Sulfurous acid reacts with barium hydroxide.

Answer:

Yes

Explanation:

The speed of light is about 300 000 km per second, so light takes about 1.28 seconds to travel from the Moon to the Earth.

Answer:

Explanation:

ask you teacher

Answer:

see below

Explanation:

1. particle motion

2. The particles of a liquid can slide past one another.

3. the kinetic energy required to break forces between particles

4. increasing its temperature until it transitions from a solid to a liquid

5. A liquid becomes a gas.

[quizlet: captncrun]

Thermal energy is in the form of heat and light is always associated with the random motion of atoms and molecules. That form of kinetic energy is used to the rise in temperature.

Hence the option B is correct.

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The molar mass of a chemical compound is defined as the mass of the sample divided by the quantity, or number of moles, in the sample, measured in moles. The total grams of Nacl needed to get 0.241 moles exists 14.084 g.

The molar mass of a chemical compound is determined by dividing its mass by the quantity of that compound, expressed as the number of moles in the sample, measured in moles. The molar mass of a substance is a bulk attribute rather than a molecular one.

The molar mass of a chemical compound is defined as the mass of the sample divided by the quantity, or number of moles, in the sample, measured in moles.

Molar mass of Nacl = 58.44g

Total grams of Nacl needed to get 0.241 moles = moles number × molar mass

= 0.241 × 58.44

= 14.084 g

Therefore, the total grams of Nacl needed to get 0.241 moles exists 14.084 g.

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Answer: 4.5 moles

Explanation:

To understand how to solve this problem, you must understand the ratios written in this chemical equation.

The equation shows that 4 moles of Al forms 2 moles Al₂O₃. This creates the ratio 2:4 or \(\frac{2}{4}\)

To solve, you can set the two ratios to each other and cross multiply.

\(\frac{2}{4} = \frac{x}{9}\)

18 = 4x

x = 4.5 mol Al₂O₃

*both \(\frac{2}{4}\) and \(\frac{4.5}{9}\) can be simplified as \(\frac{1}{2}\), which verifies your answer*

It is most likely Option A: that a chemical change occurred in step 1 and a physical change occurred in step 2.

In step 1, the yellow particles appeared in the liquid, indicating a chemical change. This could be a result of a chemical reaction between the two colorless liquids, or the addition of a reagent that caused a reaction. This change is characterized by the formation of new substances, which are the yellow particles.

In step 2, the colorless liquid was separated from the yellow particles by decantation. Decantation is a physical process that separates immiscible liquids or solid particles from a liquid by allowing them to settle and then carefully pouring off the liquid.

Therefore, This change is characterized by the separation of components of a mixture, no new substances are formed.

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Explanation:

D. inner core and outer core

a) The balanced chemical equation for the reaction is: 2H₂ + O₂ → 2H₂O

b) the number of moles of O₂ required is approximately 1.004 moles.

c)  approximately 45 liters of H₂ and 22.5 liters of O₂ are needed to obtain 45 liters of H₂O.

a) Balancing the chemical equation:

The balanced chemical equation for the reaction is: 2H₂ + O₂ → 2H₂O

b) Calculating the number of moles of the reactants needed to obtain 45 liters of H₂O:

From the balanced equation, we can see that for every 2 moles of H₂O produced, we need 2 moles of H₂ and 1 mole of O₂. Since the stoichiometry is based on moles, we need to convert the given volume of H2O into moles.

To convert volume to moles, we need to use the ideal gas law, PV = nRT. At standard temperature and pressure (STP), the molar volume of an ideal gas is 22.4 liters.

Given that we have 45 liters of H2O, we can calculate the number of moles as follows:

moles of H₂O = (volume of H₂O) / (molar volume at STP)

            = 45 liters / 22.4 liters/mol

            ≈ 2.008 moles of H₂O

Since the stoichiometry of the reaction is 2 moles of H₂O for every 2 moles of H₂, we need an equal number of moles of H₂. Therefore, the number of moles of H₂ required is also approximately 2.008 moles.

