Susan Marciano invested part of her 28,000 bonus in a fund that paid a 10% profit and invested the rest in stock that suffered a 3% loss. Find the amount of each investment if her overall net profit was 2,410

Answer:

Step-by-step explanation:

1 = 1/3(10x - 3)

3 = 10x - 3

6 = 10x

x = 6/10

x = 3/5

the coordinates of the planetarium are (3, 4).

Let the coordinates of the historic village be (x1, y1) and the coordinates of the science center be (x2, y2).

Since the planetarium is halfway between the historic village and the science center, we can find its coordinates by taking the midpoint of the line segment connecting the two points.

The midpoint formula is:

((x1 + x2)/2, (y1 + y2)/2)

Plugging in the coordinates of the historic village and the science center, we get:

((4 + 2)/2, (3 + 5)/2) = (3, 4)

what is coordinates?

Coordinates are pairs of numbers used to locate points on a plane or in space. The most common type of coordinates used are Cartesian coordinates, which consist of an x-coordinate (horizontal) and a y-coordinate (vertical) for two-dimensional points, or an x-coordinate, y-coordinate, and z-coordinate (depth) for three-dimensional points.

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Answer:

y=4

Step-by-step explanation:

Since you know that x=1 , you can substitute 1 into the equation wherever there is an x . y=5x−1.

Answer:

yes

Step-by-step explanation:

plug the values in -2>-6(1)-3 which equals -2>-9 which is a true statement. Brainliest please!!

Based on the degrees of freedom (df) of 2, it can be concluded that there are 3 total categories or levels for the two variables being tested.

In a chi-square test for independence, the degrees of freedom are calculated by subtracting 1 from the number of categories in each variable and multiplying those values together. So, in this case, df = (number of categories in variable 1 - 1) x (number of categories in variable 2 - 1). Since df = 2, there must be 3 total categories or levels for the two variables being tested.

A chi-square test for independence is a statistical test used to determine whether there is a relationship between two categorical variables. The test compares the observed frequency of responses in each category for the two variables to the expected frequency of responses if there was no relationship between the variables. If the observed and expected frequencies are significantly different, the test concludes that there is a relationship between the variables. One of the outputs of the chi-square test is the degrees of freedom (df), which is a measure of the number of categories or levels in the two variables being tested. In general, the more categories or levels there are, the more information the test has to determine whether there is a relationship between the variables.

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My first step is to draw a picture

We know the length is 4 times the width plus 2

We are told the perimeter is 544

P = 2L + 2 W

Substitute in for L

544 = 2 ( 4W + 2) + 2W

Distribute

544 = 8W + 4 + 2W

Combine like terms

544 = 10W + 4

Subtract 4 from each side

544-4 = 10W +4-4

540 = 10W

Divide each side by 10

540/10 = 10W/10

54 = W

The width is 54 yards

Now find the length

L = 4W +2 = 4(54) +2 = 218 yards

Answer: 3696cm³

Step-by-step explanation:

The formula for a Cuboid's volume is LxWxH = V

so plug the numbers in

11cm x 16cm x 21cm = V

3696cm³ = V

Answer:

1-J

2-A

3-E

4-B

5-H

6-C

7-I

8-F

9-D

10-G

Answer:

c = 29km

Step-by-step explanation:

\(A^{2}\) + \(B^{2}\) = \(C^{2}\)

\(20^{2}\) + \(21^{2}\) = 841

\(\sqrt{841}\) = 29

The table displays the first-class postage rates and corresponding years from 1978 to 2009. The rates increased gradually over the years, with increments occurring in 1981, 1983, 1988, 1991, 1995, and 1999. The postage rose from 15 cents in 1978 to 33 cents in 1999.

The first paragraph presents an overview of the table and its contents. It states that the table showcases the first-class postage rates and the corresponding years between 1978 and 2009. This information provides a clear understanding of the context and purpose of the table.

The second paragraph delves into the specific details and trends depicted in the table. It explains that the postage rates experienced periodic increases during the years mentioned. In 1981, the rate rose to 18 cents, followed by a further increase to 22 cents in 1983. Subsequently, there was a significant jump to 25 cents in 1988. The trend continued with subsequent increments to 29 cents in 1991, 32 cents in 1995, and finally reaching 33 cents in 1999. Therefore, the table highlights the gradual upward trend of first-class postage rates over the given period.

