The active ingredient in one does of antacid A is 0.50g Al(OH)3. the active ingredient in one does of antacid B is 0.50g CaCO3. Would one does of antacid A or B neutralize more stomach acid? Explain your choice, and show a calculation to support your answer.

The theoretical yield, in grams, of CO₂ is 93.97g having molar mass 44g

What is molar mass ?

The "counting unit" used by chemists to describe the quantity of atoms, ions, molecules, or formula units in a specific chemical sample is called a mole. The mole is comparable to other counting units you have employed in the past, such as pair (2), dozen (12), and gross (144). Avogadro's number (6.022 x 1023) of molecules (or formula units) make up one mole of a substance (ionic compound). The mass of 1 mole of a chemical is indicated by its molar mass. It provides you with the amount of grammes per mole of a substance, to put it another way. Therefore, grams/mole are the units for molar mass.

2C2H2 + 5O2=====> 4CO2+2H2O

Molar Mass of C2H2 = 2*12+2*2 = 28g = 1 mol

2 mol of C2H2 = 28*2 = 56g

Molar Mass of  CO2 = 12+2*16 = 44g = 1 mol

4 mol of CO2 = 4*44 = 176g

56g of C2H2 gives 176g of CO2

29.9g of C2H2 gives 176*29.9/56g of CO2

                                   = 93.97g of CO2

The theoretical yield, in grams, of CO₂ is 93.97g having molar mass 44g

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A molecular compound is defined as a molecule whose formula states the actual number of atoms bonded together in the molecule.

The atoms are joined to give a definite shape which is defined by the angles between the bonds and by the bond lengths. Molecular compounds can contain discrete molecules, which are held together by sharing electrons in covalent bonding.

Examples of molecular compounds are water, which contains H2O molecules; methane contains CH4 molecules; and hydrogen fluoride, which contains HF molecules.

As a rule of thumb, compounds that are involved in a metal binding with either a non-metal or a semi-metal will display ionic bonding.

Compounds can be composed with only non-metals or semi-metals and non-metals will display covalent bonding and will be classified as molecular compounds.

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Answer:

5

Explanation:

Answer:

i k ow its not the exact anwser but ih ope this helps

Explanation:

Energy plays a key role in chemical processes. According to the modern view of chemical reactions, bonds between atoms in the reactants must be broken, and the atoms or pieces of molecules are reassembled into products by forming new bonds. Energy is absorbed to break bonds, and energy is evolved as bonds are made. In some reactions the energy required to break bonds is larger than the energy evolved on making new bonds, and the net result is the absorption of energy. Such a reaction is said to be endothermic if the energy is in the form of heat. The opposite of endothermic is exothermic; in an exothermic reaction, energy as heat is evolved. The more general terms exoergic (energy evolved) and endoergic (energy required) are used when forms of energy other than heat are involved.

A great many common reactions are exothermic. The formation of compounds from the constituent elements is almost always exothermic. Formation of water from molecular hydrogen and oxygen and the formation of a metal oxide such as calcium oxide (CaO) from calcium metal and oxygen gas are examples. Among widely recognizable exothermic reactions is the combustion of fuels (such as the reaction of methane with oxygen mentioned previously).

If during a spectroscopy experiment a student notes a wavelength peak measurement at 280 nm, then the region of the electromagnetic spectrum observed is the UV region.

The electromagnetic spectrum refers to all types of wavelengths that radiation can emit as light, which involves both visible light and also ultraviolet (UV) radiation.

In conclusion, if during a spectroscopy experiment a student notes a wavelength peak measurement at 280 nm, the region of the electromagnetic spectrum observed is the UV region.

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Answer: The calcium ion has a 2+ charge and the phosphate ion has a 3- charge.

Answer:

C₄H₁₀(g) + O₂(g) ⇒ CO₂(g) + H₂O(g)

2 C₄H₁₀(g) + 13 O₂(g) ⇒ 8 CO₂(g) + 10 H₂O(g)

Explanation:

Butane gas (C₄H₁₀) burns in oxygen gas to produce carbon dioxide gas and water vapor. The unbalanced equation is:

C₄H₁₀(g) + O₂(g) ⇒ CO₂(g) + H₂O(g)

First, we will balance carbon and hydrogen which are in just one compound on each side.

C₄H₁₀(g) + O₂(g) ⇒ 4 CO₂(g) + 5 H₂O(g)

Finally, we will balance the oxygen atoms.

C₄H₁₀(g) + 6.5 O₂(g) ⇒ 4 CO₂(g) + 5 H₂O(g)

In order to have integers, we will multiply everý compound by 2.

2 C₄H₁₀(g) + 13 O₂(g) ⇒ 8 CO₂(g) + 10 H₂O(g)

Answer:

20.1974

Explanation:

The Atomic mass will be the same for every isotope as the number of Neutrons changes, not the number of protons.

Neon has two major isotopes. Neon-20 and Neon-22. Out of every 250 neon atoms, 225 will be Neon-2(19.992 g/mol), and 25 will be Neon-22 (21.991 g/mol), then the average atomic mass of Neon20.1974

Atomic mass of an element can be defined as the total number of neutrons and protons present in the nucleus of an atom and the  atomic number is the number of protons present in  nucleus.

the average weight of an element is called as atomic mass while atomic number is total number of protons present in the central nucleus of the atom. Atomic mass is presented a symbolic representation of A where as atomic number is represented by the letter Z.

Atomic mass can not classified  which type of element where as Atomic number classify and identify the type of element, there are different types of isotopes of an element observed on the basis of their atomic mass where as isotopes only share the same atomic number.

Neon has two isotopes such as , N e 20, N e 21 and N e 22.The average atomic mass can be calculated as:

N e  Average atomic mass = [ 19.9924 (90.92 %)] + [ 20.9940 (0.257 %)] + [ 21.9914 (8.82 %)] a m u

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Answer:

I cant see it clearly

Explanation:

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By using filtration, the sand and fine salt can be effectively separated based on their difference in particle size, providing a clean separation of the two components.

Filtration is a separation technique that takes advantage of the difference in particle size between sand and salt. It involves passing the mixture through a porous material, such as filter paper or a filter funnel, which allows the liquid (saltwater) and small salt particles to pass through while retaining the larger sand particles.

Here's how the filtration process can be carried out:

1. Set up a filter apparatus with a funnel and filter paper or a filter flask.

2. Place the mixture of sand and salt in a beaker or a flask.

3. Slowly pour the mixture into the filter paper or funnel, allowing the liquid (saltwater) to pass through while retaining the sand on the filter paper.

4. Once the liquid has passed through completely, the sand will be left behind on the filter paper or in the filter flask.

5. Carefully remove the sand from the filter paper or filter flask, and the saltwater solution can be collected separately.

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Answer:

\(\rho =0.697\frac{lb}{in^3}\)

Explanation:

Hello,

In this case, given that 1 inch equals 2.54 cm and 1 lb equals 453.6 g we apply the following conversion factor in order to compute the required density in lb/in³:

\(\rho=19.3\frac{g}{cm^3}*\frac{1lb}{453.6g} *(\frac{2.54cm}{1in} )^3\\\\\rho =0.697\frac{lb}{in^3}\)

Best regards.

Answer:

A  group 1

Explanation:

Group 1

reactivity decreases as you go from L to R or downward on the periodic table

The list which includes only bulk properties of matter is boiling point, surface tension and vapor pressure.

Definition of matter

Something that has mass and occupies space is defined as a matter.

Hence, all the physical objects or substances that are found on the planet Earth are typically composed of matter.

Matter are classified into three (3) states:

Gas

Solid

Liquid

The property of the matter that affects matter as a whole is known as bulk property of matter and they are listed as follows:

Hence, boiling point, vapor pressure and surface tension are considered as a bulk properties of matter.

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Answer:

4 Al(s) + 3 O₂(g) ⇒ 2 Al₂O₃(s)

Explanation:

Let's consider the unbalanced molecular equation when aluminum metal and oxygen gas combine to produce aluminum oxide. This is a combination reaction.

Al(s) + O₂(g) ⇒ Al₂O₃(s)

We can balance O  atoms by multiplying O₂ by 3 and Al₂O₃ by 2.

Al(s) + 3 O₂(g) ⇒ 2 Al₂O₃(s)

Finally, we multiply Al by 4 to get the balanced equation.

4 Al(s) + 3 O₂(g) ⇒ 2 Al₂O₃(s)

The specific groups of other atoms attached to a hydrocarbon chain are called functional groups.

These are specific atoms or groups of atoms that are attached to the hydrocarbon chain and give the molecule its characteristic chemical and physical properties.

Functional groups include, for example, hydroxyl (-OH), carbonyl (C=O), amino (-NH₂), and carboxyl (-COOH) groups, among others.

They are the reactive part of the molecule and determine the molecule's reactivity and its interactions with other molecules.

Thus, option B is correct.

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Answer:

D

Explanation:

In terms of relative energy, gas particles have the most energy, solid particles have the least energy and liquid particles are somewhere in between.

The percent yield for the reaction of a sample of 0.49 g of carbon dioxide was obtained by heating 1.22 g of calcium carbonate is 92.4%

Given the mass of carbon dioxide (\(CO2\)) = 0.49g

The mass of calcium carbonate (\(CaCO3\)) = 1.22g

The reaction is as follows:

\(CaCO3(s) -- > CaO(s)+CO2(s)\)

As we see 1 mole of CaCO3 is required to produce 1 mole of \(CO2\)

The molar mass of calcium carbonate, = 100.09 g/mol.

The molar mass of given carbon dioxide = 44g

mass of \(CaCO3\) used = number of moles x molar mass = 1 * 100 = 100g

Mass of \(CO2\) produced = 1 * 44 = 44g

Here for 100g of \(CaCO3\) 44g of \(CO2\) is produced.

Then for 1.22g of \(CaCO3\) = 44 * 1.22/100 = 0.53g of \(CO2\) is produced.

But the actual yield of carbon dioxide is 0.49 g

The percent yield is calculated by dividing the actual yield by the theoretical yield and multiplying by 100.

percent yield = 0.49/0.53 * 100 = 92.4%

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The final volume of the system, given that half of the gas is removed, leaving 0.50 mole in the cylinder and the system is warmed to 900 K is 18.45 liters

From ideal gas equation, we have

PV = nRT

Rearrange

V / nT = R/ P

R / P = Constant

Thus, we have

V₁ / n₁T₁ = V₂ / n₂T₂

Where

With the above formula, we can obtain the final volume of the system as follow:

V₁ / n₁T₁ = V₂ / n₂T₂

12.3 / (1 × 300) = V₂ / (0.5 × 900)

Cross multiply

1 × 300 × V₂ = 12.3 × 0.5 × 900

300 × V₂ = 5535

Divide both side by 300

V₂ = 5535 / 300

V₂ = 18.45 liters

Thus, the final volume of the system is 18.45 liters

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The best description of cis-trans isomers is that they differ in their spatial arrangement around inflexible double bonds. Option E is correct.

Specifically, cis-trans isomers are a type of stereoisomers that have the same molecular formula and the same covalent bonds but differ in the spatial arrangement of their atoms due to the inflexibility of a double bond. In cis isomers, the two substituents on each carbon atom are on the same side of the double bond, while in trans isomers, the two substituents on each carbon atom are on opposite sides of the double bond.

This results in different physical and chemical properties for the two isomers. For example, cis and trans isomers of some compounds may have different boiling points, melting points, and reactivities.  Cis-trans isomerism is an important concept in organic chemistry as it affects the properties and behavior of molecules and can have significant implications for their biological activity, environmental fate, and industrial applications. Option E is correct.

