The density of alcohol is found to be 0.772 g/mL (true value is 0.798 g/mL)

The student's calculations for the density of acetic acid are precise but not accurate. Precision refers to how close the experimental values are to each other, while accuracy refers to how close the experimental values are to the true or accepted value.

In this case, the student obtained the following density values: 0.88 g/ml, 0.81 g/ml, 0.79 g/ml, and 0.83 g/ml. These values are relatively close to each other, indicating a high degree of precision. However, the true value of acetic acid density is 1.05 g/ml, which is notably different from the experimental values. This discrepancy signifies a lack of accuracy in the student's calculations.

There could be various factors that contributed to the inaccuracy, such as errors in measurements, equipment calibration, or experimental procedure.  the student  need to identify and address these issues to improve the accuracy of their calculations in future experiments.

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Answer:

1 mol

Explanation:

It's about balacing the equation. 2 parts "b" can form 1 part "a". So take 2 mol and divide by 2.

We can see from the calculation of the number of moles of the neon that we are going to have about  2.2 moles

The mole is a unit of measurement for substance amounts in chemistry. One mole is the volume of a substance that contains the same number of elementary particles as there are in 12 grams of carbon-12. These particles can be atoms, molecules, ions, or electrons. Avogadro's number, or about 6.022 x 1023 particles per mole, is the quantity of things.

We know that;

1 mole of the Ne occupies 22.4 L

x moles will occupy 48.41L

x = 2.2 moles

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The mass of the excess reagent (H₂) is 4.04 grams, the mass of the excess reagent can be calculated by determining the limiting reagent and subtracting the amount of the limiting reagent consumed from the initial mass of the excess reagent.

To find the mass of the excess reagent, we need to determine the limiting reagent first. The limiting reagent is the reactant that is completely consumed and determines the maximum amount of product that can be formed.

Mass of N₂ = 84.06g

Mass of H₂ = 22.18g

To determine the limiting reagent, we need to compare the moles of N₂ and H₂ with their respective stoichiometric coefficients in the balanced equation:

N₂: 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃.

H₂: 3 moles of H₂ react with 1 mole of N₂ to produce 2 moles of NH₃.

Calculate the moles of N₂ and H₂:

Moles of N₂ = mass / molar mass = 84.06g / 28.02 g/mol = 3 moles

Moles of H₂ = mass / molar mass = 22.18g / 2.02 g/mol = 11 moles

From the stoichiometry, we can see that 1 mole of N₂ reacts with 3 moles of H₂. Therefore, since we have 3 moles of N₂ and 11 moles of H₂, N₂ is the limiting reagent because it will completely react with 9 moles of H₂, leaving 2 moles of H₂ in excess.

Now, we can calculate the mass of the excess H₂:

Mass of excess H₂ = moles of excess H₂ * molar mass of H₂

                  = (11 moles - 9 moles) * 2.02 g/mol

                  = 2 moles * 2.02 g/mol

                  = 4.04 g

Therefore, the mass of the excess reagent (H₂) is 4.04 grams.

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Answer: so the answer is A

Explanation: The relationship between an object's mass (m), its acceleration (a), and the applied force (f) is F=ma. ... This law requires that the direction of the acceleration vector is in the same direction as the force vectors.

Answer:

2Ga(OH)3 + 3Hg2Cl2 → 6Hg(OH) + 2GaCl3

Explanation:

Answer: 2Ga(OH)3 + 3Hg2Cl2 → 6Hg(OH) + 2GaCl3

reaction type: Double Displacement

Answer:

[Au] = 0.171 M

Explanation:

For this question, we assume the rock is 100 % gold.

First of all, we determine the moles of gold

67.3 g . 1mol/ 196.97g = 0.342 moles

Molar concentration is defined as the moles of solute, contained in 1L of solution.

Our solution volume is 2L.

M = 0.342 mol / 2L = 0.171

Molar concentration, also called molarity of solution is the most typical unit of concentration.

