The 1h nmr spectrum of a compound which has the molecular formula c6h12o2 is shown below. Draw its structure.

Among the given elements, Chlorine (symbol: Cl) has the highest (most negative) electron affinity.

Electron affinity is defined as the amount of energy released or absorbed when an electron is added to a neutral atom in the gaseous state to form a negative ion. Chlorine has an electron affinity of -349 kJ/mol, which is the highest among the given options.

Electron affinity is a physical property of an atom or a molecule that refers to the amount of energy released or absorbed when an electron is added to a neutral atom or molecule to form a negative ion. It is a measure of how much an atom or a molecule "likes" or attracts an additional electron.

Therefore, the correct answer is C. Cl.

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1) List the known and unknown quantities.

Volume: 208,000 gallons.

Density: 1.00 g/mL.

2) Convert gallons to liters.

3.7854 L = 1 gal.

3) Convert g/mL to pound/L

1 pound = 453.59 g

1000 mL = 1 L

4) Mass of water in kg.

5) Convert pounds to tons.

1 ton = 2000 pounds

The conversion factors needed are those in option D.

.

ANSWER

The arrow will be shifted to the right (OPTION B)

EXPLANATION:

Firstly, we need to write out the chemical reaction equation

From the reaction above, you will see that heat is one of the products, this means that the reaction is n exothermic reaction.

An exothermic reaction is a type of reaction in which heat is released to its surroundings.

In an exothermic reaction, a decrease in temperature will shift the equilibrium to the right

Using indicators at a certain point in each reaction the solution turned blue, indicating that a pH change had occurred due to increase in the hydroxide ion concentration.

Indicator is defined as a chemical substance which is chemically a weak acid or a weak base which changes it's color depending upon the concentration of hydrogen ions present in the solution.They dissociate slightly in water to produce ions.

These are generally derived from plant pigments and are of slightly acidic or basic in nature.There are three types of indicators:

1) natural indicators

2) synthetic indicators

3) olfactory indicators.

These are mainly used in determination of end point of titrations. Every indicator has it's pH range in which it can perform effectively.These are usually organic compounds.

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Answer:

Explanation:

The pH of a solution can be found by using the formula

\(pH = - log [ {H}^{+} ]\)

From the question we have

\(ph = - log(1.8 \times {10}^{ - 5} ) \\ = 4.7447\)

We have the final answer as

Hope this helps you

Answer: B) The half-life of Co-57 is 10 days

D) After twenty days have elapsed, about 25% of the Co-57 remains.

E) Scientists have an 8 gram sample of Co-57. After thirty days, 1 gram remains.

Explanation:

Answer:

yes 150.0grams = 150grams

The enthalpy of the reaction is 14 J/mol.

The enthalpy of a reaction (ΔH) is the amount of energy transferred between a system and its surroundings during a chemical reaction at constant pressure, measured in joules per mole (J/mol). This value is important because it can tell us whether a reaction is exothermic or endothermic, as well as give us information about the strength of chemical bonds within the reactants and products.To calculate the enthalpy of a reaction, we need to know the amount of energy released or absorbed (Q) and the number of moles of the compound involved in the reaction (n). We can use the equation:
ΔH = Q/n
Given that 6 moles of a compound produce 84 J of energy, we can calculate the enthalpy of the reaction as follows:
ΔH = Q/n
ΔH = 84 J / 6 mol
ΔH = 14 J/mol
This means that for every mole of the compound involved in the reaction, 14 J of energy is transferred between the system and the surroundings. Since the value is positive, we can conclude that the reaction is endothermic, meaning that it requires an input of energy to occur.It is worth noting that the enthalpy of a reaction can depend on a number of factors, such as temperature, pressure, and the specific conditions under which the reaction occurs. As such, it is important to take these factors into account when calculating or predicting enthalpy values.

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Answer

2,8,18,18,1

Explanation:

Answer:

The answer is Astronomy.

Explanation: Astronomy is the study of objects beyond the Earth’s atmosphere

The concentration of the NaOH solution is 10.00 g/dm³.

