Suppose the reaction Ca3(PO4)2 + 3H2SO4 → 3CaSO4 + 2H3PO4 is carried out starting with 149 g of Ca3(PO4)2 and 86.9 g of H2SO4. How much phosphoric acid will be produced?

The new volume of the gas whose pressure was changed would be = 40 milliliters.

The initial volume(V1)of the gas= 20ml

The initial pressure(P1) = 4 atm

The final pressure(P2) = 2 atm

The final volume(V2) = ?

Using the general gas formula;

P1V1 = P2V2

V2 = P1V1/P2

= 4×20/2

= 40ml

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The term that the scientist would use in this case is partial pressure. Option D

The pressure that one particular gas component within a mixture of gases exerts is referred to as partial pressure. It is the pressure that the gas would experience at the same temperature if it were the only thing in the entire volume.

When researching gas mixtures, such as in gas laws, gas phase equilibria, and gas collecting methods, partial pressures are extremely crucial for the gas.

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The combustion of methane can be represented by the equation CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)We are to find the standard enthalpy of combustion of methane.

We are also to create a Hess enthalpy diagram for the reaction. Standard enthalpy of combustion is the amount of energy released when one mole of a substance is completely burned in excess oxygen at standard temperature and pressure. We can use the data in the table to calculate the standard enthalpy of combustion of methane.The table gives us the standard enthalpies of formation of the reactants and products. The standard enthalpy of formation is the amount of energy change that occurs when one mole of a compound is formed from its constituent elements in their standard states (usually at 25°C and 1 atm).We can use the standard enthalpies of formation to calculate the standard enthalpy of combustion of methane. The standard enthalpy of combustion is given by the following equation:ΔH°c = ΣΔH°f(products) – ΣΔH°f(reactants)We can calculate the standard enthalpy of combustion of methane using the standard enthalpies of formation from the table as follows:ΔH°c = [ΔH°f(CO2(g)) + 2ΔH°f(H2O(g))] – [ΔH°f(CH4(g)) + 2ΔH°f(O2(g))]Substituting the values from the table:ΔH°c = [(–393.5 kJ/mol) + 2(–241.8 kJ/mol)] – [(–74.8 kJ/mol) + 2(0 kJ/mol)]ΔH°c = (–890.2 kJ/mol) – (–74.8 kJ/mol)ΔH°c = –815.4 kJ/mol. Therefore, the standard enthalpy of combustion of methane is –815.4 kJ/mol.We can create a Hess enthalpy diagram for the reaction as shown below: The Hess enthalpy diagram is used to show how the standard enthalpy of the reaction can be calculated using the standard enthalpies of formation of the reactants and products. The diagram shows the two steps involved in the reaction. The first step involves the breaking of the bonds in methane and oxygen to form the reactants. The second step involves the formation of the products from the reactants. The standard enthalpy of combustion is the difference between the standard enthalpies of formation of the products and reactants. The Hess enthalpy diagram shows that the same standard enthalpy of combustion can be obtained regardless of the pathway taken to get from reactants to products.

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Answer: Pentane C5H12

Explanation:

The boiling point of a substance is simply defined as the temperature whereby a liquid's vapor pressure is equal to the pressure that is surrounding the liquid and hence, the liquid will changes into vapor.

The likely molecular formula for this compound is Pentane i.e C5H12 due to the fact that its boiling point is between Butane with formula C4H10 and Hexane with formula C6H14 boiling points.

The molecular formula of the of the substance is \(\bold {C_5H_1_0}\) (pentane).

Boiling point:

It is the temperature at which liquid's vapor pressure is equal to the pressure that is surrounding the liquid and hence, the liquid start to into vaporize.

The boiling point of the given compound is 309 K which is between Butane  and Hexane.

Therefore, the molecular formula of the of the substance is \(\bold {C_5H_1_0}\) (pentane).

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Answer:

1.91 atm

Explanation:

Step 1: Calculate Henry's constant (k)

A gas has a solubility (C) of 2.45 g/L at a pressure (P) of 0.750 atm. These two variables are related to each other through Henry's law.

C = k × P

K = C/P

K = (2.45 g/L)/0.750 atm = 3.27 g/L.atm

Step 2: Calculate the pressure required to produce an aqueous solution containing 6.25 g/L of this gas at constant temperature.