Answer:

17.04 g/mol

Explanation:

Molar Mass of NH₃

we know that

Nitrogen has 14.01 gram/mol

And Hydrogen has 1.01 gram/mol

but we have 3 Hydrogens So we multiply

1.01 by 3 i.e., 3.03

Now, add

14.01

+ 3.03

17.04

So, The molar mass of ammonia, NH₃ is

17.04 g/mol

-TheUnknownScientist

Answer: Science and Mathematics- Anthropologist, Meteorologist

Engineering and technology- Fuel Cell Technician, Computer programmer, electrical Drafter, Civil Drafter

Answer:

i have the same question  

Explanation:math and science is the meteorologs and the  anthropologist

Two species can indirectly compete for the same resource even when they never come in contact with one another if they depend on the same resource but at different times.

An example of indirect competition is for example where two insect feeds on a certain plant during the day and another species feeds on the same plant during the night.

Indirect competition occurs when animals that use the same resource don't necessarily interact with one another, such as cheetahs that are active during the day and leopards that are active at night that shares a watering hole in a grassland savanna.

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Answer:

23.5 grams of AlBr3 will be produced by 27.20 grams of NaBr

Explanation:

The balanced equation here is

6NaBr + 1AlO3 = 3Na2O + 2AlBr3

6 moles of NaBr are required to produce 2 moles of AlBr3

Mass of one mole of NaBr = 102.894 g/mol

Mass of one mole of AlBr3 = 266.69 g/mol

Mass of 6 moles of NaBr = 6*102.894 g/mol

Mass of two moles of AlBr3 = 2*266.69 g/mol

6*102.894 g  NaBr produces 2*266.69 g of AlBr3

23.5 grams of AlBr3 will be produced by (6*102.894)/(2*266.69 )*23.5 = 27.20 grams of NaBr

The number of moles of gas is the same on both sides, the change in volume will not affect the equilibrium position of the reaction. The answer is B) There is no change because there are the same number of moles of gas on both sides.

To determine the change that will occur when the container is shrunk from 9.0 L to 3.0 L for the given reaction:

51.8 kJ + H₂(g) + I₂(g) → 2HI(g)

We need to consider the number of moles of gas on each side of the reaction.

On the left side, there are 2 moles of gas (H₂ and I₂), while on the right side, there are 2 moles of gas (2HI). Both sides have an equal number of moles of gas.

Therefore, the correct answer is B) There is no change because there are the same number of moles of gas on both sides.

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First of all, Z is unknown. I hope it is a mistake.

        Now, it is given that the element X has nineteen electrons. This proves that X is actually Potassium.

        As per the periodic table, both Potassium and Lithium belongs to group 1 as their valency is 1 because of the presence of only one electron in the outermost shell of electrons i.e., they lose an electron during a chemical reaction to form a stable compound. Furthermore, both are metallic.

        Magnesium belongs to group 2 and hence its valency is two, which is different from potassium though it is metallic. Similiarly, bromine belongs to group 17 and gains one electron during a reaction in contrast to potassium.

( No internal links available for reference. For clarification, check the periodic table).

The percentage (w/v) of dextrose in the solution is approximately 1.9817%. To determine the percentage (w/v) of dextrose in a solution with a given osmolarity, we need to calculate the amount of dextrose present in 100 mL of the solution.

First, we convert the osmolarity from mosmol/L to mosmol/100 mL:

100 mosmol/L = 100 mosmol/100 mL

Next, we calculate the number of moles of dextrose present in 100 mL of the solution:

Number of moles = Osmolarity (in mosmol/100 mL) / 1000

Number of moles of dextrose = 100 mosmol/100 mL / 1000 = 1 mosmol/100 mL

Now, we can calculate the mass of dextrose present in 100 mL of the solution:

Mass of dextrose = Number of moles of dextrose * Molecular weight of dextrose

Mass of dextrose = 1 mosmol/100 mL * 198.17 g/mol = 1.9817 g/100 mL

Finally, we can calculate the percentage (w/v) of dextrose:

Percentage (w/v) = (Mass of dextrose / Volume of solution) * 100

Percentage (w/v) = (1.9817 g/100 mL / 100 mL) * 100 = 1.9817%

Therefore, the percentage (w/v) of dextrose in the solution is approximately 1.9817%.

