Suppose grades on a business statistics exam are adequately described by a normal distribution with mean 76 and standard deviation of 6. If a professor decides to give As to those who scored 90 and above and Fs to those who scored 60 and below, what proportion of As and Fs combined would the professor be assigning. Indicate the interval below that contains this proportion i) .2000 to .2499 ii) 0.1500 to .1999 iii) .0000 to .0999 iv) .1000 to 1.499 v) .2500 to 1.000

Answers

Answer 1

The normal distribution with a mean of 76 and a standard deviation of 6 describes the grades on a business statistics exam. The proportion of students scoring between 90 and above (A) and 60 and below (F) is 0.0136, which falls within the interval of 0.0000 to 0.0999.

In the given context, the normal distribution refers to the statistical distribution that adequately describes the grades on a business statistics exam. It is assumed that the grades follow a normal distribution with a mean of 76 and a standard deviation of 6.

The normal distribution, also known as the Gaussian distribution or bell curve, is a continuous probability distribution characterized by a symmetric bell-shaped curve. It is widely used in statistics and probability theory due to its mathematical properties and its applicability to many real-world phenomena.

The formula for standardizing a normal variable Z is:

Z=frac{x-mu}{sigma}, where x is the raw score, μ is the mean, and σ is the standard deviation.

The proportion of grades who scored an A (90 and above) and F (60 and below) can be calculated as follows:

First, we will find the Z-score of grade 90:

Z=frac{x-mu}{sigma}=frac{90-76}{6}=2.33.

Now, we need to find the proportion of students who scored 90 and above:

P(Zge2.33)=0.0099.

Therefore, a 0.0099 proportion of students scored 90 and above.

Next, we will find the Z-score of grade 60:

Z=frac{x-mu}{sigma}=frac{60-76}{6}=-2.67.

Now, we need to find the proportion of students who scored 60 and below:

P(Zle-2.67)=0.0037.

Therefore, 0.0037 proportion of students scored 60 and below.

The proportion of students who scored between A (90 and above) and F (60 and below) is $0.0099 + 0.0037 = 0.0136.

Therefore, the professor will be assigning the proportion of 0.0136.

The interval that contains this proportion is option iii) 0.0000 to 0.0999.

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Related Questions

Simplify this expression. 1 + 4.25n + 3/2p – 3 + (–2p) + 5/4n

please help!

Answers

Answer:

11n/2 - p/2 -2

Please give me braniest

The spinner is shown has eight congruent sides the spinner is spun 200 times. What is a reasonable prediction for the number of times the spinner will land on 2 or 3

Answers

Answer:

50 times

Step-by-step explanation:

Total number of faces = total possible outcomes = 8

Number of 2 or 3 on spinner = required outcome = 2

Probability of obtaining a 2 or 3 = required outcome / Total possible outcomes

P(2 or 3) = 2 / 8 = 1/ 4

From 200 ; prediction for the number of 2 or 3

1/4 * 200

= 50 times

PLEASE HELP!!!!!! In which week was the rainfall in Portland the highest and how much fell?

weekly rainfall bar graph
Week 3, 800 cm
Week 4, 1400 cm
Week 4, 1200 cm
Week 3 900 cm

PLEASE HELP!!!!!! In which week was the rainfall in Portland the highest and how much fell?weekly rainfall

Answers

Answer:

Week 4, 1400

Brainliest plz

Step-by-step explanation:

Answer:

Week 3 and 900 cm

Step-by-step explanation:

Brainliest Please!

Each baseball hat costs the same amount of money. The cost for 18 baseball hats was $217. What is the unit price?


PLS SHOW EXPLANATION

Answers

Answer:

$12.05

Step-by-step explanation:

217 divides by 18 is 12.05

ASAP SOMEONE HELP ME OUT:)))))

ASAP SOMEONE HELP ME OUT:)))))

Answers

Answer:

10/6 i think

Step-by-step explanation:

suppose you shuffle a deck of cards and look at the top card 10 times. find the probablility that exactly 5 of the cards you see are hearts

Answers

The probability of seeing exactly 5 hearts out of 10 cards is\((13/52)^5 × (39/52)^5.\)

The probability of seeing exactly 5 hearts out of 10 cards can be calculated as follows: The total number of cards in a deck is 52. The number of hearts in a deck is 13. Since no card has been removed from the deck, the probability of seeing a heart is 13/52. The probability of seeing a non-heart is 39/52. Since we are looking at 10 cards, the probability of seeing exactly 5 hearts,

p(h)= 13/52

p(nh) = 39/52

hence, \((13/52)^5 × (39/52)^5\)

This means that the probability of seeing exactly 5 hearts out of 10 cards is \((13/52)^5 × (39/52)^5.\)

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Which represents the inverse of the function f(x) 4x?
O h(x) = x + 4
O h(x) = x - 4
O h(x) Sx
O h(x) = ~x

Answers

Answer:

\(h(x)=\dfrac{1}{4}x\)

Step-by-step explanation:

The inverse of a function is its reflection in the line y = x.

