the density of an object relies on both the blank of the object

Answer:

translate? ill edit this later

Explanation:

Three types of end products produced during fermentation lactic acid, formic acid, acetic acid durham tube to detect gas produced by microorganisms

Fermentation reacts NADH with an endogenous and organic electron acceptor and common end products of bacterial fermentation include lactic acid, formic acid, acetic acid, butyric acid, butyl alcohol, acetone, ethyl alcohol, carbon dioxide, and hydrogen and fermentation reactions are detected by the color change of a pH indicator when durham tube are mainly used in microbiology to detect gas by microorganism and gas production helps to identify the type of organism and these special tubes are placed upside down in bigger test tubes to detect the presence of gas production

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Answer to Question #96220 in Molecular Physics | Thermodynamics for Kaleesh

Answers>Physics>Molecular Physics | Thermodynamics

Question #96220

a) Determine the enthalpy changes, ΔH for the reaction below, given the following reactions and subsequent ΔH values. Please rewrite the amended chemical reaction equation again.

N2H4 (l) + CH4O (l) CH2O (g) + N2 (g) + 3H2 (g)

2NH3 (g) N2H4 (l) + H2 (g) ΔH = 22.5kJ

2NH3 (g) N2 (g) + 3H2 (g) ΔH = 57.5 kJ

CH2O (g) + H2 (g) CH4O (l) ΔH = 81.2 kJ

b) Given that the enthalpy of vaporization for water as below:

H2O (l) H2O (g) ΔH vap = 44.0 kJ mol-1

Calculate enthalpy ΔH for each of the following processes:

i) Evaporating 3.00 moles of water

ii) Evaporating 3.00 grams of water

i) Condensing 20.0 grams of water

(3 Marks)

c) Use the enthalpy of formation data to calculate the enthalpy of the reaction below.

2C2H6 (g) + 7O2 6H2O (g) + 4CO2 (g)

Answer: The number of neutrons will increase as we move from left to right in a periodic table.

Explanation:

Atomic number is equal to the number of protons.

Mass number is the sum of number of neutrons and number of protons.

As we move from left to right, both the atomic number and mass number increases.

For example: As we move from Lithium to berrylium to boron to carbon to nitrogen to oxygen to fluorine to neon , the number of neutrons increase from 4 to 5 to 6 to 6 to 7 to 8 to 10 to 10.

Thus the number of neutrons will also increase as we move from left to right in a periodic table.

Below is an example of the open-chain structure (as a Fischer projection) of 2-deoxy-D-glucose.

The Fischer projection should be aligned vertically, with the carbon atoms at the top and bottom and the oxygen atoms on the left and right. The chiral carbon atoms should be labeled and any hydrogens attached to them should be explicitly shown. Note that bonds to other hydrogens should not be shown.

O O | /| | / | | H | H | H | | H | | H | | H | H | H | | H | |H | C--C--C--C--C

The diagram provided is a Fischer projection of 2-deoxy-D-glucose. The vertical alignment of the carbon atoms at the top and bottom, and the oxygen atoms on the left and right is correct. The chiral carbon atoms should be labeled and any hydrogens attached to them should be explicitly shown. Note that bonds to other hydrogens should not be shown.

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Answer:

Temperature = 6.91K

Explanation:

Temperature = T

Number of Moles = 2.49moles

Volume = 1.0L

Pressure = 143kPa

R = 8.31kPa*L/mol.K

From ideal gas equation,

PV = nRT

P = pressure of the ideal gas

V = volume which the gas occupies

n = number of moles of the gas

R = ideal gas constant

T = temperature of the ideal gas

PV = nRT

T = PV / nR

T = (143 * 1) / (2.49 * 8.31)

T = 143 / 20.6919

T = 6.91K

The temperature of the gas is 6.91K

The value of Kb for the conjugate base of benzoic acid (C₆H₅COO⁻) is 1.59 x 10⁻¹⁰.

To find the value of Kb for the conjugate base of benzoic acid (C₆H₅COO⁻), we need to use the relationship between Ka and Kb. Ka is the acid dissociation constant and Kb is the base dissociation constant, and they are related by the equation Ka x Kb = Kw, where Kw is the ion product constant of water (1.0 x 10⁻¹⁴).

