The amplitude of a wave is it's _________ or energy

If ethanol was used to measure the density of the irregular objects, it would not have affected the results at all.

The volume of irregular objects is obtained by displacement method. A known volume of a liquid is measured out and added to a measuring cylinder.

The irregular solid is now added to the set up and the change in volume is noted. This change in volume corresponds to the volume of the object.

If the mass of the irregular object has been previously determined, the density of the object is:

Density = mass/volume

The kind of liquid (ethanol or water) used to determine the density does not affect the results.

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The best alternative to using latex-free gloves when handling ready-to-eat food is using nitrile gloves.

Nitrile gloves are a suitable alternative to latex gloves for handling ready-to-eat food. Nitrile is a synthetic material that offers similar benefits to latex in terms of flexibility and dexterity. Nitrile gloves are also resistant to punctures and chemicals, providing a protective barrier against potential contamination. Moreover, nitrile gloves are considered hypoallergenic and do not cause the same allergic reactions as latex gloves, making them safe for individuals with latex allergies or sensitivities.

When handling ready-to-eat food, it is crucial to maintain hygiene and prevent cross-contamination. Wearing gloves is an important practice to minimize the risk of transmitting harmful microorganisms. By choosing nitrile gloves as an alternative to latex gloves, one ensures the safety of individuals who may be allergic to latex while maintaining the necessary level of protection when handling food. Nitrile gloves are widely available and commonly used in food handling settings, making them a suitable and reliable choice for ensuring food safety and hygiene.

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HCI + NaOH --> NaCl + H2O

Neutralization reaction is the reaction between acid and base which results in formation of salt and water. Here salt is NaCl (common salt) in above reaction.

SO, (A) H20 + NaCl is your answer.

Answer:

I think that it is related to the orbitals and the electron pairs in each atom.

try reading about "Vsepr" theory

A titration is an experiment where a volume of a solution of known concentration is added to a volume of another solution in order to determine its concentration. Many titrations are acid-base neutralization reactions, though other types of titrations can also be performed.Aug 12,

The particle that makes the atom an unstable isotope is the neutron. When there is an excess or a deficiency of neutrons in an atom's nucleus, it becomes an unstable isotope.

Unstable isotopes are isotopes that decay and emit radiation until they reach a stable state. They are also known as radioactive isotopes. The radioactive isotopes are unstable and have an unpredictable lifespan because they have an unstable ratio of neutrons to protons. This excess of neutrons in the nucleus results in a greater electrostatic repulsion between protons, causing instability and eventually decay.Neutrons are the particles that are responsible for making atoms unstable isotopes. The excess or deficiency of neutrons in an atom's nucleus leads to an unstable state and eventually decay. Radioactive isotopes are important for various practical applications such as nuclear power, radiography, and cancer treatment.

Therefore, neutrons makes the atom an unstable isotope. The decay of unstable isotopes can be used for many practical applications such as nuclear power, radiography, and cancer treatment.

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Answer:

The correct answer is - the control group.

Explanation:

The control group is one of two groups that are present in any investigation or experiment which is not getting any treatment as the experimental group gets. It remains constant or in natural conditions instead of influenced by any treatment or factor.

An experimanetal group that is manipulated by the researcher by the independent variable is compared to The control group to see the differences developed by the manipulation or influence.

The molecular solid naphthalene had always been the unidentified solid with such a melting point around 78 degrees Celsius.

At normal temperature as well as pressure, an ionic compound would be almost certainly a solid, even though a covalent compound could be a solid, a liquid, or even a gas.

The temperature when a solid can transform into a liquid is known as that of the melting point.

Strong intermolecular interactions have led to greater melting points for some substances, while weakly attractive molecules have lower melting points.

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Answer:

Water is much smaller than either of the previous substances and exhibits weaker dispersion forces, but its extensive hydrogen bonding provides stronger intermolecular attractions, fewer molecules escaping the liquid, and lower vapor pressure than for either diethyl ether or ethanol.

Explanation:

Brain-List

Answer:

lose protons and form ions

Explanation:

I thjink hope this helps

PLease mark brainliest

Answer:

c) The natural home or environment of an animal, plant, or other organism

Explanation:

Please note that in order to post questions in Science, you must post in Science section, but not in History. You are asking a wrong question in the wrong section.

Thank You! Please Mark Brainliest! :)

Answer:

o2

Explanation:

because Co means carbon dioxide

Answer:

9.69g

Explanation:

Xmol of n2= 7.774/22.4= 0.346 mole

molar mass of n2 2×14 =28g/Mol

Mas of n2= 0.346×28

Mas of n2=9.69grams

Tertiary amines do not show N-H stretching peaks in IR Spectra Due to the presence of three alkyl group. Option C is correct alternative.

