The air conditioner in a house or a car has a cooler that brings atmospheric air from 30C to 10C, with both states at 101KPa. If the flow rate is 0.75kg/s, find the rate of heat transfer using constant specific heat of 1.004kj/kg.K

The part of a drill that holds the drill bit in place is called the chuck.

The chuck is a key component of a drill, as it securely holds the drill bit in place during operation. It is typically located at the end of the drill, and can be opened and closed to insert or remove the drill bit.

The chuck is usually operated by either a key or a lever, depending on the type of drill. It is important to make sure that the chuck is properly tightened when the drill bit is inserted, as this will ensure that the bit is secure and will not slip or come loose during drilling.

Additionally, it is important to make sure that the bit is compatible with the size of the chuck, as an improper fit could cause the bit to become stuck or damaged.

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Answer:

  4.94 kW

Explanation:

The heat energy produced by the fuel in one hour is ...

  (2.29 L/h)(0.749 kg/L)(43.7 MJ/kg) = 74.954677 MJ/h

Then the power output is ...

  (74.954677 MJ/h)(1 h)/(3600 s) = 20.8207 kJ/s

Multiplying this heat energy by the efficiencies of the processes involved, the output power is ...

  (20.8207 kW)(0.25)(0.95) = 4.94 kW

The maximum value of rolling resistance over which a loaded scraper can maintain in a speed of 11 mph is 275 lb/ton

The maximum rolling resistance is the maximum rolling friction that can cause the motion of a body or a substance to resist the force when rolled on a flat surface.

Using Rimpull Performance Chart for wheel-tractor scraper;

The total resistance = (gross+rolling) resistance

25% = 0% - rolling resistance

rolling resistance = 25%

The maximum rolling resistance = rolling resistance percentage × speed

The maximum rolling resistance \(\mathbf{=25\% ( \dfrac{11 \ lb/ton}{1 \% \ resistance})}\)

The maximum rolling resistance = 275 lb/ton

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Answer:

Anaerobic sealers

Explanation:  

Because they cure in the absence of air

Answer:

1) The three possible assumptions are

a) All processes are reversible internally

b) Air, which is the working fluid circulates continuously in a closed loop

cycle

c) The process of combustion is depicted as a heat addition process

2) The diagrams are attached

5) The net work per cycle is 845.88 kJ/kg

The power developed in horsepower ≈ 45374 hP

Explanation:

1) The three possible assumptions are

a) All processes are reversible internally

b) Air, which is the working fluid circulates continuously in a closed loop

cycle

c) The process of combustion is depicted as a heat addition process

2) The diagrams are attached

5) The dimension of the cylinder bore diameter = 3.7 in. = 0.09398 m

Stroke length = 3.4 in. = 0.08636 m.

The volume of the cylinder v₁= 0.08636 ×(0.09398²)/4 = 5.99×10⁻⁴ m³

The clearance volume = 16% of cylinder volume = 0.16×5.99×10⁻⁴ m³

The clearance volume, v₂  = 9.59 × 10⁻⁵ m³

p₁ = 14.5 lbf/in.² = 99973.981 Pa

T₁ = 60 F = 288.706 K

\(\dfrac{T_{2}}{T_{1}} = \left (\dfrac{v_{1}}{v_{2}} \right )^{K-1}\)

Otto cycle T-S diagram

T₂ = 288.706*\(6.25^{0.393}\) = 592.984 K

The maximum temperature = T₃ = 5200 R = 2888.89 K

\(\dfrac{T_{3}}{T_{4}} = \left (\dfrac{v_{4}}{v_{3}} \right )^{K-1}\)

T₄ = 2888.89 / \(6.25^{0.393}\) = 1406.5 K

Work done, W = \(c_v\)×(T₃ - T₂) - \(c_v\)×(T₄ - T₁)

0.718×(2888.89  - 592.984) - 0.718×(1406.5 - 288.706) = 845.88 kJ/kg

The power developed in an Otto cycle = W×Cycle per second

= 845.88 × 2400 / 60  = 33,835.377 kW = 45373.99 ≈ 45374 hP.

Answer:

The electric ceiling fan was invented in 1882 by engineer and inventor, Philip Diehl. He had earlier invented an electric sewing machine and adapted the motor from this invention to create the ceiling fan. He called his invention the “Diehl Electric Fan” and it was such a success that he soon had many other people competing with him.

