The average speed of a cart during a 15 s interval is 3.0 m/s . What is the total distance travels by the cart

Answers

Answer 1

Answer:

45m

Explanation:

speed= distance/ time

3.0= distance/ 15

*15 on both sides

45m= distance


Related Questions

What is one way homeostasis benefits living organisms?
it maintains balance.
It reduces air pollution.
It increases food consumption
It regulates atmospheric temperature

Answers

Answer:

it maintains balance, it keeps body temperatures , heart rate and all other bodily functions regulated to keep the organism stable when the environment is not.

Answer:

What the other guy said.

Explanation:

Yeah I'm doing this so he can have brainliest.

Bryan Allen pedaled a human-powered aircraft across the English Channel from the cliffs of Dover to Cap Gris-Nez on June 12, 1979. He flew for 169 min at an average velocity of 3.53 m/s in a direction 45° south of east. What was his total displacement?

Answers

taking the direction of Bryan as positive that is 45° south of East as positive Displacement =  35. 8 km ( approx. )

Relative velocity of an object is given as it's velocity with respect to other body ( Or reference ) . Here other body is known as reference frame wrt to which the velocity is measured .

taking the direction of Bryan as positive that is 45° south of East as positive.

we know that  , Displacement = Avg Velocity x time

     Avg Velocity = 3.53m/s   ,

     time = 169 min= 169*60sec = 10140 seconds

  So   Displacement = 10140 x 3.53 m

          Displacement =35794.2 m \(\Rightarrow\) 35.7942 km (  as 1000m = 1km  )

So  ,  Displacement =  35. 8 km ( approx. )

           Direction  =  45° south of East  

     Now, air is moving in opposite direction wrt to swimmer  so taking air velocity as negative  

 Relative velocity of swimmer with respect to air:-

              \(V_{sa }= V_s -V_a\)

where \(V_s\) = velocity of swimmer wrt to earth= 3.53m/s

            \(V_a\) = velocity of air wrt to earth = -2m/s

​​​​​  so     \(V_{sa}\)  = 3.53 -(-2) \(\Rightarrow\) 5.53m/s    wrt to air

          Direction = 45° South of East

Total displacement relative to air mass will be :

( Relative velocity wrt to air x time taken)

Relative velocity wrt to air mass = \(V_{sa}\) = 5.53m/s

  Total time taken  = 169min =169 x 60s => 10140 sec

  So

    Net  Displacement  = 5.53 * 10140 => 56074.2m

     Net  Displacement  =  = 56.0742 km

  Net displacement wrt to air = 56.1 km ( approx.)

          Direction = 45° South of East.

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A 3-kg bowling ball rolls at a speed of 5 m/s on the roof of the building that is 75 m tall.

Circle one: KE / GPE / both

Show your work for finding the values of each type of energy the object has:

Answers

The potential energy  and kinetic energy of the bowling ball are 2,205 J and 37.5 J respectively.

What is the gravitational potential energy of the bowling ball?

The bowling ball at the given position and speed possess gravitational potential energy and kinetic energy.

The potential energy  and kinetic energy of the bowling ball is calculated as follows;

P.E = mgh

where;

m is the mass of the objecth is the heightg is acceleration due to gravity

P.E =  (3 x 9.8 x 75 )

P.E = 2,205 J

The kinetic energy of the bowling ball is calculated as;

K.E = ¹/₂ mv²

where;

v is the speed of the bowling ball

K.E = ¹/₂ ( 3 ) x (5²)

K.E = 37.5 J

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when you blow across the top of a soda bottle it acts like a closed pipe. if it creates a fundamental frequency of 680 Hz, how deep is the bottle? (Speed of sound = 343 m/s) (Unit = m)

Answers

Answer:

0.125

Explanation:

acellus

solve
Q1-a)- Design circuit to simulate the following differential equation \[ \frac{d y(t)}{d t}+y(t)=4 x(t) \] Where \( y(t) \) is the output and \( x(t) \) is the input b) - For the circuit shown in Figu

Answers

Given differential equation is:

\[\frac{dy(t)}{dt}+y(t)=4x(t)\]

In order to design a circuit to simulate the given differential equation, we can use Operational Amplifiers and its properties. Operational Amplifier has a property that it has infinite input resistance, which means that it will not load the input signal and also it has very high gain, which means it will amplify the signal to a very large extent.

We can use these properties to create a circuit that simulates the given differential equation.The differential equation can be written as:

\[\frac{dy(t)}{dt}=-y(t)+4x(t)\]

Now, taking Laplace Transform of both sides, we get:

\[sY(s)+y(0)=-Y(s)+4X(s)\]

Solving for Y(s), we get:

\[Y(s)=

\frac{4X(s)+y(0)}{s+1}\]

From the above equation, we can see that the Laplace Transform of the output signal is related to the Laplace Transform of the input signal, X(s), by a transfer function that has a pole at s=-1 and a zero at s=0. This suggests that we can create a circuit that has this transfer function by using an Operational Amplifier.In order to create a circuit with the given transfer function.

Now, taking the Inverse Laplace Transform of the above equation, we get:

\[v_{out}(t)=

\frac{R_2}{R_1}e^{-t}

\int_{0}^{t} e^{u}v_{in}(u) du\]

Comparing this with the equation for y(t), we can see that the circuit shown above simulates the given differential equation.

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2. Identify and explain two factors that can influence your
skill-related fitness levels.

Answers

Genetics and experience (maybe) because sometimes genetics can give u an advantage in activness

True/False? only hard scientists have the necessary skill set to respond to moments of crisis

Answers

The statement that only hard scientists has the essential skill set to respond in times of crisis is True.

What does highly essential mean?

adjective. absolutely necessary; indispensable: Discipline is essential in an army. pertaining to or constituting the essence of a thing. noting or containing an essence of a plant, drug, etc. being such by its very nature or in the highest sense natural; spontaneous: essential happiness.

What does essential nature mean?

meanings of essential and nature all the animals, plants, rocks, etc. in the world and all the features, forces, and processes that happen or exist independently of people, such as the weather, the sea, mountains, the production of young animals or plants,  See more at nature.

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Drag each phrase below the type of freshwater wetland it describes.
shallow water or stream Marsh Swamp Bog
found in northern climates
many grasses
found in warmer climates
acidic water
looks like flooded fores

Answers

Marsh describes shallow water or stream, found in northern climates and with many grasses while Swamp looks like flooded forest, found in warmer climates and Bog represents acidic water.

A marsh is a wetland that is dominated by herbaceous rather than woody plant species which is often characterized by slow-moving waters and often has aquatic and semi-aquatic vegetation. A swamp is a wetland dominated by woody plants, usually trees and shrubs. The water in a swamp is generally stagnant or slow-moving and contains many nutrients. A bog is a type of wetland with a deep water table and spongy, acidic, nutrient-poor soil. It is dominated by sphagnum moss and other acid-loving plants such as heather and cotton grass.

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A capacitor has plates of area
3.61 x 10-4 m2 which are separated
by 4.72 x 10-6 m. What is its
capacitance?
[?] * 10?! F.

A capacitor has plates of area3.61 x 10-4 m2 which are separatedby 4.72 x 10-6 m. What is itscapacitance?[?]

Answers

Answer:

6.76875 • 10 ^-10 F

Explanation:

You just follow the formula:

C = εA/d

ε = 8.85 • 10^-12

A = 3.61 • 10^-4

D = 4.72 • 10 ^-6

So:

C = (8.85 • 10^-12)(3.61 • 10^-4)/4.72 • 10 ^-6 = 6.76875 • 10 ^-10 F

Good Luck!  :)

A fiber-optic rod consists of a central strand of material surrounded by an outer coating. The interior portion of the rod has an index of refraction of 1.97. If all rays striking the interior walls of the rod with incident angles greater than 50.4° are subject to total internal reflection, what is the index of refraction of the coating?

Answers

Answer:

The refractive index of the outer coating is 1.52.

Explanation:

Refractive index of interior part, n' = 1.97

critical angle, C = 50.4°

Let the refractive index of the coating is n.

Use the Snell's law,  

\(n\times sin r = n'\times sinC\\\\n\times sin 90 = 1.97 \times sin 50.4\\\\n = 1.52\)

Please Help!


30. A duck flying due east passes over Atlanta, where the magnetic field of Earth is 5.0 x 10-5 T directed north. The duck has a positive charge of 4.0 x 10-8 C. If the magnetic force acting on the duck is 3.0 x 10-11 N upward, what is the duck's velocity?​

Answers

Answer:

5 m/s

Explanation:

hope it helps:) u're welcome

The velocity of the duck must be 15 m/s towards the east which is explained below.

Magnetic force:

The force on a moving charge with some velocity under a magnetic field is given by:

F = qv×B

here q is the charge on the object

v is the velocity of the object

B is the magnetic field

v×B gives the direction of the force

B is towards the north, and Force is directed upwards, then velocity v should be towards the east.

3×10⁻¹¹ = 4×10⁻⁸× v × 5×10⁻⁵

v = 15 m/s

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A cross country skier moves from location A to location B to location C to location D. Each leg of the back and forth motion takes 1 minute to complete; the total time is 3 minutes.


What is the distance travelled by the skier in the first minute?

What is the displacement of the skier in the first minute?

What is the distance travelled by the skier in the first two minutes?

Please help it’ll be greatly appreciated!!

A cross country skier moves from location A to location B to location C to location D. Each leg of the

Answers

Answer:

1. 160

2. 0

3. 120

Explanation:

Mars has mass 6.40 x 10^23 kg and mean radius 3.40 x 10^3 km. How much energy must a 1500 kg rocket have in order to escape from Mars' gravitational pull, assuming it launches from Mars' surface?

Answers

To calculate the energy required for a rocket to escape Mars' gravitational pull, we need to use the formula: E = (GMm)/r Where E is the energy required, G is the gravitational constant (6.67 x 10^-11 Nm^2/kg^2), M is the mass of Mars (6.40 x 10^23 kg), m is the mass of the rocket (1500 kg),

and r is the radius of Mars (3.40 x 10^3 km + the height the rocket needs to reach to escape Mars' gravitational pull, which we'll assume is negligible).

Plugging in the values, we get:

E = (6.67 x 10^-11 Nm^2/kg^2)(6.40 x 10^23 kg)(1500 kg)/(3400000 m)

Simplifying, we get:

E = 2.41 x 10^10 J

Therefore, the rocket needs to have at least 2.41 x 10^10 Joules of energy to escape from Mars' gravitational pull.

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In each hand you hold a 0.16-kg peach. What is the gravitational force exerted by one peach on the other when their separation is (a) 0.25 m and (b) 0.50 m?

Answers

The gravitational force exerted by one peach on the other can be calculated using the formula F = G(m1m2)/r²,

where F is the force, G is the gravitational constant (6.67 x 10^-11 Nm²/kg²), m1 and m2 are the masses of the two peaches, and r is the distance between their centers of mass.

(a) When the separation between the peaches is 0.25 m, the force exerted by one peach on the other is:

F = (6.67 x 10⁻¹¹ N×m²/kg²) × (0.16 kg × 0.16 kg) / (0.25 m)² = 1.07 x 10⁻⁹N

(b) When the separation between the peaches is 0.50 m, the force exerted by one peach on the other is:

F = (6.67 x 10^-11 N×m²/kg²) ×(0.16 kg × 0.16 kg) / (0.50 m)²= 2.67 x 10⁻¹⁰ N

Therefore, the gravitational force exerted by one peach on the other decreases as the distance between them increases. This is because the force of gravity is an inverse square law, meaning that the force decreases proportionally to the square of the distance between the objects.

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Find the wavelength of a transverse wave the frequency of the wave motion is 3 Hz and the wave travels with a velocity of 48 m/s .

Answers

Answer:

16 m

Explanation:

Hypertension The INTERSALT Study investigators collected standardized data on timed 24-hour urinary excretion for 10,079 men and women from 52 population samples in 32 countries (Brown et al.) [14] One of the goals of the INTERSALTStudy was to quantify the relationship between 24-hour urinary Na ly) and estimated 24-hour urinary Na (x) obtained from casual urine specimens at one point in time. The investigators presented a simple linear regression of y on x, separately for men and women. The regression equation for men was: Y 1.03 x 7.19, with R2 0.27, n 1369 11.25 What does the R2 of 0.27 mean in words?

Answers

In words, the R2 of 0.27 means that 27% of the variability in y (24-hour urinary Na) can be explained by x (estimated 24-hour urinary Na) obtained from casual urine specimens at one point in time.

The INTERSALT Study was designed to investigate the relationship between dietary sodium and blood pressure (hypertension) in populations worldwide.

The study included 10,079 men and women from 52 population samples in 32 countries. One of the goals of the study was to quantify the relationship between 24-hour urinary Na (y) and estimated 24-hour urinary Na (x) obtained from casual urine specimens at one point in time.

The investigators presented a simple linear regression of y on x, separately for men and women. The regression equation for men was: Y = 1.03x + 7.19, with R2 = 0.27, n = 1369.

The coefficient of determination, R2, is a statistical measure that represents the proportion of the variance for a dependent variable (y) that's explained by an independent variable (x) or variables in a regression model.

In this case, the R2 of 0.27 means that 27% of the variability in y (24-hour urinary Na) can be explained by x (estimated 24-hour urinary Na) obtained from casual urine specimens at one point in time. The remaining 73% of the variability in y is due to other factors that are not included in the regression model.

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If we have a new moon today, when we will have the next full moon?

in about 6 months
in about a month
in about 2 weeks
in about 1 week

Answers

If we have a new moon today, we will have the next full moon in about 2 weeks.

What is the time difference between  a new moon and  the next full moon?

The midpoint of the cycle (half of 30 = 15) is marked by the full Moon, which occurs approximately 15 days (14.8 to be exact) following the new moon. Similar to the New Moon phase, the Moon is once again in alignment with the Earth and Sun during full moon.

However, this time, the Moon is on the other side of the Earth, thus the full area of the Moon that is illuminated by the Sun is facing us. Immediately following this brief interval, visibility starts to decline.

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an object is dropped from a cliff. after 3 seconds, its acceleration is _____ m/s 2

Answers

According to the question, The acceleration of an object in free fall near the surface of the Earth is approximately 9.8 m/s².

When an object is dropped from a cliff, it experiences gravitational acceleration directed towards the Earth. This acceleration is constant and equal to the acceleration due to gravity, which is approximately 9.8 m/s² near the surface of the Earth. Therefore, after 3 seconds, the acceleration of the object will still be approximately 9.8 m/s². The acceleration remains constant unless other forces, such as air resistance, come into play. This is because the acceleration due to gravity remains constant unless other forces, such as air resistance, significantly affect the motion.

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A 1. 8-m-long, 1. 0-mm-diameter steel string is pulled by a 3. 3 × 103 n tension force. By how much is the string stretched, in mm? the young's modulus for steel is 20 × 1010 n/m2

Answers

The steel string is stretched by 0.06 mm.

We can use Hooke's Law to find the amount of stretch in the steel string:

F = kΔL

where F is the tension force, k is the spring constant (related to the Young's modulus), and ΔL is the amount of stretch.

Rearranging the equation, we get:

ΔL = F / k

The spring constant k can be expressed as:

k = A * E / L

where A is the cross-sectional area of the string, E is Young's modulus, and L is the original length of the string.

Substituting the given values, we get:

A = \(πr^2 = π(0.5 mm)^2 = 0.785 mm^2\)

k = (π/4) * (1.0 mm)^2 * (20 × \(10^10 N/m^2\)) / (1.8 m) = 5.50 × \(10^4 N/m\)

Now we can find the amount of stretch:

ΔL = (3.3 × \(10^3 N)\)/ (5.50 × \(10^4 N/m\)) = 0.06 mm

Therefore, the steel string is stretched by 0.06 mm.

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Help please!!!! What is the difference between the type of smog experiences by cities in the eastern United States and that found in Southern California?

Answers

Both are dangerous on their own, but as they float through the air in Southern California's sunny climate, the sun bakes them into a new molecule called ozone, better known as smog.

What is Smog?

Smog development and infiltration over Los Angeles. haze and air pollution in the entire community.

Burning sulfur-containing fossil fuels, particularly coal, causes sulfurous smog, also referred to as "London smog," which is characterized by a high concentration of sulfur oxides in the atmosphere.

The two primary substances in automotive exhaust are nitrogen oxides, which are created in scorching internal combustion engines, and hydrocarbons, which are derived from gasoline.

Therefore, Both are dangerous on their own, but as they float through the air in Southern California's sunny climate, the sun bakes them into a new molecule called ozone, better known as smog.

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Han Solo is moving from left to right along the curvey y= x^2 while orbiting the planet of
Tatooine. He wants to shut off the engines of the Millenium Falcon at a certain point, so
that he will go off along the tangent line and land. At what point should he shut off the
engines in order to reach the landing point (4, 15)? Show all of your work.

Answers

At position (3, 9), where the tangent line passes through, Han Solo should turn off the engines (4, 15).

What should you do if an engine fails while you're in flight?

The first three things need to be completed, or at least started, right away: Fly the aircraft as you instantly apply full carb heat and check the gasoline in both or one of the tanks, hit the fuel boost or pump, and mix the fuel to full richness.

Finding the tangent line to the curve y = x2 at that location will help us determine when Han Solo should turn off the engines.

The derivative of the function determines the slope of the tangent line at any point on the curve y = x2.: dy/dx = 2x

Han Solo should turn off the engines at position (x1, y1). Next, we have

y1 = x1^2 (since the point is on the curve y = x^2)

dy/dx = 2x1 (since this is the slope of the tangent line at (x1, y1))

The equation of the tangent line via (4, 15) can be expressed using the point-slope form of a line as follows:

y - y1 = m(x - x1)

Substituting y1 = x1^2 and m = 2x1, we get:

y - x1^2 = 2x1(x - x1)

Now, we can substitute the coordinates of the point (4, 15) to solve for x1:

15 - x1^2 = 2x1(4 - x1)

15 - x1^2 = 8x1 - 2x1^2

x1^2 - 8x1 + 15 = 0

This quadratic equation can be factored as:

(x1 - 3)(x1 - 5) = 0

Therefore, the possible values of x1 are 3 and 5.

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A high-speed transmission medium that uses a protected string of glass to transmit beams of light.a. Trueb. False

Answers

A high-speed transmission medium that uses a protected string of glass to transmit beams of light.

Correct answer is, True.

This refers to fiber optic cables, which use glass or plastic fibers to transmit light signals at high speeds and are protected by a sheath or jacket., faster speeds, and resistance to electromagnetic interference.

This statement accurately describes fiber-optic cables, which are high-speed transmission mediums that use glass or plastic fibers to transmit light signals. Fiber-optic cables have several advantages over traditional copper cables, including higher bandwidth.

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PLEASE HELP ITS DUE IN 5 MINUTES
Try the aquatics exercises you learned in lesson 02.07 Aquatics. What was the most difficult part of completing the leg action of treading water or bicycling in the air? Why?

Answers

Answer:

For bicycling it was getting over the fear of me hurting myself pretty bad, this is because the fear is all in your head (I don't know psychology but that's true).      

And for treading water it was that the leg movements took time to get used to, because they were strange and confusing to me.

Jupiter's four large moons - Io, Europa, Ganymede, and Callisto - were discovered by Galileo in 1610. Jupiter also has dozens of smaller moons. Callisto has a radius of about 2.40 x 106 m, and the mean orbital radius between Callisto and Jupiter is 1.88 x 109 m.
(a) If Callisto's orbit were circular, how many days would it take Callisto to complete one full revolution around Jupiter?
(b) If Callisto's orbit were circular, what would its orbital speed be?

Answers

If Callisto's orbit were circular, then how many days would it take Callisto to complete one full revolution around Jupiter is 16.7 days. If Callisto's orbit were circular, what would its orbital speed be is 8.20 × 10³ m/s.

What is the time and orbital speed of Callisto?

Radius of Callisto, rc = 2.40 × 10⁶ m

Mean orbital radius, r = 1.88 × 10⁹ m

The time required for Callisto to complete one full revolution around Jupiter is given by: T = 2πr/v

where, T is the period of revolution, v is the speed of Callisto, and r is the mean orbital radius.

If Callisto's orbit were circular, then its speed would be constant, and the time required to complete one full revolution would be the same as its period of revolution.

T = 2πr/v = (2π)(1.88 × 10⁹ m)/(8.20 × 10³ m/s) ≈ 1.67 × 10⁶ s ≈ 16.7 days

The speed of Callisto in a circular orbit is given by:

v = 2πr/T = (2π)(1.88 × 10⁹ m)/(1.67 × 10⁶ s) ≈ 8.20 × 10³ m/s

Hence, Callisto's orbit were circular, then how many days would it take Callisto to complete one full revolution around Jupiter is 16.7 days. If Callisto's orbit were circular, what would its orbital speed be is 8.20 × 10³ m/s.

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Un avión da "una vuelta mortal" de radio R = 500 m con una celeridad constante v = 360 km/h. Halla la fuerza ejercida por el asiento sobre el piloto, si su masa es m = 70 kg, en las partes inferior y superior de la trayectoria circular.

Answers

Answer:

1400 N

Explanation:

Verá, durante el salto mortal, el piloto se mueve en una trayectoria circular y la fuerza que actúa sobre él es una fuerza centrípeta.

Sea la fuerza centrípeta F, la masa del piloto (m) = 70 Kg, el radio (r) = 500 my la velocidad (v) = 360 km / hr * 1000/3600 = 100 m / s

F = mv ^ 2 / r

F = 70 * (100) ^ 2/500

F = 1400 N

2. the temperature in a refrigerator coil is 267k and that in the condenser coil is 295k. assuming that the machine operates on the reversed carnot cycle, calculate : (i) c.o.p.(ref.) (ii) the refrigerating effect per kw of input work. (iii) the heat rejected to the condenser.

Answers

(i) C.O.P.(ref) = \(T_{c}\) / (\(T_{h}\) - \(T_{c}\))

(ii) Refrigerating effect per kW = (\(T_{h}\) - \(T_{c}\)) / \(T_{h}\)

(iii) Heat rejected to condenser = \(Q_{h}\) - \(Q_{c}\)

To calculate the quantities using the reversed Carnot cycle, we can use the Carnot efficiency formula:

(i) The coefficient of performance (C.O.P.) for a refrigerator operating on the reversed Carnot cycle is given by:

  C.O.P.(ref) = \(T_{c}\) / (\(T_{h}\) - \(T_{c}\))

  where Tc is the temperature of the refrigerator coil (267K) and Th is the temperature of the condenser coil (295K).

(ii) The refrigerating effect per kW of input work can be calculated as:

  Refrigerating effect per kW = (\(T_{h}\) - \(T_{c}\)) / \(T_{h}\)

  where Th is the temperature of the condenser coil (295K) and \(T_{c}\) is the temperature of the refrigerator coil (267K).

(iii) The heat rejected to the condenser can be calculated as:

  Heat rejected to condenser = \(Q_{h}\) - \(Q_{c}\)

  where \(Q_{h}\) is the heat absorbed by the condenser and \(Q_{c}\) is the heat extracted by the refrigerator.

Please note that these calculations assume idealized conditions and the reversed Carnot cycle.

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the temperature in degrees farenheight in times square during a day in aguast can be predicted by the function t(x)

Answers

The given statement is that the temperature in degrees Fahrenheit in times square during a day in August can be predicted by the function t(x).

Hence, it can be stated that the function t(x) provides a prediction for the temperature in degrees Fahrenheit in Times Square for a given value of x. Here, x represents the input variable.

It is important to note that the input variable must be provided in the correct units and format as required by the function t(x).The content loaded refers to the data that has been previously collected and is available for analysis. In the context of predicting temperature using function t(x),

the content loaded can refer to temperature data collected in Times Square during August on previous days or years. This data can be analyzed and used to develop the function t(x) that predicts temperature for a given input variable x.

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If a car is traveling 35 m/s for 200 seconds, how far will the car travel?

Answers

Hey I’m just setting up my profile so I’ll say fast

If the maximum tension in rope 1 is 18000 N calculate maximum acceleration of the helicopter before the rope breaks. The mass being held by rope 1 = 900kg

Answers

\(\begin{gathered} Given: \\ mass\text{ of the object=900Kg} \\ maxmum\text{ tension =18000N} \end{gathered}\)\(to\text{ find: the maximum acceleration of the helicopter}\)\(\begin{gathered} from\text{ Newton's second law of motion} \\ F=ma \\ F=\text{ net force on the object } \\ a=acceleration\text{ of the object} \end{gathered}\)\(\begin{gathered} force\text{ working on the mass 900Kg object} \\ mg\text{ in downward direction } \\ tension\text{ T in upward direction } \\ m=mass\text{ of the object.} \\ a\text{ = acceleration of the object} \end{gathered}\)\(\begin{gathered} applying\text{ Newton's law} \\ T-mg=ma \\ (since\text{ the acceleration is in the upward direction\rparen} \end{gathered}\)\(\begin{gathered} since\text{ due to the tension force the object is going in the upward } \\ direction\text{ and the maximum tension force can be 18000N if the tension } \\ increases\text{ beyond this value the rope will break. } \end{gathered}\)\(\begin{gathered} put\text{ T=18000N in the above equation} \\ 18000N-900Kg*9.8m\text{/s}^2=900Kg*a \\ 9180N=900Kg*a \\ a=\frac{9180}{900}m\text{/s}^2 \\ a=10.2\text{ }m\text{/s}^2 \end{gathered}\)

so when the acceleration of the helicopter will be 10.2 m/s² then the rope

will break down.

which is larger 15mm or 0.15cm

Answers

Answer:

1 cm = 10mm

Explanation:

hey there both are equal

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