IR Spectra is a powerful tool used to identify chemical compounds by measuring the vibrations of the chemical bonds. The N-H stretching peak in IR Spectra is a characteristic peak that is usually observed in primary and secondary amines. This peak is a result of the stretching vibrations of the N-H bond, which is present in primary and secondary amines.

In tertiary amines, however, the N-H bond is not present, and as a result, the N-H stretching peak is not observed in the IR Spectra. Tertiary amines are compounds that contain a nitrogen atom bonded to three carbon atoms, which results in the absence of an N-H bond. The absence of this bond is what makes the IR Spectra of tertiary amines unique and different from that of primary and secondary amines.

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After looking at answers I agree with the statement Chemistry is fun.

Answer:

Question 1:

Answer: True

• A nucleus comprises of "proton and neutron"

Question 2:

Answer: True

• Lithium atom has 3 protons while helium atom has 2 protons.

Question 3:

Answer: False

• Molecular compounds are formed when elements are combined be it metal or non-metal.

• A compound formed from a metal and non-metal is an ionic compound.

Question 4:

Answer: False

• Noble gases are inert / unreactive. They don't undergo any reaction because they are very stable.

Question 5:

Answer: True

Question 6:

Answer: False

\({ \rm{H _{2}O \: \dashrightarrow \: water}}\)

• The formular in the question is for hydrogen peroxide.

Question 7:

Answer: False

• What you have to know is that, molecular compounds such as halogens are made of discrete particles with weak vander waals forces of attraction, hence energy required to break these forces is quite low. Hence low melting points.

Question 8:

Answer: True

• Ionic compounds such as sodium chloride are highly soluble in water.

Question 9:

Answer: False

• Water is a polar covalent compound because it is formed due to hydrogen and covalent bonding. It is polar because oxygen is highly electronegative than hydrogen.

Question 10:

Answer: False

• Check answer for question 4

Question 11:

Answer: False

• They form charge of +1

Question 12:

Answer: True

• This are called radicals

Question 13:

Answer: False

• least reactive families are halogens and noble gases.

Question 14:

Answer: True

• This is a situation of ionic bonding.

Question 15:

Answer: False

• It is made up of 3 atoms.

The balanced reaction is: 2AgCl(s) + 2NO(g) → 2Ag(s) + Cl^-(aq) + 2NO3^-(aq). The standard cell potential (Eo cell) can be calculated by summing the standard reduction potentials of the half-reactions involved in the reaction.

To calculate Eo cell, we need to consider the reduction half-reactions for the species involved in the reaction. The reduction half-reactions are:

1. Reduction of Ag+ to Ag: Ag+(aq) + e^- → Ag(s) (Eo = +0.80 V)

2. Reduction of NO to NO3^-: NO3^-(aq) + 2H+(aq) + e^- → NO(g) + 2H2O(l) (Eo = +0.96 V)

By adding these two half-reactions, we can obtain the overall balanced redox reaction. Since Ag+ and NO3^- are spectator ions, they do not participate in the reaction. Thus, the balanced redox reaction becomes:

2AgCl(s) + 2NO(g) → 2Ag(s) + 2Cl^-(aq) + 2NO3^-(aq)

The standard cell potential (Eo cell) is the sum of the reduction potentials of the half-reactions:

Eo cell = Eo reduction of Ag+ to Ag + Eo reduction of NO to NO3^-

        = (+0.80 V) + (+0.96 V)

        = +1.76 V

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Answer:

uwu

Explanation:

because uwu= i dont knoow

The iodine test is used to detect the presence of starch in a substance. When iodine reacts with starch, it forms a blue-black color complex. It is positive for Glycogen, Amylose and Negative for Cellulose, sucrose

Glycogen: The expected result of the iodine test with glycogen is a blue-black color complex, similar to that of starch, as glycogen is a branched chain polymer of glucose, similar to amylopectin.
Amylose: The expected result of the iodine test with amylose is a blue-black color complex, as amylose is a linear polymer of glucose, similar to starch.
Cellulose: The expected result of the iodine test with cellulose is no color change, as cellulose is a polysaccharide composed of glucose units linked by β-1,4-glycosidic bonds, which cannot form a blue-black color complex with iodine.
Sucrose: The expected result of the iodine test with sucrose is no color change, as sucrose is a disaccharide composed of glucose and fructose units, which cannot form a blue-black color complex with iodine.

