The current in the wires of a circuit is 180.0 milliamps. If the resistance of the circuit were doubled ( with no change in voltage), then its new current would be

The final velocity of the smaller object after the collision is 1.725 meters per second to the west.

An elastic collision can be described by the principle of linear momentum conservation, whose model for these case is:

Principle of linear momentum conservation

\((2.40\,kg) \cdot \left(4\,\frac{m}{s} \right) = (2.40\,kg)\cdot v + (6\,kg)\cdot \left(2.29\,\frac{m}{s} \right)\)

Where \(v\) is the final velocity of the smaller object, in meters per second.

Then, the final velocity of the object is:

\(v = -1.725\,\frac{m}{s}\)

The final velocity of the smaller object after the collision is 1.725 meters per second to the west.

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Answer:

true

Explanation:

normally -No system has ever performed well with one object.

A system must contain more than one object is a true statement.

A system is a group of interacting or interrelated objects that act according to a set of rules to form a unified whole.

Normally, no system has ever performed well with one object.

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The answer is that the time the diver was in the air is 1.13 seconds.

To determine the time the diver was in the air, we can use the kinematic equation:

Δy = viΔt + 1/2at²,

where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0

m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²

Simplifying, we get:

4.9t² + 5.5t - 3.0 = 0

We can solve for t using the quadratic formula:

t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s

Since time cannot be negative, the time the diver was in the air is 1.13 seconds.

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The metal bowl must displace 0.196 liters of castor oil in order to float.

Archimedes' principle states that when an object is placed in a fluid, the buoyant force on the object is equal to the weight of the fluid displaced by the object. In other words, the amount of fluid displaced by the object is directly proportional to the weight of the object.

We can use the weight density of castor oil, which is 9.42 N/L, to find the volume of oil displaced by the bowl.

Volume of oil displaced = Weight of bowl / Weight density of oil

Volume of oil displaced = 1.85 N / 9.42 N/L = 0.196 L

As a result, in order to float, the metal bowl must displace 0.196 liters of castor oil.

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Answer:

32.13 N

Explanation:

Given that

mass of the crate, m = 3 kg

angle of inclination, = 35°

coefficient of static friction, = 0.3

To solve this, we can assume that the minimum force is F Newton, then use the formula

mgsinA = coefficient of static friction * [F + mgcosA]

=>3 * 9.8 * sin35 = 0.3 * [F + 3 * 9.8 * cos35]

=> 29.4 * 0.5736 = 0.3 * [F + 29.4 * 0.8192]

=> 16.86 = 0.3 [F + 24.08]

=> 16.86 = 0.3F + 7.22

=> 16.86 - 7.22 = 0.3F

=> 0.3F = 9.64

=> F = 9.64/0.3

=> F = 32.13 N

Therefore, the Force that must be applied is 32.13 N

The  net force that must be applied is  9.8 N.

The minimum force required is Fnet.

Fnet = -Ff + mgsinθ

But Ff = μN = μmgcosθ

Fnet = - μmgcosθ + mgsinθ

Where;

m = 3.00 kg

μ =  0.300

θ = 35.0o

Substituting values;

Fnet = mgsinθ - μmgcosθ

Fnet = (3 × 10 × sin 35.0o) - (3 × 0.300  × 10 × cos  35.0o)

= 17.2 - 7.4

Fnet = 9.8 N

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Answer:

Option 2 both take millions of years to form

Explanation:

Both  coal and ores take millions of years to form.

Ore is a naturally occurring rock or silt that has precious minerals in it that may be extracted, processed, and sold for a profit. These minerals are usually metals. Mining is the process of removing ore from the soil. The valuable metals or minerals are then removed by treating or refining the ore, frequently through smelting.

The concentration of the desired ingredient in an ore is referred to as its grade. To decide if a rock has a high enough grade to be worth mining and is therefore regarded as an ore, the value of the metals or minerals it contains must be evaluated against the expense of extraction.

Typically, oxides, sulphides, silicates, or native metals like copper or gold are the minerals of interest. To separate the valuable components from the waste rock, ore must be treated. Numerous geological processes collectively known as ore genesis are responsible for the formation of ore deposits.

