The average cost of living for a family of four in twelve different cities was found to be $65,351 with a standard deviation of $7,711. What is a 90% confidence interval for the true mean

Answer:

x= 3/2

Step-by-step explanation:

3/x=2

Multiply x both sides so,

3 =2x

Divide 2 to get the value of x so,

x= 3/2

The missing quantities are

Social Security= $217

Medicare = $‭50.75‬

Net Pay is $‭2,633.67‬

First, Taxable income is therefore;

= 3,500 - (76.90 x 4 )

= $‭3,192.4‬0

Federal Income Tax (FIT).

With taxable income of $‭3,192.4‬0, the tax is $565.15 plus 28% of anything above $‭3,073.

= 565.15 + (28% x (‭3,192.4‬0 - 3,073))

= 565.15 + 33.43

= $‭598.58

and, Social Security

= Gross pay x 6.2%

= 3,500 x 6.2%

= $‭217‬

and, Medicare

= 3,500 x 1.45%

= $‭50.75‬

Then, the Net Pay

= 3,500 - 598.58 - 217 - 50.75

= $‭2,633.67‬

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Answer:

108

Step-by-step explanation:

he HAS $40 NEEDS $148

he charges $12 per yard and 9 yards so 12x9=108

$108. + $40. =$148

12×9= + money he. = add it all together

108. already had. you get $108 needed

by cutting 9 yards at

$12 each.

i really hope this helps

Answer:

D. X = 20

..............

Answer:

  27 1/4

Step-by-step explanation:

You want the value of a³+2b when a=3 and b=1/8.

To find the value of the expression, put each number in place of the corresponding variable and do the arithmetic.

   a³ +2b

  = 3³ +2(1/8)

  = 3·3·3 + 2/8

  = 27 + 1/4

  = 27 1/4

__

Additional comment

The exponent of 3 tells you how many times 'a' is a factor in the product. Here, the product has the factor 3 three times.

Therefore, 1/2 cup of oil is required for every cup of water.

A number that connects a component to a whole is a proportion. For instance, there are 100 students in the school with 20 males and 80 women. The percentage of men is 20/100, or 20%. 80 out of 100, or 80%, are women.

According to the recipe, for every 2/3 cup of water, 1/4 cup of oil is needed. We can write this ratio as:

1/4 cup oil : 2/3 cup water

To find how much oil is needed per cup of water, we can set up a proportion and solve for the missing value:

1/4 cup oil : 2/3 cup water = x cups oil : 1 cup water

Cross-multiplying, we get:

1/4 cup oil * 1 cup water = 2/3 cup water * x cups oil

Simplifying, we get:

1/4 = 2/3 * x

Dividing both sides by 2/3, we get:

x = 1/2

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The critical value is 9.925, rounded to three decimal places.

To calculate the critical value for a 99.9% confidence level with a sample size of 4, we will use the t-distribution, since the population standard deviation is unknown.

The t-distribution is used when the sample size is small (usually n < 30) and the population standard deviation is unknown.

First, find the degrees of freedom (df) for the t-distribution, which is equal to the sample size (n) minus 1:

Next, we need to find the critical value (t) that corresponds to a 99.9% confidence level (or a 0.999 probability) and 3 degrees of freedom. We will look this up in a t-distribution table or use a t-distribution calculator.

Using a t-distribution calculator or table, the t-score corresponding to a 99.9% confidence level (two-tailed) and 3 degrees of freedom is approximately 9.925.

So, the critical value is 9.925, rounded to three decimal places.

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The statement is true, the scale factor maintains the proportions between the sides.

We want to see if the statement "Scale factors figures must be the same proportions on all sides from the original figure." is true or false.

Suppose we have a polygon with N sides, such that the lengths of each side are:

{L₁, L₂, L₃,...}

If we apply a scale factor k, we just need to multiply each one of these lengths by k, then we will get:

{k*L₁, k*L₂, k*L₃,...}

Now, let's take the proportion between the new lengths for sides 1 and 2, we will get:

(k*L₁)/(k*L₂) = L₁/L₂

The scale factor disappears, then the proportions are maintained,

The statement is true.

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You have teh following equation:

(x - 5)/2 = - 6

In order to find the solution to the previous equation, proceed as follow:

(x - 5)/2 = -6 multiply by 2 both sides

x - 5 = -6(2)

x - 5 = -12 add 5 both sides

x = -12 + 5 simlify

x = -7

Hence, the solution to the gicen equation is x = -7

Answer:430.2

Step-by-step explanation:

Answer:

7.6

Step-by-step explanation:

calculator

Geometry encompasses various topics such as angles, lines, triangles, circles, polygons, and more.

Whether you need help with a specific theorem, a geometric proof, or solving a particular problem, feel free to describe the problem or provide any relevant information.

You can also ask general questions about geometry concepts or seek clarification on any topic you find challenging. Remember to provide all the necessary details, such as given information, diagrams, or specific requirements of the problem, to help me understand and assist you better.

Geometry often involves visual representation, so if you can provide any diagrams or illustrations related to your question, it would be helpful. However, if you can only describe the problem or concept in words, that's perfectly fine too.

