Suppose you have two Single Factor ANOVA experiments with the same degrees of freedom, if the resulting F test statistics are: Experiment 1, F = 2.68 Experiment 2, F = 20.15 Which statement is TRUE in regards to comparing Experiment 1 and Experiment 2? A.Procedure 1 has a smaller test statistic and therefore will result in stronger evidence in favor of the alternative hypothesis. B.Procedure 2 has a larger test statistic and therefore will result in stronger evidence in favor of the alternative hypothesis. C.We should reject the null for both tests. D.Impossible to know without more information.

Answer:

cars are dum

Step-by-step explanation:

Using translation concepts, the trigonometric graph is given by:

y = sin(x) + 1 = 1sin(1x) + 1.

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

The parent function given in this problem is:

y = sin(x).

The dashed line is a shift up one unit of the parent function, hence the definition is:

y = sin(x) + 1 = 1sin(1x) + 1.

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Answer:

y=2

Step-by-step explanation:

LCM=2×2×3×5=2×6×5=2×30=60

Step-by-step explanation:

\(\large \boldsymbol{} \sf 6=\bold3\cdot \underline2 \\\\12=\bold3\cdot \underline2\cdot 2\\\\15=5\cdot\bold 3 \\\\ LCM(6 ; 12 ; 15) =\bold{3\cdot 2}\cdot 2\cdot 5=60\)

All the ordered pairs that represent points on the graph of this equation include the following:

A. (-4, 4).

C. (-2, 1)

E. (2, -5)

F. (0, -2)

In Mathematics, an ordered pair is sometimes referred to as a coordinate and it can be defined as a pair of two (2) elements or data points that are commonly written in a fixed order within parentheses as (x, y), which represents the x-coordinate or x-axis (abscissa) and the y-coordinate or y-axis (ordinate) on the coordinate plane of any graph.

In order to determine the ordered pairs that represent points on the graph of the given function, we would plot its equation by using an online graphing calculator and then read all the ordered pairs that lie on the line.

By critically observing the graph of the given function (see attachment), the solutions are include following;

Ordered pair = (-4, 4).

Ordered pair = (-2, 1).

Ordered pair = (2, -5).

Ordered pair = (0, -2).

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Complete Question:

Which ordered pairs represent points on the graph of this equation? Select all that apply.

2y= –3x–4

(-4, 4)

(7, 6)

(-2, 1)

(0, 7)

(2, -5)

(0, -2)

Anwser:

2  X=2

Step-by-step explanation:

Because I am right!

Given parameters:

    First move = 100m east

    Second move  = 50m west

Unknown:

Distance = ?

Displacement  = ?

Solution:

Distance is total path length covered

Displacement is the distance in a specific direction from start to finish.

            -----------------------→

                       100m

                            ←---------

                               50m

So,

        Distance  = first move + second move  = 100 + 50  = 150m

       Displacement  = 100 - 50  = 50m due West

One example of a nonempty subset u of R^2 such that u is closed under scalar multiplication, but u is not a subspace of R^2, is the set u = {(x, y) | x, y are rational numbers}.

This set is closed under scalar multiplication as if a and (x,y) are in u, a*(x,y) will also be in u because rational numbers are closed under multiplication.

A subset can be described with different properties, one of them is closure, a subset U is closed under an operation if the operation is applied to any two elements of U, and the result is also an element of U.

In mathematics, a subset is a set that is completely contained within another set. It is defined as a set U that is a part of a set S, such that every element of U is also an element of S. The notation used to indicate that U is a subset of S is U ⊆ S.

However, this set u is not a subspace of R^2 because it doesn't contain the zero vector (0,0) and it doesn't close under addition, as the sum of two rational numbers may not be a rational number.

Therefore, One example of a nonempty subset u of R^2 such that u is closed under scalar multiplication, but u is not a subspace of R^2, is the set u = {(x, y) | x, y are rational numbers}.

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The distance between two points A and B

This distance is the difference between these two points, and the result is:

It can be written as four or AB = 4.