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Answer: anything that can change or be changed

Explanation: In other words, it is any factor that can be manipulated, controlled for, or measured in an experiment.

Answer:

Dependend variable or Independent variable

Explanation:

A variable is anything that can change or be changed. In other words, it is any factor that can be manipulated, controlled for, or measured in an experiment. Experiments contain different types of variables.

Answer:

To perform hands-only CPR, you want your non-dominant hand on top of your dominant hand and interlocking fingers, and push right under the breast bone 30 times. A good way to remember how fast you should perform CPR, listen to the beat of "Staying Alive." If the hands don't work after 30 times, pinch their nose, tilt their head back and blow two big breaths into their mouth, then do the chest pushing again. Keep repeating these steps until they respond, you feel a pulse, or 911 arrives.

Explanation:

I actually just learned how to do CPR this week it is really cool!

May I have Brainliest please? My next rank will be the highest one: A GENIUS! Please help me on this journey to become top of the ranks! I would really appreciate it, and it would make my day! Thank you so much, and have a wonderful rest of your day!

Question:

What quantity do units represent in a value? A. Size B. Direction C. Magnitude D. Dimension

Answer:

D. Dimension

Explanation:

A unit is simply the measurement given to a dimension. In other words, units represent dimensions. For example, consider a ruler that is 20m long.

i. The value is 20m.

ii. The magnitude of the measurement is 20

iii. The unit of the measurement is meters(m) and that essentially represents the dimension (length) of the ruler.

It is not recommended to fire a gun straight up into the air.

When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.

Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.

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Answer:

at an advanced stage of social and cultural development. "a civilized society"

Explanation:

polite and well-mannered "I went to talk to them and we had a very civilized conversation" hope this helps you :)

1. Some of their debts can be eliminated, and loan terms are renegotiated with lenders.

2. All of their debts are eliminated, and they are given a fresh start.

3. All of their debts are eliminated, but they have to sell their assets, such as their homes.

D took the test UWU

The statement is all of their debts are eliminated, but they have to sell their assets, such as their homes. Option (c) is correct.

During the legal process of bankruptcy, individuals or other entities that are unable to pay their creditors back can seek partial or complete relief from their debts. Bankruptcy is typically imposed by a court order that is frequently requested by the debtor.

An opportunity to start all over is provided through bankruptcy by wiping off uncontrollable debts. In the meanwhile, creditors may be able to receive some payment based on the person or company's liquidate assets.

Declaring bankruptcy should help the economy as a whole by giving individuals and business organizations another chance to recover financially. It may also assist persons in recovering some loan repayment.

Therefore, Option (c) is correct.

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The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Answer:

Explanation:

The formula relating the speed of sound, frequency, and wavelength is:

speed = frequency x wavelength

Rearranging this formula to solve for frequency:

frequency = speed / wavelength

Substituting the given values:

frequency = 342 m/s / 1.8 m

frequency = 190 Hz

Therefore, the frequency of the sound wave is 190 Hz.

Answer:

1.5

Explanation:

Answer:

\(4.12\times 10^{-5}\ J\).

Explanation:

Given that,

Capacitance, \(C=1.4\times 10^{-7}\ F\)

Charge stored in the capacitor, \(Q=3.4\times 10^{-6}\ C\)

We need to find the electric potential energy stored in the capacitor. The formula for the electric potential energy stored in the capacitor is given by :

\(E=\dfrac{Q^2}{2C}\)

Put all the values,

\(E=\dfrac{(3.4\times 10^{-6})^2}{2\times 1.4\times 10^{-7}}\\\\=4.12\times 10^{-5}\ J\)

So, the required electric potential eenergy is equal to \(4.12\times 10^{-5}\ J\).

Answer:

As temperature increases, molecules of liquid become more active and they move more rapidly.

