Suppose the galvanic cell sketched below is powered by the following reaction: Mn(s)+NiSO4(aq) + MnSO4(aq)+Ni(s) E1 E2 S1 S2 ロ→ロ Write a balanced equation for the half-reaction that happens at the cathode of this cell. Write a balanced equation for the half-reaction that happens at the anode of this cell. DO. Of what substance is El made? Х 5 ? Of what substance is E2 made? What are the chemical species in solution Sl? What are the chemical species in solution S2?

There are two atoms with mass numbers of 2 best describes the mass numbers of the atoms in the reaction

The sum of protons and neutrons in an atomic nucleus is known as the mass number, often known as the atomic mass number or nucleon number. It roughly equates to the atom's atomic mass given in atomic mass units.

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Answer:

Pop your popcorn for 2 minutes in the microwave but if you like to pop your popcorn old fashion get popcorn seeds and put them in an pot and then put a lid over it then pop it.

Explanation:

The concentration of the HNO₃ solution needed to neutralize the 27.60 mL of 1.00 M NaOH is 2.76 M

The balanced equtaion is given below:

HNO₃ + NaOH —> H₂O + NaNO₃

Now, we shall obtain the concentration of the HNO₃ solution needed for the neutralization reaction. This is shown below:

CaVa / CbVb = nA / nB

(Ca × 10) / (1 × 27.6) = 1

(Ca × 10) / 27.6 = 1

Cross multiply

Ca × 10 = 27.6

Divide both side by 10

Ca = 27.6 / 10

Ca = 2.76 M

Thus, the concentration of the HNO₃ solution needed is 2.76 M

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Answer:

it's Beryllium

Explanation:

The sample of the gas will occupy 0.947 L.

Since there are no changes in the temperature, we use the following formula to relate both values of pressure:

Then, we replace the values to find the volume:

So, the sample of the gas will occupy 0.947 L.

Answer:

283.211

Explanation:

Chemical reactions like Canizzaro reaction involves  a chemical reaction which involves base-induced disproportionation of two molecules of  non-enolizable aldehyde to give a primary alcohol and a carboxylic acid while Stephen reaction involves the preparation of aldehydes from nitriles using tin(II) chloride,hydrochloric acid and quenching the resulting iminium salt with water.

Chemical reactions are defined as reactions which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical reaction.

There are several characteristics of chemical reactions like change in color, change in state , change in odor and change in composition . During chemical reaction there is also formation of precipitate an insoluble mass of substance or even evolution of gases.

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According to the law of conservation of mass, the mass of CO₂ formed is 6.15 g.

The mass of  Carbon dioxide, CO₂ is produced from the given reaction between 15.00 g of CaCO3 powder and add it to 60.75 g of HCl solution is determined as follows:

The mass of the calcium carbonate, CaCO₃ reacting = 15.0 g

Mass of HCl solution reacting = 60.75 g

Total mass of reactants = 60.75 g + 15.0 g

Total mass of reactants = 75.75 g

On addition of the calcium carbonate to the HCl solution, bubbles of carbon dioxide gas, CO₂, were observed and the gas allowed to escape.

Equation of the reaction: CaCO₃ (s) + 2 HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)

Mass of resulting solution = 69.60 g

According to the law of conservation of mass, mass of product = mass of reactant

Therefore, mass of CO₂ formed = 75.75 g - 69.60 g

mass of CO₂ formed = 6.15 g

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Answer:

38.8125

Explanation:

4.5 x 5.750 x 1.50 = 38.8125

Answer:

The three pKa values for phosphoric acid (H3PO4) are 2.12, 7.21, and 12.32.

Answer:

V = 268.8 L

Explanation:

Given data:

Number of moles of nitrogen = 12 mol

Temperature = 273 K

Pressure = 1atm

Volume occupy = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

1 atm × V = 12 mol ×0.0821 atm.L/ mol.K   × 273 K

V = 268.95 atm.L / 1 atm

V = 268.8 L

\(Na^+\), \(Ca^2^+\), \(F^-\), and \(S^2^-\) are monoatomic ions, while \(Cr^2^+\), \(Hg^2^+\), \(ClO^-\), \(OH^-\), NO3-, and ClO3- are polyatomic ions. H₂O is not an ion; it is a neutral molecule.

Monoatomic ions are ions formed from a single atom, while polyatomic ions are ions formed from a group of atoms bonded together. Let's classify each of the ions you provided:

Monoatomic ions:

- Na+ (sodium ion)

- Ca2+ (calcium ion)

- F- (fluoride ion)

- S2- (sulfide ion)

Polyatomic ions:

- Cr2+ (chromium(II) ion) - This ion should be Cr2+, indicating a two-positive charge on the chromium ion. It is typically found in compounds with ligands to stabilize its charge.

- Hg2+ (mercury(II) ion) - This ion is a polyatomic ion due to the presence of two mercury atoms bonded together.

- H₂O (water molecule) - This is not an ion; it is a neutral molecule consisting of two hydrogen atoms bonded to one oxygen atom.

- ClO- (hypochlorite ion) - This is a polyatomic ion consisting of chlorine and oxygen atoms.

- OH- (hydroxide ion) - This is a polyatomic ion consisting of one oxygen and one hydrogen atom.

- NO3- (nitrate ion) - This is a polyatomic ion consisting of one nitrogen and three oxygen atoms.

- ClO3- (chlorate ion) - This is a polyatomic ion consisting of one chlorine and three oxygen atoms.

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Monoatomic ions consist of a single atom, while polyatomic ions consist of more than one atom. For example, Na+ is monoatomic, while NO3- is polyatomic.

To classify ions as either monoatomic or polyatomic, you need to know the nature of these ions. Monoatomic ions are ions made up of a single atom, while polyatomic ions are made of more than one atom. For example, Na+ is a monoatomic ion because it consists of a single sodium atom. On the other hand, NO3- is a polyatomic ion because it consists of one nitrogen atom and three oxygen atoms.

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1. The IUPAC name of N is nitrogen.

2. Nitrogen dioxide

3.The IUPAC name of O is oxygen

4.The IUPAC name of OH is hydroxyl.

The IUPAC name of ·0 is a radical. It is commonly found in organic chemistry and plays an important role in many reactions.

IUPAC names for the given compounds are:1.1. N: Nitrogen

The IUPAC name of N is nitrogen.

It is a non-metal and belongs to group 15 in the periodic table. It has an electronic configuration of 1s2 2s2 2p3.1.2. NO2: Nitrogen dioxide

Explanation: NO2 is a chemical compound that is formed by the combination of nitrogen and oxygen. It is a reddish-brown gas that has a pungent odor.

The IUPAC name of NO2 is nitrogen dioxide.1.3. O: Oxygen

Explanation: The IUPAC name of O is oxygen.

It is a non-metal and belongs to group 16 in the periodic table. It has an electronic configuration of 1s2 2s2 2p4.

X: UnknownExplanation: No IUPAC name can be given to an unknown compound as the structure and composition are not known.

Y: Hydroxyl Explanation: The IUPAC name of OH is hydroxyl.

It is a functional group that is composed of an oxygen atom and a hydrogen atom (-OH). It is commonly found in alcohols and phenols. ·0: RadicalExplanation: A radical is a molecule or an ion that contains an unpaired electron.

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Note: The complete question is given below

Provide the IUPAC names for the following compounds:

\(CH_3CH_2CH(CH_3)CH_2CH_2CH_2CH_3\)

C6H5CH(CH3)2

H2NCH2CH2CH2CH2CH2NH2

CH3CH2CH2CH2CH2OH

CH3CH2CH2CHOHCH3

The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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A substance's temperature in physics' laws, is directly related to the average kinetic energy of its particles. Because the particles' mass is constant, they must travel faster as the temperature rises.

In physics, the kinetic energy of an object is the energy it possesses as a result of its motion. It is defined as the amount of work required to accelerate a body of a given mass from rest to a given speed.

The body retains its kinetic energy, having acquired it during acceleration, until its speed changes.

Kinetic energy is present in an accelerating ball, a walking human, and electromagnetic radiation like light. Another type of kinetic energy is the energy associated with the continuous, random bouncing of atoms or molecules.

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To answer this question, we need to use the ideal gas law equation, which states that PV=nRT, where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the universal gas constant, and T is the temperature of the gas.

Assuming that the sample is at standard temperature and pressure (STP), which is 0 degrees Celsius and 1 atmosphere of pressure, we can use the molar volume of gas at STP, which is 22.4 liters per mole.
So, if we know the volume of the sample, we can calculate the number of moles of oxygen gas in the sample. Let's say the volume of the sample is 50 liters.
Using the formula, we can rearrange it to solve for n: n = PV/RT. Plugging in the values we have, we get:
n = (1 atm) x (50 L) / [(0.08206 L x atm/mol x K) x (273 K)]
Simplifying this, we get n = 1.83 moles of oxygen gas in the sample.
Therefore, there are about 1.83 moles of oxygen gas in the sample, assuming that it is at STP and has a volume of 50 liters.

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The number of moles in 6.0 × 10²⁴ atoms of oxygen is 5 moles (option D).

The number of moles in a substance can be calculated by dividing the number of atoms of the substance by Avogadro's number as follows:

no of moles = no of atoms ÷ 6.02 × 10²³

According to this question, a sample of oxygen gas is said to contain 6.0 × 10²⁴ atoms of oxygen. The number of moles in this substance can be calculated as follows:

no of moles = 6.0 × 10²⁴ atoms ÷ 6.02 × 10²³

no of moles = 1 × 10¹ = 10 moles of oxygen gas

10 ÷ 2 = 5 moles of oxygen atom

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Answer:

neutral

Explanation:

pH is usually (but not always) between 0 and 14. Knowing the dependence of pH on [H +], we can summarize as follows: If pH < 7, then the solution is acidic. If pH = 7, then the solution is neutral

Answer: The absorbance for a solution is 0.0028

Explanation:

To calculate the absorption of a solution, the equation by Beer-Lambert law is used:

\(A=\varepsilon \times b\times C\)

OR

\(A=\varepsilon \times b\times \frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}\)

where,

A = absorbance = ?

\(\varepsilon\) = molar absorptivity = \)15000m^2mol^{-1}L\)

b = path length = 1 cm = 0.01 m                 (Conversion factor: 1 m = 100 cm)

Given mass of \(\beta-\) carotene = 0.1 mg = 0.0001 g     (Conversion factor: 1 g = 1000 mg)

Molar mass of \(\beta-\) carotene = 536 g/mol

Volume of solution = 10 mL

Putting values in equation 1:

\(A=15000\times 0.01\times \frac{0.0001\times 1000}{536\times 10}\\\\A=0.0028\)

Hence, the absorbance for a solution is 0.0028

Answer:

5l NO

2

at STP

No. of molecules=

22.4

5

mol=

22.4

5

×N

A

molecules

A) 5ℊ of H

2

(g)

No. of moles=

2

5

mol=

2

5

×N

A

molecules

B) 5l of CH

4

(g)

No. of moles of CH

4

=

22.4

5

mol=

22.4

5

N

A

molecules

C) 5 mol of O

2

=5N

A

O

2

molecules

D) 5×10

23

molecules of CO

2

(g)

Molecules of 5l NO

2

(g) at STP=5l of CH

4

(g) molecules at STP

Therefore, option B is correct.

Was this answer helpful?

Answer:48

Explanation:

Answer:  3. 0.125 X 10”23 molecules

Explanation:

Answer:

0 °C

Explanation:

Answer:

0 C

Explanation:

If the metal was not heated long enough, the calculated specific heat of the metal will be different from then measured specific heat capacity of the metal, and there will be error in measurement of the specific heat capacity of the metal

The specific heat capacity of a metal is the quantity of heat required to raise the temperature of a unit mass of the metal by 1 kelvin.

The heat capacity of a metal and its specific heat capacity is given by the following formula.

Q = mcΔθ

c = Q/mΔθ

where;

When a metal is heated for a long period of time, it acquires thermal energy which causes its temperature to increase.

As the temperature of the metal increases, the difference in temperature of the metal increases as well. The increase in the temperature difference of the metal causes a decrease in the specific heat capacity of the metal.

However, if the metal was not heated long enough, the difference in temperature of the metal will be small and the value of the specific heat capacity will increase.

When the value of the specific heat capacity increases, it will be different from the calculated specific heat of the metal and cause error in measurement of specific heat capacity of the metal.

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In most experiments, the decay of a large number of radioactive isotopes over time is measured in order to calculate the half-life of a radioactive isotope. They compute the quantity of radioactive atoms still present at various time points and graph the data. Time is represented on the x-axis, while the quantity of radioactive atoms left is shown on the y-axis.

