the cardiovascular control center in the medulla receives input from the __________.

Answer:

4800N

Explanation:

Given parameters:

Mass of car  = 1200kg

Acceleration = 4m/s²

Unknown:

Resultant force on car  = ?

Solution:

From Newton's first law of motion:

     Force  = mass x acceleration

 Insert parameters and solve;

   Force  = 1200 x 4  = 4800N

Answer: I never said anything to them but if i did it would be "I need a break from you, i love you but sometimes I have to find the path on my own." i would say this if i wasn't scared to hurt them.

Explanation:

The remote PIC/visual observer could make a call on the Common Traffic Advisory Frequency (CTAF) to alert the manned pilot by stating the position of the UAV and the altitude it is flying at.

The call could go something like this: "Attention all aircraft on CTAF, this is [call sign of UAV]. We have a manned aircraft approaching our area from the west and flying just north of the area from west to east at [altitude].

Please be aware of our UAV operations and take necessary precautions to avoid any potential conflicts." This call should be made in a calm and clear manner, ensuring that the manned pilot understands the situation and can take appropriate action to avoid any collisions or safety hazards.

It is important to maintain situational awareness and communicate effectively to ensure safe operations of both manned and unmanned aircraft in the airspace.

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A speaker crossover is used in a sound system to separate different frequencies and direct them to the appropriate speakers. When designing a filter for a speaker crossover circuit, it is essential to consider the range of frequencies the speaker is capable of playing.The speaker, in this case, can play sounds from 600Hz to 3kHz, which is a relatively narrow frequency range.

An appropriate filter for this speaker can be designed using a 1µ capacitor in conjunction with a 2.2mH inductor. A filter with these values will create a bandpass filter that allows frequencies between 600Hz and 3kHz to pass through, while blocking other frequencies.

This type of filter is known as a second-order filter. It can be created using a combination of a low-pass filter and a high-pass filter, or a bandpass filter, which is a combination of both.To calculate the values of the components required for a second-order filter, the following formulas can be used:1. For the capacitor C, the formula is C=1/(2πfR), where f is the cutoff frequency and R is the resistance in ohms.

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Explanation:

1. Mass of an object

2. Distance between the objects

Answer:

When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.

Explanation:

PLEASE let me know you are satisfied with my answer or not☺☺

The correct answer is Smaller than that of star B.

The parallax angle of a star is inversely proportional to its distance from Earth. Therefore, if star A is closer to us than star B, star A's parallax angle will be smaller than that of star B. The parallax angle is a measure of the apparent shift of a star's position when viewed from different vantage points on Earth's orbit.

Parallax is used to determine the distance to nearby stars. By measuring the parallax angle of a star, astronomers can calculate its distance using trigonometric principles. The smaller the parallax angle, the greater the distance to the star.

In the context of the question, since star A is closer to us than star B, it means that star A is at a shorter distance from Earth. Consequently, its parallax angle will be smaller compared to the parallax angle of star B, which indicates that star A is farther away from us than star B.

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Answer: A. When half the parent nuclei in a sample have become daughter nuclei

Explanation:

D, it provides greater accuracy for measuring stars far from the earth.

The answer is "It provides greater accuracy for measuring stars near the earth."

The stress in the rod when loaded is approximately 80 GPa.

1) Given, the maximum load in a tensile test of a mild steel specimen with size 25 mm × 25 mm in square is 120kN.

The area of the square steel specimen,

A = 25 mm × 25 mm

=625 mm²

=0.625 × 10⁻³ m²

Therefore, the maximum stress in the steel specimen,

σmax=F/A

=120 × 10³ N/(0.625 × 10⁻³ m²)

=192 × 10⁶ N/m²

Greatest tensile load on a bar 25 mm in diameter of the same material = Load on a cylindrical bar of the same material having diameter 25 mm.

Now, area of the cylindrical bar having diameter 25 mm,

A=πd²/4

=π × 25²/4 mm²

=(25²/4)π mm²

=(6.25π) mm²

=(6.25π) × 10⁻⁶ m²

Now, stress in the cylindrical bar having diameter 25 mm is given by σ=F/A, where F is the force acting on it.

