaneously,

5.5G = 7000 - 6090

5.5G = 910

    G = 910/5.5

    G = 363

Since, T > G

Hence,

T = 363,

G = 165

Calculate Profit:

150T + 130G = 150 × 363 + 130 × 165

                     = 54450 + 21450

                     = 75900

Hence, each model should be produced on a weekly basis to maximize net profit is $75,900.

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Answer:39.7

Step-by-step explanation:DUDE chilll I got you the answer is

The alternative hypothesis that will give the smallest P-value is a. μd ​≠ 0.

This is because the alternative hypothesis μd ​≠ 0 is a two-tailed test, meaning that it considers both the possibility of μd being less than 0 and greater than 0.

This means that there are two areas in the tail of the distribution that are considered when calculating the P-value, leading to a smaller P-value.The other two alternative hypotheses, μd ​< 0 and μd ​> 0, are one-tailed tests and only consider one area in the tail of the distribution, leading to larger P-values.

Therefore, the alternative hypothesis μd ​≠ 0 will give the smallest P-value.

A p-value is a statistical measurement used to validate a hypothesis against observed data. A p-value measures the probability of obtaining the observed results, assuming that the null hypothesis is true. The lower the p-value, the greater the statistical significance of the observed difference.

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Answer:

graph 1 perpendicular graph 2 neither graph3 neither graph 4 neither

graph 1 is perpendicular because of how the lines perfectly intersect

graph 2 is parrallel because those lines will never intersect to matter have far they are extended

graph 3 is neither

graph 4 is also neither

The angle that has the terminal point coordinates of (√2/2,-√2/2) is 7π/4

The terminal point is given as:

Point = (√2/2,-√2/2)

On a unit circle, we have:

(cos(θ), sin(θ)) = (x,y)

This means that:

(cos(θ), sin(θ)) = (√2/2,-√2/2)

By comparison, we have:

cos(θ) = -√2/2

sin(θ) = √2/2

Using the sine angle, we have:

sin(θ) = √2/2

Take the arc sin of bot sides

θ = 7π/4

Hence, the angle that has the terminal point coordinates is 7π/4

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Answer:

:)

Step-by-step explanation:

There is an infinitive ammount of choices. Here is some:

\( - 6 \div 16\)

\(6 \div ( - 16)\)

\(9 \div ( - 24)\)

and many many many more. Just pick one.

The expression can be anything, you just need the quotient to be -0,375

Hope I helped :)

:)

Answer: 152 units square 2

Step-by-step explanation:

Answer:

x=6   x=3

Step-by-step explanation:

x^2-9x+18=0

Factor

What 2 numbers multiply to 18 and add to -9

-6*-3 = 18

-6-3 = -9

(x-6) (x-3) =0

Using the zero product property

x-6 =0  x-3 =0

x=6   x=3

True, the estimated p-hat is a random variable and will vary slightly with different samples.

The estimated p-hat is the proportion of successes in a sample, used to estimate the population proportion. As it is calculated based on a sample, the p-hat will vary slightly with different samples. This is because each sample is unique and may not perfectly represent the population. Therefore, the estimated p-hat is considered a random variable. However, as the sample size increases, the variability in the p-hat decreases, leading to a more accurate estimate of the population proportion.

In summary, the estimated p-hat is a random variable and will vary slightly with different samples. It is important to consider the sample size when interpreting the variability of the p-hat and its accuracy in estimating the population proportion.

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The probability that Marshall wins a prize on his second spin =  0.1875

Consider an event X = the number of spins until Marshall wins a prize.

Given that a prize wheel with 4 segments of equal size, one of which is labeled winner.

So, the sample space n = 4

For given event x, the possible outcomes = 1

Using the formula of probability,

p = x/n

p = 1/4

p = 0.25

So, the probability of success p = 0.25

q = 1 - p

q = 1 - 0.25

q = 0.75

To find the probability that Marshall wins a prize on his 2nd spin.

Using formula, \(P(X = k) = (1 - p)^{k-1}p\)

For  k = 2,

\(P(X = 2) = (1 - 0.25)^{2-1}\times 0.25\)

P(X = 2) = 0.75 × 0.25

P(X = 2) = 0.1875

Thus, the required probability is  0.1875

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Answer:

0.4

Step-by-step explanation:

C = 1/5

5 x 1/5 x 2 + 7 x 1/5 +1 = 2 x 1/5 or 0.4

The area between the curves x = 28 − 7y² and x = 7y² − 28 is 0.

