The cost and revenue functions for producing and selling x units of a product are given.Cost and revenue are expressed in dollars. C(x)=125x+45,000, R(x)=125x. a. Find the number of units that must be produced and sold to break even. At this level, what is the dollar amount coming in and going out? b. Write the profit function from producing and selling x units of the product?

The  program for a  given rectangular matrix m,  if an element of m is equal to 0, sets that element's entire row and column to 0

def zeroify_matrix(m):  

rows = len(m)  

cols = len(m[0])  

rows_to_zeroify = []  

cols_to_zeroify = []  

for i in range(rows):

  for j in range(cols):

  if m[i][j] == 0:  

 rows_to_zeroify.append(i)  

cols_to_zeroify.append(j)  

for i in range(rows):  

for j in range(cols):

  if i in rows_to_zeroify or j in cols_to_zeroify:

   m[i][j] = 0  

return m

It is coded in python for the given problem of recreating a rectangular matrix, for a single element to be 0, the whole row nad column will contain zero elements.

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Answer:

\(m=\frac{7}{3}\)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Point (0, 7)

Point (-3, 0)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

A)
i) the inequality to show the number of ballons that the dance committee can buy is: 0.80b + 65 ≤ 125

ii)  solving the inequality above, we arrive at b ≤ 75
B) The graph is attached accordingly.

C) See the description of the solution below.

Let's start by defining our variables. Let b be the number of balloons that the dance committee could buy.

The cost of b balloons is $0.80b. We want to make sure that the cost of the balloons plus the amount already spent on decorations ($65) is less than or equal to the budget of $125. So we can write the following inequality:

0.80b + 65 ≤ 125

Now we can solve for b:

0.80b + 65 ≤ 125

0.80b ≤ 125 - 65

0.80b ≤ 60

b ≤ 75

Therefore, the dance committee can buy up to 75 balloons to stay within their budget.

To graph the solution set, we can plot b on the horizontal axis and shade the region to the left of b = 75, since b must be less than or equal to 75.

The solution set represents all possible values of b that satisfy the inequality. In this case, the solution set is b ≤ 75, which means that the dance committee can buy up to 75 balloons and still stay within their budget.

As the number of balloons increases, the cost of the balloons also increases, and the amount of money left in the budget decreases.

Therefore, the more balloons the dance committee buys, the less money they will have left for other decorations or expenses.

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Full Question:


Since the above question is incomplete, it appears you are referring to the question below.


The dance committee has a budget of $125 to decorate the gym for a spring dance. They already spent $65. Some members want to buy helium balloons that cost $0.80 each.

A) Write and solve an inequality to show the number of balloons that the dance committee could buy.

B) Graph the solution set for the inequality.
C) Describe what the solution means and how the number of balloons affects the amount in the budget.

Answer:

14/2+4x4-4= 19

Step-by-step explanation:

calculate

7+19-4

which is 19

(BODMAS rule is used here)

14/2 + 4 × 4 - 4

7 + 4 × 4 - 4

7 + 16 - 4

7 + 12

19

please mark brainliest <3

148

(-9 +61) - (5-101)

(-9 +61) = 52

(5-101) = -96

So, 52 - ( - 96 )

=> 52 + 96

=> 148

Hope it helps!

Answer:

-9+61-5+101

-14+162

148

hope this will help you

The 99% confidence interval for the population proportion is given as follows:

(0.4925, 0.5409).

The interpretation is that we are 99% sure that the population proportion is between these two values.

A confidence interval of proportions has the bounds given by the rule presented as follows:

\(\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}\)

In which the variables used to calculated these bounds are listed as follows:

The confidence level is of 99%, hence the critical value z is the value of Z that has a p-value of \(\frac{1+0.99}{2} = 0.995\), so the critical value is z = 2.575.

The parameters for this problem are given as follows:

\(n = 2820, \pi = \frac{1457}{2820} = 0.5167\)

Then the lower bound of the interval is given as follows:

0.5167 - 2.575sqrt(0.5167(0.4833)/2820) = 0.4925.

The upper bound of the interval is given as follows:

0.5167 + 2.575sqrt(0.5167(0.4833)/2820) = 0.5409.