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Answer:

see in your book properly

Answer:

2812.6 g of H₂SO₄

Explanation:

From the question given above, the following data were obtained:

Mole of H₂SO₄ = 28.7 moles

Mass of H₂SO₄ =?

Next, we shall determine the molar mass of H₂SO₄. This can be obtained as follow:

Molar mass of H₂SO₄ = (1×2) + 32 + (16×4)

= 2 + 32 + 64

= 98 g/mol

Finally, we shall determine the mass of H₂SO₄. This can be obtained as follow:

Mole of H₂SO₄ = 28.7 moles

Molar mass of H₂SO₄ =

Mass of H₂SO₄ =?

Mole = mass / Molar mass

28.7 = Mass of H₂SO₄ / 98

Cross multiply

Mass of H₂SO₄ = 28.7 × 98

Mass of H₂SO₄ = 2812.6 g

Thus, 28.7 mole of H₂SO₄ is equivalent to 2812.6 g of H₂SO₄

the answer should be a the the question

First, we need to determine the mass of water in the pool:

mass = density x volume

density of water = 1000 kg/m³

volume = length x width x depth

volume = 10.0 m x 4.0 m x 3.0 m = 120 m³

mass = 1000 kg/m³ x 120 m³ = 120000 kg

Next, we need to calculate the heat required to raise the temperature of the water:

q = m x c x ΔT

where q is the heat energy, m is the mass of water, c is the specific heat of water, and ΔT is the change in temperature.

c = 4.18 J/g°C (specific heat of water)

ΔT = 27.3°C - 20.2°C = 7.1°C

m = 120000 kg

q = 120000 kg x 4.18 J/g°C x 7.1°C = 35792400 J

Next, we need to convert the energy required to burn methane to heat energy:

-891 kJ/mol x (1 mol CH4/160 g CH4) x (1000 g/1 kg) = -5.569 kJ/g

We can now calculate the amount of methane needed:

energy = -5.569 kJ/g x mass CH4

mass CH4 = energy / (-5.569 kJ/g)

mass CH4 = 35792400 J / (-5569 J/g) = -6431.6 g

At STP, 1 mole of any gas occupies 22.4 L of volume. We can use this to convert the mass of methane to volume at STP:

1 mol CH4 = 16 g CH4

-6431.6 g CH4 x (1 mol CH4/16 g CH4) x (22.4 L/1 mol CH4) = -9074.4 L

Since we cannot have a negative volume, we can take the absolute value of the result:

|9074.4 L| = 9074 L

Therefore, approximately 9074 liters of methane gas at STP must be burned to raise the temperature of the water in the pool from 20.2°C to 27.3°C.

In the salt bridge, anions migrate from the F-|F2

The anode reaction is :

2I^-(aq) -------> I2(g) +2e

Cathode reaction

F2(g) + 2e------> 2F^-(aq)

In the external circuit, electrons migrate from the I-|I2 electrode (anode) to the F-|F2 electrode (cathode)

In the salt bridge, anions migrate from the F-|F2

Oxidation occurs at the anode while reduction occurs at the cathode. Anode is a positive electrode in this case, whereas cathode is a negative electrode. Oxidation occurs at the anode while reduction occurs at the cathode. The species that are oxidising provide the electrons. Any electrode where oxidation occurs is an anode. Water electrolysis is one straightforward example. The anode is a platinum electrode that is positively charged and used to convert H2 gas into H+ ions.

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According to our reactions:

1) Li(s) + O2(g) ==> Li2O(s)

It is a Redox reaction, Li is oxidized and O is reduced. We have here loss and gain of electrons.

2) It is a precipitation reaction because when the PbI2 is formed, it precipitates.

3) This is the reaction of an acid with a base, so it is an acid/base reaction.

Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

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