the array newvals will not contain any values because the code segment does not compile. {true, false, true, true} {false, true, false, false} {false, false, true, false} {true, true, false, true}
Answers
Because the code segment {false, true, false, false} does not compile, the array newvals won't have any values.
Which section of code can be utilized to regulate the execution of the dowork() method?A developer constructs a new Visualforce page and Apex extension and writes test classes that exercise 95% of the new Apex extension's functionality if (Trigger. isInsert) dowork();
How should the code be finished?Drag the proper code section to the proper spot. It is possible to use each code section just once, several times, or never at all. To read material, you might need to scroll or drag the split bar between windows.
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Answer: Because the code segment {false, true, false, false} does not compile, the array newvals won't have any values.Which section of code can be utilized to regulate the execution of the dowork() method?A developer constructs a new Visualforce page and Apex extension and writes test classes that exercise 95% of the new Apex extension's functionality if (Trigger. isInsert) dowork();How should the code be finished?Drag the proper code section to the proper spot. It is possible to use eachcode section just once, several times, or never at all. To read material, you might need to scroll or drag the split bar between windows.
Explanation: I hope this helps!-
Related Questions
The proposed grading at a project site will consist of 25,100 m3 of cut and 23,300 m3 of fill and will be a balanced earthwork job. The cut area has an average moisture content of 8.3%. The fill will be compacted to an average relative compaction of 93% based on a maximum dry unit weight of 18.3 kN/m3 and an optimum moisture content of 12.9% obtained from the modified Proctor test. Compute the volume of water in kiloliters that will be required to bring these soils to the optimum moisture content.
Answers
M = ((Ww / Ws) x 100)%
where M is the moisture content, Ww is the weight of water, and Ws is the weight of solids.
First, let's find the weight of solids for the cut area:
Ws = V x γ
where V is the volume and γ is the unit weight.
Ws = 25,100 m3 x 1.8 t/m3 x 1000 kg/t
Ws = 45,180,000 kg
Next, let's find the weight of solids for the fill area:
Ws = V x γ
where V is the volume and γ is the unit weight.
Ws = 23,300 m3 x 18.3 kN/m3 x 1000 N/kN
Ws = 425,190,000 N
Now, let's find the weight of water required for the cut area:
M = ((Ww / Ws) x 100)%
0.129 = ((Ww / 45,180,000) x 100)%
Ww = 58,402 kg
Finally, let's find the weight of water required for the fill area:
M = ((Ww / Ws) x 100)%
0.129 = ((Ww / 425,190,000) x 100)%
Ww = 548,991 kg
To find the total volume of water required, we need to convert the weight of water to volume using the density of water:
ρ = 1000 kg/m3
For the cut area:
Vw = Ww / ρ
Vw = 58,402 kg / 1000 kg/m3
Vw = 58.4 m3
For the fill area:
Vw = Ww / ρ
Vw = 548,991 kg / 1000 kg/m3
Vw = 548.991 m3
Therefore, the total volume of water required to bring the soils to the optimum moisture content is approximately 607.4 m3 or 607.4 kiloliters.
7) Identify the accurate conversion of a Boolean expression y = (ab) + (p'qr) to VHDL.
a. y = (a and b) or (not p and q and r)
b. y = (a & b) | (~p & q& r)
c. y = (a && b) || (~p && q && r)
d. y = (a or b) and (not p or q or r)
Answers
The accurate VHDL conversion for the Boolean expression y = (ab) + (p'qr) is y = (a & b) | (~p & q & r). This VHDL representation captures the intended logic of the original Boolean expression
The accurate conversion of the Boolean expression y = (ab) + (p'qr) to VHDL is option b:
b. y = (a & b) | (~p & q & r)
In VHDL, the logical AND operator is represented by "&", the logical OR operator is represented by "|", and the logical NOT operator is represented by "~". Therefore, the expression (ab) is represented as (a & b) which performs the logical AND operation between variables a and b. Similarly, (p'qr) is represented as (~p & q & r) which performs the logical AND operation between the negation of p and variables q and r. The overall expression is obtained by using the logical OR operator "|" to combine the results of the two sub-expressions.
