The amount of the radioactive atom that will be left after 60 seconds is 8 g.
The given parameters;
initial mass of the radioactive atom, N₀ = 128 ghalf-life of the radioactive atom, \(t_{1/2}\) = 15 secondstime of the radioactive, t = 60 secondsThe amount of the radioactive atoms that will be left after 60 seconds is calculated as follows;
0 --------------------------------- 128 g
15 s ------------------------------ 64 g
30 s ----------------------------- 32 g
45 s ----------------------------- 16 g
60 s ------------------------------ 8 g
Thus, the amount of the radioactive atom that will be left after 60 seconds is 8 g.
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12.12 an airplane flies at 550 km/hr at 1500 m altitude on a standard day. the plane climbs to 15,000 m and flies at 1200 km/hr. calculate the mach number of flight in both cases
To calculate the Mach number of the airplane in both cases, we need to determine the speed of the aircraft relative to the speed of sound in the atmosphere at the given altitudes. The speed of sound can be calculated using the standard atmospheric conditions.
At 1500 m altitude, on a standard day, the speed of sound can be approximated as 340.29 m/s.
Case 1: Altitude = 1500 m, Speed = 550 km/hr
Converting the speed to meters per second:
Speed = 550 km/hr = (550 * 1000) / (60 * 60) = 152.78 m/s
To calculate the Mach number:
Mach number = Speed / Speed of sound
Mach number = 152.78 / 340.29 ≈ 0.449
Therefore, at 1500 m altitude, the Mach number of the flight is approximately 0.449.
Case 2: Altitude = 15,000 m, Speed = 1200 km/hr
Using the same method as above, we convert the speed to meters per second:
Speed = 1200 km/hr = (1200 * 1000) / (60 * 60) = 333.33 m/s
To calculate the Mach number:
Mach number = Speed / Speed of sound
Mach number = 333.33 / 295.07 ≈ 1.128
Therefore, at 15,000 m altitude, the Mach number of the flight is approximately 1.128.
In summary, at 1500 m altitude, the Mach number is approximately 0.449, and at 15,000 m altitude, the Mach number is approximately 1.128. The Mach number indicates the ratio of the aircraft's speed to the speed of sound in the surrounding medium. A Mach number greater than 1 signifies supersonic flight, while a Mach number less than 1 represents subsonic flight.
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two locomotives approach each other on parallel tracks. each has a speed of 155 km/h with respect to the ground. if they are intially 8.5 km apart, how long will it be before they reach each other
The time the two locomotives will take to reach each other is 1.07 minutes.The speed of both the locomotives is 155 km/hr with respect to the ground.The distance between both the trains at initial point is 8.5 km
We have to calculate the time it will take for them to meet:Distance is equal to speed multiplied by time, so the distance between them (8.5 km) is equal to the relative speed between them multiplied by the time it takes them to meet.Let's calculate the relative speed:Relative speed = Speed of locomotive 1 + Speed of locomotive 2= 155 km/hr + 155 km/hr= 310 km/hrNow we can use the formula:Distance = Relative Speed × Time
We know the distance and the relative speed. Therefore,Time taken to meet = Distance / Relative speed= 8.5 km / 310 km/hr= 0.0274 hoursConvert hours to minutes:1 hour = 60 minutes0.0274 hours = 0.0274 × 60 minutes = 1.07 minutesSo, the time the two locomotives will take to reach each other is 1.07 minutes.
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the head of a nail is 0.39 cm0.39 cm in diameter. you hit it with a hammer with a force of 27 n.27 n. what is the pressure pheadphead on the head of the nail?
The pressure is 22.59 x 10⁵ Pa.
We need to know about pressure to solve this problem. Pressure is unit that describe how much force applied on a surface area. It can be determined as
P = F / A
where P is pressure, F is force and A is area.
From the question above, we know that
d = 0.39 cm = 0.0039 m
F = 27 N
Calculate the surface area of the nail
A = π . r²
A = π . (1/2 . d)²
A = π . (1/2 . 0.0039)²
A = 1.195 x 10¯⁵ m²
Determine the pressure
P = F / A
P = 27 / (1.195 x 10¯⁵ )
P = 22.59 x 10⁵ Pa
Hence, the pressure is 22.59 x 10⁵ Pa.