Rest assured that I'll do my best to provide clear explanations, step-by-step solutions, and any additional information or insights to help you understand and solve your geometry problem.

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Using the Venn Diagram principles, the number of customers at the supermarket who purchased both shirts and pants is 26.

A Venn Diagram shows a pictorial or graphical representation of the relationship (similarities and differences) between data sets.

In a Venn Diagram, overlapping circles or other shapes can be used to depict the logical relationships between two or more data sets or items.

The total number of customers at a supermarket = 118

The number of customers who purchased shirts, n(A) = 45

The number of customers who purchased pants, n(B) = 59

The number of customers who purchased neither shirts nor pants = 40

Let the number of customers who purchased both shirts and pants = n(A ∩ B)

n(A ∪ B) = n(A) + n(B) - n(A ∩ B)

n(A) = 45 n(B) = 59 n(A ∪ B) = 118 - 40 = 78

Substituting values:

78 = 45 + 59 - n(A ∩ B)

Solving for n(A ∩ B), we get:

n(A ∩ B) = 45 + 59 - 78 n(A ∩ B) = 26

Thus, using the formula of Venn Diagram, we can conclude that at this supermarket with 118 customers, 26 customers purchased both shirts and pants.

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Answer:

27

Step-by-step explanation:

know that

h = 3

h × h × h

3 × 3 × 3

= 27

Answer:

(4.1000)+ (2.100) + (7.10)

From the box-and-whisker plot, we have that:

a) City B had more noon temperatures above 76ºF.

b) City A had the largest IQR.

c) City B had the larger median temperature.

d) City A had the highest noon temperature.

For City A, the measures are given as follows:

Hence the interquartile range of temperatures is of:

75 - 67 = 8ºF.

For City B, the measures are given as follows:

Hence the interquartile range of temperatures is of:

80 - 73 = 7ºF.

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Answer:

give a thanks first and then ill tell you

Step-by-step explanation:

Answer:

Maybe it's D) or c) if not i'm du.mb and sorry

Step-by-step explanation:

Answer:

16.8  or 17 blue

50.4  or 50 brown

33.6  or 34 yellow

33.6  or 34 red

16.8  or 17 orange

16.8  or 17 green

Step-by-step explanation:

7 x 24 = 168 candies

blue = b

brown = w

yellow = y

red = r

orange = o

green = g

1b = 3w + 2y + 2r + 1o + 1g

1 +3 + 2 + 2 + 1 + 1 = 10

168/10 = 16.8

1(16.8) +3(16.8) + 2(16.8) + 2(16.8) + 1(16.8) + 1(16.8) =

16.8 blue

50.4 brown

33.6 yellow

33.6 red

16.8 orange

16.8 green

The option that can be used to verify the trigonometric identity, \(tan\left(\dfrac{x}{2}\right)+cot\left(x \right) = csc\left(x \right)\) is option C;

C. \(tan\left(\dfrac{x}{2} \right) + cot\left(x \right) = \dfrac{1-cos\left(x \right)}{sin\left( x \right)} +\dfrac{cos \left(x \right)}{sin\left(x \right)} =csc\left(x \right)\)

A trigonometric identity is an equations that consists of trigonometric functions that remain true for all values of the argument of the functions

The specified identity is presented as follows;

\(tan\left(\dfrac{x}{2} \right)+cot(x)=csc(x)\)

The half angle formula for tangent indicates that we get;

\(tan\left(\dfrac{1}{2} \cdot \left(\eta \pm \theta \right) \right) = \dfrac{tan\left(\dfrac{1}{2} \cdot \eta \right)\pm tan\left(\dfrac{1}{2} \cdot \theta \right)}{1 \mp tan\left(\dfrac{1}{2} \cdot \eta \right)\times tan\left(\dfrac{1}{2} \cdot \theta \right)}\)

\(\dfrac{tan\left(\dfrac{1}{2} \cdot \eta \right)\pm tan\left(\dfrac{1}{2} \cdot \theta \right)}{1 \mp tan\left(\dfrac{1}{2} \cdot \eta \right)\times tan\left(\dfrac{1}{2} \cdot \theta \right)}=\dfrac{sin \left(\eta\right) \pm sin\left(\theta \right)}{cos \left(\eta \right) + cos \left(\theta \right)} = -\dfrac{cos \left(\eta\right) - cos\left(\theta \right)}{sin \left(\eta \right) \mp sin \left(\theta \right)}\)

When η = 0, we get;

\(-\dfrac{cos \left(0\right) - cos\left(\theta \right)}{sin \left(0 \right) \mp sin \left(\theta \right)}=-\dfrac{1 - cos\left(\theta \right)}{0 \mp sin \left(\theta \right)}=\dfrac{1 - cos\left(\theta \right)}{sin \left(\theta \right)}\)

Therefore;

\(tan\left(\dfrac{x}{2} \right)=\dfrac{1 - cos\left(x \right)}{sin \left(x \right)}\)

\(cot\left(x \right) = \dfrac{cos(x)}{sin(x)}\)

