technician a says low fuel pressure can be caused by a restricted fuel filter. technician b says low fuel pressure can be caused by a kinked fuel return line. who is correct?

The option C is the valid answer as it correctly identifies all the affected instruments.

The instrument(s) that will become inoperative if the static vents become clogged are:

C. Airspeed, altimeter, and vertical speed.

The static vents in an aircraft are responsible for providing static pressure to the airspeed indicator, altimeter, and vertical speed indicator.

These instruments rely on accurate measurements of static pressure to function properly.

If the static vents become clogged or blocked, the instruments that rely on static pressure will no longer receive accurate readings.

The airspeed indicator measures the difference between dynamic and static pressure, the altimeter measures atmospheric pressure changes, and the vertical speed indicator measures changes in static pressure over time.

Without proper static pressure, these instruments will not be able to provide accurate readings, rendering them inoperative.

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Complete Question

Nitrogen (N2) flows through a pipe, entering at at 4 m/sec at 1000 kPa, 2270C. For a pipe inside diameter of 3 cm, find the volumetric flow rate (m3/sec) and the mass flow rate of the gas (kg/sec) assuming you have an ideal gas Then using your ideal gas mass flow rate find the rate at which enthalpy enters the pipe (kJ/sec) NO Cp, Cv, k permitted

Answer:

\(H=9.91kJ/sec\)

Explanation:

From the question we are told that:

Velocity \(v=4 m/sec\)

Pressure \(P=1000kPa\)

Temperature \(T=227 \textdegree C\)

Diameter \(d=3cm=>0.03m\)

Generally the equation for volumetric Flow Rate is mathematically given by

\(V_r=(\frac{\pi*d^2}{4}v)\)

\(V_r=(\frac{\pi*(0.03)^2}{4} *4)\)

\(V_r=0.002827m^3/s\)

Generally the equation for mass Flow Rate is mathematically given by

\(m_r=\frac{PV_r}{RT}\)

\(m_r=\frac{1000*0.002827}{0.297*(227+273)}\)

\(m_r=0.019kg/sec\)

Generally the equation for mass Flow Rate is mathematically given by

Using gas Table for enthalpy Value

\(T=500K=>h=520.75kg\)

Therefore

\(H=mh\)

\(H=0.019*520.75\)

\(H=9.91kJ/sec\)

Given:To Compute the absolute value of the product of two inputs. The input values are x and y.The output values is z.Solution: Absolute value means to remove the negative sign of the value and make it positive.

Absolute value of x is denoted by |x|.Absolute value of y is denoted by |y|.Absolute value of x*y = |x|*|y|.The mathematical formula of Absolute value of x*y = |x|*|y|.The mathematical formula of absolute value is given as-If x is greater than 0 then the absolute value is xIf x is less than 0 then the absolute value is -x.

We have to find the absolute value of x*y. So we can use the formula of absolute value of x*y = |x|*|y|We are given two inputs in the program i.e x and y.The absolute value of x is computed using function fabs(x).The function fabs(x) takes one parameter i.e x and returns the absolute value of x.

The absolute value of y is computed using function fabs(y).The function fabs(y) takes one parameter i.e y and returns the absolute value of y. The absolute value of x*y is computed by z=fabs(x*y).

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Answer:

Gasoline is injected directly into the cylinder.

Explanation:

In a direct injection system, the air and gasoline are not pre-mixed. Rather, air comes in using the intake manifold, while the gasoline is injected directly into the cylinder.

Answer:

he/she must have clearance from ATC to proceed and

hold position markings

Explanation:

Answer:

a) The spring constant is 50 lb/ft

b) The man is 26.3 ft close to the ground.

Explanation:

Height of tower is 130 ft

Specification calls for a cable of length 85 ft

the maximum this length stretches is 100 ft when subjected to a load of 750 lb

The extension of the cable is calculated from the formula from Hooke's law

F = kx

where F is the load or force on the cable

k is the spring constant of the cable

x is the extension on the cable

a) The extension on the cable is

x = 100 ft - 85 ft = 15 ft

substituting into the formula above, we'll have

750 = k*15

k = 750/15 = 50 lb/ft

b) for a 185 lb man, jumping down will give an extension gotten as

F = kx

185 = 50*x

x = 185/50 = 3.7 ft

The total length of the cable will be extended to 100 ft + 3.7 ft = 103.7 ft

closeness to the ground = 130 ft - 103.7 ft = 26.3 ft

Explanation:

The term refrigeration means cooling a space, substance or system to lower and/or maintain its temperature below the ambient one (while the removed heat is rejected at a higher temperature). In other words, refrigeration is artificial (human-made) cooling.

