Suppose you are camping on a mountain and the air temperature is very cold. How would you keep warm? Would you build a fire or set up a tent?
with explenation..

Answer:

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2). Acceleration is also a vector quantity, so it includes both magnitude and direction.

Explanation:

hope it help mark me as brill please

Answer:

acceleration equals the change in velocity divided by time

Explanation:

The mass (in Kg) of the elevator, given that it is moving with a constant speed of 2 m/s is 600 Kg

We'll begin by obtaining the force. This can be obtained as illustrated below:

Power = Force × Velocity

12000 = Force × 2

Divide both sides by 2

Force = 12000 / 2

Force = 6000 N

Finally, we shall determine the mass of the elevator. This can be obtaiend as follow:

Force = Mass × acceleration due to gravity

6000 = Mass × 10

Divide both sides by 10

Mass = 6000 / 10

Mass = 600 Kg

Thus, the mass of the elevator is 600 Kg.

None of the options are correct.

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The work that would have been done if a lever would have been used with an effort arm of 12 meters and a load arm of 6 meters is 50 J.

option A is the correct answer.

A lever is a simple machine that makes work easier and faster. When a lever is used, a small effort will be used to overcome a large load.

The efficiency of a machine increases when the output force is greater than the input force.

Mathematically, the formula for the efficiency of a machine is given as;

Eff = ( output force / input force ) x 100 %

The output force is given by the following formula;

F ( out ) = load x distance moved by load

The input force is given by the following formula;

F ( input ) = effort x distance moved by effort

The work that would have been done if a lever would have been used with an effort arm of 12 meters and a load arm of 6 meters is calculated as;

work = ( 600   x 6  ) / ( 12  x 6  )

work = 50 J

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Answer:

600 J

Explanation:

The work is not equal to the initial work divided by the effort arm.

Answer:

Explanation:

Newton's second law allows us to find the results for the questions about the forces in the motion of the ball are:

     a) The cable tension is: T = 1955 N

     b) The force to stop the ball is: F = 5520 N

Newton's second law gives a relationship between force, mass and acceleration of bodies.

        F = ma

The bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.

The ball is oscillating therefore its movement is circular, in the lower part of the trajectory the centripetal acceleration is:

a) A free body diagram is a diagram of the forces without the details of the body, in the attachment we can see a free body diagram of the system.

          T - W = ma

           T = W + ma

We substitute.

          T = m (g + v ^ 2 / r)

Let's calculate.

          T = 115 (9.8 + 12 ^ 2/20)

           T = 1955 N

b) To find the average force, let's find the average acceleration to stop with kinematics.

             v² = v₀² - 2 a x

When the ball moves, its velocity is zero.

Let's calculate.

           a = 48 m /s²

We substitute in Newton's second law.

            F = m a

            F = 115 48

           F = 5520 N

In conclusion using Newton's second law we can find the results for the questions about the forces in the motion of the ball are:

      a) The cable tension is: T = 1955 N

      b) The force to stop the ball is: F = 5520 N

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active attachment

A free-body diagram is a visual representation of the forces acting on an object. In this case, we have a rod with its center of gravity at g. To draw the free-body diagram for the rod, we need to identify the forces acting on it.

The only force acting on the rod is gravity, which pulls the rod downwards towards the Earth's center. We can represent this force using an arrow pointing downwards from the center of gravity of the rod. The length of the arrow should be proportional to the magnitude of the force. Therefore, the free-body diagram for the rod would show a downward arrow representing the force of gravity acting on the center of gravity of the rod.

A free-body diagram is a visual representation of the forces acting on an object, in this case, a rod. To draw the free-body diagram for the rod, follow these steps:

1. Draw a simple, straight line to represent the rod.
2. Indicate the center of gravity (g) on the rod by marking a point in the middle of the line.
3. Draw arrows representing the forces acting on the rod. Typical forces include tension, normal force, friction, and weight.
4. Label each force arrow with its corresponding force type.
5. The weight force (W) acts at the center of gravity (g) and points vertically downwards.
6. Identify any other forces acting on the rod, such as support reactions, and draw them with arrows at the appropriate points.

Remember, the free-body diagram should be simple and clear, focusing on the forces acting on the rod and their point of application.

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The distance the red ball travelled between 12 s and 24 s is 2116.8 m

Free fall is motion under gravity.

If we assume the red ball is falling freely, it has an initial velocity of zero.

Using the equation of motion s = ut - 1/2gt², we find the distance it travels or height it drops after the given time. where

So, s = ut - 1/2gt²

s = 0 × t - 1/2gt²

s = -1/2gt²

Since the distance the red ball falls is s = -1/2gt² with t = 12 s, we have

s = -1/2gt²

= -1/2 × 9.8 m/s² × (12 s)²

= -1/2 × 9.8 m/s² × 144 s²

= -4.9 m/s² × 144 s²

= -705.6 m

Since the distance the red ball falls is s = -1/2gt² with t = 24 s, we have

s' = -1/2gt²

= -1/2 × 9.8 m/s² × (24 s)²

= -1/2 × 9.8 m/s² × 576 s²

= -4.9 m/s² × 576 s²

= -2822.4 m

So, the distance the red ball travelled between 12 s and 24 s is d = s' - s

= -2822.4 m - (-705.6 m)

= -2822.4 m + 705.6 m

= -2116.8 m

So, the distance the red ball travelled between 12 s and 24 s is 2116.8 m

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In order to prevent overloading of any circuit, dual rail electrical supply includes independent tracks and P C B traces that are used to offset voltage sags between various circuits.

Using conductive paths, tracks, or signal traces etched from copper sheets laminated onto a non-conductive substrate, a printed circuit board, or PCB, is used to mechanically support and electrically link electronic components.

Semiconductors are used by practically all inverters to generate a controlled power output. An input voltage is rectified if the source has an ac input.

It is, therefore, the proper response.

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The potential difference between point a and point b of the circuit is 46.5 V.

The potential difference between point a and point b of the circuit is calculated as follows;

To determine the current flowing in the closed section of the circuit, we simply remove portion a and the resistance attached to it.

Now, we have two resistors in series, and the total resistance is calculated as follows;

Rt = R + R

Rt = 2R

The current flowing in the circuit is calculated as;

I = V/Rt

I = 5V/2R

I = 2.5 A/R

The initial voltage at point a = 49 V

When we move from point a to point b we will encounter a resistance of R, so voltage drop at this point is calculated as;

V = IR

V = 2.5 A/R x R = 2.5 V

The potential difference = 49 V - 2.5 V = 46.5 V

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Ampere s law is valid only for a long straight wire. This statement is False.

Ampere's Law, formulated by André-Marie Ampère, is a fundamental principle in electromagnetism that relates the magnetic field around a closed loop to the electric current passing through that loop. It states that the line integral of the magnetic field around a closed loop is proportional to the net current passing through the loop. Ampere's Law is not limited to long straight wires. It holds true for any closed loop, regardless of its shape or the configuration of the current-carrying elements. This includes situations with curved wires, loops, solenoids, and more complex current distributions. However, for a long straight wire, Ampere's Law simplifies the calculations as the magnetic field around it has a uniform and symmetrical distribution. This simplification allows for easier application and analysis of Ampere's Law in this specific case. But it is important to note that Ampere's Law is a general principle that applies to various geometries, not just long straight wires.

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The pressure is changing at a rate of 6.25 lb/in²/sec at this instant.

At a certain instant, the pressure is 50 lb/in², and the volume is 32 in³, which is decreasing at a rate of 4 in³/sec. We have to determine how rapidly the pressure is changing at this instant. The relation between pressure and volume can be given by the formula

PVⁿ = constant

Where P is the pressure,

V is the volume,

and n is a constant.

Since we have only one relation, we can differentiate it with respect to time to get the required relation. At this moment, the volume is changing at the rate of 4 in³/sec, so

dV/dt = -4

Differentiating the formula with respect to time we get:

PdV/dt + VdP/dt = 0

=> dP/dt

= -(PdV/dt)/VAt

this instant, the volume is 32 in³ and is decreasing at a rate of 4 in³/sec.

dV/dt = -4in³/secV

= 32 in³dP/dt

= -(PdV/dt)/V

= -[50 × (-4)]/32

= 6.25 lb/in²/sec

Therefore, the pressure is changing at a rate of 6.25 lb/in²/sec at this instant.

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your answer is c bro but if not then it's b

because you just choose c or b either one should work if you right it down right

A. If you were to travel to a planet that has twice the mass of Earth, Your weight would stay the same.

The weight of an object is a quantity representing the force exerted on a particle or the object by an acceleration field, particularly the gravitational field of the Earth at the surface.

W = mg

where;

The weight of an object depends on mass and acceleration due to gravity.

If you were to travel to a planet that has twice the mass of Earth, the following will be observed;

Thus, If you were to travel to a planet that has twice the mass of Earth, Your weight would stay the same.

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For the eutectoid composition steel initially equilibrated at 730°C, the transformation products and approximate percent after each step for the given cooling procedures are:

1. (a) Quench to 650°C and hold for 100 seconds =  steel will transform to pearlite 50% and 50% austenite.
   (b) Then cool to room temperature= the austenite will transform completely to pearlite.

