Suppose you boil an egg. What kind of change is taking place?
A. physical and chemical
B. chemical
C. physical
D. No change is occurring.

Answer:

group 2

Explanation:

all this are found in group 2

Answer:

Explanation:

Can you explain a bit further? once u do, ill edit my answer and tell you :) But to use a fidget spinner, u have to put ur thumb at the bottom and index finger at the top, and spin it with you other fingers if thats what you meant

Most of the volume of an atom is taken up by the Electron clouds, and most of the mass of an atom is found in the nucleus.

Most of the volume of an atom is taken up by the electron clouds. This is because electrons occupy the space surrounding the nucleus in orbitals and they have a relatively large amount of space between them. The electron clouds represent the region in which electrons are likely to be found at any given time.

Most of the mass of an atom is found in the nucleus. The nucleus is made up of protons and neutrons, which have a much larger mass compared to electrons. Although the nucleus is much smaller in size compared to the electron clouds, it contains almost all of the mass of an atom.

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Answer: a. 249.5 g/mol

b. 1.996 g

c. Measure 1.996 g of \(CuSO_4.5H_2O\) and dissolve in water until the volume is 400 ml

Explanation:

Molar mass is the sum of atomic masses of all the elements present.

Thus molar mass of \(CuSO_4.5H_2O\) = 1(63.5)+1(32)+4(16)+5(18) = 249.5 g/mol

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

To calculate the number of moles for given molarity, we use the equation:

\(\text{Molarity of the solution}=\frac{\text{given mass of solute}\times 1000}{\text {Molar mass of solute}}\times \text{Volume of solution in ml}}\)

\(0.02mol/L=\frac{x\times 1000}{249.5g/mol\times 400}\)

\(x=1.996 g\)

c. We need to measure 1.996 g of \(CuSO_4.5H_2O\) and dissolve it in water to make the volume 400 ml.

Answer:

Combustion reaction

Explanation:

Combustion reactions always form water and CO2.

Density is defined as the mass divided by volume.

Density is also known by the name of viscosity.

Density is denoted by D.

It's unit is basically denoted by kg/m^3.

The density of the block is 0.42 g/cm^3.

The formula of the density is, Density = mass (m) / volume (v)

Now, it is given in the word problem that,

Mass of pine wood = 27g

Volume = 4^3 = 64 cm^3

Thus, Density = 27 g /64 cm^3 = 0.42 g/cm^3.

Hence, the density of the block of pine would be 0.42 g/cm^3

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Answer

moles = 5.81 mol

Explanation

Given:

Volume = 144 L

AT SATP

1 mole = 24.4651 L

Solution:

1 mole = 24.4651 L

x mole = 144 L

x = 144/24.4651

x = 5.8 mol

Aqueous potassium permanganate that has been diluted with carbon tetrachloride with bromine. Pentane and 1-pentane are distinguished by reagents.

An unsaturation test can be performed using the bromine in carbon tetrachloride solution. Use 100 ml of carbon tetrachloride and bromine to evaluate the unsaturation of a compound when it is insoluble in water. The bromine water turns gray as a result of how the bromine reacts with an alkene's carbon-carbon double bonds. With the help of bromine, an alkene is transformed into an alkane by breaking the carbon-carbon bond.

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Answer:

I think A.

Explanation:I say A because of the substance melting the quicking does have the highest melting point because its the highest.

Answer: el estudio de la síntesis, estructura, reactividad y propiedades del diverso grupo de compuestos químicos construidos principalmente de carbono

Explanation:Hope I helped:)

Chemical Bonding : The molecules are usually categorized into two categories depending on the bonding and the bonding are classified into ionic bonds and covalent bonds.

Other comes under wander vall interactions.

If the molecular atoms are not hydrogen atoms then it must shares polar covalent bond , it is defined as the distribution of electrons unequally (that means one have partial charges considered both positive and negative.

The main reason behind the distribution of electrons in any atom is the electronegativity. It determines the distribution of of the shared electrons in the middle of two atoms in a polar covalent bonding.

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Answer:

20g/cm³

Explanation:

density= mass÷volume

m= 60g÷3cm³

= 20g/cm³

The balanced equation for the reaction between NO and O2 is given below;

2NO + O2 → 2NO2

The amount of NO used is greater than the amount of NO given.Therefore, O2 is the limiting reactant. The number of moles of NO2 produced is 0.0157 mol.

The balanced equation for the reaction between NO and O2 is given below;

2NO + O2 → 2NO2

Molar mass of NO = 30 g/mol

Molar mass of O2 = 32 g/molar

Calculate moles of NO and O2 in the reaction;

Moles of NO = Mass / Molar mass = 0.886 / 30 = 0.0295 mol

Moles of O2 = Mass / Molar mass = 0.503 / 32 = 0.0157 mol

b) Determine the limiting reactant;

To determine the limiting reactant, we compare the moles of the reactants with their coefficients in the balanced equation.

Moles of NO = 0.0295 mol

Coefficient of NO = 2

Moles of O2 = 0.0157 mol

Coefficient of O2 = 1

For NO,

Moles of NO used = 2 x Moles of O2 used = 2 x 0.0157 = 0.0314 mol

So, the amount of NO used is greater than the amount of NO given.Therefore, O2 is the limiting reactant.

c) Calculate the moles of NO2 produced;

The number of moles of NO2 produced is equal to the number of moles of the limiting reactant. Since the limiting reactant is O2,

Moles of NO2 = Moles of O2 = 0.0157 mol

Therefore, the number of moles of NO2 produced is 0.0157 mol.

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Approximately 1.52 g of (s)-1-chloro-4-ethyl-2-methylhexane and 2.12 g of triphenylphosphine would be required to get the required product.

Molar mass of (s)-(4-ethyl-2-methylhexyl)triphenylphosphonium = (4 x molar mass of C) + (1 x molar mass of Cl) + (1 x molar mass of P) + (4 x molar mass of H) + (3 x molar mass of C6H5)

= (4 x 12.01 g/mol) + (1 x 35.45 g/mol) + (1 x 30.97 g/mol) + (4 x 1.01 g/mol) + (3 x 78.11 g/mol)

= 628.02 g/mol

Next, we can use stoichiometry to determine how much (s)-1-chloro-4-ethyl-2-methylhexane and triphenylphosphine are required to produce 4.15 g of (s)-(4-ethyl-2-methylhexyl)triphenylphosphonium. The balanced chemical equation for the reaction is:

(s)-1-chloro-4-ethyl-2-methylhexane + triphenylphosphine → (s)-(4-ethyl-2-methylhexyl)triphenylphosphonium chloride

From the balanced equation, we can see that one mole of (s)-1-chloro-4-ethyl-2-methylhexane reacts with one mole of triphenylphosphine to produce one mole of (s)-(4-ethyl-2-methylhexyl)triphenylphosphonium chloride. Therefore, we need to calculate the number of moles of (s)-(4-ethyl-2-methylhexyl)triphenylphosphonium chloride produced from 4.15 g, and then use stoichiometry to determine the amount of (s)-1-chloro-4-ethyl-2-methylhexane and triphenylphosphine required.

Number of moles of (s)-(4-ethyl-2-methylhexyl)triphenylphosphonium chloride = mass / molar mass

= 4.15 g / 628.02 g/mol

= 0.0066 mol

Since the yield is given as 81%, we need to adjust the amount of (s)-1-chloro-4-ethyl-2-methylhexane and triphenylphosphine accordingly:

Amount of (s)-1-chloro-4-ethyl-2-methylhexane = 0.0066 mol / 0.81

= 0.0081 mol

Amount of triphenylphosphine = 0.0066 mol / 0.81

= 0.0081 mol

Finally, we can convert the moles of each compound to grams using their respective molar masses:

Mass of (s)-1-chloro-4-ethyl-2-methylhexane = 0.0081 mol x 186.71 g/mol

= 1.52 g

Mass of triphenylphosphine = 0.0081 mol x 262.29 g/mol

= 2.12 g

Therefore, approximately 1.52 g of (s)-1-chloro-4-ethyl-2-methylhexane and 2.12 g of triphenylphosphine would be required to produce 4.15 g of (s)-(4-ethyl-2-methylhexyl)triphenylphosphonium assuming an  81% yield of reaction.

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The text discusses the issue of global warming caused by the release of greenhouse gases, primarily from human activities such as burning fossil fuels and deforestation. It highlights the potential consequences of rising temperature.

The greenhouse effect explains how heat is trapped at the Earth's surface by "greenhouse gases." You may think of these heat-trapping gases as a blanket keeping the Planet warmer than it otherwise would be.

