The probability of the shuttle being left with no computer control systems on a mission is 0.000001.
The probability of failure for any one system on any one mission is known to be 0.01.
Since a failure of one system is independent of a failure of another system, the probability that the shuttle is left with no computer control system on a mission is 0.01 × 0.01 × 0.01 = 0.000001, or 1 in 1,000,000.
This is because the probability of three independent events occurring is the product of the individual probabilities.
Therefore, the probability of the shuttle being left with no computer control systems on a mission is 0.000001.
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A market buys watermelons for $1.25 they want to make a 20% profit what should they charge for the watermelons
Answer: $1.50
Step-by-step explanation:
Cost price of watermelon = $1.25
Profit percent = 20%
Profit = Profit percent × Cost price
= 20% × $1.25
= 20/100 × $1.25
= 0.2 × $1.25
= $0.25
Selling price = Cost price + Profit
Selling price = $1.25 + $0.25
Selling price = $1.50
They should charge $1.50 for the watermelons
Find the area of this semi-circle with radius, r = 6cm.
Give your answer as an expression in terms of pi
Answer:
72π (I think)
Step-by-step explanation:
Think of it in terms of the entire circle. A semi-circle is just half a circle, so the area of a semicircle will be half of the area of the entire circle. The radius of the semicircle is 6, so the radius of the whole circle is 12. Then, we can do \(\frac{pi*r^{2} }{2}\) to get the area of the semicircle is 72π. I'm pretty sure that's right. Let me know if I made a mistake somewhere.
. A study was conducted to analyze the effects on deer population in a particular area. Let f be an exponential function that gives the population of deer t years after the study began.
If f(t) = a · bt and the population is increasing, select all statements that must be true.
a. b>1
B. b < 1
C. The average rate of change from year 0 to year 5 is less than the average rate of change from year 10 to year 15.
D. The average rate of change from year 0 to year 5 is greater than the average rate of change from year 10 to year 15.
e. a > 0
The statements that are true are (a) b > 1, (c) The average rate of change from year 0 to year 5 is less than the average rate of change from year 10 to year 15. and (e) a > 0
What are Exponential Functions?Exponential functions are those functions where the independent variable, x is in the exponent.
Given exponential function is,
f(t) = \(a . b^t\)
The exponential function can be written as,
f(t) = \(a(1+r)^t\), where r is the rate of increase or decrease.
So, b = 1+ r
It is given that the population is increasing, so rate is positive.
So b = 1 + r, is greater than 1.
Average rate of change of a function is the ratio change in function values to the change in t values.
Change in t is same as we are measuring over 5 years.
Since the function is increasing at a constant rate, the function values will also be outgoing a large increase as the time increases.
So the average rate of change from year 0 to year 5 is less than the average rate of change from year 10 to year 15.
a is the initial population of the deer when t = 0. This must be greater than 0.
Hence the options a, c and e are correct statements.
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If a basketball player made 72 out of 85 free throws attempts how many could she make in 200 attempts
Answer:
169
Step-by-step explanation:
Use a proportion:
72/85=x/200
Solve for x
(72)(200)=85x
x=(72)(200)/85
x=169.41≈ 169
She can make 169 of 200 free throws.
Anyone pls help :) I'll give brainliest
Answer:
B. -5/2
Step-by-step explanation:
(0, -7) and (-4, 3)
m = 3+7/-4-0
m = 10/-4
m = -10/4
m = -5/2
Answer:
b
Step-by-step explanation:
please help! BRAINLIEST to correct answer!
Answer:
A
Step-by-step explanation:
u can just test them out
Answer:
A. y = 2\((x - 2)^{2}\) + 5
Step-by-step explanation:
positive 2 because the parabola faces upwards, and + 5 because it's vertex is places at (2,5)
Deon rented a truck for one day. There was a base fee of $20.95, and there was an additional charge of 74 cents for each mile driven. Deon had to pay $221.49 when he returned the truck. For how many miles did he drive the truck?
Answer:
Deon drove 270 miles.
Let x be the number of miles driven.