2. (a) Quench to 650°C and hold for 2 seconds (2 = 100.3)= steel will transform to 99.7% pearlite and 0.3% austenite.
   (b) Then quench to room temperature= the remaining austenite will transform completely to 100%pearlite.

3. (a) Quench to 650°C and hold for 10 seconds=the steel will transform to 95% pearlite and 5% austenite.
   (b) Then quench to room temperature= the remaining austenite will transform completely to 100% pearlite.

4. (a) Quench to 400°C and hold for 3.16 seconds (3.16 = 100.5)= the steel will transform to 50% bainite and 50% austenite.
   (b) Then quench to room temperature=the retained austenite will transform to  100% martensite.

5. (a) Quench to 400°C and hold for 25 seconds (25 = 101.4)= the steel will transform to 91% bainite and 9% retained austenite.
   (b) Then quench to room temperature= the retained austenite will transform to  100% martensite.

6. (a) Quench to 400°C and hold for 200 seconds (200 = 102.3)=the steel will transform to  33% pearlite, 33% bainite, and 34% retained austenite.
   (b) Slow cool to room temperature= the retained austenite will transform to 67% pearlite and 33% martensite.

7. (a) Quench to 0°C in 10 seconds=the steel will transform to martensite.
   (b) Heat to 600°C and hold for 1000 seconds=the martensite will transform to 100% austenite.

1. (a) Quench to 650°C and hold for 100 seconds.

(b) Then cool to room temperature.

After step 1(a), the steel will transform to pearlite with approximately 50% pearlite and 50% austenite. After step 1(b), the austenite will transform completely to pearlite, resulting in 100% pearlite.

2. (a) Quench to 650°C and hold for 2 seconds (2 = 100.3).
   (b) Then quench to room temperature.

After step 2(a), the steel will transform to pearlite with approximately 99.7% pearlite and 0.3% austenite. After step 2(b), the remaining austenite will transform completely to pearlite, resulting in 100% pearlite.

3. (a) Quench to 650°C and hold for 10 seconds.
   (b) Then quench to room temperature.

After step 3(a), the steel will transform to pearlite with approximately 95% pearlite and 5% austenite. After step 3(b), the remaining austenite will transform completely to pearlite, resulting in 100% pearlite.

4. (a) Quench to 400°C and hold for 3.16 seconds (3.16 = 100.5).
   (b) Then quench to room temperature.

After step 4(a), the steel will transform to bainite with approximately 50% bainite and 50% retained austenite. After step 4(b), the retained austenite will transform to martensite, resulting in approximately 100% martensite.

5. (a) Quench to 400°C and hold for 25 seconds (25 = 101.4).
   (b) Then quench to room temperature.

After step 5(a), the steel will transform to bainite with approximately 91% bainite and 9% retained austenite. After step 5(b), the retained austenite will transform to martensite, resulting in approximately 100% martensite.

6. (a) Quench to 400°C and hold for 200 seconds (200 = 102.3).
   (b) Slow cool to room temperature.

After step 6(a), the steel will transform to pearlite with approximately 33% pearlite, 33% bainite, and 34% retained austenite. During step 6(b), the retained austenite will transform to martensite, resulting in approximately 67% pearlite and 33% martensite.

7. (a) Quench to 0°C in 10 seconds.
   (b) Heat to 600°C and hold for 1000 seconds.

After step 7(a), the steel will transform to martensite. After step 7(b), the martensite will transform to austenite, resulting in 100% austenite.

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The escape speed of the rocket from the Earth's Moon is 2,375.43 m/s.

The escape speed for a rocket to leave Earth's Moon is calculated by applying the following formula.

v = √ ( 2GM / r )

where;

The escape speed of the rocket from the Earth's Moon is calculated as;

v = √ ( 2 x 6.67 x 10⁻¹¹ x 7.36 x 10²² / 1,740,000 )

v = 2,375.43 m/s

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The number of constructive interference points enclosed between two speakers is 9. It can be calculated by using wave length formula.

From the question, we can get information:

F = 500 Hz

2 speakers were separated 6 m, so d= 6 m

V = 331 m/s

We can get the wavelength of sound by the formula:

λ= v/f

   = 331/500

   = 0.662 m

Since the separation between any two consequent constructive interference point = λ

Since both the waves are emitting sound waves in phase the total number of constructive interference points which can fit in between the separation between speakers = n

nλ = d

so n = d/λ

= 6/0.662

= 9.0634

= 9

So The number of constructive interference points enclosed between two speakers is 9

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What does your model look like and the one it's being compared to?

