Sue is on planet X which is a distance 6.6x109 km from a certain star which has a radius 7000 km. Sue measures the maximum intensity of light on the surface of the planet to be 9000 W m2. Planet X has no atmosphere and so there is no absorption of light between the star and the surface of the planet. Calculate the temperature of the star, which can be assumed to be a black body. a. 6.1e5K O b. 5.78 K O c. 2.0e5K O d. 6.0e6 K e. 6.0e8 K

Answer:first of all what is your question and i can give and example which is Use them when you have 2 forces named Fa & FF or Fg & Ff acting in opposite directions on an object and you need to know the resultant of your 2 forces.

Explanation:

i searched it up

The equation that could be used to find the velocity of the satellite if it is placed in a low Earth orbit is \(v = \sqrt{\frac{Gm_p}{200 \ km} }\).

The given parameters;

A low Earth orbit is an orbit around the Earth with altitude in the range of 250 km and 2000 km.

The gravitational potential or the work done in bringing the satellite to the low Earth orbit is given as;

\(U = \frac{GMm_p}{R} \\\\\)

where;

let the value of R = 400 km

Note: any value between 250 km and 2000 km can be used BUT 400 km is the only value within this range that can be found in the given options as you will see at the end of the solution.

\(U = \frac{GMm_p}{400 \ km}\)

The kinetic energy of the satellite at the low Earth orbit is equal to the gravitational potential energy due to the altitude of the low Earth orbit.

\(K.E = U\\\\\frac{1}{2} Mv^2 = \frac{GMm_p}{400 \ km} \\\\v^2 = \frac{2Gm_p}{400 \ km}\\\\v^2 = \frac{Gm_p}{200 \ km}\\\\v = \sqrt{\frac{Gm_p}{200 \ km}}\)

Thus, the equation that could be used to find the velocity of the satellite if it is placed in a low Earth orbit is \(v = \sqrt{\frac{Gm_p}{200 \ km} }\).

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Projectile motion is a combination of constant motion in the horizontal direction, and accelerated motion in the vertical direction. Therefore, the correct answer option is: D. constant, accelerated.

Projectile motion can be defined as a form of motion which is experienced by a physical object (body) that is projected near the surface of planet Earth, while moving along a parabolic (u-shaped curve) path, and under the influence of a gravitational force only.

Based on scientific research and records by scientists such as Galileo, we can infer and logically deduce that the initial horizontal velocity of a physical object undergoing a projectile motion is always equal to its final horizontal velocity.

Additionally, Galileo stated that projectile motion combines constant or uniform motion in the horizontal direction and accelerated motion in the vertical direction.

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The velocity of the ball = 18.84 rad/sec

The centripetal acceleration of the ball = 236.63 m/s²

The centripetal force of the ball = 118.32 N

The mass of the ball = 0.5 kg

The length of the string = 1.5

The time taken = 60 s

The number of rotations = 120

The velocity of the ball can be found using the formula,

              ω = θ / t

where ω is the angular velocity

           θ is the angular rotation

           t is the time taken

Let us substitute the known values in the above equation, we get

               ω = (120 x 2 x 3.14 x 1.5 ) / 60

                    = 1,130.4 / 60

                    = 18.84 radians/sec

The formula for centripetal acceleration is

                α = ω² / r

                    = 18.84² / 1.5

                    = 345.95 / 1.5

                    = 236.63 m / s²

The centripetal force is

              F = mω² / r

                 = 0.5 x 236.63

                 = 118.32 N

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The highest possible velocity of argon gas at the nozzle exit is 706.4 m/s.

To solve this problem, we can use the equation for isentropic flow through a nozzle, which relates the inlet and exit Mach numbers, pressures, and temperatures. Since the argon gas enters the nozzle adiabatically, we can assume that the process is isentropic, meaning that the entropy of the gas is constant.

Using the given inlet conditions, we can find the inlet Mach number to be 0.258. Using the given exit pressure, we can find the exit Mach number to be 1.604. Then, using the isentropic flow equation, we can find the exit temperature to be 524.9 K. Finally, we can use the definition of Mach number to find the exit velocity to be 706.4 m/s.

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Answer:

v = √ac×r

r = \(\frac{v^2}{ac}\)

Answer:

Explanation:

Sorry cant help

The removable discontinuity occurs at x=9, for the function f(x) = x²-81/x²-5x-36.

The function, f(x) = x²-81/x²-5x-36

x²-81 = x²-9² =0

x=±9

x²-5x-36 = 0

x²+9x-4x-36 = 0

x(x+9)-4 (x+9) = 0

x =4, -9.

F(x) = (x+9) (x-9)/(x+4)(x-9)

      =(x+9)/(x+4)

Thus, x=9 the function has the removable discontinuity. At x=9 the function(f(x)) has a value and for x≠0, the f(x) = (x+9)/(x+4).

Thus, x=9 is the removable discontinuity.

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Answer:

Explanation:

MLT^-2

.....

The sinking of Amyloplasts in response to gravity is thought to be one of the ways that cells can sense and respond to the force of gravity.