First, we need to write the chemical equation for the dissociation of benzoic acid:

C₆H₅COOH + H₂O ⇌ C₆H₅COO⁻ + H₃O⁺

The Ka expression for benzoic acid is:

Ka = [C₆H₅COO⁻][H₃O⁺] / [C₆H₅COOH]

where [ ] denotes concentration.

Since benzoic acid is a weak acid, we can assume that the concentration of H₃O⁺ is negligible compared to the initial concentration of benzoic acid. Therefore, we can simplify the expression to:

Ka = [C₆H₅COO⁻][H₃O⁺] / [C₆H₅COOH] ≈ [C₆H₅COO⁻][H₃O⁺] / [initial concentration of C₆H₅COOH]

Rearranging this equation, we get:

[C₆H₅COO⁻] = (Ka x [initial concentration of C₆H₅COOH]) / [H₃O⁺]

Now we can use the relationship between Ka and Kb to find the value of Kb for C₆H₅COO⁻. Since the conjugate base is formed by the loss of a proton from the acid, we know that:

Ka x Kb = Kw

Rearranging this equation, we get:

Kb = Kw / Ka

Substituting the values, we get:

Kb = (1.0 x 10⁻¹⁴) / (6.30 x 10⁻⁵)

Kb = 1.59 x 10⁻¹⁰

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Answer:

Electron microscopy and scanning tunneling microscopes contributed to the understanding of atoms in understanding atomic structure.

The electron microscope has magnifications of about 100,000x.

This helped the scientists to have accurate image groupings of the atoms. Scanning tunnel microscope helped scientists to have the images of groups of atoms.

A monotonic sequence is a sequence of numbers in which the terms consistently increase or consistently decrease as the sequence progresses. The sequence an = 4ne^(-7n) is decreasing. To determine if the sequence is bounded, we need to analyze the behavior of the sequence as n approaches infinity.

In the monotonically increasing sequence, each term is greater than or equal to the previous term. In the monotonically decreasing sequence, each term is less than or equal to the previous term. In the non-monotonic sequence, the terms do not consistently increase or decrease. As n approaches infinity, the term 4ne^(-7n) approaches 0. Therefore, the sequence is bounded from above by 0. However, the sequence is not bounded from below as it continues to decrease indefinitely. Therefore, the sequence is bounded above but not bounded below.

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Answer:

106.5 J, and it was lost.

Explanation:

To calculate the amount of heat transferred, we can use the following formula:

Q = m * c * ΔT

where Q is the amount of heat transferred, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

For graphite, the specific heat capacity is approximately 0.71 J/g°C.

So we have:

Q = 15.0 g * 0.71 J/g°C * (-10°C)

Q = -106.5 J

The negative sign of the answer indicates that the graphite lost heat, since its temperature decreased. Therefore, the heat was transferred from the graphite to its surroundings.

So the amount of heat transferred from the graphite was 106.5 J, and it was lost.

Answer:

microbiology

Explanation:

Answer:

O2 + 4e- --> O2 4-

Cu --> 2e- + Cu2+

Explanation:

Oxygen is reduced and copper is oxidized.

We can thus write the half reactions:

O2 + 4e- --> O2 4-

Cu --> 2e- + Cu2+

According to molar concentration, the concentration of the acid is 0.064 M.

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.In case of 2 solutions it is calculated as, M₁V₁=M₂V₂ which on substitution gives M₂=0.04×60/37=0.064 M.

Thus, the concentration of the acid is 0.064 M.

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Answer:n some ways, upwelling can be a mixed blessing to coastal ecosystems. It can infuse coastal waters with critical nutrients that fuel dramatic productivity,

Explanation:

Coral reefs is the marine ecosystem which depends on upwelling from the seafloor to maintain its high productivity.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.

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Answer:

8,040  

0.0300  

699.5  

2.000 x 102

0.90100  

90, 100  

4.7 x 10-8  

10,800,000.0  

3.01 x 1021

0.000410

Explanation:

First remember the following rules of determining the last significant place value :

1. The digits from 1-9 are all significant and zeros between significant digits are also significant.

2.  The trailing or ending zeroes are significant only in case of a decimal number otherwise they are ignored. However starting zeroes of such a number are not significant.

Now observing above rules, lets determine the location of the last significant place value of each given example. I am determining the location by turning the last significant place to bold.