The total cost is 20.95 + 0.74x = 221.49
Subtracting 20.95 from both sides gives 0.74x = 200.54
Dividing both sides by 0.74 gives x = 270 miles
So the answer is 270
Answer:
271 miles
Step-by-step explanation:
The equation to find the total cost is
C = 20.95 + .74 m where m is the number of miles
221.49 = 20.95 +.74m
Subtract 20.95 from each side
221.49 -20.95 = 20.95-20.95 +.74m
200.54 = .74m
Divide each side by .74
200.74/.74 = m
271 = m
бу +11 = 17
бу =
y =
Answer:
y=1
Step-by-step explanation:
Original Equation:
6y+11=17(Group like terms)
6y=17-11(You will subtract 11 from 17)
6y=6(You will then Divide Both Sides by 6)
Y=1( Leaving y with 1 because 6 will cancel each other out, and 6 divided by 6 is 1)
In two or more complete sentences, describe how to determine if the function f(x)=2cos(x) is even by looking at a graph.
The given function f(x) = 2 cos (x) is an even function because the result of the cosine of negative angles are the same with those of positive angles.
How to determine an Even Function?
To check if a function is odd or even, we have to calculate f(−x).
The function is even if f(-x) = f(x)
The function is odd if f(-x) = -f(x)
We are given the function as; f(x) = 2 cos (x)
f(-x) = 2 cos (-x)
Now, we know that the cosine of a negative angle always gives the same value as the cosine of the positive angle and as such, we can say that;
2 cos (-x) = 2cos (x)
The same result as f(x) which tells us that it is an even function
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if a bloodstain has a length of 30 cm and a width of 1.5 cm what is the angle of impact?
If a bloodstain is 1.5cm wide and 30cm long, then the angle of impact is 30°.
What is the angle of impact?In forensic science, the angle of impact is the angle at which a blood droplet strikes a surface. It has a range of 0 to 90 degrees and is, by definition, an acute (or right) angle.
Police can partially reconstruct a crime scene by connecting the "strings" that lead from the spatter to an origin area and knowing the angle of contact.
If a bloodstain has a tail or pattern, the angle of impact can be used to forecast how the subsequent bloodstain would look.
So, bloodstain pattern analysis examines the patterns of bloodstains found at crime scenes in an effort to piece together the sequence of events that led to the bloodshed.
Mathematically, we will have:
The angle of impact = sin⁻¹ (wide stain/length stain)
The angle of impact = sin⁻¹ (1.5/3.0)
The angle of impact = 30°
Therefore, if a bloodstain is 1.5cm wide and 30cm long, then the angle of impact is 30°.
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Find the perimeter of the figure to the nearest hundredth. (includes picture)
Answer:
20+20+(circumference of a semi circle)
40+(1/2×2πr)
49+36
= 85mm
PLS HELP!! WILL GIVE BRAINLY!! ASAP PLS!!!!!
Answer:
The solutions are,
x=0 and x= 5
(I don't know if you have to write both of these or only one, sorry)
Step-by-step explanation:
\(x^2-3x+6=2x+6\\solving,\\x^2-3x-2x+6-6=0\\x^2-5x+0=0\\x^2-5x=0\\x(x-5)=0\\\\x=0, x-5=0\\x=0,x=5\)
So, the solutions are,
x=0 and x= 5
Poease help! Thank you
Answer:
28 and 12t
Step-by-step explanation:
4 x 7
4 x 3t
Answer:
28+12t
Step-by-step explanation:
Simplify the expression :)
btw you spelled please wrong
Two point charges (Q
1
=−27Q
0
and Q
2
=+55Q
0
) are held in place along the x-axis. Q
1
is at x
1
=−5a and Q
2
is at x
2
=9 a. You are interested in determining the electric field at point P located at (x,y)=(0,7a). Hint: start off by drawing a picture of this scenerio. 1) What is the x-component of the electric field from Q
1
at point P in un
o
/a
2
? kQ
o
/a
2
You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 2) What is the y-component of the electric field from Q
1
at point P in units of kQ
o
/a
2
? kQ
o
/a
2
You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 3) What is the x-component of the electric field from Q
2
at point P in units of kQ
o
/a
2
? kQ
o
/a
2
You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 4) What is the y-component of the electric field from Q
2
at point P in units of kQ
o
/a
2
? kQ
o
/a
2
You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 5) What is the magnitude of the net electric field at point P in units of kQ
o
/a
2
? kQ
o
/a
2
You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 6) If you now place another point charge (q
3
=+115Q
0
) at point P, what will be the x-component of the net force on it in units of kQ
o
/a
2
? kQ
o
/a
2
You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 7) Suppose the sign of q
3
is changed but its magnitude stays the same, q
3
=−115Q
0
. What is the x-component of the net force on it in units of (\kQo/a
∧
2\) now? kQ
o
/a
2
You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question.
