The celestial sphere turns once around each day because.

Answer:

answer should be false

Answer:

1) Animals form groups to increase their chance of survival.

2) Animals stay in groups because it makes hunting for food easier.

3) Animals can protect their young ones much easier.

Explanation: Hope it helps you :)))))

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The only locational or central tendency metric that is given that is susceptible to extreme values is the mean.

To provide answers about programmes and efforts the most fundamental purpose of measurement. For instance, someone could be interested in finding out how many lectures were offered throughout the academic year, how many people took a certain course, or what the students thought of the course.

When something is done "just in case," it is handled in add to a slew of other tasks. I asked it again just to be sure. Some information on properties was added just for good measure.

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Answer:

Oh, I didn't know if u meant decigram or decagram! So for decagram there would be 10 grams and deci gram is 0.1 grams.  Hope this helps!!

Explanation:

Answer:

Hey there!

There are 10 grams in one decagram.

Let me know if this helps :)

The month in which  the United States experiences the highest level of thunderstorm activity is July.

The United States is a vast country with a diverse climate, and thunderstorm activity varies across different regions and seasons. However, on average, thunderstorm activity is most intense in the month of July across the entire country.

This is primarily due to the fact that July is the warmest month of the year in most regions, with high temperatures and high humidity levels creating unstable atmospheric conditions that are favorable for thunderstorm development.

In addition, the peak of the Atlantic hurricane season typically occurs in late summer, which can also contribute to increased thunderstorm activity in coastal regions. While thunderstorm activity can occur at any time of year, July tends to be the month when thunderstorms are most frequent and most intense across much of the United States.

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To compute the acceleration due to gravity on the surface of Venus, we can use the formula for gravitational acceleration:
acceleration due to gravity = (G * mass of planet) / (radius of planet^2)


Given that the mass of Venus is 81.5% that of the Earth, we can calculate the mass of Venus as follows:
mass of Venus = (81.5/100) * mass of Earth. Similarly, the radius of Venus is 94.9% that of the Earth, so we can calculate the radius of Venus as follows:
radius of Venus = (94.9/100) * radius of Earth
Now, substitute these values into the formula for gravitational acceleration:
acceleration due to gravity on Venus = (G * mass of Venus) / (radius of Venus^2)
Finally, calculate the acceleration due to gravity on Venus using the given values and the formula.

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We can use Faraday's Law of Induction to solve this problem:

EMF = -N * d(phi)/dt

where EMF is the induced electromotive force, N is the number of turns in the loop, and d(phi)/dt is the rate of change of the magnetic flux through the loop.

In this problem, we are given that the induced EMF is 4 V, the magnetic field is 0.25 T, and the time taken is 1.0 s. The magnetic flux through the loop is given by:

phi = B * A

where B is the magnetic field and A is the cross-sectional area of the loop.

Substituting these values into Faraday's Law, we get:

4 = -N * d(phi)/dt

4 = -N * (d/dt)(B * A)

4 = -N * (A * dB/dt)

4 = -N * (0.5 * 0.25)

N = -32

Since we cannot have a negative number of turns, we must take the absolute value of N:

N = |-32| = 32

Therefore, the loop must have 32 turns in order for there to be an induced EMF of 4 V.

The length of the pendulum is approximately 1.04 m, rounded to two significant figures.

The period (T) of a pendulum is given by T = \(2π√(L/g)\), where L is the length of the pendulum and g is the acceleration due to gravity (approximately 9.81 \(m/s^2\)). The frequency (f) of the pendulum is simply the inverse of the period, so f = 1/T.

Given that the frequency of the pendulum is 1.5 Hz, we can calculate the period as follows: f = 1/T 1.5 Hz = 1/T T = 1/1.5 s T = 0.667 s Now, we can use the period formula to find the length of the pendulum: T = 2π√(L/g) 0.667 s =\(2π√\)(\(L/9.81 m/s^2\)) 0.667 s/(\(2π\)) = \(√(L/9.81 m/s^2\)) 0.106 \(s^2/m =\) \(L/9.81 m/s^2 L\)= 1.04 m

Therefore, the length of the pendulum is approximately 1.04 m, rounded to two significant figures. It's important to note that the length of a pendulum affects its period and, consequently, its frequency.

