the density of a pure gas at stp depends on its

Answer:

B. Liquids

Explanation:

Just had this question on my test.

Hope this helps :)

The space probe will have the highest speed on Neptune.

The final speed of the space probe in each of the planet is calculated by applying the following kinematic equation as shown below.

v = u + gt

where;

For equal time of fall, the final speed of the space probe increases with increase in the acceleration due to gravity on each planet.

Thus, the planet with the largest acceleration due to gravity will cause the greatest speed of the space probe.

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The high-speed footage of the professional golfer's practice swing reveals that the club is in contact with the initially stationary ball on the tee for only a short period of time, denoted as δ. This duration of contact is commonly referred to as the "impact interval" or "ball-club contact time."

During this brief moment, several actions occur.

Firstly, the clubhead transfers its momentum and energy to the ball, causing it to accelerate.

Simultaneously, the ball exerts a force on the clubhead, resulting in a reaction force.

The interaction between the club and the ball is governed by Newton's third law of motion, which states that every action has an equal and opposite reaction.

The duration of the impact interval, δ, depends on various factors, such as the swing speed, angle of attack, and the characteristics of the club and ball.

In general, professional golfers strive to minimize the impact interval to optimize their swing efficiency and maximize the distance and accuracy of their shots.

It's important to note that while the high-speed footage provides valuable insights into the golfer's swing mechanics, a successful golf shot involves numerous other factors, including body positioning, timing, and coordination.

Therefore, a thorough analysis of the entire swing sequence is necessary to draw comprehensive conclusions and make further improvements.

The high-speed footage of the professional golfer's practice swing shows that the club is in contact with the initially stationary ball for a short duration, denoted as δ.

This impact interval is crucial in transferring momentum and energy from the club to the ball, resulting in the desired shot outcome.

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Answer:

Explanation:

This problem bothers on the simple harmonic motion of a loaded spring

Given data

mass attached, m= 0-.675 kg

spring constant, k= 72.4 N/m

the period of oscillation can be solved for using the formula bellow

\(T= 2\pi \sqrt{\frac{m}{k} }\)

Substituting the given data into the expression above we have

\(T= 2*3.142\sqrt{\frac{0.675}{72.4} }\\T= 6.284*\sqrt{0.0093 }\\T= 0.6\)

T= 0.6 sec

Answer:

0.607

Explanation:

Trust me

East or west: it remains the same.

North: it increases.

South: it decreases.

At the North pole: it's straight up over your head.

At the equator: it's on the horizon, north of you.

South of the equator: it's below the horizon and you can't see it at all.

Answer:

It keeps particles that make up protons and neutrons together.

Explanation:

Nuclear force is a short range of force which means it will act at short range of distance like fermi order distance.

This shows the order of radius of the nuclei which means all the neutrons and protons which resides into the nucleus will exert the nuclear force on each other and this nuclear force is of large magnitude compare to electrostatic force or gravitation force between them.

While if the distance is more than the fermi order distance then the nuclear force totally disappears so it will not exist for large distances.

so here the correct answer must be

It keeps particles that make up protons and neutrons together.

The movement of a body part around a central point or axis is known as rotation.

Rotation refers to the circular movement of a body part around its axis or a fixed point. It involves the turning or twisting motion of a body segment without changing its position in space.

Flexion (a) is the movement that decreases the angle between two body parts, typically bending or decreasing the joint angle. The extension (b) is the opposite movement, increasing the angle between two body parts, typically straightening or increasing the joint angle. Abduction (d) refers to the movement of a body part away from the midline of the body.

During rotation, the body part or segment moves around an imaginary line called the axis. This axis can be within the body itself or located externally. For example, when we rotate our head from side to side, the axis of rotation is an imaginary line passing through the neck.

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Your driver's license is at risk of being cancelled if you have more than three traffic violations in one year​. The correct option is D.

The license by the central government to an individual to travel on road by his own vehicle on terms and conditions to be strictly followed.

When a driver is moving with his vehicle and come across the traffic signal, he must follow them. If he violates the traffic signals more than three times, he will get his license cancelled.

Thus, your driver's license is at risk of being cancelled if you have more than three traffic violations in one year​. The correct option is D.

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A 5,560 kg lander (weight does not include fuel) must travel to the surface of the moon and back, requiring a delta-v (change in speed) of 18.7 kilometers per second. If the specific impulse (exhaust velocity, ve) of the rocket is 4.13 kilometers per second, approximately 4,683 kg of fuel will be necessary for the lander to travel to the surface of the moon and back.