Thus, the accurate VHDL conversion for the Boolean expression y = (ab) + (p'qr) is y = (a & b) | (~p & q & r). This VHDL representation captures the intended logic of the original Boolean expression
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The accurate conversion of the Boolean expression y = (ab) + (p'qr) to VHDL is: **b. y = (a & b) | (~p & q& r)**
VHDL (VHSIC Hardware Description Language) is a programming language used for describing digital circuits and systems. In VHDL, the logical operators "and", "or", and "not" are represented by the symbols "&", "|", and "~", respectively. The conversion of the given Boolean expression to VHDL is as follows:
y = (ab) + (p'qr)
y = (a and b) or (not p and q and r)
y = (a & b) | (~p & q& r)
Therefore, option b is the accurate conversion of the Boolean expression to VHDL.
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3. Assertive communication means:
A. Confidently and directly communicating what you think and feel, without being aggressive
or passive
B.O Confidently saying what you think and feel, even If It means overshadowing someone
else's feelings
C.O Saying what you think and feel only If and when the other party gives you permission to
do so
D. None of the above
Answers
Answer:
A. Confidently and directly communicating what you think and feel, without being aggressive or passive.
Explanation:
Assertive communication is the ability to express both positive and negative ideas in a way that it is a honest and direct message. It doesn't mean to say things to the other person with the intent of causing harm or making them feel better, it's just saying things as they are.
9. The largest recorded earthquake centered in Idaho measured 7.2 on the Richter scale.
(a) The largest recorded earthquake centered in Montana was 3.16 times as powerful as the Idaho earthquake. What was the Richter scale reading for the Montana earthquake? (Round your answer to one decimal place.)
(b) The largest recorded earthquake centered in Arizona measured 5.6 on the Richter scale. How did tge power of the Idaho quake compare with that of tge Arizona quake? (Round your answer to two decimal places.)
______ times that of the Arizona quake
Answers
a. The Richter scale reading for the Montana earthquake is 7.7.
b. The power of the Idaho quake is approximately 251.19 times that of the Arizona quake.
(a) To find the Richter scale reading for the Montana earthquake, we can use the given information that it was 3.16 times as powerful as the Idaho earthquake.
Let's assume the Richter scale reading for the Montana earthquake as x.
According to the information given:
10^(3.16(x - 7.2)) = 3.16
Taking the logarithm of both sides (base 10):
3.16(x - 7.2) = log(3.16)
x - 7.2 = log(3.16)/log(10)
x - 7.2 = 0.5002
Adding 7.2 to both sides:
x = 7.2 + 0.5002
x = 7.7
Therefore, the Richter scale reading for the Montana earthquake is 7.7.
(b) To compare the power of the Idaho quake with that of the Arizona quake, we can use the formula:
Power = 10^(1.5 * Richter scale reading)
For the Idaho quake:
Power of Idaho quake = 10^(1.5 * 7.2)
For the Arizona quake:
Power of Arizona quake = 10^(1.5 * 5.6)
To find the ratio of the power of the Idaho quake to that of the Arizona quake:
Ratio = (Power of Idaho quake) / (Power of Arizona quake)
Ratio = 10^(1.5 * 7.2) / 10^(1.5 * 5.6)
Simplifying the expression:
Ratio = 10^(10.8) / 10^(8.4)
Using the property that a^b / a^c = a^(b - c):
Ratio = 10^(10.8 - 8.4)
Calculating the value:
Ratio = 10^2.4 ≈ 251.19
Therefore, the power of the Idaho quake is approximately 251.19 times that of the Arizona quake.
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Why are cars often called by numbers, like the BMW 428i or Nissan NV2500?
Answers
Answer: BMW did it again. They've show up with yet another automobile that's a genuine joy to operate a vehicle. The BMW 428i Coupe isn't so large , not to little - and it's got the elegant sport appearances of a coupe as well. Really, very pleasant really!
Explanation:
Milton has been tracking the migrating patterns of whales in the northwest Atlantic Ocean for five years. He knows where and when to find them as well as how quickly they move. Which qualification makes Milton successful in his research?
Answers
Answer:
knowledge of animal behavior and anatomy
Explanation:
the qualification that will make Milton successful in his research is a knowledge of animal behaviour and also their anatomy. the knowledge of whales behaviour has opened his eyes into their world so he knows to a great deal about them. it is through his knowledge of the behaviour of whales that he's able to get used to their migrating patterns to know where and when to find them. Also, through the body anatomy of whales he knows what their movement is like.
