T/F. some seashells are affected by more acidic water conditions because hydrogen ions tend to bond with the carbonate ions necessary for seashell formation.

Answers

Answer 1

Recently, a number of review papers on the use of biogenic calcium carbonate in engineering, biomedical, electrochemical, and environmental technologies have been published.

In the past two decades, biogenic calcium carbonate made from shell waste has drawn a lot of interest as a limestone substitute due to its role in decreasing environmental impact by converting wastes into value-added biomaterial and assisting in the transition of society to a net-zero waste system. This review differs from others on the subject in that it only examines published articles that used indirect methods rather than direct ones to extract calcium carbonate from biogenic waste shells. Simple grinding, ball milling, or mortar and pestle procedures are examples of direct or unprocessed methods.

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Related Questions

Hydrogen bonding between polyamide chains plays an important role in determining the properties of a nylon such as nylon 6,6. Draw the structural formulas for two adjacent chains of nylon 6,6, and show where hydrogen-bonding interactions could occur between them.

Answers

Answer:

See figure 1

Explanation:

In the structure of nylon 6,6 we have amide groups. In this functional group, We have a nitrogen bond to hydrogen, so in this bond, we will have a dipole, due to the electronegativity difference. Nitrogen has more electronegativity than hydrogen, therefore a positive dipole would be generated in the hydrogen atom. Additionally, in the carbonyl group (C=O) due to the oxygen, we will have also a dipole, in this case, a negative dipole because the oxygen atom has more electronegativity (compare with carbon).

When we put two strings of nylon 6,6 the positive dipole will interact with the negative dipole and vice-versa and we will obtain the "hydrogen bonds".

See figure 1

I hope it helps!

Hydrogen bonding between polyamide chains plays an important role in determining the properties of a

Calculate how many moles of element Q are in 23.53 g of element Q.



The molar mass of element Q is 40.64 g/mol

Answers

Answer:

0.579 moles

Explanation:

Moles = 23.53/40.64

= 0.5789 moles

The greenhouse effect is occurring because Group of answer choices the ozone layer is being depleted by carbon dioxide the amount of carbon dioxide in the atmosphere is increasing the ionosphere reflects low frequency radiation more ultraviolet radiation is penetrating the atmosphere the crystalline structure of the ice in the high clouds is acting like a glass ceiling, keeping the heat in

Answers

The correct answer to this question is the greenhouse effect can also be produced digitally

Consider an ice cube and a hot radiator. Which has the higher thermal energy?

the ice cube

the radiator

Answers

The answer to your question is the radiator

The thermal energy of a material increases with temperature. Therefore, the radiator  has the higher thermal energy.

What is thermal energy?

When the temperature rises, a type of energy called thermal energy is produced. The amount of thermal energy usually directly inversely proportional to the object's change in temperature. Thermal energy takes the form of heat.

The thermal energy of a material increases with temperature. The quicker motions of the substance's atoms and molecules are what cause thermal energy to grow as temperature rises.

In some cases, a substance's molecules will separate from one another and leave because the temperature is just so high. Unexpectedly, thermal energy also affects the states of matter. The radiator  has the higher thermal energy.

Therefore, the radiator has the higher thermal energy.

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during chemiosmosis, energy is released as h ions move freely across mitochondrial membranes. atp is synthesized when h ions move through a channel in atp synthase, a concentration gradient is generated when large numbers of h ions are passively transported from the matrix of the mitochondrion to the mitochondrion's intermembrane space. oh ions serve as the final electron acceptor.

Answers

During the chemiosmosis , ATP is synthesized when H⁺ ions move through a channel in ATP synthase.

The chemiosmosis is the movement of the ions through the semipermeable membrane . The ATP synthesis the free energy which is obtained by the electrons that are passes through the several carriers.  chemiosmosis is the process of the pumping of the protons through the semipermeable membrane to obtained the proton gradient. the energy will be released in the process and results in the ATP synthesis.

Thus, when the  H⁺ ions will move through the channel in the ATP synthase , ATP is synthesized , in the process of the chemiosmosis.

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What is the molarity of a solution that contains 224 grams of KOH in 2
liters of solution?

Answers

Answer:

\(\boxed {\boxed {\sf 2 \ M \ KOH}}\)

Explanation:

Molarity is a measure of concentration in moles per liter.

1. Grams to Moles

The first step is to convert the amount of grams given to moles. The molar mass is used. This found on the Periodic Table and it's the same value as the atomic mass, but the units are grams per mole.

We have 224 grams of KOH. Look up the molar masses for the individual elements.

Potassium (K): 39.098 g/mol Oxygen (O): 15.999 g/mol Hydrogen (H): 1.008 g/mol

Since the compound's formula has no subscripts, 1 formula unit has 1 atom of each element. We can simply add the molar masses together to find KOH's molar mass.

KOH: 39.098 + 15.999 + 1.008=56.105 g/mol

Use this number as a ratio.

\(\frac {56.105 \ g\ KOH}{1 \ mol \ KOH}\)

Multiply by the value we are converting: 224 g KOH

\(224 \ g \ KOH *\frac {56.105 \ g\ KOH}{1 \ mol \ KOH}\)

Flip the ratio so the units of grams KOH cancel.

\(224 \ g \ KOH *\frac {1 \ mol \ KOH}{56.105 \ g\ KOH}\)

\(224 *\frac {1 \ mol \ KOH}{56.105}\)

\(\frac {224}{56.105} \ mol \ KOH\)

\(3.992514036 \ mol \ KOH\)

2. Calculate Molarity

Remember molarity is moles per liter.

\(molarity = \frac{moles}{liters}\)

We just calculated the moles and we know there are 2 liters of solution.

\(molarity = \frac{ 3.992514036 \ mol \ KOH}{ 2 \ L}\)

\(molarity= 1.996257018 \ mol \ KOH/ L\)

3. Round and Convert Units

First, let's round. The original values have 3 and 1 significant figures. We go with the lowest number: 1. For the number we found, that is the ones place.

1.996257018

The 9 in the tenths place tells us to round to 1 up to a 2

\(2 \ mol \ KOH/ L\)

Next, convert units. 1 mole per liter is equal to 1 molar or M.

\(2 \ M \ KOH\)

The molarity of the solution is 2  M  KOH

Answer:

2M of KOH

Explanation:

224 g of KOH in 2 liters of KOH

?  of KOH in 1 liters of KOH

\(\frac{224}{2} = 112g of KOH\)

1 mole of KOH = 39 + 16+ 1 = 56g

?mole of KOH = 112g

\(\frac{112}{56}\)moles of KOH = 2 moles/1liter of KOH

written as 2M KOH

What might have been the advantages and disadvantages of just having
experienced polar explorers at the catlin arctic survey.

Answers

While having experienced polar explorers at the Catlin Arctic Survey would have been beneficial in many ways, it would also have been important for them to work collaboratively with the rest of the team.

Advantages:

Experienced polar explorers would have had a wealth of knowledge and skills, such as how to travel over the ice, how to set up camp, and how to handle emergencies.

Experienced polar explorers would have been able to make informed decisions about the best routes to take and the most efficient ways to travel. This could have helped to save time and energy.

Disadvantages:

Experienced polar explorers may have been set in their ways and resistant to new ideas. This could have hindered the team's ability to adapt to changing circumstances and make the most of new opportunities.

Experienced polar explorers may have been overconfident and taken risks that the rest of the team was not comfortable with. This could have put everyone's safety at risk.

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In the following experiment, a coffee-cup calorimeter containing 100 mL
of H2O is used. The initial temperature of the calorimeter is 23.0 ∘C
. If 6.60 g of CaCl2 is added to the calorimeter, what will be the final temperature of the solution in the calorimeter? The heat of solution ΔHsoln of CaCl2 is −82.8 kJ/mol
.
Assume that the specific heat of the solution formed in the calorimeter is the same as that for pure water: Cs=4.184 J/g⋅∘C
.

Express your answer with the appropriate units.

Answers

In the following experiment, a coffee-cup calorimeter containing 100 mL of \(H_{ 2} O\) is used. The initial temperature of the calorimeter is 23.0 ∘C. If 6.60 g of \(CaCl_{2}\) is added to the calorimeter, Final temperature of the solution in the calorimeter = 11.

The first step in solving this problem is to calculate the number of moles of \(CaCl_{2}\\\) added to the calorimeter.

Moles of \(CaCl_{2}\) = mass of \(CaCl_{2}\) / molar mass of \(CaCl_{2}\)

Moles of\(CaCl_{2}\) = 6.60 g / 110.98 g/mol (molar mass of \(CaCl_{2}\)

Moles of\(CaCl_{2}\) = 0.0594 mol

We can use the equation for heat transfer to find the change in temperature of the solution. q = mCsΔT, where q is the heat transferred, m is the mass of the solution, Cs is the specific heat of the solution, and ΔT is the change in temperature.

We know that the initial temperature of the calorimeter is 23.0 ∘C and the mass of the solution is 100 g (since the density of water is 1 g/mL). We can solve for ΔT: ΔT = q / mCs

To find q, we can use the enthalpy change of solution (ΔHsoln) and the number of moles of\(CaCl_{2}\)added: q = ΔHsoln x moles of\(CaCl_{2}\)

q = -82.8 kJ/mol x 0.0594 mol

q = -4.92 kJ

Now we can solve for ΔT: ΔT = (-4.92 kJ) / (100 g x 4.184 J/g⋅∘C)

ΔT = -11.8 ∘C

We can find the final temperature of the solution by adding the change in temperature to the initial temperature: Final temperature = 23.0 ∘C - 11.8 ∘C =11 ∘C.

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100 mL of 0.2 mol/L sodium carbonate solution and 200 mL of 0.1 mol/L calcium nitrate solution are mixed together. Calculate the mass of calcium carbonate that would precipitate and the concentration of the sodium nitrate solution that will be produced.

Answers

Answer:

Explanation:

Na2CO3+Ca(NO3)2=CaCO3+2NaNO3

nNa2CO3=0.02

nCa(NO3)2=0.02

mCaCO3=0.02*100=2 gram

nNaNo3=0.04

Cm=2/15

From the calculation, the mass of the product is 2 g.

What is a reaction?

A chemical reaction occurs when two more substances are mixed together. In this case, the reaction is shown by; Ca(NO3)2 + Na2CO3 ----> CaCO3(s) + 2NaNO3.

Number of moles of Na2CO3 = 100/1000 L *  0.2 mol/L = 0.02 moles

Number of moles of  Ca(NO3)2 = 200/1000 L *  0.1 mol/L = 0.02 moles

Since the reaction is equimolar, amount of the product = 0.02 moles * 100 g/mol = 2 g

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How much ice in grams would have to melt to lower the temperature of 352 mL
of water from 15 ∘C
to 0 ∘C
? (Assume that the density of water is 1.0 g/mL

Answers

Answer:

66 grams of ice would have to melt to lower the temperature of 352 mL of water from 15 °C to 0 °C.

Explanation:

To calculate the amount of ice that would have to melt to lower the temperature of 352 mL of water from 15 °C to 0 °C, we need to use the formula:

Q = m_water * c_water * ΔT_water + m_ice * Lf

where,
Q = the amount of heat transferred,
m_water = the mass of water, c_water is the specific heat capacity of water,
ΔT_water = the change in temperature of water, m_ice = the mass of ice,
Lf = the specific latent heat of fusion of ice.

First, let's calculate the amount of heat transferred to the water:

Q = m_water * c_water * ΔT_water
Q = 352 g * 1.0 cal/(g*°C) * (15-0) °C
Q = 5,280 cal

Next, we can use the specific latent heat of fusion of ice, which is 80 cal/g, to calculate the amount of heat required to melt the ice:

Q = m_ice * Lf
Q = m_ice * 80 cal/g
m_ice = Q / Lf
m_ice = 5,280 cal / 80 cal/g
m_ice = 66 g

If an object gets smaller due to a change in state, what happens to its volume? How will this affect its density?

Answers

Answer:

the volume of a object will go down but the density stays the same

Volume decreases while density stays the same

Suppose a student repeats Experiment 1 using strontium instead of magnesium. The student adds 4.93 g of strontium to a crucible, heats the crucible and its contents for several minutes over a Bunsen burner, and records the final mass of the crucible and its contents.

Write the balanced chemical equation for this reaction. Include physical states.
balanced equation:

What mass of product is expected to form in this reaction? Assume all of the strontium reacts.
mass of product:

Answers

The balanced chemical equation for the reaction between strontium and oxygen can be written as follows: 2 Sr (s) + \(O_2\)(g) → 2 SrO (s).

In this equation, solid strontium (Sr) reacts with gaseous oxygen (\(O_2\)) to produce solid strontium oxide (SrO).

To determine the mass of product expected to form in this reaction, we need to consider the molar ratio between strontium and strontium oxide. From the balanced equation, we can see that 2 moles of strontium react to produce 2 moles of strontium oxide.

The molar mass of strontium (Sr) is 87.62 g/mol, and the molar mass of strontium oxide (SrO) is 119.62 g/mol. Since the molar ratio is 1:1 between strontium and strontium oxide, the mass of strontium oxide formed will be equal to the mass of strontium used.

In this case, the student added 4.93 g of strontium to the crucible. Therefore, the expected mass of strontium oxide formed will also be 4.93 g.

It's important to note that this calculation assumes that the reaction proceeds to completion, meaning that all of the strontium reacts with oxygen. In actual laboratory conditions, the yield of the reaction may be less than 100% due to factors such as incomplete reaction, side reactions, or product loss.

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At 25.0°C the Henry's Law constant for dinitrogen monoxide (N2O) gas in water is 0.025 M/atm.
Calculate the mass in grams of N2O gas that can be dissolved in 325. mL of water at 25.0°C and a N2O partial pressure of 0.69 atm.
Be sure your answer has the correct number of significant digits.

Answers

Answer:

The mass in grams of N₂O gas that can be dissolved is 0.18 g

Explanation:

The solubility of a gas is proportional to the partial pressure of that gas, over a determined solvent. That's what Henry's law states. We see the formula:

S = K . Pp

Where S is solubility and K is Henry's constant. This specific for each gas and each temperature, while Pp means partial pressure.

We replace data:

S = 0.025 M/atm .  0.69atm

S = 0.01725 M

This is the solubility of the gas, so now, we need to know what mass of gas is solubilized. We convert the moles, with the volume of water.

0.01725 mol/L . 0.235 L = 4.05×10⁻³ moles

Now, we determine the mass in grams:  4.05×10⁻³ mol . 28 g / 1mol =

0.1782 g

help me solve this with work provided

help me solve this with work provided

Answers

Answer: 2.06X10^-4M

Explanation: Caffeine's molar mass is 194.2 g/mole. 10 mg is 0.010 gram, so (0.01g/194.2 g/mole) = 5.15x10^-5 moles. 250 ml = 0.250 liters.

(5.15x10^-5 moles)/(0.250 liters) = 2.06x10^-4 Molar

Which of the following is an incorrect representation for a neutral atom?

36Li
613C
3063Cu
1530P

Answers

This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li

To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.

Let's analyze the given representations:

36Li:

This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.

613C:

This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.

3063Cu:

This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.

1530P:

This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.

Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.

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Select all statements that describe a general Diels-Alder reaction.

A. The reaction is initiated by heat.
B. The reaction involves the breaking of three π bonds.
C. The reaction is endothermic.
D. The reaction involves the formation of three new C-C σ bonds.
E. The reaction is concerted.

Answers

statements that describe Diels-Alder reaction. are A. The reaction is initiated by heat. D. The reaction involves the formation of three new C-C σ bonds. E. The reaction is concerted.

The Diels-Alder reaction is initiated by heat or light and involves the formation of new C-C sigma (σ) bonds. It is a concerted reaction, meaning that the breaking of the π bonds and the formation of the σ bonds occur simultaneously. The reaction is exothermic, not endothermic, as it releases energy upon the formation of the new bonds. Therefore, statements B and C are incorrect.

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The rotational spectrum of 79BrºF shows a series of equidistant lines spaced 0-714 33 cm - apart. Calculate the rotational constant B, and hence the moment of inertia and bond length of the molecule. Determine the wavenumber of the J = 9+= 10 transition, and find which transition gives rise to the most intense spectral line at room temperature (say 300 K).
and calculate the number of revolutions per second which the Brf molecule undergoes when in (a) the J = 0 state, (b) the J = 1 state, and (c) the J = 10 state. Hint: Use E = {lwin conjunction with Eqs (2.10) and (2.13), but remember that here w is in radians per second.[its Q season 2 from fundamentals of molcular spectruscopy . banwell.c.n]​

Answers

In the J = 0 state, the BrF molecule does not undergo any revolutions per second. In the J = 1 state, it undergoes approximately 0.498 revolutions per second, and in the J = 10 state, it undergoes approximately 15.71 revolutions per second.

To calculate the rotational constant B, we can use the formula:

B = 1 / (2 * π * Δν)

Where:

B = rotational constant

Δν = spacing between consecutive lines in the rotational spectrum

Given that the spacing between consecutive lines is 0.71433 cm^(-1), we can substitute this value into the formula:

B = 1 / (2 * π * 0.71433 cm^(-1))

B ≈ 0.079 cm^(-1)

The moment of inertia (I) of the molecule can be calculated using the formula:

I = h / (8 * π^2 * B)

Where:

h = Planck's constant

Given that the value of Planck's constant (h) is approximately 6.626 x 10^(-34) J·s, we can substitute the values into the formula:

I = (6.626 x 10^(-34) J·s) / (8 * π^2 * 0.079 cm^(-1))

I ≈ 2.11 x 10^(-46) kg·m^2

The bond length (r) of the molecule can be determined using the formula:

r = sqrt((h / (4 * π^2 * μ * B)) - r_e^2)

Where:

μ = reduced mass of the molecule

r_e = equilibrium bond length

To calculate the wavenumber (ν) of the J = 9+ to J = 10 transition, we can use the formula:

ν = 2 * B * (J + 1)

Substituting J = 9 into the formula, we get:

ν = 2 * 0.079 cm^(-1) * (9 + 1)

ν ≈ 1.58 cm^(-1)

To determine the most intense spectral line at room temperature (300 K), we can use the Boltzmann distribution law. The intensity (I) of a spectral line is proportional to the population of the corresponding rotational level:

I ∝ exp(-E / (k * T))

Where:

E = energy difference between the levels

k = Boltzmann constant

T = temperature in Kelvin

At room temperature (300 K), the population distribution decreases rapidly with increasing energy difference. Therefore, the transition with the lowest energy difference will have the most intense spectral line. In this case, the transition from J = 0 to J = 1 will have the most intense spectral line.

To calculate the number of revolutions per second, we can use the formula:

ω = 2 * π * B * J

Where:

ω = angular frequency (in radians per second)

J = rotational quantum number

For J = 0:

ω = 2 * π * 0.079 cm^(-1) * 0 = 0 rad/s

For J = 1:

ω = 2 * π * 0.079 cm^(-1) * 1 ≈ 0.498 rad/s

For J = 10:

ω = 2 * π * 0.079 cm^(-1) * 10 ≈ 15.71 rad/s

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what is the molecular formula of something with an empirical formula CO that has a molar mass of 56g/mol ?

Answers

Answer:

C₂O₂

Explanation:

Step 1: Given data

Empirical formula: COMolar mass of the molecular formula: 56 g/mol

Step 2: Calculate the molar mass of the empirical formula

M(CO) = 1 × M(C) + 1 × M(O) = 1 × 12 g/mol + 1 × 16 g/mol = 28 g/mol

Step 3: Calculate "n"

We will use the following expression.

n = molar mass of molecular formula / molar mass of empirical formula

n = (56 g/mol) / (28 g/mol) = 2

The molecular formula is:

CO × n = CO × 2 = C₂O₂

Intravenous lidocaine therapy is started for a patient. The doctor's order says to add 1.0 grams of lidocaine to 250 mL of I.V. solution and deliver it to the patient at 4.0 mg/min. In this particular I.V., 20. drops = 1.0 mL. What is the flow rate in drops per minute?

Answers

The flow rate of the IV solution in drops per minute is 80 drops/min.

To determine the flow rate in drops per minute, we need to consider the conversion factors and relationships between different units.

First, let's convert the lidocaine dose from grams to milligrams, as the flow rate is given in milligrams per minute:

1 gram = 1000 milligrams

So, 1.0 gram of lidocaine is equal to 1000 milligrams.

Next, we can calculate the total volume of the IV solution in milliliters:

250 mL

To find the flow rate in milligrams per minute, we divide the dose by the total time:

Flow rate = Dose / Time

The dose is 1000 milligrams (1.0 gram) and the time is 1 minute.

Flow rate = 1000 mg / 1 min = 1000 mg/min

Now, to determine the flow rate in drops per minute, we need to convert the IV solution volume from milliliters to drops. Given that 20 drops = 1.0 mL, we can set up a conversion factor:

20 drops / 1 mL

To find the flow rate in drops per minute, we multiply the flow rate in milligrams per minute by the conversion factor:

Flow rate (drops/min) = Flow rate (mg/min) * Conversion factor

Flow rate (drops/min) = 1000 mg/min * (20 drops / 1 mL)

Now we need to convert milliliters to drops:

Flow rate (drops/min) = 1000 mg/min * (20 drops / 250 mL)

Simplifying the expression:

Flow rate (drops/min) = 1000 mg/min * (4/50)

Flow rate (drops/min) = 80 drops/min

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4. A formula with the lowest whole # ratio of elements in a compound is called?
A. chemical formula
B. molecular formula
C. covalent formula
D. empirical formul

Answers

Answer: D. empirical formula

Explanation:

A graduated cylinder contains 50.0 ml of water. A 23.5 g piece of unknown metal is carefully dropped into the cylinder. When
the metal is completely covered with water, the water rises to the 53.4 ml mark. What is the density of the unknown piece of
metal in g/ml?

Answers

To find the density of the unknown piece of metal, we can use the formula:

Density = mass / volume.

How to find the density ?The volume of the metal can be calculated by deducting the starting water volume (50.0 ml) from the final water volume (53.4 ml) after the metal is introduced. We know the mass of the unknown metal is 23.5 g.Volume of metal = 53.4 ml - 50.0 ml = 3.4 ml.Now we can substitute the values into the density formula: Density = 23.5 g / 3.4 ml = 6.9 g/ml.Therefore, the density of the unknown piece of metal is 6.9 g/ml.

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What was the purpose of incubating your ubiquity plates upside down?

A.to prevent contaminating

B.to prevent condensation from forming on the agar surface

C. incubating plates upside down is an aseptic technique

D.to prevent organisms from over-growth

Answers

The answer is B to prevent condensation from forming on the agar surface

breifly describe the chemical properties of alkaline earth metal

Answers

The periodic table's alkaline earth metals include the elements beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra).

Here are some alkaline earth metals' general chemical characteristics:

Reactivity: Although less reactive than alkali metals, alkaline earth metals are nevertheless very reactive. To reach a stable electron configuration, they easily lose their outermost two electrons, resulting in a +2 oxidation state.Metallic nature: Alkaline earth metals have a metallic character and are bright, silvery-white metals with good electrical and thermal conductivity. They are ductile and pliable, making it simple to shape and draw them into wires.Water reactivity: Alkaline earth metals react with water, though not as strong as other metals. They produce hydroxides and hydrogen gas. For instance, when magnesium combines with water, magnesium hydroxide, and hydrogen gas are produced.They quickly respond to oxygen in the air and results in forming oxides. This reactive nature towards oxygen increases down the group.

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what is the empirical formula of a compound that is found to consist of 56% chorine and no other element except iron

Answers

Answer:

FeCl₂

Explanation:

Empirical formula is the simplest formula of a compound.

Mass percentage of Chlorine  = 56%

Mass percentage Iron  = 100  - 56  = 44%

                                                              Elements  

                                                 Fe                                 Cl

Percentage mass                    44                                  56

moles                                      44/55.85                   56/35.5

                                                  0.79                         1.56

Divide by the smallest

number                                    0.79/0.79                 1.56/0.79

                                                        1                                 2

The empirical formula of the compound is FeCl₂

Can someone please help me with EARTH SCIENCE, in New York State?! I need you to label each box with a number. it’s called “rock strata correlation practice”. Number 1 would be the oldest when u label it and it’d be at the bottom.

Can someone please help me with EARTH SCIENCE, in New York State?! I need you to label each box with
Can someone please help me with EARTH SCIENCE, in New York State?! I need you to label each box with

Answers

In the rock strata correlation practice for New York State, you'll need to label each box with a number, with number 1 representing the oldest layer, located at the bottom.

To perform the correlation, start by examining the different rock layers across different locations or outcrops in New York State. Compare the characteristics of these layers, such as their composition, fossil content, and sedimentary structures. Look for similarities and patterns between the layers to determine their correlation. By identifying key markers, such as unique fossils or distinctive sedimentary structures, you can establish relationships between the rock layers at different locations. Remember to consider the principle of superposition, which states that younger rocks are typically found above older rocks unless they have been disturbed by geological processes. Applying these principles will help you accurately correlate the rock strata in New York State.

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What did Henri Matisse describe as the modern concepts of artistic expression in his Notes of a Painter (1908)?

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Henri Matisse talked about new ideas in creative expression that he thought were emerging at the moment as well as his vision for modern art.

The use of color and shape to convey emotion, according to Matisse, should take the place of the conventional representational approach that sought to mimic the real world. He held that artists should be allowed the freedom to interpret the world in light of their personal experiences and that contemporary art was really about individual expression.

Matisse believed that contemporary artists should aim for simplicity and clarity in their work, distilling the natural world down to its most basic components. To achieve a sense of coherence in entire composition, he emphasised on significance of balance and harmony in the use of color and shape. Overall, "Notes of a Painter" contributed to the development of the modernist movement in art, which emphasised the value of creativity and individual expression

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I have a balloon that can hold 100. liters
of air. If I blow up this balloon with 3.0
moles of oxygen gas at a pressure of 1.0
atmosphere, what is the temperature of
the balloon?

Answers

Answer:

T = 4.062V

Explanation:

from PV = nRT => T = PV/RT

P = 1 atm

V = Final Volume

n = 3 moles

R = 0.08206 L·atm/mol·K

T = ?

T = 1 atm · V(Liters)/(3 moles)(0.08206L·atm/mol·K) = 4.062·V(final) Kelvin

The temperature of the balloon is 406 K

We'll begin by listing out what was given from the question. This is shown below:

Volume (V) = 100 L

Mole of oxygen (n) = 3 moles

Pressure (P) = 1 atm

Temperature (T) =?

We can obtain the temperature of the balloon by using the ideal gas equation as shown below:

PV = nRTNOTE:

P is the pressure.

V is the volume.

n is the number of mole

R is the gas constant (0.0821 atm.L/Kmol)

T is the temperature.

Applying the ideal gas equation, we have:

PV = nRT

1 × 100 = 3 × 0.0821 × T

100 = 0.2463 × T

Divide both side by 0.2463

T = 100 / 0.2463

T = 406 K

Therefore, the temperature of the balloon is 406 K

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Calculate the formula weight or molecular for the following:
a. LiCI

b. SO2 (The 2 is in subscript)

Answers

Answer:

42.39, 64.06

Explanation:

Formula Weight can be calculated by adding the atomic mass of the elements in the formula.

LiCl

AM for Li is 6.94 amu, AM for Cl is 35.45 amu

\((6.94)+(35.45)=42.39\)

SO₂

AM for S is 32.06 amu, AM for O is 16 amu

\((32.06)+2(16.00)=64.06\)

If the water was intially ar 24.1 degrees celcius, what is its final temperature?

Answers

See Your Question is incomplete So I am mentioning steps only to solve it.

In order to find the Final temperature we use thermodynamics

\(\\ \sf\longmapsto Q=mc\Delta T\)

Where

\(\\ \sf\longmapsto Q=Heat\)

\(\\ \sf\longmapsto m=Mass\)

\(\\ \sf\longmapsto c=Specific\:Heat\:Capacity\)

\(\\ \sf\longmapsto \Delta T=T_f-T_i\)

Pls answer the question OR ELSE... You will step in a huge pile of gum, thereby ruining your shoes!

This is what you call a reactant that you have enough of. The one that DOES NOT run out.

Question 2 options:

Excess Reactant


Limiting Reactant

Answers

Answer:

Excess Reactant

Explanation:

Limiting Reactant is the reactant the runs out first.

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