Water vapour, carbon dioxide, methane, and other airborne gases all contribute to the greenhouse effect, which warms the Earth's surface and troposphere (lowest layer of the atmosphere).

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The hydrolysis of glyceryl triethanoate is a chemical reaction that involves the breaking of a bond in the compound using water. The products of the reaction are glycerol and acetic acid.

The hydrolysis of glyceryl triethanoate is a chemical reaction that involves the breaking of a bond in the compound using water. The starting compound, glyceryl triethanoate, has the chemical formula CH2(OOCCH3)C(OOCH3)CH(OOCCH3)2. It is also known as triacetin, which is a colorless, odorless, and tasteless liquid. During hydrolysis, the ester bonds in triacetin are cleaved by water, forming glycerol and acetic acid. The hydrolysis reaction can be represented by the equation:
CH2(OOCCH3)C(OOCH3)CH(OOCCH3)2 + 3H2O → C3H5(OH)3 + 3CH3COOH
In this equation, C3H5(OH)3 represents glycerol, while CH3COOH represents acetic acid. The hydrolysis of triacetin is an example of a saponification reaction, which is commonly used in the production of soap.

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Answer:

The formula of the precipitate formed is AgN₃ (Silver azide).

On adding aqueous ammonia to the precipitate formed, the precipitate dissolves due to the formation of a soluble complex compound with aqueous ammonia.

Explanation:

Sodium azide is NaN₃

Silver Nitrate is AgNO₃

The two of them react and theres a double displacement where the ions exchange radicals.

NaN₃(aq) + AgNO₃(aq) → NaNO₃(aq) + AgN₃(s)

The azide ion (N₃⁻), which has very similar chemical properties as the chloride ion (Cl⁻), also forms an insoluble compound with Silver.

And just like AgCl, the precipitate (AgN₃) also dissolves when ammonia is added by forming a soluble complex.

AgN₃(s) + 2NH₃(aq) → [Ag(NH₃)₂]N₃(aq)

Hope this Helps!!!

Morgan must wear PPE, use chemicals in a ventilated area, know chemical properties, and follow the procedure carefully for safety with hazardous chemicals.

When working with hazardous chemicals, it is important to wear appropriate personal protective equipment (PPE) to prevent exposure to the skin, eyes, and respiratory system. This may include gloves, lab coat, safety glasses or goggles, and a respirator if necessary.

Chemicals should be handled in a well-ventilated area to prevent inhalation of vapors or fumes. If necessary, a fume hood or other ventilation system should be used.

It is important to be aware of the properties of the chemicals being used, including their flammability, toxicity, and reactivity. Chemicals should be stored and handled appropriately to minimize the risk of accidents or exposure.

Following the experimental procedure carefully is also crucial to ensure safety. This includes measuring and mixing chemicals accurately, using appropriate equipment, and following any precautions or warnings in the experimental protocol.

In addition, it is important to be prepared for emergencies and to know the location of safety equipment, such as eyewash stations and fire extinguishers. Finally, it is important to receive training in safe chemical handling practices and to follow all laboratory safety rules and regulations.

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Answer: The statement that describes a chain reaction brought about by a nuclear reaction is "neutrons released during a fission reaction cause other nuclei to split." This is applicable to fission reactions only wherein atoms split and produce neutrons that also cause further atoms to split, thus creating a chain or series of reactions.

plz mark brainliest

Answer:

13

Explanation:

because the number of protons and electrons in the atom are the same

Answer:

It should be A

Explanation:

I hope this helps!

Answer:

(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl

Explanation:

This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.

The initial pH of pure water is 7.0, and after adding 0.028 mol of NaOH to 280.0 ml of water, the final pH is approximately 13.0 due to an increase in hydroxide ion concentration.

The initial pH of pure water is 7.0, as it is considered neutral. After adding 0.028 mol of NaOH to 280.0 ml of pure water, the final pH can be calculated.

Pure water has a neutral pH of 7.0, which means it has an equal concentration of hydrogen ions (H+) and hydroxide ions (OH-). When NaOH is added to water, it dissociates into Na+ and OH- ions. The OH- ions react with the H+ ions in the water, resulting in an increase in the concentration of hydroxide ions and a decrease in the concentration of hydrogen ions.