We have C = 6.25 g/L and k = 3.27 g/L.atm. The required pressure is:

C = k × P

P = C/k

P = (6.25 g/L)/(3.27 g/L.atm) = 1.91 atm

Answer:

Water-gas A mixture of carbon monoxide (CO) and hydrogen (H2) produced by passing steam over red-hot coke using the endothermic reaction C + H2O → CO + H2.

Answer:Compounds are chemical substances that contain more than one element. They're created during a chemical reaction where atoms are rearranged into new compound molecules. For example, if carbon atoms react with oxygen atoms they form carbon dioxide molecules.

Explanation:

Answer

A. Acidic

Explanation

Given:

[H⁺] = 2.65 x 10⁻² M

Note that: the pH values range from 0 - 14, with 7 being neutral. pHs of less than 7 indicate acidity, whereas a pH of greater than 7 indicates a base.

Also, the pH of a solution can be determine using the pH formula below:

So pH = - log [2.65 x 10⁻²]

pH = 1.58

The pH of the solution fall in the acidic range. Hence, the solution acidic.

Answer:

i. Molar mass of glucose = 180 g/mol

ii. Amount of glucose = 0.5 mole

Explanation:

The volume of the glucose solution to be prepared = 500 \(cm^3\)

Molarity of the glucose solution to be prepared = 1 M

i. Molar mass of glucose (\(C_1_2H_6O_6\)) = (6 × 12) + (12 × 1) + (6 × 16) = 180 g/mol

ii. mole = molarity x volume. Hence;

amount (in moles) of the glucose solution to be prepared

                 = 1 x 500/1000 = 0.5 mole

water acts as the solvent for this experiment

we use to calculate R f values and compare with know to determine the compound is made of example in forensic science to find DNA, amino acids

most soluble one will travel the most

c to b to a (A most further travelled)

Explanation:

This quest in requires general knowledge on chromatography

N5+ + 2e →N³

here Nitrogen gains electron so, its reduction half-reaction

20²- → 0₂

here oxygen loss electron so, its oxidation half-reaction

20² → 20₂ + 4e¯​

here oxygen loss electron so, its oxidation half-reaction

2N5+ + 4e¯ → 2N³

here nitrogen gains electron so, its reduction half-reaction

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Answer:

physical property is property that you can touch, smell as it is bumpy it smells like eggs.

Explanation:

YW

Answer:

Physical properties include: appearance, texture, color, odor, melting point, boiling point, density, solubility, polarity, and many others.

Explanation:

Answer:

C

Explanation:

Answer:

ganyan din ang alam ko

Explanation:

letter c

You would recover 36.525g of NaCl after evaporating all of the water.

To find the grams of NaCl that would be recovered after evaporating all the water, we can use the following formula:

mass = moles * molar mass

Where:

Moles = Molarity * Volume

Molarity = 0.250 M

Volume = 2500.0 mL = 2.5 L

Molar mass of NaCl = 58.44 g/mol

mass = 0.250 M * 2.5 L * 58.44 g/mol

mass = 36.525 g

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The molecule must possess dipolar bonds, exhibit suitable vibrational frequencies, and be in a form that can be analyzed using IR spectroscopy in order to be studied in an IR spectrum.

To study a molecule in an infrared (IR) spectrum, several criteria need to be considered. Firstly, the molecule should have a dipole moment, meaning it must have a separation of positive and negative charges within the molecule.

This is because IR spectroscopy primarily detects vibrations of covalent bonds, which are associated with changes in dipole moment.Additionally, the molecule should have covalent bonds that can undergo vibrational modes within the range of the instrument. IR spectroscopy typically covers the frequency range of 4000 to 400 cm⁻¹, which corresponds to the energies of molecular vibrations.

The molecule should also be able to be vaporized or dissolved in a suitable solvent to generate a homogeneous sample for analysis. Gaseous or liquid samples are commonly used in IR spectroscopy.

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Answer:

pH = 10.95

Explanation:

To solve this question we must, as first, find pKb of dimethylamine. Then, using H-H equation we can solve the pH of the buffer:

pKb dimethylamine:

Based on the equilibrium:

(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH2⁺(aq) + OH-(aq)

Kb is defined as:

Kb = [OH-] [(CH3)2NH2⁺] / [(CH3)2NH]

Both (CH3)2NH2⁺(aq) + OH- comes from the same equilibrium, that means:

[OH-] = [(CH3)2NH2⁺]

And: [(CH3)2NH] = 0.457M

[OH-] can be obtained from pH as follows:

14 -pH = pOH

14-12.2 = 1.8 =pOH

10^-pOH = [OH-] = 0.01585M

Replacing:

Kb = [0.01585M] [(0.01585M] / [0.457M]

Kb = 5.50x10⁻⁴

pKb = -logkb = 3.26

pH of the buffer:

Using H-H equation for bases:

pOH = pKb + log [conjugate acid] / [weak base]

pOH = 3.26 + log [0.280M] / [0.457M]

pOH = 3.05

pH = 14 - pOH

Given the heat of fusion of water is 6.02 kJ/mol, it takes 12.9 kJ of heat to melt 38.6 g of ice at 0 °C.

Fusion, commonly known as melting, is a physical process in which matter passes from the solid to the liquid state.

We have ice with a mass of 38.6 g at 0 °C. First, we will convert mass to moles using the molar mass of water.

38.6 g × (1 mol/18.02 g) = 2.14 mol

The heat of fusion (ΔH°fus) for water is 6.02 kJ/mol. The heat (Q) required to melt 2.14 moles of ice is:

Q = 6.02 kJ/mol × 2.14 mol = 12.9 kJ

Given the heat of fusion of water is 6.02 kJ/mol, it takes 12.9 kJ of heat to melt 38.6 g of ice at 0 °C.

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Answer:

0.725 kg

Explanation:

Step 1: Given data

Step 2: Calculate the mass of the softball

We will use the following expression.

K = 1/2 × m × v²

m = 2 K / v²

m = 2 × 145 J / (20.0 m/s)²

m = 0.725 kg

The mass of the softball is 0.725 kg.

Yes, Fe(s)+CuSO4→FeSO4(aq)+Cu(s) is a redox reaction. The reducing agent is Fe(s), while the oxidizing agent is CuSO4.

Oxidation-reduction reaction is the type of reaction in which electrons are transferred from one element to another. A compound or an element either gains are looses an electron in redox reactions.

Fe(s)+CuSO4→FeSO4(aq)+Cu(s)

From the equation above, Fe(s) is the reducing agent because it gives away 2 electrons and undergoes oxidation reaction.

From the equation above, CuSO4 is an oxidizing agent because it gives oxygen to Fe(s) and undergoes a reduction reaction.

Therefore, the reducing agent is Fe(s), while the oxidizing agent is CuSO4.

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Answer:

2nd one down

Explanation: distance divided by time interval

Answer: The answer is incus

Answer:

the answer is D . water

Explanation:

the others are organic molecules

By a redox reaction that involves the transfer of electrons, often through the dissolution of an ionic substance, electrochemical cells produce electricity from the flow of electrons.

In electrochemistry, redox or oxidation-reduction reactions, in which electrons travel from one element to another, can produce electricity. Redox processes involve the transfer of electrons from one substance to another.

Batteries use a very significant class of oxidation and reduction reactions to produce useable electrical energy. Using solutions of respective sulphates, copper and zinc metals can be combined to create a straightforward electrochemical cell.

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Consider a solution containing alcohol and water. If the mole fraction of water is 0.600, 0.4 is the mole fraction of alcohol.

A mole fraction is indeed a measurement of concentration that is equal to the product of the moles of such a component and the total moles of the solution.

Mole fraction is indeed a unitless phrase since it represents a ratio. When all the parts of a solution's mole fraction are summed up, they equal one.

mole fraction of water + mole fraction of alcohol =1

mole fraction of water=0.600

mole fraction of alcohol =1

mole fraction of alcohol =1-0.600 =0.4

Therefore, 0.4 is the mole fraction of alcohol.

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This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li

To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.

Let's analyze the given representations:

36Li:

This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.

613C:

This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.

3063Cu:

This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.

1530P:

This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.

Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.

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The amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

To find the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C, we can use the equation Q = mcAT.
First, we need to find the value of m, which is the mass of the water in grams. In this case, it is given as 200 grams.
Next, we need to find the value of AT, which is the change in temperature in degrees Celsius.

This can be calculated by subtracting the initial temperature from the final temperature, which gives us 60 C - 20 C = 40 C.
The specific heat capacity of water, C, is given as 4.18 Joules per gram per degree Celsius.
Now we can plug in the values into the equation:
Q = mcAT
Q = (200 g) x (4.18 J/g°C) x (40°C)
Q = 33,440 J
Therefore, the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

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