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What is the power of a 23.5 cm focal length lens? express your answer using 3 significant figures. (b) is this lens converging or diverging? (c) what is the focal length of a -6.75 d lens? express your answer using 3 significant figures. (d) is this lens converging or diverging?
a) The power of a 23.5 cm focal length lens is 4.26 diopters (rounded to 3 significant figures).
b) This lens is converging.
c) The focal length of a -6.75 d lens is 0.148 m (rounded to 3 significant figures).
d) This lens is diverging.
(a) The power of a 23.5 cm focal length lens can be calculated using the formula P = 1/f, where P is the power of the lens in diopters and f is the focal length in meters. Converting the focal length to meters, we get f = 0.235 m. Substituting this into the formula, we get P = 4.26 diopters (rounded to 3 significant figures).
(b) To determine if the lens is converging or diverging, we need to know if the focal length is positive or negative. A positive focal length indicates a converging lens, while a negative focal length indicates a diverging lens. Since the focal length of the given lens is positive (23.5 cm), it is a converging lens.
(c) The focal length of a lens can be calculated using the formula f = -1/d, where d is the lens power in diopters. Substituting the power of the -6.75 d lens into the formula, we get f = -1/-6.75 = 0.148 m (rounded to 3 significant figures).
(d) To determine if the lens is converging or diverging, we need to know if the focal length is positive or negative. A positive focal length indicates a converging lens, while a negative focal length indicates a diverging lens. Since the focal length of the given lens is negative (-0.148 m), it is a diverging lens.
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Una pelota de tenis de 100 g de masa lleva una rapidez de 20 m/s. Al ser golpeada por una raqueta, se mueve en sentido contrario con una rapidez de 40 m/s.
Calcular el impulso. Si le pelota permanece en contacto con la raqueta 〖10〗^(-2) sg, ¿Cuál es el módulo de la fuerza media del golpe?
The impulse of the tennis ball is 2000 Ns and the average force exerted on the ball is 200 N during the contact time of 0.01 s with the racket.
Using the formula for impulse,
impulse = change in momentum = m * Δv, where m is the mass of the ball and Δv is the change in velocity.
Δv = 40 m/s - 20 m/s = 20 m/s
impulse = (0.1 kg) * (20 m/s) = 2 kg m/s
To find the magnitude of the average force of the hit, we can use the formula: F = impulse / Δt, where Δt is the time the ball remains in contact with the racket.
F = 2 kg m/s / 0.01 s = 200 N (Newtons)
Therefore, the impulse is 2 kg m/s and the magnitude of the average force of the hit is 200 N.
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If this inclined plane moves 3 cm to the left how high will it lift the object
Answer:
It would lift the object to the same height than before you move it 3 centimeters to the left. You see, the height doesn't change if you move the inclined plane horizontally, because height is a vertical variable.
Therefore, if the inclined plane has a height of 1 meters, then the object will be lifted 1 meters up, no matter if you move the inclined plane 50 meters horizontally, it won't change its height.
Select the four components of which the entire physical universe exists are:
energy
velocity
time
space
density
matter
The four components of the physical universe are matter, energy, space, and time.
What four components do the entire universe exists?
The four components of which the entire physical universe exists are:
Matter: All the physical substances that make up the universe, including everything from stars and planets to subatomic particles, are made of matter.
Energy: Energy is a property of matter that can be transformed, but cannot be created or destroyed. It comes in many forms, including kinetic energy, thermal energy, and electromagnetic energy.
Space: Space is the three-dimensional framework in which all matter and energy exist. It provides the canvas on which the universe unfolds and shapes the way objects interact and move.
Time: Time is the dimension in which change occurs. It is essential for the universe to exist and for events to unfold in a causal and ordered manner.
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When a solid is heated, it emits electromagnetic radiation known as ________________. an example of such radiation is the element of a stove top burning bright red.
Answer:
I think the answer is thermal radiation
What does the texture of sample GOT 301 tell you about the rock’s origin?
a. The rock formed from a single phase of slow cooling deep underground.
b. The rock formed from a single phase of rapid cooling at the surface.
c. The rock formed from two phases of cooling slow followed by fast forming
finally as a rock at the surface.
d. The rock formed from cooling and reheating in multiple phases.
e. None of the above asnwers is correct.
: The texture of sample GOT 301 suggests that the rock formed from a single phase of slow cooling deep underground.