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Answer:

Step-by-step explanation:

Y=25{1/2) x

Answer:

The answer is W.

Step-by-step explanation:

Answer:

1 day

Step-by-step explanation:

Assuming all the electricians work at the same rate, we can use the formula:

(time x workers) = constant

So, if 2 electricians took 5 days, we have:

(5 x 2) = (time x 10)

Simplifying, we get:

10 = time x 10

Dividing both sides by 10, we get:

time = 1

Therefore, it would take 10 electricians 1 day to wire the house.

The collection of current NFL players is well defined and is a set

Step-by-step explanation:

For a collection to be termed as a set, it is necessary that it has distinct objects that are defined.

For example, a set of first 10 natural numbers is

A= [1,2,3,4,5,6,7,8,9,10]

It is well defined and therefore called as set which has first 10 natural numbers as its elements.

Same is the case with the collection of current NFL players.

The collection contains defined number of players. Therefore, this collection is called a set.

The members of the collection or team will be known as the elements of the set.

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Answer:

\(x= \frac{-1}{3}\) or \(x= -1\)

Step-by-step explanation:

Step 1: Subtract 1 from both sides. 3x2+4x+1−1=0−1 3x2+4x=−1

Step 2: Since the coefficient of 3x^2 is 3, divide both sides by 3. 3x2+4x 3 = −1/3 x2+ 4/3 x= −1/3

Step 3: The coefficient of 4/3x is 4/3. Let b=4/3. Then we need to add (b/2)^2=4/9 to both sides to complete the square.

Add 4/9 to both sides. x^2+ 4/3 x+ 4/9 = −1/3 + 4/9 x^2+ 4/3 x+ 4/9 = 1/9

Step 4: Factor left side. (x+ 2/3 )^2= 1/9

Step 5: Take square root. x+ 2/3 =±√ 1/9 Step 6: Add (-2)/3 to both sides. x+ 2/3 + −2/3 = −2/3 ±√ 1/9 x= −2/3 ±√ 1/9 x= −1/3 or x=−1

Answer:

The answer is C.

Step-by-step explanation:

Graphs B and D show functions, and A and C don't.

(a) For the sequence x1[n], the conjugate symmetric part (xs[n]) is {-2.5 + j4, 2.5 - j6, 4, 2.5 + j6, -1.5 - j2}, and the conjugate antisymmetric part (xa[n]) is {0, -j7, 0, j7, 0}.

(b) For the sequence x2[n], both the conjugate symmetric part (xs[n]) and conjugate antisymmetric part (xa[n]) are empty sets.

(c) For the sequence x3[n], both the conjugate symmetric part (xs[n]) and conjugate antisymmetric part (xa[n]) are empty sets.

To determine the conjugate symmetric and conjugate antisymmetric parts of a sequence, we need to perform the following calculations:

(a) For the sequence x1[n] = {-1+j3, 2-j7, 4-j5, 3+j5, -2-j}, -2 ≤ n ≤ 2:

The conjugate symmetric part (xs[n]) can be calculated as:

xs[n] = (x[n] + x*[-n])/2

The conjugate antisymmetric part (xa[n]) can be calculated as:

xa[n] = (x[n] - x*[-n])/2j

Let's calculate them step by step:

For n = -2:

xs[-2] = (x[-2] + x*[2])/2 = (-1+j3 - 4+j5)/2 = (-5 + j8)/2 = -2.5 + j4

xa[-2] = (x[-2] - x*[2])/2j = (-1+j3 - 4+j5)/(2j) = (j2 - j2)/2 = 0

For n = -1:

xs[-1] = (x[-1] + x*[1])/2 = (2-j7 + 3-j5)/2 = (5 - j12)/2 = 2.5 - j6

xa[-1] = (x[-1] - x*[1])/2j = (2-j7 - 3+j5)/(2j) = (-j2 - j12)/2 = -j7

For n = 0:

xs[0] = (x[0] + x*[0])/2 = (4-j5 + 4+j5)/2 = 4

xa[0] = (x[0] - x*[0])/2j = (4-j5 - 4+j5)/(2j) = 0

For n = 1:

xs[1] = (x[1] + x*[-1])/2 = (3+j5 + 2+j7)/2 = (5 + j12)/2 = 2.5 + j6

xa[1] = (x[1] - x*[-1])/2j = (3+j5 - 2-j7)/(2j) = (j2 + j12)/2 = j7

For n = 2:

xs[2] = (x[2] + x*[-2])/2 = (-2-j + -1-j3)/2 = (-3 - j4)/2 = -1.5 - j2

xa[2] = (x[2] - x*[-2])/2j = (-2-j - -1+j3)/(2j) = (-j2 + j2)/2 = 0

Therefore, for the sequence x1[n], we have:

Conjugate symmetric part (xs[n]) = {-2.5 + j4, 2.5 - j6, 4, 2.5 + j6, -1.5 - j2}

Conjugate antisymmetric part (xa[n]) = {0, -j7, 0, j7, 0}

(b) For the sequence x2[n] = ej2πn/5 + ejπn/3:

Since this sequence is a complex exponential sequence, it does not contain any conjugate symmetric or conjugate antisymmetric parts. In other words, both xs[n] and xa[n] will be empty sets.

Conjugate symmetric part (xs[n]) = {}

Conjugate antisymmetric part (xa[n]) = {}

(c) For the sequence x3[n] = jcos(2πn/7) - sin(2πn/4):

Similarly, since this sequence is a combination of cosine and sine functions, it does not have any conjugate symmetric or conjugate antisymmetric parts.

Conjugate symmetric part (xs[n]) = {}

Conjugate antisymmetric part (xa[n]) = {}

In conclusion:

(a) For the sequence x1[n], the conjugate symmetric part (xs[n]) is {-2.5 + j4, 2.5 - j6, 4, 2.5 + j6, -1.5 - j2}, and the conjugate antisymmetric part (xa[n]) is {0, -j7, 0, j7, 0}.

(b) For the sequence x2[n], both the conjugate symmetric part (xs[n]) and conjugate antisymmetric part (xa[n]) are empty sets.

(c) For the sequence x3[n], both the conjugate symmetric part (xs[n]) and conjugate antisymmetric part (xa[n]) are empty sets.

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\(\measuredangle A\cong \measuredangle E\implies 112=16x\implies \cfrac{112}{16}=x\implies \boxed{7=x} \\\\[-0.35em] ~\dotfill\\\\ \overline{MS}\cong \overline{NR}\implies 41=3x+5y\implies 41=3(7)+5y\implies 41=21+5y \\\\\\ 20=5y\implies \cfrac{20}{5}=y\implies \boxed{4=y}\)

Steel: σs = p/A_s; Brass: σb = p/A_b; Copper: σc = p/A_c , where A_s, A_b, A_c are the areas of the steel, brass, and copper, respectively.

To calculate the tensile stresses in the steel, brass, and copper due to the force p, we use the formula: σ = p/A, where σ is the tensile stress and A is the area of the material. For the steel, the area is A_s, so the tensile stress σs is equal to p divided by A_s. For the brass, the area is A_b, so the tensile stress σb is equal to p divided by A_b. Finally, for the copper, the area is A_c, so the tensile stress σc is equal to p divided by A_c. Therefore, the tensile stresses in the steel, brass, and copper due to the force p can be calculated using the formula σ = p/A, where A is the area of the material.

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Answer:The answer is 3(1-1)

Step-by-step explanation:

if you divide the 5 and put the 3 over you get (331-1-)

Based on the questions, 13 guests are attending her best friend’s baby shower.

Firstly, we need to write down the numbers that are already stated in the question.

43 + 9 × х = 160

Secondly, move the x to continue counting.

9x = 160 – 43

Thirdly, calculate the numbers above.

9x = 117

Then, move the X to get the answer.

X = \(\frac{117}{9}\)

Lastly, try to finish the division.

X = 13

In conclusion, the result shows that 13 guests attend Mrs. Wright’s best friend's baby shower.

The above question is about the algebraic word problem.

A word problem is a math question written in a short story scenario. Usually, it is a simple short story that is easy to understand.