Given function:

\(f(x)=4x\)

The given function has an unrestricted domain and range.

Domain:  (-∞, ∞)  →  all real numbers.Range:  (-∞, ∞)  →  all real numbers.

To find the inverse of the given function, first replace f(x) with y:

\(\implies y=4x\)

Rearrange the equation to isolate x:

\(\implies \dfrac{y}{4}=\dfrac{4x}{4}\)

\(\implies \dfrac{1}{4}y=x\)

\(\implies x=\dfrac{1}{4}y\)

Swap the x for f⁻¹(x) and the y for x:

\(\implies f^{-1}(x)=\dfrac{1}{4}x\)

This is the inverse of the given function.

The domain of the inverse function is the range of the function.

The range of the inverse function is the domain of the function.

Therefore, the domain and the range of the inverse function are unrestricted.

Domain:  (-∞, ∞)  →  all real numbersRange:  (-∞, ∞)  →  all real numbers

Therefore, the function that represents the inverse of f(x) = 4x is:

\(\boxed{h(x)=\dfrac{1}{4}x}\)

question 9 of 10 explain how you can determine the sign of the sum of two integers if one integer is positive and the other integer is negative.

Answers

To determine the sign of the sum of two integers when one integer is positive and the other is negative, we can follow a simple rule based on their magnitudes.

If the magnitude of the positive integer is greater than the magnitude of the negative integer, the sum will be positive. This is because the positive integer outweighs the negative integer, resulting in a positive value.

On the other hand, if the magnitude of the negative integer is greater than the magnitude of the positive integer, the sum will be negative. In this case, the negative integer dominates and determines the sign of the sum.

In both scenarios, the sign of the larger magnitude integer takes precedence and determines the sign of the sum. It is important to note that the sum will always have the sign of the integer with the larger magnitude, regardless of the specific values of the integers involved.

By considering the magnitudes of the integers, we can easily determine the sign of their sum when one integer is positive and the other is negative.

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what is the volume of the cylinder below

what is the volume of the cylinder below

Answers

Step-by-step explanation:

here's your solution

=> volume of cylinder = πr^2h

=> radius of cylinder = 12 unit

=> height of cylinder = 17 unit

=> volume of cylinder = 2448 π units^3

\(\huge\mathcal\pink{here's \: your \: solution}\)

\(\huge\mathfrak\purple{hope \: it \: helps \: }\)

Please help this is the last question on my test!! What is the approximate area of a circle with a radius of 4 feet? Use 3.14

Answers

Answer:

50 feet²

Step-by-step explanation:

r = 4 feet

Area of circle = \(\pi\) r²

                      = 3.14 * 4 * 4

                      = 50.24 = 50 feet²

Answer:

50.24 square feet

Step-by-step explanation:

area = π\(r^{2}\)

area = 3.14 x 4ft

area = 50.24\(ft^{2}\)

What is 9.215×10∧−7 in standard form?

Answers

Answer:

0000009215

Step-by-step explanation:

move decimal left 7 digits

A number consists of two digits whose sum is 9. If 9 is added to the number its digits are inter changed. Find the number.​

Answers

Solution:

Let the two digits of a number be X and Y

Let the digit at 10's place = X

Let the digit at 1's place = Y

The two digit number = 10X+Y

Given that

The sum of the digits = 9

⇛ X+Y = 9

⇛X = 9-Y →→→→eqn(i)

If 9 is added to the number the digits interchanged

⇛10X+Y +9 = 10Y+X

⇛10X+Y+9-10Y-X = 0

⇛9X-9Y +9 = 0

⇛9(X-Y+1) = 0

⇛X-Y+1 = 0

⇛9-Y-Y+1 = 0

⇛10-2Y = 0

⇛2Y = 10

⇛Y = 10/2

⇛Y = 5

Now

X = 9-5 = 4

Therefore the number = 45 Ans.

