Tech A says to always check the chain, steel cable, or sling and bolts to make sure they are in good condition before using them with an engine hoist. Tech B says that to prepare an engine hoist for lifting an engine, you should get the hoist as far to one side of the engine as possible. Who is correct

The cost of electricity incurred for leaving the laptop on for 16 hours is $0.2496 when it is plugged into a wall outlet and uses 2 A of current

The question requires you to find the cost incurred if a laptop is left on for 16 hours and uses 2 A current when plugged into a wall outlet (120 V). The cost of electricity is given as 6.5 cents per kilowatt-hour (kWh).

Formula used: Power (P) = V × I × cos⁡(θ)

Where V = Voltage in voltsI = Current in amperes

θ = Phase angle (in degrees)cos⁡(θ) = Power factor (unitless)

The power drawn by the laptop can be found using the formula P = V × I, where P is power, V is voltage, and I is current. P = 120 V × 2 A = 240 W

The power consumption is 240 watts per hour for 16 hours = 240 W × 16 h = 3840 watt-hours (Wh)

As given, 1 kWh = 1000 Wh

Hence, 3840 Wh = 3840/1000 = 3.84 kWh

Energy consumption = 3.84 kWh

Cost of electricity = 6.5 cents/kWh

The cost can be calculated using the following formula:

Cost = Energy consumption × Cost per unit of energy= 3.84 kWh × $0.065/kWh= $0.2496

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Answer:

Most technicians install rebuilt or new power steering pumps rather than overhauling the defective unit in the shop.

True

Explanation:

It has been established that most technicians, instead of overhauling the defective power steering pumps, prefer to install rebuilt or revamped pumps or even new pumps when they could have overhauled the unit themselves.  Some are afraid that leakage could occur again.  They are not confident enough to do the overhauling in-house or some claim that they do not have the time and other tools to carry out the overhauling.  Acknowledgedly, overhauling a power steering pump is not a job for the novice.  They require experienced and skilled hands to do the hard work.

The block has shrunk by about 45.3% based on the volume change, which is -0.453 times the initial volume.

The expression's negative sign indicates how the excessive pressure applied caused the material's volume to shrink. In other words, a decrease in volume will result from an increase in pressure. The volume change will be negative if pressure P is positive.

ΔV/V = -3K ΔP

K = E/(3(1-2v))

Given:

\(E = 60 GPa = 60 x 10^9 Pa\)

v = 0.25

a = 100 mm = 0.1 m

b = 50 mm = 0.05 m

c = 60 mm = 0.06 m

F1 = 1801 N

F2 = 50 kN = 50000 N

F3 = 100 kN = 100000 NF_total = F1 + F2 + F3

F_total = 1801 N + 50000 N + 100000 N

F_total = 151801 NΔP = F_total / (abc)

ΔP = 151801 N / (0.1 m x 0.05 m x 0.06 m)

\(ΔP = 5.0337 x 10^7 Pa\)

Finally, we can calculate the fractional change in volume using the formula:

ΔV/V = -3K ΔP

\(K = E/(3(1-2v)) = 60 x 10^9 Pa / (3(1-2(0.25))) = 6.0 x 10^10 Pa\)

\(ΔV/V = -3(6.0 x 10^10 Pa) (5.0337 x 10^7 Pa)\)

ΔV/V = -0.453

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Answer:

is it multiple choice or....

Answer:a

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A solid line around a component indicates that the component is complete. A dashed line around the component indicates that the component is being shown is not complete.

Answer:

NASA's Space Launch System will be the most powerful rocket we've ever built. When completed, SLS will enable astronauts to begin their journey to explore destinations far into the solar system.

Answer:

Explanation:

Elevation drawing

The architectural drawings that show the size of the building are called "floor plans."

Floor plans are two-dimensional representations of a building's interior spaces, and they are typically drawn to scale to show the layout and dimensions of each room or area. In addition to indicating the size of the building, floor plans may also show the location of doors, windows, walls, and other features, as well as the placement of furniture or equipment. Floor plans are an essential tool for architects, builders, and other professionals involved in the construction or renovation of buildings.

The voltage across the capacitor after it is fully charged is 12V.Once the capacitor is fully charged, it reaches its maximum voltage

When an uncharged capacitor is connected in series with a resistor, a switch, and a 12V battery, a charging circuit is formed. Initially, the capacitor has no charge, and the battery voltage of 12V is applied across it. As the circuit is closed by flipping the switch, the charging process begins.

During the charging process, the capacitor gradually accumulates charge and the voltage across it increases. However, once the capacitor is fully charged, it reaches its maximum voltage, which in this case is the same as the battery voltage of 12V.

