The complex [Zn(NH3)2Cl2]2 does not exhibit cis-trans isomerism. The geometry of this complex must be trans. :The complex [Zn(NH3)2Cl2]2 consists of 2 monomeric units, Zn(NH3)2Cl2. Here is the diagrammatic representation of the complex.
The complex is tetrahedral and thus does not exhibit cis-trans isomerism. This is because the complex does not have the required geometrical configuration for cis-trans isomerism.The compound is trans in shape. Therefore, the geometry of this complex must be trans. The term trans signifies a structure in which two ligands are present opposite to each other across the central metal ion.
In the trans isomer, the two identical ligands are present at the opposite ends of the molecule, and there is no plane of symmetry in this isomer. As a result, this isomer is chiral, with mirror-image isomers possible. The opposite of the trans isomer is the cis isomer. The cis isomer has two identical ligands on the same side of the molecule, with no ligands on the opposite side. Therefore, the geometry of this complex must be trans.
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1. Which of the following reactions best
represents the following particle diagram? (1pt)
a. 2 Na + Cl₂ 2 NaCl
b. Na₂ + 2 cl → Na₂Cl₂
c. Na₂ + Cl₂ → 2 Nacl
d. Na + 2 Cl₂ Nacl
Answer:
a. 2 Na + Cl₂ --> 2 NaCl
Explanation:
a is your answer because Cl is diatomic, there are 2 Na atoms, and the product is 2NaCl.
at a temperature of 250k, the molecules of an unknown gas, z, have an average velocity equal to that of hi at 500k. what is the identity of the gas?
The identity of the gas is hydrogen (H2).The average kinetic energy of gas molecules is directly proportional to the temperature. Using the formula for kinetic energy (KE = (1/2)mv^2), we can equate the kinetic energy of the unknown gas (Z) at 250K to that of hydrogen (H2) at 500K.
Since the average velocity is proportional to the square root of the kinetic energy, we can set up the following equation:
(1/2)mz(vz^2) = (1/2)mh(vh^2)
Given that mz is the molar mass of gas Z and mh is the molar mass of hydrogen (2 g/mol), and vz is the velocity of gas Z at 250K, and vh is the velocity of hydrogen at 500K.We can simplify the equation by canceling out the common factors:
mz(vz^2) = mh(vh^2)
The gas with an average velocity equal to hydrogen at twice the temperature is hydrogen gas itself (H2).
Since the average velocity of gas Z is equal to the average velocity of hydrogen at twice the temperature, the molar mass of gas Z must be half of the molar mass of hydrogen.
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Paper clips are made of stainless steel. Steel is a mixture. There are different kinds of steel that have slightly different ratios of substances. Stainless steel is made of iron mixed with high-density metals. Carbon steel is made of iron mixed with carbon, an element with a lower density than metals. Would you expect the density of stainless steel and carbon steel to be the same? Why or why not? Font Sizes
No, firstly bc stainless steel and carbon steel mixed with different things, high-density metals and carbon.
High-density metals and carbon both has different density which will affect the steel when they combined with iron. So it cant be the same.
if [a] and [b] are both 0.175 m, then the rate of reaction is 0.0030 m/s. what is the rate of the reaction if [a] is doubled?
Doubling the concentration of reactant [A] to 0.35 M will also double the rate of the reaction. Therefore, the new rate of the reaction will be 0.0060 M/s.
If [a] is doubled to 0.350 m, the rate of the reaction would still be 0.0060 m/s. This is because the rate of a reaction only depends on the concentration of the reactants and their respective reaction orders, not on their absolute values. Therefore, doubling the concentration of [a] would not affect the rate of the reaction as long as the concentration of [b] remains constant.
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For the reaction: 2P + 3Cl2 ---> 2PCl3
If 32.5 g of Cl2 reacts completely with excess P, how many grams of PCl3 will be produced?
If 32.5 g of Cl2 reacts completely with excess P, approximately 41.9 g of PCl3 will be produced.
