Suppose Mitch Marner (mass=80kg) and Zdano Chara (mass=116kg) collide head-on at the blue line when Marner is skating 10m/s and Chara is standing still. Whose velocity would change more and Why?
Answers
Answer:
1) The person whose velocity changes more is Marner
2) The change in velocity of Marner is more than the change in velocity of Chara because Chara has more mass than Marner
Explanation:
The given information are
The mass of Mitch Marner = 80 kg
The mass of Zdano Chara = 116 kg
Marner's skating speed before the collision = 10 m/s
From the principle of conservation of linear momentum, we have;
Total initial momentum before the collision = Total final momentum after the collision
m₁×u₁ + m₂×u₂ = m₁×v₁ + m₂×v₂
Where;
m₁ = The mass of Mitch Marner = 80 kg
m₂ = The mass of Zdano Chara = 116 kg
u₁ = The initial velocity of Mitch Marner = 10 m/s
u₂ = The initial velocity of Zdano Chara = 0 m/s
v₁ = The final velocity of Mitch Marner
v₂ = The final velocity of Zdano Chara
Given that the collision is head on, they can be assumed to have an equal instantaneous velocity immediately after collision, therefore;
v₁ = v₂ = v
We have;
m₁×u₁ + m₂×u₂ = (m₁ + m₂) × v₂
By substituting the values, we have;
80 × 10 + 110 × 0 = (80 + 110) × v = 190 × v
Which gives;
80 × 10 + 110 × 0 = 190 × v
800 = 190 × v
v = 800/190 = 80/19 = \(4\frac{4}{19} \ m/s\)
Therefore the instantaneous final velocity of both Marner and Chara is \(4\frac{4}{19} \ m/s\)
The change in velocity of Marner = \(10 - 4\frac{4}{19} = 5\frac{15}{19} \ m/s\)
The change in velocity of Chara = \(4\frac{4}{19} - 0 = 4\frac{4}{19} \ m/s\)
Therefore;
1) The person whose velocity changes more is Marner
2) The reason is because the ratio of her mass to the combined mass of both of them is less than the ratio of the Chara;s mass to the combined mass of them both
Which means that the change in velocity of Marner is more than the change in velocity of Chara because Chara has more mass than Marner.
Related Questions
which process receives geo thermal energy naturally
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which one word defines newton’s first law of motion?
Answers
Answer: Inertia
Explanation: It's known as the law of inertia, and the entire law has to do with inertia.
Answer: inertia.
Explanation: sometimes referred to as the law of inertia.
.
O
Allison drove 150 miles for 2.5 hours.
Benjamin drove for 2.73 hours and traveled 175 miles.
• Lily drove 160 miles for 2.58 hours.
• George drove for 2.46 hours and traveled 155 miles.
Which person drove at the fastest constant speed?
The formula for calculating speed: Speed = Distance/Time
Answers
Answer:
Benjamin was fastest
Explanation:
Allison- 150/2.5= 60mph
Benjamin- 175/2.73= 64.1
Lily- 160/2.58= 62.01
George- 155/2.46= 63.008
10.a wheel with radius 0.33 m and rotational
inertia 2.0 kg.m2 spins on an axle with an
initial angular speed of 3.0 rad/s. friction in
the axle exerts a torque on the wheel,
causing the wheel to stop after 6.0 s. the
average torque exerted on the wheel as it
slows down has magnitude
Answers
The average torque exerted on the wheel as it slows down has magnitude of 1.0 Nm
The rotational kinetic energy equation relates the rotational kinetic energy of an object to its moment of inertia and angular velocity. The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy. We are given the radius of the wheel, its moment of inertia, and its initial angular speed.
We are also told that the wheel stops rotating after 6 seconds due to friction in the axle, which exerts a torque on the wheel. Using the rotational kinetic energy equation, we can calculate the initial rotational kinetic energy of the wheel. We can then use the work-energy theorem to find the work done by the frictional torque, which is equal to the change in the wheel's rotational kinetic energy.
Rotational inertia(I) = 2 kg m²
Radius (r) = 0.33 m
Initial angular speed W0 = 3 rad/s
time to stop (t) = 6 s
Angular acc. (α) = ?
We know that,
W = W₀ + at
0 = 3 - a × 6
a = 3/6
a = 1/2 rad/s²
Average Torque = I*α
Torque = 2 * 1/2 Nm
Torque = 1 Nm
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by what distance must two charges of 2 c and 12 c be separated so that the repulsive force between them is 3.60 1010 n?
Answers
The distance between the charges 1.26 m. distance must two charges of 2 c and 12 c be separated so that the repulsive force between them is 3.60 1010 n
The electric force is either an attractive or repulsive force due to the charges of two particles. The force decreases with an increase in distance between the particles.
We know that the expression for the electric force is
F =kq_1q_2 / r^2
where k= 9×10^9 Nm^2/C^2→ Proportionality constant
q1=2C→ Charge
q2=3C→ Charge
r→ Distance between the charges
Hence,
F =kq_1q_2 / r^2
r=√kq_1 q2/F
r=√(9×10^9)⋅2⋅3 / 3.60×10^10
r=1.26m
The distance between the charges must be 1.26 m.
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What is the acceleration of the object in the graph?
Answers
Answer:
jus did this, the answer is A, -0.8 m/s^2 :)
Explanation:
Unless otherwise stated, all objects are located near the Earth's surface, where g = 9.80 m/s2 .A girl pushes a 20 kg lawn mower as shown in the figurea) If F = 27 N and θ = 36 ∘ what is the acceleration of the mower? Ignore friction. b) What is the normal force exerted on the mower by the lawn?
Answers
Before we begin we need to make the free body diagram of the situation, it is shown below:
Now, from Newton's second law we have that:
\(\begin{gathered} F\cos \theta=ma \\ N-W+F\sin \theta=0 \end{gathered}\)a)
From the first equation we have that:
\(\begin{gathered} a=\frac{F\cos \theta}{m} \\ a=\frac{27\cos 324}{20} \\ a=1.09 \end{gathered}\)Therefore the acceleration of the mower is 1.09 meters per second per second.
b)
From the second equation we have:
\(\begin{gathered} N=W-F\sin \theta \\ N=(20)(9.8)-27\sin 324 \\ N=211.87 \end{gathered}\)Therefore the normal force is 211.87 N
Which processes occur during the second stage of technological design? Check all that apply.
designing a solution
studying relevant information
rebuilding and retesting
reporting a solution
defining criteria of success
identifying a problem
building a prototype
Answers
Answer:
designing a solution
Explanation:
after knowing & identifying a problem we start putting a solution
the reading of a mercury barometer is 75.58cm at the base of a mountain and 66.37cm at the summit. calculate the height of the mountain (density of mercury =13.6g/m^3 and density of air =1.25kg/m^
Answers
The height of the mountain would be 1002.048 m
What is pressure?
The total applied force per unit of area is known as the pressure.
The pressure depends both on externally applied force as well the area on which it is applied.
The mathematical expression for the pressure
Pressure = Force /Area
As given in the problem the reading of a mercury barometer is 75.58cm at the base of a mountain and 66.37cm at the summit.
density of mercury =13.6g/m³
=13600 kg/m³
density of air =1.25kg/m³
the gauge pressure of the mercury = the gauge pressure of the air
ρgH for the mercury = ρgH for the air
13600×9.81×(75.58-66.37) = 1.25 ×9.81 ×(height of the mountain )
(height of the mountain) = 100204.8 cm
= 1002.048 m
Thus, the height of the mountain would be 1002.048 m
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In applying the right-hand rule as discussed in this section, which is true?.
Answers
The right-hand rule is used in the field of electromagnetism. It is a method for determining the direction of a magnetic field related to the direction of the electric current that is creating it.
The right-hand rule is also used to determine the direction of the force on a charged particle moving in a magnetic field. There are two types of right-hand rules in electromagnetism: the right-hand rule for magnetic field direction and the right-hand rule for force direction. The correct statement regarding applying the right-hand rule is that if we hold a current-carrying conductor in the right hand, then the direction of the thumb points towards the direction of the current, then the curling of the fingers represents the direction of the magnetic field around the conductor. This means that if the current flow is in the upward direction in the conductor, then the magnetic field is in the counterclockwise direction around the conductor, and if the current is flowing in the downward direction, then the magnetic field is in the clockwise direction around the conductor. In the case of a loop conductor, we can determine the direction of the magnetic field inside the loop by using the right-hand rule. In this case, if we wrap the fingers of the right hand around the loop in the direction of the current flow, then the direction in which the thumb points gives us the direction of the magnetic field inside the loop. The right-hand rule is a very useful tool in understanding and visualizing the interactions between electric currents and magnetic fields. It is also an essential tool for designing and building electrical devices such as motors and generators. The right-hand rule is a fundamental concept in electromagnetism and is used extensively in many areas of science and engineering.
The right-hand rule is used to determine the direction of a magnetic field related to the direction of the electric current that is creating it. The correct statement regarding applying the right-hand rule is that if we hold a current-carrying conductor in the right hand, then the direction of the thumb points towards the direction of the current, then the curling of the fingers represents the direction of the magnetic field around the conductor. It is a fundamental concept in electromagnetism and is used extensively in many areas of science and engineering.
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It’s a sunny Saturday afternoon and you are walking around the lake by your house, enjoying the last few days of summer. The sidewalk surrounding the perimeter of the circular lake is crowded with walkers and runners. You then notice a runner approaching you wearing a T-shirt with writing on it. You read the first two lines, but are unable to read the third line before he passes. You wonder, ”Hmmm, if he continues around the lake, I bet I’ll see him again but I should anticipate the time when we’ll pass again.”
You look at your watch and it is 5:07pm. You estimate your walking speed at 3 m/s and the runner’s speed to be about 14 m/s. You also estimate that the diameter of the lake is about 2
miles. At what time should you expect to read the last line of the t-shirt?
Answers
The anticipated time when he will appear again is 5:17 pm
The given parameters;
your speed, \(V_a\) = 3 m/s
the runner's speed, \(V_b\) = 14 m/s
the diameter of the lake, d = 2 miles = 3218.69 meters
Let the anticipated time when he will appear again = tThe circumference of the lake is calculated as;
\(C = \pi d\\\\C = 3.142 \times 3218.69 = 10,113.12 \ m\)
Apply concept of relative velocity to determine the time, in which he will appear again.
By the time he appears again;
the distance you moved + distance he moved = circumference of the circle
\(V_at + V_bt = 10, 113.12\\\\(V_a + V_b)t = 10,113.12\\\\(3 + 14) t = 10,113.12\\\\17t = 10,113.12\\\\t = \frac{10,113.12}{17} \\\\t = 594.89 \ s = 9.92 \ \min \ \approx 10 \ \min\)
\(t\ \approx \ \ 5:17 \ pm\)
Thus, the anticipated time when he will appear again is 5:17 pm
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a rectangular block weighs 240N. The area of the block in contact with the floor is 20cm2 calculate the pressure on the floor
Answers
Answer:
The pressure on the floor is 12 Pascal(Pa).
Explanation:
Given,
Force (F) = 240N
Area (A) = 20 cm^2
Pressure (P) = ?
we know that,
P = F/A
= 240/ 20
= 12 Pa
A jet play sits on the runway and then rapidly accelerates does it go to potential to kinetic energy?
Answers
लाइ फ्युजका
4
Why MCB is called the developed form of fuse? Give the reason
Answers
Miniature circuit breakers is called the developed form of fuse because MCBs are more sensitive to current than fuses. They immediately detect any abnormality and switch off the electrical circuit automatically. This prevents any permanent damage to electrical appliances and human beings
assuming the atmospheric pressure to be constant at 101,325 pa, by what amount does the volume of the balloon change?
Answers
The volume of the balloon is increased to 2.9 L.
Initial volume of the balloon, V₁ = 0.5 L
Initial temperature of the balloon, T₁ = 20°C = 293 K
Final temperature, T₂ = 150°C = 423 K
According to Charle's law,
V₁/T₁ = V₂/T₂
The final volume,
V₂ = (V₁/T₁)T₂
V₂ = 0.5 x 423/293
V₂ = 2.9 L
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Your question was incomplete, but most probably your question will be:
A balloon has a volume of 0.5 L at 20°C. If the balloon is heated to 150°C, assuming the atmospheric pressure to be constant at 101,325 pa, by what amount does the volume of the balloon change?
1. Plot the equation y = x + 1. Use the values shown for x to determine y.
Answers
how do I answer this question for you?
where is the button
I'LL MARK YOU BRAINLIST !!!!!!!!!!!!
Answers
Answer:
d. collection of photo.....
Identify the smallest measurement.
a) attometer
b) nanometer
c) centimeter
d) megameter
e) petameter
Answers
Answer:
Attometer
Explanation:
an attometer is the smallest unit of measurement.
Hope it helped!
given two identical iron bars, one of which is a permanent magnet and the other unmagnetized, how could you tell which is which by using only the two bars?
Answers
There are two identical iron bars, one of which is a permanent magnet and the other unmagnetized. We can identify that: when the magnetized bar is brought near the other bar, it will stick to it, indicating that it is magnetized. The bar that does not stick is unmagnetized.
Iron bars are used to make permanent magnets by a process called magnetization. Permanent magnets are composed of atoms and aligned electrons that have magnetic properties. The other bar that is not magnetized does not have aligned electrons, so it will not attract other magnets as a magnetized bar would.
The direction of a magnetic field will change when a magnet is brought near it. The North Pole will attract the South Pole, and they will come together. The North Pole will repel the North Pole, and the South Pole will repel the South Pole. The magnetized bar will be attracted to the unmagnetized bar, and the unmagnetized bar will not be attracted to the magnetized bar.
As a result, when the magnetized bar is brought near the other bar, it will stick to it, indicating that it is magnetized. The bar that does not stick is unmagnetized. Thus, with the aid of two bars, one magnetized and the other unmagnetized, we can determine which is which.
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How Can the human ear detect the sound
Answers
Answer:
Sound waves enter the outer ear and travel through a narrow passageway called the ear canal, which leads to the eardrum. The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear.
Explanation:
The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear. These bones are called the malleus, incus, and stapes.
a.
To improve feelings about a poor test result, a student should
Beg the teacher for a second chance at the c. Ask their parents for assistance in persuading
test
the teacher to change a grade
b. Ask for an opportunity to earn extra creditd. All of these
Please select the best answer from the choices provided
A
B
ОООО
С
D
Answers
Answer:
Well, their are two answers in their. It would be Ask their Parent for assistance in persuading and Ask for an opportunity to earn extra credit:)
Explanation:
To improve feelings about a poor test result, a student should ask for an opportunity to earn extra credits. Hence, option D is correct.
How to handle disappointment at result?Remember that you are so much more valuable than a letter on a piece of paper. Your attitude, personality, and experience are things that future employers, coworkers, teachers, friends, and family are interested in. Even while practicing excellent self-care is always important, having a program in place will help you deal with any anxiety you may be experiencing in the future.
Start with the fundamentals, like eating healthily, Getting your five a day is a fantastic place to start Since it provides your body and brain with all the nutrition they require, and it can help you deal with any cortisol increases (stress). Additionally, ensure you get at least eight hours of sleep each night and consume six to eight glasses of water each.
To improve feelings about a poor test result, a student should ask for an opportunity to earn extra credits. Hence, option D is correct.
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in what direction is the earth's angular velocity for its daily rotation on its axis
Answers
The Earth's angular velocity for its daily rotation on its axis is in the counterclockwise direction (eastward).
The Earth's angular velocity for its daily rotation on its axis is in the eastward direction. From above, this movement would look like the Earth is moving counterclockwise. This means that the Earth rotates from west to east, causing the sun to appear to rise in the east and set in the west. This is also why time zones are arranged with earlier times to the east and later times to the west. The Earth's rotation on its axis is what causes the cycle of day and night.