Answer:
knowledge of animal behavior and anatomy
The transfer function of a typical tape-drive system is given by
KG(s) = K(s + 4)/ s(s + 0.5)(s + 1)(s2 = 0.4s + 4)
where time is measured in milliseconds. Using Routh's stability criterion, determine the range of K for which this system is stable when the characteristic equation is 1 + KG(s) = 0.
Answers
Answer:
the range of K can be said to be : -3.59 < K< 0.35
Explanation:
The transfer function of a typical tape-drive system is given by;
\(KG(s) = \dfrac{K(s+4)}{s[s+0.5)(s+1)(s^2+0.4s+4)]}\)
calculating the characteristics equation; we have:
1 + KG(s) = 0
\(1+ \dfrac{K(s+4)}{s[s+0.5)(s+1)(s^2+0.4s+4)]} = 0\)
\({s[s+0.5)(s+1)(s^2+0.4s+4)]} +{K(s+4)}= 0\)
\(s^5 + 1.9 s^4+ 5.1s^3+6.2s^2+ 2s+K(s+4) = 0\)
\(s^5 + 1.9 s^4+ 5.1s^3+6.2s^2+ (2+K)s+ 4K = 0\)
We can compute a Simulation Table for the Routh–Hurwitz stability criterion Table as follows:
\(S^5\) 1 5.1 2+ K
\(S^4\) 1.9 6.2 4K
\(S^3\) 1.83 \(\dfrac{1.9 (2+K)-4K}{1.9}\) 0
\(S^2\) \(\dfrac{11.34-1.9(X)}{1.83}\) 4K 0
S \(\dfrac{XY-7.32 \ K}{Y}\) 0 0
\(\dfrac{1.9 (2+K)-4K}{1.9} = X\)
\(\dfrac{11.34-1.9(X)}{1.83}= Y\)
We need to understand that in a given stable system; all the elements in the first column is usually greater than zero
So;
11.34 - 1.9(X) > 0
\(11.34 - 1.9(\dfrac{3.8+1.9K-4K}{1.9}) > 0\)
\(11.34 - (3.8 - 2.1K)>0\)
7.54 +2.1 K > 0
2.1 K > - 7.54
K > - 7.54/2.1
K > - 3.59
Also
4K >0
K > 0/4
K > 0
Similarly;
XY - 7.32 K > 0
\((\dfrac{3.8+1.9K-4K}{1.9})[11.34 - 1.9(\dfrac{3.8+1.9K-4K}{1.83}) > 7.32 \ K]\)
0.54(2.1K+7.54)>7.32 K
11.45 K < 4.07
K < 4.07/11.45
K < 0.35
Thus the range of K can be said to be : -3.59 < K< 0.35
.Which of the following is an example of using an external integration tool?
A) Creating a Gantt chart
B) Including user representatives as active members of the project team
C) Creating a PERT chart
D) Using portfolio analysis
E) Developing a scoring model
Answers
D) Using portfolio analysis is an example of using an external integration tool.
Using an external integration tool refers to utilizing a tool or software that is external to the organization or project to facilitate integration processes. Among the options provided, portfolio analysis is an example of using an external integration tool.
Portfolio analysis is a strategic management technique that involves assessing and analyzing a portfolio of projects, investments, or resources. It helps organizations make decisions regarding resource allocation, risk management, and prioritization of projects or initiatives.
In order to conduct portfolio analysis effectively, organizations often employ specialized software or tools designed specifically for this purpose. These external integration tools enable the organization to consolidate data, perform analysis, and generate insights to support decision-making.
In contrast, the other options provided (creating a Gantt chart, creating a PERT chart, including user representatives as active members, developing a scoring model) do not necessarily require external integration tools. These activities can typically be carried out using internal resources and tools available within the organization.
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2. A silo (base not included) is to be constructed in the form of a cylinder surmounted by a hemisphere. The cost of construction per square unit
of surface area is twice as great for the for the hemisphere as it is for the cylindrical side wall. Determine the dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum. Neglect the thickness of the silo and waste in construction.
Answers
An extremum is a point where the function has its highest or lowest value, and at which the slope is zero.