Answer:

d ≈ 4.2

Step-by-step explanation:

calculate the distance d using the distance formula

d = \(\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }\)

with (x₁, y₁ ) = (3, 3 ) and (x₂, y₂ ) = (6, 6 )

d = \(\sqrt{(6-3)^2+(6-3)^2}\)

   = \(\sqrt{3^2+3^2}\)

   = \(\sqrt{9+9}\)

   = \(\sqrt{18}\)

   ≈ 4.2 ( to the nearest tenth )

Answer

\(\pink\sf{y=-1}\)

Step-by-step explanation

I'm assuming that this exercise is asking us to simplify the equation \(\sf{y=0.5(6)-4}\).

We know that 0.5 (6) means 0.5 multiplied by 6. That is the same as 6 divided by 2, which is 3:

\(\sf{y=3-4}\)

And now we just simplify the last part:

\(\sf{y=-1}\)

∴ answer: y = -1

Answer:

more context please :)

Step-by-step explanation:

Answer:

more context please

Step-by-step explanation:

The property illustrated ca be classified as the transitive property of equality

Equation are expressions separated by an equal sign. For transitive property, if two system of equation are equal, and the first is equal to the second, then they 2nd is equal to the third, they are transitive.

According to the transitive property of equality, two quantities that are equal to the same thing are equal to each other. For instance If x = 10 and 10 = y, then x = y.

Given that g = 3h and 3h = 16, then g = 16, then the property illustrated ca be classified as the transitive property of equality

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Answer:

(5, 4)

Step-by-step explanation:

(x + 2, y + 3)

(3  + 2, 1 + 3)

(5, 4)

Answer:

B' (5, 4 )

Step-by-step explanation:

the translation rule (x, y ) → (x + 2, y + 3 )

means add 2 to the original x- coordinate and add 3 to the original y- coordinate , then

B (3, 1 ) → B' (3 + 2, 1 + 3 ) → B' (5, 4 )

Answer:

330 - 78 = 252 or 83.16 % must be 29 characters long

The inequality tha calculates the possible values of x is x < 2

From the question, we have the following parameters that can be used in our computation:

The figure

Where, we have

3x + 2 < 10

And, we have

2x + 6 < 10

Evaluate the expressions

So, we have

3x < 8 and 2x < 4

Evaluate

x < 8/3 and x < 2

Hence, the inequality tha calculates x is x < 2

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The two coterminal angles in radian measure (one positive and one negative) for each angle for figure 1 and 2 are,[(13π/4),(-π/4) and [(7π/4),(-17π/4) rad] respectively.

Angles having the same terminal side at standard position are called coterminal angles.

Although the magnitudes of coterminal angles varies, they all have the same sides and vertices.

Positive or negative coterminal angles are possible. The positive coterminal is obtained by adding 2 rad or 360° to the negative coterminal, while the negative coterminal is obtained by removing 2 rad or 360°.

For figure 1;

The positive coterminal angle is found as;

\(\rm \rightarrow \theta + 2 \pi \\\\ \rightarrow \frac{5 \pi}{4} + 2 \pi \\\\ \rightarrow\frac{13 \pi}{4} \ rad\)

The negative coterminal angle is found as;

\(\rm \rightarrow \theta - 2 \pi \\\\ \rightarrow \frac{5 \pi}{4} - 2 \pi \\\\ \rightarrow\frac{-3 \pi}{4} \ rad\)

For figure 2;

The positive coterminal angle is found as;

\(\rm \rightarrow \theta + 2 \pi \\\\ \rightarrow \frac{-9\pi}{4} + 2 \pi \\\\ \rightarrow\frac{7 \pi}{4} \ rad\)

The negative coterminal angle is found as;

\(\rm \rightarrow \theta - 2 \pi \\\\ \rightarrow \frac{-9 \pi}{4} - 2 \pi \\\\ \rightarrow\frac{-17 \pi}{4} \ rad\)

Hence,the two coterminal angles in radian measure (one positive and one negative) for each angle for figure 1 and 2 are,[(13π/4),(-π/4) and [(7π/4),(-17π/4)] respectively.

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Answer:

$19.8($2.7 subtracted off)

Step-by-step explanation:

\(P = 22.5(1 - 12\%)\\P = 22.5(1 - 0.12)\\P = 22.5(0.88)\\P = 19.8\)

Answer:

Step-by-step explanation:

Where is the equation?

Answer:

D

Step-by-step explanation:

Answer:

Since the calculated value of t = 0.01145 does not fall in the critical region ║t║≥ t (0.025,19) = 2.093 so we accept H0 the data suggests that after training people can correctly predict coin toss outcomes better than the 50 percent expected by chance guessing alone.