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Help me please I swear I'm gonna di3 my science sucks
Answers
Q2) Cell membrane (d)
Q3) Provides the cell with water (b)
Q4) b
(Yw)
An electric lamp is marked 240v, 60w
It is left to operate for 1h. How much
heat is generated by the lamp
Answers
Answer:
H = 0.06 kWh
Explanation:
Given that,
Power of an electric lamp, P = 60 W
Voltage, V = 240 V
It is operated for 1 hour
We need to find the heat generated by the lamp. Heat generated is given by :
\(H=P\times t\\\\H=60\ W\times 1\ h\\\\H=60\ Wh\\\\H=0.06\ kWh\)
So, 0.06 kWh of the heat is generated by the lamp.
Consider a person standing on a scale in an elevator. If the elevator accelerates upwards with an acceleration of 1.24 m/s2 and the person has a mass of 91.3 kg, what would the scale read? HINT: you need to take into account the acceleration due to gravity, as well as that of the elevator.
Answers
Given:
The upward acceleration of the elevator, a=1.24 m/s²
The mass of the person, m=91.3 kg
To find:
The reading of the scale.
Explanation:
When the elevator is accelerating upwards, the force applied on the scale is given by,
\(F=ma+mg\)On substituting the known values,
\(\begin{gathered} F=91.3\times1.24+91.3\times9.8 \\ =1007.95\text{ N} \end{gathered}\)Final answer:
The reading of the scale is 1007.95 N
Hi. okay so, i'm checking to make sure that my homework is correct, i think that H20, N2, CO2, and CH4 is correct. PLZZZ tell me if i'm wrong!!
Answers
Answer:
put an X on the second one, the third one, the forth one, and the last one
Explanation:
can i get braineist pls
HELP PLS 100 POINTS TAKING TEST RN
WHEN you look at the speedometer in a moving car, you can see the car's.
A.instantaneous speed.
B.average speed.
C.instantaneous acceleration.
D.average acceleration.
E.average distance traveled.?
Answers
Answer:
I think he answer is C but I could be wrong
Explanation:
brainliest plz
Answer:
d mark brainlyest
Explanation:
what must be true if the cart continues at the same speed in the same direction?
Answers
The acceleration and net force must both be zero if an object is travelling continuously to the right at a constant speed.
What is the name of Newton's first law?Newton's first law states that any object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the application of an external force. The tendency to resist changes in a motion situation is known as inertia.
What is travelling in the same direction and at the same speed?The only time two objects have the same velocity is when they are going in the same direction and at the same speed. Objects moving at varying rates, in varying directions, or in both directions exhibit variable velocities.
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What is the acceleration when an object traveling at 4.7 m/s accelerates to 23.9 m/s over a distance of 300 m?
Answers
Answer:
67.2 m
Explanation: source - trust me bro
a 0.160-kg hockey puck is moving on an icy, frictionless, horizontal surface. the puck is initially moving to the right with a speed of 3.00 m/s. what is the speed of the puck after a force of 12.0 n directed to the left is applied for 0.050 s?
Answers
The speed of the puck after the force is applied for 0.050 s is approximately 0.75 m/s to the left. Note that the negative sign indicates the direction
To find the speed of the hockey puck after the applied force, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:
F_net = m * a
In this case, the net force acting on the puck is the applied force of 12.0 N directed to the left. The mass of the puck is 0.160 kg. We need to calculate the acceleration of the puck.
The acceleration can be calculated using the equation:
a = F_net / m
a = 12.0 N / 0.160 kg
a = 75 m/s²
Since the initial speed of the puck is to the right, and the force applied is to the left, the net force acts to oppose the motion. Therefore, the acceleration is negative (-75 m/s²).
To find the final speed of the puck, we can use the equation:
v_final = v_initial + a * t
where:
v_final is the final speed,
v_initial is the initial speed,
a is the acceleration,
t is the time.
Plugging in the given values:
v_final = 3.00 m/s + (-75 m/s²) * 0.050 s
v_final = 3.00 m/s - 3.75 m/s
v_final ≈ -0.75 m/s
The speed of the puck after the force is applied for 0.050 s is approximately 0.75 m/s to the left. Note that the negative sign indicates the direction, which in this case is opposite to the initial motion of the puck.
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