For O₂, since the stoichiometry is 1 mole of O₂ for every 2 moles of H₂O, we need half the number of moles of H₂O. Thus, the number of moles of O₂required is approximately 1.004 moles.

c)  the volume of the reactants:

Since the stoichiometry of the balanced equation is 2 moles of H₂for every 1 mole of O₂ and 2 moles of H₂O, we can deduce the volume of the reactants based on their molar volumes at STP.

For 2.008 moles of H₂, the volume can be calculated as follows:

volume of H₂= (moles of H₂) * (molar volume at STP)

            = 2.008 moles * 22.4 liters/mol

            ≈ 45 liters of H₂

For 1.004 moles of O₂, the volume can be calculated similarly:

volume of O₂= (moles of O₂) * (molar volume at STP)

            = 1.004 moles * 22.4 liters/mol

            ≈ 22.5 liters of O₂

Therefore, approximately 45 liters of H₂and 22.5 liters of O₂ are needed to obtain 45 liters of H₂O

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The density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

To determine the density of ammonia gas (NH3) in a 6.0 L container at a pressure of 820 mm Hg, we need to use the ideal gas law equation, which relates pressure, volume, number of moles, and temperature for a given gas.

The ideal gas law equation is:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since we are given the pressure (820 mm Hg), volume (6.0 L), and assuming standard temperature and pressure (STP), we can use the values for R (0.0821 L·atm/(mol·K)) and convert the pressure to atm by dividing by 760 (1 atm = 760 mm Hg).

820 mm Hg / 760 mm Hg/atm = 1.08 atm

Now we can rearrange the ideal gas law equation to solve for density (d):

d = (P * M) / (RT)

Where M is the molar mass of ammonia (NH3), which is approximately 17.03 g/mol.

Substituting the values, we have:

d = (1.08 atm * 17.03 g/mol) / (0.0821 L·atm/(mol·K) * 298 K)

Simplifying the equation, we find:

d ≈ 0.805 g/L

Therefore, the density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

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Answer:

3.97

Explanation:

pH of buffer solution = pKa+Log(Cb/Ca)

pH of buffer solution = -log(Ka)+log(Cb/Ca)............... Equation 1

Where Ca = concentration of acid, Cb = concentration of base.

Given: Ka = 6.5×10⁻⁵, Ca = 0.25 M, Cb = 0.15 M

Substitute into equation 1

pH of buffer solution = -log(6.5×10⁻⁵)+log(0.15/0.25)

pH of buffer solution = 4.19+(0.22)

pH of buffer solution = 3.97.

The wavelength of the series limit for the Lyman spectral series of hydrogen in units of nm is 121.6 nm

The Lyman spectral series of hydrogen describes the transition of an electron from a higher energy level to the n=1 energy level. This is described by the equation Rydberg, which states that the wavelength of a spectral line is inversely proportional to the difference between the two energy levels. Therefore, the wavelength of the series limit is equal to the Rydberg constant (1.097 x 10^7 m^-1) divided by the difference of the n=1 energy level (2.18 x 10^-18J) and infinity, which results in 121.6 nm.

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Density is a physical property of matter and is defined as the mass per unit volume of a substance. It can be calculated by dividing the mass of the substance by its volume.

To find the density of the metal, we can use the following formula:

Density = Mass/Volume

For the given sample, the mass is 20.11 g and the volume is 6.03 mL. So, we can plug in the values into the formula and get:

Density = 20.11 g / 6.03 mL

To get the final density of the metal, we need to convert the units of volume to cm^3 as the density is usually given in g/cm^3

1ml = 1cm³

So, 6.03 ml = 6.03 cm³

Density = 20.11 g / 6.03 cm³

Density = 3.344 g/cm³

Therefore the density of the metal is 3.344 g/cm³

Answer:

the boiling point of solution at 3 decimal point is 100.329०C Ans.