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The element which is likely to have a high thermal conductivity among given options is sodium.

Thermal conductivity of any substance is define as the capability of the substance to carry heat or transfer of heat.

As we know that metals are the good conductors of heat and non-metals are bad conductors, so we exclude carbon, antimony and chlorine atom from this group as they are non-metals. And sodium atom has the thermal capability.

Hence option (4) is correct.

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Answer: Option (4) is correct

Explanation:

In the original sample of substance X, there are 12 molecules and each molecule is made of 2 small red spheres and one blue sphere in the middle.

Change 1 has the same total number of red and blue spheres as the original sample, but the structure of molecules has changed. As a result, this is a chemical change.

In Change 2, the structure of molecules is changed. Some molecules contain solely red spheres, whereas others include both red and blue spheres. Furthermore, the total number of molecules is greater than the number of molecules in the original sample. This violates the principle of conservation of mass.  Hence, this is an impossible change since extra matter was created in this change.

In Change 3,  the number of the molecules and the structure of the molecules is same as the orignial sample. Hence, it is a physical change.

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The wavelength of the light is approximately 500 nm. The energy of the photon of light is approximately 6.56 x 10-20 J.

Answer: Question 1:The formula relating wavelength, frequency, and the speed of light is given by:c = fλHere,λ = wavelength, f = frequency, c = speed of lightI. n the problem, frequency is given as 5.98 x 1014 s-1. Therefore, using the formula, the wavelength of light can be calculated as follows:λ = c/f= (3 x 108 m/s)/(5.98 x 1014 s-1)≈ 500 nm

Therefore, the wavelength of the light is approximately 500 nm.

Question 2:The formula relating energy and frequency of light is given by:E = hfwhereE = energy of photonh = Planck's constant = 6.626 x 10-34 J s (Joule seconds)f = frequency of lightIn the problem, the frequency of light is given as 9.89 x 1013 Hz. Therefore, using the formula, the energy of the photon of light can be calculated as follows:E = hf= (6.626 x 10-34 J s) x (9.89 x 1013 Hz)≈ 6.56 x 10-20 J

Therefore, the energy of the photon of light is approximately 6.56 x 10-20 J.

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Answer:

4202.1 K

Explanation:

From;

PV=nRT

P= pressure of the gas = 18.5 bar

V = volume of the gas = 115L

n= number of moles of the gas =  6.1 mole

T= temperature of the gas = ?

R = gas constant = 0.083 L⋅bar⋅K−1⋅mol−1

T = PV/nR

T = 18.5 * 115/6.1 * 0.083

T = 2127.5/0.5063

T= 4202.1 K

Explanation:

1 ) first u have to balance the equation but in this case it is already balanced.

2) checking for the limiting reactant:

13 mol O2 × (1mol H2O / 1mol of O2) = 13 mol of H2O

14 mol of ethanol × (1mol H2O/ 1molof ethanol) = 14 mol of H2O

the less amount of moles produced from the O2 so the limiting reactant is oxygen

3) calculating the products moles

13 mol O2 × (1mol H2O / 1mol of O2) = 13 mol

13 mol O2 × (1mol Ch3Cooh / 1mol O2) = 13 mol

note: the ratios obtained from the balanced equation

4) the excess reagent is the ethanol 1 mol will be remain

The direction of the polarity of a bond can be indicated using the symbols δ+ and δ-.

When two atoms with different electronegativities are bonded together, the electrons in the bond are not shared equally. The atom with higher electronegativity attracts the electrons more strongly, resulting in a partial negative charge (δ-) on that atom and a partial positive charge (δ+) on the other atom. These partial charges are represented by the symbols δ+ and δ-, respectively.

