The average speed of a baseball line drive is 83 miles per hour. Josiah


a practiced a new technique to improve his hitting speed. His coach recorded


the speed of 42 random hits during practice and found that his average speed


using the new technique was 84. 2 miles per hour, with a standard deviation of


4. 7 miles per hour.


Part A: State the correct hypotheses Josiah is trying to prove the new


technique is an improvement over the old technique. (4 points)


Part B: Identify the correct test and check the appropriate conditions. (6


points)


I have the answer to part A i just have no idea how to check my conditions. PLEASE HELP!!!

Answer: Inverse Operation

Step-by-step explanation:

Answer:

Yes

Step-by-step explanation:

An equation is called a Direct Variation if it is the form y=kx, where, k cannot be equal to zero is the constant of variation.

the value of the constant of variation is obtained by diving x:

\(k=\frac{y}{x}\)

The density of \(\(c - \frac{1}{\bar{h}}\) is given by: \\\[f(x) = \frac{1}{\Gamma(n\alpha)\beta^{n\alpha}} x^{n\alpha - 1} e^{-\frac{x}{\beta}}\]\)

To find the distribution of \(\(\hat{\theta}\), we are given that \(c - \frac{1}{\bar{h}}\) has a gamma \(n\alpha, \beta\)\) distribution. The gamma distribution is defined as:

\(\[f(x) = \frac{1}{\Gamma(\alpha)\beta^\alpha} x^{\alpha - 1} e^{-\frac{x}{\beta}}\]\)

where\(\(\Gamma(\alpha)\)\) is the gamma function.

Now, let's find the density of\(\(c - \frac{1}{\bar{h}}\). Since \(c - \frac{1}{\bar{h}}\) has a gamma \(n\alpha, \beta\) distribution, we have:\[f(x) = \frac{1}{\Gamma(n\alpha)\beta^{n\alpha}} x^{n\alpha - 1} e^{-\frac{x}{\beta}}\]\)

where \(\(n\alpha\) is the shape parameter and \(\beta\)\) is the scale parameter.

Therefore, the density of \(\(c - \frac{1}{\bar{h}}\) is given by:\[f(x) = \frac{1}{\Gamma(n\alpha)\beta^{n\alpha}} x^{n\alpha - 1} e^{-\frac{x}{\beta}}\]This is the desired density for the distribution of \(c - \frac{1}{\bar{h}}\).\)

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By using the properties of the gamma distribution and substituting the given parameters, we have derived the density function for c−1h¯, which follows a gamma nα, βnc distribution.

To find the distribution of ˆθ, we are given that c−1h¯ follows a gamma nα, βnc distribution. Let's break down the problem step by step.

1. We know that c−1h¯ follows a gamma nα, βnc distribution. The gamma distribution is defined as:

\(\(f(x) = \frac{(\beta^\alpha \cdot x^{\alpha-1} \cdot e^{-\beta x})}{\Gamma(\alpha)}\)\)

  where α > 0 is the shape parameter, β > 0 is the rate parameter, x > 0 is the random variable, and Γ(α) is the gamma function.

2. To find the density of c−1h¯, we substitute the given parameters nα and βnc into the gamma distribution formula. So the density of c−1h¯ is:

\(\(f(c−1h¯) = \frac{(\beta^\alpha \cdot (c−1h¯)^{\alpha-1} \cdot e^{-\beta(c−1h¯)})}{\Gamma(\alpha)}\)\)

3. Simplifying the expression, we have:

\(\(f(c−1h¯) = \frac{(\beta^\alpha \cdot (c−1)^{\alpha-1} \cdot h¯^{\alpha-1} \cdot e^{-\beta(c−1h¯)})}{\Gamma(\alpha)}\)\)

4. Hence, we have shown that c−1h¯ has a gamma nα, βnc distribution, and its density is given by:

\(\(f(c−1h¯) = \frac{(\beta^\alpha \cdot (c−1)^{\alpha-1} \cdot h¯^{\alpha-1} \cdot e^{-\beta(c−1h¯)})}{\Gamma(\alpha)}\)\)

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The converted unit of 15 cm/s to m/hr is 540 m/hr

From the question, we have the following parameters that can be used in our computation:

Unit = 15 cm/s

In metric units

1 cm equals 0.01 meters

This means that

1 cm = 0.01 m

Substitute 1 cm = 0.01 m in Unit = 15 cm/s

So, we have the following equation

Unit = 15 x 0.01 m/s

Evaluate the products

So, we have the following equation

Unit = 0.15 m/s

Also;

In metric units

1 seconds equals 1/3600 hours

This means that

1 s = 1/3600 hr

Substitute 1 s = 1/3600 hr in Unit = 0.15 m/s

So, we have the following equation

Unit = 0.15/(1/3600) m/hr

Evaluate the quotients

So, we have the following equation

Unit = 540 m/hr

Hence, the converted unit is 540 m/hr

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Constructing a confidence interval for the mean of a distribution based on one sample is Confidence level = 1 - significance level.

The definition of the confidence level is (1-α). Zα is the number of standard deviations from the mean at which X with a certain probability lies. If Z = 1.96 is selected, the likelihood that the real mean falls inside the range is set at 0.95, hence we are asking for the 95% confidence interval.

Let us consider,

Confidence level = c

significance level \(= \alpha\)

\(c = 1 - \alpha\)

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===================================

Explanation:

HA = hypotenuse angle

The tickmarks tell us that the hypotenuse IJ is the same length as the hypotenuse LM. So that's the "hypotenuse" portion of "HA".

The "angle" portion refers to the acute angles HIJ and KLM being the same measure, as shown by the curved arc marking. We aren't referring to the right angles because the HA theorem can only be used for right triangles, so that means the right angle is already built into it (and we can ignore the right angles).

Notice how HA is a special case of AAS.

#1

Quadratic equation means having degree highest 2

#2

The z-score for a person who received a score of 19 on this biology quiz is 0.77 .

(rounded to two decimal places).A z-score, often known as a standard score, is a mathematical term that compares an individual's raw score to the population mean in terms of standard deviations. It is calculated using the formula (X - μ) / σ, where X is the raw score, μ is the population mean, and σ is the standard deviation.

Here, the population mean is 17 and the standard deviation is 2.6. Therefore, the formula for calculating the z-score of a person who received a score of 19 is as follows:(19 - 17) / 2.6 = 0.77Hence, the z-score (to 2 decimal places) for a person who received a score of 19 on this biology quiz is 0.77.

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Answer:

75

Step-by-step explanation:

1 = 0.001 kilograms so 750 = 0.75, so - 675 by 750 and u get 75

Answer:

That means he will have $100

Step-by-step explanation:

Half of 200 is 100

Answer:

The white corn section covers \(\frac{3}{20}\) of the whole field.

Step-by-step explanation:

The statement indicates that section of the white corn is a portion within the corn section of the field. The statement can be interpreted as a multiplication of rational numbers. That is to say:

\(x = \frac{1}{4} \times \frac{3}{5}\)

\(x = \frac{1 \times 3}{4 \times 5}\)

\(x = \frac{3}{20}\)

The white corn section covers \(\frac{3}{20}\) of the whole field.

emm sorry I just think your sentence is good so I search then it said it is from https://education.seattlepi.com/four-factors-influence-weather-4416.html

.... sorry TT - TT       this is a crying face if you don't understand and zoom is good but microsoft team is better I think. >-<

Answer:

  a) 22e^-0.01t kilograms

  b) about 19.906 kilograms

Step-by-step explanation:

You want an equation for the amount of salt in a 15 kL brine tank initially containing 22 kg of salt if 150 L/min of the contents is replaced by pure water.

The quantity of salt s(t) in kilograms can be described by the differential equation ...

  s(0) = 22; s'(t) = -150/15000·s(t)

The solution can be found by separation of variables.

  \(\displaystyle\dfrac{ds}{dt}=-0.01s\\\\\int{\dfrac{1}{s}}\,ds=-0.01\int{}\,dt\\\\\ln{s}=-0.01t+c_1\\\\s=c_2\cdot e^{-0.01t}\qquad\text{where $c_2$ is $s(0)=22$}\\\\\boxed{s(t)=22e^{-0.01t}}\)

The amount of salt remaining after 10 minutes is ...

  s(10) = 22·e^(-0.01·10) = 22·e^-0.1

  s(10) ≈ 19.906 . . . . kilograms

There is about 19.906 kg of salt in the tank after 10 minutes.

__

Additional comment

The initial rate of change of the amount of salt is -22/100 kg/min, so after 10 minutes, we expect an approximate reduction by 2.2 kg to 19.8 kg. Since the rate slows as salt is removed, the value 19.9 kg after 10 minutes is reasonable.

There are a couple of places where the integration constant can be put in the equation for the salt quantity. As a multiplier of the exponential function, its value is found in a straightforward way.

The area of the region enclosed by the curves 10x=2y²+12y+19 and x=-4y-10 is 174/3 units².

To find the area of the region enclosed by the curves 10x=2y²+12y+19 and x=-4y-10, we need to solve this problem in the following way:

Since the curves are already in the form of x = f(y), we need to use vertical strips to find the area.

So, the integral for the area of the region is given by:

A = ∫a b [x₂(y) - x₁(y)] dy

Here, x₂(y) = 10 - 2y² - 12y - 19/5 = - 2y² - 12y + 1/2 and x₁(y) = -4y - 10

So,

A = ∫(-3)⁻²[(-2y² - 12y + 1/2) - (-4y - 10)] dy + ∫(-2)⁻²[(-2y² - 12y + 1/2) - (-4y - 10)] dy

=> A = ∫(-3)⁻²[2y² + 8y - 19/2] dy + ∫(-2)⁻²[2y² + 8y - 19/2] dy

=> A = [(2/3)y³ + 4y² - (19/2)y]₋³ - [(2/3)y³ + 4y² - (19/2)y]₋² | from y = -3 to -2

=> A = [(2/3)(-2)³ + 4(-2)² - (19/2)(-2)] - [(2/3)(-3)³ + 4(-3)² - (19/2)(-3)]

=> A = 174/3

Hence, the area of the region enclosed by the curves is 174/3 units².

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The finance charge, on the average daily balance, for this card over this one month is $3.87.

The average daily balance is the total balance for the billing cycle divided by the number of days in the cycle.

With the ending average daily balance for the month determined above, the finance charge can be computed by multiplying it and the MPR.

The MPR is the APR divided by 12, giving the monthly interest rate.

APR interest rate = 18%

Monthly APR = 1.5% (18% ÷ 12)

Days 1-5: $200 (initial balance)        $1,000 ($200 x 5)

Days 6-20: $350 ($150 purchase)    5,250 ($350 x 15)

Days 21-30: $150 ($200 payment)    1,500 ($150 x 10)

Total                                                  $7,750

Average daily balance =                   $258.33 ($7,750/30)

Finance charge = $3.87 ($258.33 x 1.5%)

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Answer:

9

Step-by-step explanation:

the first few days have come a different person and I am sure how you can get to the claire family thing that you are

The percentage of the total mattresses that are not extra firm non-memory foam mattresses is 17%.

Let's break down the information step by step to find the percentage of the total mattresses that are not extra firm non-memory foam mattresses.

Let:

M = Total number of mattresses

MF = Memory foam mattresses

EF = Extra firm mattresses

MF&EF = Memory foam and extra firm mattresses (extra firm memory foam mattresses)

From the given information, we have:

1. 75% of the mattresses are memory foam: MF = 0.75 * M

2. 20% of the mattresses are extra firm: EF = 0.20 * M

3. 12% of the total mattresses are extra firm memory foam: MF&EF = 0.12 * M

Now, to find the percentage of mattresses that are not extra firm non-memory foam, we need to subtract the number of memory foam, extra firm, and extra firm memory foam mattresses from the total number of mattresses:

Not extra firm non-memory foam mattresses = M - (MF + EF - MF&EF)

Plugging in the values:

Not extra firm non-memory foam mattresses = M - (0.75 * M + 0.20 * M - 0.12 * M)

Not extra firm non-memory foam mattresses = M - (0.83 * M)

Now, the percentage of not extra firm non-memory foam mattresses is:

Percentage = (Not extra firm non-memory foam mattresses / M) * 100

Percentage = ((M - 0.83 * M) / M) * 100

Percentage = (0.17 * M / M) * 100

Percentage = 0.17 * 100

Percentage = 17%

So, the percentage of the total mattresses that are not extra firm non-memory foam mattresses is 17%.

The correct option is F. 17.

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Answer: D. -0.6

Step-by-step explanation:

Z score formula= x-mean/ SD

34-40/10= -3/5= -0.6

The standardized score for a tree that is 34 years old is -0.6

We have given that,

The age of trees in a forest is approximately normal with an average age of 40 years and a standard deviation of 10 years.

We have to determine what is the standardized score for a tree that is 34 years old

Z score formula= x-mean/ SD

We use the given values in the above formula so we get,

Z score =34-40/10

Z score = -3/5

Z score = -0.6

Therefore, The standardized score for a tree that is 34 years old is -0.6

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Answer:

c

Step-by-step explanation:

If you look at the two points on the graph you can see that the point that crosses the y axis is at -4

If you use the two points and count the slope you see that it is down 5 over 6 which gives it a slope of -5/6

The number of marbles that represent each vegetable option are: carrots - 3 marbles, green beans - 7 marbles, asparagus - 2 marbles, and vegetable medley - 8 marbles.

To model the situation of the catering company, we need to use percentages to represent the number of customers who choose each vegetable option. We are given that 15% of customers choose carrots, 35% choose green beans, and 10% choose asparagus. The remaining customers, who choose vegetable medley, can be represented by subtracting the sum of the other three percentages from 100%.

To represent this situation using marbles, we can assign a certain number of marbles to each vegetable option based on the percentage of customers who choose it. For example, if we use 20 marbles in total, 15% of 20 is 3, so we can assign 3 marbles to carrots. Similarly, 35% of 20 is 7, so we can assign 7 marbles to green beans. 10% of 20 is 2, so we can assign 2 marbles to asparagus. Finally, the remaining 8 marbles would represent the customers who choose vegetable medley.

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Answer:

Using the free fall calculator from omnicalculator.com, we can determine the time it takes for an object to hit the sidewalk when dropped from a 400-foot tall building. Assuming the object is dropped from rest (v₀ = 0), we use the formula s = (1/2)gt², where s is the distance fallen, g is the acceleration due to gravity (9.80665 m/s²), and t is the time of fall.

First, we convert 400 feet to meters, approximately 121.92 meters. Then, we plug in the values into the formula and solve for t:

121.92 = (1/2) * 9.80665 * t²

Simplifying the equation, we get:

t² = 121.92 / 4.903325

t² = 24.8

t ≈ 4.98 seconds Thus, an object dropped from a 400-foot tall building takes approximately 4.98 seconds to hit the sidewalk.

The correct answer of set AU A' is: option B. AU A' = U.

To determine the set AU A', we need to understand the meanings of the symbols involved.

- A: Represents a set.

- U: Denotes the universal set, which contains all elements under consideration.

- A': Represents the complement of set A, which includes all elements not in A.

- ø: Represents the empty set, which contains no elements.

Using these definitions, let's evaluate AU A':

AU A' includes all elements that are in set A or in the complement of A.

If an element is in A, it is included in AU A'. If an element is not in A, it may be in the complement of A (A'), so it is also included in AU A'.

Since any element that is in A or not in A is included in AU A', it means that AU A' is equal to the universal set U.

Therefore, the correct answer is: B. AU A' = U

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The conclusion regarding the publisher's claim is that it is not valid. When the testing firm rejected the null hypothesis after performing a test at the 0.05 level of significance.

Therefore, the claim that 50% of their readers own a laptop by the newsletter publisher is not true. A null hypothesis is a statement that is being tested for possible rejection under the assumption that it is true. It is often symbolized as H0. A one-tailed test examines only one side of the distribution, while a two-tailed test examines both sides.

For a one-tailed test, the null hypothesis is rejected if the sample statistic is at the extremes of the distribution (either in the upper or lower tail). On the other hand, for a two-tailed test, the null hypothesis is rejected if the sample statistic is at the extremes of both tails.The level of significance, denoted as alpha (α), is the probability of committing a Type I error. A Type I error is the rejection of a null hypothesis that is true. Alpha is typically set to 0.05 or 0.01. A p-value is a probability that is calculated from the test statistics.

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Therefore, the diameter of the sphere is approximately 20.2 feet when the volume is 6329 cubic feet.

The formula for the volume of a sphere is V = (4/3)πr³, where r is the radius of the sphere. To find the diameter, we need to find the radius first.

(4/3)πr³ = 632

r³ = (3/4)(6329/π)

r = ∛(3(6329/4π))

r ≈ 10.1 feet (rounded to one decimal place)

The diameter of the sphere is twice the radius, so:

d = 2r

≈ 20.2 feet (rounded to one decimal place)

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