The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum is as follows;
Height of cylinder = 2 × Radius of cylinderReason:
The given parameters are;
Form of silo = Cylinder surmounted by a hemisphere
Cost of construction of hemisphere per square unit = 2 × The cost of of construction of the cylindrical side wall
Required:
The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum
Solution:
The fixed volume of the silo, V, can be expressed as follows;
\(V = \pi \cdot r^2 \cdot h + \dfrac{2}{3} \cdot \pi \cdot r^3\)
\(h = \dfrac{V - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 }\)Where;
h = The height of the cylinder
r = The radius of the cylinder
The surface area is, Surface Area = 2·π·r·h + 2·π·r²
The cost, C = 2·π·r·h + 2×2·π·r² = 2·π·r·h + 4·π·r²
Therefore;
\(C = 2 \times \pi \times r\times \dfrac{V - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } + 4 \cdot \pi \cdot r^2 = \dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r}\)
\(C = \dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r}\)At the minimum value, we have;
\(\dfrac{dC}{dr} =0 = \dfrac{d}{dr} \left(\dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r} \right) = \dfrac{16 \cdot r^3 \cdot \pi - 6 \cdot V}{3 \cdot r^2}\)Which gives;
16·π·r³ = 6·V
\(V = \dfrac{16 \cdot \pi \cdot r^3}{6} = \dfrac{8 \cdot \pi \cdot r^3}{3}\)Which gives;
\(h = \dfrac{\dfrac{8 \cdot \pi \cdot r^3}{3} - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } = 2 \cdot r\)
h = 2·r
The height of the silo, h = 2 × The radius, 2
Therefore, the dimensions to be used if the volume is fixed and the cost is to be kept to a minimum is, height, h = 2 times the radius
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use the superposition principle to solve for va in the circuit
Answers
The superposition principle allows us to solve for va in a circuit with multiple sources by finding the individual contributions of each source and adding them up. This can be done by turning off one source at a time and solving for va in each case.
To solve for va in the circuit using the superposition principle, we first need to find the contributions of each source individually and then add them up. We can turn off one source at a time and solve for va in each case. Then we add up the individual contributions to get the final value of va.
For example, if we turn off the voltage source V1, we can redraw the circuit with V2 and the current source as the only active sources. We can then solve for va using Ohm's law and Kirchhoff's laws. We repeat the same process for V2 and the current source, each time turning off the other sources.
After finding the individual contributions, we can add them up to get the final value of va using the principle of superposition. The final value of va will be the algebraic sum of the individual values.
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High-temperature refrigeration applications will normally provide box temperatures of?
Answers
High-temperature refrigeration applications will normally provide box temperatures of 47 to 60°F.
In the question, asked to specify the range of temperature for High-temperature refrigeration applications for the box.
Refrigerants are the coolants used in refrigeration devices such as ac, refrigerators, etc. Some examples of refrigerant CFCs.
Here, the required range of temperature for High-temperature refrigeration applications varies from 47 to 60°F.
Thus, high-temperature refrigeration applications will normally provide box temperatures of 47 to 60°F.
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What is the importance of food handling machines in food industry (Explain in points).
Answers
Answer:
Explanation:
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Rosie Milojevic, Business Development at iComplied
Answered 3 years ago
For those who run or work in a business that handles food, you understand the importance of food safety and regulation compliance as it pertains to not only to certification and licensing of a company, but also the life or death of those who consume the products. Because food safety is such an important issue, we want to ensure that all companies who work in the production, preparation, or processing of food have the tools and information they need to ensure they are in full compliance 100% of the time. One slip in food safety compliance could cost someone their health or life, and this information spreads mistrust in the general public toward the company who sold the product, and also the entire product across companies throughout an entire country and beyond. So how does each company working with food ensure they comply with each and every food safety regulation? Through excellent auditing tools.
Auditing in Food Safety Must Change
Auditing in food safety compliance is essential in ensuring that all regulations are being complied with. Most auditing practices for major companies are severely out of date. Many rely on several different forms, stacks of paperwork, and data stored on multiple different computers and databases. This is incredibly inefficient, as it can be easy to miss something when comparing one sheet to the next, and paper can easily be lost or destroyed. It is also time consuming for companies to share audits over separate computers and databases, as it must be passed down from one employee to the next. Technology has granted all food safety compliance managers a simple solution. Auditing apps are the new wave solutions for companies who want all of their data stored on one cloud database that is instantly accessible with real-time data for all employees. This means that no one ever gets left out of the loop, and no new information will fall through the cracks.