By counting the number of squares on a piece of paper with grids (square shaped), and using basic formulas, it is possible to determine the area of shapes like quadrilaterals and circles, which are 2D shapes.

To find the area between the curves x = 28 − 7y² and x = 7y² − 28, we need to first find the points of intersection.

Setting the two equations equal to each other, we get:

28 - 7y² = 7y² - 28

Simplifying and solving for y, we get:

y = ±2

So, the two curves intersect at y = 2 and y = -2.

Next, we need to determine which curve is on top in each interval. To do this, we can evaluate the y-values for each curve at y = 0 and y = 2:

For x = 28 − 7y²:

- At y = 0, x = 28

- At y = 2, x = 0

For x = 7y² − 28:

- At y = 0, x = -28

- At y = 2, x = 28

So, the curve x = 28 − 7y² is on top for y between 0 and 2, and the curve x = 7y² − 28 is on top for y between -2 and 0.

Using the formula for finding the area between two curves, we can now calculate the total area:

A = ∫(-2)²[28 - 7y² - (7y² - 28)] dy + ∫02[(7y² - 28) - (28 - 7y²)] dy

Simplifying, we get:

A = 2∫02(14y² - 28) dy

A = 2[\(14y^{3/3\) - 28y]0²

A = 2(0 - 0)

A = 0

Therefore, the area between the curves x = 28 − 7y² and x = 7y² − 28 is 0.

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Answer:

7,650 lb

Step-by-step explanation:

each ton is 2,000 pounds, and there is 4.

so 8,000 -350=7,650

The solution of the subtraction operation is equal to 7,650 lb

It is defined as the conversion from one quantity unit to another quantity unit followed by the process of division, and multiplication by a conversion factor.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS - Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

We need to Subtract 350 lb. from 4 tons.

We know that each ton is 2,000 pounds, and there is 4.

so, the subtraction is;

8,000 -350=7,650

The answer is 7,550 lb. so the correct option is D.

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Answer:

Hi there! Your answer is C and D

Step-by-step explanation:

You might know that a Rhombus is a special type of parallelogram whose all sides are equal. The difference between a square and a rhombus is that all angles of a square are right angles, but the angles of a rhombus need not be right angles. So, a rhombus with right angles becomes a square. B is not because all sides are equal and it has right angles. A is not because it does not have equal sides. I hope this helps! :]

The expected population size be after two generations which has a current size of 150 and λ of 1.2 is 216.

Nt = N₀ × λ^t

Nt = Population size at generation t

N₀ = Current population size

t = Number of generations

λ = Finite rate of increase

λ = 1.2

N₀ = 150

Nt = 150 × 1.2²

Nt = 150 × 1.44

Nt = 216

Population size is defined as the number of individuals present in a designated region. Finite rate of increase is the ratio of population size from increase from one year to the next.

Therefore, the expected population size be after two generations is 216

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By solving the simultaneous equation value of x = -5, -2 and y = 1, 4.

How to solve simultaneous equation?
1. Use the elimination method to get rid of one of the variables.

2. Find the value of one variable.

3. Find the value of the remaining variables using substitution.

Given that,

y = \(x\)+3

y = \(x^{2} +5x-2\)

First both equation are equal

\(x+3 = x^{2} +5x-2\\x^{2} +4x-5 =0\\x^{2} +5x-x-5=0\\x(x+5)-1(x+5)=0\\x=1, -5\)

Then, substitute the value of x in y =x+3

y = x+3

at x= -5

y= -2

at x= 1

y = 1+3

y = 4

Hence, By solving the simultaneous equation value of x = -5, -2 and y = 1, 4.

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Answer:

Step-by-step explanation:

10.8

Answer:

Janet's dog weighs 10.8 pounds more

Step-by-step explanation:

When analyzing categorical data, it is often useful to examine the relationship between two variables. Crosstabs, or contingency tables, are commonly used to display the counts of observations in each combination of the two variables. However, these raw counts can be difficult to interpret, especially if the totals for each variable are different.
By transforming the counts into percentages of row or column totals, we can better understand the patterns and relationships in the data. Percentages allow us to compare the proportions of one variable within each category of the other variable, regardless of the total number of observations. This can help us identify any trends or patterns in the data that may not be immediately apparent from the raw counts.