Step-by-step explanation:

Researchers want to see whether training increases the capability of people to correctly predict the outcomes of coin tosses. Each of twenty people is asked to predict the outcome (heads or tails) of 100 independent tosses of a fair coin. After training, they are retested with a new set of 100 tosses. (All 40 sets of 100 tosses are independently generated). The numbers correct for each of the 20 people were as follows:

a. Do the data suggest that after training people can correctly predict coin toss outcomes better than the 50 percent expected by chance guessing alone? Give appropriate statistical evidence to support your claim.

Score Before Training Score After Training

(number correct) (number correct)              Difference              d²

46                        61                                        -15                        225

48                        62                                    -  14                        196

50                        53                                       -3                         9

54                         46                                       8                        64

54                         50                                       4                      16

54                           52                                     2                       4

54                            53                                    1                         1

54                           59                                  -5                        25

54                          60                                   -6                        36

54                           61                                   -7                        49

55                           55                                   0                         0

56                          59                                    -3                       9

57                           56                                    1                          1

58                           50                                   8                          64

58                              56                                 2                          4

61                              58                                  3                           9

61                             64                                 -3                            9

63                            57                                  6                          36

64                           61                                   3                           9

65                          54                                  11                          121        

∑                                                                   -7                          887      

The degrees of freedom = n-1= 20-1= 19

The significance level is 0.05

The test statistic is

t= d`/sd/√n

The critical region is ║t║≥ t (0.025,19) = 2.093

The null and alternate hypotheses is

H0 : ud= 0.5 against Ha: ud≠ 0.5 (two tailed test)

d`= ∑di/n= -7/20= 0.35

Sd²= ∑(di-d`)²/n-1 = 1/n-1 [∑di²- (∑di)²n]

= 1/19[ 887-(0.35)²/20] = [887-0.1225/19]= 46.67

Sd= 6.83

Therefore

t= d`/ sd/√n

t=  0.35/ 6.83/√20

t= 0.05124/ 4.472=0.01145

Since the calculated value of t = 0.01145 does not fall in the critical region ║t║≥ t (0.025,19) = 2.093 so we accept H0 the data suggests that after training people can correctly predict coin toss outcomes better than the 50 percent expected by chance guessing alone.

1) The probability distribution of the average weekly earnings for employees in general automotive repair shops is the sampling distribution of the sample mean. According to the Central Limit Theorem, if the sample size is large enough, the sampling distribution of the sample mean is approximately normal, with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.

2) To find the probability that the average weekly earnings is less than $445, we can standardize the sample mean and use a z-table. The z-score for $445 is calculated as follows: z = (445 - 450) / (50 / sqrt(100)) = -1. Using a z-table, we find that the probability that the average weekly earnings is less than $445 is approximately 0.1587.

3) Since we are dealing with a continuous distribution, the probability that the average weekly earnings is exactly equal to any specific value is zero.

4) To find the probability that the average weekly earnings is between $445 and $455, we can subtract the probability that it is less than $445 from the probability that it is less than $455. The z-score for $455 is calculated as follows: z = (455 - 450) / (50 / sqrt(100)) = 1. Using a z-table, we find that the probability that the average weekly earnings is less than $455 is approximately 0.8413. Therefore, the probability that it is between $445 and $455 is approximately 0.8413 - 0.1587 = 0.6826.

5) In answering questions 2-4, we made an assumption about the population distribution based on the Central Limit Theorem. We assumed that since our sample size was large enough (n=100), our sampling distribution would be approximately normal.

6) If we assume that weekly earnings for employees in all general automotive repair shops are normally distributed with a mean of $450 and a standard deviation of $50, then we can calculate the z-score for an employee earning more than $480 in a given week as follows: z = (480 - 450) / 50 = 0.6. Using a z-table, we find that the probability that an employee will earn more than $480 in a given week is approximately 1 - 0.7257 = 0.2743.

Answer:

The answer is d

Step-by-step explanation:

Answer: d

Step-by-step explanation:

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The effect that does NOT relate to one's driving ability is breathalyzer test results indicating a high BAC. Option B.

