The ABC Corporation manufactures and sells two products: T1 and T2. 20XX budget for the company is given below:
Projected Sales Units Price T1 60,000 $165 T2 40,000 $250
Inventories in Units January 1, 20XX December 31, 20XX T1 20,000 25,000 T2 8,000 9,000
The following direct materials are used in the two products: Amount used per unit Direct Material Unit T1 T2 A pound 4 5 B pound 2 3 C each 0 1
Anticipated Inventories Direct Material Purchase Price January 1, 2012 December 31, 2012 A $12 32,000 lb. 36,000 lb. B $5 29,000 lb. 32,000 lb. C $3 6,000 units 7,000 units
Projected direct manufacturing labor requirements and rates for 20XX are as follows: Hours per Unit Rate per Hour T1 2 $12 T2 3 $16
4
Manufacturing overhead is allocated at the rate of $20 per direct manufacturing labor-hour. Marketing and distribution costs are projected to be $100,000 and $ 300,000, respectively.
a. What is the total expected revenue (in dollars) for 20XX? b. What is the expected production level (in units) both for T1 and T2? c. What is the total direct material purchases (in dollars) for each type of direct material? d. What is the total direct manufacturing labor cost (in dollars)? e. What is the total overhead cost (in dollars)? f. What is the total cost of goods sold (in dollars)? g. What is the total expected operating income (in dollars) for 20XX?
Answers
Answer:
The ABC Corporation
a) Total Expected Revenue (in dollars) for 20XX:
Revenue from T1 = 60,000 x $165 = $26,400,000
Revenue from T2 = 40,000 x $250 = $10,000,000
Total Revenue from T1 and T2 = $36,400,000
b) Production Level (in units) for T1 and T2
T1 T2
Total Units sold 160,000 40,000
Add Closing Inventory 25,000 9,000
Units Available for sale 185,000 49,000
less opening inventory 20,000 8,000
Production Level 165,000 units 41,000 units
c) Total Direct Material Purchases (in dollars):
Cost of direct materials used T1 T2
A: (165,000 x 4 x $12) $7,920,000 $2,460,000 (41,000 x 5 x $12)
B: (165,000 x 2 x $5) 1,650,000 615,000 (41,000 x 3 x $5)
C: 0 123,000 (41,000 x 1 x$3)
Total cost $9,570,000 $3,198,000 Total = $12,768,000
Cost of direct per unit = $58 ($9,570,000/165,000) for T1 and $78 ($3,198,000/41,000) for T2
Cost of direct materials used for production $12,768,000
Cost of closing direct materials:
A (36,000 x $12) $432,000
B (32,000 x $5) 160,000
C (7,000 x $3) 21,000 $613,000
Cost of direct materials available for prodn $13,381,000
Less cost of beginning direct materials:
A (32,000 x $12) $384,000
B (29,000 x $5) 145,000
C (6,000 x $3) 18,000 $547,000
Cost of direct materials purchases $12,834,000
d) The Total Direct Manufacturing Labor Cost (in dollars):
T1 T2
Direct labor per unit 2 hours 3 hours
Direct labor rate per hour $12 $16
Direct labor cost per unit $24 $48
Production level 165,000 units 41,000 units
Labor Cost ($) $3,960,000 $1,968,000
Total labor cost $5,928,000 ($3,960,000 + $1,968,000)
e) Total Overhead cost (in dollars):
Overhead rate = $20 per labor hour
Overhead cost per unit: T1 = $40 ($20 x 2) and T2 = $60 ($20 x 3)
T1 overhead = $20 x 2 x 165,000) = $6,600,000
T2 overhead = $20 x 3 x 41,000) = $2,460,000
Total Overhead cost = $9,060,000
Cost of goods produced:
Cost of opening inventory of materials = $547,000
Purchases of directials materials 12,834,000
less closing inventory of materials = $613,000
Cost of materials used for production 12,768,000
add Labor cost 5,928,000
add Overhead cost 9,060,000
Total production cost $27,756,000
f) Total cost of goods sold (in dollars):
Cost of opening inventory = $3,928,000
Total Production cost = $27,756,000
Cost of goods available for sale $31,684,000
Less cost of closing inventory $4,724,000
Total cost of goods sold $26,960,000
g) Total expected operating income (in dollars)
Sales Revenue: T1 and T2 $36,400,000
Cost of goods sold 26,960,000
Gross profit $9,440,000
less marketing & distribution 400,000
Total Expected Operating Income = $9,040,000
Explanation:
a) Cost of beginning inventory of finished goods:
T1, (Direct materials + Labor + Overhead) X inventory units =
T1 = 20,000 x ($58 + 24 + 40) = $2,440,000
T2 = 8,000 ($78 + 48 + 60) = $1,488,000
Total cost of beginning inventory = $3,928,000
b) Cost of closing Inventory of finished goods:
T1 = 25,000 x ($58 + 24 + 40) = $3,050,000
T2 = 9,000 ($78 + 48 + 60) = $1,674,000
Total cost of closing inventory = $4,724,000
Related Questions
1. A parabolic lens focuses light onto a focal point 3 centimeters from the vertex of the lens. How wide is the lens 0.5 centimeters from the vertex? 2. If the light from a lamp casts a hyperbolic shadow pattern on the wall, calculate the equation of the hyperbola if the distance between the vertices is 2 feet and the foci are half a foot from the vertices.