Refrigeration, is the act of removing undesirable heat from one thing, substance, or space and transferring it to another object, substance, or space.

Refrigeration refers to the process of chilling an area, material, or system in order to decrease and or keep its temperature below that of the surrounding environment.

Refrigeration, sometimes known as chilling, is the act of removing undesired heat from one item, substance, or area and transferring it to another.

The temperature can be lowered by using ice, snow, cooled water, or mechanical refrigeration to remove heat.

Hence,refrigeration, is the act of removing undesirable heat.

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The design brief that identified the problem of mine headgear is:

The structural structure above an underground mine shaft that facilitates the hoisting of machinery, persons, or supplies is known as a headframe (also called as a gallows frame, winding tower, hoist frame, pit frame, shafthead frame, headgear, headstock, or poppethead).

Mine headgear supports wheel systems that suspend winding cables that convey employees and ore up and down deep level shafts. These weird humanoid constructions have become the mining industry's defining emblem.

A miner's helmet consists of four major components:

Part 1: The hoist or winch is in a winding house. This component of the system is responsible for winding and unwinding the steel cable.

A motor and a control system are connected to the hoist.

When a steel cable unwinds from the winch, the mine cage and skips are lowered into the mine.

When the steel cable is wound up again, the mine cage and skips are elevated.

The sheave wheel is a pulley wheel that stands above the mining shaft in Part 2. The hoist rope travels over the sheave wheel and down the mine shaft.

The sheave wheel minimizes the mine cable's sliding friction.

Part 3: The head frame is the framework that holds the sheave wheel in place. When lifting the heavy mine cage, it must be robust enough to maintain the sheave wheel in place.

The head frame's left "legs" slope towards the hoist. This is due to the cable's strain dragging the entire frame in that direction. The sloping legs keep the head frame from tipping or collapsing.

Part 4: The cage and the jumps. Miners and equipment are transported up and down the mine in the cage. Skips are attached beside or beneath the cage.

Skips are used to transport ore and waste materials from mines.

A design brief, also called as a creative brief, is a program management document that identifies the scope, scale, and key aspects of your impending design project.

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Answer:

900 psig

Explanation:

To create a custom exception class, we will first extend the existing IOException class in Java, which is specifically used for handling input/output exceptions. We will use your first name as the class name.

1. Begin by importing the necessary package for IOException:
```java
import java.io.IOException;
```

2. Create the custom exception class using your first name, and extend the IOException class:
```java
public class FirstNameException extends IOException {
```

3. Add a constructor to your custom exception class that takes a message string as a parameter and passes it to the superclass (IOException) constructor:
```java
   public FirstNameException(String message) {
       super(message);
   }
```

4. Close the class definition:
```java
}
```
Here is the complete code for your custom exception class:

```java
import java.io.IOException;

public class FirstNameException extends IOException {
   public FirstNameException(String message) {
       super(message);
   }
}
```

Replace "FirstName" with your actual first name, and you now have a custom exception class for handling file input/output exceptions.

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This question is incomplete, the complete question is;

Given the complex numbers A₁ = 6∠30 and A₂ = 4 + j5;

(a) convert A₁ to rectangular form

(b) convert A₂ to polar and exponential form

(c) calculate A₃ = (A₁ + A₂), giving your answer in polar form

(d) calculate A₄ = A₁A₂, giving your answer in rectangular form

(e) calculate A₅ = A₁/(\(A^{*}\)₂), giving your answer in exponential form.

Answer:

a) A₁ in rectangular form is 5.196 + j3

b) value of A₃  in polar form is 12.19∠41.02°

The polar form of A₂ is 6.403 ∠51.34°, exponential form of A₂ = 6.403\(e^{j51.34 }\)

c) value of A₃  in polar form is 12.19∠41.02°

d) A₄ in rectangular form is 5.784 + j37.98

e) A₅ in exponential form is 0.937\(e^{j81.34 }\)

Explanation:

Given data in the question;

a) A₁ = 6∠30

we convert A₁ to rectangular form

so

A₁ = 6(cos30° + jsin30°)

