Suppose that you hear a clap of thunder 16.2s after seeing the associated lightning stroke. The speed of sound waves in air is 343 m/s and speed of light in air is 3×10^(8) ms^(-1). How far you are from the lightning stroke?

There is no change in the velocity of the ball after 10 seconds and one hour due to no external force on it.

If a ball floating in outer space was pushed and attain a velocity of 4 m/s, then after 10 seconds as well as after an hour, it has the same velocity because in space there is no forces on the ball. This ball moves with the same velocity until external force is applied on it.

So we can conclude that there is no change in the velocity of the ball after 10 seconds and one hour due to no external force on it.

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If the oscillation amplitude is 0.22m, from a 0.29kg harmonic oscillator which has a total of mechanical energy 3.6j, the oscillation frequency is 4.141Hz.

It is a number of oscillations in the one-time unit, says per second. For example, a pendulum that takes 0.5s to make one full oscillation has a frequency of 1 oscillation per 0.5s or 2 oscillations / second.

How to calculate the oscillation frequency?

mass (m) = 0.29kg

Total energy (E) = 3.6j

amplitude (x) = 0.22m

E = 1/2 k*x^2

k = 2*E / x^2

= 2 * 3.6 / 0.22^2

= 148.76 N/m

Frequency (v) = 1/2π √k/m

= 1/2*3.14 * √148.76 / 0.22

= 4.141Hz

Therefore, the oscillation frequency is 4.141Hz.

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With respect to monopolies, deadweight loss refers to the net loss in consumer and producer surplus due to a monopolist's pricing strategy/policy.

Deadweight loss occurs when a monopoly restricts output and charges a higher price compared to a competitive market. This results in a reduction of consumer surplus (the difference between what consumers are willing to pay and what they actually pay) and producer surplus (the difference between the price received by producers and their willingness to sell). The loss represents a welfare loss to society as resources are not allocated efficiently.

In a monopolistic market, deadweight loss arises because the quantity produced is lower and the price is higher compared to a competitive market, leading to a distortion in the allocation of resources. This inefficiency results in a net loss of economic welfare, commonly referred to as deadweight loss.

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Answer:

Kinetic Energy

Explanation:

Ang prinsipyo ay nagsasaad na ang enerhiya ay hindi maaaring malikha o masira, ngunit maaari lamang ma-convert mula sa isang anyo patungo sa isa pa. Ang tubig sa tuktok ng napakataas na talon ay nagtataglay ng gravitational potential energy. Habang bumabagsak ang tubig, ang enerhiya na ito ay na-convert sa kinetic energy, na nagreresulta sa isang daloy sa isang mataas na bilis.

Answer:there is the scetch in the picture

Explanation:

Answer:

Reflected

Explanation:

During the process of reflection whatever that is sent forth e.g light comes back (reflects)

Answer:

transmitted

Explanation:

took quiz

Answer:24/225

Explanation:density =mass/volume

Answer:

290

Explanation:

To find the tangential and normal components of acceleration, we need to differentiate the given position vector twice with respect to time (t) to obtain the acceleration vector.

Then, we can decompose the acceleration vector into its tangential and normal components.

Given position vector: \(r(t) = t^2i + (t^2 - 1)j + 2t^2k\)

First, let's differentiate the position vector with respect to time to find the velocity vector:

\(v(t) = dr(t)/dt = 2ti + (2t)j + 4tk\)

Now, let's differentiate the velocity vector with respect to time to find the acceleration vector:

\(a(t) = dv(t)/dt = d^2r(t)/dt^2 = d^2r(t)/dt^2 = 2i + 2j + 4k\)

The acceleration vector is a(t) = 2i + 2j + 4k.

Now, let's decompose the acceleration vector into its tangential and normal components.

The tangential component of acceleration (a_T) is the component of acceleration parallel to the velocity vector. It can be calculated by taking the dot product of the acceleration vector (a) and the unit vector in the direction of the velocity vector (v/|v|):

\(a_T\) = (a · v/|v|) * (v/|v|)

To find the unit vector in the direction of v, we divide the velocity vector (v) by its magnitude:

v = 2ti + 2tj + 4tk

\(|v| = sqrt((2t)^2 + (2t)^2 + (4t)^2) = sqrt(4t^2 + 4t^2 + 16t^2) = sqrt(24t^2) = 2sqrt(6)t\)

v/|v| = (2ti + 2tj + 4tk) / (2sqrt(6)t) = (i + j + 2k) / sqrt(6)

Now, let's calculate the dot product of a and v/|v|:

a · v/|v| = (2i + 2j + 4k) · (i + j + 2k) / sqrt(6)

          = 2 + 2 + 8 / sqrt(6)

          = 12 / sqrt(6)

          = 2sqrt(6)

Finally, we can calculate the tangential component of acceleration (a_T):

\(a_T\)= (a · v/|v|) * (v/|v|)

   = (2sqrt(6)) * ((i + j + 2k) / sqrt(6))

   = 2(i + j + 2k)

Therefore, the tangential component of acceleration \((a_T)\) is 2(i + j + 2k).