To solve this problem, we'll use the stoichiometry of the balanced chemical equation and the molar masses of the reactants and products. Given the balanced chemical equation: 2P + 3Cl2 → 2PCl3
1. Calculate the moles of Cl2:
Molar mass of Cl2 = 2 × 35.45 g/mol = 70.90 g/mol
Moles of Cl2 = mass (g) / molar mass (g/mol) = 32.5 g / 70.90 g/mol ≈ 0.458 moles
2. Determine the moles of PCl3 produced using the stoichiometry:
According to the equation, 3 moles of Cl2 produce 2 moles of PCl3. So,
0.458 moles Cl2 × (2 moles PCl3 / 3 moles Cl2) ≈ 0.305 moles PCl3
3. Calculate the mass of PCl3 produced:
Molar mass of PCl3 = (30.97 g/mol) + 3 × (35.45 g/mol) = 137.32 g/mol
Mass of PCl3 = moles × molar mass = 0.305 moles × 137.32 g/mol ≈ 41.9 g
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Triangle W Z Y is cut by bisector Z X. The lengths of sides Z W and Z Y are congruent. ZX bisects ∠WZY. If the measure of ∠YXZ is (6m – 12)°, what is the value of m?
Answer:
m = 17
Explanation:
From the question we were given that
Triangle WZY is bisected by ZX; ZW = ZY
∠YXZ = (6m – 12)°
Based on the characteristics of the triangle, we see that triangle WYZ is an isosceles triangle (that is, triangle WXZ is equal to triangle YXZ)
<YXZ = <WXZ = 90°
Using ∠YXZ = (6m – 12)°
We have:
(6m – 12)° = 90°
6m = 90 + 12 ⇒ 6m = 102
m = 102 ÷ 6 = 17
m = 17
We therefore see that m is equal to 17
Answer:
B: 17
Explanation:
Why is the standard entropy of a substance in the gas state greater than its standard entropy in the liquid state?
The standard entropy of a substance in the gas state is generally greater than its standard entropy in the liquid state due to the greater molecular disorder and freedom of motion of the gas molecules compared to those in the liquid state.
In the gas state, the molecules have much more kinetic energy and are able to move freely and independently from each other, allowing them to occupy a larger volume and explore a greater number of possible states. This means that there are many more ways for the gas molecules to be arranged than in the liquid state, resulting in a greater degree of randomness or disorder. In contrast, in the liquid state, the molecules are more closely packed together and have less freedom of motion due to intermolecular forces of attraction. The number of possible states of the liquid molecules is therefore more limited than that of the gas molecules, resulting in a lower degree of randomness or disorder. Since entropy is a measure of the degree of randomness or disorder in a system, the greater molecular disorder and freedom of motion in the gas state leads to a greater standard entropy compared to the liquid state for the same substance.
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Acetone has the formula C3H6O. The empirical formula of vitamin C is _______.
Answer: The empirical formula of vitamin C is \(C_3H_4O_3\)
Explanation:
Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.
Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.
The molecular formula of Vitamin C is \(C_3H_4O_3\).
The simplest whole number ratio will be 3: 4: 3 , and thus empirical formula will be \(C_3H_4O_3\).
Ethanol is used as a fuel.
c2h5oh + 3o2 3h2o + 2co2
the complete combustion of one mole of ethanol releases 1350kj of energy.
a sample of ethanol reacts with excess oxygen to make 0.240dm3 of carbon dioxide,
measured at room temperature and pressure.
calculate the energy released, in kj, in this reaction
The energy released in this reaction can be calculated by using the stoichiometry of the balanced equation.
Since the balanced equation shows that 2 moles of ethanol produce 2 moles of CO2, we can assume that the reaction of 1 mole of ethanol will produce 1 mole of CO2. Therefore, we can use the given volume of 0.240 dm3 of CO2 to calculate the moles of CO2 produced.
From the balanced equation, we know that 1 mole of ethanol produces 2 moles of CO2. Since the volume of CO2 is given, we can use the ideal gas law to convert the volume to moles. Assuming room temperature and pressure (RT = 22.4 L/mol), we can calculate the moles of CO2 produced.
Once we have the moles of CO2, we can use the given energy value of 1350 kJ/mol to calculate the energy released in this reaction. Since 1 mole of ethanol produces 1350 kJ of energy, and we have determined the moles of CO2 produced, we can multiply the moles of CO2 by the energy value to obtain the energy released in kJ.
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What Celsius temp, T2, is required to change the volume of the gas sample in part A (T1=43 degrees Celsius, V1 = 1.65x 10^3 L) to a volume of 3.30x10^3L? Assume no change in pressure or amount of gas in the balloon.
The temperature, T2, is 359°C.