Explanation:

Answer:

  5

Explanation:

One pulse is required for each bit to be moved.

5 pulses are required.

A grounding electrode known as a "grounding rod" or "grounding stake" is frequently specified for installation at each manhole, transformer, or substation in some engineered grounding system designs.

An electrical grounding system must include a grounding electrode. It is often installed in the ground to provide a low-impedance path for the dissipation of electrical energy in the case of a fault or surge. Its typical materials include copper, copper-clad steel, or other conductive materials. In engineered grounding systems, grounding electrodes are frequently employed to shield people and equipment from electrical dangers including electrical failures and lightning strikes. To maintain the efficiency and dependability of a grounding system, proper installation and maintenance of grounding electrodes are essential. Installation of grounding electrodes at manholes, transformers, and substations is frequently specified.

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Answer:

Purpose of review papers

They carefully identify and synthesize relevant literature to evaluate a specific research question, substantive domain, theoretical approach, or methodology and thereby provide readers with a state-of-the-art understanding of the research topic.

Answer:

a. The time required for the tank to empty halfway is presented as follows;

\(t_1 = \dfrac{D_0^2 }{D^2 } \cdot \sqrt{ \dfrac{H}{g} } \cdot \left (\sqrt{2} -1 \right)\)

b. The time it takes for the tank to empty the remaining half is presented as follows;

\(t_2 = { \dfrac{ D_0^2 }{D} \cdot\sqrt{\dfrac{H}{g} }\)

The total time 't', is presented as follows;

\(t = \sqrt{2} \cdot \dfrac{D_0^2 }{D^2 } \cdot \sqrt{ \dfrac{H}{g} }\)

Explanation:

a. The diameter of the tank = D₀

The height of the tank = H

The diameter of the orifice at the bottom = D

The equation for the flow through an orifice is given as follows;

v = √(2·g·h)

Therefore, we have;

\(\dfrac{P_1}{\gamma} + z_1 + \dfrac{v_1}{2 \cdot g} = \dfrac{P_2}{\gamma} + z_2 + \dfrac{v_2}{2 \cdot g}\)

\(\left( \dfrac{P_1}{\gamma} -\dfrac{P_2}{\gamma} \right) + (z_1 - z_2) + \dfrac{v_1}{2 \cdot g} = \dfrac{v_2}{2 \cdot g}\)

Where;

P₁ = P₂ = The atmospheric pressure

z₁ - z₂ = dh (The height of eater in the tank)

A₁·v₁ = A₂·v₂

v₂ = (A₁/A₂)·v₁

A₁ = π·D₀²/4

A₂ = π·D²/4

A₁/A₂ = D₀²/(D²) = v₂/v₁

v₂ = (D₀²/(D²))·v₁ = √(2·g·h)

The time, 'dt', it takes for the water to drop by a level, dh, is given as follows;

dt = dh/v₁ = (v₂/v₁)/v₂·dh = (D₀²/(D²))/v₂·dh = (D₀²/(D²))/√(2·g·h)·dh

We have;

\(dt = \dfrac{D_0^2}{D} \cdot\dfrac{1}{\sqrt{2\cdot g \cdot h} } dh\)

The time for the tank to drop halfway is given as follows;

\(\int\limits^{t_1}_0 {} \, dt = \int\limits^h_{\frac{h}{2} } { \dfrac{D_0^2}{D} \cdot\dfrac{1}{\sqrt{2\cdot g \cdot h} } } \, dh\)

\(t_1 =\left[{ \dfrac{D_0^2}{D\cdot \sqrt{2\cdot g} } \cdot\dfrac{h^{-\frac{1}{2} +1}}{-\frac{1}{2} +1 } \right]_{\frac{H}{2} }^{H} =\left[ { \dfrac{D_0^2 \cdot 2\cdot \sqrt{h} }{D\cdot \sqrt{2\cdot g} } \right]_{\frac{H}{2} }^{H} = { \dfrac{2 \cdot D_0^2 }{D\cdot \sqrt{2\cdot g} } \cdot \left(\sqrt{H} - \sqrt{\dfrac{H}{2} } \right)\)

