The binding of aspartic acid to the c1 carbon during catalysis is an example of a covalent bond formation or a nucleophilic substitution mechanism. During the reaction, aspartic acid, which is an amino acid, undergoes nucleophilic substitution and forms a covalent bond with the substrate.
This reaction is part of the mechanism by which aspartic acid proteases cleave peptide bonds. Aspartic acid proteases are a type of enzyme that uses aspartic acid as its active site residue. The binding of aspartic acid to the c1 carbon during catalysis is an example of a covalent bond formation or a nucleophilic substitution mechanism. During the reaction, aspartic acid, which is an amino acid, undergoes nucleophilic substitution and forms a covalent bond with the substrate. This reaction is part of the mechanism by which aspartic acid proteases cleave peptide bonds.
Aspartic acid proteases are classified into two types: retroviral and cellular. Retroviral proteases are involved in the maturation of viral particles, while cellular proteases are involved in the degradation of proteins. The best-known example of aspartic acid proteases is HIV-1 protease, which plays a vital role in the life cycle of the human immunodeficiency virus. Because of its importance, HIV-1 protease is a target for antiretroviral drugs.
In conclusion, the binding of aspartic acid to the c1 carbon during catalysis is an example of a covalent bond formation or a nucleophilic substitution mechanism. This reaction is part of the mechanism by which aspartic acid proteases cleave peptide bonds. Aspartic acid proteases are a type of enzyme that uses aspartic acid as its active site residue.
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which structure is stanley & sons using to control the structural hierarchy at a low level?
Stanley & Sons is most likely using a functional structure to control the structural hierarchy at a low level.
In a functional structure, employees are grouped based on their skills and expertise, allowing for efficient coordination and communication within departments. This structure is particularly effective for organizations with clear and defined roles and responsibilities, as it fosters specialization and encourages innovation.
By implementing a functional structure, Stanley & Sons can ensure that each department is managed effectively and that the company's goals are achieved efficiently. Additionally, a functional structure promotes accountability and teamwork, enabling employees to work together to achieve their goals and support the overall success of the organization.
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Scientific investigations must be well __________ to be sure the data collected will help answer the scientist's question
Answer:
The answer is relevant.
Scientific investigations must be well relevant to be sure the data collected will help answer the scientist's question.
What is a scientific investigation?A scientific investigation is an investigation that is done in the field of science. This unravels the secrets of the earth and the logical reason behind the things happening.
There are three types of scientific investigations. They are descriptive investigation, comparative investigation, and experimental investigation. When we see a thing happening in the environment or anywhere, always find a reason behind it.
The steps in completing a scientific investigation are:
Asking questionsTo make a hypothesis.Performing research.Making an observation.Analyzing the result.Thus, the scientific investigations must be well relevant to the data.
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What does an energy flow diagram tell
people?
that energy is easily created
that energy is not created, it simply changes
from one form to another
that the exact amount of energy present at any
given time
that energy is difficult to use
que
Combustion analysis of fluorene, a polycyclic aromatic hydrocarbon used to make dyes, plastics, and pesticides, produces 11.44 g CO2 and 1.80 g H2O. Calculate the empirical formula for fluorene.
Combustion analysis of fluorene, a polycyclic aromatic hydrocarbon used to make dyes, plastics, and pesticides, produces 11.44 g CO2 and 1.80 g H2O. The empirical formula of fluorene C₆H₄.
CₓHₐ + O2 → CO2 + H2O Since the combustion is complete, so the total mass of the reactants is equal to the total mass of the reactants Therefore, Mass of O2 = (17.9 + 9.14) – 5.9 = 21.14 grams Here, the empirical formula for the hydrocarbon is CₓHₐ. So, now we have to need to determine the number of moles of the O2, CO2, and H2O :- Mole of CO2 = 17.9/44 = 0.4068 Mole of H2O = 9.14/18 = 0.5078 Mole of O2 = 21.14/32 = 0.6606. The empirical formula for the compound containing uranium and fluorine is UF6. Explanation: The empirical formula of a compound represents the lowest whole number ratio of elements in the compound. This ratio is represented by subscripts in the formula. by this information, we can consider that combustion analysis of fluorene, a polycyclic aromatic hydrocarbon used to make dyes, plastics, and pesticides, produces 11.44 g CO2 and 1.80 g H2O. The empirical formula of fluorene C₆H₄.
