Sucrose is an organic compound made by plants for quick energy. What type of organic compound is sucrose?


1-protein
2-carbohydrate
3-lipid
4-nucleic acid

Answer:

yes, some can

Explanation:

because like salt an other compounds by being decomposed

Taking into account the definition of calorimetry, the temperature change of A will be one sixth of the temperature change of B.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, for object A:

QA = cA× mA× (ΔT)A

and for object B:

QB = cB× mB× (ΔT)B

You know:

Object A has double the specific heat of object B. ⇒ cA= 2× cB

Object A has triple the mass of object B. ⇒ mA= 3× mB

If the same amount of heat is applied to both objects ⇒ QA= QB

Then:

cA× mA× (ΔT)A= QB = cB× mB× (ΔT)B

2× cB × 3× mB× (ΔT)A=  cB× mB× (ΔT)B

Solving:

6× cB × mB× (ΔT)A= cB× mB× (ΔT)B

(ΔT)A= (cB× mB× (ΔT)B) ÷ (6× cB × mB)

(ΔT)A=\(\frac{1}{6}\) (ΔT)B

Finally, the temperature change of A will be one sixth of the temperature change of B.

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Answer: Le Chatelier's principle states that a system at equilibrium will respond to any stress or change in conditions by shifting the equilibrium position to counteract the stress and restore equilibrium. In the case of indicators, the color of the indicator molecule depends on its protonation state, which in turn depends on the pH of the solution.

At relatively low pH, the solution is acidic and has a high concentration of H+ ions. In this condition, the equilibrium of the indicator molecule will shift towards the protonated form (HIn), as per Le Chatelier's principle. The H+ ions from the solution will combine with the indicator molecule to form HIn, which has a different color than its deprotonated form (In-).

Therefore, at low pH, the dominant form of the indicator is HIn. On the other hand, at high pH, the solution is basic and has a low concentration of H+ ions. In this condition, the equilibrium of the indicator molecule will shift towards the deprotonated form (In-), as per Le Chatelier's principle.

The low concentration of H+ ions in the solution makes it difficult for the HIn molecules to remain protonated, and they will undergo deprotonation to form In-. At high pH, the dominant form of the indicator is In-.

In summary, Le Chatelier's principle explains why the dominant form of the indicator molecule changes as the pH of the solution changes. At low pH, the equilibrium shifts towards the protonated form (HIn), and at high pH, the equilibrium shifts towards the deprotonated form (In-).

Answer:

1.59

Explanation:

14=pOH+pH

pOH=14-12.41

pOH=1.59

Answer:

carcinogen

Explanation:

cigarette smoke and UV radiation both of the capability to cause cancer cells in living tissue, meaning they can both be classed as carcinogens

Answer:

687.5 g of CO2

Explanation:

We'll begin by writing the balanced equation for photosynthesis. This is illustrated below:

6CO2 + 6H2O —> C6H12O6 + 6O2

Next, we shall determine the mass of CO2 absorbed and the mass of O2 released from the balanced equation. This is illustrated below:

Mass of CO2 = 12 + (2 × 16) = 12 + 32

= 44 g/mol

Mass of CO2 from the balanced equation = 6 × 44 = 264 g

Molar mass of O2 = 2 × 16 = 32 g/mol

Mass of O2 from the balanced equation = 6 × 32 = 192 g

Summary:

From the balanced equation above,

264 g of CO2 were absorbed to release 192 g of O2.

Finally, we shall determine the mass of CO2 absorbed to release 500 g of O2. This can be obtained as follow:

From the balanced equation above,

264 g of CO2 were absorbed to release 192 g of O2.

Therefore, Xg of CO2 will be absorbed to release 500 g of O2 i.e

Xg of CO2 = (264 × 500)/192

Xg of CO2 = 687.5 g

Thus, 687.5 g of CO2 will be absorbed to release 500 g of O2.