A two point charges are held in place along with equation of the x-axis:
1.E1x = (k × (-27Q0)) / (-5a)²
2.E1y = 0
3.E2x = (k ×(55Q0)) / (9a)²
4.E2y = 0
5.E= √((E1x + E2x)²)
6.F3x = (k ×(-27Q0) × (+115Q0)) / (-5a)²
7.F3x = (k × (-27Q0) × (-115Q0)) / (-5a)²
To determine the electric field at point P, we need to consider the contributions from both point charges Q1 and Q2.
The x-component of the electric field from Q1 at point P can be calculated using Coulomb's law:
E1x = (k × Q1) / r1²
Here, k represents the electrostatic constant, Q1 is the charge of Q1, and r1 is the distance between Q1 and point P along the x-axis.
Given that Q1 = -27Q0 and the distance between Q1 and point P is x1 = -5a, we can substitute these values into the formula:
E1x = (k × (-27Q0)) / (-5a)²
The y-component of the electric field from Q1 at point P is zero since Q1 is located on the x-axis.
E1y = 0
The x-component of the electric field from Q2 at point P can also be calculated using Coulomb's law:
E2x = (k × Q2) / r2²
Here, Q2 = +55Q0 and the distance between Q2 and point P is x2 = 9a:
E2x = (k × (55Q0)) / (9a)²
The y-component of the electric field from Q2 at point P is also zero since Q2 is located on the x-axis.
E2y = 0
To calculate the magnitude of the net electric field at point P, we can use the Pythagorean theorem:
E = √((E1x + E2x)² + (E1y + E2y)²)
Since E1y and E2y are both zero, the equation simplifies to:
E = √((E1x + E2x)²)
If we place another point charge q3 = +115Q0 at point P, the x-component of the net force on it can be calculated using Coulomb's law:
F3x = (k × Q1 × q3) / r1
Here, Q1 = -27Q0 and q3 = +115Q0, and the distance between Q1 and point P is x1 = -5a:
F3x = (k × (-27Q0) × (+115Q0)) / (-5a)²
If the sign of q3 is changed to q3 = -115Q0, the x-component of the net force on it can be calculated as:
F3x = (k × Q1 ×q3) / r1²
Here, Q1 = -27Q0 and q3 = -115Q0, and the distance between Q1 and point P is x1 = -5a:
F3x = (k ×(-27Q0) ×(-115Q0)) / (-5a)²
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What is the difference between AIC and BIC penalty?
The difference between AIC and BIC penalty lies in their approach to model selection.
AIC (Akaike Information Criterion) is a measure of the goodness of fit of a statistical model. It is used to compare different models and select the one that fits the data best. AIC is based on the principle of maximum likelihood, which means it is more focused on finding the model that fits the data best.
On the other hand, BIC (Bayesian Information Criterion) is a criterion for model selection based on the Bayesian approach. It is also used to compare different models, but it takes into account the complexity of the model. BIC tends to favor simpler models, and it is more focused on finding the model that is most likely to be true given the data.
In summary, AIC is more focused on finding the model that fits the data best, while BIC is more focused on finding the model that is most likely to be true given the data.
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how do i get my w2 from walgreens if i no longer work there
Send your request via email on the company mail, include your name, employee ID number, and the W2 you are asking for the particular year.
For more than a century, Walgreens has operated on the same set of values: Honesty, Trust, and Integrity with Our Customers, Our Shareholders, Our Suppliers, The Communities We Serve, and Among Ourselves.
Quality via dependable and consistent advice, goods, and services at all points of contact and through all channels.
kind, sensitive, and motivated to provide excellent service and a positive patient and customer experience in order to achieve healthy outcomes.
via service, knowledge, and the personal engagement of each member of the Walgreen team, a strong commitment to and presence in the community.
All products under the Walgreens brand come with a 100% satisfaction guarantee! Return the unused amount if you're not entirely happy, and we'll refund the entire purchase price.
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Convert the fraction
103
7497
to an equivalent percentage.
Report your answer accurate to one decimal place.
Answer:
1.4
Step-by-step explanation:
We need to convert 103/7497 into a percentage.