\(t_1 = { \dfrac{2 \cdot D_0^2 }{D^2\cdot \sqrt{2\cdot g} } \cdot \left(\sqrt{H} - \sqrt{\dfrac{H}{2} } \right) = { \dfrac{\sqrt{2} \cdot D_0^2 }{D^2\cdot \sqrt{ g} } \cdot \left(\sqrt{H} - \sqrt{\dfrac{H}{2} } \right)\)

\(t_1 = { \dfrac{\sqrt{2} \cdot D_0^2 }{D^2\cdot \sqrt{ g} } \cdot \left(\sqrt{H} - \sqrt{\dfrac{H}{2} } \right) = { \dfrac{D_0^2 }{D^2\cdot \sqrt{ g} } \cdot \left(\sqrt{2 \cdot H} - \sqrt{{H} } \right) =\dfrac{D_0^2 }{D^2 } \cdot \sqrt{ \dfrac{H}{g} } \cdot \left (\sqrt{2} -1 \right)\)The time required for the tank to empty halfway, t₁, is given as follows;

\(t_1 = \dfrac{D_0^2 }{D^2 } \cdot \sqrt{ \dfrac{H}{g} } \cdot \left (\sqrt{2} -1 \right)\)

(b) The time it takes for the tank to empty completely, t₂, is given as follows;

\(\int\limits^{t_2}_0 {} \, dt = \int\limits^{\frac{h}{2} }_{0 } { \dfrac{D_0^2}{D} \cdot\dfrac{1}{\sqrt{2\cdot g \cdot h} } } \, dh\)

\(t_2 =\left[{ \dfrac{D_0^2}{D\cdot \sqrt{2\cdot g} } \cdot\dfrac{h^{-\frac{1}{2} +1}}{-\frac{1}{2} +1 } \right]_{0}^{\frac{H}{2} } =\left[ { \dfrac{D_0^2 \cdot 2\cdot \sqrt{h} }{D\cdot \sqrt{2\cdot g} } \right]_{0 }^{\frac{H}{2} } = { \dfrac{2 \cdot D_0^2 }{D\cdot \sqrt{2\cdot g} } \cdot \left( \sqrt{\dfrac{H}{2} } -0\right)\)

\(t_2 = { \dfrac{ D_0^2 }{D} \cdot\sqrt{\dfrac{H}{g} }\)

The time it takes for the tank to empty the remaining half, t₂, is presented as follows;

\(t_2 = { \dfrac{ D_0^2 }{D} \cdot\sqrt{\dfrac{H}{g} }\)

The total time, t, to empty the tank is given as follows;

\(t = t_1 + t_2 = \dfrac{D_0^2 }{D^2 } \cdot \sqrt{ \dfrac{H}{g} } \cdot \left (\sqrt{2} -1 \right) + t_2 = { \dfrac{ D_0^2 }{D} \cdot\sqrt{\dfrac{H}{g} } = \dfrac{D_0^2 }{D^2 } \cdot \sqrt{ \dfrac{H}{g} } \cdot \sqrt{2}\)

\(t = \sqrt{2} \cdot \dfrac{D_0^2 }{D^2 } \cdot \sqrt{ \dfrac{H}{g} }\)

The ratio of the induced EMF in the loop CDBC to the induced EMF in the loop CADC can be calculated as follows:

ecdbc/ecadc = -dΦ_cdbc/dt / (-dΦ_cadc/dt) = dΦ_cadc/dt / dΦ_cdbc/dt

Let's dive deeper into the details below

The induced EMF is the voltage generated by a changing magnetic field in a coil of wire. In a loop, the induced EMF is proportional to the rate of change of the magnetic flux that is threading the loop. Therefore, in a loop, the induced EMF can be calculated as:

induced EMF = -dΦ/dt, where Φ is the magnetic flux threading the loop.

We can assume that both loops are parallel to the surface and therefore perpendicular to the magnetic field. This means that the magnetic flux threading each loop is proportional to the area of the loop, as follows:

Φ_cadc = B A_cadc and Φ_cdbc = B A_cdbc

Therefore, the ratio of the induced EMF in the loop CDBC to the induced EMF in the loop CADC can be calculated as follows:

ecdbc/ecadc = dΦ_cadc/dt / dΦ_cdbc/dt = (B A_cadc)/dt / (B A_cdbc)/dt = A_cadc / A_cdbc

The answer is the ratio of the areas of the loops.