Explanation:

given data -

molality of Nacl = 0.321 m

molal boiling point elevation constant (Kb) =0.512०C/m

# formula of change of boiling point of sample =

∆ Tb =i × Kb × m

Kb = molal boiling point of elevation constant

m = molality

i = vont's hoff factor.

Nacl is strong electrolyte and its 100% dissociate so the value of i for Nacl is 2

put value in the formula

∆ Tb = 2 × 0.512 ०C/m × 0.321m

= 0.3287

= 0.329०C

∆Tb = T'b - Tb

T'b = boiling point of solution

Tb= boiling point of solvent( water)

0.329०C = T'b - 100०c ( boiling point of water = 100०C)

T'b = 0.329०C + 100०C

= 100.329०C

hope this helps

Answer:

Explanation:

Electron (-) Negative

Proton (+) positive

Neutron(0) neutral

The methyl orange indicator will change from red to yellow at the titration's endpoint.

An acid-base indicator called methyl orange changes color between the pH ranges of 3.1 and 4.4. In acidic and basic solutions it is red and yellow, respectively

In this instance, an acid, hydrochloric acid, is being used to titrate the barium hydroxide solution. The pH of the solution will fall as we add the acid since it will neutralize the base. The hue of the methyl orange indicator will vary when the pH ranges from 3.1 to 4.4

All of the barium hydroxide will have interacted with the hydrochloric acid by the time the titration is complete leaving a neutral solution. When the methyl orange indicator becomes yellow the solution's pH is in the basic range.

Therefore, the methyl orange indicator will change from red to yellow at the titration's endpoint.

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Answer:

protons and neutrons are found in nucleus

Answer:

The answer is

C. Graph A

Answer:

Graph A

Explanation:

:)

Answer:

Chemical standard state

a. Temperature is 25C

b. Initial concentration of reactants and products is 1M

Biochemical standard state

a. Temperature is 25C

b. Initial concentration of reactants and products is 1M

Explanation:

The standard state is the reference state of a material which can be used to calculate its properties under other nonstandard conditions.

The biochemical standard state include;

a. Temperature is 25C

b. Initial concentration of reactants and products is 1M

Similarly, the chemical standard state include;

a. Temperature is 25C

b. Initial concentration of reactants and products is 1M

Hence the answer.

Gibbs energy of a reaction can be calculated from the Helmholtz equation as follows: ΔG = ΔH - TΔS. The ΔG for the given reaction is 333214.2 J.

Gibbs energy G is the energy stored in a system which is balanced from the energy for work done. The equation to find Gibbs energy change is as follows: ΔG = ΔH - TΔS.

The enthalpy change or ΔH is the difference of total enthalpy of products from the total enthalpy of reactants. In calculation, the standard enthalpy of each species in the reaction must be multiplied with their coefficients.

From the given standard values, ΔH is calculated as follows:

ΔH = ΔH (products) - ΔH (reactants).

     = [(2× -733.8) + (3 × -393.5)] -  [(-824.5) + (13 × -110.5)]

     = - 2035.8 KJ/mol

The entropy change ΔS can be calculated in a similar way from the given values as follows:

ΔS =  [(2× 445.2) + (3 × 213.6)] -  [(87.4) + (13 × 197.6)]

     = -1125 J/(mol K)

The temperature is 298 K thus ΔG can be calculated as follows:

ΔG = ΔH - TΔS

     = - 2035.8 KJ/mol -(-1125 J/(mol K) × 298 K)

     = 333214.2 J

Therefore, the Gibbs energy change ΔG for the given reaction is 333214.2 J.

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The order of elution in reversed-phase HPLC is different from that in a normal-phase separation, with more polar solutes eluting first. The mobile phase's polarity is increased to produce longer retention periods.

A method in analytical chemistry called high-performance liquid chromatography, formerly known as high-pressure liquid chromatography, is used to separate, recognize, and quantify each component in a mixture.

To obtain a consistent increase in the organic solvent (usually methanol or acetonitrile) over the course of the study, gradients in reversed-phase HPLC typically use on-line (dynamic) mixing of solvents. This increases the elution strength of the eluent over time.