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A number consists of two digits whose sum is 9. If 9 is added to the number its digits are inter changed.

Answer:

see that attachment

I hope it's help you

A number consists of two digits whose sum is 9. If 9 is added to the number its digits are inter changed.
A number consists of two digits whose sum is 9. If 9 is added to the number its digits are inter changed.
A number consists of two digits whose sum is 9. If 9 is added to the number its digits are inter changed.
A number consists of two digits whose sum is 9. If 9 is added to the number its digits are inter changed.

solve the inequality |2x-3|<7

Answers

Answer:

ɪ ʟᴏᴠᴇ ʏᴏᴜ sᴏ ᴍᴜᴄʜ ᴘʟssssss

What is the inverse of y = x2 + 16

Answers

y=x2-16
I’m not sure if I’m right or not

Answer:

\( {y}^{ - 1} = \sqrt{x - 16} \)

Step-by-step explanation:

To find the inverse of this function, we make "x" the subject of the equation .\(y = {x}^{2} + 16 \\ {x}^{2} = y - 16 \\ x = \sqrt{y - 16} \)then we interchange "y" and "x" .\(hence \: the \: inverse \: is \\ {y}^{ - 1} = \sqrt{x - 16} \)

the cookies in a jar contain a total of 1000 chocolate chips. all but one of these cookies contains the same number of chips; it contains one more chip than the others. the number of cookies in the jar is between one dozen and three dozen. what is the sum of the number of cookies in the jar and the number of chips in the cookie with the extra chocolate chip?

Answers

The total number of chocolate chips in the cookies is 1000. All the cookies, except one, have the same number of chips, while the remaining cookie has one more chip than the others. The number of cookies in the jar is between one dozen (12 cookies) and three dozen (36 cookies).


To find the sum of the number of cookies in the jar and the number of chips in the cookie with the extra chocolate chip, we can follow these steps:

1. Let's assume the number of cookies in the jar is "x". Since the number of cookies is between one dozen and three dozen, we have the inequality: 12 ≤ x ≤ 36.

2. Since all the cookies, except one, have the same number of chips, we can divide the total number of chocolate chips by the number of cookies minus one. This gives us the number of chips in each cookie (excluding the one with the extra chip). So, the number of chips in each cookie is 1000 ÷ (x - 1).

3. The cookie with the extra chip has one more chip than the others. Therefore, the number of chips in the cookie with the extra chip is 1000 ÷ (x - 1) + 1.

4. To find the sum of the number of cookies in the jar and the number of chips in the cookie with the extra chocolate chip, we add the number of cookies (x) and the number of chips in the extra chip cookie (1000 ÷ (x - 1) + 1).

Remember that the number of cookies in the jar is between one dozen and three dozen, so the sum will vary depending on the number of cookies. You can substitute different values within the given range (12 ≤ x ≤ 36) to find different possible sums.

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38. Joey paid for 5 hours of batting lessons in March.
Each hour cost him $23.50.
Joey also paid $42.25 for his membership
fee.
What is the total amount that Joey paid for his lessons in
March?

Answers

Answer:

159.75

Step-by-step explanation:

23.50×5=117.5

117.5+42.25=159.75

Find the difference.
\((3s^{2} +2st+5t^{2} )-(-2s^{2} +st+7t^{2} )\)

Possible Answers:
A: \(5s^{2} +st-2t^{2}\)
B: \(s^{2} +st-2t^{2}\)
C: \(5s^{2} +3st+12t^{2}\)
D: \(s^{2} +3st+12t^{2}\)

Answers

the answer is letter A: 5s^2+st-2t^2

Let A = {x, y, z, t, q} and B = {x y, z, t, p, q, r, s}. Find
and show each steps.
a) A ∪ B. b) A ∩ B. c) A − B. d) B − A.