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The total force the cover is experiencing is 10,200 lbs.

Pressure = Force / Area
We know that the gauge pressure of the tank is 552 psi, which means the pressure inside the tank is 552 psi above atmospheric pressure. To find the total force the cover is experiencing, we need to calculate the force based on the pressure and the surface area of the cover.

First, we need to convert the gauge pressure to absolute pressure:
Absolute pressure = Gauge pressure + Atmospheric pressure
Assuming the atmospheric pressure is 14.7 psi, the absolute pressure in the tank is:
Absolute pressure = 552 psi + 14.7 psi = 566.7 psi
Now we can use the formula for pressure to find the force:
Force = Pressure x Area
Force = 566.7 psi x 18 sq in
Force = 10,200 lbs

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Both forms of the Risk Management Framework (RMF) illustrate a systems engineering process as a way to plan, design, and build a complicated system.

Engineering is a discipline and profession that involves the application of scientific, mathematical, and practical knowledge to design, develop, build, and improve various systems, structures, machines, processes, and technologies.

Engineers utilize their expertise to solve complex problems and create practical solutions that meet societal needs.

Engineers employ a systematic and analytical approach, combining creativity, technical skills, and scientific principles to tackle challenges across different fields.

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The scale of 1 inch = 10 feet can be expressed as a fraction of 1/120.

The given scale of 1 inch = 10 feet can be written as a ratio of inches to feet, which is:

1 inch / 10 feet

To express this ratio as a fraction, we can convert the units so that both terms are in the same unit. Since there are 12 inches in 1 foot, we can convert the feet to inches by multiplying by 12, which gives:

1 inch / (10 x 12) inches

Simplifying this fraction by dividing both the numerator and denominator by 10, we get:

1/120

Therefore, the scale of 1 inch = 10 feet can be expressed as a fraction of 1/120.

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The little hardware component known as a network switch connects many computers to one local area network (LAN). Switches are not capable of sharing an Internet connection or connecting to several networks.

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The location at which the joined forces of a pressure distribution on a wholly submerged plane surface counteracts is determined by its shape, orientation, and furthermore the pressure composition.

To exemplify, when a plane surface displays an evenly distributed pressure around its center of gravity, then the center of pressure will be found beneath the center of gravity when the surface inclines.

Yet, if the same plane surface remains horizontal, the pressure arrangement will remain homogenous and thus the two centers merge. Generally speaking, the center of pressure stands below, or at most level with, the center of gravity when the plane surface is straight.

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The thermal efficiency of the Brayton cycle in the cold air standard of 25° C is 45.60 %. The correct option is A.

A Brayton cycle is the thermodynamic cycle used in the heat engine. The process has been comprised of the events as:

The given conditions in the Brayton cycle are:

Inlet Temperature (T₁) = 25° C

Inlet pressure (P₁) = 95 kPa

Outlet pressure (P₂) = 1100 kPa

The efficiency of the cycle (η) can be calculated as:

\(\eta = 1 - \dfrac {1}{\frac{P_2}{P_1}^{(\gamma-1)(\gamma)}}\)

γ is the specific heat ratio and is 1.4.

Substituting the values in the equation of efficiency:

\(\eta = 1 - \dfrac {1}{\frac{1100}{95}^{(1.4-1)(1.4)}}\\\eta = 1 - \dfrac {1}{8.421^{(\gamma-1)(\gamma)}}\\\\\eta = 45.60 \%\)

The efficiency of the Brayton cycle in the thermal conditions is 45.60%. The correct option is A.

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Your question is incomplete and most probably the complete question is:

In an ideal Brayton cycle, air is compressed from 95 kPa and 25°C to 800 kPa. Under cold air standard conditions, the thermal efficiency of this cycle is:

(a) 46%

(b) 54%

(c) 57%

(d) 39%

(e) 61 %

The problem with the following code snippet is that the pointer variable `acc_ptr` is uninitialized, meaning it does not point to a valid memory location.

In the line `*acc_ptr = 1000;`, the code is trying to dereference `acc_ptr` and assign the value 1000 to the memory location it points to. However, since `acc_ptr` is uninitialized, it does not point to a specific memory address, and attempting to dereference it leads to undefined behavior. This can result in a crash or unexpected program behavior.