What is the main purpose of the alternater
Answers
Answer:
to keep the battery charged when the vehicle is running, it also helps the battery keep the electrical components in your vehicle charged
Explanation:
What is best messaging security agent?
Answers
The best messaging security agent is a program or software that is designed to protect your messaging system from various types of security threats.
This can include spam, phishing, and other types of malware. These security agents typically use advanced algorithms and techniques to identify and block potential threats before they can cause harm to your messaging system.
Some of the best messaging security agents on the market today include Symantec Messaging Gateway, Trend Micro Hosted Email Security, and McAfee Email Gateway. These programs offer comprehensive protection against a wide range of security threats, and can help ensure that your messaging system stays safe and secure.
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a 60 cm-long, 3 cm-diameter aisi 1010 steel rod is welded to a furnace wall and passes through 20 cm of insulation before emerging into the surrounding air. the faurnace wall is at 300oc and the air temperature is 20oc. estimate the temperature of the bar tip if the heat transfer coefficient between the rod and air is taken to be 13 w/m2 k.
Answers
We may calculate the temperature of the bar tip using the boundary conditions and the one-dimensional heat conduction equation: q/A = -k(dT/dx).
Which of the following define the one-dimensional heat equation's boundary conditions?Boundary circumstances: Particular actions at x0 = 0 and L: 1. Temperature constant: u(x0,t) = T for t > 0. 2. Insulated end: for t > 0, ux
Q = hA(T s - T air), where (x0,t) = 0
When we combine these equations, we obtain:
(T s - T air) = -(k/h)(dT/dx), where hA(T s - T air)/A = -k(dT/dx).
Assuming that the temperature gradient is constant over the length of the rod and integrating both sides from x = 0 to x = L, we arrive at:
(T s - 20) = -(43.5e-3 / 13)(T s - 300)*0.6 (T s - T air) = -(k/h)(T s - T furnace)*L
Simplifying:
(T s - 20) = -1.008(T s - 300)
T s - 20 = -1.008T s + 302.4 when expanded
When we solve for T s, we obtain T s = 1265.4 K.
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An electrical engineer at GRIDCO is given two separate toolboxes to keep his working tools. The first toolbox has 4 white fuses and 3 black fuses and the second toolbox has 3 white fuses and 5 black fuses. Suppose the engineer select a fuse from the first toolbox and placed unseen in the second toolbox. What is the probability that: (a) the fuse drawn from the second toolbox is black? (B) the fuse drawn from the second toolbox is white? (8) ane is white?
Answers
(a) The probability of drawing a black fuse from the second toolbox is 4/7.
(b) The probability of drawing a white fuse from the second toolbox is 3/7.
(c) The probability that one fuse is white is 27/49.
To calculate the probabilities, we need to consider the number of white and black fuses in each toolbox.
First, let's determine the total number of fuses in each toolbox:
First Toolbox:
Total fuses = 4 white fuses + 3 black fuses = 7 fuses
Second Toolbox:
Total fuses = 3 white fuses + 5 black fuses = 8 fuses
(a) The probability that the fuse drawn from the second toolbox is black:
The probability of drawing a black fuse from the second toolbox depends on the fuse selected from the first toolbox. There are two scenarios to consider:
Scenario 1: The fuse selected from the first toolbox is black.
In this case, the second toolbox will have 3 black fuses remaining out of the total 7 fuses.
Probability = (Number of black fuses in the second toolbox)/(Total number of fuses in the second toolbox)
Probability = 3/7
Scenario 2: The fuse selected from the first toolbox is white.
In this case, the second toolbox will have 5 black fuses out of the total 7 fuses.
Probability = (Number of black fuses in the second toolbox)/(Total number of fuses in the second toolbox)
Probability = 5/7
To calculate the overall probability, we need to consider the probability of each scenario and weigh it by the probability of selecting a fuse of that color from the first toolbox. Since the fuse from the first toolbox has an equal chance of being white or black, we need to take an average of the probabilities in both scenarios.