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What can the reader conclude about the effects of hurricanes?
They only cause damage near the equator.
They cause most of their damage when they reach land.
The damage is only bad if you are inside the eye of the storm.
People are safe from hurricanes if they stay inside of their homes.
Lead, gold mercury, aluminum which one has the lowest heat capacity?
How do ionic bonds form?
Quick
Answer:
Explanation: ionic bond, also called electrovalent bond, type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound. Such a bond forms when the valence (outermost) electrons of one atom are transferred permanently to another atom.
superscript Coefficient
Me think
List a correct order the organs through which foods pacs from the mouth to the anus. b.state the ration of a balance ration for feeding poultry.
c.predict the product from when.
(I) magnesium solution react with dilute hydrochloric acid.
(ii) potassium meet with water
Mg + HCl → MgCl2 + H2. Salt and hydrogen gas are created when metal and acid combine. Magnesium produces hydrogen gas.
Thus, Salt and hydrogen gas are created when metal and acid combine. Magnesium produces hydrogen gas and magnesium chloride salt when it combines with diluted hydrochloric acid.
The gas produced by the reaction of magnesium with diluted HCl is hydrogen gas. The gas produced by the reaction of magnesium with diluted HCl is hydrogen gas.
The experiment produces very flammable hydrogen gas. No ignition source should be available to students.
Thus, Mg + HCl → MgCl2 + H2. Salt and hydrogen gas are created when metal and acid combine. Magnesium produces hydrogen gas.
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What is the answer to this ?
Answer:
12.78 or 12.80 mostly like 12.78
Explanation:
A highly reactive gas is used for refining petroleum
Answer:
Hydrogen
Explanation:
A rocket can be powered by the reaction between dinitrogen tetroxide and hydrazine:
20a
An engineer designed the rocket to hold 1. 35 kg N2O4 and excess N2H4. How much N2 would be produced according to the engineer's design? Enter your answer in scientific notation.
Expressing this answer in scientific notation, the amount of N2 produced according to the engineer's design would be approximately 1.467 x 10^1 mol.
To determine the amount of N2 produced in the reaction between dinitrogen tetroxide (N2O4) and excess hydrazine (N2H4), we need to consider the stoichiometry of the reaction.
The balanced equation for the reaction is:
N2H4 + N2O4 → N2 + 2H2O
According to the stoichiometry of the reaction, for every one mole of N2H4, one mole of N2 is produced. The molar mass of N2H4 is approximately 32.05 g/mol.
Given that the rocket is designed to hold 1.35 kg (1350 g) of N2O4, we can calculate the moles of N2H4 required:
Moles of N2H4 = Mass of N2O4 / Molar mass of N2O4
Moles of N2H4 = 1350 g / 92.01 g/mol ≈ 14.67 mol
Since the stoichiometry is 1:1, the amount of N2 produced will be equal to the moles of N2H4:
Moles of N2 produced = Moles of N2H4 ≈ 14.67 mol
Expressing this answer in scientific notation, the amount of N2 produced according to the engineer's design would be approximately 1.467 x 10^1 mol.
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Which are subatomic particles
Solve for the Gradient AB. The units will be in m/km but you should not
leave units in the answer because the answer key will not take them. Write
the answer to the tenths place and no units.
.X
B
Lake
-100
Blue River
50
А
D
5 kilometers
Contour interval 10 meters
N
0
2
3
5 kilometers
Answer:
help me mark me as a brinliest
Determine the number of oxygen atoms in 1.00 g of CaCO3
Answer:
1.81 x 10²² atoms O
Explanation:
To find the number of oxygen atoms, you need to (1) convert grams CaCO₃ to moles CaCO₃ (via molar mass), then (2) convert moles CaCO₃ to moles O (via mole-to-mole ratio from formula subscripts), and then (3) convert moles O to atoms O (via Avogadro's Number). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the amount of sig figs in the given value.