According to the Rocket Equation, the amount of fuel necessary can be calculated using the formula:

m_fuel = m0 × (1 - e^(-Δv / ve)),

where:

m_fuel is the mass of the fuel required,

m0 is the initial total mass of the lander (including fuel),

Δv is the change in velocity (delta-v) required for the mission,

ve is the exhaust velocity (specific impulse) of the rocket.

In this case, we have:

m0 = 5,560 kg,

Δv = 18.7 km/s,

ve = 4.13 km/s.

Substituting the given values into the equation, we can calculate the mass of the fuel required:

m_fuel = 5,560 kg × (1 - e^(-18.7 km/s / 4.13 km/s)).

Using a calculator or a mathematical software, we find:

m_fuel ≈ 4,683 kg.

Therefore, approximately 4,683 kg of fuel will be necessary for the lander to travel to the surface of the moon and back, considering the given values for the initial mass, delta-v, and specific impulse.

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By following these steps, you can accurately determine the temperature of the refrigerant at the compressor exit, which is crucial for understanding the performance and efficiency of the refrigeration system. To determine the temperature of the refrigerant at the compressor exit, you need to follow these steps:

1. Identify the refrigerant being used in the system, as different refrigerants have different properties and behaviors under varying conditions.

2. Obtain the pressure at the compressor exit. This can usually be found by consulting the system's specifications or measuring the pressure using a pressure gauge.

3. Consult the pressure-temperature (P-T) chart for the specific refrigerant being used. This chart provides the relationship between the pressure and temperature of the refrigerant at different points in the system.

4. Locate the exit pressure value on the P-T chart, and find the corresponding temperature. This temperature value will be the temperature of the refrigerant at the compressor exit.

By following these steps, you can accurately determine the temperature of the refrigerant at the compressor exit, which is crucial for understanding the performance and efficiency of the refrigeration system.

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Answer:

779.87 N/m²

Explanation:

Pressure = Force (F) / Area (A)

Recall :

Force = ma ; mass * acceleration due to gravity

a = 9.8 m/s² ; mass = 0.4kg

Force, F = 0.4 * 9.8 = 3.92 N

Area = πr² ; r = Radius = 4cm = 4 / 100 = 0.04 m

Area = π0.04² = 0.0050265 m²

Hence,

Pressure = 3.92 / 0.0050265

Pressure = 779.86670 N/m²

Pressure = 779.87 N/m²

a

sorry if its not right

Answer:

30

Explanation:

Power=work/time

power=300/10

Hope this helps

The correct answer to this open question is the following.

Although there are no options attached we can say the following.

The structure of the article makes the author's argument more effective because the author shares factors that drive people from behaving correctly to behave incorrectly. And these factors are the following. Anonymity when people hide to do damage. Dehumanizing and offend others. Make people feel there are unworthy and despicable. Another one, power and control of people and situations.

In October 2004, author Melissa Dittmann wrote the article "What Makes Good People Do Bad Things?" in the American Psychological Association (APA).  In her article, she refers to the fact that under certain circumstances, good people can end up doing horrible things. Social situations force normal people to transform their behavior and they cause harm to others. The specific case she mentions is the abuse of Iraqi prisoners at Aby Ghraib. This situation was documented by Philip G. Zimbardo, professor of Standford University.

Zimbardo's classic prisoner study at Stanford University revealed how social roles influence our behavior. It was conducted by Philip Zimbardo in 1971. It was used to illustrate the theory of Cognitive Dissonance and the power of authority.

The abuse scandal in Abu Gharib prison in Iraq (2003)  depicted soldiers abusing detainees. Eleven US soldiers were convicted for crimes committed against prisoners.

Answer:

a = 30 km / h²

Explanation:

Dado que

Velocidad inicial, u = 70 km / h

Velocidad final, v = 95 km / h

Tiempo, t = 30 s = 0.1 h

Lo sabemos

v = u + a t

a = aceleración

Ahora poniendo los valores en la ecuación anterior

\(95 = 70 + a \ times 0.1 \)

\(a = \ dfrac {95-70} {0.1} = 30 \ km / h ^ 2 \)

Por lo tanto, la aceleración será

a = 30 km / h²

Answer:

Potential energy

Explanation:

Potential energy is stored energy and the energy of position––gravitational energy. There are several forms of potential energy. Electrical Energy is the movement of electrical charges. Everything is made of tiny particles called atoms.