Probability of drawing a black fuse from the second toolbox = (Probability of scenario 1 + Probability of scenario 2)/2
Probability of drawing a black fuse from the second toolbox = (3/7 + 5/7)/2
Probability of drawing a black fuse from the second toolbox = 8/14
Probability of drawing a black fuse from the second toolbox = 4/7
Therefore, the probability of drawing a black fuse from the second toolbox is 4/7.
(b) The probability that the fuse drawn from the second toolbox is white:
Similarly, we can calculate the probability of drawing a white fuse from the second toolbox. It will be the complement of the probability of drawing a black fuse.
Probability of drawing a white fuse from the second toolbox = 1 - Probability of drawing a black fuse from the second toolbox
Probability of drawing a white fuse from the second toolbox = 1 - 4/7
Probability of drawing a white fuse from the second toolbox = 3/7
Therefore, the probability of drawing a white fuse from the second toolbox is 3/7.
(c) The probability that one is white:
To calculate the probability that one fuse is white, we need to consider both scenarios: either the fuse drawn from the first toolbox is white and the fuse drawn from the second toolbox is black, or the fuse drawn from the first toolbox is black and the fuse drawn from the second toolbox is white.
Scenario 1: Fuse drawn from the first toolbox is white, and the second toolbox has a black fuse:
Probability = (Probability of drawing a white fuse from the first toolbox) * (Probability of drawing a black fuse from the second toolbox)
Probability = (3/7) * (5/7)
Scenario 2: Fuse drawn from the first toolbox is black, and the second toolbox has a white fuse:
Probability = (Probability of drawing a black fuse from the first toolbox) * (Probability of drawing a white fuse from the second toolbox)
Probability = (4/7) * (3/7)
To calculate the overall probability, we need to sum up the probabilities of both scenarios:
Probability that one fuse is white = Probability
of scenario 1 + Probability of scenario 2
Probability that one fuse is white = (3/7) * (5/7) + (4/7) * (3/7)
Probability that one fuse is white = 15/49 + 12/49
Probability that one fuse is white = 27/49
Therefore, the probability that one fuse is white is 27/49.
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A simple dynamic braking system can be created by using a normally closed contact of a large relay and A. Zener regulator B. diode. C. dual SCR. D. power resistor
Answers
A simple dynamic braking system can be created by using a normally closed contact of a large relay and: D) power resistor.
Dynamic braking is a method used to slow down or stop a motor or other rotating equipment by converting the mechanical energy into electrical energy. In this process, the electrical energy is dissipated as heat.
Using a normally closed contact of a large relay, the circuit can be configured in such a way that when the motor is not energized, the normally closed contact is closed. This allows current to flow through the circuit, including a power resistor.
A power resistor is a component specifically designed to handle high power dissipation.
When the motor is operating and the power is disconnected, the dynamic braking system activates by opening the contact of the large relay, thereby connecting the power resistor in parallel with the motor.
As a result, the energy generated by the motor's deceleration is dissipated in the form of heat through the power resistor, effectively braking the motor.
The other options listed (A. Zener regulator, B. diode, C. dual SCR) are not commonly used components in a simple dynamic braking system.
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In what way is a parallel circuit different from a series circuit?
Answers
freshdirect's gives them a competitive advantage related to data which their rivals cannot match
Answers
FreshDirect has a competitive advantage when it comes to data which their rivals cannot match. FreshDirect has been using data analytics for more than a decade now to optimize their operations, improve customer experiences, and offer customized product recommendations. FreshDirect is known for its high level of customer service, which is due in part to its sophisticated data systems that help it anticipate and respond to customer needs quickly and effectively.
They can also monitor customer behavior in real-time to identify trends and preferences, which helps them tailor their product offerings and marketing campaigns to better appeal to customers. FreshDirect has also invested heavily in its supply chain, which is another area where data analytics can be extremely valuable. By using data analytics to track inventory levels, optimize delivery routes, and monitor supplier performance, FreshDirect is able to maintain a high level of operational efficiency and offer a wider range of products to customers. In conclusion, FreshDirect's investment in data analytics gives them a competitive advantage that their rivals cannot match.
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3. An ideal Otto engine, operating on the hot-air standard with k=1.34, has a compression ratio of 5. At the beginning of compression the volume is 6ft3 , the pressure is 13.75 psia and temperature is 100F. during constant - volume heating, 350 Btu are added per cycle. Compute T3,P3,T3, QA, QR, Wnet, thermal Efficiency, and mean effective pressure.