1) 8,040

8,040

Location of the last significant place value is 3 and bar is over last significant digit that is 4. Number is not decimal so ending zero is ignored. Every non zero digit is a significant.

2)  0.0300

0.0300

Location is 3 and bar is over 0. Number has a decimal point so ending zero is not ignored but starting zeroes are ignored.

3) 699.5

699.5

Location is 4 and bar is over 5.

4) 2.000 x 10²

2.000 x 10²

Location is 4 and bar is over 0. This is because the number is decimal so trailing zeroes cannot be ignored. Also if we convert this number it becomes:

200.0 so last significant digit is 0 and location of last significant digit is 4.

5) 0.90100

0.90100

Location is 5 and bar is over 0. This is because in a number with decimal point starting zeroes are ignored but trailing zeroes after decimal point are not ignored. So we count from 9 and last significant digit is 0.

6) 90, 100

90, 100

Location is 3 and bar is over 1. This is because it is not a number with decimal point. So the trailing zeroes are ignored. The count starts from 9 and last significant is 1.

7) 4.7 x 10⁻⁸

4.7 x 10⁻⁸

Location is 2 and bar is over 7. This is because the starting zeroes in a number with a decimal point are ignored. So the first digit considered is 4 and last significant digit is 7. If we expand this number:

4.7 x 10⁻⁸ =    0.000000047 = 0.000000047

Here the starting zeroes are ignored because there is a decimal point in the number.

8) 10,800,000.0

10,800,000.0

Location is 9 and bar is over 0.  Number has a decimal point so ending zero is not ignored and last significant figure is 0.

However if the number is like:

10,800,000. Then location would be 8 and bar is over 0.

9) 3.01 x 10²¹

3.01 x 10²¹

Location is 3 and bar is over 1. Lets expand this number first

3.01 x 10²¹ = 3.01 x 1000000000000000000000

                  = 3010000000000000000000

So this is the number:

3010000000000000000000

Since this is number does not have a decimal point so the trailing zeroes are ignored. Hence the count starts from 3 and the last significant figure is 1

10) 0.000410

0.000410

Location is 3 and bar is over 0. This is because the number has a decimal point so the ending zero is not ignored but the starting zeroes are ignored according to the rules given above. Hence the first significant figure is 4 and last significant figure is 0.

The statement that identifies an oxidation-reduction reaction is a reaction in which oxidation numbers change (option C).

A redox or oxidation-reduction reaction is a chemical reaction in which some of the atoms have their oxidation number changed.

In a chemical reaction that involves oxidation and reduction, the oxidation number of the involved ions either decreases or increases.

Therefore, the statement that identifies an oxidation-reduction reaction is a reaction in which oxidation numbers change.

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The amino acid that will move the farthest when subjected to electrophoresis at pH 7 is aspartic acid. This is because, at pH 7, aspartic acid will have a net negative charge due to its carboxyl group being deprotonated. Aspartic acid is the correct option.

This negative charge will cause it to migrate towards the positive electrode during electrophoresis, resulting in it moving the farthest. Alanine and histidine will also have charges at pH 7, but they will not be as strong as the charge on aspartic acid, so they will not migrate as far. The pl values given are not relevant to this question. Therefore, the correct answer is "I" - aspartic acid.

On the other hand, alanine and histidine may also have charges at pH 7, but the strength of their charges is not as significant as that of aspartic acid. Alanine is a neutral amino acid and would not migrate as far as aspartic acid. Histidine can be positively charged at pH 7 due to its basic side chain, but its positive charge is not as strong as the negative charge on aspartic acid.

The pI (isoelectric point) values provided in the question are not relevant because electrophoresis at pH 7 does not correspond to the pI of any of the amino acids. The question specifically asks about electrophoresis at pH 7, where aspartic acid, with its net negative charge, would migrate the farthest. Therefore, the correct answer is "I" - aspartic acid.

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Answer:

Below are some patterns in the charge for elements in each group.

Group 1 elements : 1 valence electron and form ions with charge +1

Group 2 elements : 2 valence electrons and form ions with charge + 2

Group 3 elements : 3 valence electrons and form ions with charge + 3(there are some exceptions as well)

Elements in groups 4 and 5 are unpredictable also the D block elements consist of multiple oxidation states..

