Suppose that the Earth's mass is doubled, but its radius remains unchanged. How will this change the escape velocity

The velocity after two minutes is v = 616.67 m/s

Using the equation final velocity = beginning velocity + acceleration * time, the final velocity of this bus after two minutes is determined. Symbolically, v is represented as follows: vi = 60 km/h, a = 5 m/s2, and t = 2 minutes. First, we must translate 60 km/h into m/s. 50/3 m/s is equal to 60 km/h or 60,000 m/36 seconds.

When determining the final velocity, v

v = vi + a * t

120 seconds at v = 50/3 m/s + 5 m/s2

v = 50/3 m/s + 600 m/s

v = 16.67 m/s + 600 m/s

v = 616.67 m/s

After two minutes, the bus's speed is 616.67 m/s. For a bus, it is a pretty implausible velocity. The speed of this object is 2,220 km/h, exceeding the speeds of both air and jet aircraft. Your acceleration time should have been capped at 20 seconds or less.

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Answer:

The car is speeding up in a negative direction.

Explanation:

Answer:

kinetic energy

Explanation:

Potential energy is stored energy.Kinetic energy is energy that a body possess as a result of its motion.

Gravitational potential energy is the energy stored in an object as the result of its height. The energy is stored as the result of the gravitational attraction of the Earth for the object

The total mechanical energy of the bicyclist is 1400 J, obtained by adding her potential energy of 720 J and kinetic energy of 680 J. The correct answer is option B.

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The number of turns turned by winding around a peg are calculated to be 0.003.

Extension δ is given by the formula,

δ = εL = σL/E = FL/AE

where, F is force

L is length

A is area

E is modulus of elasticity

⇒ (84 × 0.68)/[π(1.36 × 10⁻³)²/4](210 × 10⁹) = 0.00019 m

And this is wrapped around the peg's circumference,

Number of turns n = 0.00019/π d = 0.00019/π(15 × 10⁻³) = 0.003 times or about 1.4 degrees.

The peg needs to be turned 1.4 degrees.

Thus, the number of turns turned by winding around a peg are calculated to be 0.003.

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If the rods P and Q repel each other, that means they have the same charge signs (both are positive or both are negative)

Since the rods P and R attract each other, that means they have opposite charge signs (one is positive and the other is negative).

Looking at the options, the only one that can represent the signs of the charges on the rods is the third option. (P and Q have the same charge sign, P and R have different charge signs)

Abnormal forced extension beyond normal range of motion is called hyperextension.

To elaborate more, hyperextension is the forced extension of a joint beyond its normal range of motion.

The joint is forced into a position that is not its usual range of motion due to an external force or muscular activity.

Hyperextension often causes pain and discomfort in the affected joint and surrounding muscles.

Common sites of hyperextension include the neck, fingers, and knees.

In conclusion, hyperextension refers to an abnormal forced extension of a joint beyond its normal range of motion. Hyperextension may occur due to an external force or muscle activity, and it often causes pain and discomfort.

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a) The partial pressure of methane is 2.49 atm, ethane is 1.33 atm, and butane is 0.68 atm.

b) The total pressure of the mixture is 4.50 atm.

To calculate the partial pressure of each gas, we can use the ideal gas law equation:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to find the number of moles of each gas. We can use the formula:

moles = mass / molar mass

For methane (CH4):

moles(CH4) = 3.15 g / 16.04 g/mol = 0.196 mol

For ethane (C2H6):

moles(C2H6) = 3.15 g / 30.07 g/mol = 0.105 mol

For butane (C4H10):

moles(C4H10) = 3.15 g / 58.12 g/mol = 0.054 mol

Next, we can calculate the partial pressure of each gas using the ideal gas law:

P(CH4) = (moles(CH4) * R * T) / V

P(C2H6) = (moles(C2H6) * R * T) / V

P(C4H10) = (moles(C4H10) * R * T) / V

Assuming R = 0.0821 L*atm/mol*K and converting the temperature to Kelvin (64 °C = 337 K), and the volume is given as 2.00 L, we can substitute the values to calculate the partial pressures.

For methane (CH4):

P(CH4) = (0.196 mol * 0.0821 L*atm/mol*K * 337 K) / 2.00 L = 2.49 atm

For ethane (C2H6):

P(C2H6) = (0.105 mol * 0.0821 L*atm/mol*K * 337 K) / 2.00 L = 1.33 atm

For butane (C4H10):

P(C4H10) = (0.054 mol * 0.0821 L*atm/mol*K * 337 K) / 2.00 L = 0.68 atm

To calculate the total pressure of the mixture, we sum up the partial pressures of each gas:

Total pressure = P(CH4) + P(C2H6) + P(C4H10)

Total pressure = 2.49 atm + 1.33 atm + 0.68 atm = 4.50 atm

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Answer: Because your mass is so much less than the mass of the Earth,

Explanation:

You can't feel your gravitational force. Because the Earth's gravity has the same pull on every object, all objects fall at the same speed (in a vacuum). On Earth, we have air. Air resistance will cause some objects to fall more slowly than others will.

Hope it helps I had this question too!

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Using the left hand rule, if current points up and the field is toward you,  the  motion points up.

The left hand rule states that if the thumb, the fore finger and the middle finger are held mutually perpendicular to each other, the thumb points in the direction motion, the middle finger points in the direction of current while the fore finger points in the direction of the magnetic field.

Thus using the left hand rule, if current points up and the field is toward you,  the  motion points up.

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Answer:

The volume of the cylinder is \(653.71\ \text{cm}^3\)

Explanation:

Given that,

The height of the cylinder is 13 cm

Radius of the cylinder is 4 cm

We need to find the volume of the cylinder. The formula that is used to find the volume of a cylinder is given by :

\(V=\pi r^2 h\\\\V=\dfrac{22}{7} \times (4)^2 \times 13\\\\V=653.71\ \text{cm}^3\)

So, the volume of the cylinder is \(653.71\ \text{cm}^3\)

Answer:

653.45 is the answer

Explanation:

Answer:

Tt can be calculated by copy

The focal length of the lens is 15 cm. The correct option is C).

Using the thin lens equation

1/f = 1/d_o + 1/d_i

where f is the focal length of the lens, d_o is the object distance, and d_i is the image distance.

We are given that the object height, h_o, is 1.15 cm, the image height, h_i, is 5.75 cm, and the object distance, d_o, is 12 cm. Since the image is upright, the magnification, M, is positive:

M = h_i / h_o = 5.75 / 1.15 = 5

We can use the magnification equation to find the image distance

M = - d_i / d_o

d_i = - M * d_o = -5 * 12 cm = -60 cm

The negative sign indicates that the image is virtual, which means it is on the same side of the lens as the object.

Now we can use the thin lens equation to solve for the focal length:

1/f = 1/d_o + 1/d_i = 1/12 cm - 1/60 cm = 1/15 cm

f = 15 cm

Therefore, the focal length is 15 cm. The correct Answer is option C).

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Answer:

441J

Explanation:

Given parameters:

Mass of book  = 5kg

Height  = 9m

Unknown:

Gravitational potential energy  = ?

Solution:

The gravitational potential energy of a body is the energy due to the position of the body.

 It is given as:

   Gravitational potential energy = mass x acceleration due to gravity x height

Gravitational potential energy  = 5 x 9.8 x 9  = 441J

Answer:

Icy roads

Explanation:

There is so little friction you slide on it way more than other roads. :)

Answer: It leads to a front. A front is.., I don't know how to explain it, so I'll add a picture. Fronts are made out of clouds and usually bring rain. So the answer is C: The formation of clouds and rain.

Explanation:

It is more likely that the storm you observed, which passed over you after an hour, was a mesoscale convective system (MCS) rather than an air mass thunderstorm.

Air mass thunderstorms typically form and dissipate within the boundaries of a single air mass. They are generally short-lived and do not typically travel large distances. Therefore, it is less likely for an air mass thunderstorm to travel from a location far to the west to your current location within just an hour.

On the other hand, mesoscale convective systems are larger-scale weather systems that can cover hundreds of miles and persist for several hours or even longer. They often have organized structures, such as squall lines or clusters of thunderstorms, and can move over significant distances. It is more plausible for a mesoscale convective system to travel from a distant location to your area within the span of an hour.

Considering the time and distance covered, the fact that the storm passed over you after an hour suggests that it was likely a mesoscale convective system.

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Answer:

i. Cyclist A travelled 15 km 1 h cyclist A had started his journey from point X

  Cyclist B travelled 18 km 1 h cyclist A had started his journey from point X

ii. cyclist B overtake cyclist A 6 km from the same starting point X.

Explanation:

From the question,

- Cyclist A and B cycled at an average speed of 15 km/h and 20 km/h respectively.

- Cyclist B started his journey 6 mins after cyclist A had started.

Let the cyclist A time be t.

Then, we can write that

For Cyclist A

Speed = 15 km/h

Time = t mins

For Cyclist B

Speed = 20 km/h

Time = (t - 6) mins

i) To determine the distances travelled by cyclist A and B 1h cyclist A had started his journey,

For Cyclist A

Speed = 15km/h

Time = 1h = 60 mins

From the formula

Speed = Distance / Time

Then,

Distance = Speed × Time

Putting the values into the equation,

Distance = 15km/h × 1h

Distance = 15 km

∴ Cyclist A travelled 15 km 1 h cyclist A had started his journey from point X

For cyclist B

Speed = 20km/h

Time = 1h - 6mins = 60mins - 6mins = 54mins = 54/60 hour = 0.9 h

Also, from

Distance = Speed × Time

Putting the values into the equation

Distance = 20km/h × 0.9h

Distance = 18 km

∴ Cyclist B travelled 18 km 1 h cyclist A had started his journey from point X

ii) To determine the distance cyclist B overtake cyclist A, that is, when the distance covered by cyclist A equals that covered by cyclist B.

First, we will determine the time at which the distances covered by both cyclists were equal.