The normal component of acceleration (a_N) is the component of acceleration perpendicular to the velocity vector. It can be calculated by subtracting the tangential component of acceleration from the total acceleration vector:

\(a_N = a - a_T\)

   = (2i + 2j + 4k) - 2(i + j + 2k)

   = 2i + 2j + 4k - 2i - 2j - 4k

   = 0i + 0j + 0k

   = 0

Therefore, the normal component of acceleration \((a_N)\) is 0.

In summary, at any time t > 0, the tangential component of acceleration \((a_T)\) is 2(i + j + 2k), and the normal component of acceleration \((a_N)\) is 0.

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The speed of sound in the materials starring with the slowest to the fastest are; outer space, air, water, cold spoon and hot spoon.

Sound is a type of energy made by vibrations. These vibrations create sound waves which move through mediums such as air, water, wood, etc. When an object vibrates, it causes movement in the particles of the medium.

So sound wave is a mechanical wave that requires material medium for its propagation.

Sound wave will travel fastest in solids, so arranging material based on how sound travel in them, starting with the slowest;

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Answer:x rays are electromagnetic waves.

x rays are transverse waves

x rays travel at the speed of light

Explanation:

First half:

50 km at 50 km/hr ... 1 hour

Second half:

50 km at 100 km/hr ... 1/2 hour

Total distance = 100 km

Total time = 1.5 hours

Average speed = (100 km) / (1.5 hrs)

Average speed = 66 and 2/3 km/hr

Average velocity = 66 and 2/3 km/hr East

The average velocity of the car would be 66.67 Kilometers / hours.

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.

As given in the problem a car travels 100 km to the east. If the first half of the distance is driven at 50 km/h and the second half at 100 km/h,

The average velocity of the car = Total displacement / total time

                                                     =100 / 1.5

                                                     =66.67 Kilometers / hours

Thus, the average velocity of the car would be 66.67 Kilometers / hours.

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A plane travels north at 300 km/h while another plane travels towards south at 300 km/h and yes they are moving with the same speed.

Speed is the ratio of distance traveled by an object in total time taken.

So, speed = distance/time

In the question given, the planes are moving at 300 km/h in different directions. One of the planes travels 300 km towards north in 1 hour, while the other plain travels towards south covering the same distance in 1 hour Using the relation between distance, time and speed, we can see that both the planes are moving with the speed of 300 km/h.

Speed is a scalar quantity, that is completely described by its magnitude and have nothing to do with the direction of a moving object.

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Answer:

The bullet was 0.52 seconds in the air.

Explanation:

Horizontal Motion

It occurs when an object is thrown horizontally with a speed v from a height h.

The object describes a curved path ruled exclusively by gravity until it hits the ground.

To calculate the time the object takes to hit the ground, we use the following equation:

\(\displaystyle t=\sqrt{\frac{2y}{g}}\)

Note it doesn't depend on the initial velocity but on the height.

The bullet is fired horizontally at h=1.3 m, thus:

\(\displaystyle t=\sqrt{\frac{2\cdot 1.3}{9.8}}\)

\(\displaystyle t=\sqrt{\frac{2.6}{9.8}}\)

t = 0.52 s

The bullet was 0.52 seconds in the air.

Any substance on this earth is directly dependent on the gravitational force. The bullet fired horizontally will also faced the gravitational pull force.

To calculate the time the object takes to hit the ground, we use the following equation:-

\(t=\sqrt\frac{2y}{g}\)

The bullet is travelling in the air hence it does not depend on the velocity bt the mass. The height taken by the bullet is h=1.3m.

After putting the value to the equation, the answer will be as follows:-

\(t=\sqrt\frac{2*1.3}{9.8}\)

After solving the equation the value of time is 0.52 seconds

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Answer:

Explanation:

actually , the acceleration due to gravity depends on the distance from it's center of the earth.

when the distance from the earth increases , the acceleration due to gravity decreases as a result . The value of gravity in space is zero.

Answer:

yes it does transfer more energy per unit

Explanation:

Dissolve 2 -naphthol in ethanol in a round bottom flask.

Add sodium hydroxide pellets and boiling chips. Attach a condenser.

Heat under reflux for 20 minutes, until all the base dissolves.

Add 1 -bromobutane and reflux for an additional hour.

Pour the contents fo the round bottom flask into a beaker of ice

Collect the precipitate by vacuum filtration on a Bachner funnel

Rinse the product with cold water and dry it on the filter.

Nuclear energy is is used practically for many energy requirements because the reactions are controlled to regulate energy output

Nuclear energy is the energy reaelesed during nuclear relations.

Nuclear energy is a clean form of energy which is available in enormous amounts.

Nuclear energy is is used practically for many energy requirements because the reactions are controlled to regulate energy output.

Therefore, the control of nuclear reactions make the use if nuclear energy possible.

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Answer: A or the reactions are controlled to regulate energy output.