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Snell's law depends not only on the refractive indexes of the materials but also on the "angle of incidence" and "angle of refraction" of the light rays.

Snell's law describes the relationship between the angles of incidence and refraction when light passes through the interface between two different materials. It states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the refractive indexes of the two materials.

Mathematically, Snell's law is expressed as:

n₁ * sin(θ₁) = n₂ * sin(θ₂),

where n₁ and n₂ are the refractive indexes of the first and second materials, respectively, and θ₁ and θ₂ are the angles of incidence and refraction, respectively.

Therefore, the accurate determination of the angles of incidence and refraction is crucial for applying Snell's law to analyze the behavior of light as it passes through different media.

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Answer:

B: C + O2 = CO2

Explanation:

In Chemistry,a synthesis reaction is one that occurs when two or more reactants combine in such a manner that they form a single product.

Looking at the options, the only one where 2 reactants combine to form a single product is option C where Carbon reacts with Oxygen to form carbon (IV) oxide.

Explanation:

1. the potential difference across the combination is the algebraic sum of yhe potential differences across the individual capacitors

2. the equivent capacitance of the combination is less than the capacitance of any of the capacitors..

Answer:

The RMS value for single phase equipment is 707 kV

Explanation:

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For a single-phase unit with a peak kilovoltage of 100 kVp, the RMS value would be approximately 70.7 kV.

to calculate RMS value?In a single-phase unit set at 100 kVp (peak kilovoltage), the root mean square (RMS) value can be calculated using the relationship between peak voltage and RMS voltage for a sinusoidal waveform. The formula to find the RMS value is:

RMS voltage = peak voltage / √2

In this case, the peak voltage is 100 kVp.

Therefore, to calculate the RMS value, simply divide 100 kVp by the square root of 2 (√2 ≈ 1.414):

RMS value = 100 kVp / 1.414 ≈ 70.7 kV

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The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:

\($$F=k\frac{q_1q_2}{r^2}$$\)

where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:

\($$E=\frac{kq}{r^2}$$\)  where k is the Coulomb constant.

So, let's calculate the electric field due to each charge separately and then add them up:

For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)

For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:

\($$E_2=\frac{kq_2}{r^2}\)

\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)

The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.

To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)

Substituting the values of E1 and E2:

\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)

net comes out to be -1.5×10⁴ N/C.

Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

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For a lateral projection of the foot, the central ray is directed to the side of the foot being imaged.

In particular, the central ray travels through the medial side of the foot, which is the side closest to the body's midline, and is directed perpendicular to the image receptor (such as an X-ray film or digital detector).

By providing a side image of the foot, this projection enables visualization and evaluation of the bones, joints, and soft tissues from a lateral angle. It is frequently employed in diagnostic imaging to assess foot fractures, dislocations, and other anomalies.

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(a) To calculate the flux passing through a cylinder of radius 2m and height 3m using the definition of flux, we need to evaluate the surface integral of the vector field over the curved surface of the cylinder.

The flux, Φ, is given by the equation:

Φ = ∬S F · dA

where S represents the surface of the cylinder, F is the vector field, dA is a differential area vector on the surface, and the double integral is taken over the surface S.

In cylindrical coordinates, the surface element dA can be expressed as r dθ dz, where r is the radial distance, θ is the azimuthal angle, and dz is the height element.

Let's proceed with the calculations:

Φ = ∬S F · dA

  = ∬S (r^2A + zrzk) · (r dθ dz)

The surface S can be parameterized as follows:

r = 2

θ ranges from 0 to 2π

z ranges from 0 to 3

Φ = ∫0^3 ∫0^(2π) (r^2A + zrzk) · (r dθ dz)

Expanding the dot product and integrating:

Φ = ∫0^3 ∫0^(2π) (2^2 A + z(2)(0)) r dθ dz

  = ∫0^3 ∫0^(2π) (4A) r dθ dz

  = ∫0^3 (4A) (∫0^(2π) r dθ) dz

  = ∫0^3 (4A) [rθ]0^(2π) dz

  = ∫0^3 (4A) (2π - 0) dz

  = ∫0^3 (8πA) dz

  = (8πA) [z]0^3

  = 8πA(3 - 0)

  = 24πA

Therefore, the flux passing through the cylinder is 24πA.