The texture of a rock can provide valuable insights into its origin and formation process. In the case of sample GOT 301, the presence of a fine-grained and uniform texture indicates that the rock underwent a relatively slow cooling process. This is because slow cooling allows for the formation of small mineral grains that have had sufficient time to grow and develop.
Furthermore, the absence of any visible signs of rapid cooling, such as large crystals or a glassy appearance, suggests that the rock did not experience a sudden cooling event at the surface. If the rock had formed from a single phase of rapid cooling at the surface (option b), we would expect to see larger crystals or a glassy texture.
The texture of sample GOT 301 does not provide evidence for a two-phase cooling process (option c), as there are no distinct layers or variations in grain size that would indicate a change in cooling rates. Similarly, there is no indication of multiple phases of cooling and reheating (option d), as this would typically result in a more complex and heterogeneous texture.
Therefore, based on the texture characteristics observed in sample GOT 301, the most likely explanation is that the rock formed from a single phase of slow cooling deep underground. This suggests that the rock underwent a gradual solidification process over an extended period of time, allowing for the formation of fine-grained minerals.
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Local winds are caused by what?
A. The unequal heating of the Earths surface
B. Weather systems
C. The rotation of the Earths surface
An example of a poor coping mechanism is ?
Answer: A bad, maladaptive, unhealthy or destructive coping mechanism is one where the behavior does not resolve the problem in the long-term and may actually increase the harm. Unhealthy coping strategies may feel like they are having the desired effect in the short term.
Explanation: Yes, it was from google...
what is the two example of velocity
1. the solid cylinder and cylindrical shell in the figure have the same mass, same radius, and they turn on frictionless, horizontal axles. a rope is wrapped around each cylinder and tied to a block. the blocks have the same mass and are held the same height above the ground. both blocks are released simultaneously. which hits the ground first?
The solid cylinder and cylindrical shell will hit the ground at the same time. This is because the mass of the cylinders, radius, and height above the ground are all the same for both the solid cylinder and cylindrical shell.
Additionally, the axles are frictionless, so there is no difference in the amount of rotational inertia between the two cylinders. Therefore, the acceleration due to gravity will be the same for both cylinders and the blocks tied to them. This means that they will both fall at the same rate and hit the ground at the same time.
Both the solid cylinder and the cylindrical shell have the same mass, radius, and are turning on frictionless horizontal axles. Since the blocks attached to them have the same mass and are held at the same height, the key factor in determining which block hits the ground first is the moment of inertia of each cylinder.
Therefore, the block attached to the solid cylinder will hit the ground first.
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In terms of center of gravity, discuss what determines whether or not an object will fall over when tilted. Give examples.
In terms of center of gravity, what determines whether or not an object will fall over when tilted is the object's base of support.
An object will fall over when tilted if the line of gravity falls outside of the base of support, according to the principles of equilibrium.
Examples of objects that can fall over when tilted include: A tall, narrow vase with a small base, a pencil that is held by its point and tilted too far, a stack of books that are precariously balanced, and a ladder that is leaning against a wall.The weight of an object is concentrated in the center of mass, which is also known as the center of gravity. This is the location where the gravitational forces acting on the object can be considered to act, according to the principles of equilibrium.
To be more specific, the center of gravity is the point at which the object's weight is evenly dispersed in all directions when it is suspended from that point.The stability of an object is determined by the placement of its center of gravity in relation to its base of support. When the line of gravity of an object is inside the base of support, the object is stable, and when it is outside the base of support, the object is unstable.
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help gives 100 points
Answer:
Explanation:
from the ruler the diameter is seen to be 0.4cm.
The radius is 0.4/2 = 0.2cm.
A championship weight lifter did 11,000 J of work on a set of barbells weighing 3680 N. How much gravitational potential energy did the barbells have at the maximum height of the lift? (show the steps you followed to solve the problem - ie. the formula, calculations, and final answer)
The GPE that the barbells have at max height is ,
3680.h j=11,000 units
where h= maximum height the barbells were lifted
work done by the championship lifter ,W = 11,000 units
weight of the barbells, N = 3680 N
The gravitational potential energy, P.E., the barbells had at their maximum height of lift is given as follows;
P.E. = m × g × h
Where;
m = The mass of the barbells;
g = The acceleration due to gravity = 9.8 m/s^2
h = The maximum height to which the barbells are lifted
m × g = The weight of the barbells = 3680 N
∴ P.E. = 3680 N × h = 3680·h J
we know the law of conservation of energy, according to this the work done by the weight lifter is equals to the maximum gravitational potential energy gained by the barbell is equal to energy at maximium height i.e P.E
therefore, GPE = 3680.h j = W = 11,000j is your answer.