Answers
Given data: Compression ratio = V1/V2 = 5The initial volume of the engine = V1 = 6ft3Pressure at the beginning of compression = P1 = 13.75 psia.
Volume at the end of compression V2 = V1/r = 6/5 = 1.2 ft3Using the ideal gas equation, PV = mRT1 => P1V1 = mR(T1+460)where m is the mass of the air, R is the gas constant of air, T1 is the temperature in Fahrenheit.Rearranging and substituting the values;`m = P1V1/R(T1+460)` = (13.75 x 6) / (53.35 x (100+460)) = 0.0333 lbmCalculating the temperature and pressure at the end of the isentropic compression;P2V2^k = P1V1^kSince the process is adiabatic, PV^k = constant. Therefore;T2 = T1 * r^(k-1) = 100 * 5^(1.34-1) = 831.3 FT2/P2 = T1/P1 * r^(k) = 100/13.75 * 5^(1.34) = 170.6 F / 92.65 psiaDuring the constant volume heating process, the pressure and temperature of the air increase from (P2, T2) to (P3, T3).
The heat added to the air during the constant volume heating is rejected during the isentropic expansion process.Q1V = mCv(T3-T2) = mCv(T3-T4)where T4 is the temperature at the end of the expansion process.T4 = T1 * r^(k-1) = 100 * 5^(1.34-1) = 831.3 FQA = Q1V = mCv(T3-T4) = 0.0333 x 133.38 x (2260-831.3) = 35680.14 BtuThe compression work Wc = mCv(T2-T1) = 0.0333 x 133.38 x (831.3-100) = 3577.58 BtuThe expansion work We = mCv(T3-T4) = 0.0333 x 133.38 x (2260-831.3) = 35680.14 BtuTherefore, Wnet = We - Wc = 35680.14 - 3577.58 = 32102.56 BtuThe thermal efficiency is given by;η = Wnet/Q1V = 32102.56/350 = 91.72%The mean effective pressure (MEP) is given by;MEP = Wnet/V1(V2/r - V1) = 32102.56/6(1.2/5 - 1) = 148.1
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The main target of the diplexer is to enable the antenna to work at different frequencies. *
True
False
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True is the answer.....
Question 18 of 25
If you see an increase in traffic, step in and direct traffic to ensure safety. Is this a
safe or unsafe practice?
Select the best option.
O
Safe
Unsafe
Answers
We are required to explain if it is safe or unsafe to see an increase in traffic, step in and direct traffic to ensure safety.
Increase in traffic is the high influx of vehicles on the road. This means the number of vehicles using the road at a particular time is much. Traffic causes slow movement of vehicles and lack of patient of drivers could lead to accident.It is safe to direct traffic when there is an increase in traffic if you are a professional traffic worker. Meanwhile, it is very unsafe for a person who is not a professional traffic worker to direct traffic.Therefore, it is encouraged for only traffic officials to direct traffic.
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Answer:
Unsafe
Explanation:
Consider the products you use and the activities you perform on a daily basis. Describe three examples that use both SI units and customary units for measurement.
Answers
Answer: Three examples of activities that I can perform on a daily basis that involves both metric units (SI units) and customary units include: measuring the length of a door using a tape measure, which includes both SI units and customary units (like feet, inches, and centimeters); baking a cake that requires one teaspoon (customary unit) of baking soda, which could also be converted into four grams (SI unit); weighing myself on a weighing scale, which can be measured by pounds (customary unit) or kilograms (metric unit).
Explanation: I big brain :) (Not Really I Just Wanted To Help) I hope this helped! ;)
Three activities that I can do on a daily basis that involve both metric units (SI units) and customary units are: measuring the length of a door with a tape measure, which includes both SI units and customary units (like feet, inches, and centimeters); baking a cake that calls for one teaspoon (customary unit) of baking soda, which can also be converted to four grams (SI unit); and weighing myself on a weighing scale, which can be measured in pound and kilogram (metric unit).
