The circuit is working, and all three bulbs are lit. If a switch at B is opened,
what will happen to the circuit?
3
Y A. Bulbs 2 and 3 will go out, but bulb 1 will remain lit
• B. Bulb 2 will go out, but bulbs 1 and 3 will remain lit
• C. All three bulbs will go out.
Y D. All three bulbs will stay lit.

A) If the box moves at a constant velocity, what we know about the forces acting on the object is; the sum of the forces acting on the object must be zero.

B) If the box moves at a constant velocity, the force that opposes the motion of the box is; Frictional Force of -20 N

C) If the box experiences a force of 15 N to the left, along with the 20 N force acting to the right, the net force on the box is; F_net = 5 N

We are told that a box is being pulled across a horizontal surface by a 20N force to the right.

        In this case the opposing force will have to be the frictional force which will be -20 N to balance out the applied force.

Thus, the net force will be;

F_net = 20 - 15

F_net = 5 N

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Answer:

A simple machine is a mechanical device that helps to amplify or modify force, speed, or direction of motion. One common example of a simple machine is a lever. A lever is a rigid bar that rotates around a fixed point called a fulcrum. Depending on the placement of the fulcrum, levers can act as force multipliers, speed multipliers, or direction multipliers.

Explanation:

As an example, consider a seesaw with a length of 4 meters and a fulcrum positioned in the middle. If a person weighing 100 kg sits on one end of the seesaw, the force they apply to the lever is 100 kg x 9.81 m/s^2 = 981 N. If they push down on their end of the seesaw with a force of 500 N, the seesaw will move upward because the force they apply is greater than the weight of the person. In this case, the seesaw is acting as a force multiplier, amplifying the force applied by the person.

Alternatively, if the same seesaw is used to launch a ball, the person on one end could apply a smaller force over a longer distance. For example, if they apply a force of 50 N over a distance of 2 meters, the ball will be launched with a force of 100 N (50 N x 2) but a lower speed due to the increased distance traveled. In this case, the seesaw is acting as a speed multiplier, increasing the speed of the ball by decreasing the force applied but increasing the distance traveled.

Finally, if the seesaw is used to change the direction of motion, the fulcrum can be moved to one end of the lever and the force applied to the other end can be redirected. For example, if the seesaw is used to lift a heavy object by placing the object on one end and applying force to the other end, the seesaw is acting as a direction multiplier, changing the direction of motion of the force applied.

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One of the main reasons is that the windows and metal surfaces of the car act as a barrier to the outside air, trapping heat inside. This is known as the greenhouse effect, where the sun's rays enter the car and heat up the interior, but the windows prevent the heat from escaping.

Another factor is that cars are often made of materials that absorb and retain heat, such as upholstery and dashboard materials. These materials can heat up quickly and retain that heat, making the inside of the car feel even warmer than the outside air.Additionally, the shape and size of the car can also play a role in how warm it feels inside. For example, a small car with a small interior space will heat up more quickly than a larger car with more space for air to circulate.

To test these ideas, you could use a simple simulation by placing a thermometer inside a car on a sunny day and recording the temperature over time. You could then compare this to the temperature outside the car at the same time to see if there is a significant difference. Additionally, you could repeat this test with different types of cars and in different locations to see how these factors affect the temperature inside the car.

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Answer:

Who are the people for you then I can help you format the essay

Explanation:

Answer: 19.2N.

Explanation: To calculate Luna's weight on Asgard, we can use the formula:

weight = mass x gravity

where "mass" is Luna's mass and "gravity" is the gravitational acceleration on Asgard, which is given as 3.2 m/s^2.

So Luna's weight on Asgard would be:

weight = 6 kg x 3.2 m/s^2 = 19.2 N

Therefore, Luna's weight on Asgard is 19.2N.

La energía no se crea ni se destruye solo se transforma

Explanation:

espero y te ayude

The frequency of oscillation given the moment of inertia of the tire around the peg will be f = 1/2π✓(g/2R).

Given I = 2MR²

Torque = Mgsin(theta)R

Here, w = 2πf.

f = 1/2π✓(MgR/I)

f = 1/2π✓(MgR/2MR²)

f = 1/2π(✓g/2R)

Therefore, the frequency of oscillation is f = 1/2π(✓g/2R).