At this point, the capacitor can no longer accumulate more charge, and the voltage across it remains constant at 12V.

This is because, in a fully charged capacitor, the electric field between the capacitor plates reaches equilibrium, and the capacitor acts as an open circuit. Therefore, no current flows through the capacitor, and the voltage across it remains at the same level as the source voltage.

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Answer:A

Explanation:

Those who want to save money and will use the product for only a few years

Answer:

THE ANSWER is A - those who want to save money and will use the product for only a few years

Explanation: Got it right on edg 2021

In descending gliding flight, an airplane experiences several forces and moments. The derived equation is ΣFx = W cos(γ + α) - L = 0.

To derive the equations of motion, let's start by drawing a free body diagram.

The diagram includes the following elements:

The aircraft, represented by a body with the longitudinal and vertical axes.

A coordinate system with an x-axis (horizontal) and a y-axis (vertical) that are fixed with respect to the Earth.

The velocity vector, which makes an angle φ (phi) below the horizon.

The weight force acting vertically downward.

The lift force perpendicular to the velocity vector.

The drag force opposite to the velocity vector.

The thrust force, assumed to be zero for gliding flight.

Now, let's consider the forces acting on the aircraft. The weight force can be decomposed into components: Wx in the x-direction and Wy in the y-direction.

The lift force can be decomposed into components: Lx in the x-direction and Ly in the y-direction.

The drag force can be decomposed into components: Dx in the x-direction and Dy in the y-direction.

In the vertical plane, the equations of motion are given by:

ΣFy = Wy + Ly - Dy - W = 0, where W is the weight of the aircraft.

ΣFx = Wx + Lx - Dx = 0.

We can rewrite these equations using trigonometric relationships:

ΣFy = W sin(γ + α) - D - W = 0, where γ is the glide path angle (equal to -φ in this case).

ΣFx = W cos(γ + α) - L = 0.

Since the aircraft is in gliding flight, the thrust force T is assumed to be zero.

These equations of motion have only one degree of freedom because the aircraft's motion is constrained to the vertical plane.

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Answer:

 So its area A = 4 * 4sqrt(2) = 16sqrt(2) inches^2

Explanation:

In order to find the area of the section, we need to find the length of one of the diagonals.

Using the Pythagorean Theorem, a^2 + b^2 = c^2, we pick any side of the cube which in

itself is a square with sides 4 inches each.  The length of the diagonal of the square is

2(4^2) = c^2  or c = 4sqrt(2).

To calculate the area of the section, we must first determine the length of one of the diagonals. Using the Pythagorean Theorem, \(\bold{a^2 + b^2 = c^2}\), one selects any side of the cube which in its a square with four-inch sides.

           \(\to 2(4^2) = c^2 \\\\ \to c = 4\sqrt{(2)}\)

      \(\to A = 4 \times 4\sqrt{(2)} = 16\sqrt{(2)}\ inches^2\)

Therefore, the answer is "\(\bold{ 16\sqrt{(2)}\ inches^2}\)".

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The rate of heat loss from the anterior chamber decreases when the contact lens is in place (from 933.33 mW to 827.50 mW).

The thermal circuit of the eye without the contact lens can be represented as:

Anterior chamber (To = 37°C) --- Cornea (r1 = 10.81 mm, k1 = 0.35 W/mK, h1 = 6 W/m2K) --- Ambient (Ta = 21°C)

The thermal resistance of the cornea can be calculated as:

R1 = 1 / (2 * π * k1 * r1 * h1) = 1 / (2 * π * 0.35 * 10.81 * 10^-3 * 6) = 0.0000569 K/W

The rate of heat loss from the anterior chamber can be calculated as:

qwo = (To - Ta) / R1 = (37 - 21) / 0.0000569 = 933.33 mW

The thermal circuit of the eye with the contact lens can be represented as:

Anterior chamber (To = 37°C) --- Cornea (r1 = 10.81 mm, k1 = 0.35 W/mK, h1 = 6 W/m2K) --- Contact lens (r2 = 13.46 mm, k2 = 0.80 W/mK, h2 = 12 W/m2K) --- Ambient (Ta = 21°C)

The thermal resistance of the contact lens can be calculated as:

R2 = 1 / (2 * π * k2 * r2 * h2) = 1 / (2 * π * 0.80 * 13.46 * 10^-3 * 12) = 0.0000245 K/W

The combined thermal resistance of the cornea and the contact lens can be calculated as:

R = 1 / (1 / R1 + 1 / R2) = 1 / (1 / 0.0000569 + 1 / 0.0000245) = 0.0000443 K/W

The rate of heat loss from the anterior chamber with the contact lens can be calculated as:

qw = (To - Ta) / R = (37 - 21) / 0.0000443 = 827.50 mW

So, the rate of heat loss from the anterior chamber decreases when the contact lens is in place (from 933.33 mW to 827.50 mW).