Answer:

you should prolly put the model

Explanation:

Answer:I have to say 56

Explanation: because it is going up by 8

Answer:

Below

Explanation:

VERTICAL velocity will be   v  sin 34

HORIZONTAL velocity will be   v cos 34  = 86 cos 34 = 71.3 m/s

Using Newton's second law

\(\\ \sf\Rrightarrow F=ma\)

\(\\ \sf\Rrightarrow F=142(30)\)

\(\\ \sf\Rrightarrow F=4260N\)

Answer:

the image can be rather real or virtual

Answer:

1 Watt

Explanation:

P=W/t

P=10/10

P=1 Watt

The process of losing an electron, such as when a free radical steals an electron from a stable molecule, is called electron dissociation.

Electron dissociation occurs when an electron is removed from a stable molecule, resulting in the formation of an ion. This process can be initiated by various mechanisms, including the interaction of the molecule with other reactive species like free radicals. Free radicals are highly reactive molecules that contain an unpaired electron, and they often seek to stabilize themselves by acquiring an electron from nearby molecules.

When a free radical steals an electron from a stable molecule, it causes the molecule to lose an electron and become ionized. This electron dissociation process can have important implications in various chemical reactions and biological processes, as it can lead to the formation of new chemical species and impact the overall reactivity of molecules.

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here, we have given kinetic energy = 3.2 J

mass= 428.5 kg = 0.4285 gm

so now we know,

K.E = \(1/2mv^{2}\)

v= \(\sqrt{2K/m}\)

v= \(\sqrt{2*3.2/0.4285}\)

v=\(\sqrt{14.94}\)

v=3.86 m/s.

at 3.86m/s object will be moving to possess a kinetic energy of 3.2 j.

kinetic energy.

v= velocity

m= mass

K.E = kinetic energy

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Answer:

(A). The force acting on the rocket is mg.

(B). The initial upward acceleration of the rocket is 6.2 m/s²

Explanation:

Given that,

Mass of rocket = 5 kg

Force = 80 N

Time = 4 sec

(A). We need to draw the figure

The force acting on the rocket at each of the intervals is shown in figure.

The force acting on the rocket is mg.

(B). We need to calculate the initial upward acceleration of the rocket

Using balance equation

\(ma=F-mg\)

\(a=\dfrac{F-mg}{m}\)

Put the value in the equation

\(a=\dfrac{80-5\times9.8}{5}\)

\(a=6.2\ m/s^2\)

Hence, (A). The force acting on the rocket is mg.

(B). The initial upward acceleration of the rocket is 6.2 m/s²

The energy gap is about 8 kilocalories per pound of lost weight. bill has just lost 25 pounds, so he needs 200 fewer kilocalories per day to maintain his weight loss.

When someone loses weight, their body requires fewer calories to maintain their new weight. This is because the body has less mass to maintain, and therefore requires less energy to do so.

The amount of energy saved per pound of weight loss is referred to as the energy gap. In this case, the energy gap is 8 kilocalories per pound of lost weight. This means that for every pound of weight lost, the body requires 8 fewer kilocalories per day to maintain that weight loss.

If Bill has just lost 25 pounds, then he would need to consume 8 x 25 = 200 fewer kilocalories per day to maintain his weight loss compared to what he needed before his weight loss.

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Answer:

The answer is 9.4 m/s

Explanation:

Because you add 5.0 + 4.5= 9.4

(a) The value of C is 12.17 V/mm.

(b) The electric field is 27.04 N/m².

(c) The force is 1.90 x 10⁻¹⁷ N.

a) To determine the value of C, we first need to calculate x, which is the distance from the cathode to the anode. Using the given distance between the cathode and anode (13.6 mm), we can calculate x as 6.8 mm. We can then use this value of x, along with the given potential difference between the electrodes (264 V), to calculate the value of C using the equation C = V/x4/3:

C = 264 V/6.84/3 = 12.17 V/mm4/3

b) The electric field between the electrodes is given by Ex = -dV/dx. Using the result from part (a) for C and the given distance between the electrodes (13.6 mm), we can obtain a formula for Ex as a function of x:

Ex = -(12.17 V/mm4/3) x (4/3)x-5/3 =27.04 N/m²

c) The force on an electron when the electron is halfway between the electrodes can be calculated using the equation F = qEx, where q is the charge of the electron. Using the result from part (b) for Ex, we can calculate the force on an electron at x = 6.8 mm as:
F = -1.60 x 10⁻¹⁹ C x (-11.9 V/mm1/3)

F = 1.90 x 10⁻¹⁷ N

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