Given that blood exerts the same osmotic pressure as a 0.15 M NaCl solution, the solution could be the hypotonic solution is c. 0.008 M NaCl solution.

A hypotonic solution is one that has a lower solute concentration than another solution. In this case, the 0.15 M NaCl solution exerts the same osmotic pressure as blood, so it is isotonic to blood. The 0.68 M NaCl solution has a higher solute concentration than blood, so it is hypertonic to blood.

The 0.008 M NaCl solution has a lower solute concentration than blood, so it is hypotonic to blood. Therefore, the correct answer is c. 0.008 M NaCl solution.

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The two proteins with unequal molecular weights eluting simultaneously from a size exclusion chromatography (SEC) column is best explained by the porous structure of the column.A SEC column is used to fractionate proteins based on their size. The larger protein elutes first as it is unable to enter the pores of the column and therefore travels around the beads. Smaller proteins, on the other hand, can enter the pores of the column and take longer to elute.However, in this case, the proteins with unequal molecular weight eluted simultaneously from the SEC column. This can be best explained by the porous structure of the column. The SEC column has a very porous structure with a high capacity for separation. Due to the high porosity of the column, both the proteins passed through the pores at the same time leading to their simultaneous elution.A column with a more rigid structure such as ion exchange chromatography, does not allow for simultaneous elution of proteins with unequal molecular weights as the proteins get separated by their charges and affinity towards the resin.

Protein is a complex molecule that helps the body carry out its functions optimally. Protein can be found in several types of food such as beef, chicken, beans, eggs, fish and shrimp. Protein is a nutrient that is needed in large quantities. That's why protein is classified as a macro nutrient. Where is the best source of protein? Foods that come from the sea (seafood) are an excellent source of protein because they are usually low in fat. Fish like salmon do contain slightly higher levels of fat, but are still considered good foods for heart health.

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For the voltaic cell with nickel and iron electrodes, the shorthand notation is:
Ni(s)|Ni2+(aq)||Fe3+(aq)|Fe(s)

To calculate the standard free-energy change at 25°C for the reaction Mg2+(aq) + Zn(s) → Mg(s) + Zn2+(aq), we need to use the formula:

ΔG° = -nFE°
where ΔG° is the standard free-energy change, n is the number of moles of electrons transferred, F is Faraday's constant (96,485 C/mol), and E° is the standard cell potential.

Step 1: Determine the half-reactions and their standard reduction potentials.
Mg2+(aq) + 2e- → Mg(s)  E° = -2.37 V
Zn2+(aq) + 2e- → Zn(s)  E° = -0.76 V

Step 2: Determine the overall cell potential.
E°(cell) = E°(reduction) - E°(oxidation)
E°(cell) = (-0.76 V) - (-2.37 V) = 1.61 V

Step 3: Calculate the standard free-energy change.
ΔG° = -nFE°
ΔG° = -2 mol e- * 96,485 C/mol e- * 1.61 V
ΔG° = -310.44 kJ/mol

The standard free-energy change for this reaction at 25°C is -310 kJ/mol (rounded to three significant figures).

For the voltaic cell with Zn(s) and Al(s) electrodes, the spontaneous reaction is:
2 Al + 3 Zn2+ → 3 Zn + 2 Al3+

For the voltaic cell with nickel and iron electrodes, the shorthand notation is:
Ni(s)|Ni2+(aq)||Fe3+(aq)|Fe(s)

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For the voltaic cell with nickel and iron electrodes, based on the standard reduction potentials of Ni2+ and Fe3+, the shorthand notation for this voltaic cell is:
Ni(s)|Ni2+(aq)||Fe3+(aq)|Fe(s)

To calculate the standard free-energy change at 25°C for the reaction Mg2+(aq) + Zn(s) → Mg(s) + Zn2+(aq), we can use the following equation:
ΔG° = -nFE°
Where ΔG° is the standard free-energy change, n is the number of moles of electrons transferred in the reaction, F is Faraday's constant (96,485 C/mol), and E° is the standard cell potential.
First, we need to determine E°. We do this by looking up the standard reduction potentials for both half-reactions:
Mg2+(aq) + 2e- → Mg(s)  E° = -2.37 V
Zn2+(aq) + 2e- → Zn(s)  E° = -0.76 V
We can find the overall E° by subtracting the reduction potential of the reaction we need to reverse (Zn(s) → Zn2+(aq) + 2e-):
E° = -2.37 V - (-0.76 V) = -1.61 V
In this reaction, n = 2 since there are 2 moles of electrons transferred. Now we can calculate ΔG°:
ΔG° = -2 × 96,485 C/mol × (-1.61 V) = 310 kJ/mol (rounded to three significant figures)
For the voltaic cell with Zn(s) and Al(s) electrodes, the spontaneous reaction is:
2 Al + 3 Zn2+ → 3 Zn + 2 Al3+
For the voltaic cell with nickel and iron electrodes, based on the standard reduction potentials of Ni2+ and Fe3+, the shorthand notation for this voltaic cell is:
Ni(s)|Ni2+(aq)||Fe3+(aq)|Fe(s)

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Dams and reservoirs can provide reliable water storage but have potential environmental impacts such as habitat loss and disruption of natural flow.

Sedimentation can reduce the storage capacity of reservoirs over time, requiring periodic dredging or desilting to maintain efficiency. Evaporation can lead to water loss from the reservoir, particularly in arid or semi-arid regions with high evaporation rates. These factors need to be carefully managed to ensure the long-term sustainability and efficiency of water storage.

Sedimentation and evaporation are important considerations that need to be managed. Social and economic impacts should also be assessed. Alternative approaches and improved water management practices can enhance sustainability and efficiency. Careful planning, impact assessments, stakeholder engagement, and monitoring are crucial for mitigating negative impacts and maximizing benefits.

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Answer:

c

Explanation:

it is c but im not exactly sure

you have a 25% chance tho

sorry

2H₂+O₂⇒ 2H₂O

Given

Chemical equation :

2H₂+O₂⇒

Required

Compound produced

Solution

In determining the product that may be produced is to use the principle of the law of conservation of mass where the number of atoms/elements in the reaction either before the reaction (reactants) or after the reaction (products) is the same so that a balanced chemical equation is formed.

In the above reaction, there are two elements that play a role in the reaction, namely H and O

So that the resulting product also has these 2 elements, so we can ignore options A and C because there are elements C and Cl, while choice B does not contain the element H

The right choice: D

The methyl carbon from acetyl-CoA and the carbonyl carbon from oxaloacetate become chemically equivalent at the point of the citric acid cycle where the enzyme citrate synthase catalyzes the condensation of acetyl-CoA and oxaloacetate to form citrate.

The citric acid cycle, also known as the Krebs cycle, is a series of chemical reactions that occurs in the mitochondria of cells. One of the key steps in this cycle is the condensation of acetyl-CoA and oxaloacetate to form citrate. This reaction is catalyzed by the enzyme citrate synthase. During this reaction, the carbonyl carbon of oxaloacetate and the methyl carbon of acetyl-CoA are chemically equivalent in the molecule of citrate. This reaction marks the starting point of citric acid cycle and forms the first intermediate of the citric acid cycle.

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Explanation:

Good question!

When you react an acid with a base,the pH of the product is determined by the concentrations of the reactants (the acid and the base)

If both reactants (acid and base) are strong,the pH of the product is 7

If the acid is stronger than the base,the pH of the product will be less than 7

If the base is stronger,the pH of the product will be greater than 7

I hope this helps

Thus, the empirical formula of this compound is S2O5 S 2 O 5 .

The simplest whole number ratio of atoms from each element in a compound is called the empirical formula. The precise amount of atoms of each element in a compound is given by its molecular formula. the connection between the molecular formula and empirical formula.

The simplest whole number ratio of atoms from each component of a compound is its empirical formula. It is determined empirically utilizing data from trials. For instance, whereas the empirical formula for glucose is CH 2O, its molecular formula is C 6H 12O 6.

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A tutorial concerning atomic orbitals can help one comprehend the fundamental tenets of quantum mechanics pertaining to atoms and their electrons.

This tutorial encompasses the shapes, extents, as well as energies of atomic orbitals; moreover, it shows how they congregate to create molecular orbitals.

In addition to that, it notifies us on how the electronic arrangements of atoms determine their chemical traits and functions such as responsiveness and its capability to bond with other atoms.

Thus, a tutorial concerning atomic orbitals builds up a foundation for understanding the behavior of matter at both the atomic and molecular levels.

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Note that the video was about Orbitals in Atoms. Here is some information about that.

Existence of electrons in an energy state is referred to as Basic Atomic Orbitals.

Characterized by their shape, energy, and probability of containing an electron, the orbitals are categorized into various types such as s, p, d and f - each with a unique structure and distinct energy levels. For instance, the spherical shape of an s-orbital possesses greater energy when away from the nucleus.

Meanwhile, a p-orbital has two lobes separated by a node. Of utmost importance when examining atoms, molecules, and chemical reactions is gaining knowledge about atomic orbitals. Unlike other orbitals, d and f varieties possess a high degree of complexity regarding shape as well as energy distribution.

Physically speaking,the probability that electrons exist within these orbitals can be determined through measuring electron densities based on their distances from nuclei.

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Answer:

Explanation:

1.4193.61

2.1.69205e7

3.1.57611e14

4.46270.5

The voltage of the electrochemical cell is given by the difference between the potential of the two half-cells, Ecell = Ecathode - Eanode.

In a standard electrochemical cell, the half-cell potentials are equal to the standard reduction potentials (Eo) for the given redox reaction. However, in the experiment described, the voltage was not equal to the standard reduction potential for the Cu/Zn redox reaction at all times.

This is likely due to a few different factors.First, the initial concentrations of the Cu2+ and Zn2+ ions may not have been exactly 1 M. There could have been slight variations in the actual concentrations of the solutions used, which would result in a voltage that is different from the expected value based on the standard reduction potentials. Additionally, the Cu2+ and Zn2+ ions in solution may have reacted with each other to form other species, which could change the concentration of the ions and affect the voltage of the cell.

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Explanation:

Sodium Sulfate + water

hope it helps ya

Answer:

1 mol contains 6.022*10^23 molecules 0.36 moles contain 0.36 * 6.022*10^23 = 2.2 *10^23 molecules

Explanation:

The rate of change of the concentration of Na₂C₂O4 is -0.0551 M/s.

To determine the rate of change of the concentration of sodium oxalate (Na₂C₂O4), we can use the rate equation:

Rate = (Δ[Na₂C₂O4]) / (Δt)

where Δ[Na₂C₂O4] represents the change in concentration of Na₂C₂O4 and Δt represents the change in time.

In this case, the initial concentration of Na₂C₂O4 is 1.34 M, and after 19.3 seconds, the concentration is 0.276 M.

Substituting the values into the rate equation, we have:

Rate = (0.276 M - 1.34 M) / (19.3 s - 0 s)

Rate = (-1.064 M) / (19.3 s)

Rate = -0.0551 M/s

Therefore, the rate of change of the concentration of Na₂C₂O4 is -0.0551 M/s.

The negative sign indicates that the concentration of Na₂C₂O4 is decreasing over time, as the reactant is being consumed in the reaction.

It's important to note that the rate of a reaction is influenced by various factors, such as the reaction mechanism, temperature, and presence of catalysts. The rate can be determined experimentally by measuring the change in concentration of a reactant or product over a specific time interval.

The given information allows us to calculate the rate of change for the specific reaction involving Na₂C₂O4. However, without additional information about the reaction, it is not possible to determine the exact nature or stoichiometry of the reaction, as well as any other reactants or products involved.

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The molar mass of the unknown gas is 12.068 g/mol.

To determine the molar mass of the unknown gas, we can use Graham's Law of Effusion, which states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. We can use this relationship to calculate the molar mass of the unknown gas.

First, we calculate the molar mass of methane, which is 16.043 g/mol. Then, we use the following equation to calculate the molar mass of the unknown gas:

Molar mass of unknown gas = (molar mass of methane)² / (3.4)

Therefore, the molar mass of the unknown gas is 12.068 g/mol.

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Answer:

The velocity of the bb when it reaches a height of 203 m can be determined using the laws of projectile motion. Since the bb is moving vertically upwards, its velocity at that height will be zero.

brainlest?

Answer: v = 83.96 m/s

Assuming the acceleration due to gravity is approximately 9.8 m/s^2, we can use the principles of projectile motion and energy conservation.

Using the equation for the vertical displacement of an object in free fall:

Δy = (v₀² - v²) / (2g)

Δy = vertical displacement (203m)

v₀ = initial velocity (105 m/s)

v = final velocity (not known yet)

g = accerlation due to gravity (9.8 m/s^2)

Lets rearrange the equation to solve for the final velocity:

v = v = √(v₀² - 2gΔy)

Substituting the given values:

v = √(105² - 2 * 9.8 * 203)

v ≈ √(11025 - 3979.6)

v ≈ √(7054.4)

v ≈ 83.96 m/s

Therefore, when the BB pellet is at the height of 203m, its velocity will be approximately 83.96 m/s.

Accrued expenses is the most likely item on the income statement and balance sheet to vary spontaneously with sales (option 3).

Accrued expenses refer to an expense that a company has incurred but has not yet paid for. For example, wages that employees have earned but not yet received payment for, rent, interest, and taxes that have been accrued but not yet paid are all examples of accrued expenses.

Accrued expenses are spontaneous liabilities, which means they vary in proportion to a company's sales volume. The higher the sales, the more the company is likely to owe in accrued expenses. The company must record the accrued expenses as liabilities on the balance sheet and as expenses on the income statement.

Accrued expenses are likely to increase when sales volume increases, and they decrease when sales volume decreases. It means that accrued expenses are the most likely item on the income statement and balance sheet to vary spontaneously with sales.

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Answer:

D the sun

Explanation:

The sun adds heat to make the water evaporate.

Answer:

B)

Explanation:

The sun causes evaporation by heat, the lamps bulb will get hot and be a model of the sun. We know this because heat evaporates water.

Answer:

0.206 mol H₂O₂

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

7.00 moles H₂O₂

Step 2: Identify Conversions

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O₂ - 2(1.01) + 2(16.00) = 34.02 g/mol

Step 3: Convert

\(7.00 \ g \ H_2O_2(\frac{1 \ mol \ H_2O_2}{34.02 \ g \ H_2O_2} )\) = 0.205761 mol H₂O₂

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

0.205761 mol H₂O₂ ≈ 0.206 mol H₂O₂

Answer:

238.14

Explanation:

2 H + 2O

2(1.01) + 2(16.00) = 34.02

34.02*7 = 238.14

238.14

Answer:

energy from glucose

Explanation:

Answer:

it is a chemical process

Explanation:

rusting is the formation of reddish-brown ferric oxides on iron by low-temperature oxidation in the presence of water.

The chemical formula for rust is Fe2O3 and is commonly known as ferric oxide or iron oxide. The final product is a series of chemical reactions simplified below as- The rusting of the iron formula is simply 4Fe + 3O2 + 6H2O → 4Fe(OH)3. The rusting process requires both the elements of oxygen and water.

Answer:

when an atom loses electrons, it will then contain more protons. Thus, the charge of the atom become positive.