\(tan\left(\dfrac{x}{2} \right)+cot(x)= \dfrac{1 - cos\left(x \right)}{sin \left(x \right)} +\dfrac{cos(x)}{sin(x)}\)

\(\dfrac{1 - cos\left(x \right)}{sin \left(x \right)} +\dfrac{cos(x)}{sin(x)}=\dfrac{1-cos(x)+cos(x)}{sin(x)} = \dfrac{1}{sin(x)}\)

\(\dfrac{1 - cos\left(x \right)}{sin \left(x \right)} +\dfrac{cos(x)}{sin(x)}=\dfrac{1}{sin(x)}=csc(x)\)

Therefore;

\(tan\left(\dfrac{x}{2} \right)+cot(x)= \dfrac{1 - cos\left(x \right)}{sin \left(x \right)} +\dfrac{cos(x)}{sin(x)} = csc(x)\)

The correct option that can be used to verify the identity is option C

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1. We can simply multiply 6.50 by 2!

6.50 x 2 = 13

The book cost $13

2. The easiest way to do this is to convert the fractions into decimals.

1/4 = 0.25

1/5 = 0.2

1/8 = 0.125

Add them together: 0.575!

Subtract this from 1: .425

Multiply by 100: 42.5

42.5% is your answer!

Hope this helps!

Answer: B

Step-by-step explanation:

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Answer:

Your answer is 91, 494

Step-by-step explanation:

I will tell how is your answer is 91,494

72,931

+18,563

=91,494

Just add the question then you have your answer

Answer:

B) (0,0)

Step-by-step explanation:

The only place the line even touches the x line is at (0,0)

Answer:

\(f(x) \: = \: 3x \: - 2 \: then \: when \\ \: f(x) \: = - 11 \: then \: x \: = \: - 3.\)

\(if \: f(x) \: = \: 3x \: - 2 \: then \: when \\ \: f(x) \: = - \frac{2}{3} \: then \: x \: = \: \frac{4}{9} .\)

There are 73,440 ways can the singers finish first through fourth​.

A way, especially one of several possible variations, in which a set or number of things can be ordered or arranged.

Given that, There are 18 finalists in a singing competition. The top four singers receive prizes.

In this case, the order is required, so we'll use permutation here. You need to pick 4 out of 18.

\(^{n} P_{r}\) = n!/(n-r)!

n = 18 and r = 4

18P4 = 18!/(18-4)!

= 18!/14!

= 73,440

Hence, there are 73,440 ways possible.

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this is the answer I believe

Answer:

Step-by-step explanation:

front side: 6x3 = 18

back : 6x3 = 18

right:6x2 = 12

left:6x2 = 12

top: 3x2 =6

bottom: 3x2 =6

18 + 18 + 12 + 12 + 6 + 6

= 72

Answer:

Step-by-step explanation:

In the Intermediate Phase of mathematics education, one topic that demonstrates a hierarchical and logical progression in patterns, functions, and algebra is the concept of "Linear Equations."

The topic of Linear Equations in the Intermediate Phase builds upon the foundation laid in earlier grades and serves as a stepping stone towards more advanced algebraic concepts. Here is an overview of the topic sequence and content area spread for Linear Equations:

Introduction to Variables and Expressions:

Students are introduced to the concept of variables and expressions, learning to represent unknown quantities using letters or symbols. They understand the difference between constants and variables and learn to evaluate expressions.

Solving One-Step Equations:

Students learn how to solve simple one-step equations involving addition, subtraction, multiplication, and division. They develop the skills to isolate the variable and find its value.

Solving Two-Step Equations:

Building upon the previous knowledge, students progress to solving two-step equations. They learn to perform multiple operations to isolate the variable and find its value.

Writing and Graphing Linear Equations:

Students explore the relationship between variables and learn to write linear equations in slope-intercept form (y = mx + b). They understand the meaning of slope and y-intercept and how they relate to the graph of a line.

Systems of Linear Equations:

Students are introduced to the concept of systems of linear equations, where multiple equations are solved simultaneously. They learn various methods such as substitution, elimination, and graphing to find the solution to the system.

Word Problems and Applications:

Students apply their understanding of linear equations to solve real-life word problems and situations. They learn to translate verbal descriptions into algebraic equations and solve them to find the unknown quantities.

The content area spread for Linear Equations includes concepts such as variables, expressions, equations, operations, graphing, slope, y-intercept, systems, and real-world applications. The progression from simple one-step equations to more complex systems of equations reflects a logical sequence that builds upon prior knowledge and skills.

By following this hierarchical progression, students develop a solid foundation in algebraic thinking and problem-solving skills. They learn to apply mathematical concepts and procedures in a systematic and logical manner, paving the way for further exploration of patterns, functions, and advanced algebraic topics in later phases of mathematics education.

Answer:

-36 ÷ -3

Step-by-step explanation:

Change in her school lunch account balance per lunch = -3

Total change in her school lunch balance last month = -36

Expression to show number of times Elena bought lunch last month = Total change in her school lunch balance last month ÷ Change in her school lunch account balance per lunch

= -36 ÷ -3

= -36/-3

= 12 times

Elena bought lunch 12 times last month