To resolve the issue, `acc_ptr` should be properly initialized and assigned a valid memory address, either by allocating memory using `new` or by assigning it the address of an existing variable.

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Answer:

F. Completion date.

Explanation:

The completion date cannot be determined exactly before the job; it is also irrelevant to Painting and Finishing.

Yes, that is correct. According to the National Electrical Code (NEC), an unbroken wall space that has a minimum width of 48 inches is considered a wall space for the purpose of determining the distribution of receptacle outlets.

This means that for every 12 linear feet of wall space, at least one receptacle outlet must be installed. Additionally, no point along the wall should be more than 6 feet away from an outlet. It's important to follow these guidelines to ensure that there are enough receptacles to meet the electrical needs of the space and to promote safety by preventing overloading of circuits.

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In the HACCP (Hazard Analysis Critical Control Points) system, hazards are divided into three categories: contamination, growth of pathogens, and survival of pathogens. Hence, option D is correct.

The Hazard Analysis Critical Control Points (HACCP) system is a methodical, logical, and systematic approach to food safety management. It's a system that outlines the stages in food production where risks can be reduced, prevented, or removed altogether.

Contamination, growth of pathogens, and survival of pathogens are the three categories of hazards to consider. Contamination may result from inadequate cooking, inappropriate storage, or unclean equipment. Pathogens can grow and thrive under certain conditions. Control points are critical steps in food processing where appropriate action can prevent, minimize, or eliminate risks.

Basically, HACCP is a food safety management system that is primarily based on the principle of prevention rather than detection. The primary aim of HACCP is to identify all potential hazards associated with food production, determine the points in the process where the hazards can occur, and then put measures in place to prevent or reduce these hazards from occurring again. So, hazards are divided into three categories in the HACCP system, contamination, growth of pathogens, and survival of pathogens.

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Answer:

Overall project duration

Explanation:

Scheduling can best be defined as the process used to determine a overall project duration.

Answer:

Explanation:

From the information given:

original diameter \(d_o\) = 10 mm

final diameter \(d_f =\) 7.5 mm

Cold work tensile strength of brass = 380 MPa

Recall that;

\(\text {The percentage CW }= \dfrac{\pi (\dfrac{d_o}{2})^2 - \pi(\dfrac{d_f}{2})^2 }{\pi(\dfrac{d_o}{2})^2} \times 100\)

\(\implies \dfrac{\pi (\dfrac{10}{2})^2 - \pi(\dfrac{7.5}{2})^2 }{\pi(\dfrac{10}{2})^2} \times 100\)

\(\implies43.87\% \ CW\)

→ At 43.87% CW, Brass has a tensile strength of around 550 MPa, which is greater than 380 MPa.

→ At 43.87% CW, the ductility is less than 5% EL, As a result, the conditions aren't met.

To achieve 15% EL, 28% CW is allowed at most

i.e

The lower bound cold work = 15%

The upper cold work = 28%

The average = \(\dfrac{15+28}{2}\) = 21.5 CW

Now, after the first drawing, let the final diameter be \(d_o^'\); Then:

\(4.5\% \ CW = \dfrac{\pi (\dfrac{d_o^'}{2})^2 - (\dfrac{7.5}{2})^2}{\pi (\dfrac{d_o^'}{2})^2}\times 100\)

By solving:

\(d_o^'} = 8.46 mm\)

To meet all of the criteria raised by the question, we must first draw a wire with a diameter of 8.46 mm and then 21.5 percent CW on it.

A stall happens when the smooth airflow over the unmanned airplane`s wing is disrupted, and the lift degenerates rapidly. This is caused when the wing "exceeds its critical angle of attack."

The angle of attack refers to the angle at which the airplane's wing meets the air that is flowing over it. When an airplane actually is taking off, it is lifting the nose up into the air. And, if that nose continues to rise ultimately it reaches a point where the air is not able to smoothly flow over the wing, causing the airplane to drop. And, this is the point when the airplane exceeds its critical angle of attack.

Exceeding the critical angle of attack is known to be a stall. This has no concern with the engine stalling, it just concerns with the wings not producing enough lift to keep the airplane in the air.

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Answer:

-x, +x, -y, +y, -z, +z

Explanation:

These are the 6 axes

Answer:

building a bridge

Explanation:

you would have to sketch ideas to see what the bridge would look like and you need to know what to add to it to enhance the percentage of it working. if you sketch it you would have an idea of the process also

Building a bridge is an occasion in which an explanatory sketch would be used.