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The force of attraction between two singly charged ions, given the distance between adjacent sodium and chloride ions in a salt crystal of 2.82E-10m, can be calculated using Coulomb's law.

Coulomb's law states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Mathematically, F ∝ q1q2/d2 Where F is the force between the two charges,q1 and q2 are the charges on the two objects, andd is the distance between the two objects.The force of attraction between two singly charged ions in a salt crystal is, therefore:

F = k(q1q2/d2)where k is Coulomb's constant and has a value of 9 × 10⁹ Nm²/C². We know that the distance between adjacent sodium and chloride ions in a salt crystal is 2.82E-10m, which is the value of d in the equation.

Since the ions are singly charged, the value of q1 and q2 is 1.6 × 10^-19 C each.Substituting these values in the equation, we get: F = (9 × 10^9 Nm²/C²)(1.6 × 10⁻¹⁹C)(1.6 × 10⁻¹⁹C)/(2.82E-10m)²= 2.31 × 10⁻⁹ N.

Therefore, the force of attraction between two singly charged ions in a salt crystal with a distance of 2.82E-10m between them is 2.31 × 10⁻⁹ N.

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The dosage of 26mg can be prepared using approximately 1.625 mL of the 40mg in 2.5 mL solution.

The dosage of 22mg can be prepared using approximately 1.222 mL of the 36mg per 2 mL strength solution.

To calculate the dosage using ratio and proportion, we can set up a proportion based on the strength of the solution.

40mg in 2.5 mL solution will be used to prepare a 26mg dosage.

Let X represent the mL of the solution needed to prepare the 26mg dosage.

We can set up the proportion as follows:

40mg/2.5mL = 26mg/X mL

Cross-multiplying and solving for X, we have:

40mg * X mL = 2.5mL * 26mg

40X = 65

X = 65/40

X ≈ 1.625 mL

For the second question:

36mg per 2 mL strength solution is used to prepare 22mg.

Let Y represent the mL of the solution needed to prepare the 22mg dosage.

We can set up the proportion as follows:

36mg/2mL = 22mg/Y mL

Cross-multiplying and solving for Y, we have:

36mg * Y mL = 2mL * 22mg

36Y = 44

Y = 44/36

Y ≈ 1.222 mL

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Answer:

the answer is false

Explanation:

Answer:

36dm³

Explanation:

For this question we are required to find the volume of the ethyne which is released while reacting 6 grams of water with calcium carbide.

Here to find the volume of ethyne produced, we can find the moles of the ethyne in the reaction by using the mole concept, and then converting the mol into the volume using the formula V=nRT/p or PV=nRT (n being the moles of the gas)

1 mole of BF3 is needed to produce 48.35 moles of NaF.

Given data :

The molecule of boron trifluoride is 1.5×1016 molecules

moles of NaF = 0.023816230233136  

48 NaF = 1.15x10^16 molecules

So, 1 mole of BF3 is needed to produce 48.35 moles of NaF.

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128.8 atm is the work in atm done on the gas during this process.

W=pV, W = p V, where W is work, p is pressure, and V is the change in gas volume, can be used to calculate the work performed by a gas under a constant pressure.

The formula Work = Force Distance can be used to compute work. The joule (J) or Newton-meter (N-m) is the SI unit for work. The amount of work required to move an item one meter with one newton of force is equal to one joule.

Work done during a gas's expansion includes:

W = -PΔV

W = -P( Vfinal - Vintial)

w =  -92 ( 2.5 - 1.1 )

w = 128.8 atm

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The pH of the solution is 1.60, by mixing 20.0 ml of 0.15 m hcl with 20.0 ml of 0.10 m koh.

pH = -log[H+]

Also;

mole of substance = molarity × volume in L

The moles of HCl = 0.15 × 0.02 = 0.003 moles

The moles of KOH = 0.10 × 0.02 = 0.002 moles

The solution will be acidic since the moles of HCl is greater than that of KOH.

Moles of remaining HCl [H⁺] remaining = 0.003 - 0.002 = 0.001 moles

Molarity of remaining HCl [H⁺] remaining = 0.001/0.04 = 0.025 M

Hence, [H⁺] = 0.025 M

pH = - log(0.025)

pH = 1.6

Therefore, the pH of the resulting solution is 1.60.

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Answer:

PH scale is a universal indicator of strongness of base and acid

Answer:

you better give me brainliest

Explanation:

Zinc nitrate and calcium nitrate solution can be distinguished by reaction with ammonium hydroxide. Zinc forms a white gelatinous ppt. whereas there is no precipitation of calcium hydroxide even with excess of ammonium hydroxide