Molar Mass (CaCO₃): 40.078 g/mol + 12.011 g/mol + 3(15.998 g/mol)
Molar Mass (CaCO₃): 100.083 g/mol
1 CaCO₃ = 1 Ca and 1 C and 3 O
Avogadro's Number:
6.022 x 10²³ atoms = 1 mole
1.00 g CaCO₃ 1 mole 3 moles O 6.022 x 10²³ atoms
---------------------- x ------------------ x ---------------------- x ------------------------------ =
100.083 g 1 mole CaCO₃ 1 mole
= 1.81 x 10²² atoms O
What are chemical sedimentary rocks formed from?
Answer:
Elements in fluids.
Explanation: They're formed from elements crystalizing in fluids (Like water.) For example limestone forms on the bottom of the ocean from calcium.
Answer:
The precipitation of ions in solution
Explanation:
How many liters are in 4.5 moles of CO2 gas at STP? Pls help :)
Answer:
Explanation:
NCO 2= 4,5
VCO2= 4,5* 22,4=100,8
A- how many moles of potassium hydroxide would have to be added to 250 ml of a 0. 488 m nitrous acid solution, in order to prepare a buffer with a ph of 3. 190?
B- An aqueous solution contains 0. 333 M acetic acid.
How many mL of 0. 237 M sodium hydroxide would have to be added to 125 mL of this solution in order to prepare a buffer with a pH of 4. 940? ( ) mL
C- An aqueous solution contains 0. 382 M methylamine (CH3NH2).
How many mL of 0. 356 M perchloric acid would have to be added to 125 mL of this solution in order to prepare a buffer with a pH of 10. 900? ( ) mL
A) To calculate the moles of potassium hydroxide (KOH) required to prepare a buffer with a pH of 3.190, we need to use the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA])
In this case, the acid is nitrous acid (HA), and the conjugate base is the nitrite ion (A-).
Given:
Volume of nitrous acid solution = 250 mL
Concentration of nitrous acid = 0.488 M
pH of the buffer = 3.190
First, we need to find the pKa value for nitrous acid. The pKa value can be found in reference sources or provided in the question.
Once we have the pKa value, we can rearrange the Henderson-Hasselbalch equation to solve for [A-]/[HA]:
[A-]/[HA] = 10^(pH - pKa)
Using the concentration of nitrous acid (HA) and the calculated ratio [A-]/[HA], we can determine the moles of nitrous acid:
Moles of nitrous acid = Concentration of nitrous acid × Volume of nitrous acid solution (in liters)
Finally, since the stoichiometric ratio between KOH and nitrous acid is 1:1, the moles of KOH required will be equal to the moles of nitrous acid.
B) To calculate the mL of sodium hydroxide (NaOH) required to prepare a buffer with a pH of 4.940, we follow a similar approach:
Given:
Volume of acetic acid solution = 125 mL
Concentration of acetic acid = 0.333 M
pH of the buffer = 4.940
Concentration of sodium hydroxide (NaOH) = 0.237 M
Using the Henderson-Hasselbalch equation, we can calculate the [A-]/[HA] ratio for the acetic acid buffer system.
Then, using the volume and concentration of acetic acid (HA), we determine the moles of acetic acid.
Finally, we can use the stoichiometric ratio between NaOH and acetic acid to calculate the mL of NaOH required.
C) To calculate the mL of perchloric acid (HClO4) required to prepare a buffer with a pH of 10.900:
Given:
Volume of methylamine solution = 125 mL
Concentration of methylamine = 0.382 M
pH of the buffer = 10.900
Concentration of perchloric acid (HClO4) = 0.356 M
Using the Henderson-Hasselbalch equation, we determine the [A-]/[HA] ratio for the methylamine buffer system.
Using the volume and concentration of methylamine (HA), we calculate the moles of methylamine.
Finally, using the stoichiometric ratio between HClO4 and methylamine, we calculate the mL of HClO4 required.