From

For Cyclist A

Speed = 15 km/h

Time = t hour  

Distance = Speed × Time

Distance = 15t km

For Cyclist B

Speed = 20 km/h

Time = (60t - 6) mins = (t - 0.1) hour

Distance = 20 × (t - 0.1) = (20t - 2) km

Equate the distances

15t = 20t - 2

15t - 20t = -2

-5t = -2

5t = 2

t = 2/5

t = 0.4 hour

Hence, cyclist B overtake cyclist A 0.4 hour after cyclist A had started.

For the distance cyclist B overtake cyclist A,

From

Distance = (20t - 2) km

Distance = (20×0.4 - 2) km

Distance = (8 - 2) km

Distance = 6 km

Hence, cyclist B overtake cyclist A 6km from the same starting point X.

The point that supports both the load and the effort is the fulcrum.

A lever is a simple machine that is composed of three parts, the parts of the lever are as follows;

The point that supports both the load and the effort is the fulcrum and it is the point around which a lever rotates and that supports the lever and the load.

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Answer: C. They are regions in which strong magnetic fields make it difficult for fresh supplies of hot, ionized gas to reach the photosphere

Explanation:

Sunspots appear dark because they are regions in which strong magnetic fields make it difficult for fresh supplies of hot, ionized gas to reach the photosphere.

Sunspots are typically cooler than their surroundings. For example, the temperature of a large sunspot can be about 4,000 Kelvin which is lower than the temperature of the photosphere around it which is about 5,800 Kelvin.

Many reasons. Here are a couple:

1.) Water depth for the draft of incoming ships/vessels so they do not run aground.

2.) Distance between sea level and bottom of structures such as bridges for vessels passing underneath.

Answer:

Explanation:

The density of gold is 19.3 g/cm³. Thus, you can determine the density of the unknown cube by doing the following. Get a measuring cylinder (marked in cm³) that contains a certain volume of water (preferably above average but not close to been filled up). Get a weighing balance (that can read in grams) also.

Measure the mass of the unknown stone (using the weighing balance) and record. Take the initial volume of the water in the measuring cylinder and record (in cm³) and then drop the unknown stone inside the measuring cylinder gently (avoid splashes). Record the final volume of the cylinder after the unknown stone was dropped.

Then calculate the density of the stone by using the formula; mass ÷ change in volume

The change in volume can be determined by; Final volume - initial volume

If the answer obtained from the calculation (of the density of the stone) is not around 19.3 g/cm³ (say 19.3 ± 0.2), then the stone is not gold but if it is around 19.3 g/cm³, then the stone is gold.

The rate of change of current at the specific time is -43.86 A/s.

What is the rate of change of the current?

The emf induced in a solenoid is given by the equation emf = -L(dI/dt), where L is the inductance of the solenoid, I is the current flowing through it, and t is time. Rearranging the equation to solve for the rate of change of current, we have \(dI/dt = -emf/L.\)

Substituting the given values, we have \(emf = -12.5 mV = -0.0125 V\) and\(L = 0.285 mH = 0.000285 H\). Thus, the rate of change of current is:

\(dI/dt = -emf/L = -(0.0125 V) / (0.000285 H) = -43.86 A/s\)

Therefore, the rate of change of current at the specific time is -43.86 A/s.

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Answer:

1). average velocity= displacement/time

= here displacement is zero

= 0/1

= 0 m/s

2). average speed= total distance/time

=2πr/1

=(2×22/7×5/10)/1

22/7

3.14 km/h

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Explanation:

Answer:

\(\sf \fbox{speed = 3.14 kmph}\)

Explanation:

Given:

Radius of circular field (r) = 0.5 Km

Time taken to complete one round of field (t)= 1 hour

To find:

Average speed for the whole journey=?

Solution:

To find the average speed we will have to find the actual distance covered in given time, & the actual distance covered would be equal to the

\( \sf \: perimeter \: of \: circular \: field = 2 \pi r \\ \sf 2 \pi r = 2 \times 3.14 \times 0.5 = 3.14 \: km\)

Distance covered in 1 hour is 3.14 km,

\(\small \sf Average \: speed = \frac{Distance}{Time} = \frac{3.14}{1} \\ \small \sf \fbox{speed = 3.14 kmph}\)

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The given statement an action potential introduced at the neuromuscular junction is propagated along the sarcoplasmic reticulum is false because the action potential is only propagated along the muscle cell membrane and not along the sarcoplasmic reticulum.

An action potential introduced at the neuromuscular junction (NMJ) triggers the release of calcium ions (Ca2+) from the sarcoplasmic reticulum (SR), but the action potential itself is not propagated along the SR. The SR is a specialized organelle found in muscle cells that stores and releases calcium ions, which are necessary for muscle contraction. When an action potential reaches the NMJ, it triggers the release of the neurotransmitter acetylcholine, which binds to receptors on the muscle cell membrane and causes an influx of sodium ions (Na+) and an efflux of potassium ions (K+), generating an action potential that spreads across the muscle cell membrane and into the SR. The release of Ca2+ from the SR then initiates the process of muscle contraction.

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