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Answer:

$168

Step-by-step explanation:

Step one:

given data

cost of bed = $200

It decreased the price the price by 30%.

so the price is now

=30/100*200

=0.3*200

=60

= 200-60

=$140

It then marked up the price by 20%

the new price is

=20/100*140

=0.2*140

=28

= 140+28

=$168

The measure of ∠CAE is a) 120° since a circle contains 360°, the measure of arc CFE is two-thirds (2/3) of the circle.

B. In circle A, the measure of arc CFE is 240°. Since a circle contains 360°, the measure of arc CFE is two-thirds (2/3) of the circle. This means that the measure of angle CFE is two-thirds (2/3) of 360°, which is 240°.

Since an angle is half of its arc, the measure of angle CFE is half of 240°, which is 120°. The measure of angle CAE is equal to the measure of angle CFE, so its measure is also 120°.

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Answer:

x=6/cos 45=6√2

x=6√2

tan 45=y/6

y=tan45 ×6

y=6

2.

sin 60=y/10

y=sin60×10

y=5√3

again

Cos 60=x/10

x=½×10

x=5

3.

Sin 45=x/5

x=1/√2×5 or

x=5√2/2

again

y=5√2/2 or 5/√2[base angle of right angled isosceles triangle]

4.

Sin 30=8/x

½×x=8

x=8*2

x=16

again

cos 30= y/x

√3/2×16=y

y=8√3

5.

sin 60=7/x

x=7/[√3/2]

x=14/√3 or 14√3/3

again

cos 60=y/x

½×14√3/3=y

7√3/2=y

y=7√3/2

Note:

Sin angle =perpendicular/hypotenuse

Cos angle =base/hypotenuse

Tan angle =perpendicular /base

Based on the given sample, there is sufficient evidence to suggest that the home team has a higher probability of winning in football games.

To test the claim that the probability of the home team winning is greater than one-half, a significance test can be conducted using the given sample of 45 football games, where 28 were won by the home team. The test will determine if the observed proportion of home team wins is statistically significant enough to support the claim.

To test the claim, we can use a hypothesis test with the following null and alternative hypotheses:

Null Hypothesis (H0): The probability of the home team winning is equal to one-half or less (p <= 0.5).

Alternative Hypothesis (Ha): The probability of the home team winning is greater than one-half (p > 0.5).

To conduct the test, we can use the z-test for proportions since we have a large sample size (n = 45). The test statistic, z, can be calculated using the formula:

z = (p - p0) / sqrt[(p0 * (1 - p0)) / n],

where p is the sample proportion, p0 is the hypothesized proportion under the null hypothesis, and n is the sample size.

In this case, p is the observed proportion of home team wins, which is 28/45, or approximately 0.622. Since the null hypothesis states that p <= 0.5, we use p0 = 0.5 in the calculation.

Using the formula, the calculated z-value is:

z = (0.622 - 0.5) / sqrt[(0.5 * (1 - 0.5)) / 45] = 1.911.

Next, we compare the calculated z-value to the critical z-value at the chosen significance level. Let's assume a significance level of α = 0.05 for a one-tailed test.

Looking up the critical z-value for a one-tailed test with α = 0.05, we find it to be approximately 1.645.

Since the calculated z-value (1.911) is greater than the critical z-value (1.645), we have evidence to reject the null hypothesis. This means that the observed proportion of home team wins (0.622) is statistically significant and supports the claim that the probability of the home team winning is greater than one-half.

Therefore, based on the given sample, there is sufficient evidence to suggest that the home team has a higher probability of winning in football games.

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Step-by-step explanation:

so much sorry about that

Answer: 2^43000000 (the answer is impossibly large)

The two missing expressions are x + y and 4 * z.

Here is the C code for the two missing expressions and three assignment statements that would compile to this assembly code,

int foo(int x, int y, int p[]) {

 int z = 1 / (x + y);

 int i = 4 * z;

 int j = 8 - i;

 p[i] = 3;

 p[j] = 3;

 return 3;

}

The two missing expressions are x + y and 4 * z. The three assignment statements are i = 4 * z, j = 8 - i, and p[i] = 3.