Answers

These are the results of the set operations between set A and set B.

a) A ∪ B = {x, y, z, t, q, p, r, s}

b) A ∩ B = {x, y, z, t, q}

c) A - B = {z}

d) B - A = {p, r, s}

Let's find the set operations between set A and set B step by step:

a) Union (A ∪ B):

The union of two sets A and B, denoted as A ∪ B, is the set that contains all the elements present in either set A or set B (or both). To find the union of A and B, we combine all the elements from both sets without duplication:

A = {x, y, z, t, q}

B = {x, y, z, t, p, q, r, s}

A ∪ B = {x, y, z, t, q, p, r, s}

Therefore, the union of set A and set B is {x, y, z, t, q, p, r, s}.

b) Intersection (A ∩ B):

The intersection of two sets A and B, denoted as A ∩ B, is the set that contains all the elements common to both set A and set B. To find the intersection of A and B, we identify the elements that are present in both sets:

A = {x, y, z, t, q}

B = {x, y, z, t, p, q, r, s}

A ∩ B = {x, y, z, t, q}

Therefore, the intersection of set A and set B is {x, y, z, t, q}.

c) Set Difference (A - B):

The set difference between two sets A and B, denoted as A - B, is the set that contains all the elements that are in set A but not in set B. To find the set difference of A and B, we exclude the elements present in set B from set A:

A = {x, y, z, t, q}

B = {x, y, z, t, p, q, r, s}

A - B = {z}

Therefore, the set difference of set A and set B is {z}.

d) Set Difference (B - A):

The set difference between two sets B and A, denoted as B - A, is the set that contains all the elements that are in set B but not in set A. To find the set difference of B and A, we exclude the elements present in set A from set B:

A = {x, y, z, t, q}

B = {x, y, z, t, p, q, r, s}

B - A = {p, r, s}

Therefore, the set difference of set B and set A is {p, r, s}.

To summarize:

a) A ∪ B = {x, y, z, t, q, p, r, s}

b) A ∩ B = {x, y, z, t, q}

c) A - B = {z}

d) B - A = {p, r, s}

These are the results of the set operations between set A and set B.

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The probability of a Type II error is represented by ____. alpha beta the Type I error sigma The null hypothesis is rejected when the p-value exceeds the level of significance True False

Answers

The probability of a Type II error is represented by beta. Thus, the correct answer is option B.

Beta represents the probability of failing to reject the null hypothesis when it is false.

On the other hand, Type I error (alpha) represents the probability of rejecting the null hypothesis when it is true. A Type II error occurs when a false null hypothesis is not rejected. Hence, beta is the probability of making a Type II error.

The null hypothesis is rejected when the p-value is less than or equal to the level of significance, not exceeds it.

The p-value is the probability of obtaining a result as extreme as or more extreme than the observed result when the null hypothesis is true. If the p-value is less than the level of significance, the null hypothesis is rejected, and vice versa.

Hence, the statement "The null hypothesis is rejected when the p-value exceeds the level of significance" is false.

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assigning oxidation numbers , please help!!

assigning oxidation numbers , please help!!

Answers

Answer:

c is 1

o is q

h is 2

in ch3

c is 2 h is 3

and finally o is 1

i’ve been tryinng to find this out for hours and i’ve never got an proper answer-
can you guys please help me

ive been tryinng to find this out for hours and ive never got an proper answer- can you guys please help
ive been tryinng to find this out for hours and ive never got an proper answer- can you guys please help

Answers

Hey there mate :)

When a number is multiplied by a fraction equal to 1, the value of the number remains the same.

Using this, we can find the values:-

Image 2 answers :

\( \frac{4}{5} \times \frac{4}{4} = \frac{4}{5} \)

When we cancel the same 4 of LHS remaining we get as 4/5. By doing the same method, we can find the remaining answers.

\(\frac{2}{3} \times \frac{7}{7} = \frac{2}{3} \\ \\ \frac{5}{6} \times \frac{8}{8} = \frac{5}{6} \\ \\ \frac{3}{4} \times \frac{5}{5} \)

Image 1 answers :

\( \frac{2}{3} \times \frac{4}{2} = \frac{4}{3}\)

Here, cancel the common numbers in LHS and write back the remaining uncancelled numbers to get 4/3 in RHS.

Using same method,

\( \frac{3}{4} \times \frac{5}{3} = \frac{5}{4} \)

Next, Now in last two questions, we have to do a little differently. Till this much time we did by cancelling the common numbers. So, multiply the numerator and denominator.

\( \frac{1}{4} \times \frac{3}{2} \\ = > \frac{1 \times 3}{4 \times 2} \\ = > \frac{3}{8} \)

So, above question's answer is 3/8.

Likewise, using the same method, find the next question :-

\( \frac{2}{5} \times \frac{4}{3} \\ = > \frac{2 \times 4}{5 \times 3} \\ = > \frac{8}{15}\)

So, next answer is 8/15.