In an exponential decay curve, the remaining number of atoms declines quickly at initially before gradually levelling out on the graph. The amount of time it takes for half of the radioactive atoms in a sample to decay is known as the half-life. Scientists seek for the point on the graph where the number of atoms left is half of what it was to establish the half-life. They pick out this location on the graph and calculate the associated time. The radioactive isotope's half-life is represented by this period of time.

Similar to your example with the dimes, you could display this data on a graph if you were to run an experiment in which you threw a lot of dimes and counted how many were still there after each toss. The x-axis would show the number of tosses, and the y-axis would show how many dime are left.

If the surviving dimes follow a pattern similar to radioactive decay, you would notice a steady decline in their quantity over time. Even if the graph isn't a perfect exponential decay curve, you can still locate a point where the number of dimes left is half of what they were initially. The "half-life" of the dimes in your experiment would be represented by the corresponding number of throws at this stage.

You can comprehend the general idea of finding the time or number of events necessary for a quantity to reduce to half of its initial value by drawing a comparison between figuring out the half-life of radioactive isotopes and the fictitious scenario of figuring out the "half-life" of dimes.

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Answer:

20M or 20mol/L

Explanation:

molarity = moles/volume (in Liters)

= 2.5/0.125L

=20M or 20 mol/L

To balance the equation and identify the type of reaction, let's start by assigning coefficients to each compound: 2H2O + 1SO3 -> 1H2SO4

To balance the equation, we need to ensure that the number of atoms on both sides is the same. Here, we have two hydrogen (H) atoms on the left side and two on the right side, so hydrogen is already balanced.

We have two oxygen (O) atoms on the left side and four on the right side, so we need to balance oxygen by adding a coefficient of 2 in front of the water molecule:

2H2O + 1SO3 -> 1H2SO4

Now the equation is balanced with two hydrogen, four oxygen, and one sulfur (S) atom on both sides.

The type of reaction represented by this equation is a combination or synthesis reaction. In a combination reaction, two or more substances combine to form a new compound. In this case, water (H2O) and sulfur trioxide (SO3) combine to form sulfuric acid (H2SO4).

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Answer:

A) Using the ideal gas law, we can calculate the number of moles of gas present:

```

PV = nRT

```

where:

* P = pressure (atm) = 1 atm

* V = volume (L) = 5.6 L

* n = number of moles of gas

* R = ideal gas constant = 0.08206 L atm / mol K

* T = temperature (K) = 273.15 K

Solving for n, we get:

```

n = (P * V) / RT

```

```

n = (1 atm * 5.6 L) / (0.08206 L atm / mol K * 273.15 K)

```

```

n = 0.25 mol

```

Therefore, there are 0.25 moles of gas present.

B) The molar mass of the gas can be calculated by dividing the mass of the gas (8.0 g) by the number of moles of gas (0.25 mol):

```

Molar mass = Mass / n

```

```

Molar mass = 8.0 g / 0.25 mol

```

```

Molar mass = 32 g/mol

```

The molar mass of the gas is 32 g/mol.

C) The common atmospheric gas with a molar mass of 32 g/mol is oxygen (O2). Therefore, the gas that was collected is oxygen.

Explanation:

Answer:

a) 4p ⇒ 4s  transition is Allowed

b) 3d ⇒ 4s transition not allowed

Explanation:

a) 4p ⇒ 4s  transition

This transition is allowed because for a 4p state; l = 1 and for a 4s state I = 0

hence Δl = 1 - 0 = 1

Energy of 4p ( Ei ) = 3.75eV

Energy of 4s ( E2 ) = 3.19 eV

where : λ = 1240 eV nm / ( E₂ - E₁ )

                = 2214 nm ≈ 2.214 μm

b) 3d ⇒ 4s transition

This transition is not allowed  

a 3d state , l = 2 while for 4s state l = 0

hence Δl = 2 - 0 = 2

therefore the transition is not allowed

In order to find how many milliliters of .100 M NaOH are required to neutralize the following solution 75.5mL of .215 M H2SO4, we will use the following formula :

M1*V1 = M2*V2

Where M1 =0.215

V1=75.5ml

M2 =0.100

V2 =?

∴ V2 = M1*V1/M2

= 0.215M* 75.5ml/0.100M

= 162.33 ml

• This means that ,162.33 milliliters, of 0.1M NaOH will be required,