∴ F=σ × A

=5 × σmax × 6.25π × 10⁻⁶ N=31.25 πσmax N

The greatest tensile load on a bar 25 mm in diameter of the same material is 31.25π

σmax N when a safety factor of 5 is to be used.

2) Given, the length of an aluminum alloy rod of diameter d=12 mm, l₁=205 mm.

The length of the rod when compressed,l₂=199.9 mm.

The stress in the rod when loaded is given by

σ=F/A

=force/area

Where,

A=πd²/4

=π × (12 × 10⁻³ m)²/4=π × 144 × 10⁻⁶ m²=0.00045216 m²l₁-l₂=205-199.9=5.1 mm

Change in length=Δl=l₁-l₂=5.1 mm=5.1 × 10⁻³ m

Using the formula, Young’s modulus

=E=stress/strain

=(F/A)/(Δl/l₁)

⇒ F=E × A × (Δl/l₁)

=80 × 10⁹ Pa × 0.00045216 m² × (5.1 × 10⁻³ m/205 × 10⁻³ m)

≅8.98 kN

The stress in the rod when loaded is approximately 80 GPa.

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Answer:

the answer is C ----- it is the rate of change of velocity per unit time

Explanation:

acceleration

\( = \frac{velocity(v)}{time(t)} \)

Answer:

76.9231

Explanation:

Divide 400m by 5.2 to get the answer.

Speed = (distance) / (time to cover the distance)

Speed = (400 m) / (5.2 minutes)

Speed = (400 m) / (312 seconds)

Speed = 1.28 m/s

There's not enough given information to find his velocity.

(I'll be honest with ya, Flash: 1.28 m/s is no big deal. It's only about 2.87 miles per hour. My dog can walk faster than that, and so can most healthy people. If that's the best you can do, then you probably shouldn't be running around chasing bad guys.)

These graphs do not consistent with one another because one is graph of potential energy U(x)  vs distance(x)  and two is graph of force (F(x)) vs distance(x).

Potential energy in physics is the energy that an item retains as a result of its position in relation to other objects, internal tensions, electric charge, or other elements.

Now, if a force F(x) is applied on an object, that caused a displacement of the object a distance x. Then potential energy of the object is:

U(x) = ∫ F(x)dx.

Hence, U(x) ≠ F(x)

That's why, these graphs  do not consistent with one another.

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The spring constant is 2 N/m. The result is obtained by using the Hooke's Law formula.

The Hooke's Law states that the restoring force of a spring equals the spring constant times the change in length. It can be expressed as

F = -kΔx

Where

Note: the minus sign indicates that F is in the opposite direction to the displacement of a free end.

Given the length of a spring is 10 m. When it is stretched by a force of 16 N, the length is increased to 18 m. What is the spring constant?

From that information, we get the change in length.

Δx = 18 m - 10 m

Δx = 8 m

The spring constant is

F = -kΔx

16 = -k . 8

k = - (16/8)

k = 2 N/m

Hence, the spring constant is 2 N/m.

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Answer:

There are \(9.537\times 10^{-23}\) kilograms of radioactive material after 300 seconds.

Explanation:

From Physics we know that radioactive materials decay at exponential rate, whose differential equation is:

\(\frac{dm}{dt} = -\lambda\cdot m\) (1)

Where:

\(\frac{dm}{dt}\) - Rate of change of the mass of the radioactive material, measured in kilograms per second.

\(m\) - Current mass of the radioactive material, measured in kilograms.

\(\lambda\) - Decay constant, measured in \(\frac{1}{s}\).

The solution of the differential equation is:

\(m(t) = m_{o}\cdot e^{-\lambda\cdot t}\) (2)

Where:

\(m_{o}\) - Initial mass of the radioactive material, measured in kilograms.

\(t\) - Time, measured in seconds.