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The complete question goes thus:

The energy transferred from the anterior chamber of the eye through the cornea varies considerably depending on whether a contact lens is worn. Treat the eye as a spherical system and assume the system to be at steady state. The convection coefficient h, is unchanged with and without the contact lens in place. The cornea and the lens cover one-third of the spherical surface area.

Answer:

Explanation: Here it is: 67 Hope that helps! :)

To complete the algorithm, the missing steps 3 and 4 should iterate through the list until the end is reached. This can be achieved with a loop. Here is a possible solution:

Step 3: while position is less than or equal to n, repeat steps 4 and 5.
Step 4: increase the value of position by 1.
Step 5: if the value of the element at index position is greater than 100, increase the value of count by 1.
This revised algorithm will go through each element in the list and count the number of elements with a value greater than 100. The loop in steps 3-5 ensures that all elements are considered.
It is worth noting that there are other ways to implement this algorithm, such as using a for loop or a foreach loop, but the core logic remains the same: iterate through the list and count the elements that meet a certain condition.To complete the algorithm that counts the number of elements in a list with values greater than 100, you can replace steps 3 and 4 with the following:
Step 3: Increase the value of position by 1.
Step 4: If position is less than or equal to n, go back to step 2.
So, the complete algorithm is as follows:
1. Set count to 0 and position to 1.
2. If the value of the element at index position is greater than 100, increase the value of count by 1.
3. Increase the value of position by 1.
4. If position is less than or equal to n, go back to step 2.
5. Display the value of count.

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True. The fact that an instrument is overdue does not necessarily mean that it is defective.

Overdue refers to the expiration or passing of a specified time or deadline. It indicates that the instrument has not been serviced or calibrated within the recommended timeframe. While it is important to adhere to maintenance schedules and ensure timely servicing of instruments, being overdue does not automatically imply that the instrument is defective or malfunctioning. Defects or malfunctions are determined through proper inspection, testing, and evaluation of the instrument's performance and functionality. Therefore, being overdue for servicing does not inherently make an instrument defective; it simply indicates a delay in maintenance activities.

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1. Main memory address format:To map addresses from main memory to cache, we will first divide the address into three parts as follows:Block offset field: 3 bitsBlock number field: 8 bitsTag field: 5 bitsThe block offset field determines the location of the data word within the block. Since each block is of size 8 bytes, a 3-bit block offset field is sufficient to determine the offset of the data word within the block.

The block number field determines the block number within the cache that holds the data word. Since there are 8 blocks in the cache, a 3-bit block number field is sufficient to identify the block within the cache.The tag field is used to identify the block within main memory. Since there are 4096 blocks in main memory, a 5-bit tag field is required to identify the block within main memory. Therefore, the main memory address format is as follows:

| TAG | BLOCK NUMBER | BLOCK OFFSET || 5 bits | 3 bits | 3 bits |2. Hit Ratio Calculation:Given, direct-mapped cache consists of eight blocks, and byte-addressable main memory contains 4K blocks of eight bytes each.Let us assume that we have a program that loops three times from locations 0 to 65 (base 10) in memory, each time accessing 8 bytes of data. Let us determine the hit ratio for this program.

As the program runs for the first time, the cache is empty, so all 8 bytes of data must be brought into the cache from main memory. The address range of this data is 0 to 7. The memory address format is:| TAG | BLOCK NUMBER | BLOCK OFFSET || 5 bits | 3 bits | 3 bits |So, the tag for each block in memory is the first 5 bits of the block address. Since there are 4K blocks in main memory, there are 12 bits remaining for the block number and block offset fields.

Therefore, the size of the block number field is 3 bits (2^3 = 8) and the size of the block offset field is 3 bits (2^3 = 8).Therefore, the memory block number for the address range 0 to 7 is 0, and the block offset is the 3 least significant bits. Thus, the following blocks are accessed:

Block 0 (addresses 0 to 7)Block 1 (addresses 8 to 15)Block 2 (addresses 16 to 23)Block 3 (addresses 24 to 31)Block 4 (addresses 32 to 39)Block 5 (addresses 40 to 47)Block 6 (addresses 48 to 55)Block 7 (addresses 56 to 63)As the program runs for the second time, the blocks accessed will be Block 0 (addresses 0 to 7), Block 1 (addresses 8 to 15), Block 2 (addresses 16 to 23), and Block 3 (addresses 24 to 31).