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Answer:

. ... Because ultrasound sound waves have a difficult time traveling through the air, ultrasound gel is used to reduce the air between your patient and the transducer to reduce acoustic impedance and reflection to allow for a clear image to be produced

The velocity of the tennis ball is -22 m/s when it is hit straight up in the air can be determined by analyzing its motion. To find the time at which the velocity is -22 m/s, we need to consider the acceleration due to gravity acting on the ball.

Since the ball is being thrown straight up, its initial velocity is positive, and it will experience a constant acceleration of -9.8 m/s² due to gravity. The velocity will decrease until it reaches zero at the highest point of its trajectory, and then it will become negative as it comes back down.

To calculate the time at which the velocity is -22 m/s, we need to determine the time it takes for the ball to reach its highest point, where its velocity is zero, and then calculate the additional time it takes for the ball to reach a velocity of -22 m/s.

Since the initial velocity is not provided in the question, it is necessary to know the specific initial velocity to calculate the time at which the velocity becomes -22 m/s accurately.

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Answer:

I believe it is True... I hope it is correct :)

Explanation:

Answer : False

Explanation :

Given,

The force applied by each person who is pushing the object, F=50 N

The frictional force, f=20 N

The frictional force is the force that opposes the motion of the object. As the people are pushing the object to the right, the frictional force will be directed to the left. And as the force with which people are pushing is greater than the frictional force, the net force will also be directed towards the right.

The net force is given by,

On substituting the known values,

Therefore the net force on the object is 80 N to the right.

Thus the correct answer is option 4.

To solve this problem, we can use the continuity equation, which states that the mass flow rate (the rate at which mass flows through a point in a system) must be constant throughout the system. In other words, the mass flow rate at point 1 must equal the mass flow rate at point 2.

The mass flow rate is equal to the density of the fluid times the flow rate (also known as the volume flow rate). The flow rate is equal to the cross-sectional area of the tube times the velocity of the fluid. Therefore, we can write the continuity equation as:

density \(${ }^*\left(\right.$\) cross-sectional area \(${ }^*$\) velocity )=constant

We can rearrange this equation to solve for the velocity at each point:

velocity = constant  (density* cross-sectional area)

At point 1 , the velocity can be calculated as follows:

\($\mathrm{V} 1=$\)constant\($/\left(\right.$\) density\($\left.{ }^* \mathrm{~A} 1\right\))= constant \($/\left(\right.$\) density \($\left.* 1.00 \mathrm{~cm}^{\wedge} 2\right)$\)

At point 2, the velocity can be calculated as follows:

V 2 = constant\($/($ density $* A 2)\)= constant \($/\left(\right.$\) density \($\left.* 4.00 \mathrm{~cm}^{\wedge} 2\right)$\)

We can find the value of the constant by using the pressure difference between the two points and the ideal gas law:

\($$\mathrm{P} 1-\mathrm{P} 2=\left(\text { density }^* \text { velocity }^{\wedge} 2\right) / 2$$\)

Substituting the known values, we have:

\($$9.45 \mathrm{kPa}=\left(\text { density }{ }^* \mathrm{~V} 1^{\wedge} 2\right) / 2$$\)

Note that the density of glycerin is not given, so we cannot calculate the exact values of V1 and V2. However, we can still determine the relationships between the velocities at the two points. Specifically, we can see that the velocity at point 2 is half the velocity at point 1 .

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Answer:

Reflection

Explanation:

The particles in the atmosphere only reflect the color blue and and all others are absorbed. Only the reflected colors can be seen from our eyes not the absorbed ones

the thinnest soap film that appears black when illuminated with light with a wavelength of 540 nm and a refractive index of 1.33 is approximately 101.5 nm thick.

The thinnest soap film that appears black when illuminated with light with a wavelength of 540 nm can be calculated using the equation for the optical path length of a soap film:

2nt = (m + 1/2)λ

where t is the thickness of the film, n is the refractive index of the soap film, m is an integer representing the order of the interference fringes, and λ is the wavelength of light.

For the film to appear black, we need destructive interference between the light waves reflecting from the top and bottom surfaces of the film. This occurs when the optical path length difference between the two waves is equal to an odd multiple of half the wavelength.

In the case of the thinnest black film, we want to minimize the thickness of the film while still satisfying the condition for destructive interference at a wavelength of 540 nm.

Setting m = 0, we have:

2nt = (1/2)λ

Substituting n = 1.33 and λ = 540 nm, we get:

2t(1.33) = (1/2)(540 nm)

Solving for t, we get:

t = 101.5 nm

Therefore, the thinnest soap film that appears black when illuminated with light with a wavelength of 540 nm and a refractive index of 1.33 is approximately 101.5 nm thick.