To calculate the final pH, we need to determine the concentration of OH- ions after the addition of NaOH. Since 0.028 mol of NaOH is added to 280.0 ml of water, the concentration of OH- ions can be calculated using the molarity formula:

Molarity = Moles of solute / Volume of solution (in liters)

Converting the volume of water to liters (280.0 ml = 0.280 L), we can calculate the molarity of the OH- ions:

Molarity of OH- = (0.028 mol) / (0.280 L) = 0.10 M

The concentration of OH- ions corresponds to the pOH value, which is the negative logarithm (base 10) of the hydroxide ion concentration:

pOH = -log [OH-] = -log (0.10) ≈ 1.0

Since pH + pOH = 14 (for neutral solutions), the final pH can be calculated:

pH = 14 - pOH = 14 - 1.0 = 13.0

Therefore, the final pH after adding 0.028 mol of NaOH to 280.0 ml of pure water is approximately 13.0.

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The hypothesis is that salt water freezes faster than fresh water.

The dependent variable is time taken for ice to appear.

The independent variable is presence or absence of salt

The constants are the amount of water in each tray, freezing conditions and length of time of exposure to freezing condition.

The control group is the tray to which salt was not added

The experimental group is the tray to which salt was added

The presence of solutes in a solution causes the freezing point depression.

A solution is made up of a solute and a solvent. In the presence of a solute, the freezing point of a pure solvent is decreased. This is because freezing point is a colligative property.

Colligative properties depend on the amount of solute present.

Hence, the pure water freezes faster (ice begin to appear earlier) than the salt water.

The hypothesis put forward in this experiment was found to be invalid by the experiment.

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Answer:

m=28.8g

Explanation:

m=dv

m=24*1.2

m=28.8g

Answer

47.73 g CuO

Explanation

Given:

Chemical equation: 3CuO+ 2H3PO4 = Cu3(PO4)2 + 3H20

mass of orthophosphate acid (Cu3(PO4)2) = 39.2 g

Required: The mass of CuO

Solution:

Second method:

Step 1: Find the moles of H3PO4

n = m/M where m is the mass and M is the molar mass of H3PO4

n = 39.2g/97.994g.mol^-1

n = 0.400 mol

Step 2: Use the stoichiometry to find the moles of CuO

The molar ratio between CuO and H3PO4 is 3:2

Therefore the moles of CuO = 0.400 mol x (3/2) = 0.600 mol

Step 3: Find the mass of CuO, now that we have moles

m = n x M m is the mass, n is the moles and M is the molar mass

m = 0.600 mol x 79,545 g/mol

m = 47.73 g

Approximately 164 coulombs of charge are required to produce 0.054 g of Cu during the electrolysis of a CuSO₄ solution.

To determine the coulombs of charge needed to produce 0.054 g of Cu during the electrolysis of a CuSO₄ solution, we must first find the moles of Cu produced.

Using the molar mass of Cu (63.5 g/mol), we can calculate the moles: 0.054 g / 63.5 g/mol ≈ 0.00085 mol Cu

Now, considering the balanced half-reaction for the reduction of Cu²⁺ ions: Cu²⁺ + 2e⁻ → Cu

We see that 2 moles of electrons (2e⁻) are needed for 1 mole of Cu.

Therefore, for 0.00085 mol of Cu: 0.00085 mol Cu * 2 mol e⁻/mol Cu ≈ 0.0017 mol e⁻

Finally, using the Faraday constant (1 F = 96,485 C/mol e⁻), we can find the coulombs of charge required: 0.0017 mol e⁻ * 96,485 C/mol e⁻ ≈ 164 C

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Answer:

d) Hypothesis

Explanation:

I think d) Hypothesis is the correct answer for the question.

Hope it helps :)

To determine the moles of O₂ needed, we have to know in what ratio the two reactants react and then use the moles of C₂H₂  in reaction to determine the moles of O₂  needed. We can find this out based on their coefficient in a balanced equation:

Write a Balance Equation

2C₂H₂  +   5O₂   →     4CO₂   +   2H₂O

Compare the Mole Ratio (Equation Coefficient of C₂H₂  to  O₂)

Based on the equation, the mole ratio of C₂H₂  to  O₂  is 2 to 5. Therefore for every molecule of C₂H₂, ⁵/₂ C₂H₂ molecules are needed to react.

Find the moles of O₂

Since the number of moles of  C₂H₂   =    2.60 moles

                                then moles of O₂ = 2.60 moles × ⁵/₂