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Answer:

B. Italy

Explanation:

Hope this helps :)

Answer:

Hi there

Your answer is:

B.

Explanation:

The "metal contraption", as the text goes on to say, is treated like a friend to Bonnie. Her mom comments on this by contrasting the metal contraption to a puppy.

Hope this helps

In order for a BJT amplifier to process ac signals, the dc bias circuit must keep the BJT in the active region.

The operating point or bias point of a BJT amplifier determines the dc voltage and current conditions at which the transistor operates. The dc bias circuit is responsible for setting the appropriate bias point to keep the transistor in the desired region for amplifying ac signals.

The three main regions of operation for a BJT are saturation, cutoff, and active. In the saturation region, the transistor is fully turned on, allowing a maximum current flow. In the cutoff region, the transistor is fully turned off, and no current flows. The active region is the region where the BJT operates as an amplifier.

For processing ac signals, the BJT amplifier needs to operate in the active region. In this region, the transistor is biased such that it remains partially turned on, allowing small variations in the input signal to be amplified. The dc bias circuit ensures that the transistor remains in the active region even with changes in temperature and component variations.

To process ac signals effectively, a BJT amplifier needs to operate in the active region. The dc bias circuit plays a crucial role in maintaining the transistor's operating point in the active region, allowing it to amplify small variations in the input signal accurately. By providing the appropriate biasing conditions, the dc bias circuit ensures that the BJT amplifier functions optimally for amplifying ac signals.

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Answer:

A rectifier is an electrical device used to convert alternating current to direct current.

Explanation:

Hope this helps! Shalom

In order to find the temperature required to obtain 0.5% C at a distance of 0.5mm beneath the surface of a 0.2% C steel in 2 hours, given 1.1% C at the surface, we can make use of the Jominy end-quench test.

In the Jominy end-quench test, a standard size and shape of steel sample is heated to a high temperature and then quickly quenched at one end by spraying water on it. The water quenches the steel, causing it to cool rapidly from the high temperature. As the steel cools, it undergoes a transformation from austenite to a mixture of ferrite and pearlite.

As the steel cools, it undergoes a transformation from austenite to ferrite and pearlite. The distance from the quenched end to the point where this transformation is complete is a measure of the steel's hardenability. The hardenability of the steel depends on its composition and the cooling rate. A higher carbon content and a faster cooling rate will result in a higher hardenability.

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This work can be carried out using the combination of the aforementioned operations. To sum the components of a tuple, use the sum() method, as in result = sum(my tuple)

Here, we first convert the tuple to a list, use map() to flatten each list element, sum() to add up each element's values, and then use sum() once more to add up the list as a whole. To sum the components of a tuple, use the sum() method, as in result = sum(my tuple) The sum function adds up the items in an iterable (like a tuple) from left to right and then returns the sum.

# ------- file: myplot.py ------

import matplotlib.pyplot as plt

import numpy as np

x = np.linspace(0, 10, 100)

plt.plot(x, np.sin(x))

plt.plot(x, np.cos(x))

plt.show()

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Answer:

a) p₀ = 1.2484 atm

b) T₀ = 274.5 K

c) p* = 0.6595 atm

d) T* = 228.74 K

e) a* = 303.16 m/s  

Explanation:

Given that;

Local Mach number M = 0.7

Pressure P = 0.9 atm

Temperature T = 250 K

First we obtain the following ratios corresponding to Mach Number 0.7 from Appendix(A) table { ISENTROPIC FLOW PROPERTIES }

For M = 0.7; Pressure→ P/P₀ = 0.7209, Temperature; T/T₀ = 0.91075

Now we calculate;

a)  value of p₀

we that; P/P₀ = 0.7209

p₀ = p / 0.7209

we substitute

p₀ = 0.9 / 0.7209

p₀ = 1.2484 atm

b) value of T₀

we know that;  

T/T₀ = 0.91075

T₀ = T / 0.91075

we substitute

T₀ = 250 / 0.91075

T₀ = 274.5 K

c) value of p*

To obtain value of p*, we say;

(p* / p₀)\(_{ma=1}\) = 0.52828

p* = 0.52828 × 1.2484

p* = 0.6595 atm

d) value of T*

To obtain value of T*, we say;

(T* / T₀)\(_{ma=1}\) = 0.8333

T* = 0.8333 × 274.5

T* = 228.74 K

e) value of a*

we know that;

a* = √(γRT*)

so

a* = √(1.4 × 287 × 228.74)

a* = √(91907.732)

a* = 303.16 m/s  

Answer:

Past tense of hear = heard