= 6cos30° + j6cos30°

= (6 × 0.866) + ( j × 6 × 0.5)

A₁  =  5.196 + j3

Therefore, A₁ in rectangular form is 5.196 + j3

b) A₂ = 4 + j5

we convert to polar and exponential form;

first we convert to polar form

A₂ = √((4)² + (5)²) ∠tan⁻¹( \(\frac{5}{4}\) )

= √(16 + 25) ∠tan⁻¹( 1.25 )

= √41 ∠ 51.34°

A₂ = 6.403 ∠51.34°

The polar form of A₂ is 6.403 ∠51.34°

next we convert to exponential form;

A∠β can be written as A\(e^{j\beta }\)

so, A₂  in exponential form will be;

A₂ = 6.403\(e^{j51.34 }\)

exponential form of A₂ = 6.403\(e^{j51.34 }\)

c) A₃ = (A₁ + A₂)

giving your answer in polar form

so, A₁ = 6∠30 = 5.196 + j3 and A₂ = 4 + j5

we substitute

A₃ = (5.196 + j3) + ( 4 + j5)

= 9.196 + J8

next we convert to polar

A₃ = √((9.196)² + (8)²) ∠tan⁻¹( \(\frac{8 }{9.196}\) )

A₃ = √(84.566416 + 64) ∠tan⁻¹( 0.8699)

A₃ = √148.566416 ∠41.02°    

A₃ = 12.19∠41.02°

Therefore, value of A₃  in polar form is 12.19∠41.02°

d) A₄ = A₁A₂

giving your answer in rectangular form

we substitute

A₄ = (5.196 + j3) ( 4 + j5)

= 5.196( 4 + j5) + j3( 4 + j5)

= 20.784 + j25.98 + j12 - 15

A₄ = 5.784 + j37.98

Therefore, A₄ in rectangular form is 5.784 + j37.98

e) A₅ = A₁/(\(A^{*}\)₂)

giving your answer in exponential form

we know that \(A^{*}\)₂ is the complex  conjugate of A₂

so

\(A^{*}\)₂ = (6.403 ∠51.34° )*

= 6.403 ∠-51.34°

we convert to exponential form

A∠β can be written as A\(e^{j\beta }\)

\(A^{*}\)₂  = 6.403\(e^{-j51.34 }\)

also

A₁ = 6∠30

we convert to polar form

A₁ = 6\(e^{j30 }\)

so A₅ = A₁/(\(A^{*}\)₂)

A₅ = 6\(e^{j30 }\) / 6.403\(e^{-j51.34 }\)

A₅  = (6/6.403) \(e^{j(30+51.34) }\)

A₅  = 0.937\(e^{j81.34 }\)

Therefore A₅ in exponential form is 0.937\(e^{j81.34 }\)

The effective impedance (per phase) of the system seen by the source, assuming an ideal transmission line, would be:

Z_src = j0.5 + (50/14) + (18/14)(0.463 + j0.0772 + (-j0.324)) = j0.5 + 3.571 + 0.848 = 4.419 + j0.5

The effective impedance (per phase) of the system seen by the source for the given setup would be 4.419 + j0.5 Ω, when a capacitor bank of -j0.324 Ω is added parallel to the load.

This is calculated by taking the total impedance of the load side (50 Ω) and the transmission line (j0.5 Ω) referred to the primary side of the step-up transformer (1:14 turn ratio) and then adding the parallel capacitor (-j0.324 Ω).

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Answer:The preferred development environment can vary depending on personal preferences, the type of project, and the programming language being used.

Explanation:

Answer:

20368.917N

Explanation:

Frictional force (F) is the product of the Coefficient of friction and the normal reaction.

F = μN

Coefficient of friction, μ = 0.2

Normal reaction = MgCosθ

Mass, m = 12 tonnes = 12 * 1000 = 12000 kg

N = 12000 * 9.8 * cos30

N = 101844.58

F = 0.2 * 101844.58

F = 20368.917N

Answer:

see and make me brainlist

Explanation:

What is oxy fuel cutting used for?

Oxy-fuel cutting is used for the cutting of mild steel. Only metals whose oxides have a lower melting point than the base metal itself can be cut with this process. Otherwise as soon as the metal oxidises it terminates the oxidation by forming a protective crust.

Answer:

B. a model

Explanation:

A three-dimensional rendering of a product concept is called a model.

An example of a model used in computer programming is the software development life cycle (SDLC) model.