The assembly code shows that the first two instructions load the values of x and y into the registers %edi and %esi, respectively. The third instruction then loads the value of p[0] into the register %eax. The fourth instruction adds the value of %eax to %ecx, which stores the value of z. The fifth instruction stores the value of %ecx into p[4]. The sixth instruction loads the value of y into %edi. The seventh instruction stores the value of %edi into p[8]. The eighth instruction stores the value of %edi into %eax, which is the return value of the function.

The C code shows that the first two statements calculate the value of z and the value of i. The third statement assigns the value of 3 to p[i]. The fourth statement assigns the value of 3 to p[j]. The fifth statement returns the value 3.

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Correct Question:

A certain C function is defined as follows: int foo (int x, int y, int p[] ) \{ int z=1/ expression in x and y // three assignment statements return expression in p 3 Compiling the function (including the body) results in the following (comments have been added as hints):

movl

imull

movl

addl

movl

subl

movl

addl

retq

% edi, % ecx

% esi, % ecx

(%rdx),% eax

% eax, % ecx

% ecx, 4(%rdx)

% esi, % edi

% edi, 8(%rdx)

% edi, % eax

# first argument in % edi

# second argument in % esi

# third argument in %rdx

# return value in % eax

Show C code for the two missing expressions and three assignment statements that would compile to this assembly code. Remember that there is not necessarily a one-to-one correspondence between C statements and assembly instructions, and that declaring a parameter "int p[] " is the same as.

To determine if a function crosses the horizontal asymptote, analyse the behavior of the function as it approaches the asymptote and on either side of it.

1. Identify the horizontal asymptote of the function. The horizontal asymptote is a horizontal line that the function approaches as the independent variable (usually denoted as x) goes to positive or negative infinity. It is often denoted by a horizontal line y = a, where "a" is a constant.

2. Examine the behavior of the function as x approaches positive infinity. Evaluate the limit of the function as x goes to positive infinity. If the limit is equal to the value of the horizontal asymptote, then the function does not cross the asymptote. However, if the limit does not equal the asymptote, move to the next step.

3. Examine the behavior of the function as x approaches negative infinity. Evaluate the limit of the function as x goes to negative infinity. If the limit is equal to the value of the horizontal asymptote, then the function does not cross the asymptote. If the limit does not equal the asymptote, proceed to the next step.

4. Investigate the behavior of the function around critical points or points where the function changes its behavior. These points may include the x-intercepts or vertical asymptotes. Determine if the function crosses the asymptote around these points by analyzing the behavior of the function in their vicinity.

If, at any point in this process, the function crosses the horizontal asymptote, then it does not have a true horizontal asymptote. However, if the function approaches the asymptote and does not cross it at any point, then it has a horizontal asymptote.

It's important to note that some functions may have multiple horizontal asymptotes or no horizontal asymptote at all. The steps outlined above are a general guideline, but the specific behavior of the function needs to be analyzed to make a conclusive determination.

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Answer:

Step-by-step explanation:

42=24+9h

The set that is resulting of the union operation between set A and it's complementary A' is given as follows:

U = {x:6≤ x ≤40, x is a positive whole number}.

The union operation of two sets is a mathematical operation that combines all the elements from two sets into a single set, without any duplicates. The union of two sets A and B is denoted as A ∪ B, and is defined as the set that contains all elements that are in at least one of the sets A and B.

The set A is given as follows:

A = {1, 2, 3, 4, 5}.

The complement of it's set is the set containing all the elements that are in the universe set and are not in A.

The union operation between a set and it's complement is always the universe set, hence it is given as follows:

U = {x:6≤ x ≤40, x is a positive whole number}.

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Answer:

33.51 units³

Step-by-step explanation:

Volume of a sphere is given by the formula :

V = \(\frac{4}{3} \pi r^{3}\)

Because we have the radius we can plug it into the equation to give us :

V  = (4/3)×π×(2)³

V = 4/3×8π

V ≈ 33.51

Units will be units³ since no measurement is given but it to the power of 3 since it is volume.

Answer:

5/20

Step-by-step explanation:

5 over 20

it is just literally a five upward and a 20 downward

\(\frac{5}{20}\)

Answer:

4/19

Step-by-step explanation:

Its because yall did it wrong.