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The area of the region displayed on the radar scope is approximately 102.1 square miles. The closest answer choice is (a) 102.1, which matches our calculation. Hence option A) is the answer

To find the area of the circular region displayed on the radar scope, we need to calculate the area of the circle with the control tower at the center and a radius of 5.7 miles. The formula for the area of a circle is A = πr^2, where A is the area and r is the radius.

Substituting r = 5.7 miles into the formula, we get:

A = π(5.7)^2

A ≈ 102.1 square miles (to the nearest tenth)

Therefore, the area of the region displayed on the radar scope is approximately 102.1 square miles. The closest answer choice is (a) 102.1, which matches our calculation. Therefore the correct answer is option A).

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The area of the region displayed on the radar scope is approximately 102.1 square miles. The closest answer choice is (a) 102.1, which matches our calculation. Hence option A) is the answer

To find the area of the circular region displayed on the radar scope, we need to calculate the area of the circle with the control tower at the center and a radius of 5.7 miles. The formula for the area of a circle is A = πr^2, where A is the area and r is the radius.

Substituting r = 5.7 miles into the formula, we get:

A = π(5.7)^2

A ≈ 102.1 square miles (to the nearest tenth)

Therefore, the area of the region displayed on the radar scope is approximately 102.1 square miles. The closest answer choice is (a) 102.1, which matches our calculation. Therefore the correct answer is option A).

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Answer:D.carbon

Explanation:Protons are positively charged,neutron us nuetrally charged and electron is negatively charged and it contains a ne clues in the centre.

Answer:

Carbon

Explanation:

It is because Carbon is a relatively light element.

In this case, the film reflects most strongly red light at 640 nm and no green light at 512 nm. The thickness of the oil film is approximately 103.5 nm.

The thickness of the oil film can be determined using the equation for constructive interference in thin films:

2 * n * d = m * λ

where

n is the refractive index of the oil film,

d is the thickness of the film,

m is an integer representing the order of the interference, and

λ is the wavelength of the reflected light.

In this case, we have two equations:

2 * n * d = m * λ1 (for red light at 640 nm)

2 * n * d = m * λ2 (for green light at 512 nm)

We can divide the two equations to eliminate the integer m:

λ1 / λ2 = (m * λ1) / (m * λ2)

640 nm / 512 nm = 1.25

From this, we can determine that the refractive index of the oil film is 1.25.

Substituting the values into one of the equations, we can solve for the thickness of the oil film:

2 * 1.25 * d = 640 nm

d = 640 nm / (2 * 1.25)

d ≈ 103.5 nm

Therefore, the thickness of the oil film is approximately 103.5 nm.

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The height of the bleachers when a tennis ball dropped from the top and takes 3 seconds in flight is 45 m.

Height can be defined as the vertical distance between two points.

To calculate the height of the bleachers, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the height of the bleachers is 45 m.

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a) The net force acting on the box is 181 N at an angle of 17.3 degrees below the horizontal.

b) The box will have been pushed 2.26 m assuming the force is constant.

a) To find the net force, we need to resolve the applied force vector into horizontal and vertical components. The horizontal component is 225cos(27.0) = 196 N and the vertical component is 225sin(27.0) = 102 N. The frictional force acts in the opposite direction to the horizontal component, so the net force in the horizontal direction is 196 - 44 = 152 N.

The net force in the vertical direction is 102 N - 750 N (weight of the box) = -648 N. Using the Pythagorean theorem, the magnitude of the net force is sqrt((152 N)² + (-648 N)²) = 670 N. The angle between the net force and the horizontal is arctan(-648 N/152 N) = -17.3 degrees below the horizontal.

b) We can use the kinematic equation d = 1/2at² to find the distance the box travels in 5.00 s, where a is the acceleration of the box and t is the time. The net force in the horizontal direction is responsible for the acceleration of the box, so we can use F = ma to find the acceleration: a = F/m = 152 N/75.0 kg = 2.03 m/s².

Substituting into the kinematic equation, we get d = 1/2 * 2.03 m/s² * (5.00 s)² = 25.3 m. However, this assumes that the force is constant, which may not be true in reality.

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As per the given values, and uncertainty of the speedometer the actual speed could be 61.33 km/h.

Uncertainty = 2.0 km/h

Measured value = 90 km/h

Calculating the Percent uncertainty -

= (Uncertainty / Measured value) x 100

= (2.0 / 90 ) x 100

= 2.22%

Now, assuming the speedometer has the same percent uncertainty at 60 km/h, this percent uncertainty can be used to determine the range of speeds.