Amyloplasts are specialised organelles found in plant cells that are involved in the storage and regulation of starch. They are similar to chloroplasts in that they are both membrane-bound organelles, but amyloplasts are responsible for storing starch instead of producing it through photosynthesis.In addition to their role in starch storage, amyloplasts play a crucial role in the regulation of plant growth and development. They are involved in a process called gravitropism, which allows plants to sense and respond to the direction of gravity. This helps the plant to orient itself and grow in the correct direction.

Amyloplasts contain a dense, starch-rich cytoplasm and are typically larger and more numerous in cells that are involved in the storage of starch, such as in the roots, stems, and seeds of plants. By playing a role in both the storage and regulation of starch, amyloplasts are important for the overall health and development of the plant.

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Answer:

4.08m

Explanation:

h = PE/mg

h = 600/(15)(9.8)

h = 600/147

h = 4.08m

Since energy cannot be destroyed nor created but it can only be transformed from one form to another, the three possibilities energy transformations will be:

Conservation of energy state that energy cannot be destroyed nor created but it can only be transformed from one form to another.

When a fast moving roller coaster finishes its ride, before this, the roller coaster will be experiencing maximum kinetic energy. when it is trying to come to rest, the maximum energy = kinetic energy + potential energy and when it finally comes to a stop, the maximum energy will be equal to potential energy.

Therefore, the three possibilities energy transformations will be Kinetic energy, kinetic energy + potential energy and potential energy.

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1.33kg of ice at 0.00 celsius is added to an 8.25kg tub of water at a warmer temperature. If the final temperature is 15. 7 celcius, then the initial temperature of the warmer in the tub was 25.3°C.

We can use the principle of conservation of energy to solve this problem. The energy lost by the ice as it melts is equal to the energy gained by the water as it warms up. The energy lost or gained is given by

Q = mcΔT

Where Q is the energy lost or gained, m is the mass of the substance, c is its specific heat capacity, and ΔT is the change in temperature.

First, let's calculate the energy gained by the water

Qwater = (8.25 kg)(4.18 J/(g·°C))(15.7°C - ti)

Where we have used the specific heat capacity of water, which is 4.18 J/(g·°C).

Next, let's calculate the energy lost by the ice

Qice = (1.33 kg)(334 J/g)

Where we have used the heat of fusion of ice, which is 334 J/g.

Since the ice melts at 0°C, we can set the energy lost by the ice equal to the energy gained by the water

Qice = Qwater

(1.33 kg)(334 J/g) = (8.25 kg)(4.18 J/(g·°C))(15.7°C - ti)

Solving for ti, we get

ti = 25.3°C

Therefore, the initial temperature of the warmer in the tub was 25.3°C.

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Answer:

The radius will be "100.31 m". A further solving is given below.

Explanation:

The given values are:

Time,

T = 2 minutes

i.e.,

 = 120 seconds

Speed,

V = 5.25 m/s

As we know

⇒  \(T=\frac{2 \pi R}{V}\)

then,

⇒  \(R=\frac{TV}{2 \pi}\)

On substituting the given values, we get

⇒      \(=\frac{120\times 5.25}{2\times 3.14}\)

⇒      \(=\frac{630}{6.28}\)

⇒      \(=100.31 \ m\)

Answer:

F(10)=mass(327)x acceleration(m/s)

Explanation:

Answer:

When two tectonic plates meet, we get a “plate boundary.” There are three major types of plate boundaries, each associated with the formation of a variety of geologic features.

Explanation:

When the plates meet at the boundaries the convergent boundaries lie at the collision of two plates and the divergent lies near mid-oceanic ridges.

The earth plate tectonics are divided into the three types of plates as convergent which is the destruction of crust and are found where the heavy and light plate comes and colloid with each other submerging the heavier plate into the mantel.

The divergent ones found near the mid-oceanic ridges are the formation of a new plate as the plates diverge away from the ridges.

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Answer:

The lower fixed point, or ice point, is the temperature of pure melting ice at normal atmospheric pressure. Hopes this helps.

Explanation:

Answer:

5824 yards^2

Explanation:

area = length x width

area = 112 x 52

area = 5824

Answer:

5824 squared yards

Explanation:

The current is 3.33A, the resistance is 36.03 Ohm, and the peak voltage is 169.68V.

Given information:

The power rating of the resistive element (P) = 400 W

Voltage supplied by the outlet (V) = 120 VAC (RMS)

a) To find the current flowing through the element, the formula:

Power (P) = Voltage (V) × Current (I)

Current (I) = Power (P) / Voltage (V)

Substituting the given values:

Current (I) = 400 W / 120 VAC

= 3.33 A

b) To find the resistance of the element, Ohm's Law can be used :

Resistance (R) = Voltage (V) / Current (I)

Resistance (R) = 120 VAC / 3.33A

= 36.03 Ohm

c) To find the peak voltage, it is required to convert the RMS voltage to peak voltage. For an AC voltage, the relationship between RMS voltage (\(V_{rms\)) and peak voltage (\(V_{peak\)) is given by:

\(V_{peak} = V_{rms} \times \sqrt2\)

Substituting the given RMS voltage:

Peak voltage  = \(120 \times \sqrt2\)

= 169.68 V

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Answer:

i guess if the a glass gets to cold it will bust

Explanation:

The answer is:

To calculate the electric field at a point due to a point charge, we can use the formula:

\(E = k * q / r^2\)

where E is the electric field, k is the Coulomb constant, q is the charge of the point charge, and r is the distance from the point charge to the point where we want to find the electric field.

In this case, we have a + charge of q =\(1.50 * 10^{-8} C\) and we want to find the electric field at a point 0.200 m to the right of the charge. Therefore, the distance r = 0.200 m.

Plugging in the values, we get:

E = \((9 * 10^9 N*m^2/C^2) * (1.50 * 10^{-8} C) / (0.200 m)^2\)

E = \(1.69 * 10^5 N/C\)

The electric field is directed away from the + charge, so we include a + sign to indicate the direction of the field.

\(1.69 *10^5 N/C\) to the right (+)

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The new period (T2) is equal to the square root of 2 times the original period (T1) when the mass is doubled in simple harmonic motion.

In simple harmonic motion, the period (T) is defined as the time taken for one complete cycle of oscillation. The period is inversely proportional to the square root of the mass attached to the spring.

Let's denote the original mass as m1 and the new mass as m2. The period of oscillation with the original mass is T1, and we need to find the new period T2 with the doubled mass.

Mathematically, the period is given by:

\(T = 2\pi * \sqrt {(m/k)}\)

where k is the spring constant.

Since the spring constant remains the same, we can write the equation as:

\(T = 2\pi * \sqrt {(m/k)\)

\(T1 = 2\pi * \sqrt {(m1/k)\)

To find the new period T2 with the doubled mass (2m1), we substitute m2 = 2m1 into the equation:

\(T2 = 2\pi * \sqrt {(2m1/k)}\)

Simplifying the equation, we get:

\(T2 = 2\pi * (\sqrt {2 * \sqrt {(m1/k))\\T2 = \sqrt2 * T1\)

Therefore, the new period (T2) is equal to the square root of 2 times the original period (T1) when the mass is doubled in simple harmonic motion.

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Answer:

\(3.16*10^1^1\) kg

Explanation:

According to Newton's Law of Universal Gravitation:

\(F=G\frac{m_1m_2}{r^2}\\F=0.0996381755N\\G=6.674*10^-^1^1\frac{Nm^2}{kg^2}\\m_2=42.90kg\\r=95.32m\)

Rewriting to solve for \(m_1\):

\(m_1=\frac{F(r)^2}{G(m_2)}\\m_1=\frac{(0.0996381755N)(95.32m)^2}{(6.674*10^-11\frac{Nm^2}{kg^2})(42.90kg)}\\m_1=3.16*10^1^1kg\)

I believe this is the answer based on the given values, but it is not a logical answer.  Is it possible one or more of the values in the question were entered incorrectly?

Answer: The Earth is an oblate spheroid, meaning it is roughly spherical in shape but flattened at the poles and bulges at the equator. This shape has been scientifically proven through centuries of evidence and observations. While some people may claim that the Earth is flat, this idea is not supported by scientific evidence.

Answer:

w = -70

Explanation:

\(-w+150 = 220\)

\(-w = 70\)

\(w = -70\)

Answer: w = -70

Explanation:

   To solve, we will isolate with inverse operations.

Given:

   -w + 150 = 220

Subtract 150 from both sides of the equation:

   -w = 70

Divide both sides of the equation by -1:

   w = -70

The same thing could reasonably be said about multicollinearity. Specifically, the reason for this is due to the violation of the assumption of independent predictors.

Let us understand what these terms mean:

In statistical analysis, multicollinearity is the high correlation among predictors in a regression model. It is problematic because of its adverse effects on the model, including making it difficult to determine the effect of an independent variable, coefficients becoming insensitive to small changes in the model, and reducing the reliability of the model.

In regression analysis, independent predictors are those variables that contribute to the prediction of the dependent variable or outcome, and their inclusion in the model improves the accuracy of the prediction of the model.

In a regression model, it is an assumption that predictors are independent, which means that the predictors have little to no correlation with each other. If this assumption is violated, it is known as multicollinearity.

Therefore, the same thing could reasonably be said about multicollinearity. Specifically, the reason for this is due to the violation of the assumption of independent predictors.

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The given statement "simulated sensor inhibit a pair from firing opponent process theory" is false because in opponent process theory, the firing of one member of a color pair actually inhibits the firing of the other member, rather than simulated sensors inhibiting them.

Opponent process theory is a model of color vision that proposes that the perception of color arises from the activity of three opponent pairs of color receptors. Each pair consists of one type of receptor that responds to a particular color and another type that responds to the opposite color. According to this theory, when one receptor is activated, it inhibits the other receptor in the pair from firing. Simulated sensors, on the other hand, refer to artificially created sensors that are not a part of the opponent process theory. Therefore, they do not inhibit a pair from firing in opponent process theory.

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I think the answer for the following question is A.