All we have to do is multiply the fraction by 100:
103/7497 * 100 = 1.37
To one decimal place, the equivalent fraction is 1.4
A New York City hotel surveyed its visitors to determine which type of transportation they used to get around the city. The hotel created a table of the data it gathered.
Type of Transportation Number of Visitors
Subway 80
Bicycle 20
Car Service 30
Bus 16
Walk 54
Which of the following circle graphs correctly represents the data in the table?
circle graph titled New York City visitor's transportation, with five sections labeled walk 80 percent, bus 16 percent, car service 30 percent, bicycle 20 percent, and subway 54 percent
circle graph titled New York City visitor's transportation, with five sections labeled walk 40 percent, bicycle 8 percent, car service 15 percent, bus 10 percent, and subway 27 percent
circle graph titled New York City visitor's transportation, with five sections labeled subway 40 percent, bus 8 percent, car service 15 percent, bicycle 10 percent, and walk 27 percent
circle graph titled New York City visitor's transportation, with five sections labeled subway 80 percent, bicycle 16 percent, car service 30 percent, bus 20 percent, and walk 54 percent
Find an equation for the line tangent to the graph of the given function at the indicated point. 8 3) f(x): () = at at (4,2) X 1 4) f(x)=x2-x at (4, 12)
(a) tangent line to the graph of f(x) = x^3 at the point (4,2).
(b) equation of the tangent line to the graph of f(x) = x^2 - x at the point (4,12).
(a) To find the equation of the tangent line to the graph of f(x) = x^3 at the point (4,2), we need to find the slope of the tangent line at that point. We can do this by taking the derivative of f(x) with respect to x and evaluating it at x = 4. The derivative of f(x) = x^3 is f'(x) = 3x^2. Evaluating f'(x) at x = 4 gives us the slope of the tangent line. Once we have the slope, we can use the point-slope form of a linear equation to write the equation of the tangent line.
(b) Similarly, to find the equation of the tangent line to the graph of f(x) = x^2 - x at the point (4,12), we differentiate f(x) to find the derivative f'(x). The derivative of f(x) = x^2 - x is f'(x) = 2x - 1. Evaluating f'(x) at x = 4 gives us the slope of the tangent line. Using the point-slope form, we can write the equation of the tangent line.
In both cases, the equations of the tangent lines will be in the form y = mx + b, where m is the slope and b is the y-intercept.
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I have a question
K^2-12k+23=0
What would the answer to this be
Answer:
the answer might be -23 I think but I would I advise to wait until another person answer this question
Which expression represents the product of x³ + 2x - 1 and 24x³+3?
Answer:
The first expression is a Trinomial and the second expression is a Binomial
consider the function defined on the interval [−2,2] as follows, ()=⎧⎩⎨⎪⎪−52,52,∈[−2,0),∈[0,2].
The area between the graph of the function and the x-axis on the interval [-2,2] is -1.
The function is defined as follows:
f(x) = -5/2, x ∈ [-2,0)
f(x) = 2, x ∈ [0,2]
The graph of the function is a horizontal line at y = -5/2 on the interval [-2,0) and a horizontal line at y = 2 on the interval (0,2].
To find the area between the graph of the function and the x-axis, we need to split the interval into two parts: [-2,0) and (0,2].
On the interval [-2,0), the area is a rectangle with base length 2 and height -5/2. Therefore, the area is:
\(A1 = base * height\)= 2 * (-5/2) = -5
On the interval (0,2], the area is a rectangle with base length 2 and height 2. Therefore, the area is:
A2 = base * height = 2 * 2 = 4
The total area between the graph of the function and the x-axis is the sum of A1 and A2:
A = A1 + A2 = -5 + 4 = -1
Therefore, the area between the graph of the function and the x-axis on the interval [-2,2] is -1.
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What is 60% of $55?
$____
Answer:
33
Step-by-step explanation:
.6 * 55 = 33
Answer:
$33
Step-by-step explanation:
Cross multiply 60/100=x/55
=>60(55)=100x
=>3300=100x
divide both sides by 100 to get x by itself=> 33=x
find an equation of the tangent plane to the given parametric surface at the specified point. r(u, v) = u^2 i + 6u sin(v) j u cos(v) k; u = 2, v = 0
Answer: the equation of the tangent plane to the parametric surface at the point (2, 0) is:
4x - 48z = 8
Explanation:
To find the equation of the tangent plane to the parametric surface at the specified point, we need to determine the normal vector to the surface at that point.
