The average speed of an object, S SS, is calculated using the formula S = D T S= T D ​ S, equals, start fraction, D, divided by, T, end fraction, where T TT is the time it takes to travel a distance of D DD units. Rearrange the formula to solve for time ( T ) (T)

The distance travelled by the motorbike is 600 m and the speed of the motorbike is 20 m/s.

The motion of the motorbike can be described as linear type of motion since the distance travelled by the motorbike increases with increase in the time of motion.

There is directly linear relationship between the distance travelled by the motorbike and the time of motion of the motorbike.

The distance travelled by the motorbike is calculated as follows;

from the given graph, at time 30 seconds, the corresponding the distance of the motorbike on the vertical axis is 600 m.

distance = 600 m

The speed of the motorbike is calculated as follows;

v = d/t

v = 600 m / 30 s

v = 20 m/s

Thus, the motion of the motorbike is a linear type of motion, the distance travelled by the motorbike increases with increase in the time of motion and the speed of the motorbike depends on the distance and time of motion.

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A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.

LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.

The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.

Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.

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A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. The coefficients of static and kinetic friction between the hockey puck and the metal ramp are μs = 0.40 and μk = 0.30, respectively. The puck's initial speed is 3.8 m/s, Speed it will have when it slides back down to its starting point is 2.36 m/s

The resistance to motion of one object moving in relation to another is known as friction. It is not regarded as a fundamental force like gravity or electromagnetic, according to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab). The electromagnetic attraction between charged particles in two contacting surfaces, according to scientists, is what causes it.

using work energy theorem ,

change in kinetic energy = work done by frictional force

\(\frac{1}{2}\) m(\(x^{2}\)-\(y^{2}\)) =  μmghcos30°

where mass is m=200g

x is speed with which it slides back

y is speed at top of metal ramp=3.8 m/s

μ is coefficient of kinetic friction=0.3

g is gravity = 9.8m/\(s^{2}\)

h is height to which hockey puck is reached on metal ramp=1.18m

Substituting the values and solving for speed x,

x=2.36m/s

speed  it will have when it slides back down to its starting point is 2.36m/s

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Just before the collision, the ball has a velocity of 9.3 m/s, downward. After the collision, the ball has a velocity of 6.2 m/s, upward.

To solve this problem, we can analyze the motion of the ball and block before and after the collision using the principles of conservation of energy and momentum. Since the collision is elastic, the total kinetic energy of the system is conserved. The ball has gravitational potential energy before the collision, which is converted to kinetic energy as it falls.

The block has no kinetic energy before the collision, but gains some after the collision due to the transfer of momentum from the ball. By equating the total kinetic energy before and after the collision and using the principle of conservation of momentum, we can solve for the velocities of the ball and block.

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When the object is submerged in methanol, it displaces an amount of methanol with weight 1.052 N, i.e. with mass = (1.052 N)/g ≈ 107.347 g. With a density of 0.8 g/cm³, this means the displaced methanol and hence the object itself have a volume of

v ≈ (107.347 g) / (0.8 g/cm³) ≈ 134.184 cm³

Likewise, when submerged in benzene, the object displaces 0.951 N of benzene, whose mass is (0.951 N)/g ≈ 97.041 g with the same volume as the object. So the density d of benzene is

d ≈ (97.041 g) / (134.184 cm³) ≈ 0.723 g/cm³

Answer:

If u dig a hole 3 feet how big is that hole

Explanation:

It’s about 20 feet

The velocity of the punk at time t = 1.5 s is equal to 2.47 m/s.

The object will have two velocities during the projectile motion, one is horizontal velocity and the other is vertical velocity. The horizontal velocity of the object is constant throughout the projectile motion but the vertical velocity is changed in the projectile motion.

Given that the velocity vector is making an angle θ with a horizontal table, θ = 35°

The vertical component of the velocity of the puck can be determined as:\(u_x = u Sin 35^o = 3.60 \times 0.573 =2.06 m/s\)

The horizontal component of the velocity of the puck can be determined as:

\(u_y = u cos 35^o = 3.60 \times 0.82=2.95 m/s\)

Given the acceleration aₓ = -0.360 m/s² and a y = -0.980 m/s²

The final vertical components of the velocity of the punk are:

\(v_x = u_x + a_xt\)

\(v_x = 2.95 - (0.360) (1.5)\\v_x = 2.41 m/s\)

and, the horizontal velocity of the punk is:

\(v_y = u_y +a_yt\\v_y = 2.06 - (0.980) (1.5)\\v_y = 0.59 m/s\)

The velocity of the punk can be determined as:

\(v = \sqrt{v_x^2 + v_y ^2}\\ v =\sqrt{(5.80)^2 + (0.35)^2}\\ v = 2.47 m/s\)

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The potential energy of the lemming when it lands is 0.9108672 J.

To determine the potential energy (PE) of the lemming when it lands, we need to consider the conservation of energy. The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.

Given:

Mass of the lemming (m) = 0.0780 kg

Height of the cliff (h) = 5.36 m

First, let's calculate the potential energy when the lemming is on the cliff. Using the given formula, we have:

PE = mgh

PE = 0.0780 kg * 9.8 m/s² * 5.36 m

PE = 0.413616 J

Next, we need to determine the final kinetic energy of the lemming just before it lands. We can use the equation for kinetic energy (KE) given by KE = (1/2)mv², where v is the velocity of the lemming.

Given:

Velocity of the lemming (v) = 4.84 m/s

Calculating the kinetic energy, we have:

KE = (1/2) * 0.0780 kg * (4.84 m/s)²

KE = 0.9108672 J

According to the conservation of energy, the potential energy at the top of the cliff is equal to the kinetic energy just before landing.

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Since the car masses are unknown, we are unable to calculate the numerical value of the x-component of Car A's tangential acceleration.

The energy that is held in any object or system as a function of its position or component arrangement is known as potential energy. The object or system is unaffected by external factors like air pressure or altitude. Kinetic energy, on the other hand, describes the power of moving particles within a system or an object.

They are being affected by the kinetic frictional force, which is caused by:

f = μk * N

Therefore,

fB = μk * N = μk * mB * g

Car C is at its highest point at the top of the hill, where the normal force acting on it is equal to the force of gravity. Therefore,

fC = μk * N = μk * mC * g

where mC is the mass of Car C.

For Car A, the x-component of the tangential acceleration is given by:

aA = (fB - fC) / mA

where mA is the mass of Car A.

We can substitute the following values and simplify by assuming that the mass of each of the three automobiles is the same:

aA = (μk * mB * g - μk * mC * g) / mA

aA = μk * g * (mB - mC) / mA

Since μk = 1.00 and g = 9.81 m/s², we can plug in the values and get:

aA = (mB - mC) * 9.81 / mA

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Answer:

10

Explanation:

lyezurzup?y?ur if fk kgs7rsjzkgzitz

Objective assessment is the type which is based on repeatable, measurable data.

This involves the use of unbiased and balanced observation based on verified facts.

This is verified by the use of  repeatable and measurable data so as to ensure the accuracy is high in this scenario.

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A capacitor stores electrical energy, whereas capacitance is the ratio of a stored charge on each plate to the electric potential difference between the plates. Therefore, second option is correct.

Whenever the charge stored in the capacitor increases it increase the capacitance of capacitor but when the potential difference increases it decrease the capacitance of a capacitor.

Answer:

4 C

Explanation:

The strength of an electric field can be defined as: \(E = \frac{f}{q}\) where f=force and q=charge, and e=strength

Since we're given the strength and the force we can simply rearrange the equation so that we solve for Q:

Original Equation:

\(E=\frac{f}{q}\)

Multiply both sides by q

\(E*q = f\)

Divide both sides by E

\(q=\frac{f}{e}\)

So now plug the known values into the equation

\(q=\frac{1000 N}{250 N/C}\)

Simplify:

\(q = 4 c\)

The function is not continuous at x=1, so the answer is A.

At x=1, the two pieces of the function meet. The first piece ends with an open dot at (1,0), meaning that the function is not defined at $x=1$. The second piece starts with a closed dot at (1,-1), meaning that the function is defined at x=1 and takes the value -1 there.

Since the function is not defined at x=1, it cannot be continuous at that point. Therefore, the function is not continuous overall.

Answer:

The Cascadia Subduction Zone has not produced an earthquake since 1700 and is building up pressure where the Juan de Fuca Plate is subsiding underneath the North American plate.

Explanation:

At depths shallower than 30 km (19 mi) or so, the Cascadia zone is locked by friction while stress slowly builds up as the subduction forces act, until the fault's frictional strength is exceeded and the rocks slip past each other along the fault in a megathrust earthquake. Below 30 km (19 mi) the plate interface exhibits episodic tremor and slip .

Answer:

B)48°C

Explanation:

just is how it is. you know

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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Answer:

198 meters

Explanation:

I'm not sure but hope it helps

Answer:

Δt ≈ 5.3 x 10⁻⁷ s  or  Δt ≈ 0.5 μs.

Explanation:

Sound waves propagate at a typical speed according to the physical media.

Using the wave equation of speed:

V = λ x f

V = 0.0760 x 25 x 10³

V = 1900 m/s

Then we must use this value to find the time recorded:

V = ΔS / Δt

1900 = 10⁻³ / Δt

Δt = 10⁻³ / 1900

Δt ≈ 5.2632 x 10⁻⁷ s

Δt ≈ 5.3 x 10⁻⁷ s  or  Δt ≈ 0.5 μs

The wavelength of the Ultrasonic wave in the coating is 0.0760 m, then the time recorded is 0.5 μs if the coating is of correct thickness, that is of 1 mm

Physics refers to frequency as the quantity of waves passing a fixed location in a unit of time. Additionally, it is the quantity of vibrations or cycles that a body in periodic motion experiences in a certain period of time. One cycle or vibration is defined as the movement of a body in periodic motion across a sequence of occasions or locations before returning to its initial state. Under angular velocity, a straightforward harmonic motion is also observed.

According to the question,

Use wave equation of speed :

V = λ (wavelength) x f (frequency)

V = 0.0760 x 25 x 10³

V = 1900 m/s

The time recorded will be :

V = ΔS / Δt

1900 = 10⁻³ / Δt

Δt = 10⁻³ / 1900

Δt = 5.2632 x 10⁻⁷ s

Δt = 5.3 x 10⁻⁷ s  or,

Δt = 0.5 μs

Hence, the time recorded will be 0.5 μs if the coating is of correct thickness that is 1 mm.

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Changing the green sum of forces arrow involves manipulating applied forces, frictional forces, and normal forces, allowing for adjustments in magnitude and direction through various means.

To change the green sum of forces arrow, you can employ the following three strategies:

Adjusting Applied Forces: By modifying the magnitude or direction of the applied forces, you can alter the green sum of forces arrow. If the applied forces are increased or directed in a different way, the green sum of forces arrow will change accordingly. For instance, increasing the magnitude of a pushing force will result in a larger green sum of forces arrow in that direction.

Modifying Frictional Forces: Frictional forces play a crucial role in determining the green sum of forces. By changing the coefficient of friction or applying lubricants, you can affect the magnitude of frictional forces acting on an object. Reducing friction will decrease the green sum of forces arrow, while increasing friction will have the opposite effect.

Varying Normal Forces: The green sum of forces arrow can be influenced by adjusting the normal forces acting on an object. Normal forces are perpendicular to the surface and counteract the weight of an object. By changing the angle or surface on which an object rests, you can modify the normal forces. This alteration will subsequently impact the green sum of forces arrow.

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Answer:

In the absence of government, what would determine the way people act towards each other is the need to acquire means of survival such as food or shelter.

Thus, since the government regulates the rights and obligations of citizens to guarantee equal access to essential services and goods for life, in the event of the disappearance of the state as a form of social organization, people would tend to act selfishly. to provide itself with those goods and services.

Society would then return to a state of nature, where man competes with his peers for access to resources. So the need for those resources would ultimately determine the way humans relate to each other.

Throughout the absence of regulation, the necessity to gain means of subsistence, which includes extra help, would decide how individuals interact with one another.

As a consequence, while the organization governs individuals' rights and duties purpose of providing equitable access to vital services and products for life, if the community as more than just a form of social organization disappears, individuals might likely behave selfishly to offer such commodities.

Thus the response above is right.

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Answer:

a.75cm

Explanation:

Answer:

Increase

Explanation:

The frequency of sound determines the sound. If the frequency is lower the pitch will be lower. If the frequency is higher the pitch will be higher. This is affected by the motion of the sound source because when a sound source is moving faster the frequency will become higher.

Answer: So the force of gravity due to the sun on the moon is 2.25 times stronger than the force of gravity due to earth on the moon.

i hope this helps if not lmk!

The maximum height be 3.01 m.

According to the law of conservation of energy: The total energy of the system is conserved in a closed system, also known as an isolated system.

Given parameters:

Mass of the box: m = 2.0 kg

Spring constant: k = 2000 N/m.

Compression of spring: x = 20 cm = 0.2m

Angle of inclination: θ = 37°

Coefficient of friction: μ = 0.1

If the box raises up to distance d then according to law of conservation of energy:

1/2kx² = mgdsin37° + μ mg d sin37°

1/2kx² = mgdsin37°(1 + μ)

d = 1/2kx²/(1+μ)mgsin37° = 1/2 × 2000 × 0.2²/{(1+0.1) × 2 × 10 × sin37°}

= 3.01 m.

Hence,  The maximum height be 3.01 m.

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When a person increases their activity level to gain muscle mass, their nutritional needs change.

The key changes include increasing protein intake to support muscle growth and repair, consuming a slight caloric surplus to provide energy for muscle development, ensuring sufficient carbohydrate intake for fuel, including healthy fats for overall health, staying hydrated, and considering essential micronutrients.

Individual variations exist, so seeking personalized guidance from a professional is recommended.

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