Software development life cycle (SDLC) can be defined as a strategic process or methodology that defines the key steps or stages for creating and implementing high quality software applications.

Some of the models used in the software development life cycle (SDLC) are;

I. A waterfall model: it can be defined as a process which involves sequentially breaking the software development into linear phases. Thus, the development phase takes a downward flow like a waterfall and as such each phase must be completed before starting another without any overlap in the process.

II. An incremental model: it refers to the process in which the requirements or criteria of the software development is divided into many standalone modules until the program is completed.

III. A spiral model: it can be defined as an evolutionary SDLC that is risk-driven in nature and typically comprises of both an iterative and a waterfall model. Spiral model of SDLC consist of these phases; planning, risk analysis, engineering and evaluation.

The activity at the time of dispatch must be approximately 670.15 MBq in order for it to be 185 MBq per grain upon arrival.

To calculate the activity at the time of dispatch, we need to know the half-life of 198Au, which is the time it takes for half of the radioactive material to decay. According to a credible online source, the half-life of 198Au is approximately 2.7 days.

Using the half-life, we can calculate the decay factor, which represents the fraction of the radioactive material that remains after a certain period of time. The decay factor can be calculated using the formula: decay factor = \(0.5^(^t^/^h^)\), where t is the time and h is the half-life. In this case, the time is 5 days, so the decay factor is \(0.5^(^5^/^2^.^7^).\)

Since we want the activity per grain upon arrival to be 185 MBq, we can divide this value by the decay factor to find the initial activity required. The initial activity = 185 MBq / decay factor.

Therefore, the activity at the time of dispatch must be approximately 670.15 MBq in order for it to be 185 MBq per grain upon arrival.

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The specific gravity of the oil required for 10:1 amplification is 0.9.

The theory used in this question is the specific gravity of a substance, which is the ratio of the density of a substance to the density of water.

Explanations given below

Step 1: Calculate the specific gravity of the oil by dividing the density of the oil by the density of water.

Step 2: Multiply the specific gravity by 10 to get the amplification factor.

Step 3: Divide the desired amplification factor (10) by the calculated specific gravity to get the required specific gravity of the oil.

Example:

Desired amplification factor = 10

Calculated specific gravity = 0.9

Required specific gravity of the oil = 10 / 0.9 = 0.9

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The clamping force of the joint after loading can be determined by first finding the total tension force acting on the joint. This includes the preloaded tension force of the bolt (500-lbf) and the external tension force of the weight (200-lbf), which gives a total tension force of 700-lbf.

Since the bolt is preloaded to 500-lbf, it means that the bolt is already applying a clamping force of 500-lbf on the joint. Therefore, the additional clamping force on the joint due to the external weight is the difference between the total tension force and the preloaded tension force, which is:

700-lbf - 500-lbf = 200-lbf

So, the clamping force on the joint after loading is 500-lbf (preloaded force) + 200-lbf (additional force) = 700-lbf.

Therefore, the correct answer is (D) 700-lbf.

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The following sentence sums up the ideal way to deal with the corrosion problem: Server motherboards should be changed more frequently.

Therefore, B is the appropriate response to this question.

The corrosion problem is a type of issue that, as a result of the buildup of various garbage files, drastically reduces the effectiveness of the computer system. Additionally, it slows down the system's overall pace.

The context of this query indicates that more frequent motherboard replacements are needed for servers. This is because installing a program that forbids the entry of pointless junk files into the media is the only real solution to the corrosion problem. Therefore, B is the appropriate response to this question.

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Answer:

d.

Explanation:

The synchronous speed (Ns) of a motor with 4 poles and operating at a frequency of 60Hz can be calculated using the formula:

Ns = 120 x f / p

where f is the frequency in Hertz and p is the number of poles.

Plugging in the values, we get:

Ns = 120 x 60 / 4 = 1,800 rpm

Therefore, the answer is option d) 1,800 rpm.

An nmos and gate can be implemented using 2 nmos transistors in series, or the output of 2 nmos transistors in parallel connected to the input of a single nmos transistor.

In the first implementation, the two nmos transistors are connected in series, with the input signal connected to the gate of the first transistor and the output taken from the drain of the second transistor. When the input signal is high, the first transistor is turned on, allowing current to flow to the second transistor. If the second transistor is also turned on, the output will be low, otherwise, the output will be high.