Group 6 elements : 6 valence electrons, form ions with charge -2

Group 7 elements: 7 valence electrons, form ions with charge -1  

The octet rule is being followed, the elements form either ionic bond or covalent bond to fulfill it.

eg: when a K atom forms a K+ ion, the ion has the same electron configuration as the noble gas Ar (argon).

When an O atom gains 2 electrons to form the O²⁻ ion, the ion has the same electron configuration as the noble gas Ne (neon).  

Note: Boron (B) is in Group 3 but doesn't form ions.

A noticeable pattern in the charge for elements in each group of the periodic table is that: Elements in the same group have the same charge.

Discussion:

The pattern in the charge for elements in each group is characterized by the adoption of the same charge for elements in the same group irrespective of the period they are situated in.

An example is evident in the alkali metal, halogen and alkali Earth metals group.

The alkali metals lose their only Valence electron, to assume the octet configuration of the preceeding noble gas.

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69°C

Make me brainLiest for my answer

Answer: drain it

Explanation:

water expands when frozen

The total pressure inside the container would be 755 mmHg (barometric pressure) plus the partial pressure of the collected hydrogen gas.

The total pressure of all gases inside the container can be determined by adding the partial pressure of the collected gas to the barometric pressure.

Given that the barometric pressure is 755 mmHg, we need to find the partial pressure of the collected gas. Since the gas is generated by the reaction of hydrochloric acid and zinc metal, it is likely hydrogen gas (H2) that is being collected.

To find the partial pressure of hydrogen gas, we can use Dalton's Law of Partial Pressures, which states that the total pressure of a gas mixture is equal to the sum of the partial pressures of each individual gas component.

Therefore, the total pressure inside the container would be 755 mmHg (barometric pressure) plus the partial pressure of the collected hydrogen gas.

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The products of the given reactions are (i) CH3-N=N-NH3, (ii) C6H5-CO-CH2OH, and (iii) CH3-CO-CH3 and Na2CO3.

For reaction (i), CH3−C=O reacts with N2N−NH3 to form an imine, resulting in CH3-N=N-NH3.

In reaction (ii), C6H5−CO−CH3 undergoes reduction with KOH/Glycol and heat (Δ), leading to the formation of the alcohol C6H5-CO-CH2OH.

Finally, in reaction (iii), CH3COONa undergoes decarboxylation with NaOH/CaO and heat (Δ), producing the ketone CH3-CO-CH3 and the byproduct Na2CO3. Each reaction involves different mechanisms and reagents, resulting in the formation of different organic products.

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The element that we can be able to use for the experiment in place of potassium is sodium.

We know that the elements that can be found in the same group does react in the same way. Now we know that we have to look about among the options so that we would be able to know element that is in the same group as potassium.

Given that both sodium and potassium are members of group 1, we have to look out for the element that element thus we have to select sodium.

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Answer: Fe (iron)

Explanation:

the whole number next to the symbols on the periodic table that ascend in order by 1 are the atomic numbers, just look for the symbol next to the number 26.

Answer:

Ag

Explanation:

atomic 33 because it what what sence

The reaction of 18.5 g of O₂ with excess N₂H₄ produces approximately 16.2 g of N₂.

To determine the mass of N₂ produced when 18.5 g of O₂ reacts completely with excess N₂H₄, we need to use the balanced chemical equation and the molar masses of the compounds involved.

The balanced chemical equation for the reaction is as follows:

2 N₂H₄ + O₂ → 2 H₂O₂ + N₂

The molar mass of O₂ is approximately 32 g/mol, and the molar mass of N₂ is approximately 28 g/mol.

First, we calculate the number of moles of O₂:

Moles of O₂ = Mass of O₂ / Molar mass of O₂

Moles of O₂ = 18.5 g / 32 g/mol

Moles of O₂ ≈ 0.578 moles

According to the stoichiometry of the balanced equation, 1 mole of O₂ reacts to produce 1 mole of N₂. Therefore, the number of moles of N₂ produced is also approximately 0.578 moles.

Finally, we calculate the mass of N₂:

Mass of N₂ = Moles of N₂ × Molar mass of N₂

Mass of N₂ = 0.578 moles × 28 g/mol

Mass of N₂ ≈ 16.2 g

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Answer:

b, their strong winds uproot many of the important plants

Explanation: