Answer:
a. acute triangle (all the angles measure less than 90 degrees)
b. scalene triangle (none of the angles are congruent, so none of the sides are congruent)
Vectors: Find the vector from the point A=(−1,−7,3) to the point B=(3,−2,9).
AB→=
Equations of lines: Consider the vector equation of the line through the two points listed above. For each equation listed below, answer T if the equation represents the line, and F if it does not.
Here is the list of questions:
1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉
2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉
3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉
4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉
5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉
Answer:
\(\overrightarrow {AB} = (4,5,6)\)
1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F
2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F
3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T
4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F
5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F
Step-by-step explanation:
The vector AB is the vectorial difference between point A and B, that is:
\(\overrightarrow {AB} = \vec B - \vec A\)
Given that \(\vec A = (-1,-7,3)\) and \(\vec B = (3,-2,9)\), the vector AB is:
\(\overrightarrow {AB} = (3,-2,9)-(-1,-7,3)\)
\(\overrightarrow{AB} = (3-(-1),-2-(-7),9-3)\)
\(\overrightarrow {AB} = (4,5,6)\)
The vectorial equation of the line is represented by:
\(\langle x, y, z\rangle = \vec A + t \cdot \overrightarrow {AB}\)
Where \(t\) is the parametric variable, dimensionless. Given that \(\vec A = (-1,-7,3)\) and \(\overrightarrow {AB} = (4,5,6)\)
\(\langle x,y,z \rangle = \langle -1,-7,3 \rangle + t\cdot \langle 4,5,6 \rangle\)
Finally, the list of questions are now checked:
1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F
2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F
3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T
4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F
5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F
Which statement is true of the function f(x) = Negative RootIndex 3 StartRoot x EndRoot? Select three options.
The function is always increasing.
The function has a domain of all real numbers.
The function has a range of {y|–Infinity < y < Infinity}.
The function is a reflection of y = .
The function passes through the point (3, –27).
The ratio of people who saw a comedy movie to people who saw a documentary movie at the movie theater was 9 to 2. Of the people who saw a comedy movie, 25% of them spent more than $10 at the concession stand. If 176 people saw either a comedy or documentary at the theater last night, how many of the people who saw a comedy spent less than or equal to $10 at the concession stand?
The number of people who saw a comedy and spent less than or equal to $10 at the concession stand is 108.
How many people saw a comedy and spent less than $10?The first step is to determine the number of people would watched comedy.
Number of people who watched comedy = (ratio of people who watched comedy / sum of ratios) x total number of people
Sum of ratios = 2 + 9 = 11
Number of people who watched comedy = (9/11) x 176 = 144
Number of people who saw a comedy and spent less than $100 = percentage of people who spent less than $100 x number of people who watched a comedy
Number of people who saw a comedy and spent less than $100 = (1 - 0.25) x 144
Number of people who saw a comedy and spent less than $100 = 0.75 x 144 = 108
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What actions or steps in Excel can you take to rank them from 1st to 10thWhat actions or steps in Excel can you take to rank them from 1st to 10th
Answer:
i dont know sorry
Step-by-step explanation:
sorry hdhrhfjbdhehrhdve
find X in this problem
please help
The value of x when two chords of the circle intersect is x = 16.
What are chords of the circle?The line segment connecting any two locations on a circle's circumference is referred to as the chord of the circle. It should be noted that the diameter is the circle's longest chord, which runs through its center.
The longer chord subtends a greater angle at the center of the circle if we attempt to establish a relationship between different chords and the angle subtended by them there.
The angle CED is formed by the intersection of two chords in the circle.
The measure of angle CED is given as:
Angle CED = 1/2(DC + AB)
Angle CED = 1/2(152 + 78)
Angle CED = 1/2 (230)
Angle CED = 115
Now, Angle CED is given as:
Angle CED = 7x + 3
Substituting the value we have:
115 = 7x + 3
112 = 7x
x = 16
Hence, the value of x when two chords of the circle intersect is x = 16.
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Find x. √11 X = √17 VIRI X
1.243 is the measure of the value of x from the given expression
Solving rational equationsRational equations are those that contain rational expressions. A rational expression is a fraction with polynomial numerator and denominator. A rational expression, in other terms, is a ratio between two polynomials.
Given the following rational equation
√11 x = √17
We need to determine the measure of the value of x.