Percent uncertainty = 2.22%

Measured value = 60 km/h

Calculating the range -

= (Percent uncertainty / 100) x Measured value

= (2.22% / 100) x 60

= 1.33

Calculating the Total speed -

= 60 + 1.33

= 61.33

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Complete Question:

If your speedometer has an uncertainty of 2.0 km/h at a speed of 90 km/h ,what is the percent uncertainty? (b) If it has the same percent uncertainty when it reads 60 km/h , what is the range of speeds you could be going?

Answer:

Heat???

Sorry I am not at all sure

The ratio of magnitude 2 to magnitude 1 after the electric field change when the proton returned to its  starting point.is 1:1

The protons are ejected into an electric field pointing due north, and after 2 seconds the electric field changes to a constant uniform electric field pointing due south. 8.49 seconds after the field change, the proton returned to its starting point.

The protons were initially stationary and accelerated by the electric field. A proton's acceleration is directly proportional to its electric field and inversely proportional to its mass.

Two oppositely directed fields act on the protons, implying a net acceleration of zero. Therefore, the ratio of the magnitude of electric field 2 to the magnitude of electric field 1 is 1:1.

The ratio of magnitude 2 to magnitude 1 is 1:1

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Answer:

Explanation:

Sounds travel faster in object having high density proportion or matter. This is because particles vibrates and causing the other particle near to as well vibrate. Hence, when sound is moving from a higher dense medium like Water, the rate of traveling is high compare to it moving in air with less dense.

Since the mass is attached to an ideal spring, the system will undergo simple harmonic motion. The maximum distance the mass will fall is equal to the amplitude of the oscillation.

The period of oscillation can be calculated as:

T = 2π√(m/k)

where m is the mass and k is the spring constant.

Substituting the given values, we get:

T = 2π√(0.7 kg / 86 N/m) ≈ 0.887 s

The maximum distance the mass will fall is equal to half the amplitude of the oscillation, which can be calculated using the equation:

x = A cos(2πt/T)

where x is the displacement of the mass from its equilibrium position at time t, and A is the amplitude of oscillation.

At the maximum displacement, cos(2πt/T) will be equal to -1. Therefore,

A = -x

The velocity of the mass at the maximum displacement will be zero. Therefore, the total energy of the system will be equal to the potential energy at the maximum displacement:

1/2 k A^2 = m g A

where g is the acceleration due to gravity.

Solving for A, we get:

A = (m g / k) = (0.7 kg x 9.81 m/s^2) / 86 N/m ≈ 0.0807 m

Therefore, the maximum distance the mass will fall is approximately 0.0807 m.

The axial resistance of an axon is calculated using the formula R = ρL/A, where ρ is the resistivity, L is the length, and A is the cross-sectional area. In this case, the axial resistance is 11.28 MΩ.

The resistance along the axon is calculated using the following formula:

R = ρL/A

where:

R is the resistance in ohms

ρ is the resistivity in ohms per meter

L is the length in meters

A is the cross-sectional area in meters squared

In this case, we have:

ρ = 1.6 x 107 Ω.m

L = 0.5 mm = 0.0005 m

A = πr² = π(5 x 10-6)² = 7.854 x 10-13 m²

Therefore, the resistance is:

R = ρL/A = (1.6 x 107 Ω.m)(0.0005 m) / (7.854 x 10-13 m²) = 11.28 MΩ

Therefore, the axial resistance of the axon is 11.28 MΩ.

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Answer:

Explanation:Frequency

Hi, you did not enter the text about the Suarez family, which makes it impossible for this question to be answered accurately. However, from the context of your question, it is possible to see that you want to know two positive and negative points that the Suarez family would observe when starting a planting of organic agriculture.

Among the negative points, we can say that organic agriculture has a high cost, as the techniques used in it require a greater number of resources, which can make not only the service more expensive, but also the product. A second negative point is that the techniques used in organic agriculture are more difficult than the techniques used in conventional agriculture, since all management of organic crops must be carried out without the application of chemical products.

Among the positive points, we can say that the growing number of consumers of organic products can increase the profit that the family will have from the sale of these products. In addition, the family will have healthier, less polluted and more productive land.

Answer:

Sample response: Organic farming would have higher costs, and would be more complex than conventional farming. However, the Suarez family could charge a higher price for organic produce. This type of farming also would be better for the land.

Explanation: