tertbutylamine and ammonia. Which is more basic

Answer:

Umm … can you make it horizontal Please

Explanation:

Answer:

Explanation:

When two objects descend towards one another, the potential energy related to the gravitational field is released (transformed into kinetic energy).

The potential energy that a huge item has in relation to a different massive object due to gravity is known as gravitational energy and gravitational potential energy. When two objects descend towards one another, the potential energy related to the gravitational field is released (transformed into kinetic energy). Bringing two things farther apart increases the gravitational potential energy.

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A. DECREASING both wave frequency and wavelength.

B. DECREASING the wave frequency and INCREASING the wavelength.

According to the formula E=hf

where;

An increase in frequency leads to an increase in energy. Conversely, a decrease in frequency leads to a decrease in energy.

The wavelength of the wave does not directly affect the energy of the wave, but it is inversely proportional to the frequency. This means that as wavelength increases, frequency decreases and vice versa.

Therefore, option A, which involves decreasing both wavelength and frequency, would lead to a decrease in energy. Option B involves decreasing frequency and increasing wavelength, which would also result in a decrease in energy. Option C involves increasing both wavelength and frequency, which would lead to an increase in energy. Finally, option D involves increasing frequency and decreasing wavelength, which would also lead to an increase in energy.

Thus, the correct answer is either A or B, both of which involve decreasing frequency.

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Answer: the answer is B

Explanation: its correct

Answer:

connections, patterns

Explanation:

the investigation is to find, discover or sometimes create an idea of something

Cf cannot be a chemical symbol of an element. Therefore, option B is correct.

The term an element is defined as a substance that cannot be broken down into a simpler format. They are separate by a unequaled atomic number. The elements are formed by their atomic number in the periodic table, which highlights elements with similar properties.

Cf cannot be a chemical symbol of an element. CO is the symbol of element cobalt. B is the symbol of element boron and Cu is the symbol of an element copper.

Thus, option B is correct.

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Your question is incomplete, most probably your answer was

Which of the following cannot be the chemical symbol for an element

a. co

b. cf

c. b

d. cu

There are 80 gram of oxygen molecule present in 2.5 moles of \(O_{2}\) molecule.

The mole (sign mol) is just the SI base unit of material quantity. The amount of substance in an object is a measurement of how many elementary units of a certain substance are present.

It can be represented as:

Moles = mass / molar mass

Calculation of mass of oxygen by using moles formula:

Given data:

Moles = 2.5

Mass = ?

Molar mass = 32.

Put the value of given data in moles formula:

Mass = moles × molar mass

Mass = 2.5 × 32

Mass = 80 gram

Therefore, there are 80 gram of oxygen molecule present in 2.5 moles of \(O_{2}\) molecule.

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The volume of 0.100 M NaOH is required to precipitate all of the nickel (II) ions from 150.0 mL of a 0.321 M solution of Ni(NO₃)₂ is 483 mL.

To solve this problem, we need to first write the balanced chemical equation for the reaction between NaOH and Ni(NO₃)₂:

Ni(NO₃)₂ + 2NaOH → Ni(OH)₂ + 2NaNO₃

From this equation, we can see that 2 moles of NaOH are required to precipitate 1 mole of Ni(NO₃)₂.

Therefore, we need to calculate the number of moles of Ni(NO₃)₂ in 150.0 mL of a 0.321 M solution:

moles of Ni(NO₃)₂ = volume (L) x concentration (mol/L)

moles of Ni(NO₃)₂ = 0.150 L x 0.321 mol/L

moles of Ni(NO₃)₂ = 0.0483 mol

To precipitate all of the nickel (II) ions, we need to add an equal number of moles of NaOH.

Since the concentration of NaOH is 0.100 M, we can calculate the volume of NaOH required:

moles of NaOH = 0.0483 mol (from above)

volume of NaOH = moles of NaOH / concentration of NaOH

volume of NaOH = 0.0483 mol / 0.100 mol/L

volume of NaOH = 0.483 L or 483 mL

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Answer:

Answer: The two types of fibres obtained from the fleece of a sheep are beard hair, which are coarse and fine, and soft under hair, which grow near the skin. The under hair are used to make wool.

Explanation:

mark brainly please!

(I didn't copy the person above me! I just realized we had the same answer.)

All of the following are currently used to diagnose acute coronary syndrome and/or acute myocardial infarction except BNP.

Prior to the widespread use of troponin, creatine kinase (CK) and its MB isoenzyme (CK-MB) were the most often utilized serologic assays for the diagnosis of myocardial infarction. Over time, their use has significantly decreased. BNP elevation is a marker for people at risk for LV dysfunction, heart failure, and death when assessed 1–7 days after a MI. Measurement of cardiac troponin (TnT) is now required for the diagnosis of acute myocardial infarction (AMI). In 1992, cardiac-TnI was identified as a biochemical marker of myocardial injury. Since then, it has been demonstrated to be a highly sensitive and specific marker for the diagnose of acute myocardial infarction (AMI).

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Hydrated ionic compounds have water molecules incorporated into their structure. Heating removed the volatile component, water, from the Epsom salt sample, which is magnesium sulfate.

Hydrated ionic compounds have water molecules incorporated into their structure. In the case of Epsom salt, it is magnesium sulfate heptahydrate which means there are seven water molecules incorporated in it. On heating the Epsom salt sample, the volatile component that is removed from it is water.

An example of a hydrated ionic compound is magnesium sulfate heptahydrate (\(MgSO_{4} 7H_{2} O\)). Heating the Epsom salt sample will remove the water molecules from the hydrated compound, resulting in the formation of an anhydrous ionic compound, \(MgSO_{4}\).

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Answer:

True

Explanation:

The word Organic refers to the methods used to cultivate and process farm agricultural products. Organic foods are edible and nutritious substances consumed (both plants and animals) that are free from the use of synthetics and chemicals. In plants, the include the use of organic manure that serves as fertilizers and carrying out the weeding process by hand weeding. In animals, diseases can be prevented by maintaining a clean house or rotational grazing.

The benefit of organic foods are to produce food substances with no chemical substances.

Answer:

The number of waves that pass a point in 1 second

Explanation:

Answer:

A

Explanation:

f=v/wavelength, where v is the speed of the wave divided bt the wavelength of the wave.

To determine the answer, we need to calculate the standard free energy change of the reaction using the equation ΔG° = -234.55 kJ/mol.

Enthalpy is a thermodynamic property of a system that expresses the heat energy involved in a process, as well as the work that may be done at a constant pressure. It is represented by the symbol "H" and is usually measured in units of Joules or Calories.

Enthalpy change (ΔH) is often used to describe the difference between the enthalpy of the reactants and the products in a chemical reaction. It can be either positive endothermic or negative exothermic, depending on whether heat is absorbed or released during the reaction.

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Answer:

a drink my guy

Explanation:

just frozen

Some types of solids that are insoluble in water are:

Many solids are insoluble in water, meaning they do not dissolve in water to a significant extent. Here are some examples of common solids that are generally insoluble in water:

Metals: Most metals, such as gold, silver, platinum, and copper, are insoluble in water.

Non-Metallic Elements: Many non-metallic elements, such as carbon (in the form of graphite or diamond), sulfur, phosphorus, and iodine, are insoluble in water.

Metal Oxides: Some metal oxides, particularly those of less reactive metals, are insoluble in water. Examples include aluminum oxide (Al2O3), iron(III) oxide (Fe2O3), and lead(II) oxide (PbO).

Metal Carbonates: Most metal carbonates are insoluble in water. Examples include calcium carbonate (CaCO3), lead(II) carbonate (PbCO3), and copper(II) carbonate (CuCO3).

Metal Sulfides: Many metal sulfides are insoluble in water. Examples include lead(II) sulfide (PbS), silver sulfide (Ag2S), and mercury(II) sulfide (HgS).

Insoluble Salts: Certain salts have limited solubility in water. Examples include silver chloride (AgCl), lead(II) iodide (PbI2), and calcium sulfate (CaSO4).

It's important to note that while these solids are generally insoluble in water, they may exhibit some solubility to a small extent. The solubility of a solid in water can vary depending on factors such as temperature, pressure, and the presence of other solutes.

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Answer:

oxygen and water

Explanation:

it is because it throws oxygen and takes carbondioxide and throws excessive water through evaporation

Answer: The balanced chemical equation for the given reaction is:

2C(s) + N2(g) + 5H2(g) ⇌ 2CH3NH2(g)

The equilibrium constant expression for the reaction is:

Kc = [CH3NH2]^2/([N2][H2]^5)

At the beginning of the reaction, the concentration of N2 is 1.0 mol/2.00 L = 0.50 M and the concentration of H2 is 2.0 mol/2.00 L = 1.0 M. The concentration of C(s) is not given, but it is assumed to be large enough that its concentration does not change significantly during the reaction. Let the concentration of CH3NH2 at equilibrium be x mol/L. Then, according to the stoichiometry of the reaction, the equilibrium concentrations of N2 and H2 are (0.50 - x) mol/L and (1.0 - 5x) mol/L, respectively.

Substituting these values into the equilibrium constant expression and solving for x, we get:

Kc = [CH3NH2]^2/([N2][H2]^5)

1.8×10−6 = x^2/[(0.50 - x)(1.0 - 5x)^5]

1.8×10−6 (0.50 - x)(1.0 - 5x)^5 = x^2

1.8×10−6 (0.50 - x)(1 - 5x)^5 = x^2

This is a cubic equation that can be solved numerically to find the value of x, which represents the equilibrium concentration of CH3NH2. Using a numerical solver, we find that x = 5.42×10^-4 M. Therefore, the equilibrium concentrations of N2 and CH3NH2 are 0.50 - x = 0.499 M and x = 5.42×10^-4 M, respectively.

If the concentration of H2 is doubled, its concentration at equilibrium becomes 2.0 M - 5x. Substituting this new value into the equilibrium constant expression, we get:

K'c = [CH3NH2]^2/([N2][H2]^5)

K'c = (x^2)/[(0.50 - x)(2.0 - 5x)^5]

The value of K'c is different from Kc because it depends on the new concentration of H2. To find the ratio of K'c to Kc, we can divide the two expressions:

K'c/Kc = [(x^2)/[(0.50 - x)(2.0 - 5x)^5]] / [(x^2)/[(0.50 - x)(1.0 - 5x)^5]]

K'c/Kc = [(2.0 - 5x)^5]/[(1.0 - 5x)^5]

Substituting x = 5.42×10^-4, we get:

K'c/Kc = [(2.0 - 5(5.42×10^-4))^5]/[(1.0 - 5(5.42×10^-4))^5]

K'c/Kc = 1.31

Therefore, if the concentration of H2 is doubled, the equilibrium constant Kc increases by a factor of 1.31.

The partial charges on each fluorine atom are negative. Option B) The central O atom is the correct answer. Option B

The partial charges in a molecule are determined by the electronegativity values of the atoms involved. Electronegativity is the ability of an atom to attract electrons towards itself in a chemical bond. In the case of \(F_2O\), fluorine (F) is more electronegative than oxygen.

Fluorine is the most electronegative element on the periodic table, meaning it has a high ability to attract electrons. Oxygen is also relatively electronegative but less so than fluorine. When fluorine atoms bond with oxygen, the shared electrons will be pulled more towards the fluorine atoms, creating a polar covalent bond.

In \(F_2O\), each fluorine atom will pull the shared electrons towards itself, resulting in a higher electron density around the fluorine atoms. This creates a region of partial negative charge around the fluorine atoms.

Conversely, the oxygen atom will have a region of lower electron density and, therefore, a partial positive charge. This is because the shared electrons spend more time around the fluorine atoms due to their higher electronegativity.

Option B

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Answer:

I need further information.

Explanation:

Extra information is needed for you to know the correct information.

It is a thermodynamic quantity that is equal to the total heat content of a system. It is equal to the internal energy of the system plus the product of pressure and volume.

Enthalpy is nothing but energy and they are of 4 types in thermodynamics-

1. Internal Energy, U

2. Heat enthalpy, H

3. Helmholtz enthalpy, A

4. Gibb's Free enthalpy, G

The total energy of a system cannot be measured directly because the internal energy contains components that are unknown, not easily accessible, or are not of interest in thermodynamics. Generally, a change in enthalpy is the expression for measurements at constant pressure because it simplifies the information of energy transfer.

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The mass of 4.35 moles of potassium chloride is 324.14 grams. Potassium chloride (KCl) is a chemical compound made up of potassium and chlorine.

Potassium chloride (KCl) is a chemical compound composed of potassium and chlorine. It is commonly used as a salt substitute for people on low-sodium diets, as well as a fertilizer, a source of potassium in food additives, and a component of some medical solutions. Potassium chloride can also be used in the production of various chemicals, including explosives and pharmaceuticals.

The molar mass of potassium chloride (KCl) is 74.55 g/mol (39.10 g/mol for K and 35.45 g/mol for Cl).

To calculate the mass of 4.35 moles of KCl, we can use the following formula:

mass = moles × molar mass

So, the mass of 4.35 moles of KCl is:

mass = 4.35 moles × 74.55 g/mol

mass = 324.14 g

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Answer:

It is the mass of solute dissolved in 100 mL of the solution. i.e. Mass by Volume percentage = (Mass of solute in grams/Volume of solution in mL) x 100. Explanation:

The balanced equation is:

Cu + 2AgNO₃ -> 2Ag + Cu(NO₃)₂

The coefficients are: 1, 2, 2, 1

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

The equation given from the question can be balanced as follow:

Cu + AgNO₃ -> Ag + Cu(NO₃)₂

There are 2 atoms of N on the right side and 1 atom on the left. It can be balanced by writing 2 before AgNO₃ as s shown below:

Cu + 2AgNO₃ -> Ag + Cu(NO₃)₂

There are 2atoms of Ag on the left side and 1 on the right. It can be balanced by writing 2 before Ag as show below:

Cu + 2AgNO₃ -> 2Ag + Cu(NO₃)₂

Thus, the equation is balanced.

The coeficients are: 1, 2, 2, 1

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Answer:

Molarity: 0.092M

Molality: 0.090m

Explanation:

Molarity, M, is defined as the moles of solute (In this case, C14H12 -Molar mass: 180.25g/mol-) in 1L of solution.

The molality, m, are moles of solute per kg of solvent.

Molarity:

Moles solute:

7.9g * (1mol/180.25g) = 0.04383 moles

Liters solution:

475mL = 0.475L

Molarity: 0.04383 moles / 0.475L = 0.092M

Molality:

kg solvent:

475mL * (1.03g/mL) = 489.25g = 0.48925kg

Molality:

0.04383 moles / 0.48925kg = 0.090m

Explanation:

Ag+(aq) + 2NH3 (aq) ⇄ Ag(NH3)2 (aq)

When it comes to question of this sort, the LeChatelier principle should come to mind. The LeChatelier principle states that changes in the temperature, pressure, volume, or concentration of a system will result in predictable and opposing changes in the system in order to achieve a new equilibrium state.

increasing the concentration of Ag+

This would lead to an increase in concentration of reactants, the system would annul or oppose this change by moving towrds the right, favouring the forward reaction.

decreasing the concentration of NH3

This would lead to a decrease in concentration of reactants, the system would annul this change by moving to the left, favourin the backward reaction.

increasing the concentration of Ag(NH3)2

This would lead to an increase in concnetration of products, the system would annul or oppose this change by moving towards the left, favouring the backward reaction.

Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.