Hope this Helps...

\(Benjemin360 :)\)

which function has a graph that is narrower than the graph of h(x)=x^2

Answers

Any quadratic function whose leading coefficient is greater than 1 is narrower than \(h(x) = x^2\).

Analysis of a second order polynomial

The function \(h(x) = x^2\) belongs to the family \(y = a\cdot x^{2}\), where \(a\) is a real coefficient. The greater the \(a\), the narrower the graph. Hence, any function whose leading coefficient is greater than \(a\) presents a narrower form, that is, \(y\) shows greater values for a given value of \(x\).

Any quadratic function whose leading coefficient is greater than 1 is narrower than \(h(x) = x^2\). \(\blacksquare\)

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The seventh grade class is building target areas for a or activity. The based for the game will be a circular shape. The diameter of each circle is 5 feet. Approximately how !any square feet of the turf need to be painted for the base circle?

Answers

Answer:

Step-by-step explanation:

rwerdfsdfsdfsdfsdfsdfsdfsdfsdfsd           56

can u do question b pls​

can u do question b pls

Answers

Answer:     a) $481.62      b) $16,569.76

Step-by-step explanation:

The formula for compound interest is:    \(A = P(1 + r)^t\)     where

A is the accrued amount (balance)P is the principle (initial deposit)r is the rate (convert percentage into a decimal)t is the time (number of years)

Given: P = 3000, r = 1.15% (0.015), t = 10

\(A = 3000(1 + 0.015)^{10}\\\\\\A = 3000(1.015)^{10}\\\\\\A = 3,481.62\)

Interest Earned = accrued amount - principle

                          = 3,481.62 - 3,000

                           =   481.62

******************************************************************************************

I couldn't remember the formula so I created a table:

\(\begin{array}{c||l|c||r}\underline{Jan\ 1}&\underline{Interest\ Earned}&\underline{Deposit}&\underline{Balance}\\2019&0&3000&3,000.00\\2120&3000(1.015)&1200&4,245.00\\2121&4245(1.015)&1200&5,508.68\\2122&5508.68(1.015)&1200&6,791.31\\2123&6791.31(1.015)&1200&8,093.17\\2124&8093.17(1.015)&1200&9,414.57\\2125&9414.57(1.015)&1200&10,755.79\\2126&10755.79(1.015)&1200&12,117.13\\2127&12117.13(1.015)&1200&13,498.88\\2128&13498.88(1.015)&1200&14,901.37\\2129&14901.37(1.015)&1200&16,324.89\\\end{array}\)

2130  || 16324.89(1.015)  |       0      ||  16,569.76

1. Add 4x2y and 6x2y.12z2+10x2y−2z

Simplify 4x2y + 12z2 + 6x2y – 2z.


A. 10x2y + 10z2


B. 10x2y + 12z2 – 2z


C. 10x2y + 14z2


D. 20x2yz2

Answers

Answer:

B. 10x2y + 12z2 – 2z

Step-by-step explanation:

Divide all the terms by 2:

2xy + 12z + 3xy - z

 10x2y + 12z2 – 2z

                combine the like terms

I think the answer is b

Solve the following initial value problem:
dy dt +0.4ty = 2t, y(0) = 2

Answers

The solution to the initial value problem dy/dt + 0.4ty = 2t, y(0) = 2 is given by y = (0.2t^2 + 2) / e^(0.2t^2). We can start by recognizing that this is a first-order linear ordinary differential equation.

To solve the given initial value problem:

dy/dt + 0.4ty = 2t, y(0) = 2

We can use an integrating factor to solve it.

The integrating factor is given by the exponential of the integral of the coefficient of y, which in this case is 0.4t:

μ(t) = e^(∫0.4t dt)

    = e^(0.2t^2)

Now, we multiply both sides of the differential equation by the integrating factor μ(t):

e^(0.2t^2) * dy/dt + 0.4te^(0.2t^2) * y = 2te^(0.2t^2)

Next, we can rewrite the left-hand side of the equation as the derivative of the product of the integrating factor and y:

d/dt (e^(0.2t^2) * y) = 2te^(0.2t^2)

Integrating both sides with respect to t:

∫ d/dt (e^(0.2t^2) * y) dt = ∫ 2te^(0.2t^2) dt

Integrating the right-hand side gives:

e^(0.2t^2) * y = ∫ 2te^(0.2t^2) dt

                 = ∫ 2t d(0.2t^2)  (using u-substitution, let u = 0.2t^2)