If we know that \(m_{o} = 20\,kg\), \(\lambda = 0.179\,\frac{1}{s}\) and \(t = 300\,s\), then the initial mass of the radioactive material is:

\(m(t) = (20\,kg)\cdot e^{-\left(0.179\,\frac{1}{s} \right)\cdot (300\,s)}\)

\(m(t) \approx 9.537\times 10^{-23}\,kg\)

There are \(9.537\times 10^{-23}\) kilograms of radioactive material after 300 seconds.

Answer:

Density = Mass/volume. D= 60/30.Divide it and you'll get ur answer as 2

Answer:

So let's first start with the base which is a rectangle remember that the formula to solve the area

Explanation:

Answer:

Cardiovascular or cardio exercise refers to exercise that strengthens the cardiovascular system. The term Aerobic just means in the presence of oxygen, and aerobic exercise refers to exercise that you perform long enough to require oxygen.

From the given position -time graph it is clear that, Amiya covers a distance of 40 meters within 12 seconds.

A position - time graph is used to determine the change in position with respect to the time. We can calculate the average speed of the object from the position -time graph.

Speed is the measure of distance covered within unit time. Hence, it is the ratio of change in position to the change in time. Speed has the unit of m/s .It can also defined as the rate of displacement of an object.

From the given plot, it is clear that the Amiya is 40 meters far after 12 seconds run. After that she stops and the position gets constant. Hence, option A is correct.

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Answer:

333N

Explanation:

=>First you have to find the mass of the asteroid.

so 882N÷9.8m/s²=90Kg

then,multiply it by Mars's gravity

=>90Kg*3.7m/s²=333N

As a result, the axle exerts a torque of 29.431Nm (or 29.431 N m) in a clockwise direction.

The difference between the moments of the applied forces determines the necessary torque at the axle.

19.62 Nm of torque is needed in a counterclockwise direction.

Reasons:

The parameters listed are;

The disk weighs 5.0 kg.

Axle location equals half the disk's radius

Disk diameter, D = 40 cm = 0.4 m

15 kg applied mass at 0.1 meters from the axle

10 kilogram applied mass at 0.3 meters from the axle

Counterclockwise moment is equal to 14.715 Nm for 15 kg, 0.1 m, and 9.81 m/s2.

+ Clockwise moment minus counterclockwise moment

τ + 14.715 N·m = 34.335 N·m

Required torque is equal to 34.335 Nm minus 14.715 Nm, or 19.62 Nm.

Needed torque is 19.62 Nm in the anticlockwise direction.

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a) To maintain an overall efficiency of 0.3, the biggest difference in solar collector temperature to ambient temperature (in degree Celsius) that the system can operate in is 89.47°C.

b) If water enters the solar collector at 25°C and 1.5 kg/s, the temperature of water (in degree Celsius) at the exit of the collector is 50.14°C.

a) The formula for the biggest temperature difference between the solar collector and the ambient temperature is given below:

q_solar = A_c ατ Iₒ - A_c ULMTΔT = A_c [ατ Iₒ - ULMTΔT]

We can rearrange this formula as follows:

ΔT = ατ Iₒ / ULM - ΔT / ULM

where Iₒ = irradiation, α = product of transmissivity and absorptivity of the collector, ULM = overall heat transfer coefficient, A_c = area of collector, ΔT = T_collector - T_ambient.

Substituting the given values in the above formula, we get:

ΔT = (0.85 × 800) / (8 × 2) - (0.3 × 8) / (2 × 0.85) = 89.47°C

Thus, the biggest difference in solar collector temperature to ambient temperature is 89.47°C (approx).

b) The formula to calculate the exit temperature of water from the solar collector is given below:

ṁ₁Cp(T₁ - T₀) = q_solar - ṁ₂Cp(T₂ - T₀)

whereT₁ = Inlet temperature of water into the solar collector, T₂ = Outlet temperature of water from the solar collector, T₀ = Ambient temperature, Cp = Specific heat of water, q_solar = Heat absorbed by the collector, ṁ₁ = Mass flow rate of water entering the collector, ṁ₂ = Mass flow rate of water leaving the collector

The mass flow rate of water is given as 1.5 kg/s. Specific heat of water is 4.18 kJ/kg.K.