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https://brainly.com/question/205610663. Why is a subducting plate boundary considered a type of
convergent plate boundary?
Answer:
✔ convergent
Explanation:
Answer:
B ( Convergent)
Explanation:
This is my physics homework
Answer:
Option B is the correct answer
Explanation:
Atomic number of Americium is 95 however in option B it is given as 94.
Thus, option B is the correct answer.
A single mechanical wave moves through two strings. In the first string, the wave has a speed of 260 m/s and a wavelength of 1.8m. In the second string, the wave has a speed of 25 m/s. Calculate the wavelength of the mechanical wave in the second string.
Using the concept of Mechanical-wave, we got 0.173m as the wavelength of the second string.
A mechanical wave is actually a wave that is not capable of transmitting its energy through the vacuum. Mechanical waves which require a medium in order to transport their energy from one point to another point. The sound wave is an example of a mechanical wave. Sound waves are actually incapable of traveling through a vacuum.
We are given a speed=260m/s and wavelength=1.8m of the first string
we know that,
speed = wavelength × frequency
So putting the value in the above formula
frequency = 260 / 1.8 ......(1)equation
Similarly, for the second string,
we are given a speed=25m/s and frequency from (1) equation
wavelength = (25×1.8)/260
wavelength = 0.173m
Hence, the wavelength of the mechanical wave in the second string is 0.173m.
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Describe the difference between distance, position, and displacement
Answer:
Explanation:
Position is the location of the object (whether it's a person, a ball, or a particle) at a given moment in time.
Displacement is the difference in the object's position from one time to another.
Distance is the total amount the object has traveled in a certain period of time.
I hope this helps!
How much heat is required to warm 230 g of water from 12°C to 90°C?
(Specific Heat of Water = 4.184)
2 A boy of mass 50 kg runs up a hill of vertical height
300 m in 20 minutes Calculate: a) the average vertical force he uses to lift
himself up the hillside b) the work he does climbing the hill c) his average power
The Vertical force is the same as his weight. By using the formula of work done and power, the correct answers are:
a.) 490N
b.) 147 KJ
c.) 122.5 W
Given that a boy of mass 50 kg runs up a hill of vertical height
300 m in 20 minutes.
a) The average vertical force he uses to lift himself up the hillside will be his normal reaction force (N) on the hill
N = mg
N = 50 x 9.8
N = 490N
b) the work he does climbing the hill will be
W = F x S
W = 490 x 300
W = 147000 Joules
W = 147 KJ
c) his average power will be
P = W/t
First convert the time from minutes to seconds
20 minutes = 20 x 60 = 1200 seconds
Substitute the time t and the work done W into the power formula
P = 147000/1200
P = 122.5 Watts
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given the force field f, find the work required to move an object on the given oriented curve r(t). f, r(t), for question content area bottom part 1 the amount of work done is 2. (type an exact answer, using as needed.)
The work done is given by the line indispensable of F over the bend. The line indispensable of a vector field F along a bend C is given by:
\(∫C F . dr\)
where dr is the differential of the position vector r(t) of the bend C.
The position vector r(t) of the bend C is given by:
r(t) = <t, 6t^2>
The differential of the position vector dr is given by:
dr = <1, 12t> dt
Subbing F(x,y) = (y,x), r(t) = <t, 6t^2> and dr = <1, 12t> dt into ∫C F . dr gives:
\(∫C F . dr\) = (0 to 2)/6t2, t. 1, 12t)
dt = [18t4 + 0.5t2] from 0 to 2 = 72 + 2 = 74.
From 0 to 2 (72t3 + t) dt = [18t4 + 0.5t2].
Vector, in material science, an amount that has both extent and course. It is regularly addressed by a bolt whose course is equivalent to that of the amount and whose length is corresponding to the amount's extent. Albeit a vector has size and bearing, it doesn't have position. That is, for however long its length isn't changed, a vector isn't modified assuming it is uprooted lined up with itself.