For example, suppose we have a crosstab of gender and favorite color. The raw counts may show that more females than males prefer blue, but it's difficult to know if this difference is meaningful without knowing the total number of males and females in the sample. By transforming the counts to percentages of row totals, we can see that 40% of females prefer blue, while only 30% of males do. This suggests that there may be a relationship between gender and favorite color.

Overall, transforming raw counts into percentages of row or column totals can help us better understand the relationship between two categorical variables, especially when the totals are different.

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Answer:

12.06

Step-by-step explanation:

Answer:

The price of 2lb's of steak is 15.86

Step-by-step explanation:

Multiply

The diameter of the hemisphere with a volume of 557 m³ is approximately 12.8 m, to the nearest tenth of a meter.

The volume of a hemisphere can be calculated using the formula V = (2/3)πr³, where V is the volume and r is the radius. Given that the volume of the hemisphere is 557 m³, we can find the radius by solving for r:

557 = (2/3)πr³

To find the radius, first, we need to isolate r³ by multiplying both sides by 3/(2π):

r³ = (3 * 557) / (2 * π)

r³ ≈ 265.18

Now, take the cube root of both sides to find the radius:

r ≈ 6.4 m

To find the diameter, simply multiply the radius by 2:

d ≈ 2 * 6.4
d ≈ 12.8 m

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The area of the square, which has an apothem measuring 2.5 cm and a perimeter of 20 cm is 25 cm².

Area of square is the square of its side's length. It can be given as,

\(A=a^2\)

Here, (a) is the length of the side of the square

A square has an apothem measuring 2.5 cm and a perimeter of 20 cm. The perimeter of the square is 4 times the sides of the square.

Let suppose the side of this square is a cm. thus,

\(4a=P\\4a=20\\a=\dfrac{20}{4}\\a=5\rm\; cm\)

The area of the square is,

\(A=5^2\\A=25\rm\; cm^2\)

Hence, the area of the square, which has an apothem measuring 2.5 cm and a perimeter of 20 cm is 25 cm².

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Answer:

25cm

Step-by-step explanation:

e2020

The Mean Value Theorem (MVT) is a theorem in calculus that relates the derivative of a function to the average rate of change of the function over a given interval.

The Mean Value Theorem states that if a function f is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), then there exists a number c in (a, b) such that:

f'(c) = (f(b) - f(a)) / (b - a)

To find all numbers c that satisfy the conclusion of the Mean Value Theorem, we need to check if the hypotheses of the theorem are satisfied, i.e. if the function is continuous on the closed interval and differentiable on the open interval.

Without the specific function and interval provided, we cannot determine all numbers c that satisfy the conclusion of the Mean Value Theorem. Please provide more information so we can help you better.

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Answer:

Carlos graphed the perpendicular bisector of AB.

Step-by-step explanation:

Given a line segment AB drawn in a coordinate plane. The set of points that are the same distance from points A and B divides the line segment AB into two equal parts.

This line is referred to as the perpendicular bisector of AB.

Therefore, Carlos graphed the perpendicular bisector of AB.

There are 40 such bit strings.

To count the number of bit strings of length seven that either begin with two 0s or end with three 1s, we need to use the principle of inclusion-exclusion.

Let A be the set of bit strings that begin with two 0s, and let B be the set of bit strings that end with three 1s.

Then, we want to find the size of the set A ∪ B, which consists of bit strings that satisfy either condition.

The size of A can be calculated as follows:

since the first two digits must be 0, the remaining five digits can be any combination of 0s and 1s,

so there are \(2^5 = 32\) possible strings that begin with two 0s.

Similarly, the size of B can be calculated as follows:

since the last three digits must be 1, the first four digits can be any combination of 0s and 1s,

so there are\(2^4 = 16\) possible strings that end with three 1s.

However, we have counted the strings that both begin with two 0s and end with three 1s twice.

To correct for this, we need to subtract the number of strings that belong to both A and B from the total count.

The strings that belong to both A and B must begin with two 0s and end with three 1s, so they have the form 00111xxx,

where the x's can be any combination of 0s and 1s.

There are \(2^3 = 8\) such strings.

Therefore, the total number of bit strings of length seven that either begin with two 0s or end with three 1s is:

|A ∪ B| = |A| + |B| - |A ∩ B| = 32 + 16 - 8 = 40.

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Answer:

9, 11, and 19

Step-by-step explanation:

9, 11, and 19 are the only plausible answers because there were only 2 periods where the phone was at 100% (other than when the graph started) and these are the only hours that fell within those periods..