1st) We need to identify the volume and the temperature of the gas in the point A (initial state of gas) and point B (final state of gas):
- Point A:
V1= 1.65x10^3 L
T1= 43°C (316K)
-Point B:
V2= 3.30x10^3 L
T2= unknown
2nd) With the Ideal Gas Law and assuming there is no change in pressure or amount of gas in the balloon, we calculate the temperature in point B with the formula that relates temperature and volume:
\(\begin{gathered} \frac{V_1}{T_1}=\frac{V_2}{T_2} \\ \frac{1.65x10^3L_{}}{316K}=\frac{3.30x10^3L}{T_2} \\ T_2\cdot1.65x10^3L=3.30x10^3L\cdot316K \\ T_2=\frac{3.30x10^3L\cdot316K}{1.65x10^3L} \\ T_2=632K \end{gathered}\)It is important to use the units of the ideal gas constant, so the units must be in Kelvin (K) and liters (L). That's why the temperature (T2) it is 316 K.
3rd) Finally, it is necessary convert the Kelvin unit into Celsiud degrees:
\(\begin{gathered} T_2=632K-273 \\ T_2=359^oC \end{gathered}\)So, the temperature, T2, is 359°C.
During the process of peer review, a scientific study must have:
Group of answer choices (( its not precision//validity ))
repetition
precision
accuracy
validity
Answer:
Accuracy
I guess
Cause then it makes sense
Hope this helps
This element, in the nitrogen family, has more protons than silver, but less than xenon
Answer:
antimony
Explanation:
it has 51 protons, 4 more than silver and two less than xenon
The air around the equator has a high temperature, so it has a _______ air pressure. *
Explanation:
The air around the equator has a high temperature, so it has a _lower_____ air pressure
The atomic masses of 63Li and 73Li are 6.0151 amu and 7.0160 amu, respectively. Calculate the natural abundances of these two isotopes. The average atomic mass of Li is 6.941 amu.
If the atomic masses of 63Li and 73Li are 6.0151 amu and 7.0160 amu, respectively, then the natural abundances of these two isotopes would be respectively given that the average atomic mass of Li is 6.941 amu.
What is atomic mass?It is the sum of the mass of all the protons as well as the neutrons that are present inside the nucleus.
As given in the problem, the atomic masses of 63Li and 73Li are 6.0151 amu and 7.0160 amu, respectively and we have to calculate the natural abundances of these two isotopes. The average atomic mass of Li is 6.941 amu.
Let us assume the natural abundance of the 63Li be X and the natural abundance for 73Li be (1-X)
6.41 = 6.0151X + 7.0160 (1-X)
x = 0.6053
1-x = 0.3985
Thus, the natural abundance of the 63Li is 60.53% and the natural abundance of 73Li is 39.47 %.
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An inverse relationship can be represented by what?
Answer:
1/....
Explanation:
If we say acceleration 'a' is inversely proportional to mass 'm', then
a=1/m.
4. You have learned about the common characteristics of inner planets and outer planets. Explain
how these characteristics are verified observations and not just
the opinions of scientists. I’ll give you BRAINLIST PLEASE HELP I HAVE TO RIGHT IT DOWN!!
Answer:
We all know that the characteristics are proven, not just an opinion, because they meet the correct standards. The four inner planets are formed of rock and metal and have shorter orbits, slower rotation, and no rings. The four outer planets have longer orbits and spins, as well as a composition of gases and liquids, as well as a large number of moons and rings. The outer planets are known as gas giants because they are comprised of hydrogen and helium.
Answer: For fun FLVS
Explanation:
Which of the following elements CANNOT be extracted directly from air? a. nitrogen b. argon c. krypton d. chlorine. All of the choices are gaseous elements
The element that CANNOT be extracted directly from air is chlorine. This is the answer to the given question.
Air is a mixture of gases that are essential to sustain life. It is made up of nitrogen, oxygen, argon, carbon dioxide, neon, helium, and many other elements. There are several methods that are used to extract elements from the air.
However, not all elements can be extracted directly from air. This is because some elements are more reactive than others and they cannot be separated by simple techniques. For example, chlorine is a reactive element and cannot be extracted directly from air. It has to be prepared by chemical methods.
Chlorine is a chemical element that has the symbol Cl and the atomic number 17. It is a halogen and is located in group 17 of the periodic table. It is a yellow-green gas that is highly reactive and is used in the production of various chemicals.