                 = ∫ du

                 = u + C

                 = 0.2t^2 + C

Now, we can solve for y:

e^(0.2t^2) * y = 0.2t^2 + C

Dividing both sides by e^(0.2t^2):

y = (0.2t^2 + C) / e^(0.2t^2)

To find the value of C, we can use the initial condition y(0) = 2:

2 = (0.2(0)^2 + C) / e^(0.2(0)^2)

2 = C

Substituting C = 2 back into the solution equation:

y = (0.2t^2 + 2) / e^(0.2t^2)

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Suppose a Realtor is interested in comparing the asking prices of midrange homes in Peoria, Illinois, and Evansville, Indiana. The Realtor conducts a small telephone survey in the two cities, asking the prices of midrange homes. A random sample of 21 listings in Peoria resulted in a sample average price of $116,900, with a standard deviation of $2,300. A random sample of 26 listings in Evansville resulted in a sample average price of $114,000, with a standard deviation of $1,750. The Realtor assumes prices of midrange homes are normally distributed and the variance in prices in the two cities is about the same. The researcher wishes to test whether there is any difference in the mean prices of midrange homes of the two cities for alpha = .01. The appropriate decision for this problem is to?

Answers

The appropriate decision for this problem would depend on the calculated test statistic and its comparison to the critical value from the t-distribution table with a significance level of 0.01.

To determine the appropriate decision for this problem, the researcher needs to perform a hypothesis test. The null hypothesis (H0) would state that there is no difference in the mean prices of midrange homes between the two cities, while the alternative hypothesis (Ha) would state that there is a difference.

Since the sample sizes are relatively large (21 and 26), and the data is assumed to be normally distributed with similar variances, a two-sample t-test would be appropriate for comparing the means. The researcher can calculate the test statistic by using the formula:

\(t = (x1 - x2) / \sqrt{((s1^2 / n1) + (s2^2 / n2))}\)

Where x1 and x2 are the sample means, s1 and s2 are the sample standard deviations, and n1 and n2 are the sample sizes.

With the calculated test statistic, the researcher can compare it to the critical value from the t-distribution table with (n1 + n2 - 2) degrees of freedom, and a significance level of 0.01. If the test statistic falls within the critical region (i.e., it exceeds the critical value), the researcher can reject the null hypothesis and conclude that there is a significant difference in mean prices between the two cities. Otherwise, if the test statistic does not exceed the critical value, the researcher fails to reject the null hypothesis and concludes that there is not enough evidence to suggest a difference in mean prices.

In this case, the appropriate decision would depend on the calculated test statistic and its comparison to the critical value.

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Help!! In two or more sentences , explain how to find the time it takes for a rocket following the path h(x)= -4x^2 + 16x to hit the ground

Answers

The time it takes for a rocket following the path h(x)= -4x² + 16x to hit the ground is 4 seconds.

How to find the time for a rocket to hit the ground?

The given path equation is a function of x which is a time variable here. When the rocket hits ground, height of the rocket gets zero.

Hence equating the equation of height to zero and solving for x will give the time required for the rocket to hit the ground.

According to the given question:

We are given equation for height as

h(x) = -4x² + 16x

where x is the time in seconds

When object hits the ground the height becomes 0

So, we can set h(x) = 0 and then we can solve for x

-4x² + 16x = 0

Dividing by -4x from both sides

x - 4 = 0

x = 4 sec

So, the time it takes for a rocket  to hit the ground is 4 seconds.

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If O is an angle in standard position and its terminal side passes through the point
(3,-1), find the exact value of tan 0 in simplest radical form.
please help !

Answers

Answer:

-1/3

Step-by-step explanation:

Determine the slope between the two points: (-9,5) and (3,2)

Answers

Answer:

Let (x1, y1) = (-9, 5) and (x2, y2) = (3, 2) be the two points.

The formula for finding the slope between two points is:

m = (y2 - y1) / (x2 - x1)

Substituting the values, we get:

m = (2 - 5) / (3 - (-9))

m = -3 / 12

m = -1/4

Therefore, the slope between the points (-9, 5) and (3, 2) is -1/4.

Answer:

M = -1/4

Step-by-step explanation:

(y2-y1)/(x2-x1) = Slope

we use the x and y components of the given coordinates to find out the answer.

Therefore,

(2-5)/(3-(-9)) = -1/4

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