(b) Using the divergence theorem, the flux passing through the closed surface of the cylinder can be calculated by evaluating the volume integral of the divergence of the vector field over the volume enclosed by the surface.

The divergence theorem states:

∬S F · dA = ∭V ∇ · F dV

where V represents the volume enclosed by the surface S, ∇ · F is the divergence of the vector field, and the triple integral is taken over the volume V.

In this case, the divergence of the vector field F can be calculated as follows:

∇ · F = (∂/∂r)(r^2A) + (1/r)(∂/∂θ)(0) + (∂/∂z)(zrk)

      = 2Ar + 0 + 0

      = 2Ar

The volume V can be expressed as the product of the cylinder's height and the area of its base:

V = πr^2h

  = π(2^2)(3)

  = 12π

Now, let's calculate the flux using the divergence theorem:

∬S F · dA = ∭V ∇ · F dV

          = ∭V (2Ar) dV

          = 2A ∭V r dV

          = 2A ∭V r dr dθ dz

Integrating over the appropriate ranges:

∬S F · dA = 2A ∫0^3 ∫0^(2π) ∫0^2 r dr

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Answer:

important – mass, and distance.

The two vectors are linearly dependent when there are constants c1, c2, not both equal to zero, such that the vector equation c1 BOA + c2 BOB = 0 holds true.

Here, let's check for which values of h the vectors BOA and BOB are linearly dependent. Vector BOA = Vector BOB = <2h-1, h-1, 3-2h>.

We have to find the value of h for which the two vectors BOA and BOB are linearly dependent.

In order to do this, we need to determine the values of c1 and c2 that will satisfy the equation below:c1 (h-1) + c2 (2h-1) = 0c1 (2-h) + c2 (h-1) = 0c1 (h+1) + c2 (3-2h) = 0.

For the vectors to be linearly dependent, we have to check whether the system of equations above has non-trivial solutions, i.e. solutions where c1 and c2 are not both zero (when both are zero, we get the trivial solution).

From the first equation: c1 (h-1) + c2 (2h-1) = 0⇒ c1 (1-h) = c2 (2h-1)If h = 1, then both sides of the equation become 0. Thus, any value of c1 and c2 will satisfy this equation. Therefore, for h = 1, BOA and BOB are linearly dependent.  Answer: h = 1.

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Answer:

Your answer should be d: Foot

Explanation:

The unit "foot" is part of the english system which includes inches, feet, yards, etc.

The wavelength of light (nm) is required to eject an electron with a speed of \(2.0 \times 10^{6}\) m/s from a metal with threshold energy of \(3.4 \times 10^{-18 }\)jis 0.39nm.

A periodic wave's spatial period, or the distance across which the wave's form repeats, is defined by its wavelength. It is a characteristic of both traveling and standing waves as well as other spatial wave patterns, and it is the distance between two adjacent corresponding points of the same phase on the wave.

Speed of proton =\(c= 2.0 \times 10^6\) m/s

The threshold energy of the proton is \(E = 3.4 \times 10^{-18} J\)

The proton's wavelength is expressed as follows:

λ=hc/E

h is the Planck constant in this situation.

Now substituting the values,

λ= \((6.63\times 10^{-34}J/s\times 2.0 \times 10^{6} m/s)/3.4\times 10^{-18} J\)

=3.9x 10^-10 m

=0.39nm

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Answer:

4380N

Explanation:

you have to multiply mass with g

The weight of a 438 kg mass boulder on Earth is 4380N.​

The weight of an object is defined as the force acting on the object due to gravity. It is a standard mechanical quantity. Weight is also defined as a vector quantity because the force of gravity acts on the object.

The formula for calculating weight is

\(W_w_e_i_g_h_t= F_n_e_t_e_x_t_e_r_n_a_l = m*g\)

where F is the weight of the object in newtons (N)

m is the mass of the object in kilograms

g is the acceleration due to gravity i.e.\(9.8 m/s^2\)

Newton is the SI unit for weight.