To calculate the concentration in g/dm³ of a solution of NaOH containing 0.25 moles in 1 dm³, we need to know the molar mass of NaOH.

The molar mass of NaOH is calculated as follows:

Na (Sodium) = 22.99 g/mol

O (Oxygen) = 16.00 g/mol

H (Hydrogen) = 1.01 g/mol

Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol

Now, we can calculate the concentration (C) using the formula:

C = (moles of solute) / (volume of solution in dm³)

C = 0.25 moles / 1 dm³

C = 0.25 mol/dm³

To convert moles to grams, we can multiply the molar mass by the number of moles:

Concentration in g/dm³ = (0.25 mol/dm³) * (40.00 g/mol)

Concentration in g/dm³ = 10.00 g/dm³

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Answer:

Answer: 227.5 grams

Explanation:

Answer:

227.5

Explanation:

Acellus

The volume of CO₂ generated under condition of STP in the reaction :

CaCO₃   +  2HCl   ----->   CaCl₂   +   H₂O   +   CO₂ is  12.5 mL.

The reaction is given as :

CaCO₃   +  2HCl   ----->   CaCl₂   +   H₂O   +   CO₂
mass of CaCO₃  = 750 mg = 0.75 g

molarity of HCl = 0.100 M

volume of HCl = 25 mL = 0.025 L

moles of CaCO₃  = 0.75 / 100

                            = 0.0075 mol

moles of HCl = 0.100 × 0.025

                       = 0.0025 mol

here HCl is limiting reagent , formation of CO₂ depends on HCl

2 moles of HCl = 1 mole of CO₂

0.0025 mol of HCl = 0.0025 / 2

                               = 0.00125 mol

volume of CO₂ = moles / molarity

                          = 0.00125 / 0.100

                         = 0.0125 L = 12.5 mL

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During an elimination reaction in organic chemistry, a new double bond (π bond) is formed, resulting in the creation of an alkene functional group. This process involves the removal of a leaving group and the adjacent hydrogen atom from a molecule, resulting in the formation of a double bond between the two adjacent carbon atoms.

In elimination reactions, a strong base or acid is often used to abstract the proton from the adjacent carbon atom, generating a carbanion intermediate. The leaving group is then expelled from the molecule, and the carbanion intermediate undergoes a rearrangement to form a more stable carbocation. Finally, the base or another molecule acts as a nucleophile, capturing a proton from the carbocation to form the double bond. This newly formed double bond represents the alkene functional group and is characteristic of elimination reactions in organic chemistry.

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Question id : 33544103

Answer:

To calculate the maximum β-energy in the decay of carbon-14 (14C) to nitrogen-14 (14N), we need to use the mass difference between the initial and final nuclei. The β-decay process involves the conversion of a neutron into a proton, emitting a β-particle (electron) and an electron antineutrino.

The mass difference (∆m) between 14C and 14N is given by:

∆m = mass(14C) - mass(14N)

= 14.003241u - 14.003074u

= 0.000167u

The β-energy (Eβ) is related to the mass difference (∆m) by Einstein's mass-energy equivalence equation: E = ∆mc^2, where c is the speed of light.

Eβ = ∆m * c^2

Now, we need to convert the mass difference (∆m) from unified atomic mass units (u) to kilograms (kg) before using it in the equation. The conversion factor is approximately 1.66053906660 × 10^−27 kg/u.

∆m_kg = ∆m * (1.66053906660 × 10^−27 kg/u)

Next, we'll calculate the β-energy by substituting the values into the equation:

Eβ = ∆m_kg * c^2

The speed of light (c) is approximately 2.998 × 10^8 m/s.

Eβ = ∆m_kg * (2.998 × 10^8 m/s)^2

Let's perform the calculations:

∆m_kg = 0.000167u * (1.66053906660 × 10^−27 kg/u)

≈ 2.77273363362 × 10^−29 kg

Eβ = (2.77273363362 × 10^−29 kg) * (2.998 × 10^8 m/s)^2

≈ 2.49344368869 × 10^−13 J

The maximum β-energy in the decay of 14C to 14N is approximately 2.493 × 10^−13 Joules.

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Answer:

que es un compuesto ionico

Explanation:

A supersaturated solution is a solution that contains more than the maximum amount of solute that is capable of being dissolved at a given temperature.

Answer:

c

Explanation:

Answer:

In the followings below, the one that doesn't attract to magnets is:

Option 4, Aluminum.

Explanation:

Mainly because of the aluminum's crystal structure.

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Answer:

Aluminum

Explanation:

Ferromagnetic Metals

Ferromagnetic metals and alloys are the only magnetic metals. Out of all of the elements on the periodic table, there are only 3 metals that are attracted to magnets: iron, nickel, cobalt.

Aluminum

Aluminum is a nonferrous metal (meaning not including iron or steel) that does not include any ferromagnetic metals. Additionally, aluminum itself is not magnetic, so there is no attraction between aluminum and a magnet.

The compound that will contain the most polar bond is D. chloroethane, H3CCH2Cl. This is because the bond between the carbon and chlorine atoms is more polar than the bonds between the carbon and hydrogen atoms in the other compounds. The polarity of a bond is determined by the difference in electronegativity between the atoms involved in the bond. Chlorine has a higher electronegativity than carbon, so the bond between them will be more polar. The other compounds listed have bonds between carbon and hydrogen atoms, which have a smaller difference in electronegativity and are therefore less polar.

Answer:A

Explanation:

The carbonate ion (CO₂³⁻) can be represented by three resonance structures.

Carbonate is a carbon oxoanion. It is a conjugate base of a hydrogencarbonate. ChEBI. Carbonate Ion is a polyatomic ion with formula of CO₃(²⁻).

Here are the three resonance structures for CO₂³⁻:

Structure with double bonds between carbon and two oxygen atoms:

O-C-O

Structure with double bonds between carbon and one oxygen atom, and a single bond with another oxygen atom:

O-C-O

Structure with double bonds between carbon and two oxygen atoms:

O-C-O

In reality, the actual structure of the carbonate ion is a combination or hybrid of these resonance structures, with the negative charge being delocalized over the three oxygen atoms. The image is given below.

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Warm, dark, and poorly-ventilated locations are generally not suitable for chemical storage. it can be stored in cool places most of the time.

In general, a location suitable for chemical storage should be:

Cool: Many chemicals are temperature-sensitive and can degrade or react with other substances if exposed to high temperatures.

Dry: Moisture can cause some chemicals to react or degrade, and can also increase the risk of fire or explosion if electrical equipment is present.

Well-ventilated: Proper ventilation is important to ensure that fumes or vapors generated by the chemicals are safely dispersed.

Away from sources of heat and ignition: Chemicals should be stored away from sources of heat, sparks, and flames, to minimize the risk of fire or explosion.

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Complete question:

in general, which characteristics are necessary for a location to be suitable for chemical storage? select one or more:

A. Warm

B. Dark

C. Dry

D. Poorly-ventilated cool

The molarity of the Isopropanol solution is 1.68 M.

Molarity of any solution can be calculated as:

M = n/V, where

n = no. of moles

V = volume = 1,250mL = 1.250L

For this first we have to calculate the moles of Isopropanol (C₃H₈O), and it can be calculated as:

n = W/M, where

W = mass of C₃H₈O = 127 grams

M = molar mass of C₃H₈O = 60.1 g/mol

Moles of C₃H₈O = 127g / 60.1 g/mol = 2.1 moles

Now, we calculate the molarity of solution by using the above formula and by putting values as:

M = 2.1/1.250 = 1.68 M

Hence, 1.68 M is the molarity of the solution.

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Therefore, 9.49 grams of water is expected in the given 3.21 g sample of CuSO4 • 10H2O.

To determine the number of water molecules in the given hydrate, CuSO4 • 10H2O, we'll need to find out the molar mass of the compound and the molar mass of water to make a comparison.

The molar mass of CuSO4 • 10H2O is calculated as:

CuSO4 → 159.6 g/mol10H2O → 180.16 g/mol (18.016 g/mol × 10)CuSO4 • 10H2O → 159.6 g/mol + 180.16 g/mol

= 339.76 g/mol (rounded to three significant figures)

Thus, we can see that the molar mass of CuSO4 • 10H2O is 339.76 g/mol.

We know that this hydrate consists of ten molecules of water, each having a molar mass of 18.016 g/mol (which is the same as the molar mass of water), and one molecule of CuSO4 with a molar mass of 159.6 g/mol.

Therefore, the number of moles of water in the sample is:

(10 × 18.016 g/mol) ÷ 339.76 g/mol = 0.527 moles

So, the mass of water is equal to its molar mass multiplied by the number of moles.

The mass of water is:

0.527 mol × 18.016 g/mol = 9.49 g

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The maximum mass of MgO produced is 1.64 g.

The given equation is not balanced. Assuming the correct equation is:

Mg + H₂O → MgO + H₂

The balanced equation shows that 1 mole of Mg reacts with 1 mole of H₂O to produce 1 mole of MgO and 1 mole of H₂.

The molar mass of Mg is 24.31 g/mol, which means that 1.00 g of Mg is equal to 1.00 g / 24.31 g/mol = 0.0411 mol Mg.

According to the balanced equation, 1 mol of Mg produces 1 mol of MgO. Therefore, 0.0411 mol of Mg produces 0.0411 mol of MgO.

The molar mass of magnesium oxide is 40.31 g/mol, which means that 0.0411 mol of MgO is equal to 0.0411 mol × 40.31 g/mol

= 1.64 g of MgO.

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The pKa of acetic acid is 4.74, 6 M acetic acid to prepare 100 mL of 0.10 M \(CH3COOH\) and 9.09 mL of 0.10 M \(CH_2COOH\) and 0.91 mL of 0.10 M CH3COONa.

1. The pKa of acetic acid is 4.74, which means its buffering range is between pH 4.74 and pH 5.74. A buffer is a solution that resists changes in pH when small amounts of acid or base are added. Acetic acid and its conjugate base, acetate, combine in solution to form a buffer. The amount of acetic acid and acetate will remain relatively constant over this pH range.

2. To prepare a 0.10 M \(CH3COOH\) solution, you need to calculate the volume of 6 M acetic acid needed.

Using the formula: \(M1V1 = M2V2\), you can calculate that you need 0.17 mL of 6 M acetic acid to prepare 100 mL of 0.10 M \(CH3COOH\).

3. To prepare 10.0 mL of buffer at the following pH values, you need to calculate the volume of 0.10 M\(CH_2COOH\) and 0.10 M \(CH3COONa\). At pH 3.7, you will need 4.74 mL of 0.10 M CH2COOH and 5.26 mL of 0.10 M CH3COONa. At pH 4.7, you will need 6.45 mL of 0.10 M CH2COOH and 3.55 mL of 0.10 M CH3COONa. At pH 5.7, you will need 9.09 mL of 0.10 M CH2COOH and 0.91 mL of 0.10 M CH3COONa.

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1. The pKa of acetic acid is 4.74, which means its buffering range is between pH 4.74 and pH 5.74. A buffer is a solution that resists changes in pH when small amounts of acid or base are added. Acetic acid and its conjugate base, acetate, combine in solution to form a buffer. The amount of acetic acid and acetate will remain relatively constant over this pH range.

2. To prepare a 0.10 M CH3COOH solution, you need to calculate the volume of 6 M acetic acid needed. Using the formula: M1V1 = M2V2, you can calculate that you need 0.17 mL of 6 M acetic acid to prepare 100 mL of 0.10 M CH3COOH.

3. To prepare 10.0 mL of buffer at the following pH values, you need to calculate the volume of 0.10 M CH2COOH and 0.10 M CH3COONa. At pH 3.7, you will need 4.74 mL of 0.10 M CH2COOH and 5.26 mL of 0.10 M CH3COONa. At pH 4.7, you will need 6.45 mL of 0.10 M CH2COOH and 3.55 mL of 0.10 M CH3COONa. At pH 5.7, you will need 9.09 mL of 0.10 M CH2COOH and 0.91 mL of 0.10 M CH3COONa.

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Answer:

B

Explanation:

p block bc its last orbit is 4p5

Answer:

Explanation:

P. block