In the first step, the δ+ symbol is placed above the atom that has the partial positive charge, indicating the direction of the polarity. Similarly, the δ- symbol is placed above the atom with the partial negative charge, indicating the direction of the polarity.

The δ+ symbol represents the atom that is electron-deficient and has a higher electron density, while the δ- symbol represents the atom that is electron-rich and has a lower electron density. These symbols help in visualizing the polarity of the bond and understanding the distribution of charge within the molecule.

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A 1.26 g sample of He gas has a pressure of 0.123 arm and a volume of 32.6 L, then the temperature of the gas is -117.7 degree C.

Temperature of any gas will be calculated by using the ideal gas equation as:

PV = nRT, where

P = pressure of gas = 0.123 atm

V = volume of gas = 32.6 L

R = universal gas constant = 0.082 L.atm / K.mol

T = temperature of gas = ?

n is moles of He gas and will be calculated as:

n = W/M, where

W = given mass = 1.26g

M = molar mass = 4 g/mol

n = 1.26 / 4 = 0.315 moles

On putting values we get,

T = (0.123)(32.6) / (0.315)(0.082)

T = 155.41 K = 155.41 - 273.15 = -117.7 degree C

Hence required temperature of the helium sample is -117.7 degree C.

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The concentration of hydroxide ions in the solution at 25°C, with a pOH of 12.40, is approximately 3.98 x 10^(-13) mol/L.

To determine the concentration of hydroxide ions in a solution at 25°C with a pOH of 12.40, we can use the relationship between pOH and hydroxide ion concentration. The pOH is defined as the negative logarithm (base 10) of the hydroxide ion concentration. Mathematically, it can be expressed as pOH = -log[OH-].

Given that pOH = 12.40, we can calculate the hydroxide ion concentration by taking the antilogarithm (10 raised to the power of the negative pOH value). So, [OH-] = 10^(-pOH).

Substituting the given value into the equation, we have [OH-] = 10^(-12.40). Evaluating this expression, we find that the concentration of hydroxide ions in the solution is approximately 3.98 x 10^(-13) mol/L.

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i) you would need 60 mL of the 50X TAE Buffer stock. ii)You would need 2940 mL of distilled water (dH2O) to make up the 1X TAE Buffer to a total volume of 3 liters.

To dilute the 50X TAE Buffer to a 1X working solution for a total volume of 3 liters, you would use the following calculations:

(i) 1X TAE Buffer - stock:

For a 1X TAE Buffer, the dilution factor is 50X. Since you want to prepare a total volume of 3 liters, the volume of the stock solution needed can be calculated as follows:

Volume of 50X TAE Buffer stock = (Final volume / Dilution factor)

                              = (3 L / 50)

                              = 0.06 L or 60 mL

Therefore, you would need 60 mL of the 50X TAE Buffer stock.

(ii) 1X TAE Buffer - dH2O: To make up the remaining volume with distilled water (dH2O), subtract the volume of the stock solution from the final volume:

Volume of dH2O = (Final volume - Volume of 50X TAE Buffer stock)

             = (3 L - 0.06 L)

             = 2.94 L or 2940 mL

Therefore, you would need 2940 mL of distilled water (dH2O) to make up the 1X TAE Buffer to a total volume of 3 liters.

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2Na + 2H2O → 2NaOH + H2

The balanced equation

Answer:

Engineering is all about solving problems using math, science, and technical knowledge. And engineers have solved a lot of problems in the world by designing and building various technologies. We have everything from machines that can breathe for you in hospitals to suspension bridges to computers we use every day. All of these things were once designed by engineers using the engineering design process.

Explanation:

Answer:

Students will have to use their brains to solve problems and challenges they will face to find a solution to cleaning up oil spills. Students will face failures after completing their solution, lots of research, and problems during the making of their solutions. What will work? What won't?

Explanation:

Hope this helps!

Explanation:

No, that would be incorrect

Answer:

There arre two main parts of the atom, the nucleus and the orbital rings. The three subatomic particles are contained in each of these, the proton and neutron together in the nucleus and the electrons orbiting in the rings.