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blood test indicates the presence of a particular disease 93% of the time when the disease is actually present. The same test indicates the presence of the disease 0.4% of the time when the disease is not present. Three percent of the population actually has the disease. Calculate the probability that a person has the disease given that the test indicates the presence of the disease. Give your answer in decimal form, rounding to four decimal places.
The probability that a person has the disease given that the test indicates the presence of the disease is approximately 0.9968
To calculate the probability that a person has the disease given that the test indicates the presence of the disease, we can use Bayes' theorem.
Let's denote:
A = Event of having the disease
B = Event of the test indicating the presence of the disease
We are given the following probabilities:
P(A) = 0.03 (3% of the population actually has the disease)
P(B|A) = 0.93 (the test indicates the presence of the disease 93% of the time when the disease is actually present)
P(B|not A) = 0.004 (the test indicates the presence of the disease 0.4% of the time when the disease is not present)
We need to find P(A|B), the probability that a person has the disease given that the test indicates the presence of the disease.
Applying Bayes' theorem:
\(P(A|B) = (P(B|A) * P(A)) / P(B)\)
To calculate P(B), we can use the law of total probability:
\(P(B) = P(B|A) * P(A) + P(B|not A) * P(not A)\)
\(P(not A) = 1 - P(A) = 1 - 0.03 = 0.97\)
Substituting the values into the equation:
\(P(B) = (0.93 * 0.03) + (0.004 * 0.97) ≈ 0.0279\)
Now, calculating P(A|B):
\(P(A|B) = (0.93 * 0.03) / 0.0279 ≈ 0.9968\)
Therefore, the probability that a person has the disease given that the test indicates the presence of the disease is approximately 0.9968 (rounded to four decimal places).
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Which of the following is a decomposition reaction?
Answer: D
Explanation:
D - Decomposition of carbonates into oxide and carbon dioxide
A - Combustion reaction. Combustion of methane to form Carbon dioxide and water.
C - Reaction of reactive metal (Na) and water to form hydroxide.
B - No particular name of the reaction. Usually denoted as a synthesis redox reaction.
Answer:CaCO3  CaO + CO2
Explanation: just took it
What atomic or hybrid orbitals make up the bond between c and o in formaldehyde, ch2o?
The atomic hybrid orbitals which make up the bond between C and O in formaldehyde, \(CH_{2} O\) will be one s-orbital and two p orbital make sp2 hybridization.
The 3 new hybrid orbitals can only be created through \(sp^{2}\) hybridization, which occurs whenever an atom's two pi orbitals including one s orbital overlap with mix together. Consequently, \(CH_{2} O\) (Formaldehyde) has \(sp^{2}\)hybridization.
It is found that when atoms share one electron then it will form sigma bond whereas when atoms share more than one electrons then it will form pi bond.
Therefore, the hybridization of \(CH_{2} O\) will be \(sp^{2}\) hybridization.
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Which equipment is used to stop fires in a laboratory? extinguisher bunsen burner first aid kit eye wash.
Fire extinguisher is used to stop fires in a laboratory.
Chemical splashes on to your face then we should go to eye wash station for washing face.
Bunsen burner is knocked over while lit and a large fire is started then we should use fire extinguisher and should come out of lab.
Carbon dioxide in fire extinguisher is more denser than oxygen so when we spray carbon dioxide on fire, it cut off the contact with oxygen and fire goes off.
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REVIEW ACTIVITY FOR ACID AND BASE TITARATION In successive titration of a standard solution of 0.20 molL sodium carbonate(Na,Co), 15.0mL of hydrochloric acid was neutralized by the following volumes of sodium carbonate, 22.25ml, 20.18ml, 20.24ml,21.05ml, and 20.15ml. The indicator used was methyl orange. 1. write the balance equation for the equation
This equation represents the chemical reaction that takes place when hydrochloric acid is added to sodium carbonate, resulting in the formation of sodium chloride, water, and carbon dioxide. The reaction is a double displacement reaction, where the hydrogen ions from the acid combine with the carbonate ions from the base to form water and carbon dioxide, while the sodium ions from the base combine with the chloride ions from the acid to form sodium chloride.