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Answer:

Hello! answer: there are 7 quarters which are worth 25 cents each 6 dimes which are worth 10 cents each

there are 5 nickels which are worth 5 cents each and there are 8 pennies which are worth 1 cent each

the total value off all of these together is $2.68

Sphenathi and the other matriculants must travel at an average speed of approximately 107 km/h to reach Uptington by 09:45.

To determine the average speed at which Sphenathi and the other matriculants must travel to reach Uptington by 09:45, we need to calculate the time available for the journey and the distance between the two locations.

The time available is from 07:25 to 09:45, which is a total of 2 hours and 20 minutes. We need to convert this time to hours by dividing by 60:

2 hours + 20 minutes / 60 = 2.33 hours

Now, let's calculate the distance between Bloemfontein and Uptington. Suppose the distance is 'd' kilometers.

We can use the formula for average speed: average speed = distance / time

In this case, the average speed should be such that the distance divided by the time is equal to the average speed.

d / 2.33 = average speed

Now, let's assume that Sphenathi and the other matriculants must travel a distance of 250 kilometers to reach Uptington. We'll substitute this value into the equation:

250 / 2.33 = average speed

To find the average speed to the nearest km/h, we'll calculate the result:

average speed ≈ 107.3 km/h

Therefore, Sphenathi and the other matriculants must travel at an average speed of approximately 107 km/h to reach Uptington by 09:45.

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The person that is correct among the students is Frank who said the pencils are an example of parallel lines.

Parallel lines are lines that can never meet. These are lines that run a direction that is quite opposite to each other as we can see from the image. It is clear that the lines as shown are not able to meet at any point even if they are extended.

Thus, the person that is correct among the students is Frank who said the pencils are an example of parallel lines.

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A mathematics topic that van be looked into is how linear algebra, graph theory and optimization can be used on the airline industry.

In this case, to solve the scheduling issues faced by airlines such as planning flights, assigning planes and crews to routes - mathematical techniques can be employed.

By leveraging Linear Algebra, operators can simulate the flow of aircrafts and passengers while Graph Theory can help model flight schedules and aircraft routes.

Simultaneously using Optimization techniques in the problem-solving process can work to streamline various operations resulting in reduced costs and improved efficiency which can increase profit margins.

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Using it's concept, it is found that the absolute deviation of 30 in the data set is of 2.

The absolute deviation of a measure is given by the absolute value of the differente between the measure and the mean.

The mean is the sum of all observations divided by the number of observations. In this data-set, it is given by:

M = (26 + 35 + 27 + 30 + 22)/5 = 28

30 - 28 = 2, hence, the absolute deviation of 30 in the data set is of 2.

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Answer:

The answer is 2

Step-by-step explanation:

I took the test

Answer:

- Banking Operations salary in India with less than 1 year of experience to 10 years ranges from ₹ 1.4 Lakhs to ₹ 7 Lakhs with an average annual salary of ₹ 3.1 Lakhs based on 261 latest salaries

The value of -3√5 as the opposite of the square root is -75.

What in mathematics is a square root?

The factor we can multiply by itself to obtain a given number is the number's square root.

               Square root is represented by the symbol sqrt, which stands for square root of, end square root. Squaring an integer is the reverse of finding its square root.

-3√5

The opposite of the square root is the square, so,

-3√5 = -3 × 5²

-3√5 = - 3 × 25

-3√5 = - 75

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The the coefficient of variation for set a is 15.7% and the coefficient of variation for set b is 22.3%.

The formula for calculating the coefficient of variation is:

CV = (standard deviation / mean) x 100%

where standard deviation is a measure of the spread of the data around the mean. The CV expresses the standard deviation as a percentage of the mean.

To calculate the CV for set a, we first need to find the mean and standard deviation of the data set. The mean can be calculated by adding all the values and dividing by the number of values.

Mean = (3.97 + 3.47 + 3.99 + 4.30 + 3.16 + 3.07 + 4.24 + 2.94 + 3.56 + 3.43 + 3.06 + 3.34 + 4.35 + 3.57) / 14 = 3.65

The standard deviation can be calculated using a calculator or a spreadsheet software such as Microsoft Excel. For this set, the standard deviation is 0.574.

CV = (0.574 / 3.65) x 100% = 15.7%

To calculate the CV for set b, we need to first remove the dollar sign from each value and then find the mean and standard deviation.