Taking the square of both sides we will have:
(√11 x)² = (√17)²
11x² = 17
x² = 17/11
x² = 1.545
Take the square root of both sides
√x² = √1.545
x = 1.243
Hence the measure of the value of x from the given equation is 1.243.
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I will give brainiest to whoever answers correctly !!
Answer:
275 days
Step-by-step explanation:
From August 21 to May 23, there is 275 days!
How many 11-card hands are possible with a 20-card deck?
There is only 1 possible 11-card hand that can be formed from a 20-card deck.
To determine the number of 11-card hands possible with a 20-card deck, we can use the concept of combinations.
The number of combinations, denoted as "nCk," represents the number of ways to choose k items from a set of n items without regard to the order. In this case, we want to find the number of 11-card hands from a 20-card deck.
The formula for combinations is:
nCk = n! / (k!(n-k)!)
Where "!" denotes the factorial of a number.
Substituting the values into the formula:
20C11 = 20! / (11!(20-11)!)
Simplifying further:
20C11 = 20! / (11! * 9!)
Now, let's calculate the factorial values:
20! = 20 * 19 * 18 * ... * 2 * 1
11! = 11 * 10 * 9 * ... * 2 * 1
9! = 9 * 8 * 7 * ... * 2 * 1
By canceling out common terms in the numerator and denominator, we get:
20C11 = (20 * 19 * 18 * ... * 12) / (11 * 10 * 9 * ... * 2 * 1)
Performing the multiplication:
20C11 = 39,916,800 / 39,916,800
Finally, the result simplifies to:
20C11 = 1
Consequently, with a 20-card deck, there is only one potential 11-card hand.
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Which substance has a freezing point furthest from that of water, 0°C?
Iodine 113.5
Carbon Dioxide −78.7
Mercury −39
Glycerine 17.7
Nitrogen −210
Answer:
The freezing point of water at a pressure of one atmosphere is 0°C (32°F); that of liquid nitrogen is -209.89°C (-345.8°F).
if a number is increased by 20% then the number is 24 find the number
Answer:
20
Step-by-step explanation:
x+20%=24 x+x*20/100=24 x+0.2x=24 1.2x=24 x=24/1.2 x=20Which best compares the volumes of the two cylinders? Geometry
Answer:
The correct answer would be C
Step-by-step explanation:
please mark brainliest
The choice which best compares the volume of the cylinders is; Choice B; The volume of cylinder B is the same as that of cylinder A.
Which best compares the volumes of the two cylinders?From geometry, It can be concluded that the volume of a solid shape is the product of its cross sectional area and the height over which the area spans. On this note, since the volume of a cylinder is dependent on the radius and height of the cylinder, both cylinders have equal volumes.
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40 POINTS!!!
Two construction companies are building homes in a new neighborhood. Company A has built 18 homes and plans to build an additional 6 homes each month. Company B has built 41 homes and plans to build an additional 4 homes each month. if building goes according to their plans, in how many months will the total number of homes built by the companies be equal to each other?
Answer:
14 months until there equal
Answer:
14 months
Step-by-step explanation:
chau made $270 for 18 hours of work. At the same rate, how many hours would he have to work to make $105
Answer:
7 hours
Step-by-step explanation:
here,
270/18=105/x
x=(105*18)/270
x=7
Chau made $270 for 18 hours of work. At the same rate, Therefore Chau would have to work 7 hours at the same rate to make $105.
To find out how many hours Chau would have to work to make $105 at the same rate, we can set up a proportion using the given information:
Let x be the number of hours Chau needs to work to make $105.
We know that Chau made $270 for 18 hours of work, so the rate of earnings per hour is:
Rate = Total earnings / Number of hours
Rate = $270 / 18 hours
Rate = $15 per hour
Now, we can set up the proportion:
$15 per hour = $105 / x hours
To find x, we can cross-multiply:
$15 × x = $105
Now, solve for x:
x = $105 / $15
x = 7 hours
So, Chau would have to work 7 hours at the same rate to make $105.
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Solve the following system of equations a2+b2 ; 3a2 -2ab-b2
The system has an infinite number of solutions, but the only solution is (a, b) = (0, 0).
The given system of equations can be solved using the substitution method. We can begin by solving the first equation,\(a^2 + b^2\), for either a or b. Let's solve for a:
\(a^2 + b^2 = 0\)
\(a^2 + b^2 = 0\)
\(a^2 = -b^2\)
\(a = \pm\sqrt(-b^2)\)
We can substitute this expression for a into the second equation, \(3a^2 - 2ab - b^2 = 0\), and simplify:
\(3(\pm\sqrt(-b^2))^2 - 2(\pm\sqrt(-b^2))b - b^2 = 0\)
\(3b^2 - 2b^2 - b^2 = 0\)
0 = 0
Since 0 = 0, this means that the system of equations has an infinite number of solutions. In other words, any values of a and b that satisfy the equation \(a^2 + b^2 = 0\) will also satisfy the equation \(3a^2 - 2ab - b^2 = 0\)
However, the equation \(a^2 + b^2 = 0\) only has a single solution, which is a = b = 0. Therefore, the solution to the system of equations is (a, b) = (0, 0).
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Simplify. Leave your answer as a fraction.
Answer:
3/4, 6/8
Step-by-step explanation:
12/4 is 3. 16/4 is 4, repeat for the other one with the number 3
Answer: 5/3
Step-by-step explanation:
When dividing a fraction by another fraction, you multiply it by the reciprocal
5/2 x 4/6 =20/12 which when simplified is 5/3
Mrs. Taylor caught 6 bats in her attic in 12
minutes. How long would it take to catch 5 bats?
21x + 7
22x + 2
180
Answer:
x = 5
Explanation:
If the angle are parallel:
step 1:
21x + 7 = 22x + 2
21x - 22x = 2 -7
-x = -5
x = 5
finding upper angle, then when both lies on straight line equals to 180°
step 2:
180 = (180 - 22x - 2 ) + 21x + 7
180 = 180 - 2 + 7 - 22x + 21x
180 = -x 185
-5 = -x
x = 5
Solution:
Note that:
21x + 7 = 22x + 2 (Vertically opposite angles)Solve the equation to find the value of x.
21x + 7 = 22x + 2=> -2 + 7 = 22x - 21x=> 5 = xThe value of x is 5.
explain how to use compensation to find 3x390
The value of the given expression is 1170.
Important information:
The given expression is \(3\times 390\).Compensation:We have,
\(3\times 390\)
The number 390 can be written as \(400-10\). So,
\(3\times 400=1200\)
\(3\times 10=30\)
Now, subtract 30 from 1200.
\(1200-30=1170\)
Thus, the value of the given expression is 1170.
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What’s the answer for these two
The amount freedome ride charge more than Envo car in d miles is $20.05
What is word problem?word problem is a math problem written out as a short story or scenario. Basically, it describes a realistic problem and asks you to imagine how you would solve it using math. If you've ever taken a math class, you've probably solved a word problem.
The total charge for Enzo car =$50.50 +8¢ = $50.50 + $0.08 = $50.58
The total charge for Freedom = $70.50 + 12¢
= $70.50 + $0.12
= $70.62
therefore in d miles ;
Enzo will charge $50.58d
freedome will charge
$70.62d
therefore the amount freedome will charge more than Enzo car is $70.62 - $50.58
= $20.05
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Correct answer please
Answer:
50.75
Step-by-step explanation:
We have:
\(E[g(x)] = \int\limits^{\infty}_{-\infty} {g(x)f(x)} \, dx \\\\= \int\limits^{1}_{-\infty} {g(x)(0)} \, dx+\int\limits^{6}_{1} {g(x)\frac{2}{x} } \, dx+\int\limits^{\infty}_{6} {g(x)(0)} \, dx\\\\= \int\limits^{6}_{1} {g(x)\frac{2}{x} } \, dx\\\\=\int\limits^{6}_{1} {(4x+3)\frac{2}{x} } \, dx\\\\=\int\limits^{6}_{1} {(4x)\frac{2}{x} } \, dx + \int\limits^{6}_{1} {(3)\frac{2}{x} } \, dx\\\\=\int\limits^{6}_{1} {8} \, dx + \int\limits^{6}_{1} {\frac{6}{x} } \, dx\\\\\)
\(=8\int\limits^{6}_{1} \, dx + 6\int\limits^{6}_{1} {\frac{1}{x} } \, dx\\\\= 8[x]^{^6}_{_1} + 6 [ln(x)]^{^6}_{_1}\\\\= 8[6-1] + 6[ln(6) - ln(1)]\\\\= 8(5) + 6(ln(6))\\\\= 40 + 10.75\\\\= 50.74\)
1. Quadratics.
The path of the longest shot put by the Women's track team at Sun Devil U is modeled by h(x) = -0.017x² + 1.08x + 5.8, where x represents the horizontal distance from the start and h(x) is the height of the shot put above the ground. (Both x and h(x) are measured in feet.)
a. 4 points. Determine h(24). Round your answer to 2 decimal places. Then explain what your answer means in the context of the problem. ("In the context of the problem" means "in terms of the shot put's horizontal distance from the start and in terms of the height of the shot put above the ground.")
b. 4 points. Determine the numerical value of the vertical intercept and explain what this means in the context of the problem.
c. 4 points. Determine the numerical values of the vertex coordinates and explain what they mean in the context of the problem.
d. 4 points. How far from the start did the shot put strike the ground? Round your answer to 2 decimal places.
h(24) = 21.93, vertical intercept is 5.8, (31.76,22.95) are the vertex coordinates and the distance traveled by the shot is 73.49 feet given the equation of the path of the longest shot h(x) = -0.017x² + 1.08x + 5.8. This can be obtained by understanding the concepts of graph function.
What is the value of h(24)?Given,
h(x) = -0.017x² + 1.08x + 5.8
Put h = 24,
h(24) = -0.017(24)² + 1.08(24) + 5.8
h(24) = -9.792 + 25.92 + 5.8
h(24) = 21.93
The height of the shot put above the ground is 21.93 feet when the shot is 24 feet horizontally from the start.
What is the value of the vertical intercept?Vertical intercept, x = 0
h(0) = -0.017(0)² + 1.08(0) + 5.8
h(0) = 5.8
The height of the shot put above the ground is 5.8 feet at the start.
What is the values of the vertex coordinates?vertex coordinates,
(h,k) = [(-b/2a),-(b²- 4ac)/4a]
(h,k) = [(-1.08/2(-0.017)),-((1.08)²- 4(-0.017)(5.8))/4(-0.017)]
(h,k) = [(1.08/0.034),(1.5608)/0.068)]
(h,k) = (31.76,22.95)
The maximum height attained by the shot is 22.95 feet when it is horizontally 31.76 feet away from the start.
How far from the start did the shot put strike the ground?Put h(x) = 0,
-0.017x² + 1.08x + 5.8 = 0
Use quadratic formula for solving x,
x = (-b±√b²- 4ac)/2a
Here a = -0.017, b=1.08, c=5.8
x = [-1.08±√1.08²- 4(-0.017)(5.8)]/(2×-0.017)
x = [-1.08±√1.5608]/-0.034
x = [-1.08-1.2493]/-0.034 and x = [-1.08+1.2493]/-0.034
x = 68.509 and x = - 4.98
Distance between (68.509,0) and (- 4.98,0) = √[68.509 -(- 4.98)]² + (0-0)²
= √73.49²
= 73.49 feet
Hence h(24) = 21.93, vertical intercept is 5.8, (31.76,22.95) are the vertex coordinates and the distance traveled by the shot is 73.49 feet given the equation of the path of the longest shot h(x) = -0.017x² + 1.08x + 5.8.
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A bank account earns a fixed rate of interest compounded quarterly (every 3 month)
Answer:
Here’s what I got.
Hope it helps.
100 POINTS AND BRAINLIST
Answer:
B = 40°
a = 32.2
c = 42.0
Step-by-step explanation:
Interior angles of a triangle sum to 180°.
\(\implies B=180^{\circ}-90^{\circ}-50^{\circ}\)
\(\implies B=40^{\circ}\)
\(\boxed{\begin{minipage}{7.6 cm}\underline{Sine Rule} \\\\$\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}$\\\\\\where:\\ \phantom{ww}$\bullet$ $A, B$ and $C$ are the angles. \\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides opposite the angles.\\\end{minipage}}\)
Given values:
A = 50°B = 40°C = 90°b = 27Substitute the given values into the formula:
\(\implies \dfrac{a}{\sin 50^{\circ}}=\dfrac{27}{\sin 40^{\circ}}=\dfrac{c}{\sin 90^{\circ}}\)
Solve for a:
\(\implies \dfrac{a}{\sin 50^{\circ}}=\dfrac{27}{\sin 40^{\circ}}\)
\(\implies a=\dfrac{27\sin 50^{\circ}}{\sin 40^{\circ}}\)
\(\implies a=32.2 \;\; \sf (nearest\;tenth)\)
Solve for c:
\(\implies \dfrac{27}{\sin 40^{\circ}}=\dfrac{c}{\sin 90^{\circ}}\)
\(\implies c=\dfrac{27\sin 90^{\circ}}{\sin 40^{\circ}}\)
\(\implies c=42.0 \;\; \sf (nearest\;tenth)\)
Answer:
B = 40°
A = 32.2
C = 42.0
Step-by-step explanation:
you want to visually compare the bivariate relationships that exist among 8 different continuous variables. true or false
The statement is visually compares the bivariate relationships that exist among 8 different continuous variables. The statement is false.
What is a variable?
A symbol (often a letter) used in algebra to represent an unknowable numerical value in an equation. X and Y (real-number unknowns), z (complex-number unknowns), t (time), r (radius), and s are examples of frequently used variables (arc length).
Data with only one variable: The prefix uni and the word variate both denote one. This describes a situation when only one variable is looked at or discussed. For instance, as the only variable of interest, a researcher might track how long it takes people to finish a crossword puzzle.
Bi means two, as in bivariate data. Bivariate data therefore includes analysing and contrasting two distinct variables. For instance, a researcher might time how long it takes individuals to do a crossword puzzle while also gauging their stress levels. In this case, the researcher is looking at two variables: time and stress.
Thus it is impossible to visually compare the bivariate relationships.
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How easy is to teach and learn fractions. Motivate your answer.
Teaching and learning fractions can be relatively easy or challenging depending on various factors such as the grade level of the learner, the teaching methods used, the learning environment, and the learner's prior knowledge. However, with effective teaching strategies and consistent practice, fractions can be easily taught and learned.
Here are some factors that make fractions easy or challenging to teach and learn:
1. Conceptual Understanding: Fractions are easier to learn when students have a solid conceptual understanding of the concept. They need to understand that fractions represent a part of a whole or a quantity and that fractions can be expressed as decimals or percentages. Teachers can use visual aids such as fraction circles, number lines, and charts to help students grasp the concept.
2. Age and Grade Level: Teaching and learning fractions is easier at lower grade levels when students are introduced to fractions in a concrete way, such as dividing objects into equal parts. As students progress to higher grade levels, fractions become more abstract and complex, making them more challenging to learn.
3. Instructional Methods: Effective teaching methods that make use of real-world examples, hands-on activities, and interactive learning strategies help to make fractions more accessible and understandable. Teachers can also use online resources and educational apps to support student learning.
4. Learning Environment: A positive and supportive learning environment can make a significant difference in how easily students learn fractions. Teachers can create an environment that encourages participation and risk-taking, provides opportunities for students to work collaboratively, and celebrates student success.
In summary, teaching and learning fractions can be easy or challenging depending on various factors, including conceptual understanding, age and grade level, instructional methods, and learning environment. However, with effective teaching strategies and consistent practice, fractions can be easily taught and learned.
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Find the exponential function of the 2 points (3, 7) and (5, 63). Use
the formula f(x) = a(b)”.
Answer:
We obtained the two exponential functions:
\(y\:=\:\frac{7}{27}\left(3\right)^x\)\(y\:=-\:\frac{7}{27}\left(-3\right)^x\)Step-by-step explanation:
As we know that the exponential function is of the form
f(x) = abˣ
Given the points
(3, 7)(5, 63)We know these points belong to the exponential function.
so substituting the values (3, 7) and (5, 63) in the function
putting (3, 7)
y = abˣ
7 = ab³
also putting (5, 63)
y = abˣ
63 = ab⁵
Considering the 2nd equation
63 = ab⁵
as
\(a^b\times \:a^c=a^{b+c}\)
so
63 = ab³×b²
substituting 7 = ab³ in 63 = ab³×b²
63 = 7 × b²
b² = 63/7
b² = 9
b = ± 3
If b = 3
plug in b = 3 in the equation 7 = ab³ to find the value 'a'
7 = ab³
7 = a(3)³
7 = a × 27
a = 7/27
so, a = 7/27 and b = 3 would give us the function
y = abˣ
\(y\:=\:\frac{7}{27}\left(3\right)^x\)
if b = -3
plug in b = -3 in the equation 7 = ab³ to find the value 'a'
\(\:7\:=\:a\left(-3\right)^3\)
\(a\left(-27\right)=7\)
\(a=-\frac{7}{27}\)
so, a = -7/27 and b = -3 would give us the function
y = abˣ
\(y\:=-\:\frac{7}{27}\left(-3\right)^x\)
Thus, we obtained the two exponential functions:
\(y\:=\:\frac{7}{27}\left(3\right)^x\)\(y\:=-\:\frac{7}{27}\left(-3\right)^x\)Which inequality is represented by the number line? A. |2x + 1| ≥ 7 B. 2|x + 1| ≤ 8 C. |2x − 1| ≥ 9 D. 2|x − 1| ≤ 10
The inequality which can bee represented on the number line.
B. 2|x + 1| ≤ 8
D. 2|x − 1| ≤ 10
Given, the inequalities are:
A. |2x + 1| ≥ 7
2x+1≥7 or -2x-1≥7
2x≥7-1 or -2x≥7+1
2x≥6 or -2x≥8
x≥6/2 or x≤-8/2
x≥3 or x≤-4
therefore, (-∞,-4]∪[3,∞)
hence this inequality cannot be represented on the number line.
B. 2|x + 1| ≤ 8
2x+2≤8 or -2x-2≤8
2x≤8-2 or -2x≤8+2
2x≤6 or -2x≤10
x≤3 or x≥-5
-5≤x≤3
[-5,3]
hence this inequality can be represented on the number line.
C. |2x − 1| ≥ 9
2x-1≥9 or -2x+1≥9
2x≥9+1 or -2x≥9-1
2x≥10 or -2x≥8
x≥5 or x≤-4
(-∞,-4]∪[5,∞)
hence this inequality cannot be represented on the number line.
D. 2|x − 1| ≤ 10
2x-2≤10 or -2x+2≤10
2x≤10-2 or -2x≤10+2
2x≤8 or -2x≤12
x≤4 or x≥-6
-4≤x≤6
[-5,3]
hence this inequality can be represented on the number line.
Hence we get the required results.
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The histograms display the frequency of temperatures in two different locations in a 30-day period.
A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 14. A shaded bar stops at 10 above 60 to 69, at 9 above 70 to 79, at 5 above 80 to 89, at 4 above 90 to 99, and at 2 above 100 to 109. There is no shaded bar above 110 to 119. The graph is titled Temps in Sunny Town.
A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 16. A shaded bar stops at 2 above 60 to 69, at 4 above 70 to 79, at 12 above 80 to 89, at 6 above 90 to 99, at 4 above 100 to 109, and at 2 above 110 to 119. The graph is titled Temps in Desert Landing.
When comparing the data, which measure of center should be used to determine which location typically has the cooler temperature?
Median, because Desert Landing is symmetric
Mean, because Sunny Town is skewed
Mean, because Desert Landing is symmetric
Median, because Sunny Town is skewed
The answer is C. Mean, because Desert Landing is symmetric.
What is distributions?A distribution refers to the pattern of how data is spread out or distributed across different values or intervals. It is a way to describe and analyze the shape, center, and spread of a set of data.
According to question:To determine the location with the most consistent temperature, we need to measure the variability of the temperature data in both locations. The measure of variability that is appropriate for this purpose is the Mean, which measures the spread of the middle of the data.
The answer is C. Mean, because Desert Landing is symmetric. depending on the shape of the distributions. If the temperature data in Desert Landing is symmetric, then the Mean would be appropriate to measure the spread of the data. If the temperature data in Sunny Town is skewed, then the Mean would also be appropriate to measure the spread of the data. However, if the temperature data in either location is not skewed, then the range would not be an appropriate measure of variability.
To know more about distributions visit:
brainly.com/question/14697580
Is There only one way to solve a equation, and if so please support your thinking.
Answer:
No
Step-by-step explanation:
Theirs always multiple ways to solve something, even if their is only one way to solve it. We all think things through differently
6y+2=-2(2y-1) help pls.
Answer:
y=0
Step-by-step explanation:
6y+2=-2(2y-1)
Distribute
6y+2 = -4y +2
Add 4y to each side
6y+2 = -4y +2+4y
6y +2 =2
Subtract 2 from each side
6y +2-2 = 2-2
6y = 0
y=0