To calculate the average volume of sodium carbonate used to neutralize the hydrochloric acid, we need to add up the volumes of sodium carbonate used in each titration and divide by the total number of titrations .Therefore, the average volume of sodium carbonate used to neutralize the hydrochloric acid is 20.77mL.To calculate the amount of hydrochloric acid that will be neutralized by 25.0 mL of the sodium carbonate solution, we need to use the balanced equation and the concentration of both solutions. we can calculate the amount of hydrochloric acid in grams using the molar mass of HCl:
HCl = mol HCl × molar mass HCl
mass HCl = 0.01 mol × 36.46 g/mol = 0.3646 g
Therefore, 25.0 mL of the sodium carbonate solution will neutralize 0.3646 g of hydrochloric acid.
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What percent ionization would be expected for a 0.400 M HN3(aq) solution at 25 °C? Ka= 1.9x10-5 14. A diprotic acid, H2A, has values of Kai = 1.0x10-5 and Kaz = 1.0*10-10 at 25 °C. In a 0.10 M aqueous solution of HA, what is the concentration of the anion A2-?
The percent ionization of a 0.400 M HN3 solution at 25 °C is 0.56%.
The concentration of the anion A2- in a 0.10 M aqueous solution of HA is 9.9x10^-9 M.
Acid Dissociation Calculations.For the first question:
HN3 is a weak acid with a dissociation reaction as follows:
HN3(aq) + H2O(l) ⇌ H3O+(aq) + N3-(aq)
The equilibrium constant for this reaction is the acid dissociation constant (Ka) which is given as 1.9x10^-5. We can assume that x is the percent ionization of HN3, which is also equal to the concentration of H3O+ and N3-. Therefore, the equation to solve for x is:
Ka = [H3O+][N3-]/[HN3]
1.9x10^-5 = x^2/ (0.4 - x)
Solving this equation for x gives x = 0.0056 or 0.56% ionization.
Therefore, the percent ionization of a 0.400 M HN3 solution at 25 °C is 0.56%.
For the second question:
HA is a diprotic acid with two acid dissociation constants (Ka1 and Ka2). In this case, we are given Ka1 = 1.0x10^-5 and Ka2 = 1.0x10^-10. The dissociation reactions are as follows:
HA(aq) + H2O(l) ⇌ H3O+(aq) + A-(aq) Ka1
A-(aq) + H2O(l) ⇌ OH-(aq) + HA(aq) Ka2
We can assume that x is the concentration of H3O+ and A- ions, and that the initial concentration of HA is 0.10 M. Therefore, the equation to solve for x is:
Ka1 = [H3O+][A-]/[HA] and Ka2 = [OH-][HA]/[A-]
Since Ka2 is much smaller than Ka1, we can assume that the concentration of A- after the first dissociation is negligible compared to the initial concentration of HA. Therefore, the concentration of A- is equal to the concentration of HA that dissociated in the second dissociation reaction. Let's call this concentration x2.
From the first dissociation reaction, we have:
1.0x10^-5 = x^2/0.10
Solving for x gives x = 1.0x10^-3 or 0.001 M.
From the second dissociation reaction, we have:
1.0x10^-10 = (x2)(0.10 - x)/(x)
Solving for x2 gives x2 = 9.9x10^-9 M.
Therefore, the concentration of the anion A2- in a 0.10 M aqueous solution of HA is 9.9x10^-9 M.
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Give lewis dot structures and sketch the shapes of the following: a. secl4 b. i3 - c. pscl3 (p is central) d. if4 - e. ph2 - f. tef4 2- g. n3 - h. seocl4 (se is central) i. ph4
We structure the Lewis points and outline the forms of the following elements:
For a. SeCl4, the Lewis dot structure is:
Se | Cl
= Cl | Cl
It has a tetrahedral shape with Se as the central atom.
For b. I3-, the Lewis dot structure is:
I |
- I | I
It has a trigonal planar shape with I as the central atom.
For c. PSCl3, the Lewis dot structure is :
P | Cl
- - Cl | Cl Cl
It has a trigonal pyramidal shape with P as the central atom.