Given the parametric surface:
r(u, v) = u^2 i + 6u sin(v) j + u cos(v) k
We can compute the partial derivatives with respect to u and v:
r_u = 2u i + 6 sin(v) j + cos(v) k
r_v = 6u cos(v) j - 6u sin(v) k
Now, substitute the values u = 2 and v = 0 into these partial derivatives:
r_u(2, 0) = 4i + 0j + 1k = 4i + k
r_v(2, 0) = 12j - 0k = 12j
The cross product of these two vectors will give us the normal vector to the tangent plane:
n = r_u × r_v = (4i + k) × 12j = -48k
Now we have the normal vector to the tangent plane, and we can use it to find the equation of the plane. The equation of a plane can be written as:
Ax + By + Cz = D
Substituting the values of the point (2, 0) into the equation, we have:
4x + 0y - 48z = D
To find the value of D, we substitute the coordinates of the point (2, 0) into the equation:
4(2) + 0(0) - 48(0) = D
8 = D
Therefore, the equation of the tangent plane to the parametric surface at the point (2, 0) is:
4x - 48z = 8
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Drag the factors to the correct locations on the image.
Each factor can be used more than once, but not all factors will be used. What is the factored form of this expression? x3 - 6x2 - 9x + 54
Tiles go here
( )( )( )
Tile options:
x - 6
x - 9
x + 9
x - 3
x + 3
x + 6
Answer: x-6, x+3, x-3
Step-by-step explanation;
Split the equation into two.
x2(x-6)-9(x-6)
(x-6) is seen as one of the tiles. Now work on x2-9
x2-9 is a difference of squares meaning the last two are (x+3) and (x-3).
The piecewise function h(x) is shown on the graph.
What is the value of h(3)? Pls help!!
Given:
The graph of a piecewise function.
To find:
The value of h(3).
Solution:
We have, the graph of a piecewise function h(x).
The function is divided into two pieces. One is over the interval \(-4\leq x<1\) and another one is over the interval \(-1\leq x\leq 4\).
From the given graph it is clear that the function passes through the point (3,1). It means the values of the function is 1 at x=3.
\(h(x)=1\) at x=3.
\(h(3)=1\)
The value of h(3) is 1.
Therefore, the correct option is C.
Answer:
tis c
Step-by-step explanation:
Someone please help…………………
Answer:
с)y^2=32x
Step-by-step explanation:
A data set with whole numbers has a low value of 20 and a high value of 96.
Find the class width for a frequency table with seven classes.
Find the class limits for a frequency table with seven classes.
Answer and Step-by-step explanation:
The computation of the class width for a frequency is shown below:
Class width is
\(= \frac{Range}{Number\ of\ class} \\\\ = \frac{96 - 20}{7}\)
= 10.86
= 11
Now the class limits for a frequency table
Particulars Lower class limit to upper class limit
First class 20 - 30
Second class 31 - 41
Third class 42 - 52
Fourth class 53 - 63
Fifth class 64 74
Six class 75 - 85
Seventh class 86 - 96
The class width for a frequency table with seven classes is 10.86.
The class limits for a frequency table with seven classes are;
Particulars Lower class limit to upper class limit
First-class 20 - 30
Second class 31 - 41
Third class 42 - 52
Fourth class 53 - 63
Fifth class 64 74
Six class 75 - 85
Seventh class 86 - 96
GivenA data set with whole numbers has a low value of 20 and a high value of 96.
1. The class width for a frequency table with seven classes is;
\(\rm Frequency = \dfrac{Highest \ term - lowest\ term }{Class}\\\\ Frequency = \dfrac{96-20}{7}\\\\ Frequency = \dfrac{76}{7}\\\\ Frequency =10.86\)
The class width for a frequency table with seven classes is 10.86.
2. The class limits for a frequency table with seven classes are;
Particulars Lower class limit to upper class limit
First-class 20 - 30
Second class 31 - 41
Third class 42 - 52
Fourth class 53 - 63
Fifth class 64 74
Six class 75 - 85
Seventh class 86 - 96
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PLEASE HELP :( !! See photooo
Answer:
Step-by-step explanation:
I have no idea
Help me please , I’ll mark brainliest
Answer:
44
Step-by-step explanation:
2 x 2 = 4 which is the inner area without carpet.
12 x 4= 48 is the total area including the inner area
48-4=44 which is the area with carpet