While the breathalyzer test measures the blood alcohol concentration (BAC), it is a method used to determine the level of alcohol in a person's system and is commonly used in assessing impairment for driving under the influence.

Therefore, it directly relates to one's driving ability and is not excluded from the effects on driving ability caused by a BAC of .2 percent.

On the other hand, options, lack of coordination, impaired gross motor skills, and impaired reactions all directly relate to one's driving ability as they affect the physical and cognitive abilities necessary for safe and efficient driving.

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Answer:

Because knowing the Order of operations is vital to completing an equation. Let's say I have an unknown linear equation. How would I solve that equation without first knowing where to start? That is why the order of operations is important.

Differentiating the expression \(\frac{d}{dx} [(4x-7)^4(7x+8)^5 ]\) with respect to x will be \(16(4x-7)^3(7x+8)^5 + 35(4x-7)^4(7x+8)^4\)

We are given with

\(\frac{d}{dx} [(4x-7)^4(7x+8)^5 ]\)

Here we will be using the chain rule. According to the chain rule, we will first have to solve the parentheses as a variable. Then we will have to solve the expression within the parenthesis

First, we will differentiate \((4x-7)^4\) keeping \((7x+8)^5\) constant. Here we will first assume \((4x-7)\) as one variable and differentiate using the formula d/dx[x^n] then we will differentiate 4x - 7 to get just 4. They would be multiplied by one another

Hence we get

\(4 X4(4x-7)^3(7x+8)^5\)

\(16(4x-7)^3(7x+8)^5\)

Now, we will keep \((4x-7)^4\) constant and differentiate \((7x+8)^5\) and adding it up we get

\(16(4x-7)^3(7x+8)^5 + 5X7(4x-7)^4(7x+8)^4\)

\(= 16(4x-7)^3(7x+8)^5 + 35(4x-7)^4(7x+8)^4\)

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Complete Question

\(\frac{d}{dx} [(4x-7)^4(7x+8)^5 ]\)

Answer:

Below

Step-by-step explanation:

Losing 1/4 means there is 3/4 left when discharged

3/4 * 160 = 120 #

Answer:

(a) The event that represents success here is the percentage of adults who do not work at all while on summer vacation.

(b) X is a binomial random variable.

(c) The value of p for this binomial experiment is 0.30 or 30%.

(d) P(X = 3) = 0.2541.

(e) The probability that 2 or fewer of the 8 adults do not work during summer vacation is 0.5518.

Step-by-step explanation:

We are given that in a school it is found that 30% of adults do not work at all while on summer vacation. In a random sample of 8 adults, let X represent the number who do not work during summer vacation.

Let X = the number of adults who do not work during summer vacation

(a) The event that represents success here is the percentage of adults who do not work at all while on summer vacation.

(b) The conditions required for any variable to be considered as a random variable is given by;

So, in our question; all these conditions are satisfied which means X is a binomial random variable.

(c) The value of p for this binomial experiment is 0.30 or 30%.

(d) The above situation can be represented through binomial distribution;

\(P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r}; x = 0,1,2,......\)

where, n = number of trials (samples) taken = 8 adults

            r = number of success = exactly three

            p = probability of success which in our question is % of adults who

                  do not work at all while on summer vacation, i.e; p = 0.25

SO, X ~ Binom(n = 8, p = 0.30)

Now, the probability that exactly 3 adults do not work at all while on summer vacation is given by = P(X = 3)

          P(X = 3) =  \(\binom{8}{3}\times 0.30^{3} \times (1-0.30)^{8-3}\)

                        =  \(56 \times 0.30^{3} \times 0.70^{5}\)

                        =  0.2541

(e) The probability that 2 or fewer of the 8 adults do not work during summer vacation is given by = P(X \(\leq\) 2)

      P(X \(\leq\) 2) = P(X = 0) + P(X = 1) + P(X = 2)

= \(\binom{8}{0}\times 0.30^{0} \times (1-0.30)^{8-0}+\binom{8}{1}\times 0.30^{1} \times (1-0.30)^{8-1}+\binom{8}{2}\times 0.30^{2} \times (1-0.30)^{8-2}\)

= \(1 \times 0.30^{0} \times 0.70^{8}+8 \times 0.30^{1} \times 0.70^{7}+28\times 0.30^{2} \times 0.70^{6}\)

= 0.5518