Chlorine is also used to purify water and to sanitize swimming pools and other water bodies. It has a pungent odor and can be toxic if inhaled in large quantities. Chlorine is extracted from brine by the electrolysis of sodium chloride.
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A bottle containing 415 g of cleaning solution is used to clean hospital equipment. If the cleaning solution has a specific gravity of 0.860, what volume, in milliliters, of solution was used?
Answer: 483 mL of the cleaning solution are used to clean hospital equipment
Explanation:
The question requires us to calculate the volume, in mL, of solution is used to clean hospital equipment, given that 415g of this solution are used and the specific gravity of the solution is 0.860.
Measurements > Density
Specific gravity is defined as the ratio between the density of a given substance to the density of a reference material, such as water:
\(Specific\text{ gravity = }\frac{density\text{ of substance}}{density\text{ of reference substance}}\)The density of a substance is defined as the ratio between the mass and the volume of this substance:
\(density=\frac{mass}{volume}\)Considering the reference substance as water and its density as 1.00 g/mL, we can determine the density of the substance which specific gravity is 0.860:
\(0.860=\frac{density\text{ of substance}}{1.00g/mL}\rightarrow density\text{ of substance = 0.860g/mL}\)Thus, taking water as the reference substance, we can say that the density of the cleaning solution is 0.860 g/mL.
Now that we know the density of the cleaning solution (0.860 g/mL) and the mass of solution that is used to clean hospital equipment (415g), we can calculate the volume of solution that is used to clean the equipment:
\(\begin{gathered} density=\frac{mass}{volume}\rightarrow volume=\frac{mass}{density} \\ \\ volume=\frac{415g}{0.860g/mL}=483mL \end{gathered}\)Therefore, 483 mL of the cleaning solution are used to clean hospital equipment.
Which combination would act as an acidic buffer? A. HCl and NaOH B. CH3COOH and NaCH3COO C. HNO2 and HF D. NH3 and NH4Cl E. HCl and KCl
Answer
B. CH3COOH and NaCH3COO⁻
Explanation
By definition, a buffer is a solution of a weak acid and conjugate base or a weak base and conjugate acid used to resist pH change with added solute.
However, acidic buffers are solutions that have a pH below 7 and contain a weak acid and one of its salts.
Therefore, the combination that would act as an acidic buffer among the given options is:
B. CH3COOH and NaCH3COO
__ SnCl4 → __ Sn + __ Cl2
A. 221
B. 132
C. 121
D. 112
Answer:
Sn (s) + 2 Cl2 (g) → SnCl4 (l)
This is an oxidation-reduction (redox) reaction:
4 Cl0 + 4 e- → 4 Cl-I
(reduction)
Sn0 - 4 e- → SnIV
(oxidation)
Cl2 is an oxidizing agent, Sn is a reducing agent.
Reactants:
Sn
Names: Tin source: wikidata, accessed: 2019-09-07source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, Sn source: wikidata, accessed: 2019-09-07, Element 50 source: wikidata, accessed: 2019-09-07
Appearance: White crystalline powder source: ICSC, accessed: 2019-09-04; Gray to almost silver-white, ductile, malleable, lustrous solid. source: NIOSH NPG, accessed: 2019-09-02
Cl2
Names: Chlorine source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, Molecular chlorine source: NIOSH NPG, accessed: 2019-09-02
Appearance: Greenish-yellow compressed liquefied gas with pungent odour source: ICSC, accessed: 2019-09-04; Greenish-yellow gas with a pungent, irritating odor. [Note: Shipped as a liquefied compressed gas.] source: NIOSH NPG, accessed: 2019-09-02
Products:
SnCl4 – Tetrachlorostannane source: wikipedia, accessed: 2019-09-28source: wikidata, accessed: 2019-09-02, Tin tetrachloride source: wikipedia, accessed: 2019-09-28source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04, Tin(IV) chloride source: wikipedia, accessed: 2019-09-28
Other names: Stannic chloride source: wikipedia, accessed: 2019-09-28source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04, Tin(iv) chloride (anhydrous) source: ICSC, accessed: 2019-09-04
Appearance: Colorless to slightly yellow fuming liquid source: wikipedia, accessed: 2019-09-28; Colourless or slightly yellow fuming liquid with pungent odour source: ICSC, accessed: 2019-09-04
What happens when an ionic compound, lithium chloride, is placed in water?
Select one:
a. Solute particles in solution are uncharged.
b. The solute does not dissolve.
c. The molecule lithium chloride is found in solution.
d. The solute breaks apart into lithium and chloride ions.
Answer:
d
Explanation:
ionization takes place
In the lab, a student collects hydrogen gas over water in a eudiometer. The hydrogen gas is produced when a piece of magnesium metal reacts with excess hydrochloric acid. Part 1: (a) Write the balanced chemical equation for this reaction. Include the states of matter. Mg(s) + 2HCl (aq) — H2 (8) +MgCl, (aq) Part 2 out of 2 (b) How many moles of hydrogen gas are collected if 3.09 g of magnesium metal is used in the reaction? Report prc Moles of hydrogen gas mol H2
Moles of Hydrogen gas collected : 0.127
Further explanationThe reaction coefficient in a chemical equation shows the mole ratio of the components of the reactants and products
If one mole of the reactant or product is known, then we can determine the moles of the other compounds involved in the reaction
Reaction
Mg(s)+2HCl(aq)⇒H₂(g)+MgCl₂(aq)
mass of Mg=3.09 g
mol Mg (Ar= 24,305 g/mol) :
\(\tt mol=\dfrac{mass}{Ar}\\\\mol=\dfrac{3.09}{ 24,305}\\\\mol=0.127\)
Magnesium metal reacts with excess Hydrochloric acid, so Mg as a limiting reactant and moles of product is based on moles of Mg
From the equation, moles ratio Mg : H₂ = 1 : 1, so moles H₂ :
\(\tt \dfrac{1}{1}\times 0.127=0.127\)
which of the following compounds have integer i values? (select all that apply.) which of the following compounds have integer i values? (select all that apply.) kcl ch3cooh na2co3 hclo4
The following compounds have integer i values:KClNa2CO3
The following compounds have integer i values: KCl and Na2CO3.
i stands for van't Hoff factor and is the number of particles formed from one solute molecule in a solution.
An i value of 1 means that no particles are produced upon solvation or that the solute molecule exists independently in the solvent.
Conversely, an i value greater than one indicates that one molecule of solute produces more than one particle in the solvent. This includes molecules that dissociate into ions, form complexes, or exist in a solvent as aggregates.
It is worth noting that the i value is an experimentally derived value and may not necessarily be an integer.
According to the question, the following compounds have integer i values:KClNa2CO3
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A student leaves a 10.0 g ice cube in a sealed flask on the lab table. After some time, the ice melts. What is the mass of the liquid?Less than 10.0 g10.0 gNot enough informationGreater than 10.0 g
Step 1 - Understanding the law of mass conservation
In physics, chemistry and biology the law of mass conservation states that no atom is created or destroyed, they are only rearranged in any given physical/chemical/biological process.
Therefore, if all atoms are preserved, the total mass of reactants and products is the same.
Step 2 - Answering the exercise
The melting of an ice cube is a physical process and, as such, is also subjected to the law of mass conservation. Therefore, if 10g of ice melt, 10g of water are produced.
Answer: 10.0g
calculate how many mg of riboflavin was extracted? enter a number only; omit units. remember that ppm is equivalent to mg/l and that ppm
840.12 mg of riboflavin was extracted when the weight of the cereal sample is 1.526 g and the volume is 40 ml.
To calculate the concentration of the riboflavin extraction solution in ppm, we need to first calculate the concentration of the solution in ppb using the fluorescence intensity measurement and the calibration curve equation.
Given:
The weight of the cereal sample = 1.526 g
The volume of water used for extraction = 40.0 mL
The volume of acetic acid used for extraction = 0.25 mL
Fluorescence intensity measured at 146.00 a.u.
Calibration curve equation: y = 6.40 × x + 26.7
First, we need to calculate the concentration of riboflavin in the extraction solution using the fluorescence intensity measurement:
146.00 a.u. = 6.40 × x + 26.7
Solving for x, we get:
x = (146.00 a.u. - 26.7) / 6.40
x = 20.89 ppb
Now, we can convert the concentration from ppb to ppm:
ppm = ppb × 1000
ppm = 20.89 ppb × 1000
ppm = 20,890 ppm
Therefore, the concentration of the riboflavin extraction solution is 20,890 ppm.