For d. IF4-, the Lewis dot structure is :
I | F
- - F | F F
It has a square planar shape with I as the central atom.
For e. PH2-, the Lewis dot structure is :
P | H
- H | H
It has a bent shape with P as the central atom.
For f. TeF42-, the Lewis dot structure is :
Te | F
- - F | F F
It has an octahedral shape with Te as the central atom.
For g. N3-, the Lewis dot structure is:
N |
- N | N
It has a linear shape with N as the central atom.
For h. SeOCl4, the Lewis dot structure is:
Se | O | Cl
- - - Cl | Cl Cl
It has a tetrahedral shape with Se as the central atom.
For i. PH4+, the Lewis dot structure is:
P | H
- H | H H | H
It has a tetrahedral shape with P as the central atom.
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carbon tetrachloride displays a triple point at 249.0 k and a melting point (at 1 atm) of 250.3 k. which state of carbon tetrachloride is more dense, the solid or the liquid? explain.
Chlorine is really the main liquid used in extinguishers, which is why it works so well to put out tiny flames. It doesn't ignite at any temperature and is not flammable.
The usage of carbon tetrachloride extinguishers has been discontinued.Dichromate extinguishers were abandoned in the 1950s because to the chemical's toxicity, which causes the nerves and major organs to be destroyed when exposed to large doses. A fire's heat can also transform CTC into hydrogen cyanide gas, a chemical agent that was occasionally used.
What is the proper way to get rid of carbon tetrachloride?Get in connect with a licensed, professional rubbish disposal company to have this material removed. After combining it in or combining it with an explosive solution, burn the chemical in a thermal crematorium with an intake and scrubber;
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HELPPP ASAPPPPP I WILL GIVE BRAINLIEST
Ocean currents contribute to global climates and occur due to differences in temperature, salinity, and density. WHY do you THINK these differences can cause currents to form?
Answer:
Its changes over time.
Explanation:
I think because each ocean current has a different temperature.
Answer:
Thermohaline circulation. This is a process driven by density differences in water due to temperature (thermo) and salinity variations in different parts of the ocean. Currents driven by thermohaline circulation occur at both deep and shallow ocean levels and move much slower than tidal or surface currents.
what is 26 atomic number?
Answer: Fe (iron)
Explanation:
the whole number next to the symbols on the periodic table that ascend in order by 1 are the atomic numbers, just look for the symbol next to the number 26.
what happens to the electric conductance of an electrochemical conductor and metallic conductor with increase in temperature
Calculate the number of moles in 583g of H2SO4 in 1.50 kg of water (the acid solution used in an automobile battery)?
The number of moles in 583g of H2SO4 in 1.50 kg of water is 9.33 moles.
To calculate the number of moles, we need to use the formula:
moles = mass (in grams) / molar mass (in grams/mol)
Step 1: Calculate the molar mass of H2SO4
H2SO4 is composed of 2 hydrogen atoms (H), 1 sulfur atom (S), and 4 oxygen atoms (O). We can find the molar mass by adding up the atomic masses of each element:
(2 * atomic mass of H) + atomic mass of S + (4 * atomic mass of O)
Step 2: Calculate the molar mass of H2SO4
(2 * 1.01 g/mol) + 32.07 g/mol + (4 * 16.00 g/mol) = 98.09 g/mol
Step 3: Calculate the number of moles
moles = mass / molar mass
moles = 583 g / 98.09 g/mol ≈ 5.95 moles
However, we need to consider that the H2SO4 is dissolved in 1.50 kg (1500 g) of water. Assuming H2SO4 is completely ionized, it dissociates into 2 H+ ions and 1 SO4^2- ion. Therefore, the number of moles of H2SO4 will be twice the number of moles calculated in Step 3.
moles = 5.95 moles * 2 = 11.9 moles
However, we have to keep in mind that we are calculating the moles of H2SO4 dissolved in water, which is the acid solution used in an automobile battery. Hence, the final answer is rounded to two decimal places: 9.33 moles.
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Which of the following liquids has the lowest viscosity?