Thus, In contrast to the normal phase HPLC, which employs a polar stationary phase and a less polar mobile phase, the reverse phase HPLC makes use of a nonpolar stationary phase and a polar mobile phase.

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Answer:

112 L O2.

Explanation:

Explanation:

CH4(g)+2O2(g)=CO2(g)+2H2O. 58.2l/22.4l=2.60moles CH4*2=5.20 moles H2O

Answer:

B people control how plants or animals reproduce to get desired traits

Explanation:

if you get it correct mark meh brainliest or however you say it so ppl know its correct

Scientific notation is the way that scientists handle large numbers and small numbers. For example, instead of writing 0.000 000 0056, they write 5.6 × 10⁻⁹.

We can think of 5.6 × 10⁻⁹ as the product of two numbers: 5.6 (the digits) and 10⁻⁹ (the power of 10).

Here are some examples of scientific notation.

1000 = 1 × 10³; 7354 = 7.354 × 10³

100 = 1 × 10²; 482 = 4.82 × 10²

10 = 1 × 10¹; 89 = 8.9 × 10¹

1 = 1 × 10⁰; 6 = 6 × 10⁰

1/10 = 0.1 = 1 × 10⁻¹; 0.32 = 3.2 × 10⁻¹

1/100 = 0.01 = 1 × 10⁻²; 0.053 = 5.3 × 10⁻²

1/1000 = 0.001 = 1 × 10⁻³; 0.0078 = 7.8 × 10⁻³

The exponent of 10 is the number of places we must shift the decimal point to get the scientific notation.

Each place the decimal moves to the left increases the exponent by 1.

Each place the decimal point moves to the right decreases the exponent by 1.

EXAMPLE:

Write the following numbers in scientific notation: 1001;

6 926 300 000; -392; 0.000 000 13; -0.0038

Solution:

1.001 × 10³; 6.9263 × 10⁹; -3.92 × 10²; 1.3 × 10⁻⁷; -3.8 × 10⁻³

Hope this helps!

The correct option is (d) To express very large or very small number.

What is the Scientific Notation?

Scientific notation is a way to present numbers that are too large or too small to be easily written in decimal form. The three components of  scientific notation are coefficient, base and exponent. The proper format to write a scientific notation is a x 10^b, where a is a number or decimal number and b is the power of 10 to make scientific notation equivalent to original number. When a number between 1 and 10 is multiplied by a power of 10 then the number is expressed in scientific notation. For example,  10000000 can be written as 10⁷, which is the scientific notation and the exponent is positive here. Similarly, for the negative exponent 0.000001 can be can be represented as 10-⁷.                             Hence, the scientific notation is used to express very large or very small numbers.

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Answer:

10.6.

Explanation:

What is given?

[H⁺] = 2.79 x 10⁻¹¹ M.

Step-by-step solution:

Let's see the formula of pH:

Where [H⁺] is the proton concentration in M. So we have to replace the given data in the formula:

The pH of a [H⁺] = 2.79 x 10⁻¹¹ M solution would be 10.6.

The mass of TiC that can be produced is 2.06 g. The limiting reagent is Cl₂.

Calculate the moles of MnO₂

The molar mass of MnO₂ is 86.94 g/mol. So, the number of moles of MnO₂ is:

moles of MnO₂ = mass of MnO₂ / molar mass of MnO₂

= 8.00 g / 86.94 g/mol

= 0.0921 mol

Calculate the moles of HCl

The volume of the HCl solution is 15.0 mL. The density of the HCl solution is 1.13 g/mL. So, the mass of the HCl solution is:

mass of HCl solution = volume of HCl solution × density of HCl solution

= 15.0 mL × 1.13 g/mL

= 16.95 g

The mass of HCl in the solution is 36.4% of the mass of the solution. So, the mass of HCl is:

mass of HCl = 0.364 × mass of HCl solution

= 0.364 × 16.95 g

= 6.14 g

The molar mass of HCl is 36.5 g/mol. So, the number of moles of HCl is:

moles of HCl = mass of HCl / molar mass of HCl

= 6.14 g / 36.5 g/mol

= 0.167 mol

Calculate the moles of Cl₂ produced

The balanced equation for the reaction is:

2 MnO₂(s) + 4 HCl(aq) → 2 MnCl₂(aq) + 2 Cl₂(g)

For every 2 moles of MnO₂, 2 moles of Cl₂ are produced. So, the number of moles of Cl₂ produced is:

moles of Cl₂ = moles of MnO₂ / 2

= 0.0921 mol / 2

= 0.0460 mol

Calculate the moles of TiO₂

The mass of the sample that contains TiO₂ is 5.20 g. The TiO₂ content of the sample is 67.0%. So, the mass of TiO₂ in the sample is:

mass of TiO₂ = 0.670 × mass of sample

= 0.670 × 5.20 g

= 3.48 g

The molar mass of TiO₂ is 79.86 g/mol. So, the number of moles of TiO₂ is:

moles of TiO₂ = mass of TiO₂ / molar mass of TiO₂

= 3.48 g / 79.86 g/mol

= 0.0434 mol

Determine the limiting reagent

The moles of Cl₂ produced is less than the moles of TiO₂. So, Cl₂ is the limiting reagent.

Calculate the mass of TiC produced

The balanced equation for the reaction is:

TiO₂(s) + C(s) + Cl₂(g) → TiCl₄(g) + CO₂(g) + CO(g)

For every 1 mole of TiO₂, 1 mole of TiC is produced. So, the mass of TiC produced is:

mass of TiC = moles of TiO₂ × molar mass of TiC

= 0.0434 mol × 47.86 g/mol

= 2.06 g

Therefore, the mass of TiC that can be produced is 2.06 g and the limiting reagent is Cl₂.

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The indium has only two naturally occurring isotopes. The mass of the indium-113 is 112.9041 amu and the mass of indium-115 is 114.9039 amu. The  relative abundance of indium-115 is 57 %.

The average atomic mass is given as follows :

Average Atomic Mass = ∑(Relative Abundance × Mass)

The mass of indium-113 = 112.9041 amu

The mass of indium-115 = 114.9039 amu

Relative abundance for indium-113 =x

Relative abundance for indium-115 = (1-x)

x(112.9041) + (1 - x)(114.9039) = 114.818

x = 0.043 = 4.3 %

Relative abundance for indium-113 = 4.3 %

Relative abundance for indium-115 = 1 - 0.43

                                                         = 0.57 = 57 %

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Moles of an ideal gas are : 0.288

In general, the gas equation can be written

\(\large{\boxed{\bold{PV=nRT}}}\)

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.082 l.atm / mol K

T = temperature, Kelvin

Volume=V=3 L

T = 45°C+273=318 K

P = 2.5 atm

\(\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{2.5\times 3}{0.082\times 318}\\\\n=0.288\)

Answer:

Cl

Explanation:

In a covalent bond between Cl and H, (Cl) tends to attract electron density from the other element in the bond.

Chlorine is more electronegative than hydrogen. In general, elements towards the top-right of the periodic table are more electronegative. This is because these elements are desperate for a few more electrons to fill their outermost shell (and have a full octet). The more electronegative an element is, the more it wants electrons. As a result, highly electronegative atoms have a greater pull on the electrons in a covalent bond.

Answer:

During the early Paleozoic Era, the Earth's surface was very different from what it is today. The continents were arranged differently, forming one large supercontinent called Pangea. This landmass was surrounded by a single large ocean called Panthalassa. The climate was much warmer and wetter than it is today, with no ice caps at the poles.

The first land plants, known as bryophytes, appeared during the early Silurian Period, around 430 million years ago. These plants were small and simple, lacking roots and vascular tissue. They grew in damp environments, such as along the edges of lakes and streams. They were important in the development of soils and in the colonization of land by other organisms, such as insects and other arthropods.