Sketches of explanations are created to demonstrate form, structure, and function. They accurately and objectively communicate a design, placing more emphasis on explanation than pitch. Outside of the design team, explanation sketches must be understandable.

Exploratory sketches, often referred to as thinking drawings, are a type of personal communication that frequently serve as the starting point for brand-new product concepts.

During a brainstorming session or for personal usage in a design notebook, these quick sketches are meant to quickly capture ideas. Exploratory research aims to study the important aspects of a topic that hasn't gotten much attention.

Thus, it is Building a bridge.

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The missing term in the presented paragraph is environmental.

In recent years the effects of climate change have been strongly manifested around the world causing:

Therefore, many companies have begun to investigate productive alternatives to reduce their environmental impact. In the case of the car industry, companies have deepened their research on other sources of energy such as:

One of them is Toyota, the Japanese brand that has developed cars that work hybrid, that is, with gasoline and electric power. This will reduce the emissions of CO2 and other harmful gases into the atmosphere.

Therefore, it is possible to infer that the missing term in the paragraph is Environmental.

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Answer:

The resulting pressure of the gas when its volume decreases is 300 kN/m².

Explanation:

Given;

initial volume of the gas, V₁ = 80 L

number of moles of the gas, n = 0.5 moles

initial pressure of the gas, P₁ = 150 kN/m² = 150 kPa

Determine the constant temperature of the gas using ideal gas equation;

PV = nRT

where;

R is ideal gas constant = 8.315 L.kPa/K.mol

T is the constant temperature

\(T = \frac{P_1V_1}{nR} \\\\T = \frac{150.kPa \ \times \ 80 .L}{0.5 .mol \ \times \ 8.315(L.kPa/mol.K)} \\\\T = 2,886.35 \ K\)

When the gas is compressed to half of its volume;

new volume of the gas, V₂ = ¹/₂ V₁

                                             = ¹/₂ x 80L = 40 L

The new pressure, P₂ is calculated as;

\(P_2V_2 = nRT\\\\P_2 = \frac{nRT}{V_2} \\\\P_2 = \frac{0.5 \times 8.315\times 2886.35}{40} \\\\P_2 = 300 \ kPa = 300 \ kN/m^2\)

Therefore, the resulting pressure of the gas when its volume decreases is 300 kN/m².

The distance below the top of the cliff that the two balls cross paths is 7.53 meters.

Given the following data:

Scientific data:

To determine how far (distance) below the top of the cliff that the two balls cross paths, we would apply the third equation of motion.

Mathematically, the third equation of motion is given by this formula:

\(V^2 = U^2 +2aS\)

Where:

Substituting the parameters into the formula, we have;

\(V^2 = 0^2 +2(9.8) \times 30\\\\V^2 = 588\\\\V=\sqrt{588}\)

V = 24.25 m/s.

Note: The final velocity of the first ball becomes the initial velocity of the second ball.

The time at which the two balls meet is calculated as:

\(Time = \frac{S}{U} \\\\Time = \frac{30}{24.25}\)

Time = 1.24 seconds.

The position of the ball when it is dropped from the cliff is calculated as:

\(y_1 = h-\frac{1}{2} at^2\\\\y_1 = 30-\frac{1}{2} \times 9.8 \times 1.24^2\\\\y_1 = 30-7.53\\\\y_1=22.47\;meters\)

Lastly, the distance below the top of the cliff is calculated as:

\(Distance = 30-22.47\)

Distance = 7.53 meters.

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Answer:

A. Yes, it will run

B. X will not replace any value

Explanation:

A. Will it run?

First, the algorithm can be interpreted in python as follows:

#Set Minimum to 1

MINIMUM = 1

#For every element X in the list L

for X in L:

#If current element X is less than MINIMUM

    if X < MINIMUM:

#Set MINIMUM to X

         MINIMUM = X

#Print MINIMUM

print(MINIMUM)

The algorithm will run without error because it follows the right sequence and has no syntax error

B. Will X replace any value?

No, it won't

The smallest positive integer is 1.

So, setting the MINIMUM to 1 means that the value of X in the list will not replace the MINIMUM because the MINIMUM has already been set