As opposed to vectors, customary amounts that have a greatness however not a course are called scalars. For instance, relocation, speed, and speed increase are vector amounts, while speed (the greatness of speed), time, and mass are scalars.
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correct question is:
Given the force field F, find the work required to move an object on the given orientated curve. F(x,y) = (y,x) on the parabola y = 6x^2 from (0,0) to (2,24) I'm not sure how to set up the integral of this problem.
The amount of work done is 10π^2 - 10 to move an object on the given oriented curve.
The work required to move an object on the given oriented curve, we can use the formula:
Work = ∫ F · dr
where F is the force field and dr is the differential displacement vector along the curve. In this case, the force field F is given as F = (5z, 5x, 5y), and the oriented curve r(t) is given as r(t) = (sin(t), cos(t), t), for 0 ≤ t ≤ 2π.
First, we need to find dr. Taking the derivative of r(t) with respect to t, we get:
dr = (cos(t), -sin(t), 1) dt
Next, we calculate F · dr:
F · dr = (5z, 5x, 5y) · (cos(t), -sin(t), 1) dt
= 5z cos(t) + 5x(-sin(t)) + 5y dt
= 5t cos(t) - 5sin(t) + 5t dt
Now, we can integrate F · dr over the given interval:
Work = ∫ (5t cos(t) - 5sin(t) + 5t) dt
Integrating term by term, we get:
Work = 5 ∫ t cos(t) dt - 5 ∫ sin(t) dt + 5 ∫ t dt
Integrating each term, we have:
Work = 5(t sin(t) + cos(t)) - 5(-cos(t)) + 5(\(t^2\)/2)
Evaluating the integral at the upper and lower limits (t = 2π and t = 0), we get:
Work = 5(2π sin(2π) + cos(2π)) - 5(-cos(2π)) + 5((2π\()^2\)/2) - 5(0 sin(0) + cos(0)) - 5(-cos(0)) + 5(\(0^2\)/2)
Simplifying further, we have:
Work = 5(2π(0) + 1) - 5(1) + 5(4π^2/2) - 5(0 + 1) - 5(1) + 5(0)
Work = 5 + 5(2π^2) - 5 - 5 - 5
Work = 5(2π^2) - 10
So, the amount of work done is 10π^2 - 10.
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complete question: given the force field f, find the work required to move an object on the given oriented curve r(t). F= (5z,5x,5y), r(t) = (sint, cost,t), for 0≤ st≤2x, the amount of work done is (type an exact answer, using as needed.)
A circular platform of radius 4.0 m is initially spinning with an angular velocity of 8.0 rad/s. The angular velocity is then increased to 10 rad/s over the next 4.0 seconds. Assume that the angular acceleration is constant. What is the magnitude of the angular acceleration of the platform?
The magnitude of the angular acceleration of the platform is 0.5 rad/s^2.
To find the magnitude of the angular acceleration of the platform, we can use the formula:
angular acceleration = (change in angular velocity) / (time taken)
Here, the initial angular velocity (ω1) of the platform is 8.0 rad/s and the final angular velocity (ω2) is 10 rad/s. The time taken (t) for the change in angular velocity is 4.0 seconds.
So, the change in angular velocity is:
ω2 - ω1 = 10 rad/s - 8.0 rad/s = 2.0 rad/s
And the angular acceleration is:
angular acceleration = (change in angular velocity) / (time taken)
angular acceleration = 2.0 rad/s / 4.0 s
angular acceleration = 0.5 rad/s^2
Therefore, 0.5 rad/s^2 is the magnitude of the angular acceleration of the platform.
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a normal person stands at the top of a 14.64-m tall cliff overhanging a pool of water. she throws two stones, 0.35 s apart, both straight down and finds they reach the water at the same time. the first stone's initial speed was 2.52 m/s. how fast was the second stone moving as it hit the water (i.e. what is its speed)?
The velocity of the second stone as it hit the water was 2.5m/s.
According to the question;
A person throws two stones into a pool of water from the top of a 14.64-meter-high cliff, 0.35 seconds apart.
The initial speed of the first stone was 2.52 meters per second.