- Scientific Forms of Energy_ Stored Energy, Kinetic Energy ...ei.lehigh.edu › learners › energy › readings › energy_basics

The sound intensity level (b) of the given sound wave is 20 decibels. The sound intensity level (SIL) in decibels (dB) can be calculated using the formula.

In this formula, I is the intensity of the sound wave, and I₀ is the reference intensity. The reference intensity for sound is typically 10⁻¹² W/m².

SIL (dB) = 10 * log10(I / I₀)

In your case, the intensity of the sound wave (I) is 100 times the reference intensity (I₀). So, we can write the equation as:

SIL (dB) = 10 * log10(100 * I₀ / I₀)

Notice that I₀ appears in both the numerator and denominator, so we can cancel it out:

SIL (dB) = 10 * log10(100)

Now, we can use the properties of logarithms to simplify the expression:

SIL (dB) = 10 * (2) = 20 dB

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The criterion of significant figures can to find the result with reliable figures

          X = 9.2 10⁻⁵

now with the propagation of errors we obtain the result with its uncertainty

         X ± ΔX = (9.2 ± 0.5) 10⁻⁵

given Parameter

     * expression values ​​with their absolute errors

to find

     * the result with the correct significant figures

     * the absolute error of the expression

Significant figures are defined with the number of decimals that give information, the number of figures in a quantity gives information about the uncertainty of this quantity.

There are two criteria for applying significant figures:

     * Add and subtract the result of going with the number of decimal places of the figure that has the least

    * Product and division as a result of going with the least number of significant figures than the value that has the least.

Remember that the zero to the left do not form a pair of the significant figures

Let's apply this belief to the case presented, let's write the precaution

              \(x = \frac{a-b}{c}\)

where in this case they are worth

         a = 0.0336 ± 0.0002

         b = 0.010 ± 0.001

         c = 255.4 ± 0.4

We see that the significant figures of each parameterize (a, b, c) and their absolute errors are correct.

Let's apply the criteria to the operation

          a-b = 0.0336 - 0.010

          a- b = 0.0236

we apply the criterion of significant figures for the subtraction, the result must be with 3 decimal places

        a - b = 0.024

let's do the other operation

         X = \(\frac{a-b}{c}\)

         X = 0.024 / 255.4

         X = 9.24 10⁻⁵

We apply the criterion of significant figures for the division, in this case the result is left with two significant figures

         X = 9.2 10⁻⁵

The uncertainty or error of the measurements is of most importance as it determines how many significative figures are reliable at a given magnitude.

If the magnitudes are measured with some type of instrument, the absolute error is given by the appreciation of the instrument, if the magnitude is calculated using some equation, the errors must be propagated using the variations of each parameter in the worst case.

the uncertainty of the calculated quantity (X) is

        \(\Delta X = | \frac{dX}{da}| \Delta a + | \frac{dX}{db} | \Delta b + | \frac{dX}{dc}| \Delta c\)

let's perform the derivatives

        \(\frac{dX}{da} = \frac{1}{c}\)

        \(\frac{dX}{db} = - \frac{1}{c}\)

        \(\frac{dX}{dc} = - \frac{a-b}{c^2}\)

we substitute

remember that the bulk value guarantees that we tune the worst case. So all the mistakes add up

          ΔX = \(\frac{1}{c}\)  Δa +

          ΔX = (Δa + Δb) + Δc

we substitute

         ΔX = \(\frac{1}{255.4}\)  (0.0002 + 0.001) + \(\frac{0.0336-0.010}{255.4^2}\)  0.4

         ΔX = 4.698 10⁻⁶ + 1.45 10⁻⁷

         ΔX = 4.8 10⁻⁶

Absolute errors must be given with a single significant figure

         ΔX = 5 10⁻⁶

The result of the requested quantity using the criterion of significant figures and propagation of errors is

          X ± ΔX = (9.2 ± 0.5) 10⁻⁵

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Answer:

This is basically Simple Harmonic Motion - where the wave disturbance is in the same direction as the wave direction.

That describes (B).

note that y = A cos ω t          where the disturbance is y and ω the the angular frequency and is in the same direction as the disturbance y

This seems the make (D) a satisfactory answer

The projection of the disturbance y is perpendicular (sinusoidal) to the time axis, but the disturbance is still in the same direction as the wave motion

The wave generated by a spring is a transverse wave where, the particles oscillate in a direction perpendicular to the the wave motion.

Mechanical waves are energy transfer through a medium. Unlike electromagnetic waves, mechanical waves cannot transfer through vacuum.

There are two types of mechanical waves namely, transverse waves and longitudinal waves. Transverse waves are those in which the oscillation of particles or disturbance is created perpendicular to the wave motion.