To calculate how many mg of riboflavin was extracted, we need to use the following formula:
Amount of riboflavin = concentration of riboflavin x volume of solution
The volume of the extraction solution is 40.0 mL + 0.25 mL = 40.25 mL.
To convert the volume to liters:
Volume of solution = 40.25 mL ÷ 1000 mL/L = 0.04025 L
Now we can substitute the values into the formula:
Amount of riboflavin = 20,890 ppm x 0.04025 L
Amount of riboflavin = 840.12 mg
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The question is -
Following the grinding of 1.526 g of cereal, extraction of riboflavin is performed, using 40.0 mL of water and 0.25 mL of glacial acetic acid, followed by sonication and filtration. 200. uL of this extraction solution is diluted to 10 mL in pH 7.0 phosphate buffer. Fluorescence intensity measured 146.00 a.u. at the operational wavelength. If the external standard calibration curve equation (fluorescence intensity v. concentration in ppb) is y = 6.40 *x + 26.7, then what is the concentration of the extraction solution in ppm? Enter a number only; omit units. Remember that ppm is equivalent to mg/L and that ppm = ppb *1000.
Calculate how many mg of riboflavin was extracted. Enter a number only; omit units. Remember that ppm is equivalent to mg/L and that ppm = ppb *1000.
Why do some things stop while others keep going?
because they run out of energy.
EXPLANATION:
when it is transferred and to other objects, or their kinetic energy is converted into gravitational energy.
A jeweler has five rings, each weighing g, made of an alloy of silver and gold. She decides to melt down the rings and add enough silver to reduce the gold content to . How much silver should she add
Complete question :
A jeweler has five rings, each weighing 18 g, made of an alloy of 10% silver and 90% gold. She decides to melt down the rings and add enough silver to reduce the gold content to 75%. How much silver should she add?
Answer:
Kindly check explanation
Explanation:
Given the following :
Weight of each alloy = 18g
Initial % of Silver = 10% = 0.1
Initial % of Gold = 90% = 0.9
New % of gold = 75% = 0.75
Hence, new % of silver will be (1 - 0.75) = 0.25
Let the amount of silver to be added = s
Hence,
Initial gold content = final gold content + added silver
18 * 0.9 = 0.75(18 + s)
16.2 = 13.5 + 0.75s
16. 2 = 13.5 + 0.75s
16.2 - 13.5 = 0.75s
2.7 = 0.75s
s = 2.7 / 0.75
s = 3.6
S = 3.6
Hence the amount of silver needed per ring in other to reduce the gold content = 3.6g
Total for the 5 rings = (3.6 * 5) = 18g
Carlos likes to bowl. He timed how long it took for his ball to travel the length of an 18-m lane in the bowling alley. He plotted the final distance and time on a line graph. Carlos drew a line from this point to the origin of the graph.
Carlos likes to bowl. He timed how long it took his ball to travel the length of the bowling alley's 18-meter lane. The ball will travel 12 m far after it had travelled for 2 s.
What is length?Length can be defined as a term used for identifying the size of an object and distance travelled by the object from one point to another point.
The S.I. unit of length is meter.
It can also be defined as the amount of time that something can last.
Thus, Carlos likes to bowl. He timed how long it took for his ball to travel the length of an 18-m lane in the bowling alley. The ball will travel 12 m far after it had travelled for 2 s.
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Your question is incomplete but most probably your full question was
Carlos likes to bowl. He timed how long it took for his ball to travel the length of a an 18-m lane in the bowling alley. He plotted the final distance and time on a line graph. Carlos drew a line from this point to the origin of the graph.
How far down the lane was the ball after it had traveled for 2 s?
6 m
9 m
12 m
18 m
HELP ASAP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
When will a fossil be used in finding the absolute age of rocks?
A.if it existed for a limited period of time and in a small area
B.if it existed for a limited period of time and in a wide area
C.if it existed for a long period of time and in a wide area
D.if it existed for a long period of time and in a small area
An atom with which atomic diagram is most similar to calcium?
Answer:
C
Explanation:
Calcium is an element with a total of 20 electrons.
It has 4 shells with a configuration of:
2, 8, 8, 2
Option C is the most similar to calcium but the number of shells is not complete.
It still requires two more shells with 8 and two electrons respectively.