Refrigerant-134a at 1 MPa and 100 C is to be cooled to 1 MPa and 28 C in a condenser by air. The air enters at 125 kPa and 25 C with a mass flow rate of 697 kg/min and leaves at 97 kPa and 58 C. Determine the mass flow rate of the refrigerant. Assume air has a constant heat capacity determined at room temperature. Report the mass flow rate of the refrigerant in kg/min with one decimal digit, for example 95.3 or 105.6.
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A sewage lagoon that has a surface area of 10 ha and a depth of 1 m is receiving 8,640 m^3 /d of sewage containing 100 mg/L of biodegradable contaminant. At steady state, the effluent from the lagoon must not exceed 20 mg/L of biodegradable contaminant. Assuming the lagoon is well mixed and that there are no losses or gains of water in the lagoon other than the sewage input, what biodegradation reaction rate coefficient (d^-1) must be achieved for a first-order reaction?
Answers
The mass balance equation for the sewage lagoon can be expressed as:
Qin x Cin = Qout x Cout + V x R
Where:
Qin = influent flow rate = 8,640 m^3/d
Cin = influent concentration of biodegradable contaminant = 100 mg/L
Qout = effluent flow rate = Qin (since there are no losses or gains of water)
Cout = effluent concentration of biodegradable contaminant = 20 mg/L (maximum allowable concentration)
V = volume of lagoon = 10 ha x 10,000 m^2/ha x 1 m = 100,000 m^3
R = biodegradation reaction rate (kg/m^3/d) x density of water = k x Cin
Assuming a first-order reaction, the biodegradation rate can be expressed as:
R = k x Cin
Substituting the values in the mass balance equation and rearranging:
k = (Qin x (Cin - Cout)) / (V x Cin)
k = (8,640 m^3/d x (100 mg/L - 20 mg/L)) / (100,000 m^3 x 100 mg/L)
k = 0.0691 d^-1
Therefore, the biodegradation reaction rate coefficient that must be achieved for a first-order reaction is 0.0691 d^-1.
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name three types of resistors and where it is best applied at.
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Answer:
Fixed, Variable, Linear and Non-Linear Resistors & Applications
Explanation:
a what type of contact is used with the High pressure switch?
Answers
A printers display shows no reading the problem might be
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Put your printer through a hard reset. Try turning off both the printer and your computer, then restarting both if that doesn't fix the problem. Then try to remove and reinstall your printer's driver.
What causes printing errors?A problem with the printer itself may exist if the status of your printer reads "Printer in error state." Check to see if the printer is on and wired or wirelessly linked to your computer. Make sure the cover is closed and the paper isn't jammed, and check if there isn't enough paper or ink.
Of all printer errors, paper jams are arguably the most dreadful. There are a few problems that might be present when it comes to smudges, faded lettering, and poor image quality.
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A Newtonian liquid flows in the annular space between to fixed horizontal concentric cylinders. The radius of the inner cylinder is ri and the outer cylinder is ro. Two static pressure taps separated by a distance L along the outer pipe are connected to a manometer with reading of h. Develop an expression for the shear stress on the inner and outer cylinder walls as a function of h. Assume the flow is fully developed and laminar.
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Answer:
See explaination
Explanation:
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concentration polarization arises during fluid ultrafiltration when high molecular weight proteins accumulate near the membrane surface because the membrane restricts transport.
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Concentration polarization arises during fluid ultrafiltration when high molecular weight proteins accumulate near the membrane surface because the membrane restricts transport. This occurs due to the following steps:
1. During ultrafiltration, fluid containing proteins is forced through a semi-permeable membrane under pressure.
2. The membrane selectively allows smaller molecules (such as water and solutes) to pass through, while restricting the transport of larger molecules, such as high molecular weight proteins.
3. As the fluid passes through the membrane, the concentration of high molecular weight proteins near the membrane surface increases, as they are unable to cross the membrane.
4. This accumulation of proteins leads to a concentration gradient, with a higher concentration of proteins near the membrane surface compared to the bulk fluid. This gradient is referred to as concentration polarization.
5. Concentration polarization can reduce the efficiency of ultrafiltration, as it increases the resistance to fluid flow through the membrane, and may also lead to fouling or clogging of the membrane pores by the accumulated proteins.
concentration polarization arises during fluid ultrafiltration when high molecular weight proteins accumulate near the membrane surface because the membrane restricts transport. While an exact solution can found by numerical integration explain the process theoretically .
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