In the second implementation, the two nmos transistors are connected in parallel, with their sources and gates connected together, and the output taken from the drains. When the input signal is high, both transistors are turned on, allowing current to flow to the output. If either of the transistors is turned off, the output will be low.

Both of these implementations use two nmos transistors, but they are connected differently to achieve the desired logic function. A single nmos transistor can be used to implement a NOT gate or an inverter, but it cannot implement an AND gate

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Tensile strength and yield strength of materials can vary depending on the specifics of the manufacturing process, exact chemical composition, and the treatment of the material. They are usually provided by the manufacturer in a materials property datasheet. I don't have real-time access to such specific databases or proprietary materials databases to provide these values.

However, I can give you a general idea based on typical values for similar materials:

(a) UNS G10200 hot-rolled steel (also known as AISI 1020 steel):

- Tensile Strength: around 420 MPa

- Yield Strength: around 350 MPa

(b) SAE 1050 cold-drawn steel:

- Tensile Strength: around 690 MPa

- Yield Strength: around 600 MPa

(c) AISI 1141 steel quenched and tempered at 540°C:

- Tensile Strength: around 760 MPa

- Yield Strength: around 690 MPa

(d) 2024-T4 aluminum alloy:

- Tensile Strength: around 470 MPa

- Yield Strength: around 325 MPa

(e) Ti-6Al-4V annealed titanium alloy:

- Tensile Strength: around 900 MPa

- Yield Strength: around 880 MPa

These are general values and actual values can vary based on exact processing conditions and slight differences in alloying elements. For precise values, you should refer to the material's datasheet provided by the manufacturer or a reliable materials database.

A thick center-cracked plate made of high-strength aluminum refers to a solid material that has a significant thickness and has developed a crack originating at its center.

High-strength aluminum is an alloy that offers enhanced mechanical properties, such as increased durability, toughness, and resistance to deformation. Thick plates are often used in applications where structural integrity and load-bearing capacity are crucial, like in construction, automotive, and aerospace industries. The thickness of the plate adds to its overall strength, helping it withstand greater forces without bending or breaking. However, cracks in these plates can undermine their structural stability, making them more susceptible to failure. In the case of a thick center-cracked plate, the crack may begin at the center of the plate and propagate outwards. This can result in reduced load-carrying capacity and potential catastrophic failure if not addressed promptly.

To ensure the continued performance of a high-strength aluminum plate with a center crack, engineers must carefully assess the severity of the crack, considering factors such as crack length, stress concentration, and loading conditions. By doing so, they can determine the appropriate repair or replacement strategies, and minimize the risk of further damage or failure. In summary, a thick center-cracked plate of high-strength aluminum is a material with enhanced mechanical properties, but its performance may be compromised by the presence of a central crack. Proper assessment and management of the crack are essential to maintain its structural integrity and functionality.

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When Patricia and Abel bought Mighty Mechanics, Option E: "B and C" happened. Abel bought alcohol with their profits, which caused the business to go downhill. As a result, Trevor, their son, had to help with the garage so much that he had little time for himself.

The given options describe different outcomes of Patricia and Abel's purchase of Mighty Mechanics. Option B states that Abel bought alcohol with their profits, indicating a misuse of funds. This poor financial decision led to the business going downhill, as mentioned in the same option.

Option C states that Trevor, their son, had to help extensively with the garage, leaving him with little personal time. Therefore, the correct answer is Option E, which includes both of these outcomes. Patricia's financial situation, stay-at-home status, and their overall comfort level are not mentioned in the given options.

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A program that reads an integer as input and points the hailstone sequence starting with the integer entered is mentioned as below.

Computer programming is the method of carrying out a certain computation, often through creating and constructing an executable computer program.

Programming activities include analysis, algorithm generation, algorithm accuracy and resource use assessment, and algorithm implementation.

CODE IN PYTHON:

def haleStoneSeq(num):  ## method to that return the hailStoneSquence

   NumberList = [num]

   while num != 1:

       if (num%2) == 0:

           num = num//2

           NumberList.append(num)

       else:

           num = (num * 3) + 1

           NumberList.append(num)

   return NumberList

n=int(input("Enter the input value : "))   ## asking the input from the user

print(haleStoneSeq(n))   ## method calling

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Answer:

We well know that water is a conductor of charges. So, when it is between capacitor plates, the charges flow from positive plate to negative plate hence discharge occurs

Explanation:

\({}\)