Mean = ($24,800 + $30,000 + $22,300 + $20,400 + $19,000 + $32,200 + $23,000 + $23,000 + $24,000 + $27,200 + $34,900) / 11 = $25,727.27

The standard deviation can be calculated using a calculator or spreadsheet software. For this set, the standard deviation is $5,746.38.

CV = ($5,746.38 / $25,727.27) x 100% = 22.3%

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Answer:

\(\boxed {\boxed {\sf ( - \frac{9}{2}, -1) \ or \ (-4.5, -1) }}\)

Step-by-step explanation:

We are asked to find the midpoint of a line segment. When you find the midpoint, you essentially find the average of the x-coordinates and the y-coordinates. The midpoint formula is:

\((\frac {x_2+x_1)}{2}, \frac{y_2+y_1}{2})\)

In this formula, (x₁, y₁) and (x₂, y₂) are the endpoints of the line segment. we are given the endpoints R (-6, 1) and S (-3, -3). If we match the value and the corresponding variable we see that:

Substitute the values into the formula.

\(( \frac{-3 + -6}{2} , \frac{ 1+ -3}{2} )\)

Solve the numerators.

\((\frac {-9}{2}, \frac {-2}{2})\)

Divide.

\(( - \frac {9}{2}, -1})\)

The fraction can also be written as a decimal.

\((-4.5 , -1)\)

The midpoint of the line segment RS is (-9/2, -1) or (-4.5, -1).

Answer:

Area = 14¹/16 yd² or 14.0625 yd²

Step-by-step explanation:

2. The figure given is a square having equal sides of 3¾ yd each.

Formula for area of the square = a²

Where,

a = 3¾ yd

Plug in the value into the equation:

Area = (3¾)²

Change to improper fraction

Area = (15/4)²

Area = 225/16

Area = 14¹/16 yd² or 14.0625 yd²

Answer:

Mean: 30 students

Standard deviation: 5.2 students

Step-by-step explanation:

Khan

Answer:

x=4

Step-by-step explanation:

it tel you that f(x) = 7 so replace "f(x)" for 7 in the equation. You then get 7 = 4x - 9 so now you solve for x. You have to isolate x so you add 9 to the other side since you do the opposite of -9. Once you add 9 and 7, then divide the answer by 4. You should get 4 = x.

Work:

f(x) = 4x - 9

7 = 4x - 9

7 + 9 = 4x

16 = 4x

16 ÷ 4 = x

4 = x

Answer:

2x² + 5x + c = 0

For this quadratic equation to have one double root, the discriminant must equal 0.

5² - 4(2)(c) = 0

25 - 8c = 0

c = 25/8

2x² + 5x is not a perfect square because the coefficient of x², 2, is not a perfect square.

2x² + 5x is not a perfect square.

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Answer:

a) Countably Infinite

b) Countably Infinite

Step-by-step explanation:

To find - Determine whether each of these sets is countable or uncountable. For those that are countably infinite, exhibit a one-to-one correspondence between the set of positive integers and that set.

(a) integers not divisible by 3.

(b) the real numbers with decimal representations consisting of all 1s.

Proof -

a)

Let

A be the set of integers that are not divisible by 3

Now,

A is countably infinite.

The one-to one correspondence between the set to positive integers and A be -

f(n) = 3(n/4 - 1) + 1                if n is divisible by 4

     = 3(n-1)/4 + 2                 if n - 1 is divisible by 4 and n ≥ 1

     = -[ 3(n-2)/4 + 1]             if n - 2 is divisible by 4 and n ≥ 2

     = -[ 3(n-3)/4 + 2]             if n - 3 is divisible by 4 and n ≥ 3

b)

Let B be the set of the real numbers with decimal representations consisting of all 1s.

Now,

B is countably infinite.

The one-to one correspondence between the set to positive integers and B be -

When the function listed positive number, then we will list the corresponding negative number immediately after it before listing the next positive number.

Now,

The set of real number starts with 1, 11, 111, ... and the decimal representation consisting all 1s is -

1.1, 1.11, 1.111, 1.1111 .........(countable)

11.1, 11.11, 11.111, 11.1111 ........(countable)

111.1, 111.11, 111.111, 111.1111 ......(countable)

and so on

So,

There are countable infinite elements

Answer:

A. S(t) = 50 [3 ln t/ln2 +1]

Step-by-step explanation:

We are told that the rate of change in sales S is inversely proportional to time.