Answer:

1.2 kg

__________________________________________________________

We are given:

Mass of the block = 2 kg

Coefficient of Static Friction = 0.6

__________________________________________________________

Friction Force on the Block:

Finding the Normal Force:

We know that the normal force will be equal and opposite to the weight of the 2 kg block

So, Normal Force = mg

replacing the variables with the given values

Normal Force = (2)(9.8)                    [Taking g = 9.8]

Normal Force = 19.6 N

Friction force on the Block:

We know that:

Coefficient of Static Friction =  Static Friction Force/Normal Force

replacing the variables

0.6 = Static Friction force / 19.6

Static Friction force = 0.6*19.6 N                 [Multiplying both sides by 19.6]

Static Friction force = 11.76 N

__________________________________________________________

Largest Mass that can Hang:

We know that the Static Friction force is 11.76 N, this means that a force of 11.76 N will be applied to keep the object at rest

So, if the weight of the second block is less than the static friction force, it will hang

Weight of the second block ≤ 11.76

We know that weight = mg

mg ≤ 11.76

m(9.8) ≤ 11.76                                                   [since g = 9.8]

m ≤ 1.2 kg                                                        [dividing both sides by 9.8]

From this, we can say that the maximum mass of the second block is 1.2 Kg

Answer:

(a) \(\vec F_{\parallel} = -\frac{102}{13}\,i-\frac{103}{13}\,j\) , (b) \(\vec F_{\perp} = \frac{102}{13}\,i -\frac{68}{13}\,j\), (c) \(W = -51\)

Explanation:

The statement is incomplete:

The force on an object is \(\vec F = -17\,j\). For the vector \(\vec v = 2\,i +3\,j\). Find: (a) The component of \(\vec F\) parallel to \(\vec v\), (b) The component of \(\vec F\) perpendicular to \(\vec v\), and (c) The work \(W\), done by force \(\vec F\) through displacement \(\vec v\).

(a) The component of \(\vec F\) parallel to \(\vec v\) is determined by the following expression:

\(\vec F_{\parallel} = (\vec F \bullet \hat {v} )\cdot \hat{v}\)

Where \(\hat{v}\) is the unit vector of \(\vec v\), which is determined by the following expression:

\(\hat{v} = \frac{\vec v}{\|\vec v \|}\)

Where \(\|\vec v\|\) is the norm of \(\vec v\), whose value can be found by Pythagorean Theorem.

Then, if \(\vec F = -17\,j\) and \(\vec v = 2\,i +3\,j\), then:

\(\|\vec v\| =\sqrt{2^{2}+3^{3}}\)

\(\|\vec v\|=\sqrt{13}\)

\(\hat{v} = \frac{1}{\sqrt{13}} \cdot(2\,i + 3\,j)\)

\(\hat{v} = \frac{2}{\sqrt{13}}\,i+ \frac{3}{\sqrt{13}}\,j\)

\(\vec F \bullet \hat{v} = (0)\cdot \left(\frac{2}{\sqrt{13}} \right)+(-17)\cdot \left(\frac{3}{\sqrt{13}} \right)\)

\(\vec F \bullet \hat{v} = -\frac{51}{\sqrt{13}}\)

\(\vec F_{\parallel} = \left(-\frac{51}{\sqrt{13}} \right)\cdot \left(\frac{2}{\sqrt{13}}\,i+\frac{3}{\sqrt{13}}\,j \right)\)

\(\vec F_{\parallel} = -\frac{102}{13}\,i-\frac{153}{13}\,j\)

(b) Parallel and perpendicular components are orthogonal to each other and the perpendicular component can be found by using the following vectorial subtraction:

\(\vec F_{\perp} = \vec F - \vec F_{\parallel}\)

Given that \(\vec F = -17\,j\) and \(\vec F_{\parallel} = -\frac{102}{13}\,i-\frac{153}{13}\,j\), the component of \(\vec F\) perpendicular to \(\vec v\) is:

\(\vec F_{\perp} = -17\,j -\left(-\frac{102}{13}\,i-\frac{153}{13}\,j \right)\)

\(\vec F_{\perp} = \frac{102}{13}\,i + \left(\frac{153}{13}-17 \right)\,j\)

\(\vec F_{\perp} = \frac{102}{13}\,i -\frac{68}{13}\,j\)

(c) The work done by  \(\vec F\) through displacement \(\vec v\) is:

\(W = \vec F \bullet \vec v\)

\(W = (0)\cdot (2)+(-17)\cdot (3)\)

\(W = -51\)

Answer:

Just 3

Explanation:

I believe the other two are incorrect

The acceleration of the car is determined as 0.35 m/s².

The acceleration of the car is calculated by applying the formula for Newton's second law of motion as follows;

F(net) = ma

where;

Fy = F sinθ

200 = F x sin(30)

F = 200 / sin(30)

F = 400 N

The tension in horizontal direction;

Fₓ = 400 N x cos(30)

Fₓ = 346.4 N

The acceleration of the car is calculated as;

a = Fₓ / m

a = 346.4 / 1000

a = 0.35 m/s²

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The velocity of the punk at time t = 1.5 s is equal to 2.47 m/s.

The object will have two velocities during the projectile motion, one is horizontal velocity and the other is vertical velocity. The horizontal velocity of the object is constant throughout the projectile motion but the vertical velocity is changed in the projectile motion.

Given that the velocity vector is making an angle θ with a horizontal table, θ = 35°

The vertical component of the velocity of the puck can be determined as:\(u_x = u Sin 35^o = 3.60 \times 0.573 =2.06 m/s\)

The horizontal component of the velocity of the puck can be determined as:

\(u_y = u cos 35^o = 3.60 \times 0.82=2.95 m/s\)

Given the acceleration aₓ = -0.360 m/s² and a y = -0.980 m/s²

The final vertical components of the velocity of the punk are:

\(v_x = u_x + a_xt\)

\(v_x = 2.95 - (0.360) (1.5)\\v_x = 2.41 m/s\)

and, the horizontal velocity of the punk is:

\(v_y = u_y +a_yt\\v_y = 2.06 - (0.980) (1.5)\\v_y = 0.59 m/s\)

The velocity of the punk can be determined as:

\(v = \sqrt{v_x^2 + v_y ^2}\\ v =\sqrt{(5.80)^2 + (0.35)^2}\\ v = 2.47 m/s\)

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The frequency of f3 is approximately 716 Hz.

The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.

a. Given two frequencies, f1 and f2, the frequency ratio is as follows:

frequency ratio= \(\frac{f2}{f1}\)

Inputting the values provided yields:

frequency ratio = \(\frac{576}{320Hz}\) =1.8.

As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.

b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:

frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)=  \(\frac{f}{ (f1 / 1.3348) }\)

By dividing the numerator and denominator by 1.3348, we may make this more straightforward:

frequency ratio= (f × 1.33348)/f1

As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.

c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831

Therefore, the frequency of f3 is:

f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz

Therefore, the frequency of f3 is approximately 716 Hz.

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Answer:

B. Nuclear to Electrical

Explanation:

Atoms are split at power plants to create electricity. The energy conversion in this process is from nuclear to electrical energy.

Answer:

Carbon dioxide and water vapour

Explanation:

So the products of a combustion reaction are primarily:

carbon dioxide + water vapour, however other gases such as nitrogen, methane, and sulphur dioxide are also produced in smaller concentrations.

Carbon dioxide and water vapour are the main byproducts

Answer:

Carbon dioxide

Explanation:

The major byproduct of fossil fuel combustion is carbon dioxide. When fossil fuels such as coal, oil, and natural gas are burned, they release carbon dioxide into the atmosphere. This is because fossil fuels are made up of hydrocarbons, which are compounds made up of carbon and hydrogen. When these compounds are burned, they react with oxygen in the air to produce carbon dioxide \(\rm (CO_2)\) and water vapor \(\rm (H_2O)\).

Methane is also produced during fossil fuel combustion, but in smaller amounts compared to carbon dioxide. Sulfuric acid is not a byproduct of fossil fuel combustion, but rather a product of the reaction between sulfur dioxide \(\rm (SO_2)\) and water vapor in the atmosphere. While water vapor is also produced during fossil fuel combustion, it is not considered a major byproduct, as it is a natural component of the air and atmosphere.

According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.

Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.

Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.

He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.

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Answer:

B. 10 cm

x^3 = 1 L

1 L = 1000 cm^3 (since 1 L = 1000 cm^3)

x^3 = 1000 cm^3