For above given information,

Weight= m*g

m= 438 kg

g= 10 N/kg

So, W= 438*10= 4380 N

Thus, the weight of a 438 kg mass boulder on Earth is 4380N.​

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If the following forces act on an object: 50 N North, 20 N South, and 30 N west, then the magnitude of the net force would be 42.42 Newtons.

What is a force?

Force is the displacement of an object and the rate at which an object of mass is accelerated for a particular distance. This quantity is a vector quantity that contain the magnitude of the quantities along with the direction.

Examples of vector quantities are displacement, velocity, acceleration, force, etc.

As given in the problem if the following forces act on an object: 50 N North, 20 N South, and 30 N west.

The net force = √ ( 30² + 30² )

                     = 42.42 Newtons

Therefore, the magnitude of net force applied in three direction is 42.42 N.

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Answer:

Explanation:

Water waves are generally a transverse wave which do not cause permanent displacement of molecules of the medium. Transverse waves are waves in which the direction of propagation of the wave is perpendicular to the direction of vibration of the particles of the medium.

As the wave propagates from one point to another on the surface of water transferring energy, a molecule of water on its surface vibrates upwards and downwards. Its motion is perpendicular to the direction of propagation of the wave. After the vibration, it comes back to its initial position.

Answer:

0.3937008

Explanation:

Answer: 1 centimeter is your answer

I apoligize that this is a late answer , I stumbled upon this post. Good luck to any future veiwers. P.S the picture below is for a similiar question for other students who pressed this post

Answer:

» (a)

Explanation:

Velocity is the rate of change in displacement.

\({ \rm{velocity = \frac{ \triangle displacement}{time} }} \\ \)

The change from one position to another is displacement or distance between the points.

\( = { \rm{ \frac{22000}{200} }} \\ \\ = { \tt{110 \: m {s}^{ - 1} }}\)

The dwarf planet Eris orbits the Sun every 557 years. The average distance (semimajor axis) from the Sun is 67.7 a.u.

A line segment that passes through the center and periphery foci and terminates at the broadest points of the perimeter is known as an ellipse's main axis in geometry. The semi-major axis goes from the center via a focus and out to the periphery since it is one of the main axes. In essence, it is the radius of an orbit at its two farthest points. The radius serves as the semi-major axis for the unique instance of a circle. The semi-major axis can be compared to the long radius of an ellipse.

A line segment associated with most conic sections, such as ellipses and hyperbolas, and which forms right angles to the semi-major axis is known as the semi-minor axis (a semi-minor axis).

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▹ Answer

This organelle is known as the mitochondria,

▹ Step-by-Step Explanation

The mitochondria is the site of cellular respiration and is often referred to as the "powerhouse of the cell". The mitochondria makes energy which is known as ATP, and also operates other processes.

Hope this helps!

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Answer:

The Mitochondria

Explanation:

The mitochondria is often known as the powerhouse of the cell.

This is because it produces energy (ATP) by breaking down glucose.

Also, as mentioned, it is where cell respiration takes place.

So, the coefficient of kinetic friction approximately 0.21.

Hi ! Here I will help you to solve the problem of the coefficient of kinetic friction. An object that experiences kinetic friction, indicates that the object move from its place. Remember that friction is also a force, but reduces the value of the force acting. Kinetic friction force is influenced by the normal force (N) and the coefficient of kinetic friction. The greater the value of the normal force (N) and/or the coefficient of friction, the greater the value of the kinetic friction force. [See the attached image to see the breakdown of the friction force].

For kinetic friction, there are the following equations that you will use in various problem conditions. However, the equation in the box is the formula you use for solve this problem.

\(\sf{\sum F = m \cdot a}\)

\(\sf{F - f_k = m \cdot a}\)

\(\boxed{\sf{\bold{F - \mu_k \cdot m \cdot g = m \cdot a}}}\)

With the following condition:

We know that:

What was asked ?

Step by step:

\(\sf{F - \mu_k \cdot m \cdot g = m \cdot a}\)

\(\sf{300 - \mu_k \cdot 145 \cdot 9.8 = 145 \cdot 0}\)

\(\sf{-\mu_k \cdot 1,421 = -300}\)

\(\sf{\mu_k = \frac{-300}{-1,421}}\)

\(\boxed{\sf{\mu_k \approx 0.21}}\)

So, the coefficient of kinetic friction approximately 0.21.

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