Thus;

dS/dt = k/t

Where k is the constant of proportionality.

So,

dS = (k/t)dt

Integrating both sides gives us;

S = (kIn t) + C

We are given that after 2 and 4 weeks are 200 units and 350 units respectively.

Thus;

S(2);

(k In 2) + C = 200 - - - (eq 1)

(k In 4) + C = 350 - - - -(eq 2)

To find k, let's subtract eq 1 from eq 2 to get;

(k In 4) - (k In 2) = 350 - 200

(k In 4) - (k In 2) = 150

k(In 4 - In 2) = 150

0.6931k = 150

k = 150/0.6931

k = 216.42

Plugging this for k in eq 1 gives;

(216.42 In 2) + C = 200

C = 200 - 150

C = 50

Thus;

S(t) = (216.42In t) + 50

Now 216.42 can also be expressed as;

150/In 2

Thus;

S(t) = ((150/In 2)In t) + 50

Factorizing out gives;

S(t) = 50 [(3 ln t/ln2) + 1]

Option A is the correct answer

Answer:

47

Step-by-step explanation:

I took the test

Answer:

a) the probability of A students study for more than 10 hours per week

P(X>10) = 0.117

b) The probability that an student spends between 7 and 9 hour

P(7<x< 9) = 0.9522

Step-by-step explanation:

Step(I):-

Let 'X' be random variable of  the normal distributed with a mean of 7.5 hours and standard deviation of 2.1 hours

mean of the Population is = 7.5 hours

standard deviation of the Population = 2.1 hours

\(Z = \frac{x-mean}{S.D}\)

Z = 1.1904

The probability of A students study for more than 10 hours per week

P(X>10) = 0.5-A(Z₁) = 0.5 -A(1.1904) = 0.5 - 0.3830 = 0.117

Step(ii):-

Put x=7

\(Z = \frac{7-7.5}{2.1}= -0.238\)

put x=9

\(Z = \frac{9-7.5}{2.1} = 0.7142\)

The probability that an A student spends between 7 and 9 hour

P(7 < x< 9) = A(9) - A(7)

                 = 0.7142 +0.238

= 0.9522





Answer:

a. Experiment

b. yes

Step-by-step explanation:

The study being conducted in this scenario is an experiment because different groups are being created and both an independant variable and dependant variable are being introduced. This means that there is researcher involvement and therefore makes this an experiment and not an observational study.

Yes, a case can be made for such a claim. This is because the music being played is the dependent variable in each of the groups. Meaning that the only difference in each of the groups was the music. Therefore, any differences in the data gathered can be connected to the music.

Answer:

x < -3 or x > 2

Step-by-step explanation:

x² + x - 6 > 0

Convert the inequality to an equation.

x² + x - 6 = 0

Factor using the AC method and get:

(x - 2) (x + 3) = 0

If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

x - 2 = 0

x = 2

x + 3 = 0

x = -3

So, the solution is x < -3 or x > 2

Answer:

Hello!!! Princess Sakura here ^^

Step-by-step explanation:

C≈12.57 yd

A≈12.57 yd²

Answer:

$6932.73

Step-by-step explanation:

16400(0.9175)^10

6932.73464

Egbert must deposit $19,602.52 as a lump sum in order to have $40,000 in the fund at the end of 10 years.

To calculate the required lump sum deposit, we can use the formula for compound interest:

A = P\((1+r/n)^{nt}\)

Where:

A = the future value (desired amount in the fund) = $40,000

P = the initial principal (lump sum deposit we need to find)

r = the annual interest rate in decimal form = 7% = 0.07

n = the number of compounding periods per year = 4 (quarterly compounding)

t = the number of years = 10

Plugging in these values, the formula becomes:

$40,000 = P\((1+(0.07/4)^{(4*10)}\)

Simplifying further:

$40,000 = P\((1.0175)^{40}\)

Now we can solve for P by dividing both sides of the equation by

P = $40,000 /\((1.0175)^{40}\)

Using a calculator to evaluate the expression, we find:

P ≈ $19,602.52

Therefore, Egbert must deposit approximately $19,602.52 as a lump sum in order to have $40,000 in the fund at the end of 10 years.

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