In longitudinal waves, the particle motion or disturbance is created along the wave motion. The wave generated in a spring is transverse wave thus, the disturbance created by moving it up and down will be perpendicular to the wave motion.

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Answer:

Concave mirrors reflect light to a central point (converging)

Suppose the source is to the left of the  mirror in  question.

Parallel rays into the mirror are always reflected towards the focal point.

In the case of a concave mirror the real parallel rays pass thru the focal point.

If the mirror is convex the rays will diverge to the left and act as if they were emanating from the focal point to the right of the mirror.

The wavelength of a wave of the frequency is increased to 784 Hz will be 0.57 metre.

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The given data in the problem is;

f₁ is the  frequency of  a sound wave in case 1 = 196 Hz

\(\lambda\)₁ is the wavelength for the  = 1.76 meters.

f₂ is the  frequency of  a sound wave in case 2 = 784 Hz

\(\lambda_2\) is the wavelength for case 2=?

The speed of the wave for the same medium is same which is given as;

\(\rm v = \lambda_1 f_1 \\\\ \rm v = 1.76 \times 196 \\\\ \rm v =344.96\ m/sec\)

For case 2;

\(\lambda_2 = \frac{v}{f_2} \\\\ \lambda_2 = \frac{344.96}{784} \\\\ \lambda_2=0.44\)

Hence the wavelength of a wave of the frequency is increased to 784 Hz will be 0.57 metre.

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At a location 40 degrees from the axis (either 40 degrees north or south), the distance from the axis would be approximately 6,250 kilometers.

The distance from the Earth's axis to a location on Earth is known as the radius of the Earth. At any point on the Earth's surface, the radius will be the same. However, the Earth's axis itself does not move, but rather the Earth rotates around its axis. The axis runs through the North and South Poles, and this rotation takes approximately 24 hours to complete, resulting in day and night cycles. At a location 40 degrees from the axis (either 40 degrees north or south), the distance from the axis would be approximately 6,250 kilometers.

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Answer:

\( \boxed{\sf Distance \ travelled = 62.5 \ m} \)

Given:

Initial velocity (u) = 25 m/s

Final velocity (v) = 0 m/s (Rest)

Time taken (t) = 5 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

\( \boxed{ \bold{s = (\frac{v + u}{2} )t}}\)

By substituting value of v, u & t in the equation we get:

\( \sf \implies s = ( \frac{0 + 25}{2} ) \times 5 \\ \\ \sf \implies s = \frac{25}{2} \times 5 \\ \\ \sf \implies s = 12.5 \times 5 \\ \\ \sf \implies s = 62.5 \: m\)

\( \therefore\)

Distance travelled by car (s) = 62.5 m

The distance  car travel during that time is 62.5 meter.

Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.

Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.

Initial velocity (u) = 25 m/s

As the car becomes rest, final velocity (v) = 0 m/s (Rest)

Time taken (t) = 5 seconds.

The deceleration of the car: a = (initial speed - final speed)/time interval

= ( 25 m/s - 0 m/s)/5 second

= 5 m/s²

The distance  car travel during that time = ut - at²/2

= 25 × 5.0 meter - (5×5²/2) meter

= 62.5 meter.

Hence, the distance  car travel during that time is  62.5 meter.

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In order to form a hypothesis that would illustrate the relationship between mass and kinetic energy, we first need to understand what kinetic energy and mass are and how they are related. Kinetic energy is the energy that an object possesses due to its motion, and is given by the formula KE = 0.5mv², where m is the mass of the object and v is its velocity. Mass, on the other hand, is a measure of the amount of matter in an object.

The relationship between mass and kinetic energy is direct, meaning that as mass increases, so does kinetic energy, provided that velocity remains constant. Similarly, if velocity increases, then kinetic energy will increase as well, provided that mass remains constant.

The hypothesis that illustrates this relationship can be stated as follows:If the mass of an object is increased, then the kinetic energy of the object will also increase, because kinetic energy is directly proportional to mass, assuming velocity remains constant.In other words, if the mass of an object is doubled, then its kinetic energy will also double, assuming that its velocity remains constant. This hypothesis can be tested through experiments that involve measuring the kinetic energy of objects with different masses, but with the same velocity.

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If the mass of an object increases, then its kinetic energy will increase proportionally because mass and kinetic energy have a linear relationship when graphed.