Answers
1. The width of the lens 0.5 centimeters from the vertex is 6 centimeters.
1. To find the width of the lens 0.5 centimeters from the vertex, we can use the property of a parabolic lens that states the distance from the vertex to the focal point is equal to half the width of the lens.
Given:
Distance from vertex to focal point (f) = 3 centimeters
Let's denote the width of the lens as "w". According to the property mentioned above, we can write the equation as:
f = w/2
Substituting the given value of f, we have:
3 = w/2
To find the width of the lens, we can solve the equation for "w":
w = 3 * 2 = 6 centimeters
Therefore, the width of the lens 0.5 centimeters from the vertex is 6 centimeters.
2. To find the equation of the hyperbola with the given information, we need to determine the coordinates of the vertices and the distance between the foci.
Given:
Distance between the vertices (2a) = 2 feet
Distance between the foci (2c) = 0.5 feet
The distance between the center of the hyperbola and each focus is given by the relation: c^2 = a^2 + b^2, where "a" is the distance from the center to each vertex, and "c" is the distance from the center to each focus.
Since we are given 2a = 2 feet and 2c = 0.5 feet, we can solve for "a" and "c" as follows:
2a = 2
a = 1 foot
2c = 0.5
c = 0.25 feet
Now, we can write the equation of the hyperbola in standard form:
(x^2 / a^2) - (y^2 / b^2) = 1
Substituting the values of "a" and "c", we have:
(x^2 / 1^2) - (y^2 / b^2) = 1
(x^2) - (y^2 / b^2) = 1
The equation of the hyperbola is (x^2) - (y^2 / b^2) = 1. The specific value of "b" is not given in the provided information, so we cannot determine the exact equation of the hyperbola without additional information.
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Consider the following parameters of a virtual memory system: Virtual Address (bits): 33 Page Size: 4 KB PTE Size (byte): 4 For a single-level page table, how many page table entries (PTE) are needed? For a single-level page table, how much physical memory is needed for storing the page table?
Answers
8 MB Physical memory needed to storing for page table.
How to solveGiven
Virtual address = 33 bit.= 2³³ B
Page Number (P) Page Size (d)
21 12
Page Size = 4KB= 4*2¹⁰ B= 2²*2¹⁰ B (12 bit)
( 1K = 2¹⁰).
Total Number of Page (P) =
Virtual address Size/ Page Size
= 2³³B/ 2¹²B
= 2²¹ .
Page Table data structure used to mapping between Virtual Address and Physical Address.
page table contains all information about every page in PTE (Page Table Entry) .
In one PTE contain information of one page.
Size of Page Table
= Number of Page * Size of PTE
= 2²¹ * 4 B
= 2²¹ * 2² B
= 2²³ B
= 2³ MB. ( 1M = 2²⁰)
= 8MB.
8 MB Physical memory needed to storing for page table.
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What is the importance of food handling machines in food industry (Explain in points).
Answers
Answer:
Explanation:
Profile photo for Rosie Milojevic
Rosie Milojevic, Business Development at iComplied
Answered 3 years ago
For those who run or work in a business that handles food, you understand the importance of food safety and regulation compliance as it pertains to not only to certification and licensing of a company, but also the life or death of those who consume the products. Because food safety is such an important issue, we want to ensure that all companies who work in the production, preparation, or processing of food have the tools and information they need to ensure they are in full compliance 100% of the time. One slip in food safety compliance could cost someone their health or life, and this information spreads mistrust in the general public toward the company who sold the product, and also the entire product across companies throughout an entire country and beyond. So how does each company working with food ensure they comply with each and every food safety regulation? Through excellent auditing tools.
Auditing in Food Safety Must Change
Auditing in food safety compliance is essential in ensuring that all regulations are being complied with. Most auditing practices for major companies are severely out of date. Many rely on several different forms, stacks of paperwork, and data stored on multiple different computers and databases. This is incredibly inefficient, as it can be easy to miss something when comparing one sheet to the next, and paper can easily be lost or destroyed. It is also time consuming for companies to share audits over separate computers and databases, as it must be passed down from one employee to the next. Technology has granted all food safety compliance managers a simple solution. Auditing apps are the new wave solutions for companies who want all of their data stored on one cloud database that is instantly accessible with real-time data for all employees. This means that no one ever gets left out of the loop, and no new information will fall through the cracks.
_____ are NOT considered road users.
Answers
Answer: gas station employees
Explanation:
their not using the road
The employees and workers of a gas station and small aircraft pilots are not considered as road users. Road users are the people such as drivers and pedestrians who uses the road.
Who are Road users?Road users include both the drivers as well as the pedestrians and cyclists. Their behavior is the area which has by far the biggest potential for improving the road safety. Road users means a motorist, passenger, public transportation operator, or user, truck driver, bicyclist, motorcyclist, or pedestrian, including a person with disabilities as well.
The important characteristics of the road user include intelligences, skills, experience, knowledge and literacy. Proper knowledge of the vehicle characteristics, the driving practices, rules of roads and traffic behavior are necessary for the purpose of safe traffic operations.
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what is the interval distance between cleanouts along a lateral line
Answers
The correct answer is There must be cleanouts every 100 feet along the sewer lateral run.
Every 100 feet along large sections of pipe, a cleanout is necessary. This measurement is made from the point where the horizontal drainage pipe connects to the building sewer to its highest point. Except for cleanouts for pipe bigger than 4 inches (102 mm), which need not be greater than 4 inches, cleanouts must be the same size as the piping they service (102 mm). It will probably emerge from the earth outside of your house, somewhere between the foundation and the street. The area closest to the bathroom on the side of the house may also be where the cleanout is. Although these are uncommon for most homes, cleanout access ports might potentially be concealed by drywall or positioned in the basement.
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abdulla hired granite construction to build an addition onto his home. granite construction dug the foundation but then abandoned the project. granite construction has substantially performed as they started the job, and is entitled to receive the full contract price minus the value of the defects.
Answers
The provided case is false since abdulla did not commission Granite Construction to build an addition to his house. Rock Construction dug the structure, but later abandoned the project. With the exception of the estimated defects, Stone Construction is eligible to receive the full contract amount.
What is full contract amount?The total sum that is obligated under this Agreement for any payments made by the State to the Contractor for the completion of the Work in accordance with the Contract Documents is referred to as the "Contract Amount." The lifetime worth of a contract is referred to by the term total contract value, which is also known as contract value. TCV gives organisations the ability to accurately assess the annual contract value (your company's annual contract value) and the cost of your customer acquisition initiatives. Knowing the worth of your contract gives you the ability to create a successful plan that will ultimately help your business. In this article, we'll explain what TCV is, how to calculate it, and other helpful hints and suggestions for using it.
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Explain any three ways research can facilitate the work of building technicians
Answers
According to the research, research can facilitate the work of building technicians in the conception, materials to use and planning of the project.
What are building technicians?They are experts in construction projects, supporting the design of plans, estimating costs, planning work methods, etc.
Research can facilitate the work of building technicians in the following ways:
Conception, design and planning of the project.Selection of materials for floor, wall and ceiling systems.Carry out the programming of works, budgets and analysis of unit prices.Therefore, we can conclude that according to the research, research can facilitate the work of building technicians in the conception, materials to use and planning of the project.
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.Tech A says that unitized hubs have a wheel nut with a higher installation torque than
serviceable wheel bearings. Tech B says that unitized hubs have the proper bearing end
play designed into the assembly once they are torqued properly. Who is correct?
a. Tech A
b.
Tech B
C
Both a and b
D
Neither a and d
Answers
Tech A says that unitized hubs have a wheel nut with a higher installation torque than serviceable wheel bearings. Tech B says that unitized hubs have the proper bearing end play designed into the assembly once they are torqued properly is Option C: Both a and b
Describe a wheel bearing?When compared to manually adjusted, PreSet, or LMS hub assemblies, unitized hub assemblies often require a lot more assembly torque and special spindle nut systems.
Therefore, An essential component of the wheel assembly that connects the wheel to the axle is a wheel bearing. A metal ring is used to hold a group of steel balls (also known as ball bearings) or taper (also known as tapered bearings) together. It permits the wheel to spin easily and with little resistance.
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If you’re shopping for a rack switch, what component on the switch tells you it can be mounted to a rack? a. AC adapter b. Rack ears c. Padded feet d. Large fans
Answers
The correct answer is b. Rack ears. Rack ears are the pieces of metal on the sides of the switch that enable it to be mounted to a rack. They are adjustable and allow the switch to fit securely into the rack.
What is metal?Metal is a type of material made up of many small particles that are tightly packed together. It is a hard, dense material that is highly versatile and can be used for a wide range of applications. Metals are typically composed of iron, nickel, cobalt, or other metallic elements. Metal is strong and can be used to create durable and long-lasting products, such as tools and furniture. Metal is also malleable and can be shaped into a variety of forms. It is also highly conductive, meaning it can transmit electricity, heat, and sound. Metals can be polished to create a glossy finish and are often used in jewelry and other decorative items. Additionally, metals are used in automotive, aerospace, and other industrial applications due to their strength and durability.
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A simply supported beam \( A B \) is subjected to couples \( M_{1} \) and \( 3 M_{1} \) acting as shown in the figure. Determine the maximum magnitude of the shear force in the beam if \( M_{1}=60 \ma
Answers
Given, Simply supported beam AB is subjected to couples M1 and 3M1 as shown below:
The beam can be represented as shown in the below figure:
Determine the maximum magnitude of the shear force in the beam,
if M1 = 60 N-m.
The free body diagram of the simply supported beam AB can be represented as shown in the below figure:
can observe that the beam is symmetric about the midpoint ‘C’.
Hence, the reactions at point A and B are equal and have opposite directions.
The reaction at point C is equal to zero.
The moment equation about point A can be given as:
M1 + RAX × L1/2 + 3M1 = 0RAX = -4/3 M1/L1
Where,
L1 = L/2
From the above equation, we can find that RAX is negative.
This implies that it is acting in the opposite direction to that which is shown in the figure.
The moment equation about point B can be given as:
RBY × L1/2 - M1 - 3M1 = 0RBY = 8/3 M1/L1
The moment equation about point C can be given as:
M1 × L/4 - RBY × L/4 = 0
Now, we can determine the values of RAX, RBY and MC using the above equations.
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From a tension test, the experimental data (true strain – true stress) are: True Strain True Stress (MPa) 0.01 69.0 0.03 119.5 0.06 169.0 0.1 218.2 0.15 267.2 0.2 308.6 0.25 345.0 0.3 378.0 0.35 408.2 0.4 436.4 0.45 462.9 0.5 488.0 0.8 617.0 Define the Strength coefficient (K) and strain hardening exponent (n) representing a power law true stress/strain curve (σ=KƐ n )
Answers
we have to calculate the strength coefficient (K) and strain hardening exponent (n) representing a power law true stress/strain curve (σ=Kɛⁿ).To determine the strength coefficient (K), we have to take the antilogarithm of the intercept of the fitted curve (log σ = n log ɛ + log K) of a true stress-true strain curve, which is obtained from the plotted data.
The strain hardening exponent (n) is the slope of the fitted curve log σ = n log ɛ + log K. In other words, it is the slope of the graph plotted between the true stress (σ) and the true strain (ɛ) taken in logarithmic scales.Using the experimental data above, we can calculate the strength coefficient (K) and strain hardening exponent (n) as follows:It can be seen that the slope of the graph plotted between the true stress (σ) and the true strain (ɛ) is given by the slope of the line joining the points on the curve. Using two points (0.06, 169) and (0.5, 488), we can obtain the slope:Thus, the strain hardening exponent (n) is 0.44 (approximately).
The strength coefficient (K) is calculated as the antilogarithm of the y-intercept of the straight line.Using the values of n and intercept from above, we have:K = 69.0/0.06⁰.⁵⁷= 408.74Thus, the strength coefficient (K) and strain hardening exponent (n) representing a power law true stress/strain curve (σ=Kɛⁿ) are approximately 408.74 MPa and 0.44 respectively.
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Who is the first engineer of world ? and why?
Answers
Answer:
Imhotep
Explanation:
The first engineer known by name and achievement is Imhotep because he had builded the step pyramid of Egypt.
how to answer for computer science quora how do your interests directly connect with cornell engineering? if you have an intended major, what draws you to that department at cornell engineering? if you are unsure what specific engineering field you would like to study, describe how your general interest in engineering most directly connects with cornell engineering. it may be helpful to concentrate on one or two things that you are most excited about\.\* (250 words)
Answers
Focus primarily on highly precise specifics of what Cornell offers and how it matches with your interests and values. You can regard this as a "Why us?" essay with some optional "Why major" spice.
How to write essay ?Cornell is fundamentally a research institution, and I am fundamentally a researcher. The Collective Embodied Intelligence Lab would be the ideal place for me to put what I have learned from my own work in that area to use while learning from Dr. Petersen and her ground-breaking research in termite-inspired construction robots. The lab focuses on the control of multi-agent robotic systems, especially drawing inspiration from insect swarm mechanics. Cornell is known for its research, but what truly stood out to me was its distinct dedication to project teams. I discovered I wanted to join every team after doing my homework on them. Consider Baja; the idea of creating an off-road car from scratch is comparable to FTC competitions. Even though I have a strong foundation in CAD, wiring, and chassis construction, I'm eager to tackle more complex issues with even more room for creativity.To learn more about essay refer :
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Identify the 3 levels of braking that precede the need to lock up your wheels?.
Answers
When it comes to driving a car, braking is a very important skill to have. Braking is the process of slowing down or stopping a moving vehicle. Knowing how to brake effectively can be the difference between avoiding a crash and causing one.
Below are the three levels of braking that precede the need to lock up your wheels:
1. Perception braking: This is the first level of braking that precedes the need to lock up your wheels. Perception braking refers to the driver's ability to recognize the need to brake in response to a situation. This type of braking is necessary when you notice a potential hazard on the road, such as a pedestrian, a cyclist, or another car. Perception braking requires that you react quickly to the situation and apply the brakes as soon as possible.
2. Controlled braking: The second level of braking that precedes the need to lock up your wheels is controlled braking. This type of braking requires that you apply the brakes firmly but smoothly. The idea is to slow down the vehicle without locking up the wheels. Controlled braking is essential when you are driving on a wet or slippery road surface, as it allows you to slow down the car without losing control.
3. Threshold braking: The third level of braking that precedes the need to lock up your wheels is threshold braking. This is the most advanced form of braking and requires a lot of skill and experience. Threshold braking involves applying the brakes to the point just before the wheels start to lock up. At this point, the driver eases off the brakes slightly to maintain traction and control. Threshold braking is the most effective form of braking in emergency situations, as it allows the driver to slow down the vehicle quickly without losing control.
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a simple ideal rankine cycle with water as the working fluid operates the boiler at 2500 psia and the condenser at 5 psia. What is the minimum temperature required at the turbine inlet such that the quality of the steam leaving the turbine is not below 80 percent. When operated at this temperature, what is the thermal efficiency of this cycle?
Answers
The minimum temperature required at the turbine inlet is approximately X degrees Celsius, ensuring the steam leaving the turbine maintains a quality of at least 80%. The thermal efficiency of the cycle, when operated at this temperature, is approximately Y%.
To determine the minimum temperature at the turbine inlet, we need to consider the steam conditions at the turbine exit. Given that the steam quality should be at least 80%, we know that 80% of the mass flow rate will be in the vapor phase, and 20% will be in the liquid phase.
The saturation pressure at the condenser operating pressure of 5 psia can be found using steam tables. Once we have the saturation pressure, we can determine the corresponding temperature.
By applying the first law of thermodynamics, we find the work output of the turbine. From the turbine work and the enthalpy of the steam at the turbine exit, we can determine the enthalpy at the turbine inlet using the steam tables.
Finally, using the enthalpy at the turbine inlet, along with the given boiler pressure of 2500 psia, we can determine the corresponding temperature at the boiler inlet.
The thermal efficiency of the Rankine cycle is the net work output divided by the heat input. The heat input can be calculated using the enthalpy difference between the boiler inlet and condenser exit, considering the mass flow rate and the specific heat of water.
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(a) What is the distinction between hypoeutectoid and hypereutectoid steels? (b) In a hypoeutectoid steel, both eutectoid and proeutectoid ferrite exist. Explain the difference between them. What will be the carbon concentration in each? (c) In bullet format compare and contrast the expected mechanical behavior of hypoeutectoid and hypereutectoid steels in terms of: (i) Yield strength (ii) Ductility (iii) Hardness (iv) Tensile strength (d) If you want to choose an alloy to make a knife or ax blade would you recommend a hypoeutectoid steel alloy or a hypereutectoid steel alloy? Explain your recommendation in 1-3 bullet points. (e) If you wanted a steel that was easy to machine to make a die to press powders or stamp a softer metal, would you choose a hypoeutectoid steel alloy or a hypereutectoid steel alloy? Explain your choice in 1-3 bullets.
Answers
Answer:
See explanation below
Explanation:
Hypo-eutectoid steel has less than 0,8% of C in its composition.
It is composed by pearlite and α-ferrite, whereas Hyper-eutectoid steel has between 0.8% and 2% of C, composed by pearlite and cementite.
Ferrite has a higher tensile strength than cementite but cementite is harder.
Considering that hypoeutectoid steel contains ferrite at grain boundaries and pearlite inside grains whereas hypereutectoid steel contains a higher amount of cementite, the following properties are obtainable:
Hypo-eutectoid steel has higher yield strength than Hyper-eutectoid steel
Hypo-eutectoid steel is more ductile than Hyper-eutectoid steel
Hyper-eutectoid steel is harder than Hyper-eutectoid steel
Hypo-eutectoid steel has more tensile strength than Hyper-eutectoid steel.
When making a knife or axe blade, I would choose Hyper-eutectoid steel alloy because
1. It is harder
2. It has low cost
3. It is lighter
When making a die to press powders or stamp a softer metals, I will choose hypo-eutectoid steel alloy because
1. It is ductile
2. It has high tensile strength
3. It is durable
Answer:
(a)
Steels having carbon within 0.02% – 0.8% which consist of ferrite and pearlite are known as hypoeutectoid steel.
Steels having greater than 0.8% carbon but less than 2.0% are known as hypereutectoid steel.
(b)
The proeutectoid ferrite formed at a range of temperatures from austenite in the austenite+ferrite region above 726°C. The eutectoid ferrite formed during the eutectoid transformation as it cools below 726°C. It is a part of the pearlite microconstiutents . Note that both hypereutectoid and hypoeutectoid steels have proeutectoid phases, while in eutectoid steel, no proeutectoid phase is present.
Proeutectoid signifies is a phase that forms (on cooling) before the eutectoid austenite decomposes. It has a parallel with primary solids in that it is the first phase to crystallize out of the austenite phase. If the steel is hypoeutectoid it will produce proeutectoid ferrite and if it is hypereutectoid it will produce proeutectoid cementite. The carbon concentration for both ferrites is 0.022 wt% C.
(c)
(i) Yield strength: The hypoeutectoid steel have good yield strength and hypereutectoid steels have little higher yield strengh.
(ii) Ductility: The hypoeutectoid steel is more ductile and the ductility has decreased by a factor of three for the eutectoid alloy. In hypereutectoid alloys the additional, brittle cementite on the pearlite grain boundaries further decreases the ductility of the alloy. The proeutectoid cementite restricts plastic deformation to the ferrite lamellae in the pearlite.
(iii) Hardness: hypoeutectoid steels are softer and hypereutectoid steel contains low strength cementite at grain boundary region which makes it harder than hypoeutectoids.
(iv) Tensile strength: Grain boundary regions of hypereutectoid steel are high energy regions prone to cracking because of cementite in the grain boundaries, its tensile strength decreases drastically even though pearlite is present. Hypoeutectoid steel contains ferrite at grain boundaries and pearlite inside grains, so grain boundaries being the high energy state region, it has a higher tensile strength.
(d)
I would recommend hypereutectoid steel alloy to make a knife or ax blade
1- Hardness is required at the surface of the blades.
2- Ductility is not needed for such application.
3- Due to constant impact, the material will not easily yield to stress.
(e)
I would choose a hypoeutectoid steel alloy to make a steel that was easy to machine.
1- hypoeutectoid steel alloys have high machinability, hence better productivity
2- It will be used on softer metals, hence its fitness for the application
3- Certain amount of ductility is required which hypoeutectoid steel alloys possess.
Explanation:
See all together above
Think about how could you design, build, and test a light maze. What specific behavior of light will be essential to the success of your design It is due today
Answers
Answer:
Reflection
Explanation:
The specific behavior of light that will be essential to ensure the success of your design is "Reflection". This is because light maze makes use of a mirror and it's the light that is reflected that we see with our eyes. Also, the manner in which light is reflected off objects will affect the colors that are reflected as well.
Forces always act in equal and opposite pairs
Answers
a two-wire copper transmission line is embedded in a dielectric material with
Answers
We can see here that a two-wire copper transmission line is embedded in a dielectric material with a relative permittivity (dielectric constant) of εr.
What is a dielectric material?A substance or medium that has the capacity to isolate or separate electrical charges and obstruct the flow of electricity is referred to as a dielectric material.
The dielectric substance acts as an insulator and supports the transmission line structure, while the copper wires are employed to transfer electrical impulses.
We can say that embedding a two-wire copper transmission line in a dielectric material with a specific relative permittivity provides insulation, minimizes interference, and influences the electrical characteristics of the transmission line.
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cse/eee 120 capstone design project home security gate controller project summary the goal of this project is to design a gate controller for a home security system. the project is now in the prototype stage, where a simplified version of the home security system will be built. the system operates in the following manner:
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We created a program that alternates between the localization, steering, and navigation modules. The navigation module implements a routing algorithm and selects the global route.
What is program?A program is described as a set of instructions that a computer executes to do a certain activity. Study programs are made to fit your specific learning needs and get you ready for more education, training, or work.
Navigation modules are defined as the interactions that let users move between, inside of, and outside of the various pieces of content in your app. Extra parts are frequently included in the modules to make the sensor easier to use.
Thus, we created a program that alternates between the localization, steering, and navigation modules. The navigation module implements a routing algorithm and selects the global route.
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The extraction of oil from groundnut paste with hexane is shown as a single stage operation as follows:
Suppose that the feed composition is 36% oil and 64% inert solids and that pure hexane is to be used in the extraction. In one trial, 3 kg of hexane was used per kg of feed. The composition of the extract was 32% oil and no inert solid. It is also known that each kg of inert solids retains 1.8 kg of solution. Represent the following compositions on a right-angled diagram:
(a) The feed
(b) The extract
(c) Underflow (raffinate)
(d) The initial mixture of feed and the solvent
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The diagram for the extraction to represent the information given is attached.
What is extraction?Extraction refers to the process of obtaining or removing something from a particular source or location. It can refer to various fields such as chemistry, physics, medicine, and data analysis.
In chemistry, extraction is the process of separating a particular component or substance from a mixture using various methods such as solvent extraction, distillation, or chromatography. In physics, extraction can refer to the removal of energy or particles from a system. In medicine, extraction refers to the removal of a tooth or a foreign object from the body. In data analysis, extraction refers to the process of retrieving specific data or information from a large set of data.
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Write a for loop to populate vector userGuesses with NUM_GUESSES integers. Read integers using cin. Ex: If NUM_GUESSES is 3 and user enters 9 5 2, then userGuesses is {9, 5, 2}.
#include
#include
using namespace std;
int main() {
const int NUM_GUESSES = 3;
vector userGuesses(NUM_GUESSES);
int i = 0;
/* Your solution goes here */
return 0;
}
Answers
The following code snippet can be used to write a for loop to populate vector userGuesses with NUM_GUESSES integers:```
#include
#include
using namespace std;
int main() {
const int NUM_GUESSES = 3;
vector userGuesses(NUM_GUESSES);
int i = 0;
for(i = 0; i < NUM_GUESSES; i++) {
cin >> userGuesses[i];
}
return 0;
}
```Here, the for loop starts with i=0, and it will continue until i is less than NUM_GUESSES. Inside the loop, userGuesses[i] is read from the standard input using cin statement. Finally, the userGuesses vector is populated with NUM_GUESSES integers.
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explain why brittle materials crack when exposed to large stress concentrations that does not fracture ductile materials.
Answers
A crack in a brittle material adds a lot of stress to its tip. one way to prevent such a crack from progressing is to drill a hole. at the end of the crack to increase its radius and thus reduce the stress. fracture occurs in a brittle material when the stress concentration exceeds the reduction in strength of the material.
What is brittle material?Brittle materials are characterized by low deformation, poor resistance to impact and load-vibration, high compressive strength and low tensile strength. Most inorganic non-metallic materials are brittle materials.
Brittle materials include glass, ceramics, graphite, and some alloys that have very low ductility and where cracks can form without plastic deformation and can soon develop into brittleness.
A material is considered brittle when it breaks under tension with little elastic deformation and no significant plastic deformation.
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Which of the following are desirable characteristics of refractory ceramics?
a. Ability to remain unreactive and inert in severe environments.
b. Ability to withstand high temperatures.
c. Ability to withstand low temperatures.
d. High strengths.
e. Thermally insulative.
Answers
the following are desirable characteristics of refractory ceramics
a. Ability to remain unreactive and inert in severe environments.
b. Ability to withstand high temperatures.
d. High strengths.
e. Thermally insulative.
The ability to withstand high temperatures is essential for refractory ceramics, as they are often used in high-temperature applications such as furnaces and kilns. The ability to remain unreactive and inert in severe environments is also important to ensure that the material does not react with the surrounding environment or other materials in the system, which could lead to degradation or failure of the component. High strength is desirable to prevent fracture or deformation under mechanical loads. Lastly, being thermally insulative is useful for applications where heat needs to be contained or controlled within a given space.
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while on an ifr flight, a pilot emerges from a cloud to find himself within 300 feet of a helicopter. which of the following alternatives best illustrates the 'macho' reaction?
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While on an IFR flight, a pilot emerges from a cloud to find himself within 300 feet of a helicopter. He flies a little closer, just to show him 'macho' reaction.
The term "IFR" refers to the set of regulations that apply to aircraft flying under IMC, or instrument meteorological conditions. Instrument flying, in its broadest sense, entails cloud-based flight. Weather that is "below the minimums prescribed for flying under Visual Flight Rules" is more specifically referred to as IMC.
Instrument flight is so named because the pilot exclusively uses the instruments in the cockpit to navigate. IMC (flying in the clouds) requires an instrument rating and an IFR flight plan.
Without any outside references, flying by instruments sounds risky, but with the right training, it's really safe. Training involves instruction in the use of navigational aids such VORs, ADF, and GPS, as well as instrument landing system approach flying (ILS).
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What are the differences of the 2 rectifiers in terms of its
output?
State the importance of a capacitor filter in a power supply
circuit. How does it perform filtering?
How does a Full-Wave Rectifier
Answers
A rectifier is an electrical device that converts alternating current (AC) to direct current (DC).
There are two types of rectifiers: half-wave rectifiers and full-wave rectifiers.
The difference between the two rectifiers in terms of its output is that a full-wave rectifier produces a smoother output than a half-wave rectifier.
A full-wave rectifier produces a DC output that is close to the peak value of the AC input, while a half-wave rectifier alternating a DC output that is half the peak value of the AC input.
capacitor filter is an essential component of a power supply circuit.
The primary function of a capacitor filter is to smooth out the DC voltage that is produced by the rectifier.
It performs this function by charging and discharging the capacitor at the same rate as the AC input.
This charging and discharging process helps to remove any ripples that might be present in the output voltage of the rectifier.
A full-wave rectifier is a type of rectifier that produces a DC output that is close to the peak value of the AC input.
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When handling chemicals and solvents, technicians are recommended to
Answers
Answer:
To wear PPEHave prior knowledge of explosive levels and elemental propertiesKnow procedure to eliminate any threatAnswer
have PPE on wash hands after
Explanation:
Kim deposits her annual bonus into a savings account that pays 8% interest compounded annuallyThe size of her bonus increases by $2,000 each year, and the initial bonus amount is $5,000. Determine how much will be in the account immediately after the fifth deposit
Answers
The amount that would be in Kim's account immediately after the fifth deposit would be $50,998.0
How to find the amount that would be in the accountWe have the amount in Year 0 to be the first deposit. This is given as $5000.
The formula used to calculate this is
P x (1+r) + T
Where P = principal
r = interest rate, hence 1 + 8% = 1.08
T is the increases of 2000
The bonus is said to increase by 2000 every year
2000 + 5000 = $7000
In year 1.
5000 x 1.08 + 7000
= 12,400
In year 2 add 2000 to 7000
(12,400 * 1.08) + 9000
= 22,392
Do the same for year 3
(22,392 * 1.08) + 11,000
= 35,183.36
Do the same for the 4th year
(35,183.36 * 1.08) + 13,000
= $50,998.0288
Therefore we can see that after the deposit is done 5 times the account would have $50,998.02 in it
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Warfare strategizing is a(n)
activity.
select the best answer from the choices provided.
oa. intellectually rigorous
ob. spiritually demanding
oc. physically tiring
od. intuitive
Answers
Warfare strategizing is an intellectually rigorous activity that requires careful planning and analysis.
It involves evaluating different options and potential outcomes, and making informed decisions based on the available information. This process can be challenging and complex, as it requires a deep understanding of military tactics and a keen sense of judgment. Despite the mental demands of strategizing, it is a critical component of warfare and plays a crucial role in achieving victory. Warfare strategizing is an activity best described as (a) intellectually rigorous. It requires a deep understanding of military tactics, extensive knowledge of the enemy's strengths and weaknesses, and the ability to make strategic decisions under pressure. While it may also be spiritually demanding, physically tiring, or intuitive, the primary characteristic of warfare strategizing is its intellectual rigor.
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the platform in a two-point scaffold should be no more than _____ inches wide.
Answers
The platform in a two-point scaffold should be no more than 14 inches wide.
This is in accordance with OSHA regulations, which require the platform width to be at least 14 inches but no more than 20 inches. The reason for this is to ensure that workers have enough space to work comfortably while also reducing the risk of tripping or falling. Additionally, the platform should be level and secured properly to prevent any movement or instability. It's important to note that the weight capacity of the platform should also be taken into consideration to avoid overloading it. In summary, the platform width of a two-point scaffold should be within the range of 14-20 inches and must be properly secured and leveled for safe use.
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