Substituting the given values in the above formula, we get:

1.5 × 4.18 (50 - 25) = (800 × 0.85 × 2) - 1.5 × 4.18 (T₂ - 25)

37.425 = 1360 - 6.27 T₂ + 94.05

T₂ = 50.14°C

Thus, the temperature of water (in degree Celsius) at the exit of the solar collector is 50.14°C (approx).

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Answer:

Explanation:

According to Newton's second law

F = ma

m is the mass = 0.12kg

a is the acceleration = v-u/t

a = 5-0/0.6

a = 5/0.6

a = 8.333m/s²

Get the force

F = 0.12 * 8.333

F = 1.0N

Hence the average resultant force acting on the ball while it is being hit is 1.0N

Explanation:

It is given that,

Initial velocity of the projectile, u = 142 ft/s

Initial height off the ground, \(h_o = 93\ feet\)

We need to find the height of the projectile t seconds after its shot. It is a concept of kinematics. The equation of projectile is given by the formula as follows :

\(h= -16t^2+ut+h_o\)

t is time in seconds

So, putting all the values we get :

\(h= -16t^2+128t+112\)

Hence, this is the required solution.

Answer:

KE is not conserved because it takes work to pull on the string

(KE is a scalar and not a vector quantity)

Momentum is conserved because any force acting on the particle is perpendicular to its direction of motion

Answer:

b

Explanation:

because its b duuuuuuuu

Given 16 kg of a radioactive sample with a certain half-life of 15 years:

To determine how much of the 16 kg radioactive sample is left after 60 years with a half-life of 15 years, we will use the following steps:

1. Calculate the number of half-lives that have passed: 60 years / 15 years per half-life = 4 half-lives
2. Calculate the remaining sample amount using the formula: remaining amount = initial amount * (1/2)^number of half-lives
3. Apply the formula: remaining amount = 16 kg * (1/2)^4 = 16 kg * 1/16 = 1 kg

After 60 years, 1 kg of the radioactive sample is left. The correct answer is D. 1kg.

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The chemical formula for dinitrogen tetroxide is C) N204.

Nitrogen that exists in its diatomic form, which is also known as molecular nitrogen or nitrogen gas, is referred to as dinitrogen. This form of nitrogen has two nitrogen atoms joined by a triple covalent bond, which satisfies the Lewis electron rules by having two lone, nonbonding electron pairs, one on each Nitrogen atom.

Whereas Dinitrogen tetroxide is colourless, Nitrogen dioxide is brown. As the temperature drops, the brown color's intensity falls. As a result, a drop in temperature results in a rise in Dinitrogen tetroxide. As temperature drops, equilibrium is pushed to the Dinitrogen tetroxide side.

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Explanation:

since oil needs more boiling time and a higher boiling temperature the oil would have to be in the pot longer than the water if it needs to be boiled longer that is why the blue line for oil temp. is significantly higher than that of the water temp.

a) Work needed to stretch the spring from 12 m to 14 m is 8 J. b) Force of 64 N will keep the spring stretched by 16 m beyond its natural length.

When spring is stretched or compressed, such that length changes by an amount x from its equilibrium length, then it exerts force F = -kx in a direction towards its equilibrium position.

(a) Potential energy, U = (1/2)kx^2

k is spring constant, and x is displacement from natural length of spring.

W = U = (1/2)k(9-6)^2 = (1/2)k(3)^2 = (9/2)k

Therefore, k = (2/9)W = (2/9)(18 J) = 4 J/m.

W = (1/2)k(14-12)^2 = (1/2)(4 J/m)(2 m)^2 = 8 J

So the work needed to stretch the spring from 12 m to 14 m is 8 J.

(b)F = kx

F is force, k is spring constant, and x is displacement from the natural length of spring.

x = F/k = 64 N / 4 J/m = 16 m

Therefore, a force of 64 N will keep the spring stretched by 16 m beyond its natural length.

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