Answer:

A. The angle with which the light passes from glass into water is approximately 31.97°

B. The image formed is, real, inverted, and smaller than the object

C. The image distance is 53.2\(\overline 6\) cm

The image is real

D. The magnification is approximately 0.182

E. The type of lens required is a concave lens which corrects the focus of a powerful eye lens or a long eyeball

Explanation:

The given parameters for the light wave are;

The refractive index of the glass medium, n₁ = 1.5

The angle of incidence of the light, θ₁ = 28°

The refractive index of water, n₂ = 1.33

A. Let θ₂ represent the angle with which the light passes from glass into water

Snell's law is mathematically stated as follows;

n₁·sin(θ₁) = n₂·sin(θ₂)

According to Snell's law, we have;

1.5 × sin(28°) = 1.33 × sin(θ₂)

sin(θ) = (1.5 × sin(28°))/1.33 = 0.52947920615

∴ θ₂ = arcsin(0.52947920615) ≈ 31.97°

The angle with which the light passes from glass into water, θ₂ ≈ 31.97°

B. Please find attached the drawing of the image created with Microsoft Visio

From the drawing, we have that the image formed is real inverted smaller than the object and between the focus and radius of curvature

C. The location of the object from the mirror, u = 94.0 cm

The focal length of the mirror, f = +34.0 cm

The mirror formula for a concave mirror is given as follows;

\(\dfrac{1}{f} = \dfrac{1}{u} + \dfrac{1}{v}\)

Therefore, we have;

\(\dfrac{1}{34.0} = \dfrac{1}{94.0} + \dfrac{1}{v}\)

\(\dfrac{1}{v} = \dfrac{1}{34.0} - \dfrac{1}{94.0} = \dfrac{15}{799}\)

\(\therefore \dfrac{v}{1} = v =\dfrac{799}{15} = 56.2\overline 6\)

The image distance, v = 799/15 = 53.2\(\overline 6\) cm

Therefore the image is in front of the mirror, which is a real image

The image is real

D. The given parameters of the object and lens are;

The distance of the object from the lens, u = 65.0 cm

The distance of the image formed from the lens, i = -18 cm

The magnification, M, is given as follows;

\(M = \dfrac{-v}{u}\)

Therefore;

\(M = \dfrac{-(-11.8)}{65.0} = \dfrac{59}{325} \approx 0.18153846153\)

The magnification, M ≈ 0.182

E. For a person who is near sighted, the light from objects from distant location are almost parallel and are brought to a focus in front of the retina and therefore, they appear blurred

The use of a concave lens is required to correct nearsightedness as it causes the light to appear come from a point before the focus such that the divergent rays of the object refracted through the concave lens comes to a focus at the.

Neglecting the weight of the piston and plunger, The weight of the car is approximately 1,630 kg.

To solve this problem, we can use the principle of Pascal's law which states that pressure applied to a confined fluid is transmitted equally in all directions. This means that the pressure applied to the input piston will be transmitted through the fluid to the output plunger, resulting in a much larger force.

To find the weight of the car, we need to first calculate the force applied to the output plunger. We can do this by using the formula:

Force = Pressure x Area

Since the pressure is the same throughout the fluid, we can use the pressure at the input piston to find the force at the output plunger. The pressure is given by:

Pressure = Force / Area

For the input piston, we have:

Pressure = 160 N / 12 cm^2 = 13.33 N/cm^2

This same pressure is transmitted to the output plunger, so we can use it to find the force:

Force = Pressure x Area = 13.33 N/cm^2 x 1200 cm^2 = 16,000 N

Now we can find the weight of the car using the formula:

Weight = Force / Gravity

Assuming a gravitational acceleration of 9.81 m/s^2, we get:

Weight = 16,000 N / 9.81 m/s^2 = 1,630 kg

Therefore, 1,630 kg (approximately) is the weight of the car.

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The probable question may be:

The input piston and output plunger of a hydraulic car lift are at the same level, as shown in the drawing. the cross-sectional area of the input piston is 12 cm2, while that of the output plunger is 1200 cm2. the force f1 applied to the input piston has a magnitude of 160 n. what is the weight w of the car? neglect the weight of the piston and plunger.

ANSWER

EXPLANATION

If force F keeps the object in equilibrium

Answer:

See below

Explanation:

Find the x components of all of the forces shown, add them together, the x-component of the force F will be exactly opposite ( same magnitude but 180 degrees different)

30 cos 55  +     40 cos 205   +   50 cos 320  =  19.26    <====x component sum of all of the forces shown

F  (the x component of ) will be   Either    - 19.26   At zero degrees

                                                                 Or 19.26 at 180 degrees