We may use the kinematic equation to determine the second stone's speed when it struck the water:
v² = u² + 2as
where,
v = the final velocity = final velocity of second stone in this case = to find out
u = initial velocity = 2.52 m/s
a = acceleration = acceleration due to gravity in this case = -9.8 m/s²
s = distance = 14.64 m
In the equation, we may substitute the known values to obtain:
v² = 2.52²- 2(-9.8)×14.64
⇒ v² = √(2.52^2 - 2(-9.8)(14.64)) m/s
⇒ v² = √(6.3408) m/s
∴ v² = 2.5 m/s
As a result, when the second stone hit the water, it was traveling at a speed of 2.5 m/s.
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A peron i driving hi Lamborghini with a ma of 2,000 kg at 10 m/. He ee a police car around the corner and low down to 2m/. What i hi change in momentum? _ kgm/
The change in the momentum was found to be 16,000 kgm/s
Change in momentum ?
Situations involving impulse and momentum are all around us, whether we notice it or not. Before we begin evaluating these daily instances, we'll go over the fundamental ideas of impulse and momentum.
In physics, an impulse (Ft) is a force (F) operating over a certain time (t) that results in a change in momentum (p) of an object. The impulse-momentum theorem is the equation of impulse with the change in momentum.
the change in the momentum was Δp=mxΔv
Δp=2000x8
Δp=16,000 kgm/s
therefore the change in momentum was found to be 16,000kgm/s
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Explain in terms of energy the process
which takes place as a solid at its melting
point changes into a liquid at the same
temperature.
Explanation:
Endothermic reaction as heat from the environment is absorbed.
the transformation from solid to liquid is due to the latent heat of fusion/ enthalpy of fusion.
the heat energy absorbed from the environment is used to break the bonds of the solid structure therein converting it to a liquid. this is the reason why the temperature of the substance is constant at the state changes.
a cylinder weighs 29.2 grams what is its density? and will it float in water?
In order to determine the density of a cylinder, we need to know its mass and volume. The mass of the cylinder is given as 29.2 grams, but the volume is not provided. Without the volume, it is impossible to calculate the density of the cylinder.
As for whether or not the cylinder will float in water, that also depends on its density. If the density of the cylinder is less than the density of water (1), then it will float. However, without knowing the density of the cylinder, it is impossible to determine whether or not it will float in water.
Imagine you had a small bulb, an index card with a narrow slit cut in it, and a mirror arranged as shown in the top view diagram at right.
This arrangement can be used for various purposes, such as creating a focused beam of light or directing the light towards a specific point.
This setup with a small bulb, an index card with a narrow slit, and a mirror allows for the manipulation and control of light.
In the given scenario, you have a small bulb, an index card with a narrow slit, and a mirror. Let's understand how these components are arranged.
Firstly, the small bulb is placed in such a way that it emits light in all directions. Next, the index card with a narrow slit is positioned in front of the bulb. The purpose of the slit is to allow only a narrow beam of light to pass through.
Now, the mirror is placed at an angle near the bulb and the index card. The mirror reflects the beam of light that passes through the slit. By adjusting the angle of the mirror, you can control the direction in which the reflected light is projected.
In this setup, the slit acts as a light source and the mirror reflects the light beam. This arrangement can be used for various purposes, such as creating a focused beam of light or directing the light towards a specific point.
This setup with a small bulb, an index card with a narrow slit, and a mirror allows for the manipulation and control of light.
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Astronomers and physicists now believe they know what is happening to the missing neutrinos from the Sun (the neutrinos that our theories say should be emerging from the Sun, but our experiments in that underground mine could not find). These neutrinos are:
The missing neutrinos from the sun had merely tranformed into muon and tau neutrinos escaped detection.Hardly interacting with other matter,neutrinos comes in three different types electron,muon,and tau.
Hence option (b) turning into different type of neutrino in a neutrino oscillation is correct
Disclaimer:The question given on the portal is incomplete .Here is the complete question .
Question :Astronomers and physicists now believe they know what is happening to the missing neutrinos from the Sun (the neutrinos that our theories say should be emerging from the Sun, but our experiments in that underground mine could not find). These neutrinos are:
a)not being produced by the Sun because our star's nuclear fusion period has ended
b)turning into a different type of neutrino in a neutrino oscillation
c)being converted to antimatter in the core of the Sun and being destroyed as they hit matter
d)changing course before they reach the Earth as they hit other neutrinos in space
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