Explanation: did it on edge!

After considering the given data we conclude that the nova simply represents an outburst of  exertion and a release of energy, emblematic  of bringing a white dwarf closer and closer to the critical threshold where it can no longer hold itself up against gravitational collapse.

 According to present understanding, a nova is caused by a white dwarf star in a  double system" stealing" gas from its  near companion star. When enough gas builds up on the  face of the white dwarf, it triggers a thermonuclear explosion that blasts the star's atmosphere into astral space, creating the envelope seen as visible light during the nova event.  

This explosion causes the  unforeseen appearance of a bright,  supposedly" new" star that  sluggishly fades over weeks or months. All observed novae involve white dwarfs in close  double systems. The mainsub-classes of novae are classical novae,  intermittent novae( RNe), and dwarf novae. The  unforeseen increase in energy expels the atmosphere into astral space creating the envelope seen as visible light during the nova event.  

Although the  fairly more spectacular  marvels of either a  winner or a kilonova are  frequently all the rage, the nova has one abecedarian advantage it does n’t destroy either of the ancestor objects that give rise to it. rather, a nova simply represents an outburst of  exertion and a release of energy, emblematic  of bringing a white dwarf closer and closer to the critical threshold where it can no longer hold itself up against gravitational collapse.  
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A nova is caused by a thermonuclear explosion on the surface of a white dwarf star due to the accretion of matter from a companion star.

A nova is a sudden, bright outburst of light from a star that occurs due to a thermonuclear explosion on the surface of a white dwarf star. The explosion is caused by the accretion of matter from a companion star onto the surface of the white dwarf. As the matter accumulates, it undergoes nuclear fusion, releasing a tremendous amount of energy in the form of light and heat. This sudden increase in brightness makes the star appear much brighter than usual, hence the term 'nova'.

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The electric field exerted by a point charge is given by:

where q is the charge and r is the distance to the point where we want to calculate the electric field.

In this case we have three charges with the following properties:

Now, the total electric field on a point is the addition of all the charges; in this case we want the net field to be zero. Then we have:

Now, since the last equation does not have a real solution this means that this distribution of charges will not exert a zero electric field on the origin.

Therefore, there's no possible distance for the field to be zero in this charge configuration

The method you do an exercise to target particular muscle groups is known as technique.

When workouts are performed properly, the muscles and joints that are being particularly targeted by the movement get the load. When an exercise is performed improperly, it frequently results in the loading of other joints and muscles as well as a reduction in the benefit to the target muscles.

Whatever your weightlifting objectives, using perfect form is the first and most crucial step. Technique has a greater influence than weight used, whether you're trying to bulk up or tonify. Bad form simply won't yield the same outcomes.

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Hello! :3

I'm pretty sure you should be coloring the lines. The green line should be convergent, the blue line should be transformed,  and the red line should be divergent.

Hope this helps! I'm not 100% sure! :)))))

The lift experienced by maglev trains is due to magnetic forces. Maglev trains, short for magnetic levitation trains, utilize magnetic forces to achieve lift and propulsion.

The principle behind maglev technology involves the interaction between magnetic fields and electric currents to generate repulsion or attraction forces. The lift experienced by maglev trains is primarily due to magnetic repulsion. The train's undercarriage contains magnets, typically superconducting electromagnets or permanent magnets, which create a strong magnetic field. The track, on the other hand, is equipped with a series of coils or magnets that produce a corresponding magnetic field. When the train moves along the track, the magnetic fields of the undercarriage and the track interact, resulting in a repulsive force that levitates the train above the track.

By effectively repelling the train from the track, the magnetic forces create a "floating" effect, reducing friction and allowing the train to move smoothly and efficiently. This enables maglev trains to achieve high speeds and provide a comfortable ride. In addition to lift, magnetic forces are also used for propulsion in maglev systems, where alternating magnetic fields push and pull the train forward. In summary, the lift experienced by maglev trains is indeed due to magnetic forces, specifically the repulsion generated between the magnetic fields of the train and the track.

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Incorporating physical activity into your everyday routine is one approach to care for your skeletal system.

Walking, running, and climbing stairs are all weight-bearing workouts that can help you grow strong bones and reduce bone loss. Substance misuse should be avoided.

The human skeleton is the body's internal framework. It is made up of around 270 bones at birth, which lowers to approximately 206 bones by adulthood as certain bones fuse together.

It is to be noted that the skeleton's bone mass accounts for around 14% of total body weight and achieves maximal density around the age of 21.

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The answer is C

! I took the test lol :)

The rotation is a circulatory motion of an object around the axis and maybe for infinite time and pass internally by the body's own center of mass then the body is said to be spinning.

Hence option C is correct.

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Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.

The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:

ωn = √(K / M),

where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.

Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.

ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.

Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

The correct question is given as,

M= 20kg

Fo = 90 N

ω = 6 rad/s

K = 400 N/m

C = 125 Ns/m

Determine the frequency of applied force at which resonance will occur?

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